A body of mass 60kg is displaced through 90m in 4 second when force is applied to it.calculate acceleration and the force applied​

Answer:

500ms times 2 would be when the ball reaches the max horizontal distance.

Then to find the angle, use the formula of time to reach max height t = u sin theta / g . With t being the max height time 500ms, u being 10m/s

For initial vertical velocity just use u sin theta.

The max horizontal height is "10 meters" and the initial vertical velocity is "4.9 m/s".

Given:

Horizontal velocity,

Time,

At max height,

(a)

→ Time to flight (T) will be:

= [tex]2t[/tex]

= [tex]2\times 0.5[/tex]

= [tex]1 \ second[/tex]

→ Horizontal distance will be:

= [tex]V_x\times T[/tex]

= [tex]10\times 1[/tex]

= [tex]10 \ meters[/tex]

(b)

→ The initial vertical velocity will be:

[tex]V_{yf} = V_y +gt[/tex]

   [tex]0 = V_y - 9.8\times 0.5[/tex]

  [tex]V_y = 4.9 \ m/s[/tex]

Thus the above answers are correct.

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Answer:

  48 ft/s

Explanation:

Acceleration due to gravity decreased the upward velocity to zero in 1.5 seconds (half the total time), so the initial velocity must have been ...

  (32 ft/s^2)(1.5 s) = 48 ft/s

Answer:

PART A

In a solid

The attractive forces keep the particles together tightly enough so that the particles do not move past each other. ... In the solid the particles vibrate in place. Liquid – In a liquid, particles will flow or glide over one another, but stay toward the bottom of the container.

In a liquid

Particles are quite close together and move with random motion throughout the container. Particles move rapidly in all directions but collide with each other more frequently than in gases due to shorter distances between particles.

A gas

The particles move rapidly in all directions, frequently colliding with each other and the side of the container. With an increase in temperature, the particles gain kinetic energy and move faster.

PART B

The molecules are continually colliding with each other and with the walls of the container. When a molecule collides with the wall, they exert small force on the wall The pressure exerted by the gas is due to the sum of all these collision forces. The more particles that hit the walls, the higher the pressure.

Explanation:

GOOD LUCK!!! :)

Answer:

The pressure is  [tex]P = 1.31*10^{5} \ Pa[/tex]

Explanation:

From the question we are told that

    The depth of the swimming pool is  [tex]d = 3.00 \ m[/tex]

     The density of water is  [tex]\rho = 1.00*10^{3} \ kg /m^3[/tex]

Generally the  total pressure exerted on the bottom of the swimming pool is mathematically represented as

          [tex]P = P_o + \rho * g * h[/tex]

Here [tex]P_o[/tex] is the atmospheric pressure with value

        [tex]P_o = 101325 \ Pa[/tex]

So

        [tex]P = 101325 + [1000 * 9.8 * 3][/tex]

=>     [tex]P = 130725 \ Pa[/tex]

=>    [tex]P = 1.31*10^{5} \ Pa[/tex]

Answer:

The magnitude will be "353.5 N". A further solution is given below.

Explanation:

The given values is:

F = 500 N

According to the question,

In ΔABC,

⇒ [tex]\angle BCA = (90-30)[/tex]

⇒             [tex]=60^{\circ}[/tex]

then,

⇒ [tex]\angle BAC=(180-45-60)[/tex]

⇒             [tex]=75^{\circ}[/tex]

Now,

The corresponding angle will be:

⇒ [tex]\angle FAC=60^{\circ}[/tex]

⇒ [tex]\angle FAB=70+60[/tex]

⇒             [tex]=135^{\circ}[/tex]

Aspect of F across the AC arm will be:

= [tex]F\times cos(60)[/tex]

On putting the values of F, we get

= [tex]500\times (.5)[/tex]

= [tex]200 \ Newton[/tex]

Component F along the AC (in magnitude) will be:

= [tex]F\times cos(135)[/tex]

= [tex]500\times (-.707)[/tex]

= [tex]-353.5 \ N \[/tex]

Answer:

The kinetic coefficient of friction between box and floor is 0.443.

Explanation:

Let suppose that the box is accelerated uniformly, the acceleration ([tex]a[/tex]), measured in meters per square second, is determined by the following kinematic formula:

[tex]a = \frac{v_{f}-v_{o}}{t}[/tex] (1)

Where:

[tex]v_{o}[/tex], [tex]v_{f}[/tex] - Initial and final speeds of the box, measured in meters per second.

[tex]t[/tex] - Time, measured in seconds.

If we know that [tex]v_{o} = 0\,\frac{m}{s}[/tex], [tex]v_{f} = 2\,\frac{m}{s}[/tex] and [tex]t = 4\,s[/tex], then the acceleration experimented by the box is:

[tex]a = \frac{2\,\frac{m}{s}-0\,\frac{m}{s} }{4\,s}[/tex]

[tex]a = 0.5\,\frac{m}{s^{2}}[/tex]

Based on the body diagram, we proceed to form the equations of equilibrium:

[tex]\Sigma F_{x} = P\cdot \cos \theta -\mu_{k}\cdot N = m\cdot a[/tex] (1)

[tex]\Sigma F_{y} = N - m\cdot g - P\cdot \sin \theta = 0[/tex] (2)

Where:

[tex]P[/tex] - Magnitude of the force exerted on the box, measured in newtons.

[tex]\theta[/tex] - Direction of the force exerted on the box, measured in sexagesimal degrees.

[tex]\mu_{k}[/tex] - Kinetic coefficient of friction between box and floor, dimensionless.

[tex]N[/tex] - Normal force from the floor to the box, measured in newtons.

[tex]m[/tex] - Mass of the block, measured in kilograms.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

Now we proceed to solve the system of equation for the kinetic coefficient of friction between box and floor:

By (1)

[tex]\mu_{k}\cdot N = P\cdot \cos \theta -m\cdot a[/tex]

[tex]\mu_{k} = \frac{P\cdot \cos \theta - m\cdot a}{N}[/tex]

By (2)

[tex]N = m\cdot g +P\cdot \sin \theta[/tex]

And then, we get the resulting expression:

[tex]\mu_{k} = \frac{P\cdot \cos \theta - m\cdot a}{m\cdot g + P\cdot \sin \theta}[/tex] (3)

If we know that [tex]P = 400\,N[/tex], [tex]\theta = 50^{\circ}[/tex], [tex]m = 25\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]a = 0.5\,\frac{m}{s^{2}}[/tex], then the kinetic coefficient of friction between box and floor is:

[tex]\mu_{k} = \frac{(400\,N)\cdot \cos 50^{\circ}-(25\,kg)\cdot \left(0.5\,\frac{m}{s^{2}} \right)}{(25\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)+(400\,N)\cdot \sin 50^{\circ}}[/tex]

[tex]\mu_{k} = 0.443[/tex]

The kinetic coefficient of friction between box and floor is 0.443.

The kinetic coefficient of friction between box and floor is 0.443.It is the ratio of friction force and the normal recation force.

It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N).

Mathematically it is defined as the product of the coefficient of friction and normal reaction.

The given data in the problem is;

F is the force =400 N

m is the mass of box= 25-kg

u is the velocity starting from rest=0

v is the velocity achieved = 2.0 m/s

t is the time = 4.0 s.

[tex]\rm \mu[/tex] is  the coefficient of kinetic friction between box and floor.

The aceleration is found as;

[tex]\rm a= \frac{v_f-v_u}{t} \\\\ \rm a= \frac{2-0}{4} \\\\ \rm a= 0.5 m/sec^2[/tex]

The normal reaction force is find as;

[tex]N= mg +P sin \theta[/tex]

The cofficient of the kinetic coefficient of friction between box and floor;

[tex]\rm \mu_k = \frac{Pcos \theta - ma }{N } \\\\ \rm \mu_k = \frac{Pcos \theta - ma }{ mg +P sin \theta } \\\\ \rm \mu_k = \frac{400 cos 50^0 - 25 \times 0.5 }{ 25 \times 9.81 +400 \times sin 50^0 } \\\\ \rm \mu_k =0.443[/tex]

Hence he kinetic coefficient of friction between box and floor is 0.443.

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Answer:

5000 m³

Explanation:

density = mass / volume

mass = density × volume

mass = 1000 × 5

mass = 5000 ( kg )

Explanation:

[tex]advantage[/tex]

It is Sensitivity to surface defects. ...

[tex]disadvantage[/tex]

There is a major heat loss during cycling eddy currents due to friction in the magnetic circuit, especially where the core is saturated

Please mark as brainliest answer

Answer:

120V

Explanation:

Given parameters:

Current  = 6A

Resistance  = 20Ω

Unknown:

Voltage = ?

Solution:

According to ohms law;

           V = IR

Where V is the voltage

            I is the current

            R is the resistance

Now, insert the parameters and solve;

    V  = 6 x 20  = 120V

Explanation:

The beat is a word used for sound waves. The beat frequency is the difference in frequency of two waves. ... In sound, we hear said beat frequency as the rate at which the loudness of the sound varies whereas we hear the ordinary frequency of the waves as the pitch of the sound.

Explanation:

Beats :--

A wave not only travels in space but it also propagates through time, so if the two waves can produce interference by overlapping in space they should also produce an interference pattern when they overlap in time, this phenomenon is called beats.

Beat Frequency :--

The beat frequency is when two sound waves with different frequencies come across each other, then their amplitude gets added and subtracted alternatively for a given time period. This leads to the growth of the sound to louder and softer.

Answer:

length=2

Explanation:

You simply find the zeros of the quartic polynomial

The factored form is (x+1)(x-5)(x-2)=0

The zeros become -1,5 and 2

Dimension 5 is already given and the question says length>width and 2>-1

Therefore length=2

Answer:

210 m/s

Explanation:

We will use this equation for an elastic collision:

In this case, m₁ = mass of golf ball (0.046 kg) and m₂ = mass of the golf club (0.22 kg).

v₁ is 0 m/s since the ball is at rest on the tee.

v₂ is 44 m/s, given in the problem.

v₁ is what we are trying to find.

v₂ is 0 m/s since the ball will be at rest on the ground.

Plug these values into the elastic collision equation:

Simplify this equation.

Get rid of the units.

Multiply the left side of the equation.

Divide both sides by 0.046.

The speed of the ball when it leaves the tee is about 210 m/s.

Answer:

B.

Explanation:

Intrusive and extrusive rocks are igneous rocks and marble is metamorphic, by the process of elimination, B would be the correct answer.

Answer:

answer is B

Explanation:

Answer:

Quantity with direction and magnitude

Displacement

Explanation:

The correct options that describe the physical properties of matter are "A substance's resistance to flow," and "A substance's ability to conduct electricity." The correct options are B and C.

Physical properties of matter are characteristics that can be observed or measured without changing the substance's identity. These properties can help us identify and classify different substances.

Here in the Question,

Let's consider each option one by one:

A. A substance's pH is a chemical property of matter, which indicates whether a substance is acidic, neutral, or basic. It depends on the substance's chemical composition and the concentration of hydrogen ions in it. Therefore, this option is not a physical property.

B. A substance's resistance to flow is a physical property, also known as viscosity. It refers to how easily a substance can flow or be poured. For example, honey has a high viscosity, while water has a low viscosity. This property depends on the intermolecular forces between the molecules of the substance, which affect how closely they pack together. Therefore, this option is a physical property.

C. A substance's ability to conduct electricity is a physical property that depends on its structure and the presence of charged particles, such as ions or electrons. Substances that can conduct electricity are called conductors, while those that cannot are called insulators. Metals are good conductors of electricity, while plastics are good insulators. Therefore, this option is also a physical property.

D. Whether a substance rusts is a chemical property that indicates how a substance reacts with other substances, specifically with oxygen. Rusting occurs when iron or steel reacts with oxygen in the presence of water, forming a reddish-brown compound called iron oxide. Therefore, this option is not a physical property.

E. A substance's inability to combine with other substances is also a chemical property that depends on the substance's reactivity. Inability to combine with other substances may be due to a substance's stable electronic configuration, such as noble gases. Therefore, this option is also not a physical property.

Therefore, options B and C are true.

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Answer:

If lone pairs of electrons, electrons not bonded to other atoms, are located in the molecule, this will change the molecular geometry, not the electron geometry. If all the electron groups are bonded, with no lone pairs, then the electron geometry and molecular geometry are the same.

Answer: The plasma membrane is called a selectively permeable membrane as it permits the movement of only certain molecules in and out of the cells. Not all molecules are free to diffuse. If plasma membrane ruptures or breaks down then molecules of some substances will freely move in and out of the cells. Semipermeable membrane describes a membrane that allows some particles to pass through (by size), whereas the selectively permeable membrane "chooses" what passes through (size is not a factor). Selective permeability is a property of cellular membranes that only allows certain molecules to enter or exit the cell. This is important for the cell to maintain its internal order irrespective of the changes to the environment. For example, water, ions, glucose and carbon dioxide may need to be imported or exported from the cell depending on its metabolic activity. Similarly, signaling molecules may need to enter the cell and proteins may need to be released into the extracellular matrix. The presence of a selectively permeable membrane allows the cell to exercise control over the quantum, timing and rate of movement of these molecules.

Explanation: hope this helps you with your work/assingment! Have a wonderful day/night!

Answer:

1306.67 s

Explanation:

From the question given above, the following data were obtained:

Volume of water = 70 L

Power (W) = 18000 w

Specific heat capacity (C) = 4200 J/g℃

Initial temperature (T1) = 20 ℃

Final temperature (T2) = 100 ℃

Time (t) =?

Next, we shall determine the mass of the water. This can be obtained by converting 70 L to kg. This is illustrated below:

1 L = 1 kg

Therefore,

70 L = 70 Kg

Thus, the mass of the water is 70 kg.

Next, we shall determine the heat energy involved. This is can be obtained as follow:

Mass (M) of water = 70 Kg

Specific heat capacity (C) = 4200 J/g℃

Initial temperature (T1) = 20 ℃

Final temperature (T2) = 100 ℃

Heat Energy (Q) =?

Q = MC(T2 – T1)

Q = 70 × 4200 × (100 – 20)

Q = 294000 × 80

Q = 3520000 J

Thus, the heat energy involved is 3520000 J

Finally, we shall determine the time taken.

Power (W) = 18000 w

Heat Energy (Q) = 3520000 J

Time (t) =?

Power = energy / time

18000 = 3520000 / time

Cross multiply

18000 × time = 3520000

Divide both side by 18000

Time = 3520000 / 18000

Time = 1306.67 s

Answer:

15 cm

Explanation:

Dari pertanyaan yang diberikan di atas, diperoleh data sebagai berikut:

Gaya 1 (F₁) = 225 N

Jarak terpisah 1 (d) = 5 cm

Gaya 2 (F₂) = 25 N

Jarak terpisah 2 (d₂) =?

Kita dapat memperoleh persamaan yang berkaitan dengan gaya dan jarak muatan dua titik dengan menggunakan rumus berikut:

F = Kq₁q₂ / d²

Perbanyak silang

Fd² = Kq₁q₂

Menjaga Kq₁q₂ konstan, kita memiliki:

F₁d₁² = F₂d₂²

Dengan rumus di atas maka diperoleh jarak sebagai berikut:

Gaya 1 (F₁) = 225 N

Jarak terpisah 1 (d) = 5 cm

Gaya 2 (F₂) = 25 N

Jarak terpisah 2 (d₂) =?

F₁d₁² = F₂d₂²

225 × 5² = 25 × d₂²

225 × 25 = 25 × d₂²

5625 = 25 × d₂²

Bagilah kedua sisinya dengan 25

d₂² = 5625/25

d₂² = 225

Hitung akar kuadrat dari kedua sisi

d₂ = √225

d₂ = 15 cm

Oleh karena itu, muatan dua titik harus berjarak 15 cm untuk memiliki gaya tarik 25 N

Answer:

I'm thinking Newton's first law of motion.

Explanation:

"An object at rest remains at rest, or if in motion, remains in motion at a constant velocity unless acted on by a net external force."

Answer:Moon phases are determined by the relative positions of the Moon, Earth, and Sun.

Explanation:

Instead, the Moon's phase depends only on its position relative to Earth and the Sun. The Moon doesn't make its own light, it just reflects the Sun's light as all the planets do.

Answer:

The maximum height it reaches will be 20 m.

The time taken by it to reach the height will be: t = 2 seconds.

Explanation:

We know the equation of the motion under gravity

v² - u² = 2gs

u = initial velocity = 20 m/s

v = final velocity = 0 m/s

[tex]s\:=\:h_{max}[/tex]

so

[tex]v^{2} \:-\:u^{2} \:=\:2gs[/tex]

substituting u = 20 m/s, v = 0 m/s, g = -10 and [tex]s\:=\:h_{max}[/tex]

[tex]\left(0\right)^2-\:\left(20\right)^2=\:2\left(-10\right)\times h_{max}[/tex]

[tex]2\left(-10\right)\times h_{max}=-400[/tex]

[tex]\frac{2\left(-10\right)h_{max}}{-20}=\frac{-400}{-20}[/tex]

[tex]\:h_{max}=20[/tex] m

Therefore, the maximum height it reaches will be 20 m.

We know the equation

u = gt

substitute u = 20, g = 10

20 = 10 × t

t = 20/10

t = 2 seconds

Therefore, the time taken by it to reach the height will be: t = 2 seconds.

Answer:

[tex]\theta=\tan^{-1}\dfrac{a}{g}[/tex]

Explanation:

Here we are assuming that the car is moving in a straight line and is traveling on a smooth surface. When the car is moving with acceleration [tex]a[/tex] the bob moves in the opposite direction with the same acceleration. Gravity is acting on the bob so it is experiencing an acceleration of [tex]g[/tex] downwards.

The angle between the acceleration [tex]a[/tex] and the acceleration due to gravity [tex]g[/tex] is

[tex]\theta=\tan^{-1}\dfrac{a}{g}[/tex].

Answer:

The rate of heat transfer of the second object is greater than the first object.

Explanation:

[tex]\varepsilon[/tex] = Emissivity of the object

[tex]\sigma[/tex] = Stefan-Boltzmann constant = [tex]5.67\times 10^{-8}\ \text{W/m}^2/\text{K}^4[/tex]

[tex]T_1[/tex] = Temperature of surface 1 = [tex]25^{\circ}\text{C}+273.15=298.15\ \text{K}[/tex]

[tex]T_2[/tex] = Temperature of surface 2 = [tex]40^{\circ}\text{C}+273.15=313.15\ \text{K}[/tex]

[tex]T_0[/tex] = Surrounding temperature = [tex]25^{\circ}\text{C}+273.15=298.15\ \text{K}[/tex]

Rate of heat transfer is given by

[tex]P_1=\varepsilon \sigma (T_1^4-T_0^4)\\\Rightarrow P_1=\varepsilon \sigma A_1(298.15^4-298.15^4)\\\Rightarrow P_1=0\ \text{W}[/tex]

[tex]P_2=\varepsilon \sigma (T_2^4-T_0^4)\\\Rightarrow P_2=\varepsilon 5.67\times10^{-8} A_2(313.15^4-298.15^4)\\\Rightarrow P_2=\varepsilon A_297.2[/tex]

[tex]\varepsilon A_297.2>0[/tex]

So, [tex]P_2>P_1[/tex]

Hence, the rate of heat transfer of the second object is greater than the first object.

Answer:

20metere

Answer:

Dr Hutson is the author of several books among them: John Adams and the Diplomacy of the American Revolution (1980); winner of the Gilbert Chinard Prize, 1981; To Make All Laws: The Congress of the United States, 1789-1989 (Washington and Boston, 1989-90; 4th edition, Washington, 1990); The Sister Republics

Answer:

Dr Hutson is the author of several books among them: John Adams and the Diplomacy of the American Revolution (1980); winner of the Gilbert Chinard Prize, 1981; To Make All Laws: The Congress of the United States, 1789-1989 (Washington and Boston, 1989-90; 4th edition, Washington, 1990); The Sister Republics: ... Explanation: HOPE I HELPED!!!!!

Answer:

kinetic and potential energy). The opposite is true when you remove thermal energy: Particles move slower (less kinetic energy). Particles get closer together (less potential energy)

Answer:

Explanation:

kinetic and potential energy). The opposite is true when you remove thermal energy: Particles move slower (less kinetic energy). Particles get closer together (less potential energy).

Does this make sense??-

Answer:

45C in a minute is

45/60 C in a second

.75 C in a second is 3/4 of an ampere.

Explanation:

The current through a circuit when it takes one minute for 45C of charge to pass to a point in an electric circuit is 0.75 Ampere.

The electric circuit: a way for current to travel. A battery or generator is a device that provides energy to the charged particles that make up the current, a device that uses current, such as a lamp, an electric motor, or a computer, and the connecting wires or transmission lines to make up an electric circuit. Ohm's law and Kirchhoff's rules are two fundamental laws that quantitatively define how electric circuits function.

Given information,

The charge, q = 45 coulombs,

the time, t =1 minute

t = 60 sec

A minute at 45C is, In one second, 45/60 C,3/4 of an ampere is equal to 0.75 C per second.

Therefore, the current through a circuit when it takes one minute for 45C of charge to pass to a point in an electric circuit is 0.75 Ampere.

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Answer:  c or b

Explanation: