A black widow spider hangs motionless from a web that extends vertically from the ceiling above. If the spider has a mass of 1.27 g, what is the tension in the web

Answer:

The value of 96,745 joules in Btus is 91.6965673 or 91.7 Btus.

Explanation:

Btus stands for British thermal unit. It is the unit of energy. 96,745 Joules is equal to 91.7 Btus of energy.

Energy is the quantitative property of an object which is transferred to an object or to a physical system, that is recognizable in the performance of the work done and in the form of heat and light generated by the object or system. Energy is a conserved quantity, according to the law of conservation of energy which states that energy can be transformed, but not created or destroyed.

A British thermal unit (Btu) is a measure of the heat content or energy of fuels or energy sources. 1 BTU is roughly equal to the amount of energy which is required to raise the temperature of one pound of water by 1 degree Fahrenheit.

1 Joule = 0.000947817 Btu

Therefore, 96,745 Joules = 91.696 or 91.7 Btus

The value of 96,745 joules in Btus is 91.6965673 or 91.7 Btus.

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Answer:

d

Explanation:

Answer:

The value of a is 5 and b is -4.

Explanation:

You have to solve it by comparison :

(8 , 3) + (b , 2) = (4 , a)

(8+b , 3+2) = (4 , a)

8 + b = 4

b = 4 - 8

b = -4

3 + 2 = a

a = 5

Explanation:

Track and Field is a sport, which is includes disciplines of running, jumping, and throwing events. The sport traces back to Ancient Greece. The first recorded examples of this sport were at the Ancient Greek Olympics. In Ancient Greece, only one event was contested, the stadion footrace. Later on, the game expanded to more events.Events of track and field are divided into three: track events, field events, and combined events. Track events consist of Sprints, middle-distance, long distance, hurdles and relays; Field events consist of jumps and throws; while combined events consist of pentathlon, heptathlon, and decathlon. Track and field is usually played outdoors in stadiums. The usual features of a track and field stadium are the outer running track, and the field within the track

Answer:

Acceleration: -9.8 m/s^2

Velocity: -28.2 m/s

Displacement: 143.1 m

Explanation:

The acceleration of gravity for any object close to earth is approximately -9.8 m/s^2.

Now, to find the velocity after 9 seconds, we can use a kinematics formula, where x is the final velocity:

Final Velocity = Initial Velocity + Acceleration * Time

x = 60 + -9.8*9

x = 60 - 88.2

x = -28.2

The velocity is -28.2 m/s.

Lastly, to find the displacement, we can use another kinematics formula, where y is the displacement:

Displacement = (Final Velocity + Initial Velocity)/2 * Time

y = (-28.2 + 60)/2 * 9

y = 143.1

The displacement is 143.1 meters.

Answer:

10 seconds a mile. D. 10 s

Explanation:

25-24.6= .4

To find how long she will take to move 4 m relative to the train, take the distance she wants to travel divided by her velocity relative to the train.

4 / .4 = 10

Hope this helps you! :)

Answer:

10s

Explanation:

Answer:

a

 [tex]\frac{d \phi_{E}}{dt} =1.1977 *10^{10} \ V\cdot m/s[/tex]

b

 [tex]I = 0.106 \ A[/tex]

Explanation:

From the question we are told that

  The current is  [tex]I = 0.106 \ A[/tex]

   The length of one side of the square [tex]a = 4.60 \ cm = 0.046 \ m[/tex]

    The separation between the plate is  [tex]d = 4.0 mm = 0.004 \ m[/tex]

Generally electric flux is mathematically represented as

       [tex]\phi_E = \frac{Q}{\epsilon_o}[/tex]

differentiating both sides with respect to t is  

       [tex]\frac{d \phi_{E}}{dt} = \frac{1}{\epsilon_o} * \frac{d Q}{ dt}[/tex]

=>     [tex]\frac{d \phi_{E}}{dt} = \frac{1}{\epsilon_o} *I[/tex]

Here [tex]\epsilon_o[/tex] is the permitivity of free space with value  

        [tex]\epsilon _o = 8.85*10^{-12} C/(V \cdot m)[/tex]

=>   [tex]\frac{d \phi_{E}}{dt} = \frac{0.106}{8.85*10^{-12}}[/tex]

=>   [tex]\frac{d \phi_{E}}{dt} =1.1977 *10^{10} \ V\cdot m/s[/tex]

Generally the displacement current between the plates in A

    [tex]I = 8.85*10^{-12} * 1.1977 *10^{10}[/tex]

=>  [tex]I = 0.106 \ A[/tex]

Answer:

Its color

Explanation: I got it right

Answer:

induced electromotive force (Voltage)    E = - N dΦ / dt

Explanation:

When the magnetic flux this coil induces a current in each turn of the coil, which is why an induced electromotive force (Voltage) appears at the ends of the coil.

This phenomenon is fully explained by Faraday's law

        E = - dΦ / dt

where in the case of a coil with N turns of has

        E = - N dΦ / dt

Rl flux is the product of the normal to the area by the magnetic field, in this case the flux changes so we can assume that the area of ​​the coil is constant

Complete Question

The complete question is shown on the first uploaded image

Answer:

The value is [tex]|v| = 6.93[/tex]

Explanation:

From the question we are told that

    The initial point is [tex](x_1 , y_1 , z_1 ) = (-1 , 7 , 4 )[/tex]

    The  terminal point is  [tex](x_2 , y_2 , z_2) = (-5 , 11, 8 )[/tex]

Generally the magnitude of the vector is mathematically represented as

     [tex]|v| = \sqrt{(x_2 -x_1 )^2 + (y_2 - y_1 )^2 + (z_2 -z_1)^2}[/tex]

=>   [tex]|v| = \sqrt{(-5 -(-1) )^2 + (11 - 7 )^2 + (8 -4)^2}[/tex]

=>   [tex]|v| = 6.93[/tex]

Answer:

one time i was one the flat ground at my aunts house then we went on a hike so i brought my bike it had just rained that day so it was kinda muddy so there was sticks everywhere.i was riding up hill and noticed that it was very hard,then i rode down hill and it was much better

Explanation:

Answer:

125 m

Explanation:

m = 3kg

v = 50m/s

u = 0m/s

a = +g = 10m/s²

s = H = ?

using the formula,

v² = u² + 2as

50² = 0² + 2(10)(H)

2500 = 20H

H = 2500/20

H = 125m

Answer:

The astronaut is moving at a speed of 0.238 m/s in a direction opposite the direction of the water shot out.

Explanation:

We are given;

Mass of astronaut; m1 = 84 kg

Mass of water shoot out; m2 = 2 kg

Initial speed of astronaut; u1 = 0 m/s

Initial speed of water shoot out; u2 = 0 m/s

Final speed of shoot out; v2 = 10 m/s

From law of conservation of momentum, we can say that;

Initial momentum = final momentum

Thus;

m1•u1 + m2•u2 = m1•v1 + m2•v2

Where v1 is the final speed of the astronaut

Plugging in the relevant values, we get;

(84 × 0) + (2 × 0) = (84 × v1) + (2 × 10)

0 = 84v1 + 20

-20 = 84v1

v1 = -20/84

v1 = -0.238 m/s

The negative sign indicates that the astronaut is moving 0.238 m/s in a direction opposite the direction of the water shot out.

Let H and D denote the height and diameter, respectively, of cylinder P, and h and d the height and diameter of cylinder Q.

Then the volumes of P and D, denoted V and v, respectively, are

V = π (D / 2)² H = π D ² H / 4

v = π (d / 2)² h = π d ² h / 4

The height of P is twice the height of Q, so H = 2h.

The diameter of P is half the diameter of Q, so D = d / 2.

Substitute these into equation for the volume of cylinder P:

V = π (d / 2)² (2h) / 4

V = π (d ² / 4) (2h) / 4

V = π d ² h / 8

V = 1/2 • π d ² h / 4

V = v / 2

That is, cylinder P has half the volume of cylinder Q.

Recall that density is equal to mass per unit of volume. So R and ρ, the respective densities of cylinders P and Q, are

R = m / V = m / (v / 2) = 2 m / v

ρ = m / v

which means cylinder P has twice the density of cylinder Q (assuming both cylinders have the same mass m).

Answer:

Explanation:

When discussing Newton's laws of motion, the most likely used terms when talking about Newton's third law of motion are action and reaction. According to this law, for every action there is an equal and opposite reaction

Answer: C. "action" and "reaction"

Explanation: Newtons 3rd law of motion: for every action, there is an equal and opposite reaction (action and reaction forces are described by this law).

Have a nice day. :)

Answer:

They both hit the ground at the same time.

Explanation:

if you drop a 100 g and 200 g mass simultaneously from the same height they’ll hit the ground at the same time.

Yes, there is a role of a very simple equation of kinematics i.e.

s=ut+1/2(at^2)

so, s means the height is the same for both masses(h), u(initial velocity) is obviously zero cause you are dropping it, a (acceleration) is due to the gravity here only ‘g’.

time is taken for a particular object to hit the ground,

t= (2h/g)^1/2 .

We can see that there is no term for the mass of objects, meanwhile, the mass of the object has nothing to do with the time taken in hitting the ground in this case.

Answer:

θ₁ = 5.4°

θ₂ = 10.86°

Explanation:

The angle ca be found by using grating equation:

mλ = d Sinθ

where,

m = order of diffraction

λ = wavelength = 405.3 nm = 4.053 x 10⁻⁷ m

d = grating element = 1/230 lines/mm = 0.0043 mm/line = 4.3 x 10⁻⁶ m/line

θ = angle = ?

FOR m = 1:

(1)(4.053 x 10⁻⁷ m) = (4.3 x 10⁻⁶ m/line) Sin θ₁

Sin θ₁ = 0.09425

θ₁ = Sin⁻¹(0.09425)

θ₁ = 5.4°

FOR m = 2:

(2)(4.053 x 10⁻⁷ m) = (4.3 x 10⁻⁶ m/line) Sin θ₁

Sin θ₂ = 0.1885

θ₂ = Sin⁻¹(0.1885)

θ₂ = 10.86°

Answer:

Explanation:

reading of scale = reaction force of surface R

centripetal force = R - mg = m v² / R , m is mass , v is velocity and R is radius of the circular path .

R = mg + m v² / R

given ,

m v² / R = .80 mg

v² = .80 x g x R

= .8 x 9.8 x 9 = 70.56

v = 8.4 m /s

Answer:

The right approach will be "1.3". A further explanation is given below.

Explanation:

As we know,

In Decibels, the change in sound volume will be:

= [tex]10log\frac{I_1}{I_2}[/tex]

Now,

According to the question,

⇒ [tex]1=10 log \frac{I_1}{I_2}[/tex]

By applying cross multiplication and putting the value of log, we get

⇒ [tex]10^{\frac{1}{10} }=\frac{I_1}{I_2}[/tex]

⇒ [tex]1.26=\frac{I_1}{I_2}[/tex]

⇒ [tex]\frac{I_1}{I_2}=1.3[/tex]

Answer:

F = 93.49 × 10^(-9) N

Explanation:

We are given;

Length of rectangle; a = 1.1 m

Width of rectangle; b = 0.9 m

Charge on rectangle; q = 2.3 × 10^(-9) C

Formula for force is;

F = kq²/r²

Where;

k is a constant = 8.99 x 10^(9) N.m²/C²

a) on the width side, we have;

F = [8.99 x 10^(9) × (2.3 × 10^(-9))²]/0.9²

F = 58.79 × 10^(-9) N

This is on the y-axis

b) on the length side, we have;

F = [8.99 x 10^(9) × (2.3 × 10^(-9))²]/1.1²

F = 39.3 × 10^(-9) N

This is on the x-axis

C) using pythagoras theorem, for the diagonal side, we have c² = a² + b².

Thus;

F = [8.99 x 10^(9) × (2.3 × 10^(-9))²]/(1.1² + 0.9²)

F = 23.54 × 10^(-9) N

Using trigonometric ratios, we can find the angle θ.

tan θ = b/a

tan θ = 0.9/1.1

tan θ = 0.8182

θ = tan^(-1) 0.8182

θ = 39.29°

Resolving along x and y axis, we have;

F_x = 23.54 × 10^(-9) × cos 39.29°

F_x = 18.22 × 10^(-9) N

F_y = 23.54 × 10^(-9) × sin 39.29°

F_y = 14.91 × 10^(-9) N

Resultant force will be;

F = √((Σf_x)² + (ΣF_y)²)

F = √[(18.22 × 10^(-9)) + (39.3 × 10^(-9))]² + [(14.91 × 10^(-9)) + (58.79 × 10^(-9))²]

F = √[(33.0855 × 10^(-16)) + (54.317 × 10^(-16))]

F = 93.49 × 10^(-9) N

Answer:

Explanation:

separation between slit d = 1.2 x 10⁻⁴ m

distance of screed D = 3.5 m

distance of second order right fringe

= 2λD / d where λ is wavelength of light .

2λD / d  = .0375

2 x λ x 3.5 / 1.2 x 10⁻⁴ = .0375

λ = 6428 x 10⁻¹⁰ m

= 643 nm .

Answer:

0.2Nm

Explanation:

F1 = 30.0N

F2 = 20.0N

R = 2.0cm = 0.02m

F1R1 - F2R2 = net Torque

30(0.02) - 20(0.02) = net Torque

0.6-0.4 = net Torque

Therefore net Torque = 0.2Nm

The figure below shows two forces [tex]F_1[/tex] = 30.0 N and [tex]F_2[/tex] = 20.0 N acting on an object that can rotate around a centre axle. The net torque in 0.2 N-m

The force that can cause an object to rotate along an axis is measured as torque. Similar to how force accelerates an item in linear kinematics, torque accelerates an object in an angular direction. A vector quantity is a torque.

Torque is defined as Γ=r×F=r F sin(θ). In other words, torque is the cross product of the force vector, where 'a' is the angle between r and F, and the distance vector (the distance between the pivot point and the place where force is applied).

Torque due to [tex]F_1[/tex] = 30.0 N is 0.6 N-m outside the plane and due to   [tex]F_2[/tex] = 20.0 N is 0.4 N-m inside the plane so net torque is 0.2 N-m outside the plane.

The figure below shows two forces [tex]F_1[/tex] = 30.0 N and  [tex]F_2[/tex] = 20.0 N acting on an object that can rotate around a centre axle. The net torque in 0.2 N-m outside the plane.

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Answer:

2.1 rad/s

Explanation:

Given that,

Mass of a tether ball, m = 0.546 kg

Length of a rope, l =  4.56 m

The maximum tension the rope can withstand before breaking is 11.0 N

We need to find the maximum angular speed of the ball. Let v is the linear velocity. The maximum tension is balanced by the centripetal force acting on it. It can be given by :

[tex]F=\dfrac{mv^2}{r}\\\\v=\sqrt{\dfrac{Fr}{m}} \\\\v=\sqrt{\dfrac{11\times 4.56}{0.546}} \\\\=9.584\ m/s[/tex]

Let [tex]\omega[/tex] is the angular speed of the ball. The relation between the angular speed and angular velocity is given by :

[tex]v=r\omega\\\\\omega=\dfrac{v}{r}\\\\=\dfrac{9.584}{4.56}\\\\=2.1\ rad/s[/tex]

So, the maximum angular speed of the ball is 2.1 rad/s.

Answer:

a = 2.94 m/s²

Explanation:

In order for the cup not to slip, the unbalanced force on cup must be equal to the frictional force:

Unbalanced Force = Frictional Force

ma = μR = μW

ma = μmg

a = μg

where,

a = maximum acceleration for the cup not to slip = ?

μ = coefficient of static friction = 0.3

g = acceleration due to gravity = 9.8 m/s²

Therefore,

a = (0.3)(9.8 m/s²)

a = 2.94 m/s²

Answer: C. Body fat percentage

Explanation:

Answer:

your answer is C

Explanation:

Answer:

B

Explanation:

Answer:

B.)Static

Hope I helped

Answer:

69

Explanation:

Answer: The displacement is 18.8 meters.

Explanation:

Let's define the North as the positive y-axis and the East as the positive x-axis.

We also can assume that if the point (x, y) represents the position of the boy, the initial position is (0 paces, 0 paces).

"A boy on a treasure hunt walks 12 paces West,"

West would be the negative x-axis in this case, then:

the position will be (-12 paces, 0 paces)

"then 21 paces North"

Now the position will be (-12 paces, 21 paces)

"then 25 paces East."

Now the position will be (-12 paces + 25 paces, 21 paces)

                                       = (13 paces, 21 paces)

Now we have the initial and final positions of the boy,  (0 paces, 0 paces) and (13 paces, 21 paces) respectively.

We want to find the displacement, which is defined as the distance between the final position and the initial position.

Remember that for two vectors (a, b) and (c, d), the distance is:

D = √( (a - c)^2 + (b  - d)^2)

In this case, the displacement will be:

D = √( ( 13 paces - 0 paces)^2 + (21 paces - 0 paces)^2) = 24.7 paces.

But we want this quantity in meters, so we can use the relation:

1 pace = 0.762 meters.

Then 24.7 paces, are 24.7 times 0.762 meters.

D = 24.7*0.762 m = 18.8 meters.

Answer:

Question 1 the answer is 5 cm for the one pulley system, I just took the quiz

Question 2 is 10 cm

Explanation:

The rope only needs to move 5 cm for the mass to move from 15 to 20.

For the 2 pulley system the string has to move twice as far making it 10 cm. I took the quiz and got 100%