A binary star system that is detected from the drop in luminosity as one star passes in front of the other is called ___________.

•Question⟿What is meant by solenoid?

•Answer⟿If a conducting wire is wound in form of a cylindrical coil whose diameter is less in comparison to its length, the coil is called a solenoid. It looks like a helical spring.

•Question⟿How does a current carrying solenoid behave?

•Answer⟿

Explanation:

current carrying solenoid behaves as an electromagnet. The uniform magnetic field inside it may magnetise a steel rod permanently. Detailed Answer: A coil of many circular turns of insulated copper wire wrapped closely in the shape of a cylinder is called a Solenoid.

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Answer:

the pressure will be 297.01 kpa

Answer:

helium and hydrogen

Explanation:

Answer:

Potential -> Kinetic -> Potential ->

Explanation:

Point A is potential becuase it's stopped (its energy isn't released). Point B is where that potential energy is released and turned into Kinetic energy. And point C is where potential energy is stored again. Same with point D.

Horizontal component of ball, u = 0 m/s.

Height from which it thrown, h = 62 m.

By equation of motion :

[tex]s=ut+\dfrac{at^2}{2}[/tex]

Putting all given equation, we get :

[tex]62=0\times t+\dfrac{10t^2}{2}\\\\t=\sqrt{12.4}\ s\\\\t = 3.52\ s[/tex]

Therefore, time taken is 3.52 s.

Hence, this is the required solution.

Answer:

The total current in the circuit is the current that travels thru a single conductor that connects to the parallel circuit (current from a electromotive source, etc.)

I = I1 + I2 + I3 ...... In

If n items are in parallel with another, then I is the total current passing thru these items

Answer:

-273.15 celcius

−218.52 Réaumur

Explanation:

273. 15 kelvin = 0 degrees celcius

C + 273.15 =k

08. Degrees celcius = 1 Réaumur

C x 0.8 = rea

Answer: joule, unit of work or energy in the International System of Units (SI); it is equal to the work done by a force of one newton acting through one metre.

Explanation:

This is a unit used to measure energy or work. One joule is the amount of energy required to produce one watt of power for one second. It's also the work done by a force equal to one newton exerted over a distance of one meter.

Hope this helps!

Answer:

sum of the kinetic and potential energy

Explanation:

For an accurate design of the pendulum that will match the period, the length of the pendulum clock must be 0.25 m.

The period of oscillation of simple pendulum is calculated as follows;

[tex]T = 2\pi \sqrt{\frac{l}{g} }[/tex]

where;

Make "L" the subject of the formula in the above equation.

[tex]\frac{T}{2\pi} = \sqrt{\frac{l}{g }} \\\\\frac{T^2}{4\pi^2} = \frac{l}{g} \\\\l = \frac{gT^2}{4\pi ^2} \\\\l = \frac{(9.8)(1)^2}{4\pi ^2} \\\\l = 0.25 \ m[/tex]

Thus, the length of the pendulum clock is 0.25 m.

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Answer:

[tex]a=155.750\ m/s^2[/tex]

Explanation:

It is given that,

A small rock is shoot at Dennis' neighbor's flowerpots. The rock travels a distance of 12.5 cm from the point at which he pulls it back to the point at which it leaves the slingshot.

Final velocity of the rock, v = 6.24 m/s

The initial velocity of the rock, u = 0 (as it was at rest)

Let a is the acceleration of the rock. It can be calculated using the equation of kinematics as follows :

[tex]v^2-u^2=2ad\\\\\text{Put u = 0 }\\\\v^2=2ad\\\\a=\dfrac{v^2}{2d}\\\\a=\dfrac{(6.24)^2}{2\times 12.5\times 10^{-2}}\\\\a=155.750\ m/s^2[/tex]

So, the average acceleration of the rock is [tex]155.750\ m/s^2[/tex].

It is shaped like a pinwheel describing a spiral galaxy. A flat, rotating disk containing stars, gas, and dust, as well as a central concentration of stars known as the bulge, makes up most spiral galaxies.

Spiral galaxies are a type of galaxy first described by Edwin Hubble are part of the Hubble sequence.

A flat, rotating disk containing stars, gas, and dust, as well as a central concentration of stars known as the bulge, makes up most spiral galaxies.

Many of these are surrounded by a fainter halo of stars, many of which are found in globular clusters.

The Pinwheel Galaxy is a spiral galaxy located approximately 21 million light-years from Earth. M101 is the name given to this swirling galaxy by scientists.

In the Northern Hemisphere, it can be found in the constellation Ursa Major, also known as the "Big Dipper." Binoculars or a small telescope can be used to see if the sky is clear and dark.

Hence it is shaped like a pinwheel describing a spiral galaxy.

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Hi there!

We know that there are TWO forces acting on the man.

We can express this in an equation. Let DOWN be NEGATIVE, and UP be POSITIVE.

[tex]F_{net} = N - F_g[/tex]

Recall that a SCALE measures the NORMAL FORCE, NOT the WEIGHT. Therefore:

N = 700 N

W = 900 N

[tex]F_{net} = 700 - 900 \\\\F_{net} = -200N[/tex]

Since downward is negative, the net force is acting DOWNWARD.

Answer:

f

Explanation:

Answer:

Explanation:

4.0/5

10

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Electrical power  =  (voltage) x (current)

Electrical energy  =  (power) x (time)

Combine those definitions:

            Energy  =  (voltage) x (current) x (time)

Divide each side by (voltage x time), and we have

            Current  =  Energy / (voltage x time)

You told us that

            Energy = 1.8 x 10⁷ joules

            Time  =  1 hour  =  3,600 seconds

so we have

            Current  =  (1.8 x 10⁷) / (voltage x 3,600).

If you live in the US, Canada, or Mexico, your voltage is 120 volts.

            Current = (1.8 x 10⁷) / (120 x 3,600)  =  41-2/3 Amperes

If you live practically anywhere else in the world, your voltage is 240 volts.

             Current = (1.8 x 10⁷) / (240 x 3,600)  =  20-5/6 Amperes.

Answer:

B. 3

Explanation:

Answer:

Hello

a) the change of velocity over time

Answer:

c.the change of velocity over distance

The acceleration is derived from the some other quantities like change in velocity / time take . If we see carefully that formula of acceleration you find that it is basically derived from fundamental quantities therefore acceleration is called a derived quantities.

A) The PBR catalyst weight that is required to achieve 80% conversion in the absence of pressure drop is : 370 mg  

B) The fluidized CSTR catalyst weight necessary to achieve 80% conversion is : 995.025 g

To calculate the PBR catalyst weight required to achieve 80% conversion in the absence of pressure drop we will apply the equation below

w = [tex]\frac{V_{o} }{KC_{ao}(1/x - 1 ) }[/tex]  ---- ( 1 )

insert values into equation ( 1 )

w = [tex]\frac{50 kmol}{0.54 * 10 (\frac{1}{0.8}) * 1 }[/tex]

PBR catalyst weight ( w ) = 370 mg

applying the equation below

W = [tex]\frac{Fbwx}{-r'Bu}[/tex]

   = [tex]\frac{50kmol/r * 0.8}{0.042mol/gcat.h}[/tex]

   = 995.025 gcat

Hence we can conclude that The PBR catalyst weight that is required to achieve 80% conversion in the absence of pressure drop is : 370 mg  The fluidized CSTR catalyst weight necessary to achieve 80% conversion is : 995.025 g.

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Try the suggested option, all the details are in the attachment.

Explanation:

1) to calculate the moles of CCl₄;

2) to calculate the moles of HF;

3) to calculate the mass of CCl₂F₂;

4) to calculate the mass of ureacted HF.

Answer:

b

Explanation:

Answer:

its b, the sun is directly over earths north end

Explanation:

Answer:

45.1 m/s

Explanation:

use the equation v = u + at  substitute the values v = 0 + 9.8×4.6  v = 45.08  round to about 3 s.f v = 45.1 m/s I do apologize if I'm incorrect.

The mass of water increases, the freezing point of water decreases. and the buoyancy of objects in the water increases may occur when the ocean sanity increases.

Seawater is salty due to a variety of substances. The majority of them arrive via rivers, which bring chemicals dissolved from rock and soil. The most common is sodium chloride, also known as salt.

The most popular approach to quantify salinity is to count the amount of salt in 1,000 g of water, which is referred to as ppt. The majority of the ocean has a salinity of 34 to 36 parts per thousand.

Salinity makes water colder and denser by lowering its temperature. The chilly water sinks to the ocean's depths. Slow currents carry it throughout the marine basins.

Because the items have a lower density, they flow across the water's surface. As a result, the buoyancy of items in water improves.

So the events that may occur when ocean salinity increases will be;

1)The mass of water increases.

2) Freezing point of water decreases.

3) buoyancy of objects in the water increases.

Hence the masses of water increase, the freezing point of water decreases. and the buoyancy of objects in the water increases may occur when the ocean sanity increases.

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The compression of 10 cm by a 100 N force on the plane that has a

coefficient of friction of 0.39 give the following values.

Mass of the block, m = 3 kg

[tex]Spring \ constant, K = \dfrac{100 \, N}{0.1 \, m} = \mathbf{ 1000\, N/m}[/tex]

Coefficient of kinetic friction, [tex]\mu_k[/tex] = 0.39

Therefore, we have;

Friction force = [tex]\mathbf{\mu_k}[/tex]·m·g·cos(θ)

Which gives;

Friction force = 0.39 × 3 × 9.81 × cos(48°) ≈ 7.68

Work done by the motion of the block, W ≈ 7.68 × d

The work done = The kinetic energy of the block, which gives;

[tex]\mathbf{\dfrac{1}{2} \times k \cdot x^2 }= 7.68 \cdot d[/tex]

The initial kinetic energy in the spring is found as follows;

K.E. = 0.5 × 1000 N/m × (0.1 m)² = 5 J

The initial velocity of the block is therefore;

5 = 0.5·m·v²

v₁ = √(2 × 5 ÷ 3) ≈ 1.83

Work done by the motion of the block, W ≈ 7.68 N × 0.07 m ≈ 0.5376 J

Chane in kinetic energy, ΔK.E. = Work done

ΔK.E. = 0.5 × 3 × (v₁² - v₂²)

Which gives;

ΔK.E. = 0.5 × 3 × (1.83² - v₂²) = 0.5376

Which gives;

The height at which the block will stop moving, h, is given as follows;

[tex]At \ the \ maximum \ height, \ h, \ we \ have ; \ \dfrac{1}{2} \times 1000 \times 0.1^2 = 7.68 \times x[/tex]

Which gives;

[tex]Length \ of \ the \ incline \ at \ maximum \ height, \ x_{max} =\dfrac{ 7.68 }{ \dfrac{1}{2} \times 1000 \times 0.1^2 } \approx 1.536[/tex]

The distance up the inclined, the block rises, at maximum height is therefore;

[tex]x_{max}[/tex] ≈ 1.536 m

Therefore;

h = 1.536 × sin(48°) ≈ 1.1415

From the above solution for the height, the length of the incline is he

distance along the incline at maximum height which is therefore;

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Answer:

Gravity, Friction, Air resistance, magnetism, static electricity

Explanation:

Answer:

gravity friction air resistant are a few

Answer:

The final velocity s 12 m/s.

For the upwards trajectory:   (using the positive value of g in the downward direction)

Vf = Vi - g t = 0   where Vi is initial velocity and Vf the velocity at max height

Vf = 12 - g t = 0      t = 12 / g     time to reach max height

For the downwards trajectory

Vf = Vi + g t = 0 + g t    =  g * 12 / g = 12  where t was found above

We know the from  2 g h = Vf^2 - Vi^2, since the height is the same in both directions, that the ball reaches the ground with at the same speed at which it was sent.

Also, conservation of energy shows that the ball must return to the ground with the speed with which was projected.

Answer:

400 m/s

Explanation:

If it is moving at a velocity of 80 m/s from rest, then after 5 s it would be at 400 m/s.

80 x 5 = 400