A balloon contains 0.118 mol of gas and has a volume of 2.58 L . If an additional 0.116 mol of gas is added to the balloon (at the same temperature and pressure), what will its final volume be? Can you also show the work so I can understand why is it that answer. thank you

Answer:

the discovery will always need to be tested more where if you're investigating you should already be in a more controlled environment

The difference between accidental discoveries and scientific investigations are as follows.

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Answer:

 Lewis structure of Hydronium ion is shown below :                          

Explanation:

Lewis structure : It is a representation of valence electrons on the atoms in a molecule

Here , Hydronium ion is given , which contains 1 atom of oxygen and 3 atoms of hydrogen .

Oxygen has a total of 6 valence electrons and hydrogen contains 1 valence electron .

Oxygen share its 3 valence electrons with 3 hydrogen atoms and left with 3 valence electrons. From these three valence  electrons of oxygen atom  two electrons will be shown as a pair of electrons on oxygen atom but a single electron can not be shown . So , to simplify this, one positive charge is shown overall .  

Resonance structure will be same as the hybrid structure because all  three atoms are same , that is hydrogen .

Answer:

A. P₂ / P₁ = 2

B. P₂ / P₁ = 1.1

Explanation:

A. Determination of the ratio P₂/P₁

Volume = constant

Initial temperature (T₁) = 46 K

Final temperature (T₂) = 92 K

Final pressure /Initial pressure (P₂/P₁) =?

P₁/T₁ = P₂/T₂

P₁/46 = P₂/92

Cross multiply

46 × P₂ = P₁ × 92

Divide both side by P₁

46 × P₂ / P₁ = 92

Divide both side by 46

P₂ / P₁ = 92 / 46

P₂ / P₁ = 2

B. Determination of the ratio P₂/P₁

Volume = constant

Initial temperature (T₁) = 35.4 °C = 35.4 + 273 = 308.4 K

Final temperature (T₂) = 69.0 °C = 69 + 273 = 342 K

Final pressure /Initial pressure (P₂/P₁) =?

P₁/T₁ = P₂/T₂

P₁/308.4 = P₂/342

Cross multiply

308.4 × P₂ = P₁ × 342

Divide both side by P₁

308.4 × P₂ / P₁ = 342

Divide both side by 308.4

P₂ / P₁ = 342 / 308.4

P₂ / P₁ = 1.1

The various factors that impact the solubility of substances in water are - nature of solute and solvent, temperature, pressure and pH.

The solubility of substances in water is influenced by several factors:

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Answer:

Towards the big bully

Explanation:

If a big bully and a small child are involved in a thug of war, it is clear that the bully is stronger than the child and he/she will pull the rope used in the thug of war with a greater force.

By so doing, the ball attached at the centre of the rope will naturally be drawn towards the stronger bully.

The equation for the energy required to melt 2 kg of gold is 3440 kJ.

Energy is the ability to do work or cause change. It is an essential part of everyday life and is present in many forms, such as thermal energy, electrical energy, chemical energy, and mechanical energy. Energy can be converted from one form to another in order to do work.

The equation for calculating the energy required to melt a certain mass of material is Q = m x Lf, where Q is the energy required (in joules), m is the mass of the material (in kilograms), and Lf is the latent heat of fusion (in joules per kilogram).
Using the table below, we can see that the latent heat of fusion for gold is 1760 kJ/kg. Therefore, the equation for the energy required to melt 2 kg of gold is: Q = 2 kg x 1760 kJ/kg = 3440 kJ.

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Answer:

n = 2.23 moles

Explanation:

Given the following data;

Standard temperature = 273 K

Standard pressure = 101.325 kPa

Volume = 50 liter

R = 8.314 J/mol·K  

To find the number of moles, we would use the ideal gas law formula;

PV = nRT

Where;

Making n the subject of formula, we have;

[tex] n = \frac {PV}{RT} [/tex]

Substituting into the formula, we have;

[tex] n = \frac {101.325*50}{8.314*273} [/tex]

[tex] n = \frac {5066.25}{2269.722} [/tex]

n = 2.23 moles

Therefore, 2.23 moles of carbon dioxide at STP will fit in a 50 liter container.

Answer:

pH = 4.71

Explanation:

We can find the pH of a buffer (Mixture of weak acid: CH3COOH, and its conjugate base: CH3COONa) using H-H equation:

pH = pKa + log [CH3COONa] / [CH3COOH]

Where pH is the pH of the buffere = 4.74, pKa the pka of the buffer and [] could be taken as the moles of each reactant.

As initially [CH3COONa] = [CH3COOH], [CH3COONa] / [CH3COOH] = 1:

pH = pKa + log 1

4.74 = pKa

To solve this question we need to find the initial moles of each species, The CH3COONa reacts with HCl to produce CH3COOH. That means the moles of CH3COOH after the reaction are: Initial CH3COOH + Moles HCl

Moles CH3COONa: Initial CH3COONa - Moles HCl.

Moles CH3COOH:

0.100L * (0.50mol / L) = 0.050 moles CH3COOH + 0.0020 moles HCl =

0.052 moles CH3COOH

Moles CH3COONa:

0.100L * (0.50mol / L) = 0.050 moles CH3COONa - 0.0020 moles HCl =

0.048 moles CH3COONa

Using H-H equation:

pH = 4.74 + log [0.048 moles] / [0.052 moles]

The pH be after 0.0020 mol of HCl has been added to 100.0 mL of the buffer is 4.71.

Buffer solution is a mixture of weak acid and its conjugate base or vice versa.

We can calculate the pH of buffer solution by using Henderson - Hasselbalch Equation:

pH = pKa + log[CH₃COONa] / [CH₃COOH]

Initially concentration of CH₃COONa is equal to the concentration of CH₃COOH and equal becomes:

4.74 = pKa + log(1)

pKa = 4.74

Given moles of added HCl moles = 0.002 mole

Given molarity of each CH₃COOH & CH₃COONa = 0.50M

Given Volume = 100mL

We can calculate the moles by using the formula:

n = M × V

Moles of CH₃COOH & CH₃COONa = 0.100 × 0.50 = 0.050 moles

Moles of CH₃COOH = 0.050moles CH₃COOH + 0.0020moles HCl =

0.052moles CH₃COOH

Moles of CH₃COONa = 0.050moles CH3COONa - 0.0020moles HCl =

0.048moles CH₃COONa

Now, resultant pH will be:

pH = 4.74 + log [0.048 moles] / [0.052 moles]

pH = 4.71

Hence, pH of resultant solution is 4.71.

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Answer:

0.203 is the mean of the concentration of the HCl solution

Explanation:

You have 5 concentrations. The most appropiate result is the mean of those results. The mean is a statistical defined as the sum of each result divided by the total amount of results. For the results of the problem, the mean is:

0.210 + 0.204 + 0.201 + 0.202 + 0.197 = 1.014 / 5 =

Answer:

1) Ra

K

Na

Li

2) Na

Mg

Al and Si

Answer:

a

Explanation:

documentary is best researcher!.

Answer:

isn't it 0.998

Explanation:

cause 0.998 is in the same grams / mole. I don't get

A calorimeter has been filled with 75 mL of water. The number of grams of water is 74.85 grams.

A calorimeter is an instrument that is used to measure calorimetry. It is used to measure the heat of chemical reactions and physical and chemical changes.

Mass is the quantity of matter in a physical body. Volume is the space occupied by a three-dimensional object. Mass is the quantity of matter in a physical body. The product of the compound's molar mass and the substance's moles are defined as mass.

Given, that the volume of the water is 75 mL

The temperature of the water is 25 °C

The density of water is 0.998 g/mL

To calculate the mass, the volume is multiplied by density.

Mass = volume x density

putting the values in the formula

75 x  0.998 = 74.85 grams

Thus, the grams of water that have at 25°C is 74.85 grams.

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Answer:

The answer is basic

Explanation:

Choose letter b or basic. You welcome.

The strong acid and strong base has high rate constant of dissociation. The rate constant for weak acid and base for the dissociation is low, they do not easily dissociate in water. Therefore option B is the correct option.

Acid is a solution which releases H⁺ hydrogen ion when dissolved in water. Base releases hydroxide ion OH⁻ ion when dissolved in water.

pH is a measurement of amount of hydronium ion H₃O⁺ in a given sample. Strength of acidic nature is directly proportional to the concentration of hydronium ion.

On subtracting pH from 14, we get pOH which measures the concentration of hydroxide ion in a given solution. Temperature affect the pH. At room temperature pH scale is between 0 to 14. 7 is the pH of neutral solution. A solution of the ionic salt NaF is basic in nature.

Therefore, option B is the correct option.

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Answer:

a hydrogen bond between the hydrogen of water and the nitrogen of the amine

a hydrogen bond between the oxygen of water and a hydrogen from the -NH2 group

Explanation:

A hydrogen bond is formed between molecules in which hydrogen is bonded to a highly electronegative element.

In amines, hydrogen is bonded to nitrogen while in water, hydrogen is bonded to oxygen. Both are highly electronegative elements hence hydrogen bonding is possible between amines and water.

This hydrogen bond may involve;

The hydrogen of water and the nitrogen of the amine

Or

The oxygen of water and a hydrogen from the -NH2 group

Answer:

55.44L of the 0.17M NaOH are required

Explanation:

Phosphoric acid, H3PO4, reacts with NaOH as follows:

H3PO4 + 3NaOH → Na3PO4 + 3H2O

Where 1 mole of H3PO4 reacts with 3 moles of NaOH

To solve this question we need to find the moles of H3PO4 in the aliquot. Using the balanced equation we can find the moles of NaOH and its volume with the concentration (0.17M) as follows:

Moles H3PO4:

15.4mL = 0.0154L * (0.204mol/L) = 0.00314 moles H3PO4

Moles NaOH:

0.00314 moles H3PO4 * (3mol NaOH / 1mol H3PO4) = 0.009425moles NaOH

Volume NaOH:

0.009425moles NaOH * (1L/0.17moles NaOH) = 0.05544L 0.17M NaOH =

Answer:

E = 8085 kJ

Explanation:

Given that,

The mass of a truck, m = 1500 kg

Height, h = 550 m

We need to find the gravitational potential energy of the truck. It can be calculated as follows :

[tex]E=mgh[/tex]

Put all the values,

[tex]E=1500\times 9.8\times 550\\\\E=8085000\ J\\\\or\\\\E=8085\ kJ[/tex]

So, the gravitational potential energy is 8085 kJ.

Answer:

Each electrode attracts ions that are of the opposite charge. Positively charged ions, or cations, move toward the electron-providing cathode, which is negative; negatively charged ions, or anions, move toward the positive anode.

Answer:

1. Its formation requires very strong updrafts = a. Hail

2. Its formation requires falling through a layer of above-freezing air = d. Freezing Rain

3. Precipitation from cumuliform clouds is typically of this nature = c. Shower

4. Precipitation from stratus clouds is typically of this nature = Drizzle

Explanation:

Hail formation requires very strong updrafts, these updrafts are the upward moving air created in a thunderstorm. This period of noticeable thunderstorms creates hails.

Freezing rain requires the presence of warm air, it requires falling through a layer of above-freezing air to the colder air below to produce an ice coating on anything it drops on.

Showers are produced by cumuliform clouds which look like cotton balls. Since cumuliform clouds precipitate too, these clouds can have fluctuating rain in a day in the form of showers.

Drizzle which raises low visibility is considered a type of liquid precipitation since it also falls from a cloud. Drizzle which is obviously smaller in diameter when compared to that of raindrops, however, is common with stratus clouds.

Answer:

2

Explanation:

The number of carbon atoms that are sp²-hybridized in this alkene is 2

Because all the single bonded carbon atoms in the alkene are  sp²-hybridized

There are three(3) single formed via sp² orbitals and one ( 1 ) PI bond formed via Pure-P-orbital

attached below is the some part of the solution

Answer:

1) Greater than zero, and equal to the rate of the reverse reaction

2) Greater than zero, but less than the rate of the reverse reaction

3) Greater than zero, and equal to the rate of the reverse reaction

Explanation:

A reaction system is said to be in equilibrium when the rate of forward reaction is equal to the rate of reverse reaction.

Before we remove HCH3CO2 from the system, the system was in equilibrium. Recall that when a system is in equilibrium, the rate of forward reaction is equal to the rate of reverse reaction. The rate of reaction is greater than zero because products are being formed as the reactants interact with each other.

When HCH3CO2 is removed from the system, the equilibrium position shifts towards the left hand side hence the rate of reverse reaction is greater than the rate of forward reaction.

When the system attains equilibrium again, the rates of forward and reverse reaction become equal.

Answer:

Qp > Kp, por lo tanto, la presión parcial de BrF₃(g) aumenta hasta alcanzar el equilibrio.

Explanation:

Paso 1: Escribir la ecuación balanceada

BrF₃ (g) ⇌ BrF(g) + F₂(g)      Kp(T) = 64,0

Paso 2: Calcular el cociente de reacción (Qp)

Qp = pBrF × pF₂ / pBrF₃

Qp = 1,50 × 2,00 / 0,0150 = 200

Paso 3: Sacar una conclusión

Dado que Qp > Kp, la reacción se desplazará hacia la izquierda para alcanzar el equilibrio, es decir, la presión parcial de BrF₃(g) aumenta hasta alcanzar el equilibrio.

Answer:

The wavelength of a microwave is LONGER than the wavelength if visible light.

0.152 moles

The mass of the oxygen gas produced = 4.87 g

Also, The molar mass of oxygen gas,  =  = 32 g/mol

The formula for the calculation of moles is shown below:

moles = [tex]\frac{Mass-taken}{Molar-mass}[/tex] *

Thus,

moles = [tex]\frac{4.87g}{32g/mol }[/tex]

Both given values and the answer is in 3 significant digits.

brainlist pls?

*i put a dash between mass and taken as formulas do no spaces

Answer:

a. the proportion of elements to compounds is constant.

Answer:

0.350 L

Explanation:

First we convert 2.18 g of Na₂O₂ into moles, using its molar mass:

Then we convert 0.0279 moles of Na₂O₂ into moles of O₂, using the stoichiometric coefficients of the reaction:

Finally we use the PV=nRT formula to calculate the volume of oxygen produced:

Inputting the data:

Answer:

a) The mechanism of the reaction is the Elimination Bimolecular or E2.

b) Steps for the mechanism of this reaction is given as follows,

c) Reaction rate = K[Organic compound][[tex]NaoCH_{2} CH_{3}[/tex]].  

Explanation:

a) The mechanism of the reaction is the Elimination Bimolecular or E2.

c) This is an E2 reaction, so it depends on the concentration of both substrate and reactant. If we increase the concentration of [tex]NaoCH_{2} CH_{3}[/tex], the reaction rate will be increased.

Reaction rate = K[Organic compound][[tex]NaoCH_{2} CH_{3}[/tex]].  

b) Steps for the mechanism of this reaction is given as follows,

Answer:

8 oxygen. 9 flourine. 10. Neon. 5 Boron

Answer: the answer is A

Explanation: add me hope i helped