Answer:
B.
Explanation:
When a ball is thrown vertically upward, the acceleration due to gravity always acts downward to the ball. When the ball is moving up the acceleration due to gravity will decrease
hope thats right!
You lift your pet cat vertically by 2.0 m, and
then you lower it vertically by 2.0 m. During this
exercise, is the total work done by gravity positive,
negative, or zero? Explain your answer.
Answer:
zero cause the positivity and negativity would cancel out
Explanation:
How is vibrational motion connected to waves?
Answer:
Explanation:
Waves and wave functions are direct ways to graph vibrational motion. Specifically, for cases dealing with vibrating strings. If you were to move a tensioned string up and down with your arm, you would produce a wave with a given frequency, period, and amplitude.
Name the angle between the refracted ray and the normal at the point of refraction,
Answer:
hiiiiiiiiiiiiiiiiii
mm
Answer:
It is called the angle of refraction
When your mass increases, your weight remains constant , True or false
I think the answer is true
which of the following would typically be used to express speed
Answer:
One term that could be used as speed is sprint or rush
Explanation:
How fast Will a brick be going after it falls for 2.5 seconds?
Answer:
25 m/s
Explanation:
Initial Velocity = 0 m/s
Time = 2.5 m/s
Acceleration due to gravity = 9.8
Final Velocity = ?
By the formula,
[tex]V_{f} = V_{i} + at[/tex]
[tex]V_{f}= 0 + 10 x 2.5[/tex]
Vf = 25 m/s
After 2.5 seconds the velocity of ball will be 24.5 m/s.
We have a brick falling from a certain height.
We have to find the velocity of the brick after 2.5 seconds of falling.
What do you mean by Free fall ?The motion of any object under the influence of gravity alone is called as free fall.
According to the question -
Initial velocity = u = 0 m/s
Final velocity = v m/s (say)
g = 9.8 m/[tex]s^{2}[/tex]
t = 2.5 seconds
Using the first equation of motion -
v = u + at
v = 0 + gt
v = 9.8 x 2.5 = 24.5 m/s
Hence, after 2.5 seconds the velocity of ball will be 24.5 m/s.
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Which solutions have a density greater than 1.0 g/mL?
Mass = 888 g Volume = 800 mL
Mass = 7.8 g Volume = 8.7 ml
Mass = 725 g Volume = 715 mL
Mass = 1.3 g Volume = 1.1 ml
Mass = 18 g Volume = 19 mL
Mass = 1.25 g Volume = 1.78 ml
The solutions that have their mass greater than their volumes are:
Mass = 888 g Volume = 800 mL Mass = 725 g Volume = 715 mL Mass = 1.3 g Volume = 1.1 mlThe ratio of the mass of a substance to its volume is known as the density of the substance. Mathematically;
Density = Mass/Volume
For any solution to have a density greater than 1, the mass of the substance must be greater than its volume.
For the given option, the solutions that have their mass greater than their volumes are:
Mass = 888 g Volume = 800 mL Mass = 725 g Volume = 715 mL Mass = 1.3 g Volume = 1.1 mlLearn more here: https://brainly.com/question/17780219
This table shows the weights of four different objects that are sitting on the floor. A person tries to lift each object with a force of 18 N, upward. Which
statement is supported by the data in the table?
Answer: A
Explanation:
The guy above me was right
Motion is caused by the forces acting on a body. A body will move in the direction of in which the net force is greater. Therefore, objects 1 and 2 will not move but 3 and 4 will accelerate upward.
From the table ; the upward force of 18N is lesser than the force maintained by the objects at rest. Hence, objects 1 and 2 will not move.
However, objects 3 and 4 have forces 16N and 8N respectively which are lesser than the upward force, hence, the body will move upward since the upward force is greater.
Therefore, objects 1 and 2 will not move but 3 and 4 will accelerate upward.
Learn more :https://brainly.com/question/20382231
How far does a car that weighs 5,000 n go
if 18,000 j of work is done on it?
Answer:
d = 3.6 m
Explanation:
The formula for Work: W = F * d
Where F is force in Newtons (N) and d is the distance travelled in meters (m). In order to do work, you need to force an object throughout a distance.
That's why pushing a wall (that doesn't move) is not considered work, because you can't move the wall to a distance.
So what we know:
F = 5,000 N
W = 18,000 J
d = W / F (according to the formula, right?)
d = 18,000 / 5,000 = 3.6 m
An Alaskan rescue plane traveling 41 m/s
drops a package of emergency rations from
a height of 165 m to a stranded party of explorers.
The acceleration of gravity is 9.8 m/s
2.What is the vertical component of the velocity
just before it hits? (Choose upward as the
positive vertical direction)
Answer in units of m/s.
Answer:
-56.9 m/s
Explanation:
Given:
Δy = -165 m
v₀ = 0 m/s
a = -9.8 m/s²
Find: v
v² = v₀² + 2aΔy
v² = (0 m/s)² + 2 (-9.8 m/s²) (-165 m)
v = -56.9 m/s
a particular eco solar system has five planets in total a b c d and e the table lists the orbital periods of these planets in days
will mark brainliest !!!
Kepler's Law (3)
T² ≈ r³
The square of the orbital period ≈ the cube the distance to the sun
The farther away the planet is, the bigger the radius, the bigger the period
A block of solid copper sits on a flat, level table. Copper has a density of 8. 94 ✕ 103 kg/m3. The mass of the block is 20. 4 kg
For a block of solid copper sits on a flat, level table. Copper has a density of 8. 94 ✕ 103 kg/m3, the volume of the block is mathematically given as
V = 2.28x10^3
What is the volume of the block (in m3)?Generally, the equation for the volume of the block is mathematically given as
V = m/p
V = 20.4/8.94x10^3
V = 0.00228
V = 2.28x10^3
In conclusion, the volume of the block is
V = 2.28x10^3
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On an average, a human heart is found to beat 75 times in a minute. Calculate its frequency and time period.
Frequency=
75/60=5/4=1.25s^{-1}Now
Time period:-
[tex]\\ \rm{:}\dashrightarrow \dfrac{1}{\nu}[/tex]
[tex]\\ \rm{:}\dashrightarrow \dfrac{1}{1.25}[/tex]
[tex]\\ \rm{:}\dashrightarrow \dfrac{4}{5}[/tex]
[tex]\\ \rm{:}\dashrightarrow 0.8s[/tex]
Which pair does NOT have an electric force between them?.
Two neutral objects will not have any electric force of attraction or repulsion between them.
What is the condition for the electric force between two objects?As we know from the electrostatics that whenever there are two charges having a positive charge on one and a negative on the other will attract each other
similarly, if they are having like charges which are both of them having positive or both of them having a negative charge then there will be a force of repulsion between them.
But if both of them or even one of them is neutral then there will not be any electric force between them.
Thus neutral objects will not have any electric force of attraction or repulsion between them.
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what is steam engine it's action and reaction
Explanation:
steam shooting out through 2 l shaped Falls creators and action force that is accompanied by backward reaction in force in opposite direction
The center of the Hubble space telescope is 6940 km from Earth’s center. If the gravitational force between Earth and the telescope is 9. 21 × 104 N, and the mass of Earth is 5. 98 × 1024 kg, what is the mass of the telescope? Round the answer to the nearest whole number. Kg.
Answer:
Approximately [tex]11121\; {\rm kg}[/tex] (rounded to the nearest whole number as required, assuming that planet Earth is a uniform sphere.)
Explanation:
Let [tex]G[/tex] denote the gravitational constant. [tex]G \approx 6.6743 \times 10^{-11}\; {\rm N \cdot m^{2} \cdot kg^{-2}}[/tex].
Let [tex]M[/tex] denote the mass of planet Earth. Let [tex]m[/tex] denote the mass of the telescope. Let [tex]r[/tex] denote the distance between the telescope and the center of planet Earth.
Note the unit conversion for the distance [tex]r[/tex]:
[tex]\begin{aligned}r &= 6940 \; {\rm km} \times \frac{10^{3}\; {\rm m}}{1\; {\rm km}} \\ &= 6.940 \times 10^{6}\; {\rm m}\end{aligned}[/tex].
By Newton's Law of Universal Gravitation, the magnitude of the gravitational force between planet Earth and this telescope would be:
[tex]\begin{aligned}W &= \frac{G\, M\, m}{r^{2}}\end{aligned}[/tex].
Rearrange this equation to find the mass [tex]m[/tex] telescope in terms of [tex]G[/tex], [tex]M[/tex], and [tex]r[/tex]:
[tex]\begin{aligned}G\, M\, m &= W\, r^{2}\end{aligned}[/tex].
[tex]\begin{aligned}m &= \frac{W\, r^{2}}{G\, M}\end{aligned}[/tex].
Substitute in the value of [tex]G[/tex], [tex]M[/tex], and [tex]r[/tex]:
[tex]\begin{aligned}m &= \frac{W\, r^{2}}{G\, M} \\ &\approx \frac{9.21 \times 10^{4}\; {\rm N} \times (6.940 \times 10^{6}\; {\rm m})^{2}}{6.6743 \times 10^{-11}\; {\rm N \cdot m^{2} \cdot kg^{-2}} \times 5.98 \times 10^{24}\; {\rm kg}} \\ &\approx 11121\; {\rm kg}\end{aligned}[/tex].
Answer:
11,121 kg
Explanation:
What’s the mass of the sample please help me!
Answer:
A. 0,11
Explanation:
Sorry if wrong. i hope this helps. thank you.
Two technicians are discussing engine cleaning. Technician A says heads and engine blocks only need cleaned on the outside, since oil keeps the inside clean. Technician B says heads and blocks will need to be hot tanked, blasted or baked. Who is correct?a. Technicians A.b. Technicians B.c. Both Technicians A and B.d. Neither Technician A and B.
An airplane flying at a speed of 130 mi/h (58.1 m/s) and at an altitude of 4.9 km drops a food package. Without a parachute, at what angle (degrees) below the horizontal will the package strike the ground?
The food package will strike the ground at 11 degrees below the horizontal.
Time for the food package to hit the groundThe time for the food package to hit the ground is calculated as follows;
h = vt + ¹/₂gt²
let the initial velocity be horizontal
4900 = 0(t) + (0.5 x 9.8)t²
4900 = 4.9t²
t² = 4900/4.9
t² = 1,000
t = √1,000
t = 31.62 s
Final speed of the food package when it hits groundvf(y) = vo + gt
vf(y) = 0 + (31.62 x 9.8)
vf(y) = 309.88 m/s
Angle of projectionThe horizontal component of the speed will be constant, while vertical component will change
[tex]tan(\theta ) = \frac{V_y}{V_x} \\\\\theta = tan^{-1} (\frac{V_y}{V_x})\\\\\theta = tan^{-1} (\frac{309.88}{58.1} )\\\\\theta = 79^0[/tex]
Angle below the horizontal = 90 - 79 = 11⁰
Thus, the food package will strike the ground at 11 degrees below the horizontal.
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A rock is thrown upward with an initial velocity of 29m/s. What is the rock's maximum height?
43 m
35.8 m
14.5 m
O 58 m
alcohol,monosodium glutamate (vetsin), water, fruit extract,sugar, coffe powder, salt, cow's milk, cocoa powder, liquid detergent. solute or both or solvent
Answer: solute: sugar, coffee powder, salt, cocoa powder, liquid detergent, monosodium glutamate (vetsin).
solvent: cow's milk, water, fruit extract
Explanation:
A solution is a mixture that is made up of two or more substances including solute and solvent.
The solute is one which can be dissolved in a liquid part that is solvent. The solute can be liquid or solid. Solutes are sugar, salt, coffee powder, cocoa powder, liquid detergent, monosodium glutamate.
The solvent is one which dissolves in it solute particles or molecules. Solvent are cow's milk, water, and fruit extract.
A group of stars connected by lines is circled and labeled Saturn.
The night sky is filled with images of wild animals. Which animal is the circled constellation named after?
scorpion
serpent
snake
salamander
The direct transfer of thermal energy between particales of matter that are touching is called
he cai
9) Mount Everest is 8848 m above the sea level. Find the
acceleration due to gravity at this height. The value of
acceleration due to gravity at the earth's surface is 9.8 m/s2
and the radius of the earth is 6400km.
Given parameters:
Height of Everest = 8848m
Acceleration due to gravity on earth = 9.8m/s²
Radius of the earth = 6400km = 6400000m
Unknown:
Acceleration due to gravity at the peak of Everest =?
Solution:
According to Newton's law of universal gravitation, we have that acceleration due to gravity is proportional to the altitude.
To solve this problem, use the mathematical expression below;
g[tex]_{e}[/tex] = g(1 - [tex]\frac{2h}{R}[/tex])
where g[tex]_{e}[/tex] is gravity on top of Everest
g is the gravity on the earth surface
h is the height of the mountain
R is the radius of the earth
g[tex]_{e}[/tex] = 9.8 (1 -[tex]\frac{2 x 8848}{6400000}[/tex] )
g[tex]_{e}[/tex] = 9.8 (1-0.002765) = 9.77m/s²
The acceleration due to on top of Everest is 9.77m/s²
An immersion heater is rated 120w. How long does it take the heater to raise the temperature of 1.2kg of water by 15°c.
Answer:
dmakqkwnwj fddfgdddwsf
will the value of g be affected by the radius of the earth? consider the real shape of the earth. compare the acceleration due to gravity for the freely falling object in the poles of the earth and other regions.
Answer:
Yes, the value of g affected by the radius.
Explanation:
The formula for the force of gravity of 2 objects is
[tex]F_{gravity} = G\frac{m_{1}m_{2}}{r^2}[/tex], where m1 and m2 are the masses of the 2 objects, r is the radius, and G is the gravitational constant, which is approximately [tex]6.67 \cdot 10^{-11}[/tex].
Therefore, as the radius if bigger, the force of gravity is going to be smaller exponentially.
In the graph above, what is the instantaneous speed of the object after the first five seconds?
A) 0 m/s
B) 5 m/s
C) 12.5 m/s
D) 25 m/s
Answer:
D) 25 m/s
Explanation:
In order to solve this problem we must use the following kinematics equation.
[tex]v_{f} =v_{i} +(a*t)\\[/tex]
where:
Vf = final speed [m/s]
Vi = initial speed = 0
a = acceleration = 5[m/s^2]
t = time = 5[s]
After 5 seconds the acceleration is equal to 5 [m/s^2]
Now replacing the values in the equation:
Vf = 0 + (5*5)
Vf = 25[m/s]
Freezing point is a ____________________ property.
chemical
physical
Tell some types of light rays?
Answer: microwaves, infrared light, ultraviolet light, X-rays and gamma-rays
Hopes this helps!
Red light
Orange light
Green light
Violet light
Laser light
Bright light
Dim light
Sun light
What do magnesium and chlorine react to form?
A.
MgCl2
B.
Mg2Cl
C.
MgCl
D.
Mg2Cl2
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