A ball is thrown straight up and rises to a maximum height of 22 m. At what height is the speed of the ball equal to half of its initial value

Answers

Answer 1

Answer:

The height of the ball when the speed of the ball is half of its initial value is 16.5 m

Explanation:

Given;

maximum height reached by the ball, h = 22 m

let the initial velocity of the = u

The equation of maximum height reached by the ball is calculated as;

v = u² - 2gh

where;

v is the final velocity at the maximum height = 0

0 = u² - (2 x 9.8)22

0 = u² - 431.2

u² = 431.2

u = √431.2

u = 20.765 m/s

Half of the initial speed = ¹/₂ x 20.765 m/s = 10.383 m/s

The height of the ball at this half value of speed is calculated as;

v² = u² - 2gh

where;

v is the final speed = 10.383 m/s

u is the initial speed = 20.765 m/s

(10.383)² = (20.765)² - (2 x 9.8)h

(2 x 9.8)h = (20.765)² - (10.383)²

19.6h = 323.379

h = 323.379 / 19.6

h = 16.5 m

Therefore, the height of the ball when the speed of the ball is half of its initial value is 16.5 m


Related Questions


If you live in the southern hemisphere, what season would you be experiencing in position C this diagram?
A)
Fall
B)
Summer
C)
Winter
D)
Spring

Answers

I think it’s C HOPE ITS RIGHT
The answer to this question is B

Help please !

Which nucleotides form an RNA molecule?


Choose all that apply:


1) Adenine (A)
2) Uracil (U)
3) Thymine (T)
4) Cytosine (C).

Answers

Answer:

1) Adenine (A)   2. Uracil (U)   4) Cytosine (C)

Explanation:

"RNA consists of four nitrogenous bases: adenine, cytosine, uracil, and guanine."

A record rotates on a turntable at 33 rpm. You may want to review What is the angular speed in rad/s?

Answers

Answer:

the angular speed in rad/s is 3.45

Explanation:

The computation of the angular speed in rad/s is as follows:

As we know that

1 rpm means 1 revolution per minute

Also 1 minute = 60 seconds

SO, for 33 rpm, the angular speed is

= 33 ÷ 60 × 2π

= 3.45  rad/s

As the revolution is of 360 degrees i.e. equivalent to 2π

Hence, the angular speed in rad/s is 3.45

The alarm at a fire station rings and a 87.5-kg fireman, starting from rest, slides down a pole to the floor below (a distance of 4.10 m). Just before landing, his speed is 1.75 m/s. What is the magnitude of the kinetic frictional force exerted on the fireman as he slides down the pole?

Answers

Answer:

[tex]F_f=840N[/tex]

Explanation:

From the question we are told that

Weight of fireman [tex]W_f= 87.5kg[/tex]

Pole distance [tex]D=4.10m[/tex]

Final speed is [tex]V_f 1.75m/s[/tex]

Generally the equation for velocity is mathematically represented as

[tex]v^2 = v_0^2 + 2 a d[/tex]

Therefore Acceleration a

[tex]a'= v^2 / 2 d[/tex]

[tex]a'= 0.21m/s^2[/tex]

Generally the equation for Frictional force [tex]F_f[/tex] is mathematically given as

[tex]F_f=m*a[/tex]

[tex]F_f=m*(g-0.21)[/tex]

[tex]F_f=87.5*(9.81-0.21)[/tex]

Therefore

[tex]F_f=840N[/tex]

what is one reason that john adams and benjamin franklin believed the articles of confederation should be revised.

Answers

Answer:

Explanation:

Their most intimate experience probably happened during an unsuccessful peace mission in September 1776. The British forces had recently raced across Long Island (New York) and almost destroyed the American Army. The British commander, Adm. Lord Richard Howe, then offered peace. Congress sent Adams, Franklin, and Edward Rutledge (South Carolina) to meet Howe on Staten Island.

Howe hoped to resolve the differences between what Great Britain still considered its colonies and the mother country. The Americans insisted on British recognition of independence, but Howe had no such authority, and Adams and Franklin had little of their own. Although cordial, the meeting broke up without success after just three hours.

During the mission, Adams and Franklin lodged together at crowded inn in a small room with only one window. Adams records an unforgettable and amusing story in his diary about that evening and hearing Franklin’s theory of colds.

During which season of the year will your nails grow most quickly?

summer

spring

fall

winter

Answers

ANSWER: THE ANSWER IS SUMMER

Answer:

summer

Explanation:

Helppp plssss I am needing help for science and there is a photo pls answer

Answers

Answer:

sorry I don't really know :P

Explanation:

Answer:

how many of those questions do you need answers to?

Explanation:

A 2.5 kg tribble is placed in a bucket and whirled in a 1.4 m radius vertical circle at a constant tangential speed. If the force on the tribble from the bucket does not exceed 10 times its weight (tribbles are a hardy species), the maximum tangential speed is

Answers

Given that,

Mass of a tribble, m = 2.5 kg

Radius, r = 1.4 m

The force on the tribble from the bucket does not exceed 10 times its weight.

To find,

The maximum tangential speed.

Solution,

The force acting on the tribble is equal to the centripetal force.

F = 10mg

The formula for the centripetal force is given by :

[tex]F=\dfrac{mv^2}{r}[/tex]

v is maximum tangential speed

[tex]v=\sqrt{\dfrac{Fr}{m}} \\\\v=\sqrt{\dfrac{mgr}{m}} \\\\v=\sqrt{{10gr}} \\\\v=\sqrt{10\times 9.8\times 1.4} \\\\v=11.7\ m/s[/tex]

So, the maximum tangential speed is 11.7 m/s.

A baseball has an approximate mass of 0.15 kg. If a bat strikes the baseball with a force of 6 N, what is the acceleration of the ball?

Answers

Answer:

a = 40 [m/s²]

Explanation:

These kinds of problems can be solved using Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

F = force = 6 [N]

m = mass = 0.15 [kg]

a = acceleration [m/s²]

[tex]a=F/m\\a=6/0.15\\a=40[m/s^{2} ][/tex]

Answer:

40 .............vxfhgcffffxxxhhxcjcxghxfgxsfg

Which statements compare linear and angular momentum? Check all that apply.

Both measure the tendency of objects to resist a change in motion.
Both are affected by the mass of the object in motion.
Both are affected by the distribution of mass relative to an axis.
Both involve velocity.
Both involve rotation.

Answers

Answer:

A,B,D

Explanation:

cause ik

How much power is produced by flashlight that has a voltage of 12 volts and a current of 6.5 x 10^-2 amps? A. 0.78 watts B. 78 watts C. 190 watts D. 0.0054 watts E. 1.9 watts

Answers

Answer:

the powar produced is 0.7 watts

A birthmark is generally a:

macule.

excoriation.

pustule.

bullae.

Answers

B is the answer sweet hart

Answer:

macule

Explanation:

its aa flat round areausually distingurished from its surroundung skin by its changed in color. smaller than 1cm  am small hemorrhage spot.

a proton travelling along is x-axis is slowed by a uniform electric field E. at x = 20.0 cm, the proton has a speed of 3.5x10^6 m/s and at 80.0 cm the speed is zero. Determine the magnitude and direction of e,

Answers

Answer:

[tex]E=101955.8volt/m[/tex]

The electric field direction is toward the right

Explanation:

From the question we are told that

Initial X-co-ordinate of proton [tex]X_1=20.0cm => \frac{20}{100}m[/tex]

Initial speed of Proton [tex]V_1= 3.5*10^6 m/s[/tex]

Final X-co-ordinate of proton [tex]X_2=80.0cm => \frac{80.0}{100}m[/tex]

Final speed of Proton [tex]V_2=0[/tex]

Generally the mass of Proton is given by

[tex]m_P=1.67*10^-27[/tex]

Generally the kinetic energy of the proton is mathematically given by

 [tex]K.E_p=1/2mv^2[/tex]

 [tex]K.E_p=1/2*1.6*10^-^2^7*(3.5*10^6)^2[/tex]

  [tex]K.E_p=9.8*10^-^1^5[/tex]

Generally the change in electric potential [tex]\triangle V[/tex] is mathematically given by

   [tex]\triangle V =\frac{K.E_p}{q}[/tex]

Charge on a proton [tex]q=1.602*10^-^1^9[/tex]

   [tex]\triangle V =\frac{9.8*10^-^1^5}{1.602*10^-^1^9}[/tex]

   [tex]\triangle V =61173.5volts[/tex]

Generally the equation for magnitude of an electric field is mathematically given by

  [tex]E=\frac{\triangle V}{\triangle d}[/tex]

Where

[tex]d=0.8m-0.2m\\d=0.6m[/tex]

Therefore

    [tex]E=\frac{61173.5}{0.8-0.2}[/tex]

    [tex]E=\frac{61173.5}{0.6}[/tex]

    [tex]E=101955.8volt/m[/tex]

The direction of the charge is towards the right

     

54:29
Mason notices that his boat sinks lower into the water in a freshwater lake than in the ocean. What could explain
this?
The boat is more dense in salt water.
The boat is less dense in salt water.
Salt water is less dense than freshwater
O Salt water is more dense than freshwater
Save and Exit
Sube
Mark this and retum

Answers

Answer:

Salt water is more dense than freshwater

Explanation:

The only and best explanation for this phenomenon for this occurrence is that salt water is more dense than freshwater.

Density is the mass per unit volume of a substance. When a substance is A more dense than the other substance B, B will float on A. So, the density of the salt water is higher than that of the fresh water because it has more particles per unit volume compared to fresh water. Therefore, the boat will go farther into the fresh water compared to the salt water.

what is rhe average velocity od a baseball dropped from rest that falls for 2 seconds?​

Answers

Answer:

19.6m/s

Explanation:

Given parameters:

Initial velocity  = 0m/s

Time  = 2s

Unknown:

Average velocity  = ?

Solution:

We can use the final velocity of the ball before landing to determines its average velocity ;

 Using;

              v  = u + gt

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity

t is the time

              v  = 0 + 9.8 x 2 = 19.6m/s

When Mary talks, she creates an intensity level of 60 dB at your location. Alice talks with the same volume, also giving 60 dB at your location. If both Mary and Alice talk simultaneously from the same spot, what would be the new intensity level that you hear

Answers

Answer:

hm

Explanation:

facil

An Olympian lifts a 1,375-kilogram set of weights a vertical distance of 2 meters in the weightlifting event.
The force of gravity equals 9.8 m/s. What is the potential energy of the weights?

Answers

Answer:

PE = MGH.  1375 x 9.8 x 2. = 26950 joules

Explanation:

First do 1375 x 9.8 which is MG then times it by 2 which is H

Mass x Gravity x Height

the gravity will always be 9.8

I would love a brainliest

The the potential energy of the weights lifted 2 meters above the surface is E[P] = 26950 joules.

What is Potential energy?

The energy of a body by virtue of its position is called potential energy. Mathematically -

E[P] = mgh

Given is an Olympian who lifted a 1,375-kilogram set of weights a vertical distance of 2 meters in the weightlifting event.

We can write the given data as follows -

Mass of weights = [M] = 1375 Kg

Displacement = [h] = 2 meters

Therefore, using the formula for potential energy, we can write -

E[P] = mgh

E[P] = 1375 x 9.8 x 2

E[P] = 26950 joules

Therefore, the the potential energy of the weights lifted 2 meters above the surface is E[P] = 26950 joules.

To solve more questions on Mechanical Energy, visit the link below-

https://brainly.com/question/20719292

#SPJ6

If she returned home by the same path 7 h 30 min after she left, what were her average speed and velocity in km/h for the entire trip

Answers

Answer:

speed  v = 0.148 m / s

velocity   v = 0

Explanation:

In this exercise we must be careful that the speed is a scalar and the speed is a vector, let's start by looking for the speed

           v = Δx /Δt

   

the distance traveled is x = 2d and the time taken is

           t = 7h 30 min

let's reduce to seconds

          t = 7 h 3600s / 1h + 30 min 60s / 1min = 27000 s

so the speed is

          v = 2d / 27000

to finish the calculation suppose a distance traveled d = 2000 m

          v = 2 2000/27000

          v = 0.148 m / s

this is the raides which is the speed module

Velocity is a vector,

          v = Dx / Dt

in this case the displacement is

           Dx = d -d

           Dx = 0

the total displacement is zero since it returns to the starting point, consequently the velocity is zero

          v = 0

bold is a vector

How much work would be needed to lift the ball from the 2-m shelf to the 5-m shelf, and how much potential energy would it have on the 5-m shelf?

Answers

Answer:

a) 2.94 N

b) 4.90 N

Explanation:

Let us assume that the weight of the ball is 0.98 N

Solution:

a) An object’s gravitational potential energy depends on two factors which are height and its weight (or mass). The equation for gravitational potential energy (PE) is given as:  

Potential energy = weight (w) * height (h)

PE = wh

Potential energy at 2 m shelf = weight * height = 0.98 N * 2 m = 1.96 N

Potential energy at 5 m shelf = weight * height = 0.98 N * 5 m = 4.90 N

The work needed to lift the ball from the 2-m shelf to the 5-m shelf = Potential energy at 5 m shelf - Potential energy at 2 m shelf

The work needed to lift the ball from the 2-m shelf to the 5-m shelf = 4.90 N - 1.96 N = 2.94 N

b) Potential energy at 5 m shelf = weight * height = 0.98 N * 5 m = 4.90 N


My dog Ubu can run at 21 mi/h. How far can he travel in 40 minutes?

Answers

Answer:

14

Explanation:

21miles/3=7

7*2=14

Beams of light undergo construction interference when two different beams intersect to form one brighter beam of light . Which model of the nature of light dose this behavior?

Answers

Answer:the wave model

Explanation:

The electrical resistance of a circuit is influenced by the _____, _____, and _____ of the wires.

Answers

Answer:

Length, gauge/size and composition

Explanation:

The longer the wire is the more resistance

The thinner the wire is more resistance

The difference in material effects the resistance ie. copper versus aluminium.

How much heat Q2Q2 is transferred to the skin by 25.0 gg of steam onto the skin? The heat of vaporization for steam is L=2.256×106J/kgL=2.256×106J/kg.

Answers

Answer:

56400Joules

Explanation:

The quantity of heat required is expressed as;

Q = mL

m is the mass = 25g = 0.025kg

L is the latent heat of vaporization for steam = 2.256×10^6J/kg

Substitute into the formula as shown;

Q = 0.025×2.256×10^6

Q = 56400Joules

Hence the quantity of hear required is 56400Joules

The amount of heat transfer from the steam is of 56400 J.

Given data:

The mass of steam is, m = 25.0 g = 0.025 kg.

The latent heat of vaporization of steam is, [tex]L = 2.256 \times 10^{6} \;\rm J/kg[/tex].

When heat is to be given to a unit mass of substance to converts it from a liquid phase to vapor phase. Then it is known as Latent heat of vaporization. The amount of heat is expressed as,

[tex]Q = m \times L[/tex]

Solving as,

[tex]Q = 0.025 \times (2.256 \times 10^{6})\\\\Q = 56400 \;\rm J[/tex]

Thus, we can conclude that the amount of heat transfer from the steam is of 56400 J.

Learn more about the Latent heat of vaporization here:

https://brainly.com/question/24203857

Sound waves are simultaneously interpreted through air (going through the external,
middle, then inner ear) and through the bone in the inner ear, stimulating the
acoustic nerve.

True

False

Answers

Not sure if this is right but I think it’s TRUE sorry if it’s wrong....

Answer:

its true

Explanation:

i took it

A horse is working steadily, providing 750 W of output power. How much food energy does the horse need to work for 1 hour, to the nearest MJ

Answers

Answer:

Under assumption that all food energy that needs the horse is transformed into work, then the horse needs approximately 3 megajoules of food energy to work for 1 hour.

Explanation:

Since horse is working steadily, the power experimented by the horse ([tex]\dot W[/tex]), measured in watts, is at constant rate. Then, the work needed by the horse ([tex]W[/tex]), measured in joules, is equal to that power multiplied by time ([tex]\Delta t[/tex]), measured in seconds. That is:

[tex]W = \dot W\cdot \Delta t[/tex] (1)

If we know that [tex]\dot W = 750\,W[/tex] and [tex]\Delta t = 3600\,s[/tex], then the work needed for the horse is:

[tex]W = (750\,W)\cdot (3600\,s)[/tex]

[tex]W = 2.7\times 10^{6}\,J[/tex]

[tex]W = 2.7\,MJ[/tex]

Under assumption that all food energy that needs the horse is transformed into work, then the horse needs approximately 3 megajoules of food energy to work for 1 hour.


On a circular racetrack with a radius of 3.23 m, a certain road car set a speed record of 3.72
m/s. If the car had a mass of 250 kg, what was the net force acting on it?

Answers

Answer:

F = 1071.08 N

Explanation:

Given that,

The radius of the circular track, r = 3.23 m

Speed of the car, v = 3.72 m/s

The mass of the car, m = 250 kg

We need to find the net force acting on it. The centripetal force will act on it and it is given by the relation as follows :

[tex]F=\dfrac{mv^2}{r}\\\\F=\dfrac{250\times (3.72)^2}{3.23}\\\\F=1071.08\ N[/tex]

So, the net force acting on the car is 1071.08 N.

Migration is the seasonal movement of a population of organisms from one place to another True or false

Answers

Answer:

true lol its jist common sense

Answer: Seasonal migration is the movement of various species from one habitat to another during the year. Resource availability changes depending on seasonal fluctuations, which influence migration patterns. ... Many species, especially birds, migrate to warmer locations during the winter to escape poor environmental conditions.

Explanation:

What is the Potential Energy of a spring stretched 5.0 cm that has a
spring constant of 79 N/m?

Answers

Answer:

The Potential Energy of the stretched spring is = 1.975 J

Explanation:

Recall that the potential energy of a spring of constant k stretched x\a distance x is given by the formula:

U = 1/2  k x^2

Therefore in our case, converting the stretch from cm of meters (0.05 m), this is

U = 1/2 * 79 * 0.05 J = 1.975 J

A material that restricts the flow of electricity or thermal energy is a what

Answers

Answer: Insulator

Explanation:

An insulator is a material that restricts the flow of electricity or thermal energy.

Answer:

plastic or wood

Explanation:

An object accelerates downward at a constant rate of 2.00 m/s2 while completely submerged in water. Neglect the viscosity (fluid friction) of the water. The average density of the object is ______ kg/m3. Use g

Answers

Answer:

833kg/m³

Explanation:

We have volume as Vm³

Density of this object = dKg/m³

Water density = 1000kg/m³

g = 10m/s²

We calculate FB which is the the buoyant force on object. Calculated as volume of object multiplied by water density

Fb = 1000Vg upwards

W = Vdg

Acceleration = net upwards/m

M = mass

2 = (1000g-gd)/d

2d = 10000 - 10d

2d + 10d = 10000

12d = 10000

d = 833.33kg/m³

Approximately 833kg/m³

The average density of the object is therefore 833kg/m³

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