A ball is projected horizontally from the top of a 92.0-meter high cliff with an initial speed of 19.8m/s. Determine the horizontal displacement.

Answer:

T = [tex]1/2\pi \sqrt (k/m) \\[/tex] so period of mass spring system becomes 2 times w.r.t original problem.

Explanation:

[tex]T =1/2\pi \sqrt(k/m)\\[/tex] so when k = 1 is replaced by 4 it means it becomes

k" = 4k

[tex]T' = 1/2\pi \sqrt(k'/m)\\T' = 1/2\pi \sqrt(4k/m)\\T' = 2(1/2\pi\sqrt(k/m)\\)\\T' = 2T[/tex]

Explanation:

Unbalanced Forces in Action

Unbalanced forces can change the motion of an object in two ways. ... Second, when unbalanced forces act on a moving object, the velocity of the object will change. Remember that a change in velocity means a change in speed, direction or both speed and direction.

Explanation:

Given that,

Mass, m = 0.08 kg

Radius of the path, r = 2.7 cm = 0.027 m

The linear acceleration of a yo-yo, a = 5.7 m/s²

We need to find the tension magnitude in the string and the angular acceleration magnitude of the yo‑yo.

(a) Tension :

The net force acting on the string is :

ma=mg-T

T=m(g-a)

Putting all the values,

T = 0.08(9.8-5.7)

= 0.328 N

(b) Angular acceleration,

The relation between the angular and linear acceleration is given by :

[tex]\alpha =\dfrac{a}{r}\\\\\alpha =\dfrac{5.7}{0.027}\\\\=211.12\ m/s^2[/tex]

(c) Moment of inertia :

The net torque acting on it is, [tex]\tau=I\alpha[/tex], I is the moment of inertia

Also, [tex]\tau=Fr[/tex]

So,

[tex]I\alpha =Fr\\\\I=\dfrac{Fr}{\alpha }\\\\I=\dfrac{0.328\times 0.027}{211.12}\\\\=4.19\times 10^{-5}\ kg-m^2[/tex]

Hence, this is the required solution.

Answer:

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Explanation:

Answer:

[tex]f=1/2\pi *\sqrt{k/m}[/tex]

Explanation:

This is the equation of the frequency of a spring in the horizontal direction.

Could we have the choices? If we have those we could help you!   εїз

Answer:

Pic not clear.........

Answer:

False

Explanation:

Im pretty sure the answer is false

Answer: Electric charges

Explanation: Atmospheric pressure isn't able to crush you because it doesn't result from weight or surface area. Atmospheric pressure, also known as weather patterns, results from escaping atmospheric gases coming together and creating electric charges. Oceanic pressure in caused from high compression of the upper layers of the water, producing thousands of tons of liquid weight crushing the bottom layer. This is how they are different forms of pressure.

Answer:

40Kg

Explanation:

F=m×a

24N÷0.6m/s^2=40

Answer:

vps = vbr + vrs - vpb

Explanation:

Answer:

The speed the apple must be thrown in order for it to land in the basket is  2.554 m/s.

Explanation:

Given;

height above the ground, h = 3.0 m

horizontal distance, X = 2.0 m

The time to drop from the given height;

h = ¹/₂gt²

[tex]t = \sqrt{\frac{2h}{g} }\\\\t = \sqrt{\frac{2*3}{9.8} }\\\\t = 0.783 \ s[/tex]

The horizontal speed traveled by the apple is given by;

vₓ = X / t

vₓ = 2 / 0.783

vₓ = 2.554 m/s

Therefore, the speed the apple must be thrown in order for it to land in the basket is  2.554 m/s.

Explanation:

workdone = force x distance

workdone= 25 x 4

workdone = 100 joules ( the unit for workdone is joules or Nm )

POWER = workdone/ time

power = 100/5

power = 20 watts ( the unit for power is watts or Nm/s )

Answer:

The correct option is A

Explanation:

Generally, when the temperature of matter is low and starts to cool, the kinetic energy of it's particles decreases which causes the motion of the atoms within it's particles to also decrease. When the kinetic energy of the particles decreases, it causes the matter to form a mass by coming together since it's atoms will no longer be able to move freely as before (just like in solids) - this is the reason for the formation of ice in the freezing compartment.

From the explanation above, it can be deduced that the correct option is A

Answer:

pic

Explanation:

The graph which best shows the velocity v of the quarter from when it is tossed up until it reaches the ground is attached in the answer.

Velocity is the time rate of change of displacement. The displacement and velocity both are vector quantities. They represent magnitude and direction as well.

A quarter is tossed up from the roof of a skyscraper and hits the sidewalk below.

The velocity will decrease with the time linearly.

The graph which best shows the velocity v of the quarter from when it is tossed up until it reaches the ground is attached in the solution.

Learn more about velocity.

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#SPJ2

Answer:

protons and electrons

Answer:

6/7 kg

Explanation:

We are given:

Mass of the object (m) = 14 kg

Force applied (F) = 12 N

Acceleration of the Object:

From newton's second law of motion, we know that:

F = ma

Replacing the variable with the given values

12 = 14 * m

m = 12 / 14                                                        [dividing both sides by 14]

m = 6/7 kg

Hence, the Object has a mass of 6/7 kg

Answer:

true i think

Explanation:

The amplitude of a sound wave determines its loudness or volume. A larger amplitude means a louder sound, and a smaller amplitude means a softer sound. In Figure 10.2 sound C is louder than sound B. The vibration of a source sets the amplitude of a wave.

Answer:

True

Explanation:

Look up the definition of amplitude

Answer:

2.27

Explanation:

Potential energy =mgh so from there u can substitute the values

Answer:

A. Heat flowing from cold to hot

Explanation:

The second law of thermodynamics speaks about entropy and directions of processes. These directions go only in one direction, just as time moves only in one direction, as we know it. It is impossible to see time moving forward in a different sense. In the same way, the processes associated with heat transfer, go in a single direction this direction is associated with bodies at different temperatures. Where heat is transferred from a higher temperature body to a lower temperature body.

Heat transfer processes from a cold body to a hot body, do not exist and can not be achieved in a natural way.

Answer:

C

Explanation:

Answer:

In real measurements, the acceleration that is measured is always less than the acceleration of gravity, therefore there must be a force that opposes the movement, which is why Aristotle says that vacuum stenos

Explanation:

When a rock starts the vacuum, there are no friction forces that make its movement, therefore, if close to the Earth, the rock has an acceleration equal to the acceleration of gravity.

In real measurements, the acceleration that is measured is always less than the acceleration of gravity, therefore there must be a force that opposes the movement, which is why Aristotle says that vacuum stenos

Answer:

A. Reversibility

Explanation:

Because if you don't progress then you do the opposite, you reverse.

Sorry if my explanation is confusing it made sense in my head i just didn't know how to put it.

hope this help. ;)

Answer:

A. Reversibility

Explanation:

Answer:

there are uncountable sun are there but sun is star therefore there are uncountable stars are there

Answer:

1 but For many years scientists have studied our own solar system. But until the last few years, we knew of no other solar systems. This may seem surprising, as the Sun is one of about 200 billion stars (or perhaps more) just in the Milky Way galaxy alone.

Explanation:

Answer:

 T = 556K

Explanation:

For this exercise let's use Stefan's law

        P = σ A e T⁴

where the stafan-Boltzmann constant is 5,670 10⁻⁸ W / m² K⁴.

In this case the area of ​​a circular cylinder is

        A = π r²

the radius is

         r = d / 2 = 0.150 m

        A = π (0,150)²

        A = 7.0685 10⁻² m²

let's clear

         T⁴ = P /σ A e

         T⁴ = 100 / (5.670 10⁻⁸   7.0685 10⁻²  0.26)

         T⁴ = 9.5966 10¹⁰ = 959.66 10⁸

         T = 5.56 102 K

         T = 556K

The temperature of the filament is 366.3 K

Using the equation for radiated power, P

P = σεAT⁴ where σ = Stefan-Boltzmann constant = 5.67 × 10⁻⁸ W/m²K⁴, ε = emissivity = 0.26, A = area of cylindrical tungsten filament = πDh (since it radiates through its sides)where D = diameter of tungsten filament = 0.40 mm = 0.4 × 10⁻³ m and h = length of tungsten filament = 30.0 cm = 0.3 m and T = temperature of tungsten filament.

Since we require the temperature of the filament, making T subject of the formula, we have

T = ⁴√(P/σεA)

T = ⁴√(P/σεπDh)

Since P = 100 W, substituting the values of the variables into the equation, we have

T = ⁴√(P/σεπDh)

T = ⁴√(100 W/5.67 × 10⁻⁸ W/m²K⁴× 0.26 × π× 0.4 × 10⁻³ m × 0.3 m)

T = ⁴√(100 W/0.5558 W/K⁴ × 10⁻⁸)

T = ⁴√179.93 × 10⁸ K⁴)

T = 3.663 × 10² K

T = 366.3 K

So, the temperature of the filament is 366.3 K

Learn more about temperature of a filament here:

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Answer:

The student must change the launch angle from 20º to 45º to maximize the horizontal distance.

Explanation:

The dart experiments a parabolical motion, which is the combination of horizontal uniform motion and vertical uniform accelerated motion due to gravity, in which effects from air friction and Earth's rotation can be neglected. The equations of motion are described below:

[tex]x = x_{o}+v_{o}\cdot t \cdot \cos \theta[/tex] (1)

[tex]y = y_{o}+v_{o}\cdot t\cdot \sin \theta +\frac{1}{2}\cdot g\cdot t^{2}[/tex] (2)

Where:

[tex]x_{o}[/tex], [tex]y_{o}[/tex] - Initial coordinates of the dart, measured in meters.

[tex]x[/tex], [tex]y[/tex] - Current coordinates of the dart, measured in meters.

[tex]v_{o}[/tex] - Initial velocity of the dart, measured in meters per second.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]t[/tex] - Time, measured in seconds.

[tex]\theta[/tex] - Launch angle, measured in sexagesimal degrees.

According to the statement, we need to determine the launch angle when [tex]\Delta x = x-x_{o} > 0[/tex], [tex]\Delta y = y-y_{o}= 0[/tex] and [tex]v_{o} > 0[/tex]. Then, we obtain the following system of linear equations:

[tex]\Delta x = v_{o}\cdot t \cdot \cos \theta[/tex] (1b)

[tex]v_{o}\cdot \sin \theta + \frac{1}{2}\cdot g \cdot t = 0[/tex] (2b)

By (2b), we clear time as follows:

[tex]t = -\frac{2\cdot v_{o}\cdot \sin \theta}{g}[/tex]

And it is applied in (1b) afterwards:

[tex]\Delta x = -\frac{2\cdot v_{o}^{2}\cdot \sin\theta \cdot \cos\theta}{g}[/tex]

[tex]\Delta x = -\frac{v_{o}^{2}\cdot \sin 2\theta}{g}[/tex] (3)

Where [tex]\Delta x[/tex] is the horizontal distance, measured in meters.

In order to determine the launch angle such that distance is maximized, we require the first and second derivatives of the function. That is:

First derivative

[tex]\Delta x' = -\frac{2\cdot v_{o}^{2}\cdot \cos 2\theta}{g}[/tex] (4)

Second derivative

[tex]\Delta x'' = \frac{2\cdot v_{o}^{2}\cdot \sin 2\theta}{g}[/tex] (5)

By equalizing (4) to zero, we find the following trigonometric equivalence:

[tex]\cos 2\theta = 0[/tex]

[tex]2\cdot \theta = 90^{\circ}[/tex]

[tex]\theta = 45^{\circ}[/tex]

A launch angle of 45º is a critical point of (3). If we know that [tex]g< 0[/tex] and [tex]\theta = 45^{\circ}[/tex] in (5), then [tex]\Delta x'' < 0[/tex], which means that critical point determined above leads to a maximum distance. Then, the student must change the launch angle from 20º to 45º to maximize the horizontal distance.

Answer:

#_foton2 = 2.96 10¹⁶ photon / s

Explanation:

We are going to solve this exercise in parts, first we will calculate how many photons are in the beam and then the amount that pass through the pinhole.

To find the energy of a photon, let's use the Planck relationship

          E = h f

          c = λ f

we substitute

          E₀ = h c /λ

          E₀ = 6.63 10⁻³⁴ 3 10⁸/337 10⁻⁹

          E₀ = 5.90 10⁻¹⁹ J

Now we can use a direct ratio rule to find out the number of photons in the beam. If 1 photon has an energy E₀, how many photons are in an energy 5.00W

         # _foton = 1  5/ E₀ = 1 5 / 5.90 10⁻¹⁹

         #_foton = 8.5 10¹⁸ photons / s

This number of photons is uniformly distributed in the area of ​​the circle with diameter 5.90mm = 5.90 10⁻³m

      R= d/2=  2.95 10⁻³ m

     r = d/2 = 0.55 10⁻³ m

let's find the beam area

         A = π R²

         A = π (2.95 10⁻³)²

         A = 2.73 10⁻⁵ m²

the pinhole area

        a = π r²

        a = π (0.55 10⁻³)²

        a = 9.50 10⁻⁷ m²

Let's use another direct ratio (rule of three) if there are 8.5 1018 photons / s in an area A how many photons pass through the area at

         # _foton2 = 8.5 10¹⁸ a / A

         # _fotn2 = 8.5 10¹⁸ 9.50 10⁻⁷ /2.73 10⁻⁵

         #_foton2 = 2.96 10¹⁶ photon / s

Answer:

The value is  [tex]\mu_k = 0.03[/tex]

Explanation:

From the question we are told that

  The force applied on the ice is [tex]F = 29.4 N[/tex]

   The mass of the ice block is  [tex]m = 100 \ kg[/tex]

Generally for the ice block to move at constant speed , the force applied on it must be equal to the kinetic frictional force which is mathematically represented as

         [tex]F_F = m* g * \mu_k[/tex]

=>      [tex]F = F_F = m* g * \mu_k[/tex]

=>      [tex]29.4 = 100 * 9.8 * \mu_k[/tex]

=>       [tex]\mu_k = 0.03[/tex]

Answer:

A closed loop that electrons can travel in.

Explanation: