A and B are complementary angles. If mA = (2x + 30)° and mB = (7x – 3), then find the measure of B.

Answers

Answer 1

Answer:

mB=46

Step-by-step explanation:

2x+30+7x-3=90

Combine like terms

9x+27=90

Subtract by 27 on both sides

9x=63

Divide by 9 on both sides

x=7

mB=(7x-3)

Substitute 7 for x

mB= 7(7)-3

mB= 49-3

mB=46

Answer 2

Answer:

The measure of B is 46°

Step-by-step explanation:

To solve this equation, you need to add the two equations, and set them equal to 90° since they are complementary angles

2x+30+7x-3=90

You also need to add like terms, so 2x+7x and 30+-3, or 30-3

9x+27=90

Then you need to isolate the variable by subtracting 27 from both sides

9x+27-27=90-27

=

9x=63

Then you need to divide both sides by 9 to get x=7

Since we know what x is, we plug x into the equation (7x-3) and we will now have 7(7)-3.

To solve this, we multiply 7 and 7, and subtract 3 to get 46.

So the answer is mB=46

I hope this helps!!

   


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The y intercept is where the function intersects the y-axis.

Answer:

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Answers

Answer:

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Step-by-step explanation:

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Answers

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[tex] \red { \orange {\boxed {\boxed{Answers}}}}[/tex]

[tex] = (x + 5)(x + 4)[/tex]

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Answers

Answer:

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Step-by-step explanation:

1 = 1

2 = 3

3 = 6

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Answers

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

Hi here is the explanation

We just do the opposite of the question

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Answers

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Answers

Answer:

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Step-by-step explanation:

The answer is -4.9 because:

1) As the number line increases, the numbers are also increasing even though  it seems like they are decreasing.

2) The number that comes right after -5 is -4.9

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Answers

Answer:

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Step-by-step explanation:

equation of a circle is (x-h)^2+(y-h)^2=r^2

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(x-14)^2+(y-3)^2=9 answer

The equation of a circle is externally tangent to the given circle and has a center at (14, 3) is [tex](x-14)^2 + (y-3)^2=9[/tex]

The standard formula for finding the equation of a circle is expressed as:

[tex](x-a)^2+(y-b)^2=r^2[/tex]

where

(a, b) is the centre

r is the radius

Given the center at (14, 3)

If the equation of a circle is externally tangent to the given circle and has a center at (14, 3), then the radius will be 3

Substitute the radius and the centre into the expression above to have:

[tex](x-14)^2 + (y-3)^2=3^2\\(x-14)^2 + (y-3)^2=9[/tex]

Hence the equation of a circle is externally tangent to the given circle and has a center at (14, 3) is [tex](x-14)^2 + (y-3)^2=9[/tex]

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Answers

Answer:

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Step-by-step explanation:

The value of 'x' in the solution set is 5 Option D

How to determine the value of x

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Answers

[tex]\large\underline{\bf \red{Step \:by\: Step \:Explanation:}}[/tex]

Let us take ,

First integer be x .Second integer be y .

Also let us consider x > y .

According to first Condition :-

⇒ x - y = 1.

⇒ x = y + 1. .............(i)

According to second Condition :-

⇒ x × y = 30 .

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[tex]\red{\bf \longmapsto y = 5 , (-6)}[/tex]

Here y can sustain both values 5 and minus 6 as y is an integer.

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Hence possible answers are ,

[tex]\boxed{\purple{\bf x = -6 , y = -5 }}[/tex]

[tex]\qquad\qquad\qquad \bf Or [/tex]

[tex]\boxed{\purple{\bf x = 6 , y = 5 }}[/tex]

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Answers

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

Answer:

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Answers

Answer:

What you are looking for is the ratio which is 5/9

Step-by-step explanation:

all you had to do was add them together

Answer:

Step-by-step explanation:

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Answers

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Answers

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Step-by-step explanation:

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