(a) The maximum frequency of revolution is 4.0 rad/s.
b (i) The tension in the string is maximum when the object is at the top of its path and minimum when it is at the bottom of its path.
b (ii) The speed of the mass can be found using the minimum tension in the string is 2 m/s.
What is the maximum frequency of revolution?
The maximum frequency of revolution is given by the maximum tension in the string, which is 60 N.
T = mv² / r
where;
m is the mass of the object (0.60 kg), v is its linear speed, r is the radius of the circle (1.20 m).The linear speed is given by:
v = 2πrf
where;
f is the frequency of revolutionf = √T / (mr²))
f = √(60 / (0.60 x 1.20²))
f = 4.0 rad/s
(i) The tension in the string is maximum when the object is at the top of its path and minimum when it is at the bottom of its path. This is because the tension provides the centripetal force that keeps the object moving in a circular path.
(ii) The speed of the mass can be found using the minimum tension in the string, which is 2.1 N:
T = mv² / r = 2.1 N
Rearranging and solving for v, we get:
v = √(Tr / m)
v = √(2.1 x 1.20 / 0.60)
v = 2.0 m/s
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determine the resultant hydrostatic force fr on the upper face of the submerged surface. what is the direction of the force?
As for the formula, yr=yc +(I/(A*yc)), is to find the force acting on a vertical plate (plate perpendicular to the surface of the water)
Assume a flat plate is present in a tank of water, at a depth of h from the water's surface, and that the plate is parallel to the water's surface.
The force acting on the plate will be equal to the weight of the water present above it.
The volume of the water present above it is A*h, where A is the area of the flat plate and h is depth.
kg/m3 is the density of water in rho.
rho*h*A gives the mass of the water above the plate.
Thus by multiplying g, we get the weight of the water above the plate.
In the above experiment, the force acting on the quadrant is balanced by slotted weights and you will be able to obtain the force.It would have been better if you had showed the simplified diagram.
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The width of a rail is 15 cm. The dimensions of a railway sleeper are 2.5m x 25 cm. If 1600
evenly spaced sleepers are placed for every kilometer of rail, by what factor is the pressure
exerted by the trains on the ground lessened?
The pressure put on the ground by trains has decreased by a ratio of 62.5.
The sleeper spacing formula, what is it?The n + x is used to represent sleeper density. The number of sleepers needed for one rail length is shown by the symbol n + x in this case. A rail's length is given by n. The necessary number of sleepers is 17 13 multiplied by 1000, which comes to 1307.69 x 1308 Numbers.
It is the quantity of sleepers necessary to support a rail-length of railroad track. Its formula is (n + x), where n is the length of a rail in meters and x is a constant with a range of 3 to 6 (the length of a rail for broad gauge (B.G.) track is 13 meters, while that for meter gauge (M.G.) track is 12 meters).
2.5 * 25 = 62.5.
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two pucks moving on a frictionless air table are about to collide, as shown above. the 1.5 kg puck is moving directly east at 2.0 m/s. the 4.0 kg puck is moving directly north at 1.0 m/s. question what is the magnitude of the total momentum of the two-puck system after the collision? responses
The magnitude of total momentum of the two-puck system is 7.0 kg m/s.
The total momentum of the two-puck system before the collision is the vector sum of the momentum of each puck. The momentum of each puck can be found using the equation:
p = mv, where m is the mass and v is the velocity.
The momentum of the 1.5 kg puck is:
p1 = m1 * v1 = 1.5 kg * 2.0 m/s = 3.0 kg m/s
The momentum of the 4.0 kg puck is:
p2 = m2 * v2 = 4.0 kg * 1.0 m/s = 4.0 kg m/s
The total momentum of the two-puck system before the collision is:
p_before = p1 + p2 = 3.0 kg m/s + 4.0 kg m/s = 7.0 kg m/s
Since the collision is elastic (no friction), the total momentum of the two-puck system after the collision will be the same as before the collision, meaning the magnitude of the total momentum after the collision will be 7.0 kg m/s.
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48) During an experiment in physics class, a student places a large block on a plank.
The student raises one end of the plank to form an incline until just before the
block starts to slide down. The block experiences a force of 26 N parallel to the
incline and 42 N perpendicular to the incline. What is the coefficient of static
friction such that the block stays at rest?
Answer:
Below
Explanation:
The block does not slide, so the force of friction equals the down the slope force. Ff = 26 n the Fn is given as 42 N
Definition of static coefficient of friction = Ff/Fn = 26/42 = .62
you have likely noticed that the temperature on the thermometer tends to fluctuate. is this fluctuation realistic? why or why not?
The degree of change in a thermometer's thermometric characteristic for a unit temperature change is known as sensitivity. When something fluctuates, it undergoes rapid, unpredictably changing change.
What does temperature variation mean?Thermal fluctuations are arbitrary departures from the average state of a system that take place in an gravity system, according to statistical mechanics. All thermal fluctuations grow in size and frequency as temperature rises and diminish as temperature falls closer to absolute zero.
What causes temperature changes?That must be "temperature fluctuation," I suppose. Low pressure and high pressure are two separate sorts of pressure, which is why that is the case. Low pressure systems frequently bring inclement weather, which may include wind, rain, snow, or hail. As also, in those.
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(a) rank points a through d according to the magnitude of the electric field at those points. if any of the electric fields have equal magnitudes, explicitly state this. explain your ranking.
The strength of the electric field is strongest when the lines are close together and weakest when they are far apart.
What is the magnitude of the electric field?The electric field is the region of space around an electrically charged particle or object where the charge body feels force. Examples: -Electric fields are created by charges and their configurations, such as capacitors and battery cells.
The force per charge applied to the test charge can be used to determine the electric field's strength. Its definition gives birth to the common metric units for electric field strength.
It is assumed that the field's direction corresponds to the force it would apply to a positive test charge. With a positive point charge, the electric field radiates outward, and from a negative point charge, it radiates in.
Therefore, The units of an electric field would be force units divided by charge units, as an electric field is defined as a force per charge.
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of the four main types of organic molecules, the type that consists of mostly carbon and hydrogen and does not dissolve in water are the
There is Covalent bond between Carbon and Hydrogen.
What is Covalent bond?In chemistry, a covalent bond is an interatomic coupling formed when two atoms share an electron pair. The electrical attraction of their nuclei for the identical electrons is what causes the binding.
When the linked atoms' combined energies are lower than those of widely spaced atoms, a covalent connection is created. To learn more, go to chemical bonding: ionic bonding. The inorganic elements hydrogen, nitrogen, chlorine, water, and ammonia (H2, N2, Cl2, H2O, NH3) as well as all organic compounds are examples of molecules with covalent connections.
Covalent bonds are denoted as solid lines joining atom pairs in structural representations of molecules.
Therefore, There is Covalent bond between Carbon and Hydrogen.
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a rock undergoing free fall on planet x is thrown upward at 5.0 m/s. it undergoes constant acceleration vertically downward, and when it lands it is traveling downward at 15.0 m/s. if the rock lands 20.0 m below where it was thrown upward, how long does it spend in the air?
The rock which undergoing free fall spends approximately 1.02 seconds more in the air if the rock lands 20.0 m below where it was thrown upward.
The rock undergoing free fall on planet x is thrown upward at 5.0 m/s and it undergoes constant acceleration vertically downward. When the rock landing the velocity was 15.0 m/s.
The time spent in the air by the rock can be calculated using
v = u + at
where v is the final velocity 15 m/s downward, u is the initial velocity 5 m/s upwards, a is the acceleration which is constant here and equal to acceleration due to gravity ⇒ 9.8 m/s² and finally t is the time in the air.
v = u + at ⇒ v - u = at
15.0 m/s - 5.0 m/s = g × t
10.0 m/s = g × t
t = 10.0 m/s / g ⇒ t = 10.0 m/s / 9.8 m/s² = 1.02 s
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the principle that explains the scattering of shortwave radiation and accounts for earth's blue sky is question 36 options: rayleigh scattering. transmission. mie scattering. refraction.
"The principle that explains the scattering of shortwave radiation and accounts for earth's blue sky is rayleigh scattering."
Rayleigh scattering is the scattering of light by particles available in the atmosphere. According to Rayleigh's scattering law, the quantity of scattering of the light is inversely proportional to the fourth power of the wavelength.
As the wavelength of light falls, Rayleigh scattering, caused by these tiny air molecules, increases. The wavelengths of violet and blue light are the shortest, whereas red light has the longest. The sky appears blue during the day because blue light is scattered more than red light.
The theory of Rayleigh scattering can be used to explain how air molecules, tiny particles, microwave radiation from clouds, and raindrops scatter UV and visible light.
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calculate the gravitational field strength on the surface of mars. mars has a radius of 3.43x106 m and a mass of 6.37x1023 kg.
On the surface of Mars, the gravitational field strength is roughly [tex]3.71 m/s^2.[/tex]
The influence that a large body has on the space surrounding it, exerting force on another large body, is described by the gravitational field. The following formula can be used to determine the strength of the gravitational field (g) on the surface of a planet:
g = [tex]\frac {GM}{ r^2}[/tex]
where G is the gravitational constant [tex]6.67 \times 10^{-11} Nm^2/kg^2[/tex], M is the mass of the planet, and r is the radius of the planet.
Plugging in the values for Mars:
g = [tex]6.67 \times 10^{-11} Nm^2/kg^2[/tex] x [tex]\frac{(6.37 \times 10^23 kg)}{(3.43 \times 10^6 m)^2}[/tex]
g= [tex]3.71 m/s^2.[/tex]
Consequently, the strength of the gravitational field on the surface of Mars is about. [tex]3.71 m/s^2.[/tex]
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103) if the collision is elastic and the final speed of object b is 5.0 m/s, what is the final velocity of object a?
The final velocity of object A is equal to the final velocity of object B, which is 5.0 m/s.
If the collision between objects A and B is elastic, then both momentum and kinetic energy are conserved.
Let the initial velocity of object A be [tex]v_A[/tex] and the initial velocity of object B be [tex]v_B[/tex]. The mass of object A is and the mass of object B is [tex]m_B[/tex].
Conservation of momentum:
[tex]m_A v_A + m_B v_B = m_A v' + m_B v'[/tex]
where v' is the final velocity of both objects.
Conservation of kinetic energy:
[tex]\dfrac{1}{2} m_A v_A^2 + \dfrac{1}{2} m_B v_B^2 = \dfrac{1}{2} m_A v'^2 + \dfrac{1}{2} m_B v'^2[/tex]
Substituting v' in terms of [tex]v_A[/tex] and [tex]v_B[/tex] using the momentum conservation equation,
[tex]v_A = \dfrac{m_A - m_B}{m_A + m_B}v_B + \dfrac{2m_B}{m_A + m_B}v_B[/tex]
[tex]v_A = \dfrac{(m_A - m_B + 2m_B)v_B}{m_A + m_B}[/tex]
[tex]v_A = \dfrac{(m_A + m_B)v_B}{m_A + m_B}\\= v_B[/tex]
Therefore, the final velocity of object A is equal to the final velocity of object B.
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a guitar string is 65.0 cm long and is tuned to produce a lowest frequency of 196 hz. a. what is the speed of the wave on the string? b. what are the next two higher resonant frequencies for this string?
Information given are: L=65cm =0.65m, f=196Hz, a v=?, Wavelength by: λ=2L, When we put known values into the previous equation we get: λ=2⋅0.650m = 1.30m, And speed is given by: v=λf, v=1.30m⋅196Hz, Finally: a v = 255 m/s, b., f2=392Hz, f3=588 Hz.
Which is the length of a standing wave with four antinodes vibrating on a 60 cm long guitar string?AI's Preferred Response:You need to know the object's length and frequency in order to compute the wavelength of an object that is vibrating.The frequency in this instance is 60 Hz, and the length was 60 cm.This wave has a 2.4 cm wavelength.
How can I determine frequency?
For the given string, L = 65.0 cm = 0.65 m and v = 254.8 m/s. The next two higher resonant frequencies can be calculated as:
f_2 = 2(v/2L) = (2)(254.8 m/s)/(2)(0.65 m) = 196.0 Hz x 2 = 392 Hz
f_3 = 3(v/2L) = (3)(254.8 m/s)/(2)(0.65 m) = 196.0 Hz x 3 = 588 Hz
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two identical spring-mass systems are allowed to oscillate. system a oscillates vertically while system b oscillates horizontally. if both systems have the same initial spring stretch, which system will experience the largest maximum velocity?
If two spring-mass systems that are similar to one another are permitted to oscillate, system a will oscillate vertically while system b will oscillate horizontally. System A has the highest possible maximum velocity.
It is possible for a spring-mass system to oscillate vertically. T denotes the duration of the oscillation. The system is then launched into a low orbit around the earth. The total energy is the sum of the kinetic and potential energies because there are no dissipative forces in the SHM of the mass and spring system.
A mass hung on a spring will oscillate after being shifted. The period of the oscillation depends on the mass and stiffness of the spring. Data logging is used in this experiment to investigate the period, displacement, velocity, and acceleration of the output from a motion sensor.
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as part of an exercise program, a woman walks south at a speed of 2.00 m/s for 60.0 minutes. she then turns around and walks north a distance 3000 m in 30.0 minutes. what is the woman's average velocity during her entire motion?
The woman's average velocity during her entire motion is 0.823m/s.
Distance traveled in the south = 60×60×2= 7200m
Distance traveled in the North = 3000m
Net Displacement = 7200-3000= 4200m
Average velocity= Net Displacement /Time = 4200m / (60+25)×60= 0.823m/s.
The pace is the directional speed of an item in motion as a demonstration of its price of alternate in the role as observed from a specific body of reference and as measured via a particular widespread of time (e.g. 60 km/h northbound). speed is a fundamental concept in kinematics, the branch of classical mechanics that describes the motion of our bodies.
Velocity is a bodily vector amount; each significance and route are needed to define it. The scalar absolute value (significance) of speed is known as velocity, being a coherent derived unit whose quantity is measured inside the SI (metric device) as meters in step with second (m/s or m⋅s−1). as an example, "5 meters in step with 2d" is a scalar, whereas "5 meters consistent with 2nd east" is a vector. If there is a trade-in velocity, route, or each, then the object is stated to be present process an acceleration.
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PLS HELP ME
a uniform metre rule of mass 150g is pivoted at the 60cm mark.calculate the mass which when hung at the 85cm mark will balance the ruler horizontally
The mass which when hung at the 85cm mark will balance the ruler horizontally is 600 g.
What is the mass that balances the meter rule?
The mass which when hung at the 85cm mark will balance the ruler horizontally is calculated as follows;
( 150 g x 60 cm ) = ( 85 cm - 60 cm) m
( 150 g x 60 cm ) = ( 15 cm) m
where;
m is the mass that will balance the meter rule horizontallyThe mass which when hung at the 85cm mark is calculated as
m = ( 150 g x 60 cm ) / ( 15 cm )
m = 600 g
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in 2005, jarno trulli was the pole winner of the u.s. grand prix race with a speed of 133 mi per hr. what was his speed in cm/s?
With such a pace of 133 miles per hour, Jarno Trulli won the pole position for the U.S. Main Event Race in 2005. How fast was he moving, in cm/s inches x 10 S Jarno Trulli has been the pole winner in 2005.
What makes position crucial in physics?
Position is a crucial piece of knowledge in physics because many motion equations depend on it. A location is precisely defined in physics as a place of origin or being. It is typically shown as an x-y axis diagram. The origin of something is where it first began.
What is the formula for positions?
The position formula is shown as. Whereas the body's initial location is x 1, its final position upon dislocation is x 2. When a shift in position occurs, the displacement changes at a rate of x.
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7. Determine what happens to the wavelength when the
waves change between the following parts of the
electromagnetic spectrum.
Infrared to Radio waves:
Radio waves to Microwaves:
Ultraviolet to gamma rays:
Gamma rays to X-rays:
Infrared to Ultraviolet:
Yellow to blue:
Green to orange:
Infrared to red:
Ultraviolet to violet:
At the point when waves change starting with one medium then onto the next, the frequency of the wave changes relying upon the properties of the two mediums.
What befalls the frequency when the waves change between the accompanying pieces of the electromagnetic range?Infrared to Radio waves: Frequency increments
Radio waves to Microwaves: Frequency diminishes
Bright to Gamma beams: Frequency diminishes
Gamma beams to X-beams: Frequency diminishes
Infrared to Bright: Frequency diminishes
Yellow to blue: Frequency diminishes
Green to orange: Frequency increments
Infrared to red: Frequency increments
Bright to violet: Frequency diminishes
At the point when waves change starting with one medium then onto the next, the frequency might change relying upon the refractive lists of the two media.
Assuming the refractive list of the subsequent medium is more noteworthy than the first, then, at that point, the frequency will diminish. In the event that the refractive record of the subsequent medium is lower than the first, then, at that point, the frequency will increment.
The electromagnetic spectrum is what?The spectrum of all EM radiation is known as the electromagnetic (EM) spectrum. The visible light from your house's lamp and the radio waves from a radio station are both examples of electromagnetic radiation, which is energy that moves and spreads out.
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a monatomic ideal gas undergoes an isothermal expansion at 300 k, as the volume increased from 0.020 m3 to 0.040 m3. the final pressure is 120 kpa. how much heat energy is transferred to or from the gas? the ideal gas constant is r
The heat energy is transferred to or from the gas is 1.73 Joule. The result is obtained by using the heat energy formula in isothermal process.
What is the heat energy in isothermal process?In isothermal process, where the temperature is constant, the internal energy also does not change.
ΔU = Q - W = 0
It makes
Q = W
W = nRT ln (V₂/v₁)
Where
Q = heat energy (J)W = work (J)n = number of molesR = ideal gas constant (8.31 JK⁻¹mol⁻¹)T = temperature of the system (K)V₁ & V₂ = Volume of the gas (m³)We have a monoatomic ideal gas undergoes an isothermal expansion.
T = 300 KV₁ = 0.020 m³V₂ = 0.040 m³P₂ = 120 kPaFind the heat energy transferred to or from the gas!
Since it is in isothermal process, the heat energy transferred is
Q = W
Q = nRT ln (V₂/v₁)
Q = 1(8,31)(300) ln (0.040/0.020)
Q = 2.493 ln 2
Q = 1.73 Joule
Hence, the transferred energy in the isothermal process is 1.73 Joule.
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A fire engine is moving at 40 m/s and sounding its
horn. A car in front of the fire engine is moving at
30 m/s, and a van in front of the car is stationary.
Which observer hears the fire engine's horn at a
higher pitch, the driver of the car or the driver of
the van?
The driver of the van will hear a higher pitch due to his higher relative velocity.
What is relative velocity?The relative velocity of an object is the velocity of the object with respect to a stationary observer.
If a fire engine is moving at 40 m/s and sounding its horn. Also if A car in front of the fire engine is moving at 30 m/s, and a van in front of the car is stationary.
The relative velocity of the stationary van is calculated as;
Vv = -40m/s - 30 m/s = - 70 m/s
The driver of the van will hear a higher pitch since his combined relative velocity of both cars is 70 m/s.
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What are the byproducts of nuclear energy and what are the options for disposing of the waste?
Nuclear energy production generates several byproducts, including spent nuclear fuel and high-level radioactive waste. These byproducts pose a significant challenge for safe disposal and management.
There are several options for disposing of nuclear waste, including:
Deep geological disposal: This involves burying the waste in deep geological formations, such as salt mines or clay deposits, where it will be isolated from the biosphere for a very long time.
Reprocessing: This involves separating reusable materials from spent nuclear fuel, with the remaining waste being further processed and prepared for disposal.
Interim storage: This involves temporarily storing waste in secure facilities until a permanent disposal solution can be found.
Ocean dumping: This involves disposing of waste in the deep ocean, which is currently banned under international agreements.
The most widely accepted method of disposing of high-level radioactive waste is deep geological disposal. However, the implementation of this method requires significant investment, public acceptance, and technical expertise, and is currently only being carried out in a few countries. As the amount of nuclear waste continues to grow, it is important for countries to develop safe and sustainable disposal solutions to protect human health and the environment.
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an aluminum wire having a cross-sectional area equal to 6.00 10-6 m2 carries a current of 6.50 a. the density of aluminum is 2.70 g/cm3. assume each aluminum atom supplies one conduction electron per atom. find the drift speed of the electrons in the wire.
The drift speed of the electrons in the aluminum wire is 9.32 x 10¹⁹ meters per second.
The drift speed of electrons in a wire can be calculated using the equation:
drift speed = current / (charge density x cross-sectional area)
where charge density is the number of charges per unit volume and is given by:
charge density = current / (number of electrons per atom x drift speed x cross-sectional area)
Since each aluminum atom supplies one conduction electron per atom, the number of electrons per atom is equal to Avogadro's number (NA) and can be calculated as follows:
number of electrons per atom = NA = 6.022 x 10²³ atoms/mol
The number of moles of aluminum in the wire can be calculated using the density and the cross-sectional area:
number of moles = mass / (density x molar mass)
where mass = volume x density and volume = cross-sectional area x length
mass = cross-sectional area x length x density
number of moles = cross-sectional area x length x density / (density x molar mass)
= cross-sectional area x length / molar mass
Finally, the charge density can be calculated:
charge density = current / (number of electrons per atom x drift speed x cross-sectional area)
= current / (NA x drift speed x cross-sectional area)
Substituting this into the equation for drift speed:
drift speed = current / (charge density x cross-sectional area)
= current / (current / (NA x drift speed x cross-sectional area) x cross-sectional area)
= NA x drift speed / current
So, we have a simple equation:
drift speed = NA / current = 6.022 x 10²³ atoms/mol / 6.50 A
drift speed = 9.32 x 10¹⁹ m/s
So, the drift speed of the electrons in the aluminum wire is 9.32 x 10¹⁹ meters per second.
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counters
10
10
с
Alec has 14 fins to put on 3 bottle rockets. He puts the same
number of fins on each rocket, and he uses as many fins as he can.
How many fins does Alec put on each rocket?
Alec puts
fins on each rocket.
14 ÷ 3
Alec put 4 fins on each rocket.
Word problemAlec has a total of 14 fins to put on 3 rockets. To find out how many fins he puts on each rocket, we can divide the total number of fins by the number of rockets:
14 fins ÷ 3 rockets = 4 with 2 left over
Since he uses as many fins as he can on each rocket, he must put 4 fins on each of two rockets and 6 fins on the third rocket (for a total of 4+4+6 = 14 fins).
Thus, Alec puts 4 fins on each rocket.
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where run vertically, annex a of nfpa 72 recommends a separation of one foot for the outgoing and return conductors of ? circuits.
Fire detection pull stations are referred to as "manual fire alarm boxes" in NFPA 72.The code stipulates that a specific floor's closest pull station shall be no and over 200 feet away.
NFPA 72's scope of application?NFPA 1, Fire Code, makes numerous references to NFPA 72.The principal section of the Code governing detection, alarm, & communication systems is 13.7.
What is level 1 of the NFPA 72 pathway survivability?Pathway resiliency In accordance to NFPA 13, Level 1 shall include any connecting wires, cables, or even other physical paths that are properly covered by an automated sprinkler system, as well as any such pathways that are covered by metal wire harnesses or metal-armored cables.
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the reaction to the force in part a is a force of magnitude , exerted on the by the . its direction is .
The reaction to the force in Part A is a force of magnitude 5 N exerted on the earth by the book. Its direction is upward.
What is Force?Force may be characterized as a process involving pushing or pulling upon an object that significantly results from the object's interaction with another object. Whenever an interaction between two things, takes place, there is a force upon each of the entities.
According to the context of this question, the direction of the force on the first object is opposite to the direction of the force on the second object. Forces always come in pairs like equal and opposite action-reaction force pairs.
Therefore, the reaction to the force in Part A is a force of magnitude 5 N exerted on the earth by the book. Its direction is upward.
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What is the coefficient of kinetic friction if a car going at 20 m/s stops in 50 m?
The car that slows down to 20 m/s stopped 50 meters away. Assume a slowness is always present. The friction coefficients for static and dynamic surfaces are 0.5 and 0.03, respectively and the coefficient of kinetic friction is 0.203.
What function do coefficients serve?an amount or signal that increases a quantity or signal
Three is employed to measure some attribute as both the exponent to x in the expression 3x.
The coefficient could be adverse?In addition to other sorts of numbers, coefficients can always be fractions, whole numbers, positive, negative, irrational, and more. Deleterious coefficients include those with negative values, to put it simply. Any negative integer, such as -8 in the formula -8z or -11 in the expression -11xy, can be a negative coefficient.
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in 2.0 minutes, a ski lift raises 5 skiers at constant speed to a height of 115 m. the average mass of each skier is 65 kg. what is the average power provided by the tension in the cable pulling the lift?
Average power provided by the tension in cable when 5 skiers where uplift is 176.04watt.
We can characterize power as the speed of taking care of business, it is the work done in unit time. The SI unit of force is Watt (W) which is joules each second (J/s). Once in a while the force of engine vehicles and different machines is given concerning Strength (hp), which is roughly equivalent to 745.7 watts.We can characterize normal power as the complete energy consumed separated by the all out time taken. In basic language, we can say that typical power is the typical measure of work done or energy changed over per unit of time.
We know that power is the ratio of the work done to the respective time taken
here,work done is the potential energy at height of 115m which is equla to mgh.
Now,weight of 5 skiers is =65×5kg=325kg.
Now,potential energy of 5 skiers is 325×65=21125Joules.
Total time taken =2min=2×60=120sec.
Therefore,power provided by the tension in cable is 21125/120=176.04Watt.
Hence,power provided by the tension in cable is 176.04watt.
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a lion can produce a roar with a sound intensity level of 114 db at a distance of 1.00 m . what is the sound intensity level at a distance of 4.00 m ? assume that intensity obeys the inverse-square law. express your answer in decibels using three significant figures.
A lion can produce a roar with a sound intensity level of 114 db at a distance of 1.00 m . The intensity level at 4 m from the lion is 16 DB.
The decibel, or dB, is widely used to measure sound levels even though it is a measurement of pressure rather than sound. A decibel is a logarithmic unit used to indicate the relationship between a physical quantity and a reference level.
The square of the distance and the decibel intensity are inversely related.
I₂ = D₁²
I₁ D₂²
The sound intensity level at one meter is 114 dB.
I₂ = 1²
114 4²
I₂ = 16 Db
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a fluid flows along a streamline from point 1 to point 2 in a constant diameter, horizontal pipe with no pressure change. if viscous effects are considered, which point has more energy?
At point 1 has more energy. The pipe's narrowest section has the lowest velocity, while its broadest section has the lowest pressure.
Why is the pipe's widest section where pressure is highest?Fluid molecules were able to exert greater pressure as the velocity lowers than when they're traveling swiftly, when some of their pressure may be partially dissipated toward their motion or velocity. As a result, the pressure is highest where the pipe is the broadest and the velocity of the fluid is lowest.
Does pipe diameter affect pressure?Water velocity and pipe diameter are interdependent in a water-flowing pipeline. The pressure inside a pipe will inevitably increase as its diameter lowers. According to the scientific method, the area for conveyance can be lowered in order to lower pressure.
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if a system of pulleys contains more than one cord, relate the position of a point on one cord to a point on another cord. how many equations are required? group of answer choices one one per cord twice the number of cords
The number of equations required to relate the position of a point on one cord to a point on another cord in a system of pulleys with more than one cord is equal to twice the number of cords.
In a system of pulleys with more than one cable, the number of equations needed to connect the location of a point on one cord to a point on another chord is equal to twice the number of cords. This is because for each cord, an equation is needed to describe its position as a function of time, and another equation is needed to describe its velocity as a function of time.
In a system of pulleys with more than one cable, the number of equations needed to connect the location of a point on one cord to a point on another chord is equal to twice the number of cords. This is due to the necessity for two equations: one to describe each cord's position as a function of time and another to explain its velocity as a function of time.
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The complete question is
if a system of pulleys contains more than one cord, relate the position of a point on one cord to a point on another cord. how many equations are required? group of answer choices
a. one one per cord
b. twice the number of cords
c. thrice the number of cords
d. none of the above
what do we call waves in matter that transmit energy through particle motion? what nonmaterial waves consist of pure energy
A mechanical wave is a vibration of matter, a wave responsible for the transmission of energy through a medium.
His four examples of mechanical waves?
Creeping waves, water waves, stadium waves, and jump rope waves are other examples of mechanical waves. Everyone needs a medium to exist. A Slinky wave requires a Slinky turn. Water waves needs the water. Stadium waves need stadium fans. A jump rope wave requires a jump rope.
What are the sources of mechanical waves?
Mechanical waves are created by interactions between adjacent particles in a medium. This interaction transfers energy and momentum from one particle to the next, and the net effect is to pass these quantities from the source to the receiver.
What is important in mechanical waves?
A mechanical wave is a wave that requires a medium to carry energy from one place to another. Mechanical waves cannot travel through particle-free regions of space because they rely on particle interactions for energy transport.
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