A 75.0-kg athlete performs a single-hand handstand. If the area of the hand in contact with the floor is 125 cm2, what pressure is exerted on the floor

Answers

Answer 1

The pressure exerted on the floor by the athlete having a mass of 75 Kg is 58800 N/m²

How to determine the force

Mass (m) = 75 KgAcceleration due to gravity (g) = 9.8 m/s²Force (F) =?

F = mg

F = 75 × 9.8

F = 735 N

How to determine the pressure Force (F) = 735 NArea (A) = 125 cm² = 125×10¯⁴ m²Pressure (P) =?

P = F / A

P = 735 / 125×10¯⁴

P = 58800 N/m²

Thus, the pressure exerted on the floor is 58800 N/m²

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Related Questions

hi how are you toady



what does it mean????

Answers

Answer:

Am doing well am fine thank you

my day was good i really did do nun but start on my essay

What is the net force acting on a car cruising at a constant velocity of 70 km/h (a) on a level road, (b) on an uphill road?

Answers

The net force on the car for either case will be zero, since the car is moving at a constant velocity.

Net force on the car

The net force on the car is the sum of all the forces acting on the car.

∑F = ma

When the car is on a level road

When the car is on a level road, the only two forces acting on the car is the applied force and frictional force of the road.

F - Ff = 0

The net force will be zero, since the car is moving at a constant velocity.

When the car is on uphill

The forces acting on the car at the uphill is the applied force, weight of the car acting downwards and the frictional force acting opposite direction.

F - Wsinθ - μFₙcosθ = 0

The net force will be zero, since the car is moving at a constant velocity.

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List the even numbers between 3 and 13 in set
notation

Answers

Answer:

{2,4,6,8,10,12}

Explanation:

Even Numbers

Any number that can be exactly divided by 2 is called an even number.

The even numbers between 3 and 13, written in set notation, are:

{2,4,6,8,10,12}

Answer:

4, 6, 8 , 10, 12

Explanation:

List the even numbers between 3 and 13 in set

notation

[4, 6, 8 , 10, 12]

thanks

Help me real quick someone

Answers

Explanation:

10 ......

.....

.....

.....

.....

The wavelength of a wave is less than
450 nanometers. Which color would this wave most likely appear
?

Answers

Answer:-

[tex]\longrightarrow \sf Indigo [/tex]

Solution:-

The color and their corresponding wavelength ranges are given in the table below.

[tex]\begin{gathered}\begin{gathered}\boxed{\begin{array}{c|c} \bf colour & \bf wavelength\\ \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf red & \sf 650 - 700 \\ \\ \sf orange & \sf 600 - 650 \\ \\ \sf yellow & \sf \: 580 - 600 \\ \\ \sf green & \sf 550 - 580 \\ \\ \sf cyan & \sf 500 -550 \\ \\ \sf \: blue& \sf450 - 500\\ \\ \sf indigo & \sf 425- 450\\ \\ \sf violet & \sf 380 - 425 \end{array}} \\ \end{gathered}\end{gathered}[/tex]

After observing the table, we can predict that wave is most likely appear Indigo.

Note- The wavelengths boundaries between the colours are not very sharp and they form a continuous spectrum.

A certain spring stretches 15 cm when a load of 50.0 N is suspended from it. How much will the spring stretch if 78N is suspended from it

Answers

Answer:

23.4 cm

Explanation:

15 : 50 = x : 78

15*78 = 50x

x = 15*78/50 = 23.4 cm

The spring stretch is, 23.4 cm.

What is the stretch of the spring?Potential energy that is stored as a result of the deformation of an elastic item, such as the stretching of a spring, is known as elastic potential energy. It is equivalent to the work required to stretch the spring, which depends on both the length of the stretch and the spring constant, k.

What happens to a spring when you stretch it?A spring exerts a force F = -kx in the direction of its equilibrium position when it is stretched or compressed to a length that differs by an amount x from its equilibrium length. A spring's force acts to return the spring to its equilibrium length; it is a restoring force.

What causes a spring to stretch?A typical spring is a tightly wrapped metal coil or spiral that stretches when pulled (by applying force) and returns to its original shape when released (remove the force). A spring is elastic, in other words.

According to the question:

15 : 50 = x : 78.

15×78 = 50x.

x = 15×78/50.

  = 23.4 cm.

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What is the force with which a body

is attracted by the earth towards its centre?

| वह कौन सा बल है जिसके कारण कोई भी

व्तुपर्थृवी के केंद्र की ओर आक र्तष होती है?

A : Mass | द्रव्यमान

B : Weight | भार

C : Volume | आयतन

D : Density | घनत्व
Ans:
B : Weight | भार

Answers

Answer:

Explanation:

Gravity

Gravity is the force by which a planet or other body draws objects toward its center. The force of gravity keeps all of the planets in orbit around the sun.

Danielle took an iron nail and wrapped thin copper wire around it, then connected the ends of the copper wire to a battery. Which two forces can Danielle's device produce?

A. electrical force and frictional force

B. electrical force and magnetic force

C. frictional force and gravitational force

D. magnetic force and gravitational force

Answers

Answer:

It's B (electrical force and magnetic force) I just took the test.

The two forces can Danielle's device produce will be an electrical force and magnetic force. Daniel forms a coil resulting in both forces.

What is electric force?

Electric Force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force. it is the ratio of voltage to the distance between them.

Danielle took an iron nail and wrapped thin copper wire around it, then connected the ends of the copper wire to a battery.

A coil of wire that carries an electric current is a solenoid. A solenoid is an electromagnet formed by a helical coil of wire. Which generates a magnetic field when an electric current is passed through the coil.

A solenoid is a form of coil that produces a magnetic field when the electric current is passed through it. A solenoid is created when a conductive wire is used to make a loop.

The two forces can Danielle's device produce will be an electrical force and magnetic force. Daniel forms a coil resulting in both forces.

Hence option B is correct.

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How was the 6th quark discovered?

Answers

Answer:

A team of scientists in Geneva, headed by Professor of Physics Carlo Rubbia, has found evidence of a sixth kind of quark, one of the most sought after discoveries in modern physics. ... Rubbia developed this particular proton collision method and has been working with it since the late 1970s

The force that keeps objects moving in a circle is called centripetal force. A. True B. False​

Answers

Answer:

true

Explanation:

look it up

hope this helped u ;)

Answer:

True

Explanation:

Took The Test

How do you write numbers in
scientific notation? Explain
with an example.

Answers

Answer:

3.34x10*5

Explanation:

this is just a example.

take 3 sig.fig

Why do water wet glass ?​

Answers

Answer:

Forces of attraction between a liquid and a solid surface are called adhesive forces. ... Water wets glass and spreads out on it because the adhesive forces between the liquid and the glass are stronger than the cohesive forces within the water.

can someone tell me if my answer correct?

Answers

Answer:

yes

Explanation:

yes to my best known knowledge I am thinking that your answer is correct

In some amazing situations, people have survived falling large distances when the surface they land on is soft enough. During a traverse of Eiger's infamous Nordvand, mountaineer Carlos Ragone's rock anchor gave way and he plummeted 515 feet to land in snow. Amazingly, he suffered only a few bruises and a wrenched shoulder. Assuming that his impact left a hole in the snow 3.5 ft deep, estimate his average acceleration as he slowed to a stop (that is while he was impacting the snow). Pick a coordinate system where down is positive.

Answers

Have you seen my dad?

Consider a 35-L evacuated rigid bottle that is surrounded by the atmosphere at 100 kPa and 22 ℃. A valve at the neck of the bottle is now opened and the atmospheric air is allowed to flow into the bottle. The air trapped in the bottle eventually reaches thermal equilibrium with the atmosphere as a result of heat transfer through the wall of the bottle. The valve remains open during the process so that the trapped air also reaches mechanical equilibrium with the atmosphere. Determine the net heat transfer through the wall of the bottle during this filling process. -pinterest\.\*

Answers

Answer:

3.5 KJ

Explanation:

Energy balance equation is given as;

E_in - E_out = ΔE_system

Thus;

Q_in = (m_2•u_2) - (m_i•h_i)

Now, m_i = m_2

Tbus;

Q_in = (m_2•u_2) - (m_2•h_i)

Q_in = m_2(u_2 - h_i)

Now mass of the air in the bottle is given as;

m_2 = (P_2•V)/(R•T2)

From table A-1 attached, R = 0.287 KJ/Kg.k

We are given;

P_2 = 100 kPa

V = 35 L = 0.035 m³

T2 = 22°C = 22 + 273 K = 295 K

Thus;

m_2 = (100 × 0.035)/(0.287 × 295)

m_2 = 0.04134 kg

Now, from table A-17 attached, at Temperature of 295 K, we have;

Internal energy; u2 = 210.49 KJ/Kg

Enthalpy; h_i = 295.17 KJ/Kg

From earlier, we saw that;

Q_in = m_2(u_2 - h_i)

Thus;

Q_in = 0.04134(210.49 - 295.17)

Q_in = -3.5 KJ

Thus, Q_out = 3.5 KJ

So, the net heat transfer = 3.5 KJ

As a fish jumps vertically out of the water, assume that only two significant forces act on it: an upward force F exerted by the tail fin and the downward force due to gravity. A record Chinook salmon has a length of 1.50 m and a mass of 46.0 kg. If this fish is moving upward at 3.00 m/s as its head first breaks the surface and has an upward speed of 5.80 m/s after two-thirds of its length has left the surface, assume constant acceleration and determine the following.

a. The salmon's acceleration
b. The magnitude of the force F during this interval N

Answers

Answer:

a

   [tex]a =  12.32 \  m/s^2[/tex]

b

 [tex]F = 1017.52 \  N[/tex]

Explanation:

From the question we are told that

  The  length of the Chinook salmon is  [tex]l =  1.50 \  m[/tex]

   The mass of the Chinook salmon is [tex]m  =  46.0 \ kg[/tex]

   The  upward velocity in water is  [tex]u =  3.00 \ m/s[/tex]

    The  upward velocity in air is [tex]v =  5.80 \ m/s[/tex]

   

Generally from kinematic equations

     [tex]v^2  =  u^2 +  2as[/tex]

=>    [tex] 5.80^2  =  3.00^2 +  2  *  a *  [ [\frac{2}{3} * l ][/tex]

=>   [tex] 5.80^2  =  3.00^2 +  2  *  a *  [ [\frac{2}{3} * 1.5 ][/tex]

=>   [tex] 5.80^2  =  3.00^2 +  2  *  a *  [1 ][/tex]      

=>    [tex]a =  12.32 \  m/s^2[/tex]

Generally magnitude of the force F during this interval in N  is mathematically represented as

      [tex]F  =  m (a + g )[/tex]

=>    [tex]F  =  46.0 (12.32 + 9.8 )[/tex]

=>    [tex]F = 1017.52 \  N[/tex]

A student in the Biomechanics class has decided that she would like to make her arms
stronger. She has a mass of 63 kg, She chooses to complete some elbow flexion exercises
using a kettlebell. For this problem, consider the hand and forearm to be a single segment.
The distance from her elbow to her wrist is 22.86 cm.
The force from the kettlebell is applied to her hand, which is 30.48 cm from her elbow joint.
She knows that the moment arm of the elbow extensor muscles about the elbow axis is

Answers

The resistive force from load of the kettle lifted by the arm is determined from principle of moment and the magnitude is 71 kg.

Moment of force about a point

The moment of force about a point is the product of applied force and the perpendicular distance of the force action. The moment of force about a point is equal to the torque exerted by the force.

τ = Fr

where;

F is the resistance force of the kettler is perpendicular distance

F₁r₁ = F₂r₂

925(22.86) = F₂(30.38)

696 N = F₂

in kg, m = 696/9.8 = 71 kg

Thus, the resistive force from the applied force and distance is 71 kg.

The complete question is below:

If she wants the elbow flexors to exert 925 N of force during an isometric contraction, what should the resistance force be at 90 deg of flexion (the upper arm is vertical and the forearm is parallel to the ground) in kg

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a 1000 kg car traveling at 70 m/s takes 3 m to stop under full braking. the same car under similar road conditions, traveling at 140 m/ s takes how long to stop under full braking?

Answers

Answer:

0.21 SECONDS

Explanation:

THE CAR TRAVELS AT A SPEED OF 140M/S AND A DISTANCE AS THE PREVIOUS = 3M THEREFOR S=D/T, T=D/S= 3/140= 0.12 SEC

The graph in the figure shows the position of a particle as it travels along the x-axis. What is the magnitude of the instantaneous velocity of the particle when t=1.0 s?

Answers

Answer:

pls first attach the fig.

The graph in the figure shows the position of a particle as it travels along the x-axis. The magnitude of the average speed of the particle between t = 1.0 s and t = 4.0 s is 1.3 m / s. Therefore, option B is correct.

What do you mean by average speed ?

The term average speed is defined as the total distance traveled by the object in a particular time interval.

In the kinematics studies the movement of bodies, give the relationships between position, velocity and acceleration. In the special case that the acceleration is zero the motion is known as uniform motion.

       v = Δ x / Δt

Where v is the velocity, Δx is the position variation and Δt is the time variation in the analyzed interval.

Therefore,

v =  2.0 - ( - 2.0 ) / 4.0 - 1.0

v = 1.33 m / s          

Thus, The magnitude of the average speed of the particle between t = 1.0 s and t = 4.0 s is 1.3 m / s, option B is correct.

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Your question is incomplete, most probably your question was

The graph in the figure shows the position of a particle as it travels along the x-axis. What is the magnitude of the average speed of the particle between t = 1.0 s and t = 4.0 s?

Please help!! The graph in the figure shows the position - 1, Graph is attache below in image.

PLEASE HELP ME!!!!!!!!!!
IT'S REALLY EASY I'M JUST STUPID

Explain what happens to the particles in a substance during a physical change.

Answers

Answer:

nothing lol

Explanation:

nothing changes in a physical change, particles stay the same unless a chemical change happens

Determine the equivalent capacitance of the combination shown when C = 12 n

Answers

Hi there!

Recall the following.

Capacitors in series:
[tex]C_T = \frac{1}{C_1} + \frac{1}{C_2} +...+ \frac{1}{C_n}[/tex]

Capacitors in parallel:

[tex]C_T = C_1 + C_2 + ... + C_n[/tex]

Begin by solving for the resulting capacitance of both paths.

Path on the left:
[tex]\frac{1}{C_T} = \frac{1}{2C} + \frac{1}{C} = \frac{3}{2C}\\C_T = \frac{2C}{3}[/tex]

Path on the right:
[tex]\frac{1}{C_T} = \frac{1}{C} + \frac{1}{3C} = \frac{4}{3C}\\\\C_T = \frac{3C}{4}[/tex]

Now, since we ADD capacitors in parallel, we can add the resulting capacitances together:
[tex]C_T = \frac{2C}{3} + \frac{3C}{4}[/tex]

Substitute in 12 F for C and solve.

[tex]C_T = \frac{2(12)}{3} + \frac{3(12)}{4} = \frac{24}{3} + \frac{36}{4} = 8 + 9 = \boxed{17F}[/tex]

10. The speed of a transverse wave is 15 m/s. The frequency of the wave is 2.5 Hz.
What is the wavelength? *

Answers

…………………………............

Answer:

Wavelength = 6m

Explanation:

Given that,

→ Transverse wave = 15 m/s

→ Frequency = 2.5 Hz

Then the required wavelength is,

→ Transverse wave ÷ Frequency

→ 15 ÷ 2.5

→ 15/2.5 = 6m

Hence, the wavelength is 6m.

A passenger plane is travelling down the runway with a speed of 20\,\dfrac{\text{km}}{\text{h}}20 h km ​ 20, start fraction, start text, k, m, end text, divided by, start text, h, end text, end fraction, then speeds up with constant acceleration over 2.4\,\text{km}2.4km2, point, 4, start text, k, m, end text over 59\,\text{s}59s59, start text, s, end text. We want to find the final velocity of the plane at the moment of take-off. Which kinematic formula would be most useful to solve for the target unknown?

Answers

Given that,

Initial speed, u = 20 km/s

Acceleration of plane, a = 2.4 km/h²

Time, t = 59 s

We need to find the expression to find the final velocity of an object.Let the final velocity is v.

Using the second equation of kinematics:

[tex]\Delta s=ut+\dfrac{1}{2}at^2[/tex]

a is acceleration, [tex]a=\dfrac{v-u}{t}[/tex]

So,

[tex]\Delta s=ut+\dfrac{1}{2}\times \dfrac{v-u}{t}\times t^2\\\\\Delta s=ut+\dfrac{1}{2}(v-u)t\\\\\Delta s=\dfrac{2ut+vt-ut}{2}\\\\\Delta s=\dfrac{vt+ut}{2}\\\\\Delta s=(\dfrac{v-u}{2})t[/tex]

We can use the above formula to find the final velocity (v) of the plane.

The direction of force of Earth's magnetic field is from the geographic South
Pole to the geographic North Pole. Where is Earth's magnetic north pole?
A. Near Earth's center
B. Near Earth's equator
C. Near Earth's North Pole
D. Near Earth's South Pole

Answers

Answer:d

Explanation:

Answer:

D

Explanation:

Furthermore, the magnetic pole near earth's geographic north pole is actually the south magnetic pole. When it comes to magnets, opposites attract. This fact means that the north end of a magnet in a compass is attracted to the south magnetic pole, which lies close to the geographic north pole.

i mark you branliest

Answers

Answer:

No :)

Explanation:

What can increase the number of deaths in a population?

Answers

Answer:

a pandemic?

Explanation:

i dont know if there is like a A answer and it can kill lot of people

A person is sitting at the very back of a canoe of length L, when the front just bumps into the dock. show answer No Attempt 50% Part (a) If the canoeist gets up and walks to the front of the canoe and there is no friction between the boat and the water, how far will they be from the dock

Answers

The distance of the canoeist from the dock is equal to length of the canoe, L.

Conservation of linear momentum

The principle of conservation of linear momentum states that the total momentum of an isolated system is always conserved.

v(m₁ + m₂) = m₁v₁ + m₂v₂

where;

v is the velocity of the canoeist and the canoe when they are together

u₁ is the velocity of the canoeu₂ velocity of the canoeistm₁ mass of the canoem₂ mass of the canoeist

Distance traveled by the canoeist

The distance traveled by the canoeist from the back of the canoe to the front of the canoe is equal to the length of the canoe.

Thus, the distance of the canoeist from the dock is equal to length of the canoe, L.

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Part I: Friction Parabola Track 1. Click Reset and observe the energy bars as the skater moves back and forth. As the skater descends his kinetic energy (green) ____________ and his potential energy (blue)_________. The total energy bar_____________. 2. Considering the bottom of the parabola as a reference line, measure the maximum height (h) the skater climb. h

Answers

As the skater descends his kinetic energy increases and his potential energy decreases. The total energy remains constant.

What is energy?

Energy is the ability to do work. Types of energy are potential, kinetic, thermal and so on.

Potential energy is the energy stored in an object due to its position relative to another object. Kinetic energy is the energy due to the motion of an object.

As the skater descends his kinetic energy increases and his potential energy decreases. The total energy remains constant.

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Example Compute the capacitance of a parallel-plate capacitor with plates 10cm by 20cm, separation of 5mm, and a mica dielectric.​

Answers

Answer:

Explanation:

Mica dielectric constant (k) is approximately 3. The distance between the plates is 5 mm = [tex]5\times10^{-3}[/tex] m = d and the area of each plate is[tex]A = 0.1\times 0.2=2\times 10^{-2} m^{2}[/tex]. So, the capacitance of that capacitor is:

[tex]C=\frac{\epsilon_{0}kA}{d}=\frac{(8.85\times10^{-12})(3)(2\times10^{-2}}{5\times10^{-3}}=10.62\times10^{-11} =1.062\times10^{-10} F[/tex]

or approximately 0.106 nF.

A 50 kg student who is capable of generating 700 watts of power climbs a set of stairs that is 6.5 m high. Calculate the amount of work that the student needs to do in order to climb the stairs.​

Answers

the amount of work that the student needs to do in order to climb the stairs is 3185 J

What is work?

Work can be defined as the product of force and distance.

To calculate the amount of work that the student needs to do in order to climb the stairs, we use the formula below

Formula:

W = mgh............ Equation 1

Where:

W = Work done by the student in order to climb the stairs.m = mass of the studentg = acceleration due to gravityh = height of the student

From the question,

given:

m = 50 kgg = 9.8 m/s²h = 6.5 m

Substitute these values into equation 1

W = 50(9.8)(6.5)W = 3185 J

Hence, the amount of work that the student needs to do in order to climb the stairs is 3185 J.

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