Explanation:
Force, F = 60 N
Angle, [tex]\theta=30^{\circ}[/tex]
We need to find horizontal and vertical component of the force.
Horizontal component,
[tex]F_x=F\cos\theta\\\\=60\times \cos(30)\\\\=51.96\ N[/tex]
Vertical component,
[tex]F_=F\sin\theta\\\\=60\times \sin(30)\\\\=30\ N[/tex]
So, the horizontal and vertical component are 51.96 N and 30 N respectively.
Which type of circuit would be best to use for lights used for decorations? Question 1 options: Series circuit. One bulb could go out and the strand will stay on. Series circuit. One bulb could go out and the rest go out. Parallel circuit. One bulb goes out and the rest go out. Parallel circuit. One bulb could go out and the strand will stay on.
Answer:
One bulb could go out and the strand will stay on.
Explanation:
In series circuit, there is only one path provided for the current to flow. So, all the lights are required to be in working condition, for the others to work. And if anyone light bulb goes out, the circuit will become incomplete and the rest of the strand will also go out. Because there is only one path for current flow which is now broken.
On the other hand, in parallel circuits, each light bulb has a separate connection with the source. Current path to each bulb is independent of the others. Therefore, if one bulb goes out, the rest of the strand will stay on.
So, the correct option is:
One bulb could go out and the strand will stay on.
Assuming perfect optics, if the smallest feature you can resolve when observing around 660 nm is of angular size 0.04 arcsec, what would the size (in arcsec) of the finest feature you can resolve if you make your observation around wavelength 1320 nm, assuming everything else is the same
Answer:
The value is [tex]\theta _2 = 0.08 \ arcsec[/tex]
Explanation:
From the question we are told that
The first wavelength is [tex]\lambda_1 = 660 \ nm = 660 *10^{-9 }[/tex]
The first angular size is [tex]\theta_1 = 0.04 \ arcsec[/tex]
The second wavelength is [tex]\lambda _2 = 1320 \ nm = 1320 *10^{-9 } \ m[/tex]
Generally according to Rayleigh Criterion we have that
[tex]\theta= 1.22 * \frac{\lambda }{D}[/tex]
given every other thing remains constant we have that
[tex]\theta = k * \lambda[/tex]
Here k represented constant so
[tex]k = \frac{\theta }{\lambda}[/tex]
=> [tex]\frac{\theta_1}{ \lambda_1} = \frac{\theta_2}{ \lambda_2}[/tex]
=> [tex]\frac{\theta_1}{ \theta_2} = \frac{\lambda_1}{ \lambda_2}[/tex]
So
[tex]\frac{ 0.04}{ \theta_2} =0.5[/tex]
=> [tex]\theta _2 = 0.08 \ arcsec[/tex]
These steps are involved in the production of work by a four-stroke heat engine. Place the steps in the correct order. Piston moves up, compressing gas and causing gas to increase its temperature: Piston moves up, pushing burned gases through exhaust valve: 1 Spark plug fires, causing combustion as gas is still compressed; increase in energy from combustion pushes piston down: Piston moves down, allowing fuel-air mixture to enter intake valve:
Answer:
correct order 2,4,3,1
Explanation: correct on edge
A. 230 N
B. 194 N
C. 250 N
D. 340 N
Answer:
I think C 250 it is correct
23 POINTS!! will get brainiest
What is the relationship between temperature range and proximity to the coast?
Answer:I think it’s because both can provide heat and cold
Explanation:
Describe the energy transfers and transformations for a javelin, starting from the point at which an athlete picks up the javelin and ending when the javelin is stuck into the ground after being thrown.
Explanation:
When the Javelin is at rest on the ground, Potential Energy and Kinetic Energy are zero. immediately the Athlete picks the javelin up from the ground, there is an increase in the Kinetic Energy this increase continues until the javelin comes to a halt. Potential Energy also increases.
As the Athlete throws javelin, there is a decrease in the Potential Energy, the Kinetic Energy increases simultaneously until the javelin hits the ground.
after which Potential Energy and Kinetic Energy becomes zero.
An object that floats in water weighs 20 N in air.
a. What is the weight of the object in water?
b.What is the Upthrust acting on the object in water?
c. What is the weight of the water displaced by the object?
Answer:
a. Weight of Object in Water = 20 N
b. Up thrust = 20 N
c. Weight of Water Displaced = 20 N
Explanation:
a.
The weight of the object remains same in the water as well. Because, the same force of gravity is acting there as well. Hence,
Weight of Object in Water = 20 N
b.
Since, the object floats on the water. Therefore, according to Archimedes' principle the up thrust force acting on the object must be equal to the weight of object:
Up thrust = Weight of object
Up thrust = 20 N
c.
From Archimedes' Principle, we know that the up thrust or the Buoyant force is equal to the weight of the water displaced by the object. therefore:
Weight of Water Displaced = Up thrust
Weight of Water Displaced = 20 N
Aner shopping. It took Jacob 18 seconds to push his shopping cart to his car. He was moving at 2 meters per second. His daughter walked beside the cart for one-third of the time it took Jacob to reach his car. How far did Jacob's cart move while his daughter was walking beside Write your answer as a whole number meters
Answer:
I am going to answer you just wait a little bit.
A block of wood of length L = 21.0 cm, width w = 9.53 cm, and height h = 5.92 cm is just barely immersed in water by placing a mass m on the top of the block. The density of the wood is rho = 0.390 g/cm^3. The value of m is:______
a. 0.72 kg
b. 1.2 kg
c. 1.6 kg
d. 7.1 kg
e. 0.36 kg
Answer:
0.462kg
Explanation:
Density = Mass/Volume
Given
Density of the wood = 0.390 g/cm^3
Volume of the wood = Length * Width * Height
Volume = 21 * 9.53 * 5.92
Volume = 1,184.7696cm³
Get the mass m;
mass = density * volume
mass = 0.390 * 1,184.7696
mass = 462.060144g
The mass in kg is 0.462kg
What is black body radiation? Explain in detail.
An object that absorbs all radiation falling on it, at all wavelengths, is called a black body. When a black body is at a uniform temperature, its emission has a characteristic frequency distribution that depends on the temperature. Its emission is called black-body radiation
hope it helps
Light of intensity So and polarized horizontally passes through three polarizes. The first and third are horizontal, but the second is oriented 0.3927 rad to the horizontal. In terms of So , what is the intensity of the light that passes through the set of polarizers
Answer: the intensity of the light that passes through the set of polarizers is 0.7285 S₀
Explanation:
based on the data in the question;
As the first polarizer lets all the light through because its plane of polarization is not different from light.
The second polarizer has 2 effects;
firstly, it reduces the intensity by a factor cos²0.3927^c; if you switch the calculator to radians mode, this will give you 0.85355
Secondly; it changes the plane of polarization of the light to be the same as the polarizer; therefore the light now has a plane of polarization of 0.3927 rad to the horizontal.
Hence;
after the second effect, the light enters the third polarizer at 0.3927 rad to the plane of polarization of third polarizer. So the intensity is again reduced by a factor 0.85355.
Therefore
the Overall reduction is by a factor of 0.85355 × 0.85355 S₀
= 0.7285 S₀
Therefore the intensity of the light that passes through the set of polarizers is 0.7285 S₀
Does anyone know the answer to this page and the next one that it has?
Young's double slit experiment is one of the quintessential experiments in physics. The availability of low cost lasers in recent years allows us to perform the double slit experiment rather easily in class. Your professor shines a green laser (568 nm) on a double slit with a separation of 0.107 mm. The diffraction pattern shines on the classroom wall 3.5 m away. Calculate the fringe separation between the third order and central fringe.
Answer:
18.58 mm
Explanation:
Formula for the fringe width is;
β = λL/d
We are given;
λ = 568 nm = 568 × 10^(-9) m
L = 3.5 m
d = 0.107 mm = 0.107 × 10^(-3) mm
β = (568 × 10^(-9) × 3.5)/(0.107 × 10^(-3))
β = 0.01858 m = 18.58 mm
A woman exerts a horizontal force of 3 pounds on a box as she pushes it up a ramp that is 10 feet long and inclined at an angle of 30 degrees above the horizontal. Find the work done on the box.
Answer: 67 how much candy does nick have
Explanation:
A space probe is sent to an alien planet and conducts an experiment in order to determine the acceleration due to gravity on the planet. It produces the following table
Object Rock Grain of sand Metal bolt
Mass 20 grams 0.8 grams 79 grams
Recorded force of gravity :0.1224 N 0.00501 N 0.4871 N
Given this data, which of the following the closest approximation of the acceleration due to gravity on this planet
a
3.8 m/s^2
b
4.0 m/s^2
c
9.9 m/s^2
d
6.1 m/s^2
Answer: D. 6.1 m/s^2
Explanation:
A ball of clay is thrown at a wall at a velocity of 28.0 m/s. After it hits the wall, it
takes 0.020 s to stop. What is the acceleration of the clay when it hits the wall?
Answer:
Explanation:
1400 m/s2
The acceleration of the ball when it hits the vertical wall is -1,400 m/s²
The given expression:
velocity of the ball, v = 28 m/s
time of motion of the ball, t = 0.02 s
To find:
the acceleration of the ball when it hits the vertical wall.The acceleration of the ball is calculated as follows:
[tex]acceleration = \frac{\Delta velocity}{\Delta time} = \frac{Final \ velocity\ - \ initial \ velocity }{time} \\\\final \ velocity \ of \ the \ ball \ when \ it \ hits \ the \ wall = 0\\\\acceleration = \frac{0 - 28}{0.02} \\\\acceleration = - \ 1,400 \ m/s^2[/tex]
Thus, the acceleration of the ball when it hits the vertical wall is -1,400 m/s²
Learn more here: https://brainly.com/question/14109204
A golfer shoots a ball horizontally off a cliff with a speed of 80.0 m/s, and it lands 471m from the base of the cliff.
1. How long is the golf ball in the air?
2. What is the height of the cliff?
3. What is the golf ball/s speed when it lands?
Answer:
1. t = 5.89 s
2. h = 170 m
3. Vf = 57.8 m/s
Explanation:
1.
First, we analyze the horizontal motion of the golf ball. Assuming the air friction to be negligible, the horizontal motion will be uniform. So, e can use the following equation:
[tex]s = vt[/tex]
where,
s = horizontal distance covered by the golf ball = 471 m
v = horizontal speed of golf ball = 80 m/s
t = time taken by the golf ball in air = ?
Therefore,
[tex]471\ m = (80\ m/s)t\\\\t = \frac{471\ m}{80\ m/s}\\\\[/tex]
t = 5.89 s
2.
Now, we analyze the vertical motion. Using 2nd equation of motion:
[tex]h = v_{i}t + \frac{1}{2}gt^2[/tex]
where,
h = height of cliff = ?
vi = vertical component of initial speed of ball = 0 m/s(ball was shot horizontally)
g = acceleration due to gravity = 9.81 m/s²
t = time of flight = 5.89 s
Therefore,
[tex]h = (0\ m/s)(5.89\ s) + \frac{1}{2}(9.81\ m/s^2)(5.89\ s)^2[/tex]
h = 170 m
3.
Now, we can use 1st equation of motion:
[tex]v_{f} = v_{i} + gt\\v_{f} = 0 m/s + (9.81\ m/s^2)(5.89\ s)\\[/tex]
Vf = 57.8 m/s
When two objects collide is the momentum before equal to the momentum after the collision? What happens to the individual carts momentum in terms of momentum before and after collision?
Answer:
a collision occuring between two objects in an isolated system, the total momentum of the two objects after the collision. That is, the momentum lost by object 1 is equal to the momentum gained by object 2.
thank you.
An arrow is shot straight up in the air at an initial speed of 15 m/s. After how much time is the arrow heading downward at a speed of 8 m/s?
Answer:
2.35 seconds
Explanation:
Remark
This is a question where direction matters. Let us call down + and up minus. It won't matter. The answer will be the same.
Formula
a = (vf - vi)/t
Givens
a = 9.8 m/s^2
vi = - 15 m/s
vf = 8m/s
Solution
9.8 = (8 - - 15)/t Multiply both sides by t
t * 9.8 = 23 Divide by 9.8
t = 23/9.8
t = 2.35 s
The moment of inertial of the hoop yo-yo when it is: (a) rotating about its center of mass, and (b) rotating about the point where the tension force is applied
mass=332g
diamater=35.9cm
thickness.95cm
Answer:
a) The moment of inertia of the hoop yo-yo rotating about its center of mass is [tex]I_{g} = 0.0108\,kg\cdot m^{2}[/tex].
b) The moment of inertial of the hoop yo-yo rotating about its center of mass is [tex]I_{O} = 0.0216\,kg\cdot m^{2}[/tex].
Explanation:
a) The hoop yo-yo can be modelled as a tours with a minor radius [tex]a[/tex], related with the thickness, and with a major radius [tex]b[/tex], related with the diameter, and with an uniform mass. The momentum of inertia about its center of mass ([tex]I_{g}[/tex]), measured in kilogram-square meters, which is located at the geometrical center of the element, is determined by the following formula:
[tex]I_{g} = \frac{1}{4}\cdot m \cdot (4\cdot b^{2}+3\cdot a^{2})[/tex] (1)
[tex]b = 0.5\cdot D[/tex] (2)
[tex]a = 0.5\cdot t[/tex] (3)
Where:
[tex]D[/tex] - Diameter, measured in meters.
[tex]t[/tex] - Thickness, measured in meters.
[tex]m[/tex] - Mass, measured in kilograms.
If we know that [tex]m = 0.332\,kg[/tex], [tex]D = 0.359\,m[/tex] and [tex]t = 9.5\times 10^{-3}\,m[/tex], then the moment of inertia of the hoop yo-yo is:
[tex]a = 0.5\cdot (9.5\times 10^{-3}\,m)[/tex]
[tex]a = 4.75\times 10^{-3}\,m[/tex]
[tex]b = 0.5\cdot (0.359\,m)[/tex]
[tex]b = 0.180\,m[/tex]
[tex]I_{g} = \frac{1}{4}\cdot (0.332\,kg)\cdot [4\cdot (0.180\,m)^{2}+3\cdot (4.75\times 10^{-3}\,m)^{2}][/tex]
[tex]I_{g} = 0.0108\,kg\cdot m^{2}[/tex]
The moment of inertia of the hoop yo-yo rotating about its center of mass is [tex]I_{g} = 0.0108\,kg\cdot m^{2}[/tex].
b) The hoop yo-yo rotate at a point located at a distance of half diameter from the center of mass of the element, whose moment of inertia is determined by the Theorem of Parallel Axes:
[tex]I_{O} = I_{g} +m\cdot r^{2}[/tex] (4)
Where:
[tex]r[/tex] - Distance between parallel axes, measured in meters.
If we know that [tex]I_{g} = 0.0108\,kg\cdot m^{2}[/tex], [tex]m = 0.332\,kg[/tex] and [tex]r = 0.180\,m[/tex], then the moment of inertial of the hoop yo-yo rotating about the point where the tension force is applied is:
[tex]I_{O} = 0.0108\,kg\cdot m^{2}+(0.332\,kg)\cdot (0.180\,m)^{2}[/tex]
[tex]I_{O} = 0.0216\,kg\cdot m^{2}[/tex]
The moment of inertial of the hoop yo-yo rotating about its center of mass is [tex]I_{O} = 0.0216\,kg\cdot m^{2}[/tex].
which nervous system includes the spinal cord
A. Sympathetic
B. autonomic
C. Central
D. Somatic
Answer:
the central nervous system
Answer: C. central
Explanation:
A sound wave enters a new medium where sound travels faster. How does this affect the frequency and wavelength of the sound?
А. The frequency increases and the wavelength decreases.
B. The frequency decreases and the wavelength increases.
C. The frequency stays the same and the wavelength increases.
D.The frequency stays the same and the wavelength decreases.
E. Neither the frequency nor the wavelength is affected.
Answer:
The frequency stays the same and the wavelength decreases.
Explanation:
When sound wave enters a new medium where sound travels faster, its frequency will remain same because it depends only on the source.
The relation between wavelength and speed is inverse, it means when the speed of sound increases, its wavelength will decrease.
So, the frequency stays the same and the wavelength decreases. Hence, the correct option is (d).
write the characteristic of aluminum
Answer:
see below
Explanation:
alluminium is,
1.lustrous
2.highly malleable
3.reactive metal
4.some times acts as non metal
5.good conductor
6.obtained from bauxite
7.Atomic number 13 so electrons and protons are 13
8.neurons are 14
9.ductile
10.melting point is very high approximately 660 degree celsius.
Answer:
It has low density, is non-toxic, has a high thermal conductivity, has excellent corrosion resistance and can be easily cast, machined and formed.
Explanation:
Car A travelled 300k in 5 hours, what was its average speed?
Speed =distance/time
Speed=300/5=60 km/h
mark brainliest please
when an object (like a ball) falls, some of its _____ energy changes to _____ energy, due to the law of conservation of energy
a.) kinetic, potential
b.) kinetic, motion
c.) potential, kinetic
d.) motion, potential
Answer:
c ) potential your welcome hehea 6.5 kg box is pulled across a floor by a horizontal 12.0 N tension force. If there is a 5 N friction exerted on the box, what is its acceleration
Explanation:
Fnet = 12.0N - 5.0N = 7.0N
a = Fnet/m = 7.0N/6.5kg = 1.07m/s².
A food processor draws 8.47 A of current when connected to a potential difference of 110 V.
How much electrical energy is consumed by this food processor monthly (30 days) if it is used on average of 10.0 min every day?
Answer:
27.95[kW*min]
Explanation:
We must remember that the power can be determined by the product of the current by the voltage.
[tex]P=V*I[/tex]
where:
P = power [W]
V = voltage [volt]
I = amperage [Amp]
Now replacing:
[tex]P=110*8.47\\P=931.7[W][/tex]
Now the energy consumed can be obtained mediate the multiplication of the power by the amount of time in operation, we must obtain an amount in Kw per hour [kW-min]
[tex]Energy = 931.7[kW]*30[days]*10[\frac{min}{1day} ]=279510[W*min]or 27.95[kW*min][/tex]
Pitch refers to A. how high or low a note is. B. the loudness of a note. C. the length of the note. D. the range of notes in the composition.
This is music by the way.
Answer:
A
Explanation:
OKAY REAL QUICK A NOTE REPRESENTS THE 12 TONES ON THE CHROMATIC SCALE WHICH IN TURN REPRESENTS THE WHOLE OF SOUND IN ALL MUSIC- EACH NOTE HAS A PITCH THAT REPEATS IN EVERY OCTAVE.
A horse pulls a wagon with 2000N of at constant velocity. What is the friction acting on the wagon?
0N
1000N
1500N
2000N
Answer:
f = 0 N
Explanation:
It is given that,
A horse pulls a wagon with 2000N of at constant velocity.
We need to find the friction acting on the wagon.
As the wagon is pulled with a constant velocity. If its velocity is constant, it means its acceleration is 0. As a result friction force is 0.
Hence, the correct option is (a).
Find the range of projectile launched at the angle of 45 with an intial velocity of 25 m/s
Answer:
10
Explanation:
Given that :
Initial Velocity (u) = 25 m/s
Range can be obtained using the relation :
Range = (u² * sin2θ) / g
g = 10m/s ; θ = 45
Range = [10² * sin2(45)] / 10
Range = [100 * 1] ÷ 10
Range = 10