A 6.00 L container of N_2 has a temperature of 273 K. Calculate the volume if the temperature is doubled.


a
24.0 L

b
12.0 L

c
6.0 L

d
3.0 L

Answers

Answer 1
V1/T1 =V2/T2 (using charles law)

V1=6.00
V2=?
T1=273
T2=273

Making V2 the subject of formula the equation then becomes

V2= V1xT2/T1

6.00x263/273=6.0L

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Answer:

ABRAHAM DIDN’T THINK ISAAC WOULD DIE!

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Answer:

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How many moles of chlorine could be produced by decomposing 157g NaCl? 2NaCl --> 2Na+Cl2

Answers

Here is the answer for your question which the mole of chlorine is 1.34

By decomposing 157g of NaCl, approximately 1.35 moles of chlorine can be produced.

To determine the number of moles of chlorine that could be produced by decomposing 157g of NaCl, we need to use the molar mass of NaCl and apply stoichiometry.

The molar mass of NaCl is the sum of the atomic masses of sodium (Na) and chlorine (Cl), which is approximately 22.99 g/mol + 35.45 g/mol = 58.44 g/mol.

Now, we can calculate the number of moles of NaCl:

Moles of NaCl = Mass of NaCl / Molar mass of NaCl

Moles of NaCl = 157 g / 58.44 g/mol

Moles of NaCl ≈ 2.69 mol

According to the balanced equation 2NaCl → 2Na + Cl₂, we can see that for every 2 moles of NaCl, we produce 1 mole of Cl₂.

Therefore, using the stoichiometric ratio, we can calculate the number of moles of chlorine produced:

Moles of Cl₂ = (Moles of NaCl / 2) × 1

Moles of Cl₂ = 2.69 mol / 2

Moles of Cl₂ ≈ 1.35 mol

Thus, by decomposing 157g of NaCl, approximately 1.35 moles of chlorine can be produced.

Learn more about chlorine from the link given below.

https://brainly.com/question/19460448

#SPJ2

-- --- .-. ... . / -.-. --- -.. . / .. ... -. .----. - / - .... .- - / ..-. ..- -. / .- -. -.. / .. .----. -- / ..- ... .. -. --. / .- / - .-. .- -. ... .-.. .- - --- .-. / - --- --- / ... --- what did I say in Morse code? ​

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That is what is says in morse code.

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Check all of the following below which describe experimental errors that would affect the percent chloride you report in your experimental results: ____________
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Answers

The options that describe the experimental errors that would affect the percent of chloride reported are:

B (You added excess silver nitrate into the reaction mixture) and D (The transfer from the reaction beaker to the filter funnel was imperfect).

While performing experiments, there are some errors that occur which are generally known as experimental errors.

These experimental errors are the difference between the true measurement and what we measured.

There are three types of experimental errors they include:

systematic,

random, and

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Human errors occur due to carelessness of the observer.

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when you added excess silver nitrate into the reaction mixture

when the transfer from the reaction beaker to the filter funnel was imperfect due to lost of some of the reaction solution.

Therefore, the options describe the experimental errors that would affect the percent of chloride reported are B and D.

Learn more about experimental errors here:

https://brainly.com/question/2764830

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Answer:

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Answer:

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Answer:

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