A 5.7 diameter horizontal pipe gradually narrows to 3.6 cm. The the water flows through this pipe at certain rate, the gauge pressure in these two sections is 32.5 kPa and 24.0 kPa, respectively. What is the volume of rate of flow?

The output by the equation and energy required for friction is 160,000 J. Efficiency is 0.267 or 26.7% and this efficiency can be improved by friction reduction.

The weight of the water pushed and the height it is lifted can be multiplied to determine the beneficial work done by the pump. The volume of water in the tank multiplied by its density yields the weight of the water therein. The tank's total volume, which can be determined by multiplying the tank's cross-sectional area by its height, is equal to half of the amount of water in the tank (8 m). The water therefore weighs:

Volume is calculated as cross-sectional area times height (2 m x 8 m = 16 m3).

Weight is equal to volume times density, or 16 m3 times a density of 1000 kg/m3 equals 16,000 kg.

Useful work=Weight x Height = 16,000 kg x 10 m = 160,000 J for useful work.

A proportion of the useful work can be used to estimate the amount of energy needed for friction. This proportion is influenced by the pump's design, the water's viscosity, and other elements. The energy needed for friction can be computed using a 10% friction loss as follows:

Frictional energy equals 0.1 x 160,000 J, or 16,000 J.

The ratio of the pump's useful work to its energy input can be used to calculate the pump's efficiency. The energy input can be estimated as the motor's power (1 kW) times how long it runs for (10 minutes, or 600 seconds). So, the efficiency can be determined as follows: Energy input is calculated as follows: 1 kW x 600 sec = 600,000

Efficiency is calculated as follows: 160,000 J of useful work per 600,000 J of energy input, or 26.7%.

The friction loss can be decreased, the pump's design can be improved to reduce energy losses, or the motor's power can be increased to increase the pump's efficiency. As the beneficial work performed by the pump is directly proportional to the height the water is lifted, increasing the height the water is lifted is another alternative.

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Because Mg2+ is more positively charged than Na+, MgO has a higher melting point than NaF. Moreover, O2 has a stronger negative charge than F (I & II only, option A)

Ionic solids MgO and Naf both exist. MgO has a higher melting point than NaF because it takes more energy to break the bonds in MgO since it contains higher-charged ions than NaF (Na+ and F).

While Naf (Na+ and F) has a monovalent nature, MgO (Mg2+ and O2) has both divalent (Mg2+ and O2) ions. In the crystal lattice of MgO, the electrostatic forces between the ions are higher than in the case of Naf. As a result, MgO's melting point (2642⁰ C) is greater than NaF's (992⁰ C).

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A dry-type evaporator is another name for a direct expansion evaporator. An evaporator seems to be a container or platform that converts liquid into vapor.

In contrast to the condenser, the evaporator absorbs heat from the compartment's air while converting refrigerant liquid to gas. Due to the reduced pressure and heat dissipation, the liquid refrigerant is much cooler than for the fan air surrounding it when it reaches the evaporator.

One of the popular evaporators is the LTV. Basically, it is a liquid separator coupled to a shell and tube heat exchanger. The climbing film evaporator and the descending film evaporator are quite similar. It is the total opposite of something like a falling movie.

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Compared to the bowling ball, the golf ball after the collision has a) less momentum but more kinetic energy.

The bowling ball's velocity and, consequently, its kinetic energy are significantly lower than those of the golf ball because its mass is significantly greater than that of the latter.

Why is the kinetic energy of a bowling ball greater than that of a golf ball?

First off, heavier objects in motion have more kinetic energy than lighter ones. For example, a bowling ball travelling at 10 m/s (the equivalent of a very fast sprint) has a lot more kinetic energy than a golf ball travelling at the same speed.

How does a collision between a bowling ball and bowling pins alter their kinetic energy?

When two objects collide, some of the kinetic energy is converted during the collision to another form of energy, this is known as an inelastic collision. A portion of the kinetic energy from the bowling ball is transferred to the pins when it strikes them, as evidenced by the way bowling balls and pins scatter and bounce after impact.

Which ball has more inertia, a golf ball or a bowling ball?

As a result of having more mass than a golf ball, a bowling ball will have a higher moment of inertia.

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The final volume is therefore equal to 3.0 mm3 * (1 atm) / (4 atm) = 0.75 mm3.

The volume of an ideal gas is proportional to its temperature and inversely proportional to its pressure. Since the temperature of the air in the bubble stays the same, the ratio of the initial pressure to the final pressure is equal to the ratio of the final volume to the initial volume.

Since the pressure inside the bubble at a depth of 4 times atmospheric pressure is 4 times atmospheric pressure, the pressure inside the bubble at the surface is equal to atmospheric pressure.

The final volume is therefore equal to 3.0 mm3 * (1 atm) / (4 atm) = 0.75 mm3.

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Answer:

100 ohms

Explanation:

the bulb is just a resistor that gets hot and emits light.... series circuit resistance just add together... 10 + 90 = 100 ohms

Answer:

humerus, phalanges, carpals, etc

Explanation:

these examples are non skull bones of the axial skeleton

The PE (potential energy) of the ball at the very top of the diagram is 100 J.

The KE (kinetic energy) of the ball at the very top of the diagram is 0 J.

The PE of the ball the location shown as I on the diagram is 50 J.

The KE of the ball the location shown as J on the diagram is 50 J.

Friction is a force that acts between two objects that are in contact with each other and opposes their relative motion.

The velocity of the ball the location shown as B on the diagram can be calculated by the equation KE = 0.5 * m * v^2, where m is the mass of the ball (2 kg) and KE is the kinetic energy (50 J). Solving for velocity, we get v = sqrt(KE / (0.5 * m)) = sqrt(50 / (0.5 * 2)) = 7 m/s.

The PE of the ball the location shown as F on the diagram as the ball hits the ground is 0 J.

The KE of the ball the location shown as G on the diagram as the ball hits the ground can be calculated by the equation KE = PE + 0.5 * m * v^2, where m is the mass of the ball (2 kg) and v is the velocity of the ball (calculated in #5 as 5 m/s). Solving for KE, we get KE = 0 + 0.5 * 2 * 5^2 = 50 J.

Using the equation KE = 0.5*m*v2, the velocity can be determined to be 7.07 m/s for B and E and 10 m/s for H and K.

The 100 J of original mechanical energy is present at each position. So the KE for A is 50 J.

The KE of the ball the location shown as A on the diagram can be calculated by the equation KE = PE + 0.5 * m * v^2, where m is the mass of the ball (2 kg) and v is the velocity of the ball. The KE at A will be 50J.

The PE of the ball the location shown as C on the diagram can be calculated by conserving energy, meaning that the initial PE at the top of the ramp plus any work done by friction must equal the final KE at this location. This can be expressed as PE + work done by friction = KE, where work done by friction is equal to friction force times distance. So, at C, PE=50J and the KE of the ball the location shown as D on the diagram can be calculated by the equation KE = PE + 0.5 * m * v^2 So, KE for D will be50J.

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Answer:

vamos tú puedes

Explanation:

Answer:

The average acceleration of the sports car is 16.9 m/s².

The boat's velocity relative to the water is 6.8 m/s, in the negative y direction.

To calculate the boat's velocity relative to the water, we first need to subtract the speed of the river from the desired speed of the boat. The desired speed of the boat is 5.0 m/s, and the speed of the river is 1.8 m/s. Thus, the boat's velocity relative to the water is 5.0 m/s - 1.8 m/s = 3.2 m/s.

To determine the direction of the boat's velocity relative to the water, we need to consider the direction of the river and the desired direction of the boat.

The river is flowing in the positive x direction, while the desired direction of the boat is in the negative x direction. Therefore, the direction of the boat's velocity relative to the water is in the negative y direction.

To calculate the magnitude of the boat's velocity relative to the water, we use the Pythagorean theorem. The magnitude of the boat's velocity relative to the water is equal to the square root of the sum of the squares of its x and y components. Thus, the magnitude of the boat's velocity relative to the water is 6.8 m/s (3.2 m/s in the negative y direction).

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A square has a charge in the middle and four charges at each of the four corners that are each equal to Q. if the economy is balanced.

As balancing is the definition of the word "equilibrium," it follows that a chemical process reflects an balance between both the reactants and the products involved in the reaction. In some physical processes, such as the melting of ice at 0°C, in which both snow and water are present, the equilibrium state can also be observed.

The physical characteristic of matter that enables it to feel a force when exposed to an electromagnetic field is called electric charge. The two most frequent types of electric charges are positive and negative charges.

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Deep is the water level in the well below where she tossed the stone is 52.92 m.

Consider the equation of motion s = ut + 0.5 at²

Take the upward direction as positive,

           Initial velocity, u =   8 m/s

           Acceleration, a =   -9.81 m/s²

           Time, t = 4.20 s

Substituting

        s = ut + 0.5 at²

        s = 8 x 4.20 + 0.5 (-9.81) x 4.20²

        s = -52.92 m

Depth of well = 52.92 m

The pace is the directional speed of an item in motion as a demonstration of its price of alternate in the role as observed from a specific body of reference and as measured via a particular widespread of time (e.g. 60 km/h northbound). speed is a fundamental concept in kinematics, the branch of classical mechanics that describes the motion of our bodies.

Velocity is a bodily vector amount; each significance and route are needed to define it. The scalar absolute value (significance) of speed is known as velocity, being a coherent derived unit whose quantity is measured inside the SI (metric device) as meters in step with second (m/s or m⋅s−1). as an example, "5 meters in step with 2d" is a scalar, whereas "5 meters consistent with 2nd east" is a vector. If there is a trade-in velocity, route, or each, then the object is stated to be present process an acceleration.

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After converting he units from R to Joule, we obtain 5.33 × 10⁻¹⁰ J·cm⁻⁴ as the result.

What is joule?

To convert  R to J, convert their units,

1 kPa·km = 1.0 × 10⁻⁸ J(cm⁻⁴)

0.0533 kPa·km = -0.0533 × 1.0 × 10⁻⁸ J(cm⁻⁴)

= 5.33 × 10⁻¹⁰ J·cm⁻⁴

Thus, After converting he units from R to Joule, we obtain 5.33 × 10⁻¹⁰ J·cm⁻⁴ as the result.

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You heard a frequency of 428.8 Hz, and your companion heard a frequency of 426.8 Hz.

The quantity of oscillations that pass a set location in a predetermined period of time is known as frequency. Therefore, if a wave passes through in half a second, the amplitude is 2 per moment. This same frequency is 100 times per hour if it consumes 1/100 of an hour.

The frequency of oscillation and granular phenomenon, such as mechanical energy, speech recordings (sound), electromagnetic radiation, and light, is a crucial parameter in science and engineering.

The frequency you heard,

f = f(s) / [1 - (v(s)/v) ]

f = 400 / [1 - 23/342]

f = 400 / (1 - 0.0672)

f = 400 / 0.9328

f = 428.8 Hz

The frequency your friend hearing,

f = f(s) * [1 + (v(s)/v) ]

f = 400 * [1 + 23/342]

f = 400 * (1 + 0.0672)

f = 400 * 1.0672

f = 426.8 Hz

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The period of the oscillation is obtained by dividing the time with the number of oscillation.

The period of oscillation is the time taken by a repeating periodic motion to complete one full cycle. It is a measure of the time it takes for an object in a repeating motion to return to its original position.

The period of an oscillation is usually denoted by the symbol T and is usually expressed in units of seconds

The period for the different run is calculated as follows;

T = t / n

where;

Run 1 , T = 14.22/10 = 1.422 seconds

Run 2, T = 14.18 / 10 = 1.418 s

Run 3, T = 14.15 / 10 = 1.415 s

Run 4, T = 14.28 / 10 = 1.428 s

Run 5, T = 14.33 / 10 = 1.433 s

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The heat supplied during compression is 432.26 K and the work done on the air is -3.859 KJ/kg

To find the compression temperature use the formula:

                                      P₁T₁= P₂T₂

To answer this question, we can use the following formula of work:

                                 W = mR (T₁ - T₂)/η - 1

now given,

mass: m = 1 kg

Law PV^1.3 : η = 1.3 (P¹°³)

initial pressure: P₁ = 1.02 bar,

initial temperature: T₁ = 20 + 273 = 293 K

final pressure: P₂ = 5.5 bar

final temperature: T₂ = ?

work: W = ?

Putting the given values ​​in the above equation, we get,

Temperature:

P₁T₁ = P₂T₂

T₂ = P₁T₁/P₂

T₂ = (5.5/1.02)0.3/1.3 × 293

T₂= (5.392)0.2308 × 293

T₂ = 1.4753 x 293

T₂ = 432.26 K.

So, the heat supplied during compression is 432.26 K.

Work:

W = mR (T₁ - T₂)/η - 1   → R = 8.314 J/Kmol

W = 1(8.314)(293 - 432.26)/1.3 - 1

W = 8.314(-139.26)/0.3

W = -1157.8/0.3

W = -3859.3 J/kg

W = -3.859 KJ/kg

So, the work done on the air is -3.859 KJ/kg

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If Zack wants to toss his physics book out the window and have it land on Yvette's front seat, he should throw straight outward (throw 2).

Given that Yvette and Zack are both moving at the same speed, their relative velocities are zero. When a book is thrown, its component of velocity in the car's motion direction is equal to that of the car.

At the time of the throw, the book will be moving at the same speed as the car. Yvette's vehicle travels at the same speed; from the viewpoint of the book, both vehicles are immobile. This indicates that the book only needs to proceed directly to Yvette's front seat. Simply slide the book to Yvette's front seat from here.

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It will take the boat 47.35 seconds to get to the dock on the northern shore.

The velocity of an object in relation to another object or observer is defined as relative velocity. The time rate of change of one object's relative position with respect to another object is defined as relative velocity.

We can start by using vector addition to find the velocity of the boat relative to the shore.

The velocity of the boat relative to the water is 6.50 m/s, and the velocity of the water relative to the shore is 4.00 m/s,

Let the boat's relative velocity to shore is v(bs)

water relative velocity  to shore is v(ws)

boat's relative velocity to water is v(bw)

So: v(bs) = √(v(bw)² + v(ws)² - 2 × v(bw) × v(ws) × cos(57.0°))

Plugging in the known values, we get:

v(bs) = √(6.50² + 4.00² - 2 × 6.50 × 4.00 × cos(57.0°)) = 5.47 m/s

Next, we can use this velocity to find the time it takes for the boat to cross the river:

t = d / v(bs) = 259.0 m / 7.76 m/s = 47.35 s

Thus, it will take the boat 47.35 seconds.

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A magnifying glass is a simple optical device that uses a convex lens to produce a magnified image of an object.

When a magnifying glass is held close to an object, the lens refracts the light that is reflected off the object and causes it to converge or come together at a point. This point is called the focal point, and it is where the magnified image is formed. The image appears larger and closer than the actual object because it is formed by the light that has been bent and converged by the lens.

The magnification produced by a magnifying glass depends on the power of the lens, which is determined by its focal length.

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The velocity is 4.9 m/s.

Centripetal acceleration is the acceleration that acts towards the center of a circular path and is required to maintain an object in circular motion. It is defined as the rate of change of velocity of an object moving in a circular path.

The formula for centripetal acceleration can be expressed as:

a_c = v^2 / r

Given that;

a = v^2/r

a = acceleration

v = tangential velocity

r = radius

Thus;

v = √ar

v = (6 * 4)^1/2

v = 4.9 m/s

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The temperature of the hot bath is approximately 400 °C.  (Option B).

To find the temperature of the hot bath, we need to use the temperature coefficient of resistance (α) of platinum and the resistance at 0°C and 100°C as a reference.

The equation to find the temperature is given by:

T = (R/R0 - 1) / α + T0

Where R is the resistance at the hot bath temperature, R0 is the resistance at 0°C, T0 is 0°C, and α is the temperature coefficient of resistance of platinum.

Using this equation and the given values, we can calculate T as:

T = (5.795/5 - 1) / (5.39/5 - 1) * (100 - 0) + 0 = approximately 400 °C

So the temperature of the hot bath is approximately 400 °C .

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The frequency of a microwave oven that emits radiation at a wavelength of 500 cm would be  6.00 × 10¹⁰ Hz (B)

The frequency of a radiation in physics is the quantity of waves passing a fixed location in a unit of time. It also indicates how many cycles or vibrations a body in periodic motion experiences in a given unit of time. Heinrich Rudolf's name was given to the SI unit that measures frequency known as the hertz. Additionally, 1 Hz means one cycle per second.

The distance between the two closest points that are in phase with one another is known as a wavelength. As a result, a single full wavelength separates two nearby peaks or troughs on a wave. Typically, the wavelength of a wave is denoted by the letter lambda (λ).

The following formula gives the relationship between wavelength and frequency:

                                                  V = f × λ

Where:

V = wave speed

   = 3 × 10⁸ m/s (speed of light)

F = frequency

λ = wavelength

  = 0.005 m

Thus, the frequency of the microwave would be:

3 × 10⁸ m/s = f × 0.005 m

f = ( 3 × 10⁸ m/s) ÷ (0.005 m)

f = 6 × 10¹⁰ Hz

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Answer:

It takes approximately 10.3 seconds to accelerate from 70km/h to 120km/h, when the acceleration is 2.0m/s.

Options e, A jogger maintains a constant speed around the boundaries of a rectangular field. The jogger's acceleration is never zero.

An object's acceleration is a measurement of how quickly its velocity changes.

The jogger's acceleration is not zero since they are altering their velocity every time they get to a corner of the rectangular field. This is referred to as centripetal acceleration and is the acceleration necessary to maintain an object's circular motion at a constant speed.

Although the jogger's pace is constant, their direction is changing, which causes a change in their velocity, which in turn causes a change in their acceleration.

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The given statement '' the four principal types of space our text names are: deep space, flat space, split space, and ambiguous space'' is false as the four principal types of space our text names are: atmospheric space, void space, domestic space, and liminal space.

Atmospheric space is the space between objects, where the environment can affect the objects in it. Void space is the empty space that can be found in a room or an area, but can also be found in one’s mind.

Domestic space is the space we create at home, and it is a space that reflects our identity and emotions. Finally, liminal space is a space between two states, where something is neither this nor that and can be seen as a threshold.

All of these spaces are integral to understanding how humans interact with the world, and they all contribute to the overall experience of living.

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Answer:

Explanation:

2nd choice:  120 N in row one and 67 N in row two

Applied forces have to be equal in magnitude and opposite in direction to cancel each other out and result in no change to the object's motion