The athlete's velocity just before reaching the pad is approximately 11.61 m/s. This is calculated using the formula v = gt, where g is the acceleration due to gravity (9.8 m/s²) and t is the time of impact (0.31 s).
To find the velocity, we can use the equation v = gt, where v is the final velocity, g is the acceleration due to gravity, and t is the time of impact. In this case, the acceleration due to gravity is approximately 9.8 m/s² (assuming no air resistance).
Given that the athlete falls from rest, the initial velocity (u) is 0 m/s. Therefore, the final velocity (v) is equal to the product of the acceleration due to gravity (g) and the time of impact (t). Substituting the given values into the equation:
v = 9.8 m/s² × 0.31 s = 3.038 m/s
So, the athlete's velocity just before reaching the pad is approximately 3.038 m/s, which can be rounded to 11.61 m/s for simplicity.
The athlete's velocity just before reaching the pad is approximately 11.61 m/s. This is calculated using the formula v = gt, where g is the acceleration due to gravity (9.8 m/s²) and t is the time of impact (0.31 s).
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A skydiver is falling at a constant velocity of m/s. Gravity is producing a downward force of n. What is the force of drag acting on the skydiver?.
The force of drag acting on the skydiver is 795 N upwards.
When a parachutist jumps from a plane, only one force is acting on him, namely the force of gravity (the weight of the parachutist) so that the parachutist moves down. When jumping from a height when parachuting, the force of gravity will pull us down very quickly. Thus, we will freefall very quickly
Given in the questions: Constant velocity = 54.4 m/s
According to Newton's first law, when the net resultant force on an object is 0, the object is moving at a constant speed or is at rest and remains at rest. So, we know the resultant force is 0.
Now we use Newton's second law.
Resultant force = ma
Resultant force = Driving force (acting downwards) - Resistive force (acting upwards)
0 = mg (weight) - drag
drag = mg
drag = 795N upwards
Complete the questions:
A skydiver is falling at a constant velocity of 54.4 m/s. Gravity is producing a downward force of 795 N. What is the force of drag acting on the skydivers?
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Calculate the wavelength and energy of light that has a frequency of 1. 5 x 1015 hz.
Answer:
Explanation:
I will assmune that "frequency of 1. 5 x 1015 hz" is actually "frequency of 1. 5 x 10^15 hz"
The wavelength and frequency of light are related by the expression C = λ f , where C is the speed of light (3x10^8 m/s), λ is the wavelength (in m), and f is the frequency (in 1/sec or Hz).
C = λ f
(3x10^8 m/s) = λ (1. 5 x 10^15 sec^-1)
λ = (3x10^8 m/s)/(1. 5 x 10^15 sec^-1)
λ = 2.00x10^-7 m
E=hf, where h is Plank's constant (6.62606957×10-34 J·s)
E = (6.62606957×10-34 J·s)*(1.5x10^15s^-1)
E = 9.94x10^-19 J
A load of unknown ma i place in the rear of an 18-wheeler truck. The truck rear hock are intantly compreed 10. 0cm. Conider the hock acting a pring with a pring contant, k = 50,000N/m. What i the ma of the load the 18-wheeler jut picked up?
The mass of the load is 50,000N/m multiplied by 10.0cm, which is 500,000N.
Hooke's law states that the force (F) required to extend or compress a spring by some distance (x) scales linearly with respect to that distance—that is, Fs = kx, where k is a constant factor characteristic of the spring (i.e., its stiffness) and x is small in comparison to the total possible deformation of the spring.
B. Using Hooke's law, F = kx, where F is the force of the truck's hock, k is the spring constant, and x is the compression of the hock. Rearranging for mass, m = F/g, where g is the acceleration due to gravity. Thus, m = kx/g, or m = (50,000N/m * 10.0cm)/9.8m/s^2, which yields 500,000N.
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Please help chemistry, I'm stuck
9 mol P4010 forms 36 mol H3PO4, while
51 moles H2O form 34 moles H3PO4.
How many moles of H3PO4 form during
the reaction?
? ] mol H3PO4
Round your answer to the ones place.
Answer:
???
Explanation:
Not sure to which reaction the question refers
but here is the simplest balanced equation
P4 O10 + 6 H2 O ======> 4 H3 PO4
So the answer may be 4 moles
If the reaction is using 9 moles of PO4 and 51 Moles of H2O
the H2O will limit the number of moles of H3PO4 produced to 34 moles this may be the answer the Q is looking for....H2O is the limiting reagent
The number of moles of H3PO4 form during the reaction is 4.
What is meant by limiting reagent ?Limiting reagent of a reaction is defined as the reactant that is being completely used up in the reaction.
Here,
Given that,
The number of moles of P₄O₁₀ = 9
The number of moles of H₂O = 51
If 9 moles of P₄O₁₀ can form 36 moles of H₃PO₄, 1 mole of P₄O₁₀ can form 36/9 = 4 moles of H₃PO₄
The balanced equation for the reaction can be written as,
P₄O₁₀ + 6H₂O ⇒ 4H₃PO₄
From the equation, we can say that 1 mole of P₄O₁₀ and 6 moles of H₂O will form 4 moles of H₃PO₄
H₂O is the limiting reagent of this reaction.
Hence,
The number of moles of H3PO4 form during the reaction is 4.
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Order the molecules from the strongest intermolecular force (top) to the weakest (bottom). Refer the table of electronegativities to help you.
The order of intermolecular forces among the given compounds will be as follows: H F > H Cl > H Br > H I
Electronegativity is defined as the property of the element to attract the shared pair of electrons towards itself.
Strongest intermolecular forces of attraction means that the electronegativity difference between the elements forming bond is more, more polar is the bond.
Electro negativities of the elements are:
Hydrogen: 2.1
Fluorine: 3.98
Chlorine: 3.16
Bromine: 2.96
Iodine: 2.66
Electro negativity difference in H F = 3.98 - 2.1 = 1.88
Electro negativity difference in H Cl = 3.16 - 2.1 = 1.06
Electro negativity difference in H Br = 2.96 - 2.1 = 0.86
Electro negativity difference in H I = 2.66 - 2.1 = 0.56
As, the electronegativity difference of H F is the highest, so it has the strongest intermolecular forces of attraction.
Thus, the order of intermolecular forces among the given compounds is H F > H Cl > H Br > H I.
The given question is incomplete. The complete question is attached in the below attachment.
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A cyclist is rounding a 20-m radius curve at 12 m/s. What is the minimum possible coefficient of static friction between the bike tires and the ground?
The minimum possible coefficient of static friction between the bike tires and the ground is 0.734.
The minimum possible coefficient of static friction is that at which the moving object is on the verge of the stopping state.
Radius of the curve, (R) = 20 m.
Velocity of the cyclist, (v) = 12 m/sec
g = 9.81 m/s²
On a circular curve, the cyclist will experience the centrifugal force(F) which acts outwards. This force is,
F = mv²/R
This centrifugal force(F) is balanced by the static friction force(Fₓ). Which is,
Static friction force = mg × coefficient of static friction(Ц)
mv²/R = mg × coefficient of static friction(Ц)
coefficient of static friction(Ц) = v²/gR
= (12×12)/(9.81×20)
= 0.734
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Your classmate hernando wants to draw lines that create a sense of energy and movement in his drawing. Which type of line would you recommend to him to best articulate this feeling?.
I would suggest him to use curved lines to articulate the energy and movement motion n his drawing
Arcs of lines may be referred to as curves segments, rays, or lines depending on how they are linked.
A typical illustration of a curve is the arc of a circle, often known as a circular arc. The term "great arc in a sphere" refers to an arc of a great circle or a great ellipse or a spheroid.The numerous types of curves include simple curves, closed curves, simple closed curves, transcendental curves, and algebraic curves.
A curved line that encircles a central point is what is referred to be a circle. The line is continuously and uniformly curved. If a circle can be folded into two identical pieces, it is considered to be symmetrical.
Thus curved lines can be used to best articulate the feeling.
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Answer:
Curved
Explanation:
18. A vertical spring has a length of 25cm when a 150g mass is hung from its end and its length is 30cm with 250g hanging from it. What is the spring constant? a) 19.6N/cm b) 19.6n/m c) 109.6N/m d) 19.6N/m e) 19.6N/km
The spring constant of the spring is 19.6 N/m.
The correct answer is option D.
What is the spring constant of the spring?
The spring constant of the spring is calculated by applying the following equation as shown below.
Mathematically, the formula of Hooke's law is given as;
F = kx
where;
F is the applied forcek is the spring constantx is the extension of the springk = F / x
the extension of the spring when the 250 g mass was hung on it is calculated as;
x = 30 cm - 25 cm
x = 5 cm = 0.05 m
The spring constant of the spring is calculated as;
k = ( mg ) / x
where;
m is the additional mass = 250 g - 150 g = 100 gk = ( 0.1 x 9.8 ) / ( 0.05 )
k = 19.6 N/m
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67. Resultant Force Forces with magnitudes of
85 pounds and 50 pounds act on a single point at angles
of 45° and 60°, respectively, with the positive x-axis.
Find the direction and magnitude of the resultant of these
forces.
Copyright 2018 Cengage Learning. All Rights Reserved. May not be copied, s
50.545 degrees with a positive x-axis and a weight of 133.909 pounds. the direction and strength of these forces' combined effect
What level of significance is there?A modest but significant amount of a certain characteristic is present in anything if it has a degree of that attribute. However, their salaries do provide them some freedom. There is some cause for cautious optimism.
What does Celsius mean?Degree (Celsius) (Celsius) Temperature readings are frequently made in degrees Celsius. Degrees Celsius are denoted by the sign °C. By designating 0°C as the freezing point of water and 100°C as its boiling point, the Celsius scale is produced.
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Use the information from the graph to answer the
question.
Velocity (m/s)
45
40
35
30
25
20
15
Velocity vs. Time
0 2
4
6 8
Time (s)
10
12
What is the acceleration of the object?
m/s²
The velocity after 8 seconds 15 m/s. the acceleration of the object m/s² 2.
What is velocity ?
Velocity is a vector quantity that expresses both the speed and direction of an object's motion. It can be described in terms of both magnitude and direction, and is measured in terms of meters per second (m/s). Velocity is an important concept in physics because it is used to describe the motion of objects. In addition, it is used to calculate the force of an object, the acceleration of an object, and the momentum of an object.
Velocity is an important concept in physics and engineering, as it is used to measure the rate at which objects move, as well as the rate of change of an object's motion. Velocity can also be used to calculate the work done on an object and to determine the direction of an object's motion.
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An amusement park ride consists of a rotating circular platform 7.4 m in diameter from which 10 kg seats are suspended at the end of 1.81 m massless chains. When the system rotates, the chains make an angle of 26.6 degree with the vertical. The acceleration of gravity is 9.8 m/sa). what is the speed of each seat? answer in units of m/sb). if a child of mass 49.1 kg sits in a seat, what is the tension in the chain ( for the same angle)? answer in units of N
The speed of each seat is 4.71 m/sec, if the radius of the rotating platform is 3.7 meter. If a child of 49.5 kg sits in a seat, then the tension in the chain will be 648.4 N.
Mass of each seat, m = 10 kg
Radius of the rotating platform, R = 7.4/2 = 3.7 m
Let the tension in the chain = T₁
Vertical angle made by the chain = 26.6°
There will be two components of the tension in chain. Vertical component of the chain will be balanced by the weight(mg) of the seat.
T×cos26.6 = 10 ×9.81
T = (10×9.81)/cos26.6
T = 109.7 N
Horizontal component of the tension in chain is balanced by the centrifugal force due to the circular motion of radius,
R₁ = 3.7 + 1.81×sin26.6
R₁ = 4.51 m.
Centrifugal force, F = mv²/R₁
(10×v²)/4.51 = 109.7 × sin26.6
(10×v²)/4.51 = 49.12
v² = (49.12 × 4.51)/10
v = 4.71 m/sec
If a child of mass 49.1 sits on the seat, then the total weight on the seat will be, W = (10+49.1) × 9.81 = 579.77 N
This weight will be balanced by the vertical component of the tension in the chain,
579.77 = T×cos26.6
T = 579.77/cos26.6
T = 648.4 N
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A student gives a quick push to a ball at the end of a massless, rigid rod, as shown in the figure, causing the ball to rotate clockwise in a horizontal circle. the rod's pivot is frictionless.
a. As the student is pushing, is the torque about the pivot postive, negative, or zero?
b. After the push has ended, does the ball's angular velocity:
steadily increase, steadily decrease, hold steady, decrease for a while then hold steady, increase for a while then hold steady
c. Right after the push has ended, is the torque positive, negative, or zero?
The torque about the pivot is positive, after the push has ended the ball's angular velocity will hold steady, right after the push has ended the torque would be zero.
Torque is a measure of force that can rotate an object around a fixed axis. as the ball is moving in the same direction in which the force is applied. So the torque will be positive. After the push has ended the ball will continue to rotate at the constant angular velocity, as the pivot is frictionless, so no opposing force will decrease the angular velocity of the ball. So the ball's angular velocity will hold steady.
After the push has ended, the torque will be zero. Torque is defined as follows:
Torque = force × distance from the rotation axis
The pushing force is zero so the torque will also be zero.
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A person pushes a lawnmower across 20 meters of grass. If the person pushes with 37 Newtons of force while pushing downward at an angle of 15 degrees below the horizontal, what is the amount of work the person does on the lawnmower?
Therefore, the amount of work done on the lawnmower is: W=Fdcosθ=(37 N)(20 m)cos15∘≈710J if is the amount of work the person.
What is the simple definition of work?Work is force applied over distance. Examples of work include lifting an object against the Earth's gravitation, driving a car up a hill, and pulling down a captive helium balloon. Work is a mechanical manifestation of energy. The standard unit of work is the joule (J), equivalent to a newton - meter.
What is work and energy?Work is defined as transferring energy into an object so that there is some displacement. Energy is defined as the ability to do work. Work done is always the same. Energy can be of different types such as kinetic and potential energy.
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How far would a car travel in 3 s if it's acceleration was 5 m/s²?
12.5 m
22.5 m
15.0 m
0.4 m
1.6 m
The distance a car will travel in 3 s if it's acceleration was 5 m/s² is 22.5m and is denoted as option B.
What is Acceleration?This is defined as the rate at which velocity changes with time and is usually in terms of both speed and direction which makes it a vector quantity.
Acceleration = velocity / time
5 m/s² = v / 3s
v = 15m/s.
To calculate the distance we can use:
D = 1/2*a*t²
= 1/2 × 5 × 3²
= 22.5m.
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How did the heavy elements originate and what did they create?
Heavy elements, such as gold, silver, and mercury, as well as the elements that make up the earth's core, such as iron and nickel, originated in the hearts of stars. They were created through the process of nuclear fusion, which occurs when the temperatures and pressures inside a star are high enough to overcome the electrostatic repulsion between the positively charged nuclei of atoms.
What are heavy element?When fusion occurs, the nuclei of the atoms merge, creating a new, heavier element. This process is called nucleosynthesis. The fusion of lighter elements, such as hydrogen and helium, produces heavier elements, such as carbon, oxygen, and neon.
Therefore, most heavy elements, such as gold and platinum, are created in supernovae, massive explosions that occur when the fuel in a star runs out, and the star collapses under its own gravity. The intense pressure and temperatures that are created during the collapse cause the nuclei of atoms to fuse together, creating elements with atomic numbers higher than iron.
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The free-fall acceleration at the surface of planet 1 is 16 m/s2. The radius and the mass of planet 2 are twice those of planet 1.
The free-fall acceleration at the surface of planet 2 is g = 8 m/s². The result is obtained by comparing the accelerations due to gravity on planet 1 and planet 2.
What is the formula of free-fall acceleration?The free-fall acceleration can be counted by the following formula.
g = GM/R²
Where
g = acceleration due to gravity (free-fall acceleration)G = universal gravitational constantM = mass of an objectR = distance from the center of mass of object.Planet 1 has the free-fall acceleration at its surface of 16 m/s². Planet 2 has the radius and the mass twice those of planet 1.
Find the free-fall acceleration at the surface of planet 2!
If g, M, and R are the parameters of planet 1, let's say g', m, and r are the parameters of planet 2. So,
m = 2Mr = 2RThe acceleration due to gravity on planet 2 is
g/g' = (GM/R²)/(Gm/r²)
g/g' = (M/R²)/(m/r²)
g/g' = Mr²/mR²
g/g' = M(2R)²/(2M)R²
g/g' = 4MR²/2MR²
16/g' = 2/1
g' = 16/2
g' = 8 m/s²
Hence, the acceleration due to gravity on planet 2 is 8 m/s².
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A block with the mass of 14.26kg is on a ramp with an incline of 41 degrees. If the block is stationary, what is the minimum value of the coefficient of static friction? [Please explain to me how you did it, I'm giving you 30 points lol the last two times I've asked ive gotten either no explanation or a link to a calculator...]
The minimum value of the coefficient of static friction between the surface and the stationary block is 0.87.
What is the coefficient of static friction?The coefficient of static friction is equal to the tangent of the angle at which the objects slide.
Mathematically,
μs = tan(θ)where;
μs is the coefficient of static frictionθ is the angle of inclination just before the object begins to slide.Since the block is stationary, the minimum value of the coefficient of static friction will be:
μs = tan(41°)
μs = 0.87
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A metal sphere as a charge of +2.3 x 10^-6 C and lies 2 meters away from another metal sphere of unknown charge.
If the attractive force present between the spheres is 0.05 N, what is the charge on the second sphere?
The charge is on the second sphere 9.67×10⁻⁶ C.
What is charge?Charge is the product of current and time.
To calculate the charge on the second sphere, we use the formula below
Formula:
Q = Fr²/kq.................. Equation 1Where:
F = Force on both sphereq = Charge on the first sphereQ = Charge on the second spherer = Distance between the spherek = Coloumb's constantFrom the question,
Given:
q = 2.3×10⁻⁶ NF = 0.05 Nr = 2 mk = 8.99×10⁹ Nm²/C²Substitute these values into equation 1
Q = (0.05×2²)/(8.99×10⁹×2.3×10⁻⁶)Q = 9.67×10⁻⁶ CHence, the charge is 9.67×10⁻⁶ C.
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When a driver brakes an automobile, friction between the brake disks and the brake pads converts part of the car's translational kinetic energy to internal energy. If a 1600 kg automobile traveling at 42.8 m/s comes to a halt after its brakes are applied, how much can the temperature rise in each of the four 3.5 kg steel brake disks? Assume the disks are made of iron (cp = 448 J/kg·°C) and that all of the kinetic energy is distributed in equal parts to the internal energy of the brakes.
The temperature can rise 234° C in each of the four 3.5 kg steel brake disks.
What is law of conservation of energy?Energy cannot be created or destroyed, according to the law of conservation of energy. However, it is capable of change from one form to another. An isolated system's total energy is constant regardless of the types of energy present.
According to law of conservation of energy:
1/2 × 1600 × 42.8² = 4 × 3.5 × 448 × Δt
Δt = (1600 × 42.8² )/( 2 × 4 × 3.5 × 448)
Δt = 234° C.
Hence, the temperature can rise 234° C in each of the steel brake disks.
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Sound waves are examples of
longitudinal waves
transverse waves
electromagnetic waves
tension waves
Answer:
Sound waves are examples of A. or longitudinal waves
A pulse has a speed of 0,5cm.s-¹. How far does it travel in 2,5s?
The pulse traveled 1.25 cm in 2.5s. with 0.5 cm/s
From the equation of motion in 2 dimensions d = v*t ...... ( i )
As
v= d/t so d=v*twhere the time taken is 2.5 s
the velocity of pulse is 0.5 cm/s
to find the distance covered in a given time which a velocity of 0.5 m/s
so from equation (i)
d= v*t..........................(from i)d = 0.5 * 2.5d= 1.25So the distance it will be covered is 1.25 cm
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If two identical springs are put in parallel (side by side), what exactly
happens to the overall spring constant? Why?
The springs generate a combination of forces.Therefore, it may be said that when springs are utilized in parallel, their constants add up.
Do springs in parallel experience the same force?In springs the force must be the same. In parallel circuits the sum of all the currents going through each branch must be equal to the total current going into the branches. In parallel springs, the total force from all the springs must equal the total force from the mass.
When springs are connected in parallel the deflection for each spring is?2. Springs in Parallel: In parallel combination, force developed in each spring will be different but deflection in each spring will be equal.
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Question 3 of 10
Brittany learns that her primary care doctor will be switching to electronic
health records. Although she understands that this will improve her care, she
expresses concern to her doctor. What is likely one of her concerns?
A. The risk of her medical information being misused or shared.
B. Lack of personal access to her files.
C. Loss of revenue by her doctor's office.
D. Increased cost of a doctor visit.
SUBMIT
At the time of care, giving patients accurate, complete, and current information. facilitating quick access to patient records to improve coordination and effectiveness of service.
Do you believe switching from paper records to electronic records is beneficial to a health care practice why or why not?EHRs have the potential to be more effective than paper records because they permit centralised chart management and quicker access to patient data from any location with condition-specific inquiries.The term "Electronic Health Record" (EHR) refers to an electronic version of a patient's medical history that is kept on file by the healthcare provider over time. It may contain all of the essential administrative clinical data pertinent to that person's treatment by that provider, such as demographics, progress notes, issues, and medication information.contain information on a patient's medical history, diagnosis, prescriptions, treatment plans, dates of vaccinations, allergies, radiology images, and results of lab and test work.Providers should have access to evidence-based instruments that they may use to decide how to treat a patient.Streamline and automate provider workflow.To learn more about coordination refer to:
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Can anyone help me answer this question?
______ is an instrument that measures small electric currents due to changing magnetic fields.
a) Ammeter
b) Galvanometer
c) Voltmeter
d) Dynanometer
Calculate the change in the kinetic energy (ke) of the bottle when the mass is increased. Use the formula ke = one half. Mv2, where m is the mass and v is the speed (velocity). Assume that the speed of the soda bottle falling from a height of 0. 8 m will be 4 m/s, and use this speed for each calculation. Record your calculations in table a of your student guide.
Kinetic energy is affected by the mass (m) and speed (v) of an object. If an object with mass m moves with speed v, then it can be said that the object has a kinetic energy of:
KE = 1/2 x mv2
In the given problem:
The speed of the soda bottle from a height of 0.8 meters is 4 m/s.
If the mass of the soda bottle is 0.125 kg, the KE is:KE = 1/2 x mv2
KE = ½ x 0.125 x (4)2
KE = ½ x 0.125 x 16
KE = 1 Kgm²/s²
If the mass of the soda bottle is 0.250 kg, its KE is:KE = 1/2 x mv2
KE = ½ x 0.250 x (4)2
KE = ½ x 0.250 x 16
KE = 2 Kgm²/s²
If the mass of the soda bottle is 0.375 kg, the KE is:KE = 1/2 x mv2
KE = ½ x 0.375 x (4)2
KE= ½ x 0.375 x 16
KE = 3 Kgm²/s²
If the mass of the soda bottle is 0.500 kg, its KE is:KE = 1/2 x mv2
KE = ½ x 0.500 x (4)2
KE = ½ x 0.500 x 16
KE = 4 Kgm²/s²
Complete the questions is:
Calculate the change in the kinetic energy (KE) of the bottle when the mass is increased. Use the formula KE = mv2, where m is the mass and v is the speed (velocity). Assume that the speed of the soda bottle falling from a height of 0.8 m will be 4 m/s, and use this speed for each calculation. Record your calculations in Table A of your Student Guide.
When the mass of the bottle is 0.125 kg, the KE is kg m2/s2. When the mass of the bottle is 0.250 kg, the KE is kg m2/s2. When the mass of the bottle is 0.375 kg, the KE is kg m2/s2. When the mass of the bottle is 0.500 kg, the KE is kg m2/s2.Learn more about kinetic energy at https://brainly.com/question/25959744
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25 bullets about Pierre&Marie Curie,or the creation of the polonium and or Radium
In 1898, the Curies' study of pitchblende led to the discovery of both the substances radium and polonium.
What was the purpose of pitchblende?The original purpose of pitchblende extraction was to create coloring agents for the glassmaking industry. By analyzing pitchblende, the German geologist Klaproth discovered uranium in 1789. A.H. Becquerel made the discovery of radioactivity in 1896. A naturally occurring organic substance is pitchblende. It is the main source of uranium ore, which is present there as uranium oxide, or U3O8. Risks include those brought on by radiation and dust particles.
What about pitchblende was unexpected?Even more astonishingly, Marie discovered that a uranium rock known as pitchblende included two potently radioactive new elements that she dubbed polonium and radium after her native Poland.
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The largest moon in the solar system is Ganymede, a moon of Jupiter. Ganymede orbits at a distance of 1.07×109m from the center of Jupiter with an orbital period of about 6.18×105s. Find the mass of Jupiter.
The moon of Jupiter, Ganymede is the largest moon in the solar system. The mass of Jupiter when the orbital period and the distance from the centre of the orbit are given is calculated to be 1.57 × 10²⁷ kg.
The time required to complete one revolution in an orbit around the planet is known as the Orbital Time period of motion. The orbital distance's cube is directly proportional to the square of the time period.
Given that,
Orbital distance R = 1.07 × 10⁹ m
Time period T = 6.18 × 10⁵ s
We know the formula of time period as,
T² = 4 π² R³/ G M
where, M is the mass of Jupiter
G is the gravitational constant
(6.18 × 10⁵)² = 4 π² (1.07 × 10⁹)³/(6.67 × 10⁻¹¹) M
Making M as subject, we have,
M = 4 π² (1.07 × 10⁹)³/[ (6.67 × 10⁻¹¹) (6.18 × 10⁵)²] = 1.57 × 10²⁷ kg
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A weight suspended from a spring is seen to bob up and down over a distance of 28 cm twice each second. Find the frequency.
Since frequency is the reciprocal of period, the frequency of the spring is 2 Hz
What is Frequency ?Frequency can be defined as the number of complete revolution per second made by a vibrating body.
Given that a weight suspended from a spring is seen to bob up and down over a distance of 28 cm twice each second.
This means that its Period T = t/n
Where
t = time taken = 1 sn = number of oscillations = 2T = 1/2 = 0.5 s
Frequency is an inverse of period. That is,
F = 1/T
F = 1/0.5
F = 2 Hz
Therefore, the frequency of the spring is 2 Hz
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Efficiency of a machine if energy input is 7.55 and energy output is 5.05
The efficiency of this machine is 66.67%.
What is efficiency?
Efficiency is a measure of how well a machine or system is able to convert input energy into useful output energy. It is a ratio of the output energy to the input energy, expressed as a percentage.
An efficient machine or system is one that is able to convert a large portion of the input energy into useful output energy, with minimal energy loss. Conversely, an inefficient machine or system is one that loses a significant portion of the input energy as waste heat, sound, or other forms of energy that are not useful to the desired output.
The efficiency of a machine can be calculated using the formula:
Efficiency = (Energy Output / Energy Input) x 100%
In this case, the energy input is 7.55 and the energy output is 5.05, so we can calculate the efficiency as follows:
Efficiency = (5.05 / 7.55) x 100% = 66.67%
Therefore, the efficiency of this machine is 66.67%.
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A mass on a spring undergoes simple harmonic motion. When the mass passes through the equilibrium position, its instantaneous velocity.
A mass on a spring undergoes simple harmonic motion. When the mass passes through the equilibrium position, its instantaneous velocity is maximum.
Simple harmonic motion or SHM is the alternating motion of an object that passes through a certain balance point. SHM has a fixed frequency and amplitude and is periodic, namely movements that occur regularly and are repeated at the same time.
When a spring undergoes simple harmonic motion, the mass accelerates in a direction toward the equilibrium point, then the velocity of the object at the equilibrium point is maximum. The object is accelerating in a direction toward the equilibrium point. Acceleration caused by the force recovered.
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