a 500g model rocket with a weight of 4.90 N is launched straight up. The small rocket burns for 5s and has a steady thrust of 20N. What maximum altitude does the rocket reach

Answer:

true

Explanation:

the dog hasn't moved, displacement has direction, and there is no movement or direction involved, his final position and initial are the same

Answer:

Psychophysics is the subfield of psychology devoted to the study of physical stimuli and their interaction with sensory systems.

Explanation:

Hope this helps <3

Answer:

eating an apple

Explanation:

Eating food gives your body the nutrients and energy it needs.

Answer:

The time when the mass will reach its first maximum velocity  is 1.8 s.

Explanation:

Given;

mass of the pendulum, m = 3 kg

length of the pendulum, l = 0.8 m

height in which the pendulum is raised to, h = 0.2 m

the mass will reach its first maximum velocity when it returns to its initial position, i.e at the middle (x = 0).

the distance between the initial position of the pendulum and the height in which it is raised is the maximum displacement (A).

If we form a right angle triangle with respect to the height in which the pendulum is raised;

the height of the right triangle, H = L - 0.2 = 0.8 - 0.2 = 0.6 m

the hypotenuse side, = L = 0.8 m

the base of the triangle (opposite side) = A

A² = L² - H²

A² = (0.8)² - (0.6)²

A² = 0.28

A = √0.28

A = 0.529 m

The maximum velocity of the pendulum is calculated as;

[tex]V_{max} = A \omega\\\\V_{max} = A \sqrt{\frac{g}{l} } \\\\V_{max} = (0.529)\sqrt{\frac{9.8}{0.8} }\\\\V_{max} = 1.852 \ m/s[/tex]

The period is calculated as;

[tex]V_{max} = A\omega\\\\V_{max} = A (\frac{2\pi}{T} )\\\\T = \frac{2\pi A }{V_{max}}\\\\T = \frac{2\pi \ \times \ 0.529}{1.852} \\\\T = 1.8 \ s[/tex]

Therefore, the time when the mass will reach its first maximum velocity  is 1.8 s.

The total mechanical energy of the particle of mass m at the surface of the planet of mass M when the distance is R (planet's radius) is [tex] E = \frac{GmM}{R}  + \frac{1}{2}mv_{e}^{2} [/tex].            

When the particle is at rest at a distance "r" from the planet's center, it only has gravitational potential energy. As the particle falls to the planet's surface, some initial gravitational potential energy converts to kinetic energy.      

The total mechanical energy of the particle at the planet's surface is equal to the sum of the gravitational potential energy and kinetic energy, so:

[tex] E = P + K [/tex]    

[tex] E = maR + \frac{1}{2}mv_{e}^{2} [/tex]  (1)

Where:

m: is the mass of the object

a: is the acceleration due to gravity on the surface of the planet

R: is the radius of the planet

[tex]v_{e}[/tex]: is the escape velocity                            

The acceleration due to gravity is given by:

[tex] a = \frac{GM}{R^{2}} [/tex]  (2)  

By entering equation (2) into (1), we have:

[tex] E =mR\frac{GM}{R^{2}}  + \frac{1}{2}mv_{e}^{2} [/tex]  

[tex] E = \frac{GmM}{R}  + \frac{1}{2}mv_{e}^{2} [/tex]

Therefore, the total mechanical energy of the particle is [tex] E = \frac{GmM}{R}  + \frac{1}{2}mv_{e}^{2} [/tex]

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I hope it helps you!  

Answer:

Ekin = 250000 [J]

Explanation:

The kinetic energy of a body or object can be calculated based on the mass and the speed with which it moves. This energy can be easily calculated by means of the following equation.

[tex]E_{kin}=\frac{1}{2} *m*v^{2}[/tex]

where:

m = mass = 200 [kg]

v = velocity = 50 [m/s]

Now replacing:

[tex]E_{kin}=\frac{1}{2} *200*(50)^{2}\\E_{kin}=250000[J][/tex]

Answer:

Jupiter's gravitational acceleration is 24.8 m/s^2

Explanation:

Recall that the weight under the influence of a gravitational acceleration G is defined as:

Weight = m * G

Then, in our case we have

372 N = 15 kg * G

G = 372/15  m/s^2

G = 24.8 m/s^2

Answer:

6g/cm³

Explanation:

Density is the mass per unit volume of any substance. To solve this problem:

   Density  = [tex]\frac{mass}{volume}[/tex]  

 Since mass = 600g

Let us find the volume;

    Volume  = length x width x height

   Volume  = 25cm x 2cm x 2cm  = 100cm³  

Therefore;

         Density  = [tex]\frac{600}{100}[/tex]    = 6g/cm³

Answer:

the length of the simple pendulum is 0.25 m.

Explanation:

Given;

mass of the air-track glider, m = 0.25 kg

spring constant, k = 9.75 N/m

let the length of the simple pendulum = L

let the frequency of the air-track glider which is equal to frequency of simple pendulum = F

The oscillation frequency of air-track glider is calculated as;

[tex]F = \frac{1}{2\pi } \sqrt{\frac{k}{m} } \\\\F = \frac{1}{2\pi } \sqrt{\frac{9.75}{0.25} } \\\\F = 0.994 \ Hz[/tex]

The frequency of the simple pendulum is given as;

[tex]F = \frac{1}{2\pi} \sqrt{\frac{g}{l} } \\\\2\pi(F) = \sqrt{\frac{g}{l} } \\\\2\pi (0.994) = \sqrt{\frac{9.8}{l} } \\\\6.2455 = \sqrt{\frac{9.8}{l} } \\\\(6.2455)2 = \frac{9.8}{l} \\\\39.006 = \frac{9.8}{l} \\\\l = \frac{9.8}{39.006} \\\\l = 0.25 \ m[/tex]

Thus, the length of the simple pendulum is 0.25 m.

Answer:

a = 8 m/s^2, Ffriction = 10 N, μk = 0.205

Explanation:

a. Force = Mass*Acceleration,

(since you didn't add the units..."5 block"....for the mass, I will assume it to be in kg, per SI units)

40 N = 5 kg*acceleration,

a = 40/5 = 8 m/s^2

b. As you know newtons second law (F=m*a) is actually in the form Fnet = m*a. Which means that if the friction force comes into play, it would be Fapplied - Ffriction = m*a.

Fapplied - Ffriction = m*a,

40 - Ffriction = 5*6,

40 - Ffriction = 30,

Ffriction = 40 - 30 = 10 N

c. The coefficient of kinetic friction is calculated by the formula "Ffriction = μk*Fnormal".

10 = μk*Fnormal (Fnormal = m*g = 5*9.8)

10 = μk*49,

μk=10/49 ≈ 0.205

Answer:

I guess C

Explanation:

cause you can just try with hot water and ice cubes you know.

and we all know that ice will melt and the hot tea will get cold.

Answer:

D option

Explanation:

heat move from hot source to cold sink untill equilibrium reached

Answer:

bruuuuuuuuh

Explanation:

id                  

Answer:

4.3 * 10^28 kg

Explanation:

Given:

Period, T = 84s

Radius of satellite orbit, r = 8*10^6

Using the relation :

M = 4π²r³ / GT²

Where G = Gravitational constant, 6.67 * 10^-11

M = 4*π^2*(8*10^6)^3 / 6.67 * 10^-11 * 84^2

M = (20218.191872 * 10^18) / 47063.52 * 10^-11

M = 0.4295937 * 10^18 - (-11)

M = 0.4295937 * 10^29

M = 4.295937 * 10^28 kg

M = 4.3 * 10^28 kg

Mass of planet Nutron = 4.3 * 10^28 kg

Answer:

d)infrared waves

Explanation:

A remote control uses light waves just beyond the visible spectrum of light—infrared light waves—to change channels on your TV. This region of the spectrum is divided into near-, mid-, and far-infrared.

Answer:

He would be in space.

Explanation:

Answer: What would happen if a human traveled to Uranus?

As an ice giant, Uranus doesn't have a true surface. The planet is mostly swirling fluids. While a spacecraft would have nowhere to land on Uranus, it wouldn't be able to fly through its atmosphere unscathed either. The extreme pressures and temperatures would destroy a metal spacecraft.

Explanation:

Answer:

The slope intercept form is probably the most frequently used way to express equation of a line. To be able to use slope intercept form, all that you need to be able to do is 1) find the slope of a line and 2) find the y-intercept of a line.

Explanation:

Answer:You plot the numbers and divide

Explanation:

The object takes 0.5 seconds to complete one rotation, so its rotational speed is 1/0.5 rot/s = 2 rot/s.

Convert this to linear speed; for each rotation, the object travels a distance equal to the circumference of its path, or 2π (1.2 m) = 2.4π m ≈ 7.5 m, so that

2 rot/s = (2 rot/s) • (2.4π m/rot) = 4.8π m/s ≈ 15 m/s

thus giving it a centripetal acceleration of

a = (4.8π m/s)² / (1.2 m) ≈ 190 m/s².

Then the tension in the rope is

T = (50 kg) a ≈ 9500 N.

Answer:

true true true true true

This question is incomplete, the complete question is;

Styrofoam has a density of 32kg/m³.

What is the maximum mass that can hang without sinking from a 50-cm diameter Styrofoam sphere in water

Answer: the required maximum mass is 63.3459 kg

Explanation:

Given that;

diameter d = 50 cm = 0.5 m

radius r = 0.5 / 2 = 0.25 m

Styrofoam density = 32kg/m³

Volume of sphere V = 4/3 πr³.

we substitute

V = 4/3 π(0.25)³

V = 0.06544 m³

Mass of sphere M = Volume × Density

we substitute

Mass of sphere M = 0.06544 m³ × 32kg/m³

Mass of Sphere M = 2.09408 kg

Mass of the water it displace will be;

volume × density

we know that density of water = 1000 kg/m³

so

Mass of the water it displace = 0.06544 m³ × 1000kg/m³

= 65.44 kg

Now the difference between mass of water and mass of the Styrofoam will be the amount of mass that the sphere can support

so

65.44 kg - 2.09408 kg = 63.3459 kg

Therefore, the required maximum mass is 63.3459 kg

Answer:

t = 0.196 s

Explanation:

The speed of a pulse is determined by the characteristics of the medium, its density and its resistance to stress, as long as these remain the speed will be constant for which we can use the kinetic expressions of the uniform movement

          v = x / t

          t = x / v

calculate

          t = 2/102

          t = 0.196 s

Answer:

the mass of the box is 51.98 kg.

Explanation:

Given;

applied horizontal force, F = 450 N

coefficient of friction, μ = 0.795

constant velocity, v = 1.2 m/s

At constant velocity, the acceleration of the object is zero and the net force will be zero.

[tex]F_{Net} = F - F_k\\\\0 = F - F_k\\\\F_k = F\\\\\mu \ N = F\\\\\mu (mg) = F\\\\m = \frac{F}{\mu g} \\\\m = \frac{405}{0.795 \ \times \ 9.8} \\\\m = 51.98 \ kg[/tex]

Therefore, the mass of the box is 51.98 kg.

Answer:

D

Explanation:

transparent_objects that allows light to pass through and can you see through them

Answer: Yes indeed it does.

Explanation: Newton's Three Laws of Motion explain how forces create motion in sport. These laws are usually referred to as the Laws of Inertia, Acceleration, and Reaction. maybe brainliest to level up.

Answer: 0.85amps

Explanation: Power = 102watts; Voltage = 120voltsP = IxV ; I = P divided by V = 102 divided by 120 = 0.85amps