a 5.00 kg mass is at the origin. a 7.00 kg mass is located at x = 0.600 m, and a 4.00 kg mass is at x = 0.900 m. What is the net gravitational force on the 5.00 kg mass?

Answers

Answer 1

Answer:

Given,

A 5 kg mass is at the origin. A 7 kg mass is located at x = 0.6 m and a 4 kg mass is at x = 0.9 m.

To find,

the net gravitational force on the 5 kg mass.

we know, from Newton's gravitational law, two massive bodies attract each other by a force , F = Gm₁m₂/r²

so, 7 kg mass attracts 5kg mass by the force, F₁ = G(7kg)(5kg)/(0.6)²

= 35G/0.36 = 97.22G

similarly, 4kg mass attracts 5kg mass by the force, F₂ = G(4kg)(5kg)/(0.9)²

= 20G/0.81 = 24.69G

net gravitational force = F₁ + F₂

= 97.22G + 24.69G

= 121.91G

we know, G = 6.67 × 10¯¹¹ Nm²/Kg²

F = 121.91 × 6.67 × 10¯¹¹

= 813.1397 × 10¯¹¹ N

= 8.131397 × 10^-9 N ≈ 8.13 × 10^-9 N

Therefore net gravitational force acting on mass 5kg is 8.13 × 10^-9 N


Related Questions

Compare and Contrast atoms and ions..Thanks for your help!

Answers

Answer:

atoms is basic unit of matter, neutral because of the equal numbers to + and - particle charges.

ions is a charged molecule formed by the loss or gain of electrons.

Hope this helps

please hellllllllllppppppppp meeeeee​

Answers

Answer:

The displacement of the man has a magnitude of 40 m

Explanation:

Distance and Displacement

A moving object constantly travels for some distance at defined periods of time. The total distance is the sum of each individual distance the object traveled. It can be written as:

dtotal=d1+d2+d3+...+dn

This sum is obtained independently of the direction the object moves.

The displacement only takes into consideration the initial and final points of the path defined by the object in its moving. The displacement, unlike distance, is a vectorial magnitude and can be even zero if the object starts and ends the movement at the same point.

The man walks around half the circumference and ends up at the opposite side of the circled shape. Taking into consideration only the starting and ending points, the man's displacement is a vector whose magnitude is the diameter of the circle, thus:

The displacement of the man has a magnitude of 40 m

Can I have some help, please?

Answers

Answer:

yes you can gwet help with a whole lot of nothing

Explanation:

To win the game, a placekicker must kick a football from a point 44 m (48.1184 yd) from the goal, and the ball must clear the crossbar, which is 3.05 m high. When kicked, the ball leaves the ground with a speed of 24 m/s at an angle of 31◦
from the horizontal.
The acceleration of gravity is 9.8 m/s^2.
By how much vertical distance does the ball clear the crossbar?
Answer in units of m.

Answers

Answer:

The distance by the ball clear the crossbar is 1.15 m

Explanation:

Given that,

Distance = 44 m

Speed = 24 m/s

Angle = 31°

Height = 3.05 m

We need to calculate the horizontal velocity

Using formula of horizontal velocity

[tex]u_{x}=u\cos\theta[/tex]

Put the value into the formula

[tex]u_{x}=24\cos(31)[/tex]

[tex]u_{x}=20.5\ m/s[/tex]

We need to calculate the vertical velocity

Using formula of vertical velocity

[tex]u_{y}=u\sin\theta[/tex]

Put the value into the formula

[tex]u_{y}=24\sin(31)[/tex]

[tex]u_{y}=12.3\ m/s[/tex]

We need to calculate the time

Using formula of time

[tex]t=\dfrac{d}{u_{x}}[/tex]

Put the value into the formula

[tex]t=\dfrac{44}{20.5}[/tex]

[tex]t=2.1\ sec[/tex]

We need to calculate the vertical height

Using equation of motion

[tex]h=u_{y}t+\dfrac{1}{2}at^2[/tex]

Put the value into the formula

[tex]h=12.3\times2.1-\dfrac{1}{2}\times9.8\times(2.1)^2[/tex]

[tex]h=4.2\ m[/tex]

We need to calculate the distance by the ball clear the crossbar

Using formula for vertical distance

[tex]d=h-3.05[/tex]

Put the value of h

[tex]d=4.2-3.05[/tex]

[tex]d=1.15\ m[/tex]

Hence, The distance by the ball clear the crossbar is 1.15 m

what is steam engine it's action and reaction​

Answers

Explanation:

steam shooting out through 2 l shaped Falls creators and action force that is accompanied by backward reaction in force in opposite direction

How far did the object travel by the end of eight seconds, according to the graph above?
A) It traveled 4 centimeters.
B) It traveled 8 centimeters.
C) It traveled 12 centimeters.
D) It traveled 20 centimeters.

Answers

Answer:

The object traveled 4 cm by the end of eight seconds. Correct: A)

Explanation:

Speed vs Time Graph

In a speed-time graph, speed is plotted on the vertical axis and time is plotted on the horizontal axis. If the graph is a horizontal line, the speed is constant, if the line is sloped up, the speed is increasing and the acceleration is positive and constant, and if the line is sloped down, the speed is decreasing and the acceleration is negative and constant.

The distance traveled by the object can be found by calculating the area under the graph and above the x-axis.

The graph provided shows two different zones: the first 4 seconds, the speed is constant at 1 cm/s, and the last 4 seconds, the speed is zero, i.e. the object is not moving.

The area behind the first zone is a rectangle of height 1 cm/s and base 4 sec, thus the distance is 1 * 4 = 4 centimeters.

The second zone corresponds to an object at rest, thus no distance is traveled.

The object traveled 4 cm by the end of eight seconds.

A) Correct. As shown above

B) The distance traveled is 4 cm. Incorrect

C) The distance traveled is 4 cm. Incorrect

D) The distance traveled is 4 cm. Incorrect

Which solutions have a density greater than 1.0 g/mL?
Mass = 888 g Volume = 800 mL
Mass = 7.8 g Volume = 8.7 ml
Mass = 725 g Volume = 715 mL
Mass = 1.3 g Volume = 1.1 ml
Mass = 18 g Volume = 19 mL
Mass = 1.25 g Volume = 1.78 ml

Answers

Density = Mass / Volume

A) Density = 888/800 = 1.11g/mL > 1.0g/mL
B) Density = 7.8 / 8.7 = 0.897g/mL < 1.0g/mL
C) density = 725 / 715 = 1.01 g/mL > 1.0g/mL
D)density = 1.3/1.1= 1.18 g/mL > than 1.0 g/mL
E) Density = 18/19 = 0.95g/mL < 1.0g/mL
F) Density = 1.25/1.78 = 0.7 g/mL < 1.0g/mL

SUMMARY:
A C D have densities greater than 1.0g/mL

The solutions that have their mass greater than their volumes are:

Mass = 888 g Volume = 800 mL  Mass = 725 g Volume = 715 mL Mass = 1.3 g Volume = 1.1 ml

The ratio of the mass of a substance to its volume is known as the density of the substance. Mathematically;

Density = Mass/Volume

For any solution to have a density greater than 1, the mass of the substance must be greater than its volume.

For the given option, the solutions that have their mass greater than their volumes are:

Mass = 888 g Volume = 800 mL  Mass = 725 g Volume = 715 mL Mass = 1.3 g Volume = 1.1 ml

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On an average, a human heart is found to beat 75 times in a minute. Calculate its frequency and time period.

Answers

1 min=60sHeart beats per minute=75

Frequency=

75/60=5/4=1.25s^{-1}

Now

Time period:-

[tex]\\ \rm{:}\dashrightarrow \dfrac{1}{\nu}[/tex]

[tex]\\ \rm{:}\dashrightarrow \dfrac{1}{1.25}[/tex]

[tex]\\ \rm{:}\dashrightarrow \dfrac{4}{5}[/tex]

[tex]\\ \rm{:}\dashrightarrow 0.8s[/tex]

what is the measure of m​

Answers

Answer:

x = 50°

Explanation:

52° + 78° + x = 180° (Because of the angle sum property)

=> 130° + x = 180°

=> x = 180° - 130°

=> x = 50°

Answer:

50°

Explanation:

Step 1:

52° + 78° + x = 180°       Sum of a Δ

Step 2:

130° + x = 180°       Combine Like Terms

Step 3:

x = 180° - 130°      Subtract 130° on both sides

Answer:

x = 50°

Hope This Helps :)

I really need help with this, I would be happy if someone could help me.

You fly round-trip from Los Angeles to New York. The flight takes 6 hours each way and covers a distance of 4800 km. What were your average speed and average velocity on this round-trip flight?

Answers

Answer:

Average speed = 800 km/h and average velocity = 0

Explanation:

You fly round-trip from Los Angeles to New York.

Distance covered, d = 4800 km in 6 hours

We need to find the average speed and average velocity on this round-trip flight. Round trip means to come back at the initial point.

Total distance = 4800 km + 4800 km = 9600 km

Time, t = 6 h + 6 h = 12 h

Average speed,

[tex]v=\dfrac{9600\ km}{12\ h}\\\\v=800\ km/h[/tex]

So, the average speed is 800 km/h

When it comes back to the initial point. Its displacement is equal to 0. It means its average velocity will be equal to 0.

1. A mass of 630g is hung on a spring. Using Force = mass x gravity, what is the force of the mass, acting on the spring?

Answers

Answer:

The answer is 6.3

Explanation:

[tex]f \: = \: m(kg) \times g( \frac{n}{kg} )[/tex]

[tex]f \: = \: 630 \times {10}^{ - 3} \times 10 = 6.3[/tex]

The normal force acting on a body is the weight by gravitational pull of earth. The force acting on the hanging mass of 630 g is 6.17 N.

What is force?

Force is an external agent acting on a body to deform it or to change it from the state of rest or motion. Force is a vector quantity having both magnitude and direction.

A  normal force acting on a body is due to its weight by gravitational pull of earth. The force of gravitation is a kind of force by which an object attracts other objects into its centre of mass. The strength of force depends on the mass of the object.

The weight of an object in earth is the product of its mass and gravity. The acceleration due to gravity on earth is 9.8 m/s². Therefore, the force by weight of the hanging mass of 630 g or 0.630 Kg is :

0.63 × 9.8 m/s² = 6.17 N.

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In the graph above, what is the instantaneous speed of the object after the first five seconds?
A) 0 m/s
B) 5 m/s
C) 12.5 m/s
D) 25 m/s

Answers

Answer:

D) 25 m/s

Explanation:

In order to solve this problem we must use the following kinematics equation.

[tex]v_{f} =v_{i} +(a*t)\\[/tex]

where:

Vf = final speed [m/s]

Vi = initial speed = 0

a = acceleration = 5[m/s^2]

t = time = 5[s]

After 5 seconds the acceleration is equal to 5 [m/s^2]

Now replacing the values in the equation:

Vf = 0 + (5*5)

Vf = 25[m/s]

A group of stars connected by lines is circled and labeled Saturn.

The night sky is filled with images of wild animals. Which animal is the circled constellation named after?


scorpion

serpent

snake

salamander

Answers

Answer: scorpion I think

Which type of force is shown in the image?

Answers

Answer:

D contact force

Explanation:

How fast Will a brick be going after it falls for 2.5 seconds?

Answers

Answer:

25 m/s

Explanation:

Initial Velocity = 0 m/s

Time = 2.5 m/s

Acceleration due to gravity = 9.8

Final Velocity = ?

By the formula,

                           [tex]V_{f} = V_{i} + at[/tex]

                            [tex]V_{f}= 0 + 10 x 2.5[/tex]

                            Vf = 25 m/s

After 2.5 seconds the velocity of ball will be 24.5 m/s.

We have a brick falling from a certain height.

We have to find the velocity of the brick after 2.5 seconds of falling.

What do you mean by Free fall ?

The motion of any object under the influence of gravity alone is called as free fall.

According to the question -

Initial velocity = u = 0 m/s

Final velocity = v m/s (say)

g = 9.8 m/[tex]s^{2}[/tex]

t = 2.5 seconds

Using the first equation of motion -

v = u + at

v = 0 + gt

v = 9.8 x 2.5 = 24.5 m/s

Hence, after 2.5 seconds the velocity of ball will be 24.5 m/s.

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Davien and Jackson are headed to a beach that is 50km from school. At noon, Davien leaves his house that is 10 km closer to the beach than the school is and moves at 40 km/h. Jackson starts from school at 12:30 P.M. And moves at 100 km/h. What time does Davien reach the beach? * Answer Format: Time

Answers

Distance between Davien's school and beach, D = 50 km.

Also, Davian's house is 10 km closer to the beach than the school.

So, distance between Davien's house and beach, d = 40 km.

Speed of Davian, s = 40 km/h.

Now, time taken is given by :

[tex]t =\dfrac{Distance}{Speed}\\\\t=\dfrac{40}{40}=1\ hour[/tex]

Therefore, Davien reach the beach at 1 : 30 P.M .

Hence, this is the required solution.

A heavy brick weighs more than a fluffy cushion, but the cushion takes up more space. Which object has more matter? How do you know?

Answers

Answer:

Explanation:The brick has more matter because it has more mass. :))

Propane burns in oxygen to produce carbon dioxide and water. What are the chemical formulas of the reactants and products? The formulas of the reactants are C3H8, O, and CO2. The formula of the product is H2O. The formulas of the reactants are C3H8 and O2. The formulas of the products are CO and H2O. The formulas of the reactants are C3H8 and O2. The formulas of the products are CO2 and H2O.

Answers

Answer:

The formulas of the reactants are C3H8 and O2. The formulas of the products are CO2 and H2O.

Explanation:

Propane is the third member of the alkane group with the general formula CnH2n+2. According to this question, propane burns in oxygen to produce carbon dioxide and water. This means that propane and oxygen are the reactants of this reaction while carbon dioxide and water are the products.

The chemical formulas of the respective reactants and products are as follows:

REACTANTS:

Propane = C3H8 i.e C3H(2×3)+2

Oxygen = O2

PRODUCTS:

Carbon dioxide = CO2

Water = H2O

The balanced chemical reaction is as follows:

C3H8 + 5O2 ----> 3CO2 + 4H2O

Answer:

Option C would be your answer!

The formulas of the reactants are C3H8 and O2. The formulas of the products are CO2 and H2O.

Also, for the second part, the answer is Option B!

C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g)

Explanation:

This is correct on Edge! :D

I hope this helped!

Which phenomenon is an example of electric discharge?

A) Friction


B) Lightning


C) Magnetism


D) Static cling

Answers

I think it is D pls don’t get mad if is wrong I am not really sure

which of the following would typically be used to express speed

Answers

Answer:

One term that could be used as speed is sprint or rush

Explanation:

What’s the mass of the sample please help me!

Answers

Answer:

A. 0,11

Explanation:

Sorry if wrong. i hope this helps. thank you.

An airplane flying at a speed of 130 mi/h (58.1 m/s) and at an altitude of 4.9 km drops a food package. Without a parachute, at what angle (degrees) below the horizontal will the package strike the ground?

Answers

The food package will strike the ground at 11 degrees below the horizontal.

Time for the food package to hit the ground

The time for the food package to hit the ground is calculated as follows;

h = vt + ¹/₂gt²

let the initial velocity be horizontal

4900 = 0(t) + (0.5 x 9.8)t²

4900 = 4.9t²

t² = 4900/4.9

t² = 1,000

t = √1,000

t = 31.62 s

Final speed of the food package when it hits ground

vf(y) = vo + gt

vf(y) = 0 + (31.62 x 9.8)

vf(y) = 309.88 m/s

Angle of projection

The horizontal component of the speed will be constant, while vertical component will change

[tex]tan(\theta ) = \frac{V_y}{V_x} \\\\\theta = tan^{-1} (\frac{V_y}{V_x})\\\\\theta = tan^{-1} (\frac{309.88}{58.1} )\\\\\theta = 79^0[/tex]

Angle below the horizontal = 90 - 79 = 11⁰

Thus, the food package will strike the ground at 11 degrees below the horizontal.

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Which would have a longer vector arrow?
a: A vector representing 100 miles/hour north
b: Avector representing 100 miles/hour east
c: A vector representing 100 miles/hour south
d: They would all be the same length​

Answers

All the vectors would all be the same length.

option D is the correct answer.

What is the magnitude of a vector?

The magnitude of a vector is the length of the vector. This is the absolute value of the vector.

The length of a vector describes its magnitude, so the magnitude or length of the given vectors is determined as follows;

A vector representing 100 miles/hour north ⇒ magnitude = 100 miles / hour

A vector representing 100 miles/hour east ⇒ magnitude = 100 miles / hour

A vector representing 100 miles/hour south ⇒ magnitude = 100 miles / hour

Thus, all the given vectors have equal magnitude but different directions.

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You lift your pet cat vertically by 2.0 m, and
then you lower it vertically by 2.0 m. During this
exercise, is the total work done by gravity positive,
negative, or zero? Explain your answer.

Answers

Answer:

zero cause the positivity and negativity would cancel out

Explanation:

It
starts at position 0 and moves to the right until it arrives at
position 1. It then turns around and stops at position 2.
What is the average velocity of the ghost for the entire trip
if the entire trip takes 7 seconds?
0 -1.42 m/s
-1.42
1.42
O 1.42 m/s

Answers

The answer is 0 -1.42 m/s

he cai
9) Mount Everest is 8848 m above the sea level. Find the
acceleration due to gravity at this height. The value of
acceleration due to gravity at the earth's surface is 9.8 m/s2
and the radius of the earth is 6400km.​

Answers

Given parameters:

Height of Everest  = 8848m

Acceleration due to gravity on earth  = 9.8m/s²

Radius of the earth = 6400km = 6400000m

Unknown:

Acceleration due to gravity at the peak of Everest  =?

Solution:

According to Newton's law of universal gravitation, we have that acceleration due to gravity is proportional to the altitude.

 To solve this problem, use the mathematical expression below;

        g[tex]_{e}[/tex]   = g(1 - [tex]\frac{2h}{R}[/tex])

where g[tex]_{e}[/tex]  is gravity on top of Everest

            g is the gravity on the earth surface

            h is the height of the mountain

            R is the radius of the earth

      g[tex]_{e}[/tex]   = 9.8 (1 -[tex]\frac{2 x 8848}{6400000}[/tex] )

      g[tex]_{e}[/tex]  = 9.8 (1-0.002765)   = 9.77m/s²

The acceleration due to on top of Everest is  9.77m/s²

Question 8 of 10
Which term describes the sum of all forces acting on an object
A Free body force
B. Centripetal force
0, Nat force
D. Reaction force

Answers

Answer:

Net force ! because it the total force that being addednon the obj !

When your mass increases, your weight remains constant , True or false

Answers

I think the answer is true

An immersion heater is rated 120w. How long does it take the heater to raise the temperature of 1.2kg of water by 15°c.

Answers

Answer:

dmakqkwnwj fddfgdddwsf

Which pair does NOT have an electric force between them?.

Answers

Two neutral objects will not have any electric force of attraction or repulsion between them.

What is the condition for the electric force between two objects?

As we know from the electrostatics that whenever there are two charges having a positive charge on one and a negative on the other will attract each other

similarly, if they are having like charges which are both of them having positive or both of them having a negative charge then there will be a force of repulsion between them.

But if both of them or even one of them is neutral then there will not be any electric force between them.

Thus neutral objects will not have any electric force of attraction or repulsion between them.

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