A 5.00-kg ball, moving to the right at a velocity of +2.00 m/s on a frictionless table, collides head-on with a stationary 7.50- kg ball. Find the final velocities of the balls if the collision is (a) elastic and (b) completely inelastic

Answers

Answer 1

The velocity of the balls if the collision is perfectly elastic is -0.78 m/s and v₂ = 1.98 m/s.

What is Elastic and inelastic collisions?

A state where there is no net loss in the kinetic energy in the system of two objects as the result of the collision is called as an elastic collision.

Inelastic collisions is a type of collision where there is a loss of kinetic energy.

Using the law of conservation of momentum:

m₁u₁ + m₂u₂ = m₁v₁ + m₂ v₂ (u₂ = 0)

5 x 2 = 5v₁ + 7v₂

10 = 5v₁ + 7v₂

v₂ = (10 - 5v₁)/7

Elastic collision so kinetic energy conserved:

1/2 x 5 x (2)²  = 1/2 (5v₁² + 7v₂²)

20 = 5v₁² + 7((10 - 5v₁)/7)²

140 = 35v₁² + 5v₁² + 100 - 20v₁

40v₁² - 20v₁ - 40 = 0

v₁ = -0.78 m/s

The first ball is lighter so its velocity will change direction due to collision.

v₁ = -0.78 m/s

10 = 5(-0.78) + 7v₂

v₂ = 1.98 m/s

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Related Questions

A speaker use a 9V battery. It has a resistance of 200 ohms. What is the current flowing through the speaker?​

Answers

The current flowing through the speaker  is 0.045 ampere.

What is electric current?

The rate of electron passage in a conductor is known as electric current. The ampere is the electric current's SI unit. Electrons are little particles that are part of a substance's molecular structure.

The potential difference of the speaker = 9 V.

The resistance of the speaker = 200 Ω.

According to Ohm's law,

potential difference  = resistance × current flowing

Hence, the current flowing through the speaker =   potential difference ÷ resistance

= 9 V/200 Ω

= 0.045 Ampere.

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A rock is dropped from a sea cliff, and the sound of it striking the ocean is heard 3.7 s later.
If the speed of sound is 340 m/s, how high is the cliff?
Neglect all frictional forces.

Answers

The height of the cliff, given that the sound of rock dropped from the cliff was heard 3.7 s later is 629 m

How do I determine the height of the cliff?

We know that echo of sound wave is given by the following formula:

Speed = (2 × distance) / time

Using the above formula, we can determine the height of the cliff. This is illustrated below:

Time = 3.7 secondsSpeed of sound = 340 m/sHeight of cliff =?

Speed = (2 × height) / time

340 = (2 × height) / 3.7

Cross multiply

2 × height = 340 × 3.7

2 × height = 1258

Divide both sides by 2

Height = 1258 / 2

Height = 629 m

Thus, from the above calculation, we can conclude that the height of the cliff is 629 m

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2. Write the equation for finding speed (v) when given a displacement (difference between two positions X₁ and x2) and the corresponding interval (difference between two clock readings t₁ and t₂). After writing the equation, apply it to find the speed of Walking Dude.​

Answers

Based on the speed formula and the data provided on displacement and time, the speed of the walking dude is 200 m/s.

What is the formula for determining the speed of a body?

The formula for determining the speed of a body is given below:

Speed = x₁ - x₂ / t₁ - t₂

where;

x₂ - x₁ = change in displacement

t₂ - t₁ = change in time

The speed of the walking dude can be determined as follows:

1. Speed at t = 0.02 seconds

speed = 4 / 0.02

speed = 200 m/s

2.  Speed at t = 0.04 seconds

speed = 8 / 0.04

speed = 200 m/s

3.  Speed at t = 0.06 seconds

speed = 12 / 0.02

speed = 200 m/s

4.  Speed at t = 0.08 seconds

speed = 16 / 0.02

speed = 200 m/s

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How would I solve for KE with only mass no velocity?

Answers

Answer:

K.E = (p)^2 / 2m

Explanation:

the first method is : K.E = (p)^2 / 2m where p is the momentum of the object. so here u should be given the momentum and the mass of the object.

Which statement about energy is correct?

A. Energy is destroyed when a car uses gasoline.
B. Energy can be created in a power plant.
C. Energy can be classified as one of three types: potential energy, kinetic energy, and chemical energy.
D. Energy can be changed from one form to another.

Answers

Answer:

D

Explanation:

Energy can not be created or destroyed (law of conservation of energy), so that throws out choices A and B.  There are more classifications of energy than are listed in choice C.  D is the only true statement.

Circuits
Calculate the total Resistance, Current, and Power in the circuits

Answers

The equivalent resistance of the circuit = 8 Ω. Current = 3 Ampere. Power =  72 watt.

What is electrical circuit?

A circuit in electronics is a complete circular channel via which electricity flows. A current source, conductors, and a load make up a straightforward circuit. In a broad sense, the word "circuit" can refer to any permanent path through which electricity, data, or a signal can pass.

The equivalent resistance of the circuit = 2 Ω + 4 Ω + (6 Ω || 3Ω)

= 8 Ω

Current flowing through the circuit = (24 V ÷ 8 Ω) = 3 Ampere.

Power = VI = 24 × 3 watt = 72 watt.

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why is the persistence method of forecasting limited?

Answers

The persistence method is the simplest forecasting method. But it has its own limitations.

When weather patterns change slowly and features on weather maps move slowly, the persistence approach works effectively. It also works effectively in regions where the weather varies little from day to day throughout the summer. However, if the weather changes drastically from day to day, the persistence approach frequently fails and is not the ideal forecasting strategy to utilize.

It may appear that the persistence forecast is only useful for shorter-term forecasts like for day or two. However one of the most significant tasks of the persistence forecast is anticipating long-term weather conditions or producing climate forecasts. Making long-term projections for monthly and seasonal weather conditions requires considerable ability. For predictions longer than ten days, certain alternative forecasting approaches, such as numerical weather prediction, lose all of their accuracy. Persistence is therefore a "hard to beat" strategy for forecasting over extended time periods.

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What is the current reading on the ammeter A?

Answers

The current reading on the ammeter A is 0.30 A.

What is electric current?

A stream of charged particles, such as electrons or ions, travelling through an electrical conductor or a vacuum is known as an electric current. The net rate of electric charge flowing through a surface or into a control volume is how it is calculated.

Charge carriers, which can be any of a number of particle kinds depending on the conductor, are the moving particles.

Current is scalar quantity and it follows the algebraic summation during addition.

The current reading on the ammeter A is = (0.20 A + 0.10 A) = 0.30 A.

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Suppose 2.00 V is applied to a parallel plate capacitor having plates of area 5.00 m2 that are separated by 0.121 mm of Teflon. Determine the charge stored in the capacitor. (Teflon κ=2.1)

Answers

The charge stored in the capacitor is 9.94 x 10^-10 C.

What is the charge stored in the capacitor?

The capacitance C of a parallel plate capacitor is given by the formula:

C = ε₀ε₁A / d

where ε₀ is the permittivity of free space (8.85 x 10^-12 C^2/Nm^2), ε₁ is the permittivity of the dielectric material (Teflon, with a value of 2.1 x 8.85 x 10^-12 C^2/Nm^2), A is the area of the plates (5.00 m^2), and d is the distance between the plates (0.121 mm = 0.121 x 10^-3 m).

Plugging in the values, we get:

[tex]C = ε₀ε₁A / d = (8.85 x 10^-12 C^2/Nm^2) (2.1) (5.00 m^2) / (0.121 x 10^-3 m) = 4.97 x 10^-10 F[/tex]

The charge stored in the capacitor is given by the formula:

Q = CV

where V is the voltage applied across the capacitor (2.00 V). Plugging in the values, we get:

[tex]Q = CV = (4.97 x 10^-10 F) (2.00 V) = 9.94 x 10^-10 C.[/tex]

So the charge stored in the capacitor is 9.94 x 10^-10 C.

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0. •Given that the apparent expansivity of a liquid is 0.00015³ 1² and the linear expansivity of the container is 0.00012

Answers

The real expansion of the apparent expansion of 0.00015 x 10⁻³  per Kelvin and the linear expansion of the container 0.00012 x 10⁻³ per kelvin is 1.8 x 10⁻¹³ per Kelvin.

Apparent expansion is the expansion we see when a liquid is heated without a vessel is called true expansion. The expansion of a liquid that is felt without taking into account the expansion of its container is called apparent expansion. The actual expansion of a liquid is always greater than the apparent expansion.

For actual expansion, the following formula is used:

real area = apparent area x linear area

So,

real expansivity = 0.00015 x 10⁻³ x 0.00012 x 10⁻³

real expansivity = 0.000000018 x 10⁻⁶

real expansivity = 1.8 x 10⁻¹³

The answer is 1.8 x 10⁻¹³ per Kelvin.

Your question is incomplete but most probably your full question was:

Given that apparent expansivity of a liquid is 0.00015x10(raised to power -3) per Kelvin and the linear expansivity of the container is 0.00012 x 10(raised to power -3) per Kelvin, calculate the real expansivity.

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What type of decay is this?

Answers

Answer:

It is Gamma decay of radiation.

1)A remote controlled car moves on the ground. The parametric equations of its motion are:
X (t)= 5-20t e y(t)= -1+6t^2-2t.
a) Predict the trajectory of the particle.
b) Characterize the movement along each coordinate axis
c) What is the average acceleration in the first second of motion? And the acceleration in t= 1s

Answers

For a remote controlled car on the ground: X (t)= 5-20t e y(t)= -1+6t²-2t.

a) The trajectory of the particle can be found by plotting the values of x and y as a function of time, t.

b) The movement along each coordinate is 2 seconds.

c) Average acceleration and acceleration is 16m/s² and 2m/s² respectively.

How to calculate motion?

b) The movement along each coordinate axis can be characterized by considering the behavior of x(t) and y(t) separately. The x-coordinate, x(t), decreases with time and reaches a minimum value of -15 at t=1 second. The y-coordinate, y(t), increases with time, reaches a maximum value of 3 at t=1 second, and then decreases to 0 at t=2 seconds.

c) To find the average acceleration in the first second of motion, find the average velocity over that time interval and then find its derivative. The average velocity in the first second of motion can be calculated as the average of the initial velocity and the final velocity. The initial velocity is -19 m/s and the final velocity is -13 m/s, so the average velocity is -16 m/s. The derivative of velocity with respect to time is acceleration. So, the average acceleration in the first second of motion is (13-(-19))/2 = 16 m/s².

The acceleration in t=1s can be found by taking the derivative of velocity with respect to time. At t=1 second, the velocity is -13 m/s and the acceleration is (3-(-1))/(1-(-1)) = 2 m/s².

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What is the angle between the vectors A and - A when they are drawn from a common origin?

Answers

Answer:

180

Explanation:

Because both are anti-parallel.

The driver of a pickup truck going 100 m/s applies the brakes, giving the truck a uniform acceleration of 6.5m/s^2 while it travels 20.0m.

a. What is the speed of the truck in kilometers per hour at the end of this distance?
b. How much time has elapsed?

Answers

Answer:

The speed of the truck in kilometers per hour at the end of the 20.0m distance is approximately 36.4km/h. The time elapsed is approximately 3.03 seconds.

Explanation:

Answer:

The speed of the truck in kilometers per hour at the end of the 20.0m distance is approximately 36.4km/h. The time elapsed is approximately 3.03 seconds.

Explanation:

Which of the following best describes why astronauts have to wear gravity boots when they are on the moon but not
when they are on the Earth?
A The moon's gravity is stronger than Earth's gravity.
The moon's surface is denser than the Earth's surface.
The Earth's gravity pulls them down to the Earth's surface.
The Earth's surface is magnetic, but the moon's surface is not.

Answers

The best description of why astronauts have to wear gravity boots on the moon but not on Earth The moon's gravity is stronger than Earth's gravity.

What is gravity?

The best description of why astronauts have to wear gravity boots on the moon but not on Earth is that the moon's gravity is weaker than Earth's gravity. The force of gravity is the attraction between two objects with mass, and the strength of the force depends on the mass of the objects and the distance between them. The moon has much less mass than the Earth, so its gravitational force is much weaker.

This means that objects on the moon weigh much less than they do on Earth, and astronauts have to wear gravity boots to keep from floating away. On the Earth, the force of gravity is much stronger, so objects are pulled down to the Earth's surface. This is why we don't need gravity boots to walk around on the Earth. The density of the surface or the magnetic properties of the surface do not play a significant role in this context.

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7. Two small cubes have 8 µC charge each.
First the cubes are placed 10 cm apart, and
then they are moved closer so they are 2 cm
apart. Which of these correctly describes
how the force between the charges changes?

Answers

The labor involved in moving two charges from a distance of 'd 1 '=10 cm to a closer distance of 'd 2 '=4 cm must be determined for two charges q 1 =12 C and q 2 =8 C.

Does capacitance enhance electric potential?

Between capacitor plates, the field is constant, but the potential rises linearly. As long as the geometry of the capacitor doesn't change, the capacitance won't either. The potential difference will therefore rise in a straight line with the charge since C = Q/V.

To do this, we first determine the charge in the system's potential energy and then take the difference.

Now, d 1 =10cm=1010 2 =10 1 m, and d 2 =4cm=410 2 m.

Consequently, potential (V 1) equals 4 0 when q 1 and q 2 are separated by d 1.

Potential (V 2) equals 4 0 when q 1 and q 2 are separated by a distance of d 2.

Work completed =V 2 + V 1 = 0

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A balloonist is directly above a straight road 1.6 miles long
that joins two towns. She finds that the town closer to her is
at an angle of depression of 36° and the farther town is at
an angle of depression of 32°. How high above the ground
is the balloon?

Answers

The height of the balloon is 1.3 miles above the ground.

What is height?

Height is the measure of vertical distance, either how "tall" something or someone is, or how "high" the point is. For example, a person's height is typically measured using a stadiometer and is recorded in centimeters or feet and inches. The height of a mountain is usually measured in meters or feet. In aviation, height is measured from the surface of the earth, either above ground level (AGL) or above mean sea level (AMSL).

The answer to this question can be found by using the trigonometric formula of Tangent. To calculate the height of the balloon, we must find the length of the hypotenuse in the triangle formed by the two towns and the balloonist.

Using the formula for tangent, we can calculate the length of the hypotenuse. The formula is:

tan (angle) = opposite side/adjacent side

In this case, the opposite sides are the two towns, and the adjacent side is the height of the balloon.

For the first town, the formula is:

tan 36° = 1.6/x

Solving for x, we can calculate the length of the hypotenuse for the first town to be 2.8 miles.

For the second town, the formula is:

tan 32° = 1.6/x

Solving for x, we can calculate the length of the hypotenuse for the second town to be 2.9 miles.

Since the hypotenuse is the total distance between the two towns and the balloonist, the height of the balloon can be calculated by subtracting the total length of the two towns (1.6 miles) from the hypotenuse of the second town (2.9 miles).

The height of the balloon is 1.3 miles above the ground.

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A girl is swinging on a swing. At the lowest point of her swing, she has 900 J of kinetic energy and 300 J of potential energy. A moment later, she has 552 J of kinetic energy. What is her potential energy at this point, in J?

Answers

The potential energy at that point is  648 J.

What is her potential energy?

We have to note that by the use of the law of the conservation of the mechanical energy that energy can not be created or destroyed but that the energy can be converted from one form to the other.

We now know that the total energy of the system is; 900 J + 300 J = 1200 J

It then follows from the law of the conservation of the mechanical energy that this total energy must be constant.

Potential energy at that point = 1200 J - 552 J

= 648 J

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A typical industrial-scale wind turbine has a peak efficiency of about 0.44 for a wind
speed of 9 m·s−1. That is, it converts about 44% of the kinetic energy of the wind
approaching it into usable electrical energy. The total air flow impinging on such a
turbine with a rotor diameter of 43 m is about 15,000 kg·s−1 for the given wind speed.(a) How much electrical energy is produced when 1 kg of air passes through the
turbine?
(b) What is the power output of the turbine?
(c) If there is no heat transferred to the air, and if its temperature remains
unchanged, what is its change in speed upon passing through the turbine?

Answers

1 kg of air passing through the turbine produces 1.98 kg m^2/s^2 of energy.

How much electrical energy is produced?

The energy produced by the turbine can be calculated as follows:

Energy = Efficiency x Kinetic Energy of air

Efficiency = 0.44

Kinetic Energy of air = 1/2 * Mass * Velocity^2

Mass = 1 kg

Velocity = 9 m/s

Plugging in the values:

Energy = 0.44 * (1/2 * 1 kg * 9^2 m^2/s^2) = 0.44 * (1/2 * 9 kg m^2/s^2)

= 0.44 * 4.5 kg m^2/s^2

= 1.98 kg m^2/s^2

So 1 kg of air passing through the turbine produces 1.98 kg m^2/s^2 of energy.

(b) The power output of the turbine can be calculated as follows:

Power = Energy / Time

Time = 1 s (time taken by 1 kg of air to pass through the turbine)

Plugging in the values:

Power = 1.98 kg m^2/s^2 / 1 s = 1.98 kg m^2/s^3

= 1.98 J/s

= 1.98 Watts

So the power output of the turbine is 1.98 Watts.

(c) The change in velocity can be calculated using the law of conservation of energy:

Initial Kinetic Energy + Work done on air = Final Kinetic Energy

Work done on air = Efficiency x Initial Kinetic Energy

Plugging in the values:

Initial Kinetic Energy = 1/2 * 1 kg * 9^2 m^2/s^2 = 40.5 kg m^2/s^2

Work done on air = 0.44 * 40.5 kg m^2/s^2 = 17.82 kg m^2/s^2

Final Kinetic Energy = 40.5 kg m^2/s^2 - 17.82 kg m^2/s^2 = 22.68 kg m^2/s^2

Final Velocity = sqrt(2 * Final Kinetic Energy / Mass)

Plugging in the values:

Final Velocity = sqrt(2 * 22.68 kg m^2/s^2 / 1 kg) = sqrt(45.36 kg m^2/s^2)

= 6.72 m/s

So the change in velocity of the air upon passing through the turbine is 9 m/s - 6.72 m/s = 2.28 m/s.

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please help
Mineral classes such as halides, sulfates, carbonates, oxides, and sulfides can contain all of the following elements, except _____.

silica
oxygen
fluorine
sulfur

Answers

Mineral classes such as halides, sulfates, carbonates, oxides, and sulfides can contain all of the following elements except silica.

Answer:

silica

Explanation:

A piece of uranium drops from 1500 Celsius to 900 Celsius what state of matter would we expect it to be in 

Answers

At 900 degrees Celsius, we would expect the uranium to be in a solid state.

What is phase transition theory?

The theory used in this question is the phase transition theory.

This theory states that when a substance is heated or cooled, it can change from one state of matter to another, such as from a solid to a liquid or from a liquid to a gas.

It explains the behavior of matter at different temperatures.

Uranium is a metallic element that can exist in a solid, liquid, or gaseous state depending on its temperature.

When the temperature of uranium is above its melting point of 1132°C, it will be in a liquid state.

When the temperature of uranium drops from 1500°C to 900°C, it will pass through the liquid state and become a solid.

At 900°C, the uranium will be in a solid state.

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The distance versus time graph for Object A and Object B are shown.

A graph titles Distance vs Time. A curved line is drawn through point 10 on y axis and this line is labeled Object A. The graph for Object B is a straight slanting line passing through the origin

Which statement best describes the motion of Object A and Object B?

Both objects move with variable speed.
Both objects move with constant speed.
Object A moves with constant speed and Object B moves with variable speed.
Object A moves with variable speed and Object B moves with constant speed.

Answers

The statement that best describes the motion of Object A and Object B is that Object A moves with variable speed and Object B moves with constant speed.

What is speed?

The speed of an object is described as the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time. Speed is thus a scalar quantity.

From the graph, we can deduce that Object A moves with variable speed as there is change in its movement towards a specified part and Object B moves with constant speed.

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Find the gravitational field on the surface of an alien planet that has an estimated mass of 8.5 x 1026 kg and radius of 3.5 x 104 km. Show all work

Answers

The gravitational field on the surface of the planet is approximately 9.81 m/s^2

What is gravitational field?

Gravitational field can be defined as the force field that exists in the space around every mass or group of masses.

The gravitational field on the surface of a planet can be calculated using Newton's law of gravitation:

G * m_planet / r^2

Where:

G = 6.67 x 10^-11 Nm^2/kg^2 is the gravitational constant

m_planet = 8.5 x 10^26 kg is the mass of the planet

r = 3.5 x 10^4 km is the radius of the planet (converted to meters)

First, let's convert the radius to meters:

3.5 x 10^4 km = 3.5 x 10^4 x 10^3 m = 3.5 x 10^7 m

Next, let's plug in the values and simplify the expression:

g = G * m_planet / r^2

g = (6.67 x 10^-11 Nm^2/kg^2) * (8.5 x 10^26 kg) / (3.5 x 10^7 m)^2

g = (6.67 x 10^-11 Nm^2/kg^2) * (8.5 x 10^26 kg) / (1.225 x 10^15 m^2)

g = 9.81 m/s^2

Therefore, The gravitational field on the surface of the planet is approximately 9.81 m/s^2

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Which material could you claim is translucent?
A. pure air
B. clear plastic
frosted glass
D. construction paper PLEASE HELP

Answers

Answer:c

Explanation:edge 2023

Answer: c is actually true

Explanation:

a body of mass 5kg accelerates uniformly with a steady force of 20N. calculate the speed of the car after 5 seconds

Answers

Answer:

F=ma

v-u=at

Explanation:

F=ma

v-u=at

A car has an acceleration of 4m/s squared. What will the increase in its velocity be after 2 seconds? If it started with a velocity of 30m/s, what is its final velocity?

Answers

A car has an acceleration of 4m/s squared. If it started with a velocity of 30m/s, 38m/s is its final velocity.

What is acceleration?

Acceleration: the rate at which the speed and direction of a moving object vary over time. A point or object going straight forward is accelerated when it accelerates or decelerates.

Even though the speed is constant, motion on a circle accelerates so because direction is always shifting. Both tangential to the acceleration for all other motions.

v = u + at

V= final velocity=?

U= initial velocity=  30m/s

a= acceleration = 4m/s²

substituting all the given values in the above equation, we get

v = 30+ 4× 2

V= 38m/s

Therefore,  38m/s  is its final velocity.

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what role does observation play in weather forecasting

Answers

Observation is an integral part in scientific investigation. In weather forecasts, keen observation is very essential in weather forecast to scientifically report the climate changes.

What is weather forecasting ?

Weather forecasters provide up to date information regarding the changes in weather in different regions and the factors affecting it. The primary atmospheric measurements that aid weather forecasters in making their predictions are observation on temperature, humidity, precipitation, air pressure, wind speed, and wind direction.

Since the first weather observations were kept on record, these same criteria have been utilized. However, there have been substantial changes in the types and quality of weather devices as well as the approaches to evaluating observations.

Thermometers, rain gauges, barometers, and anemometers are common tools for observing the weather. Wind profilers, weather balloons  Doppler radar, and satellites are a few examples of more advanced equipment.

Human observations continue to give crucial information on sky conditions, clouds, and the kind, size, and amount of precipitation even with the highly sophisticated instruments currently accessible.

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Use the image to answer questions 41 through 43. Anita plays with some magnets. She learns that small round magnets have the north pole on one side and the south pole on the other. Anita hangs a small round magnet from a string. Then she attaches a paper bird to the south pole side of the magnet. The north pole side of the magnet is uncovered on the back of the bird. 41 Which of these actions would make Anita's bird move away from the object that moves toward it? A. moving the south pole end of a bar magnet toward the "bird side" of the round magnet B. touching the "bird side" of the round magnet with a metal clip C. touching the "bird side" of the round magnet with a plastic pen D. moving the north pole end of a bar magnet toward the "bird side" of the round magnet​

Answers

D. moving the north pole end of a bar magnet toward the "bird side" of the round magnet.

How do magnets work?

Magnets work due to the movement of electrons, which creates a magnetic field. In a magnet, electrons are lined up in such a way that their magnetic fields are all pointing in the same direction, creating a net magnetic field. When a magnet is near a piece of ferromagnetic material, such as iron, the electrons in the ferromagnetic material start to line up with the electrons in the magnet, resulting in an attractive force. This is how magnets stick to each other and to other ferromagnetic objects.

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Consider two vectors, what is the magnitude of |A-B|

Answers

The magnitude of |A-B| is given by √{A²+B²-2ABcosθ}.

What is vector?

In physics, a vector is a quantity with both magnitude and direction. It is often represented by an arrow whose length is proportional to the magnitude of the quantity and whose direction is the same as that of the quantity.

A vector does not have position, while having magnitude and direction. In other words, a vector's shape is unaltered if it is shifted parallel to itself as long as its length is unaltered.

Let consider two vector [tex]\vec{A}[/tex] and [tex]\vec{B}[/tex] and angle between them is θ, then the magnitude of |A-B| is given by = √{A²+B²-2ABcosθ}

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The mass of the cold water is 13 Kg

What law of conservation of mass?

The law of conservation of mass states that in a closed system, the total mass of substances present in the system remains constant over time, regardless of the processes that take place within the system.

We can see that mass of the hot water = 10 Kg

Mass leaving = 33 Kg

Mass of the cold water = 33 Kg - 10 Kg

= 13 Kg

Since the mass is constant then if we apply the law of the  consideration of mas to the question that we have here we can see that the mass of teh cold water is 13 Kg.

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