A 2kg water balloon is flying at a rate of 4m/s^2. With what force will it hit its target?

Answers

Answer 1

Explanation:

F=m×a

m=2kg

a=4m/s^2

F=2kg×4m/s^2

F=8N

Answer 2

A 2 kg water balloon is flying at a rate of 4 m/s². Force with which balloon will hit its target is 8 Newton.

What is force?

A force is a push or pull upon an object resulting from the object's interaction with another object. Whenever there is body with some mass than there is force.

Given in the question mass and acceleration of balloon, force is given as

F = m*a

m = 2 kg

a = 4 m/s²

F = 2 kg×4 m/s²

F = 8 N

A 2 kg water balloon is flying at a rate of 4 m/s². Force with which balloon will hit its target is 8 Newton.

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Related Questions


1. You walk along a long straight school corridor for 55
m, then you turn around and walk 30 m in the
opposite. Finally, you turn again and walk 39 m in
the original direction and stop. What is your
displacement from your starting point?

Answers

Explanation:

14 m is the displacement and towards the north

Please I need help fast <3

Answers

Answer:

Where is the picture send again please

Explanation:

what metaphor most closely describes the nature of space-time?
a. chemistry formula
b.fabric
c. sine wave
d. moebius strip

Answers

Answer:

b.fabric

Explanation:

Nowadays, when people talk about space-time, they often describe it as resembling a sheet of rubber. This, too, comes from Einstein, who realized as he developed his theory of general relativity that the force of gravity was due to curves in the fabric of space-time.

Answer:

B. fabric

Explanation:

Change.
Wax melting is an example of a chemical reaction.
True or false

Answers

i believe it is a physical change not chemical

The wave height is equal to twice the _____.wave period wave height wave amplitude wave velocity wavelength

Answers

The wave height is equal to twice the amplitude of the wave.

The wave height of a wave of given wave with amplitude, period and wavelength is equal to twice the amplitude of the wave.

The amplitude of a wave is the maximum displacement of the wave, starting from the zero position of the wave. The wave height measures twice the maximum displacement of the wave.

Thus, we can conclude that the wave height is equal to twice the amplitude of the wave.

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What is the given formula for acceleration?.

Answers

Answer:

a=v/t (searched)

Explanation:

a=acceleration

v=change in velocity

t=time

(searched)

How many sulfur atoms are there in 25 molecules c4h4s2?.

Answers

There are 50 atoms (twice the amount of the molecules)

a 1200-kg pick-up truck traveling south at 15 m/s suddenly collides with a 750-kg car that is traveling east. the two vehicles stick together and slide along the road after colliding. a highway patrol officer investigating the accident determines that the final position of the wreckage after the collision is 25 m, at an angle of 50° south of east, from the point of impact. she also determines that the coefficient of kinetic friction between the tires and the road at that location was 0.40. what was the speed of the car just before the collision?

Answers

The conservation of momentum, Newton's second law and kinematics allows to find the result for the initial speed of the car is:

The speed of the car is 40 m/s at the East direction.

Given parameters

Mass of the truck M = 1200 kg. Truck speed v₀₁ = 15 m / s towards the South. Mass of the car m = 750 kg. Travel east The two vehicles unite. The braking distance d = 25m  at 50º SE The friction coefficient μ = 0.40

To find

The initial speed of the car.

The momentum is defined by the product of the mass and the velocity of the body, so it is a vector quantity. In the case of an isolated system the momentum is conserved.

In the attachment we see a diagram of the vehicle crash, let's write the moment for each axis.

y-axis

Initial instant. Before the shock.

          [tex]p_{oy}[/tex]  = M v₀₁

Final moment. After the crash

          [tex]p_{fy}[/tex] = (M + m) [tex]v_{fy}[/tex]

The system is formed by the two vehicles for which during the crash it is isolated and the momentum is conserved.

          [tex]p_{oy} = p_{fy} \\\\M v_{o1} = (M+m) v_{fy} \\v_{fy} = \frac{M}{M+m} \ v_{o1}[/tex]          

           

Calculate us

           [tex]v_{fy} = \frac{1200}{1200+750} \ 15[/tex]  

           vfx = 9.23 m / s

x-axis

Initial instant. Before the crash.

           p₀ₓ = m v₀₂

Final moment. After the crash.

           [tex]p_{fx}[/tex] = ​​(M + m) [tex]v_{fx}[/tex]  

The momentum is preserved.

          [tex]p_{ox}= p_{fx} \\m v_{o2) = (M+m) \ v_{fx}[/tex]  

Let's find the velocity just after the collision, let's use Newton's second law,

y-axis

        N-W = 0

        N = W = (M + m) g

x-axis

       fr = (M + m) a

The friction force is the macroscopic manifestation of the interactions between the two bodies.

       fr = μ N

We substitute.

       μ  g = a

     

Now we can use kinematics.

        v² = v₀² - 2a d

When the vehicles stop their speed is zero.

        v₀² = 2 a x

        v₀ = [tex]\sqrt{2\ \mu \ g \ d}[/tex]

Let's calculate.

       v₀ = [tex]\sqrt{2 \ 0.40 \ 9.8 25 }[/tex]  

       v₀ = 14 m / s

This is the speed of the two vehicles just after the collision, that is, let's use trigonometry to find their components.

          cos 25 = [tex]\frac{v_{ox}}{v_o}[/tex]  

          v₀ₓ = v₀ cos 25

          v₀ₓ = 14 cos 25

          v₀ₓ = 12.69 m / s

We substitute in the expression of the conservation of the momentum in the x-axis.

           m v₀₂ = (M + m) [tex]v_{fx}[/tex]  

           [tex]v_{o2} = \frac{M+m}{m} v_{fx}[/tex]  

           

Let's calculate.

           [tex]v_{o2} = \frac{1200+750}{750} \ 12.69[/tex]  

           vfy = 32.99 m / s = 40 m / s

In conclusion using the conservation of momentum, Newton's second law and kinematics we can find the result for the initial speed of the car is:

The speed of the car is 40 m/s at the East direction.

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Help me quickly! please!!!

A cable pulls a car up a mountain with a force of 4 × 103 N at a vertical constant velocity of 5 m.s-1. It takes 5 minutes to reach the top.

(a)How much work is done in getting the car to the top?
(b)How much work would have been done if the vertical speed was 2,5 m.s-1?
(c)Calculate the power exerted on the cable car in those 5 minutes.

Answers

Answer:

(a) 6,000,000J      

(b)  3,000,000J

(c)  For A 20,000W

But for B 10,000W

The work done in getting  the car to the top is equal to 6 ×10⁶ J. If the vertical speed is 2.5 m/s then, the work done will be  3 ×10⁶ J. The power exerted on the car is in 5 minutes is 20000 J/s.

What is work done ?

In physics, work done is the dot  product of force and displacement. Let w be the work done and F and ds be the force and displacement. Then

W = F.ds

It is given that the, the force of the cable is 4 × 10³ N. The velocity is 5 m/s and time is 5 minutes or 300 seconds. Now, the displacement is the product of time and velocity.

ds = velocity ×  time

    =  300 s ×  5 m/s

    = 1500 m.

Thus the work done = F × ds

                                  = 4 × 10³ N ×  1500 m

                                  = 6 ×10⁶ J .

If the velocity is reduced to half 2.5 m/s , then work done will be reduced to half as 3 ×10⁶ J.

Power is the rate of work done. Thus it is the ratio of work done to time. The power exerted on the car in 5 minutes = 6 ×10⁶ J /300s

                                                                        = 20000 J/s

Hence, the power exerted on the cable car in 5 minutes is 20000 J/s.

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What acceleration occurs if the friction force in #4 is now 4N?

Answers

The acceleration of the 20 N force is 6.67 m/s^2. The acceleration of the 4N force is 1.33 m/s^2.

What is force?

We define the force that acts on a body as that which is able to cause an acceleration or that which is able  to change the direction of an object. Recall that from the Newton first law, an object would continue in its state of rest or uniform motion unless the object is acted upon by an external force.

Now the frictional force is the force that tends to resist the motion of two surfaces that are in contact. Owing to the fact that it is a resistive force its direction is always opposite the force that seeks to move the object forward.

Now;

F = ma

a = F/m

a = 20 N/3Kg

a = 6.67 m/s^2

If the force is 4N;

a = F/m

a = 4N/3Kg

a = 1.33 m/s^2

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Missing parts;

How would you calculate the acceleration if you push with a 20 N horizontal force on a 3 kg block on a horizontal friction-free air table? What is the acceleration if the friction force is 4 N?

what third force must be added to the two forces 30 Newton at 30 degree and 80 Newton at 135 degree the resolution for equal to zero​

Answers

Answer:

Resolve the vectors:

F1 = 30 cos 30 i + 30 sin 30 j = 26 i + 15 j

F2 = 80 cos 135 i + 80 sin 135 j = -56.6 i + 56,6 j

F1 + F2 = (26 - 56.6) i + (15 + 56.6) j = -30.6 i + 71.6 j

The offsetting force would be

F3 = 30.6 i - 71.6 j

The magnitude of this vector is (30.6^2 + 71.6^2)^1/2 = 77.9

cos theta 3 = 30.6 / 77.9 = 66.9 deg

Check:

77.9 * sin 66.9 = 71.6  agreeing in magnitude with F3

Now we need the quadrant of the offsetting vector

sin theta 3 = -         cos theta 3 = +

This occurs in the fourth quadrant and theta 3 = 360 - 66.9 = 293.1 deg

what kind of frog species is this

Answers

Answer: i think its a bullfrog forgive me if im wrong i dont exactly know

Explanation:

Answer:

that is an African bullfrog

I'll give brainliest​

Answers

Good luck dude hahaha

Answer: figuratively speaking both the lines for the force Q and force P is equal.

i select true helllpppp me

Answers

This is true! The The Coriolis effect describes the pattern of deflection taken by objects not firmly connected to the ground as they travel long distances around Earth.

What is occurring in the umbra?

A. a total solar eclipse
B. a total lunar eclipse
C. a partial lunar eclipse
D. a partial solar eclipse

Answers

Answer:

A. a total solar eclipse

Explanation:

During a solar eclipse,the moon comes between the sun and Earth, casting its shadow over the Earth

A girl pushes her little brother on his sled with a force of 300 N for 750 m.
How much work is this? _______________
How much energy is used?__________
How much power does she use if it takes her 25s?_________
How much power does she use if she runs and complete the 750m in 10s?________

Answers

Answer:

W = F× d

= 300×750

= 225000

E = 225000

P = 300×750/25 = 9000

P = 300× 750/10 = 22500

A scientist fills a container with sea water. The container has dimensions 30 cm x 30 cm x 40 cm The density of sea water is 1020 kg/mº. Calculate the mass of the sea water in the container.​

Answers

Answer:

30600kg

Explanation:

density=m/v make v subject of the formula

Which of the following is NOT an indicator of a chemical reaction?

OPTIONS

A. A phase change



B. A temperature change



C. A color change



D. A gas being created

Answers

Answer:

c

Explanation:

The changing of color of a substance is not necessarily an indicator of a chemical change. For example, changing the color of a metal does not change its physical properties. However, in a chemical reaction, a color change is usually an indicator that a reaction is occurring.

A new tube is used each time a blood sample is tested.Explain why valid results are only obtained if each tube is identical

Answers

Valid results are only obtained if each tube is identical because; effective comparison of the tested blood each time can only be achieved if the testing model is constant in which case each tube is identical.

Discussion:

During scientific tests such as that described in the question; it is important to keep all parameters of testing constant.

This is so because, the utmost motive of the testing model is to draw comparison. It is on this note that valid results are only obtained if each tube is identical.

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What would be the acceleration of a block sliding down an inclined plane that makes an angle of 45° with the horizontal if the coefficient of sliding friction between two surfaces in 0.3? 141

Ans: 4.95 m/sec?​

Answers

Answer:

unfortunately we have not received a reply to the park yet but

Explanation:

mohamedz and he had killed him

PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!

Walter has a paper due on a novel that he has not read. He knows that his teacher will expect detailed references to the novel in his paper. He is thinking that he can listen to it while he is lifting weights and multi-task. What is the BEST response to Walter?
A.
He does not really need to concentrate on exercise, so it is fine.
B.
He would be better off focusing on his workout and then turning to the novel.
C.
If he is doing a type of exercise that allows him to stop and take notes, it is fine.
D.
Doing as many tasks as possible is generally a good idea and promotes efficiency.


PLEASE NO LINKS

Answers

Answer:

I'm no expert, but multitasking is a no bueno. Because multitasking reduces your efficiency and performance because your brain can only focus on one thing at a time. When you try to do two things at once, your brain lacks the capacity to perform both tasks successfully.

Therefore I would choose A, considering he could easily workout another time, whilst the test is a one time thing. He can't redo the test, but he can workout again. So my answer is A.

If he HAS to workout and study at the same time, then C would be appropriate.

I hope this helps!

I need help quickly pls

Answers

Answer:

Ok I'm not 100% on this one but, try 3 lifes sorry if u get it wrong D:

Explanation:

If 40 N force is exerted by a box covering 2 metre square area, calculate pressure.

Answers

Force=40NArea=2m^2

[tex]\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}[/tex]

[tex]\\ \sf\longmapsto Pressure=\dfrac{40}{2}[/tex]

[tex]\\ \sf\longmapsto Pressure=20Pa[/tex]

[tex] \sf \huge \red {\dag} Given[/tex]

[tex]\sf \longmapsto \: Force \: = 40 \: Newtons[/tex]

[tex]\sf \longmapsto \: Area \: = \: 2m \: Square \: ( {2m}^{2} )[/tex]

We know that the formula of Pressure is

[tex]\sf \longmapsto \: Force/Area[/tex]

Let's start.

Put the values

[tex]\sf \longmapsto \: \: P = 40 \: newtons(force)/2(Area)[/tex]

[tex]\sf \longmapsto Pressure \: 20 \: N/m^2[/tex]

[tex]\boxed{\sf\red{\boxed{ \sf Pressure ≈ \: 20 \: N/m^2}}}[/tex]

PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!


Imagine that a car is speeding down the highway and it hits a large bump in the road that forces it off the road. What would Newton call that object?
A.
a physical object
B.
a course interrupter
C.
an unbalanced force
D.
an unfortunate event


PLEASE NO LINKS OR I WILL REPORT YOU

Answers

Answer:

C. unbalanced force

Explanation:

it is called unbalanced force because it has changed direction of the moving object

Emma travels at a speed of 23 miles per hour for 3.5 hours. How far has she travelled?

Answers

You’d do 23 x 3.5 which equals 80.5 miles, she traveled 80.5miles

Answer: 80.5 miles

Explanation:

3.5 x 23 = 80.5

Define displacement in your own word

Answers

Answer:

Displacement is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.

Explanation:

With no friction, you can use the relationship between potential and kinetic energy to predict the speed of the car at the bottom of this hill from its starting height. To do this start by setting the kinetic and potential energy equations equal to one another

Answers

The speed of the car at the bottom of the hill is obtained as, [tex]v = \sqrt{2gh}[/tex]

According the principle of conservation of energy, the total potential energy of the car will be converted to maximum kinetic energy when the car is at the bottom of the hill.

[tex]K.E = P.E\\\\\frac{1}{2} mv^2 = mgh\\\\v^2 = 2gh\\\\v= \sqrt{2gh}[/tex]

where;

v is the speed of the car at the bottom of the hillh is the height of the hillg is acceleration due to gravity

Thus, the speed of the car at the bottom of the hill is obtained as, [tex]v = \sqrt{2gh}[/tex]

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sports photographers often use large aperture, long focal length lenses. what limitations do these lenses impose on the photographs?

Answers

Answer:

The depth of focus achievable with those lenses is small.

Explanation:

A larger aperture makes it much harder to focus on more than one object. When using a telephoto lens (the ones the question is referring to), the depth of focus is very small. For example, using a telephoto lens to take a photo of a runner might get the runner in focus, but certainly not the track, or the audience behind them. If you look at photos, especially older photos, of Olympians in almost any sport you can see this.

Hope this helps!

Describe the changes that occur inside a helium balloon as it rises from sea level

Answers

Answer:

The balloon expands in the number of particles per cubic centimeter decreases. This happens because as it expands there is a decrease in the density of area. The Dead Sea is a solution that is so dense that you easily float on it.

State the universal law of gravitation.
Answer in detail​

Answers

Answer:

Explanation:

Newton's law of universal gravitation is that every particle attracts every other particle in the universe with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

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