A 2.5 kg tribble is placed in a bucket and whirled in a 1.4 m radius vertical circle at a constant tangential speed. If the force on the tribble from the bucket does not exceed 10 times its weight (tribbles are a hardy species), the maximum tangential speed is

The comet will have the most gravitational potential energy at : ( B ) Point A

Given that the gravitational potential energy between two bodies is expressed as

Ux = - GMm / d ------ ( 1 )

where :

G = gravitational constant

M = mass of larger body ( sun )

m = mass of comet

d = distance between the bodies

Therefore the greater the distance ( d ) between the bodies the less negative the potential gravitational energy the smaller body will possess. from the image attached below, the point on the orbit that is farthest from the sun is Point A

Hence we can conclude that the comet will have the most gravitational potential energy at : ( B ) Point A

Learn more about gravitational potential energy : https://brainly.com/question/15849218

Answer: its letter c

Explanation:

Answer:

The time when the mass will reach its first maximum velocity  is 1.8 s.

Explanation:

Given;

mass of the pendulum, m = 3 kg

length of the pendulum, l = 0.8 m

height in which the pendulum is raised to, h = 0.2 m

the mass will reach its first maximum velocity when it returns to its initial position, i.e at the middle (x = 0).

the distance between the initial position of the pendulum and the height in which it is raised is the maximum displacement (A).

If we form a right angle triangle with respect to the height in which the pendulum is raised;

the height of the right triangle, H = L - 0.2 = 0.8 - 0.2 = 0.6 m

the hypotenuse side, = L = 0.8 m

the base of the triangle (opposite side) = A

A² = L² - H²

A² = (0.8)² - (0.6)²

A² = 0.28

A = √0.28

A = 0.529 m

The maximum velocity of the pendulum is calculated as;

[tex]V_{max} = A \omega\\\\V_{max} = A \sqrt{\frac{g}{l} } \\\\V_{max} = (0.529)\sqrt{\frac{9.8}{0.8} }\\\\V_{max} = 1.852 \ m/s[/tex]

The period is calculated as;

[tex]V_{max} = A\omega\\\\V_{max} = A (\frac{2\pi}{T} )\\\\T = \frac{2\pi A }{V_{max}}\\\\T = \frac{2\pi \ \times \ 0.529}{1.852} \\\\T = 1.8 \ s[/tex]

Therefore, the time when the mass will reach its first maximum velocity  is 1.8 s.

Answer:

13.2m

Explanation:

Step one:

given data

Energy= 5610J

Force F= 425N

Required

The distance traveled

Step two:

We know that work done is given as

WD= force* distance

so

5610=425*d

divide both sides by 425

d= 5610/425

d=13.2m

Answer:

Distance covered is: 45 meters

Displacement is 15 meters to the right of where he started

Explanation:

Notice that Brady has walk a path that looks like an incomplete rectangle of height 5 meters and length 25meters, although he actually didn't cover the full length (25 meters) when getting back to the point where he started (he made just 10 meters instead of 25 after the third turn right) See attached image.

Therefore, Brady's displacement is 15 meters to the right of where he started, and the total distance he covered is :

Distance = 5m + 25m + 5m + 10m = 45m

Answer:

Either B or D. The answer itself is 2.

Explanation:

The equation for the kinetic energy would be 1/2*mv^2.

When m is doubled, we can plug in 1 and 2 to compare our answers.

Plugging in 1 for mass would give us the answer 1/2*v^2.

Plugging in 2 for mass would give us v^2. This means that the velocity was multiplied by 2, meaning that the answer is it is multiplied by 2.

I am not sure which answer is correct since there seems to be two answer choices with 2 in it, but the answer is either B or D (I will call it ABCD because I do not want to cause confusion by saying 2 multiple times).

Answer:

the answer to your question is false.

Answer:

I don't get the question

Answer:

the length of the simple pendulum is 0.25 m.

Explanation:

Given;

mass of the air-track glider, m = 0.25 kg

spring constant, k = 9.75 N/m

let the length of the simple pendulum = L

let the frequency of the air-track glider which is equal to frequency of simple pendulum = F

The oscillation frequency of air-track glider is calculated as;

[tex]F = \frac{1}{2\pi } \sqrt{\frac{k}{m} } \\\\F = \frac{1}{2\pi } \sqrt{\frac{9.75}{0.25} } \\\\F = 0.994 \ Hz[/tex]

The frequency of the simple pendulum is given as;

[tex]F = \frac{1}{2\pi} \sqrt{\frac{g}{l} } \\\\2\pi(F) = \sqrt{\frac{g}{l} } \\\\2\pi (0.994) = \sqrt{\frac{9.8}{l} } \\\\6.2455 = \sqrt{\frac{9.8}{l} } \\\\(6.2455)2 = \frac{9.8}{l} \\\\39.006 = \frac{9.8}{l} \\\\l = \frac{9.8}{39.006} \\\\l = 0.25 \ m[/tex]

Thus, the length of the simple pendulum is 0.25 m.

Answer:

Gravity and Friction

Explanation:

How gravity and friction work which u probably know

Answer:

Force

Explanation:

Answer:

7.59Ns

Explanation:

Given parameters:

Force  = 1360N

Time of contact  = 5.85 x 10⁻³s

Unknown:

Impulse  = ?

Solution:

The impulse of the ball is given as:

        Impulse  = Force x time

       Impulse  = 1360 x 5.85 x 10⁻³ = 7.59Ns

Answer:

Ft=24,443.5 kgm/s

Explanation:

Step one

Given data

Mass of automobile m=1577kg

Initial Velocity u=17m/s

Final Velocity v=1.5m/s

Time t=0.18s

Step two

From the impulse and momentum equation

Ft=mΔv

Substitute

Ft=1577*(17-1.5)

Ft=1577*15.5

Ft=24,443.5 kgm/s

Answer:

Answer d) Lab B's reading is less precise than Lab A's

Explanation:

Recall that accuracy is a measure of how close to the actual physical quantity the experiment leads to. In this case, we don't know what the true age is,so we cannot tell which reading is more accurate.

But we can tell which reading is more precise given the value of their reported errors. Since Lab A shows a smaller error in years (+/- 20 years versus 30 years), as well as a smaller percent error (3.9% versus 5.1%), we can say that Lab's A reading is more precise than Lab B's reading.

This agrees with answer labeled d).

Answer:

[tex]W_b \approx 16336J[/tex]

Explanation:

From the question we are told that

Force of pull [tex]F= 92.5[/tex]

Weight of handle [tex]W_h=27.5 kg[/tex]

Angle of handle [tex]\angle =35.0[/tex]

Distance [tex]d=215.6 m[/tex]

Generally the work done by the boy can mathematically be represented as

[tex]W_b=F*dcos \theta[/tex]

[tex]W_b=92.5*27.5 *cos(35)[/tex]

Therefore

[tex]W_b=16336.34922J[/tex]

[tex]W_b \approx 16336J[/tex]

Answer:

Amplitude.

Explanation:

Radio waves can be defined as an electromagnetic wave that has its frequency ranging from 30 GHz to 300 GHz and its wavelength between 1mm and 3000m. Therefore, radio waves are a series of repetitive valleys and peaks that are typically characterized of having the longest wavelength in the electromagnetic spectrum.

Basically, as a result of radio waves having long wavelengths, they are mainly used in long-distance communications such as the carriage and transmission of data. Some examples of communication technologies that uses radio waves are radio set, mobile phones, television etc.

For a wave, an amplitude is defined as the maximum height of a crest, or depth of a trough, relative to the normal level

Answer:

Weight of honey required to fill bath tub  is 435kg

Honey is 1.45 times heavier than water

Explanation:

Rough volume of a bathtub is 300 litres

density of honey is 1.45 kg/L

Density of honey in bath tub is given by

[tex]\rho = \frac{mass}{volume}[/tex] where, mass is the weight of honey in bath tub and volume is volume of bath tub

on substituting the given values in above equation we get

1.45 = [tex]\frac{mass}{300}[/tex]

⇒1.45 x 300 = mass of honey in bath tub or weight of honey

⇒ weight of honey required to fill bath tub  is 435kg

density of water is 0.997 kg/L

therefore for the same amount of volume the ratio of weight of honey to water is equal to ratio of density of honey to water

∴ [tex]\frac{W_h}{W_w} = \frac{\rho_h}{\rho_w}[/tex]

on substituting the value of densities we get

[tex]\frac{W_h}{W_w} = \frac{1.45}{1}[/tex]

⇒ honey is 1.45 times heavier than water

Answer:

true true true true true

Answer:

A tropical year, also known as a solar year, an astronomical year, or an equinoctial year, is, on average, approximately 365 days, 5 hours, 48 minutes and 45 seconds long.

Explanation:

Answer:

eating an apple

Explanation:

Eating food gives your body the nutrients and energy it needs.

Answer:

He would be in space.

Explanation:

Answer: What would happen if a human traveled to Uranus?

As an ice giant, Uranus doesn't have a true surface. The planet is mostly swirling fluids. While a spacecraft would have nowhere to land on Uranus, it wouldn't be able to fly through its atmosphere unscathed either. The extreme pressures and temperatures would destroy a metal spacecraft.

Explanation:

Answer:

D

Explanation:

transparent_objects that allows light to pass through and can you see through them

Given :

A SONAR used in a ship sends ultrasound waves and receives the echo after 2.0 s.

To Find :

The depth of the shoal of fish if the speed of sound in water is 1250 m/s.

Solution :

Let, the depth of the shoal fish is d.

Now, it is given that it takes 2.0 s to receive the echo.

Also, distance covered by echo is 2d.

Now, 2d = s × t

2d =  1250 m/s × 2 s

d = 1250 m

Therefore, the depth of the shoal of fish is 1250 m.

Answer:

a = 8 m/s^2, Ffriction = 10 N, μk = 0.205

Explanation:

a. Force = Mass*Acceleration,

(since you didn't add the units..."5 block"....for the mass, I will assume it to be in kg, per SI units)

40 N = 5 kg*acceleration,

a = 40/5 = 8 m/s^2

b. As you know newtons second law (F=m*a) is actually in the form Fnet = m*a. Which means that if the friction force comes into play, it would be Fapplied - Ffriction = m*a.

Fapplied - Ffriction = m*a,

40 - Ffriction = 5*6,

40 - Ffriction = 30,

Ffriction = 40 - 30 = 10 N

c. The coefficient of kinetic friction is calculated by the formula "Ffriction = μk*Fnormal".

10 = μk*Fnormal (Fnormal = m*g = 5*9.8)

10 = μk*49,

μk=10/49 ≈ 0.205

Answer: 0.85amps

Explanation: Power = 102watts; Voltage = 120voltsP = IxV ; I = P divided by V = 102 divided by 120 = 0.85amps

The object takes 0.5 seconds to complete one rotation, so its rotational speed is 1/0.5 rot/s = 2 rot/s.

Convert this to linear speed; for each rotation, the object travels a distance equal to the circumference of its path, or 2π (1.2 m) = 2.4π m ≈ 7.5 m, so that

2 rot/s = (2 rot/s) • (2.4π m/rot) = 4.8π m/s ≈ 15 m/s

thus giving it a centripetal acceleration of

a = (4.8π m/s)² / (1.2 m) ≈ 190 m/s².

Then the tension in the rope is

T = (50 kg) a ≈ 9500 N.

Answer:

Sedentary lifestyle is the lifestyle by which most physical activity is abandoned, performing activities that do not require energy consumption or large muscle movements on a large scale, such as using a computer, driving a car or playing video games.

Today, most young people have gradually turned towards sedentary lifestyles, mainly motivated by the increase in technological availability, and the extensive dependence generated on technology both to communicate with their peers (cell phones, social networks, etc. .) and for leisure time (video games, etc.).

Some ways to promote physical activity in young people and prevent sedentary lifestyle can be to create sports groups, where young people can establish social relationships without depending on networks or technological devices, or establish tasks of physical activity during study or work hours.

Answer:

it is A or D

Explanation:

Answer:

ANswer:A

Explanation:

Answer:

the answer is c

Explanation: