A 20-turn coil of area 0.32 m2 is placed in a uniform magnetic field of 0.055 T so that the perpendicular to the plane of the coil makes an angle of 30∘ with respect to the magnetic field.

The flux through the coil is

Answer:

b gases

Explanation:

this is because gases spread out through out the entire container because they have no definite shape and are always moving.

Answer:

a) The final pressure is 1.68 atm.

b) The work done by the gas is 305.3 J.

Explanation:

a) The final pressure of an isothermal expansion is given by:

[tex] T = \frac{PV}{nR} [/tex]

[tex] T_{i} = T_{f} [/tex]

[tex] \frac{P_{i}V_{i}}{nR} = \frac{P_{f}V_{f}}{nR} [/tex]

Where:

[tex]P_{i}[/tex]: is the initial pressure = 5.79 atm

[tex]P_{f}[/tex]: is the final pressure =?

[tex]V_{i}[/tex]: is the initial volume = 420 cm³

[tex]V_{f}[/tex]: is the final volume = 1450 cm³

n: is the number of moles of the gas

R: is the gas constant

[tex] P_{f} = \frac{P_{i}V_{i}}{V_{f}} = \frac{5.79 atm*420 cm^{3}}{1450 cm^{3}} = 1.68 atm [/tex]

Hence, the final pressure is 1.68 atm.

b) The work done by the isothermal expansion is:

[tex] W = P_{i}V_{i}ln(\frac{V_{f}}{V_{i}}) = 5.79 atm*\frac{101325 Pa}{1 atm}*420 cm^{3}*\frac{1 m^{3}}{(100 cm)^{3}}ln(\frac{1450 cm^{3}}{420 cm^{3}}) = 305.3 J [/tex]

Therefore, the work done by the gas is 305.3 J.

I hope it helps you!        

Option 3.) Increasing the voltage across the wire.

I know that the other answers are incorrect because, for one thing, the more resistance in a substance, the less flow of the current there is. Also, using a longer wire doesn't change anything, it just makes a electrical current go on longer. Lastly decreasing the voltage would make the current decrease in the atoms that flow through it to power an object.

-R3TR0 Z3R0

Answer:

Explanation:

individual and then net

hope that helps I could be wrong about this one though

Answer:

The net force on the hovercraft is 11200 N.

Explanation:

Given;

force exerted on the hovercraft by wind, F₁ = 5000 N north

force exerted on the hovercraft by the propeller, F₂ = 10,000 N west

The net force on the hovercraft is calculated as;

[tex]F_{net} = \sqrt{F_1^2 + F_2^2} \\\\F_{net} = \sqrt{5000^2 + 10,000^2} \\\\F_{net} = 11180.34 \ N\\\\F_{net} = 11200 \ N \ (3.s.f)[/tex]

Therefore, the net force on the hovercraft is 11200 N.

Answer: [tex]r = \sqrt{\frac{p}{4pil}}[/tex]

Explanation:

[tex]l = \frac{p}{4pir^2} \\4pir^2l=p\\r^2 = \frac{p}{4pil} \\r = \sqrt{\frac{p}{4pil}}[/tex]

Answer:

Option D. is correct.

Explanation:

The object's mechanical energy refers to the sum of the potential and kinetic energies of the object. When an object falls, its potential energy (PE) decreases, and its kinetic energy (KE) increases. The increase in kinetic energy is exactly equal to the decrease in potential energy.

Option D. is correct.

Answer:

Participant 1 wins

Explanation:

Coefficient of static, μ = F/N, where F is the frictional force and N is the normal force.

The force exerted by each participant is the sum of the frictional force acting on each of them and the maximum force with which each participant pulls on the rope.

Frictional force, F =  μ * N

Normal force, N = mass * acceleration due to gravity, g

For Participant 1; μ = 2.0, mass = 60 kg, g = 9.8 m/s²

Frictional force = 2.0 * 60 * 9.8 = 1176 N

Total force = (1176 + 1000) = 2176 N

For Participant 2; μ = 1.2, mass = 80 kg, g = 9.8 m/s²

Frictional force = 1.2 * 80 * 9.8 = 940.8N

Total force = (940.8 + 1200) N = 2140.8 N

From the values obtained above, Participant 1 exerts more force than Participant 2, therefore, Participant 1 wins

Answer:

3. Fructose

Explanation:

Fructose is a sugar found naturally in fruits, fruit juices, some vegetables and honey.

it is number 3 (Fructose)

Answer:

k = 7.84 N/m

Explanation:

We are given;

Mass hanging object; m = 0.2 kg

Extension; Δx = 0.25 m

Now, formula for the force is;

F = k•Δx

Where k is the spring constant

Since we have mass, then F = W = mg = 0.2 × 9.8 = 1.96 N

Thus;

1.96 = k × 0.25

k = 1.96/0.25

k = 7.84 N/m

Answer:

Its the sum of the potential energy and the kinetic energy

Answer:

20 m/s. have a great day

Answer:

since v decreased by 20m/s in 5 sec, a = -4 m/s^2

assuming the 3 seconds started at t=0,

s = 30t - 2t^2

s(3) = 30(3) - 2(9) = 72m

Answer:

chinawares are wrapped by paper while packaging to reduce the chances of the wares breaking when falling

Answer:

The calculation that you then need to do is 25000 x 0.0136 = 340. You must not forget the units of speed, which here are metres per second, or m/s. Your final answer is 340 m/s.

Answer:

The added mass will mean a longer period of oscillation.

Explanation:

The period of oscillation here is given by the formula;

T = 2π√(m/k)

Where m is mass and k is spring constant

From the equation of oscillation period above, it's obvious that when we increase the mass, the oscillation period will also increase.

Thus, the added mass will mean a longer period of oscillation.

Answer:

suppose buying pizza for a work party leads to positive morale and to the work being done in half the time. Pizza is the independent variable, Work speed is the dependent variable, The mediator, the middle man without which there would be no connection, is positive morale. Denaturation, in biology, the process of modifying the molecular structure of a protein. Denaturation involves the breaking of many of the weak linkages, or bonds (e.g., hydrogen bonds), within a protein molecule that is responsible for the highly ordered structure of the protein in its natural (native) state.

Explanation:

hope this helps have a good rest of your day :) ❤

Explanation:

HW1. For example, suppose buying pizza for a work party leads to positive morale and to the work being done in half the time. Pizza is the independent variable, Work speed is the dependent variable, The mediator, the middle man without which there would be no connection, is positive morale.

HW2. The word denature means to render food unpleasant or dangerous to consume, it is denatured by adding a substance known as a denaturant. Aversive agents—primarily bitterants and pungent agents—are used to produce an unpleasant flavor.

Hope It Helps U

Please Mark As Brainl

Answer:

A, C, D and E are the true statement about current flowing.

Answer:

0.16

Explanation:

Given data

Force F= 80N

Mass m= 50kg

Reaction R= Weight= mg= 50*9.81= 490.5N

We know that

F=UR

Substitute and solve of U

U=F/R

U= 80/490.5

U=0.16

Hence the coefficient of friction is 0.16

Answer:

Explanation:

a ) from San Antonio to Houston let distance be d km .

Average speed = total distance / total time

time = distance / speed

Total time = (d / 2 x 75 ) +( d / 2 x 106 )

= .0067 d + .0047 d

= .0114 d

Average speed  = d / .0114 d = 87.72 km /h

b ) from Houston back to San Antonio

Total time = (d / 2 x 106 ) +( d / 2 x 75 )

= .0047 d + .0067 d

= .0114 d

Average speed  = d / .0114 d = 87.72 km /h

c )

For entire trip :

total distance = 2d

total time = 2 x .0114 d

Average speed  = 2 d / 2 x .0114 d

= 87.72 km /h .

The initial speed of the bullet = v₁= 511.07 m/s

Given

17.4 g bullet

5506 g wooden

The velocity of the block+bullet :1.61 m/s

Required

The initial speed

Solution

Momentum

m₁v₁+m₂v₂=m₁v₁'+m₂v₂'

v₂=0 ⇒block at rest

v₁'=v₂'=1.61 m/s

the equation becomes :

m₁v₁=(m₁+m₂)v'

17.4v₁=(17.4+5506)1.61

v₁= 511.07 m/s

Answer:

you would be better off if the car bounced backwards

Explanation:

because if the hood was dismembered than you have a high chance of very bad injury but if it is just bounced back you would have less chance of getting hurt if properly sitting and seat belted.

s=600 m

t=12 s

s=0.5*a*t² (initial speed V0=0)

a=(2*s)/t²

a=(2*600)/12²

a≈8.33 m/s²

L= s(t2=12s)-s(t1=11s) -> (distance during the twelfth second)

L=0.5*a*(t2²-t1²)

L=0.5*((2*s)/t²)*(t2²-t1²)

L=0.5*((2*600)/12²)*(12²-11²)

L ≈ 95.83 m

Answer and Explanation:

(a) The fre-body diagrams for each block is shown below. In the block of mass 3.60 kg, there are 3 forces acting on it: horizontal force due to the rope ([tex]F_{t}[/tex]), vertical gravitational force ([tex]F_{g}[/tex]) and vertical normal force ([tex]F_{n}[/tex]), due to the surface. Since there is no vertical movement, [tex]F_{g}[/tex] and [tex]F_{n}[/tex] cancels it out. So, for this block, net force is horizontal due to the rope [tex]F_{t}[/tex].

The block of mass m is hanging from the pulley, so there is the force of the rope ([tex]F_{t}[/tex]) and the gravitational force ([tex]F_{g}[/tex]). Both are vertical, because there is no surface "holding" block m.

(b) Since both blocks are attached to each other, the acceleration will be the same. To calculate it, we use the Second Law of Motion:

[tex]F_{r}=m.a[/tex]

[tex]a=\frac{F_{r}}{m}[/tex]

[tex]a=\frac{18.8}{3.6}[/tex]

a = 5.22

The acceleration of either block is 5.22 m/s².

(c) Block m has 2 forces acting on it: tension and gravitational force. Gravitational force is the force of attraction the Earth does over an object. It is calculated as the product of mass and gravitational acceleration, which has magnitude g = 9.8 m/s².

Suppose positive referential is going up. To determine mass:

[tex]F_{r}=m.a[/tex]

[tex]F_{t}-F_{g}=m.a[/tex]

[tex]F_{t}-m.g=m.a[/tex]

[tex]18.8-9.8m=5.22m[/tex]

[tex]15.02m=18.8[/tex]

m = 1.25

Block m has 1.25 kg.

(d) Gravitational force is also called weight. So, as described above: [tex]F_{g}=m.g[/tex].

The weight for the hanging block is

[tex]F_{g}=1.25*9.8[/tex]

[tex]F_{g}=[/tex] 12.25 N

Comparing tension and weight:

[tex]\frac{12.25}{18.8}[/tex] ≈ 0.65

We can see that, weight of the hanging block is almost 0.65 times smaller than the tension on the rope.

Answer:

If A + B = C for the vector equation then substituting for B gives

A + (-A) = C = 0

The only thing that can be said about "C" is that it has zero magnitude.

Explanation:

1.

We use the equation

h = [tex]\frac{gt^2}{2}[/tex], where

h is the height traveled,

g is the acceleration due to gravity and

t is the time taken to reach height h.

We can now calculate t to be

[tex]\sqrt{\frac{2*1.2 m}{9.81 m/s^2} }[/tex]

= 0.495 s

Let v be the initial velocity of the player.

The player deaccelarates from v m/s to 0 m/s in 0.495 s at the rate of 9.81 m/s^2.

v = 9.81 m/s^2 x 0.495 s = 4.85 m/s

2.

The player takes 0.3 s to increase his velocity from 0 m/s to 4.85 m/s. So his average accelaration is

4.85 m/s / 0.3 s = 16.2 m/s^2

Answer:

Endothermic, because energy is absorbed (A)

Explanation:

The reaction that take place in the instant cold pack causes the surroundings around it, including the bag that contains it. When the bag loses heat to the cold pack, the cold pack absorbs the heat, thereby causing the environment (the bag) to be cold.

Answer:

See calculation below

Explanation:

Average speed = Distance/Time

a) Given

Distance = 17.9km

Time = 26.6minutes

Time = 26.6/60 hr

Time = 0.443hr

Average speed  = 17.9/0.443

Average speed = 40.38km/hr

b) If she returned home by the same path 7 h 30 min after she left, the distance will be the same;

Distance = 17.9km

Time = 7.5hr

Average speed = 17.9/7.5

Average speed = 2.387km/hr

Velocity of the entire trip = 40.38km/hr + 2.387km/hr

Velocity of the entire trip = 42.77km/hr

Hence the velocity of the entire trip is 42.77km/hr

Answer:

the speed of the electron from charge q1 is 7.17×10⁶ m/s

Explanation:

Given the data in the question;

the potential at the center of the two charges will be;

V = k( q1/(d/2) + q2/(d/2)

so we substitute

V = (9×10⁹)( (3.95×10⁻⁹/(0.39/2) + 1.80×10⁻⁹/(0.39/2)

V = 265.4 V

the potential at a distance of 10 cm from the charges will be

V = k( q1/(d1) + q2/(d2)

(d1 = 10cm = 0.1m and d2 = 39cm - 10cm = 29cm = 0.29m )

V' = (9×10⁹)( (3.95×10⁻⁹/0.1 + 1.80×10⁻⁹/0.29

V' = 411.4 V

Now, from the conservation of energy the speed of the electron from charge q1 will be;

E = ( V' - V) qe

1/2mv² = ( V' - V) qe

v² = [( V' - V) qe] / 1/2m

v =√ ([( V' - V) qe] / 1/2m)

v =√ ([2( V' - V) qe] / m)

we substitute

v =√ (2[( 411.4  - 265.4) 1.6×10⁻¹⁹] / 9.1×10³¹)

v = 7.17×10⁶ m/s

Therefore, the speed of the electron from charge q1 is 7.17×10⁶ m/s

The spring constant : k = 40 N/m

Given

Force = 20 N

The displacement of the spring=x=0.5 m

Required

The spring constant = k

Solution

Hooke's Law

F = k.x

k = F/x

Input the value :

k = 20/0.5

k = 40 N/m