A 20 mL sample of human urine was found to have 10 mg of
urea during analysis. The molar mass of urea is 60.1 g/mol.
Calculate the molarity of urea in the given sample.

Answers

Answer 1
0.008
Molarity=
Mw
2

×V
sol

(in mL)
W
2

×1000

⟹W
2

=5 mg =5×10
−3
g
∴M=
60×10
5×10
−3
×10
3


=0.008

Related Questions

If anyone could help I’d appreciate it

Answers

Answer: 2.00 mol

Explanation:

The balanced chemical equation is:

[tex]2H_2(g)+O_2(g)\rightarrow 2H_2O(g)[/tex]  

According to stoichiometry :

2.00 moles of [tex]H_2[/tex] require = 1.00 moles of [tex]O_2[/tex]

Thus 2.00 moles of [tex]H_2[/tex] will require=[tex]\frac{1}{2}\times 2.00=1.00moles[/tex]  of [tex]O_2[/tex]

Thus both will act as limiting reagents and will be fully consumed.

2.00 moles of [tex]H_2[/tex] will form = 2 moles of [tex]H_2O[/tex]

Thus 2.00 moles of [tex]H_2[/tex] will form = [tex]\frac{2}{2}\times 2.00=2.00moles[/tex]  of [tex]H_2O[/tex]

  Thus 2.00 moles of [tex]H_2O[/tex] will be produced from the given masses of both reactants.

How many grams are in 1.2 x 1024 atoms of sodium?

Answers

Answer:

46 g

Explanation:

First we convert 1.2 x 10²⁴ atoms of sodium into moles, using Avogadro's number:

1.2x10²⁴ atoms ÷ 6.023x10²³ atoms/mol = 2.0 mol

Then we convert 2.0 moles of sodium into grams, using sodium's molar mass:

2.0 mol Na * 23 g/mol = 46 g

Thus, there are 46 grams in 1.2x10²⁴ atoms of sodium.

write a balanced equation between oxalic acid and potassium hydroxide ​

Answers

2 KOH(aq) + H2C2O4(s) → K2C2O4(aq) + 2 H2O(l) When a sample of oxalic acid (H2C2O4), which is a diprotic acid (both H-atoms are acidic), is titrated with 0.250 M potassium hydroxide solution, 24.66 mL of the potassium hydroxide solution are required to neutralize the acid. I don’t know is this gonna help but ok ._.

how many atoms are in 0.5 mole of aluminum

Answers

Answer is:
0.5•(6.022 • 10^23)=3.011 • 10^23
Explanation in photo below

According to the Avogadro's number, there are 3.011×10²³ atoms in 0.5 mole of aluminium.

What is Avogadro's number?

Avogadro's number is defined as a proportionality factor which relates number of constituent particles with the amount of substance which is present in the sample.

It has a SI unit of reciprocal mole whose numeric value is expressed in reciprocal mole which is a dimensionless number and is called as Avogadro's constant.It relates the volume of a substance with it's average volume occupied by one of it's particles .

According to the definitions, Avogadro's number depend on determined value of mass of one atom of those elements.It bridges the gap between macroscopic and microscopic world by relating amount of substance with number of particles.

Number of atoms can be calculated using Avogadro's number as follows: mass/molar mass×Avogadro's number, on substituting values in formula, 0.5×6.023×10²³=3.011×10²³ atoms.

Thus, there are 3.011×10²³ atoms in 0.5 mole of aluminium.

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Write a structural formula for each of the following: (a) 3-Methylcyclobutene (b) 1-Methylcyclopentene (c) 2,3-Dimethyl-2-pentene (d) (Z)-3-Hexene (e) (E)-2-Pentene (f) 3,3,3-Tribromopropene (g) (Z,4R)-4-Methyl-2-hexene (h) (E,4S )-4-Chloro-2-pentene (i) (Z)-1-Cyclopropyl-1-pentene (j) 5-Cyclobutyl-1-pentene (k) (R)-4-Chloro-2-pentyne (l) (E)-4-Methylhex-4-en-1-yne

Answers

Answer:

Attached below

Explanation:

(a) 3-Methylcyclobutene

(b) 1-Methylcyclopentene

(c) 2,3-Dimethyl-2-pentene

(d) (Z)-3-Hexene  

(e) (E)-2-Pentene

(f) 3,3,3-Tribromopropene

(g) (Z,4R)-4-Methyl-2-hexene

(h) (E,4S )-4-Chloro-2-pentene

(i) (Z)-1-Cyclopropyl-1-pentene

(j) 5-Cyclobutyl-1-pentene

(k) (R)-4-Chloro-2-pentyne

(l) (E)-4-Methylhex-4-en-1-yne

The structural formula of a compound ( chemical ) is the representation of the molecular structure of the compounds ( i.e. it shows how the atoms in the compound is arranged, also the chemical bonding within the molecules are represented as well.

10) 81 grams of Au is how many mL ?

Answers

Answer: Thus 81 grams of Au is 9210 ml

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.

To calculate the moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]

[tex]\text{moles of Au}=\frac{81g}{196.96g/mol}=0.411moles[/tex]

1 mole of Au occupies = 22.4 L

Thus 0.411 moles of Au occupy = [tex]\frac{22.4}{1}\times 0.411=9.21L=9210ml[/tex]

81 grams of Au is 9210 ml

Look at the H-R diagram. Which area of the diagram represents the white dwarfs? Give answer like top, right corner.

Answers

Answer:

I did this TGA got it right it is bottom left corner

Explanation:

What are ALL full chemical reactions that ensue for each of the following disinfectants (may be more than one for each): (5 points) Cl2 (g) at pH 9

Answers

Answer:

The reactions that might ensue are

Cl[tex]_{2}[/tex](g) + H[tex]_{2}[/tex]O ----------  > HOCl + HCl

 HOCl -------- > [tex]H^+[/tex](aq) + O[tex]CI^-[/tex](aq)

Cl2(g) + [tex]OH^-[/tex](aq) ----- > O[tex]CI^-[/tex](aq) + HCl

Explanation:

The Disinfectant Given is

CI2 (g) at PH 9

Determine the chemical reactions that might ensue

due to the High concentration of [tex]H^{+} (aq)[/tex] the formation of [tex]OCI^-[/tex](aq) will be better and this will decrease the power of the disinfectant.

Hence the chemical reactions that might ensue can be represented below as :

Cl[tex]_{2}[/tex](g) + H[tex]_{2}[/tex]O ----------  > HOCl + HCl

            HOCl -------- > [tex]H^+[/tex](aq) + O[tex]CI^-[/tex](aq)

Cl2(g) + [tex]OH^-[/tex](aq) ----- > O[tex]CI^-[/tex](aq) + HCl

What is 2AI(s) + FeO3(s) = Ai2O3(s) + 2Fe(s)

Answers

Answer:

it's a double displacement Reaction.

How can y’all do this

When sodium hydroxide NaOH dissociates in water, the oxygen atoms on the hydroxide anions will interact with:

Answers

Answer:

Hydroxide ions ( OH−) are negatively charged, and the formal negative charge is on the oxygen atom. Since opposite charges attract, the oxygen atoms will interact with the positive end of water's dipole.

Explanation:

Why does an asteroid get hotter when it goes close to the sun?

Answers

It gets hotter because if the heat waves from the sun we all know the sun is really hot obviously so the heat wave make it hot

I don’t understand please help

Answers

It’s C)H2SO4
Good luck
I agree the answer is C according to my research about it

what is another name for horse

Answers

Answer:

Mount, Charger, Colt, Pony, and Folt

Explanation:

Answer:

A stallion or a mare

Explanation:

is sublimation exothermic or endothermic

Answers

Answer:

endormic

Explanation:

It occurs at a temperature and pressures below a substance's triple point on its phase diagram, which corresponds to the lowest pressure at which the substance can exist as a liquid

Help bestie pls help ASAP thank you

Answers

Explanation:

heyyyyyyyyy how are you sure

GROUP NUMBER
ELEMENT
Potassium
Fluorine
Silicon
Radon
Gold
Beryllium
Oxygen
Neon
Rubidium
Tungsten
Arsenic
Calcium
Sodium
Aluminum
Chromium
Iodine
Helium
Nitrogen
Iron
Zinc

Answers

Answer:

Jet ğıpep2pep2p2pp3oroe88r82

Calculate the molarity of a solution that contains 3.00x10-2 mol NH4Cl in exactly 450 cm3 of solution.

Answers

Answer:

0.06moles/litres

Explanation:

molarity = no of moles / volume in litres = 3.00*10^-2/(450/1000)=0.06 moles/litres

Answer:

0.07mol/dm^3

Explanation:

Please mark as brainliest

Calculate the pH of a 4.988 M solution of ascorbic acid, which has a ka of 8.0 x 10-5.
Report your answer with two decimal places. Example: 6.99

Answers

Answer:

pH= 1.70

Explanation:

I      4.988        0     0

C     -x             +x     +x

E     4.988 -x    x       x

8.0 x 10^-5 = X^2/ 4.988 - x

(since the X value is so small, round 4.988-x to 4.988 because X is close to zero)

8.0 x 10^-5 = x^2/4.988

x4.988           x4.988

4.0 x 10^-4 = x^2

x = .0199

pH=-log[.0199] = 1.70

How many fluorine atoms are there in 39.4 moles of CF4?

Answers

Answer:

here

Explanation:

Answer: 4

A molecule of carbon tetrafluoride, CF4 , is made up of 1 carbon atom bonded to 4 fluorine atoms. Each carbon atom weighs 12.0 amu and each fluorine atom weighs 19.0 amu so 1 CF4 molecule weighs 1×12.0 amu + 4×19.0 amu = 88.0 amu. This number, 88.0, is called the molecular weight (or molecular mass) of CF4.

Calculate the pH of a solution with [H+] =1x10^-5

Answers

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Answer: 5

Explanation:

I hope this helped!

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- Zack Slocum

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Is the Swedish timber industry more likely a result of good resource availability or a lack of trees elsewhere on Earth?

Answers

Answer:

The forest products industry plays a major role in the Swedish economy, and accounts for between nine and 12 percent of Swedish industry's total employment, exports, sales and added value. It includes companies within the pulp and paper industry, as well as the wood-mechanical industry.

Select the description of a galvanic (voltaic) cell. An electrochemical cell that uses electricity to produce an oxidation-reduction reaction. An electrochemical cell that produces electricity from a spontaneous oxidation-reduction reaction. One-half of an electrochemical cell in which either oxidation or reduction occurs. Connects the two half-cells in an electrochemical cell to maintain electrical neutrality.

Answers

Answer:  An electrochemical cell that produces electricity from a spontaneous oxidation-reduction reaction

Explanation:

Galvanic cell is a device which is used for the conversion of the chemical energy produced in a redox reaction into the electrical energy.

Galvanic cell consists of two half cells known as anode and cathode. Oxidation takes place at anode and reduction takes place at cathode. The two half cells are connected by a salt bridge which contains an electrolyte which maintains the electrical neutrality.

2.0M Propionic Acid HC3H5O2 Dissolves In Distilled Water. If It Has A Ka Of 1.3*10-5, What Is The Final PH?

The base ethylamine C2H5NH2 has a Kb of 5.6*10-4. What will the pH be in .53 molar solution?

Answers

Answer: first you have to calculate the amount ionized. We will say it is x mol / L

then % ionization = (amount ionized / initial concentration) * 100%

x can be calculated using an ice chart

HC3H5O2           -----> H+    + C3H5O2-

Initial HC3H5O2 = 0.250  

change              = -x

equilibrium         = 0.250 - x

initial H+            = 0

change              = +x

equilibrium         = x

C3H5O2- initial   = 0

change              = +x

equilibrium         = x

Ka         = [H=][C3H5O2-] / HC3H5O2]

 1.3 * 10 ^ -5    = [x][x] / (0.250 - x)  

So 1.3 * 10 ^ -5 * (0.250 - x)   = x ^ 2  

     3.25 * 10^ -6 - (1.3 * 10^-5)x = x^2   now this is a quadratic equation and you have to rearrange it and solve for x

x^2 + 1.3 * 10^-5)x - 3.25 * 10^ -6 = 0

use the equation x = {-b (+ or -)[b^2 - 4.a.c] ^ 1/2} / 2a

you should get x = 1.80 * 10 ^ -3 or x = -1.80* 10^-3

but x can not be negative..

so x = 1.80 * 10 ^ -3

so percent ionization = (1.80 * 10 ^ -3 / 0.250) * 100%

                               =0.72 %

the other way which is more easier is  

assuming that x is very small and therefore 0.250 - x is approximately equals to 0.250  

then 1.3 * 10^-5 = x^2 / 0.250

so x^2    = 1.3 * 10^-5 * 0.250

        x   = 1.80 * 10 ^-3

then percent ionization is = (1.80 * 10 ^ -3 / 0.250) * 100%

                               =0.72 %

if the percent ionization is > 5 % you can not do that approximation. in such a case you have to solve the quadratic equation. that is why I showed both methods.

now you can do the parts b and c

b answer : percent ionization = 1.27 %  

c answer : 2.54%

good luck

If 0.000066 moles of 0.01 M solution of carbonic acid dissociates, then what is Ka of carbonic acid

Answers

Answer: 4.4 x 10^-7

Explanation:

0.000066 x 0.0000066 / 0.01

= 4.4 x 10^-7

Boyle's Law states that when a sample of gas is compressed at a constant temperature, the pressure P and volume V satisfy the equation PV = C, where C is a constant. Suppose that at a certain instant the volume is 300 cm3, the pressure is 180 kPa, and the pressure is increasing at a rate of 30 kPa/min. At what rate is the volume decreasing at this instant?

Answers

Answer:

The gas is decreasing at a rate of 50 cubic centimeters per minute.

Explanation:

The Boyle's Law is represented by the following expression:

[tex]P\cdot V = k[/tex] (1)

Where:

[tex]P[/tex] - Pressure, in kilopascals.

[tex]V[/tex] - Volume, in cubic centimeters.

[tex]k[/tex] - Proportionality constant, in kilopascal-cubic centimeters.

By definitions of rate of change and implicit differentiation, we derive the following differential equation:

[tex]\dot P \cdot V + P\cdot \dot V = 0[/tex] (2)

Where:

[tex]\dot P[/tex] - Rate of change of the pressure, in kilopascals per minute.

[tex]\dot V[/tex] - Rate of change of the volume, in cubic centimeters per minute.

Then, we clear the rate of change of the volume within (2):

[tex]P\cdot \dot V = -\dot P\cdot V[/tex]

[tex]\dot V = -\left(\frac{\dot P}{P} \right) \cdot V[/tex]

If we know that [tex]P = 180\,kPa[/tex], [tex]\dot P = 30\,\frac{kPa}{min}[/tex] and [tex]V = 300\,cm^{3}[/tex], then the rate of change of the volume is:

[tex]\dot V = -\left(\frac{\dot P}{P} \right) \cdot V[/tex]

[tex]\dot V = -50\,\frac{cm^{3}}{min}[/tex]

The gas is decreasing at a rate of 50 cubic centimeters per minute.

If 220 mL of a 12.0 M HCl solution is diluted to 1000 mL, what will be the concentration of the new solution?

Answers

Answer:

2.64 M

Explanation:

Use the dilution equation M1V1 = M2V2, where:

M1 = 12.0 M HCl

V1 = 220 mL HCl

M2 = ?

V2 = 1000 mL HCl

(12.0 M HCl)(220 mL HCl) = M2(1000 mL HCl)

M2 = 2.64 M HCl

Pictures of every moon

Answers

Answer:

Where?

Explanation:

During a running (dynamic) compression test at idle, a good engine should produce PSI. A. 150 to 200 B. 100 to 150 C. 30 to 60 D. 60 to 90​

Answers

Answer:

b

Explanation:

During a running (dynamic) compression test at idle, a good engine should produce PSI between 60 to 90​. The correct answer is option D.

A running compression test is a diagnostic test that measures the compression pressure of an engine while it is running.

The test is performed by connecting a compression gauge to the spark plug hole of each cylinder and then cranking the engine over to measure the compression pressure. The compression pressure of an engine is an important indicator of its overall health and performance. A low compression pressure can indicate a number of issues, such as worn piston rings, damaged valves, or a blown head gasket. On the other hand, a high compression pressure can indicate that the engine is in good condition and has strong compression.

Therefore, in general, a good engine should produce compression pressure between 60 to 90​ PSI during a running compression test at idle. Option D is the correct answer.

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Ethanol (C2H5OH) is produced from the fermentation of sucrose in the presence of enzymes.
C12H22O11(aq) + H2O(g) 4 C2H5OH(l) + 4 CO2(g)
Determine the theoretical yield and the percent yields of ethanol if 665 g sucrose undergoes fermentation and 305.0 g ethanol is obtained.
theoretical

Answers

actual yield of ethanol = 305.0g

molar mass of sucrose = 342g

molar mass of ethanol  =46g

mass of sucrose = 665g

mole of sucrose = mass / molar mass = 665/342

mole of sucrose =1.9 mole

sucrose :  C2H5OH

       1      :  4

     1.9     : 1.9x4 =7.6 mole of C2H5OH are formed

mass (therotical yield ) of C2H5OH= mole x mass

mass (therotical yield ) of C2H5OH= 7.6 x 46 = 349.6g

percent yields of ethanol =  actual /therotical x100

=305/349.6x100 = 87.24 %

Consider a free lysine amino acid in a solution buffered to pH = 9.00. What will be the overall charge on the residue?
Is it -2, -1, 0, 1, 2?

Answers

Answer:

Explanation:

+1

The overall charge on the residue ( lysine residue ) is ; ( C )  0 charge

The a-aminium group of lysine amino acid will begin deprotonating by the presence of NaOH as the pH level of the solution increases.

Given that the pKa level of a-aminium group = 9. when the pH of  the solution is buffered to 9.0 . half of the a-aminium ions that is present in the lysine amino acid will deprotonate leaving the overall charge on the lysine residue at neutral ( 0 charge ).

Hence we can conclude that the overall charge on the residue is a 0 charge.

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