Answer:
Fc=mv2/r v=√(Fcr/m) v=√[(3.6 N)(0.38 m)/(0.0012kg)] v=33.76388603 m/s v=38 m/s
Explanation:
in the circus, a clown is launched from a cannon at 40 m/s, 60o from the horizontal. where should the other clowns hold the net so that the projectile clown lands unharmed (at the same level)
In order for the clown to land unharmed, the other clowns should hold the net at a point along the trajectory of the clown that is equal to the launch height of the clown.
The point can be calculated using the following equation:
Distance = velocity × time
Where velocity = 40 m/s and time = 2(velocity × sin(60o))/9.8 (where 9.8 is gravitational acceleration).
Therefore, the distance = 40 m/s × 2(40 m/s sin(60o))/9.8 = 80 m.
The other clowns should aim to place the net at a point that is 80 meters away from the cannon and at a height of 40 meters. This point should correspond to the apex of the trajectory, which is the highest point that the clown will reach when launched. The clowns should also make sure that the net is held at an angle of 30 degrees with respect to the horizontal, to ensure that the clown lands safely at the same level where it was launched.
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5. A spring of k-500 N/m that is initially compressed 2m is used to launch a 100N load of bricks up a 2 m tall
hill. Find the speed of the bricks at the top of the hill.
a. Qualitatively complete the energy flow diagram and the energy bar graphs.
The kinetic energy of the brick equal the elastic potential energy at the top of the hill. Using this, the speed of the brick is 14 m/s.
What is elastic potential ?The elastic potential of a spring is directly proportional to the squire of the displacement.
Then,
p = 1/2 k x²
Given that, spring constant k = 500 N/m
height of the hill x = 2 m
weight of the load = 100 N
then mass = 100N/9.8 m/s² =10.20 Kg.
At the top of the hill, kinetic energy of the hill is equal to the elastic potential.
then, 1/2 mv² = 1/2 k x²
speed v of the brick = √kx²/m
v = √(500 N/m × 2 m²/10.20 kg)
= 14 m/s.
Therefore, the speed of the brick at the top of the hill is 14 m/s.
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1)Depending on the amount of water in the lake, the salinity of an ocean is 34.5 0/00, If this were the case, 1000g of this would consist of____ grams of water and ____grams of salt.
2)Describe how salinity and temperature effect the density of sea water:
(1) If this were the case, 1000g of this would consist of 965.5 grams of water and 34.5 grams of salt.
(2) Increase in either salinity or temperature leads to an increase in the density of seawater and vice versa.
What is the amount of water and salt contained?The salinity of seawater is typically measured in "parts per thousand" (ppt), which means that for every 1000 parts (by weight) of seawater, 34.5 parts are salt.
So it implies that in 1000g of seawater with a salinity of 34.5 ppt, there would be 34.5g of salt and 965.5g of water.
Salinity has a direct effect on the density of seawater because the dissolved salts in seawater increase its mass, which in turn increases its density.
Temperature also affects the density of seawater because as the temperature increases, the water molecules move faster and the spaces between them increase, leading to a decrease in the density of the water.
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a sine wave is a periodic signal that question 9 options: 1) can be measured in terms of it's amplitude, frequency and phase 2) has equal phase, frequency and amplitude 3) is digital or analog 4) has a maximum peak amplitude equal to it's frequency
A sine wave is a periodic signal that can be measured in terms of it's amplitude, frequency and phase.
Sine waves have equal phase, frequency, and amplitude. The phase of a sine wave determines its position relative to a reference point in time, and a sine wave always starts at zero phase. The frequency of a sine wave is the number of cycles it completes in one second, and the amplitude of a sine wave is the maximum value it reaches. In a pure sine wave, these three properties are constant and equal.
Sine waves are analog signals and are commonly used in communication systems, audio and video processing, and electronic signal processing. They are also used in scientific and engineering applications, such as vibration analysis, acoustics, and control systems.
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--The complete question is, a sine wave is a periodic signal that, 1) can be measured in terms of it's amplitude, frequency and phase 2) has equal phase, frequency and amplitude 3) is digital or analog 4) has a maximum peak amplitude equal to it's frequency--
Draw a plot (hand drawn is ok) of the pressure vs. temperature between 20 and 60 degrees c, labelling the axes, including units, and showing your data points. sketch a line showing the ideal gas law.
The temperature axis is the horizontal axis on a graph where the temperature values are plotted. In other words, it is the x-axis of a graph where the values on the x-axis represent different temperatures. The temperature axis is usually labeled with the units in which temperature is measured, such as degrees Celsius (°C), degrees Fahrenheit (°F), or Kelvin (K). The temperature axis is an important component of many scientific and engineering graphs, particularly those that involve the study of thermal properties and changes in temperature over time.
The plot should have the temperature on the x-axis and the pressure on the y-axis. The temperature axis should be labeled in degrees Celsius (°C) and the pressure axis should be labeled in units of pressure such as Pascals (Pa) or atmospheres (atm).
The data points should be plotted between 20°C and 60°C, with several points at different temperatures and corresponding pressures. These points should be labeled with their respective temperature and pressure values.
A line showing the ideal gas law should be plotted on the same graph. This line should be a smooth curve that passes through or near the data points. The equation of the ideal gas law is PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the absolute temperature. When plotted on a pressure-temperature graph, the ideal gas law forms a straight line.
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A player catches a ball. Consider the action force to be the impact of the ball against the player's glove: The reaction t0 this force is the A) player's grip on the glove. B) force the glove exerts on the ball. C)friction of the ground against the player's shoes D) muscular effort in the player's arms
The reaction to the action force of the impact of the ball against the player's glove is option B): "the force the glove exerts on the ball".
This is known as Newton's Third Law of Motion, which states that for every action, there is an equal and opposite reaction. So, as the ball exerts a force on the glove, the glove exerts an equal and opposite force on the ball, allowing the player to catch the ball. The other options listed (A, C, and D) are not directly related to the action-reaction force pair involved in the catch.
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Calculate the kinetic energy (in joules) of a 108kg women running at a speed of 8m/s.
Answer:
KE = 3456 J
Explanation:
Two thin conducting wires are used to connect very large conducting plates to opposite poles of a battery. Chemical reactions within the battery produce an emf E that "pushes" one electron after another onto the wire connected to the negative terminal of the battery. and "pulls" one electron after another from the wire connected to the positive terminal of the battery a. Given that positive charges repel each other and negative charges also repel each other like charges repel"), speculate about how the similarly-charged particles that accumulate on each side of the battery amange themselves on the (tiny) wires and (very large) plates. b. After the battery has worked for a while, there are a lot of extra electrons on the plate connected to the battery's negative terminal (we'll call this total electrical charge -q) and a lot of extra positive charge on the plate on the left (let's call this total electrical charge +q). How do these extra charges affect the battery's ability to push even more charge onto the plates? Will there come a time when the battery has pushed all the charge it can onto the plates? c. While the battery is charging up the plates, is there a current flowing in the wires? d. The capacitance Cof a pair of conductors (ike these two plates) is defined to be the ratio of the total charge that is on the positive conducting plate (with -e on the negative plate) and the voltage difference AV between the plates. That is, C Av. Given your answers to the other parts of this question, why do you think this quantity is called the "capacitance"?
To lessen electrostatic attraction between them, the extra charges will be dispersed equally on the enormous conducting plates as widely as feasible.
What is EMF?a. When the battery is connected to the wires, the negatively charged electrons on the wire attached to the negative terminal of the battery will reject one another, driving them to spread as much as possible down the wire.
Positively charged holes (holes left over when electrons are missing) behave similarly to negatively charged holes in that they repel one another and spread out as much as possible down a wire connected to a positive terminal of a battery.
b. In order to prevent the battery from pushing more charge onto the plates, the extra charges on the plates will generate an electric field between them.
The back EMF, sometimes referred to as the counter EMF, grows as the charge on the plates rises. The back EMF will eventually equal the battery's EMF, at which time the battery will be unable to push any more charge onto the plates.
c. Yes, as the battery charges the plates, there will be a current going through the cables. The current is the passage of electrons from the battery's negative terminal onto the negative plate through the wire.
d. Because it shows how well the two plates can hold an electrical charge, much like a capacitor does, the amount C is known as capacitance.
Therefore, For a given voltage differential between the plates, the capacitance increases the amount of charge that may be stored.
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the bolts on the cylinder head of an engine require tightening to a torque of 84 m n. if a wrench is 28 cm long, what force perpendicular to the wrench must the mechanic exert at its end
300 N of force must be applied by the mechanic perpendicular to the end of the wrench.
The SI unit of force is what?The SI unit of force is the newton, denoted by the letter N. Base units that are pertinent to force are: The symbol for the length unit of a metre is m. the kilogramme (kg), a unit of mass. S represents the second, a measure of time.
The following formula can be used to resolve this issue:
Torque equals force times distance times sin (angle), where:
Torque is the 84 mN desired torque.
Force is the unknowable force that we must discover.
Distance is the length of the wrench in meters, which is 0.28 m
Angle is the angle between the wrench and the direction of the force, which is 90 degrees for a perpendicular force (sin(90) = 1)
Plugging in the values, we get:
84 mN = Force x 0.28 m x 1
Solving for Force, we get:
Force = 84 mN / 0.28 m
Force = 300 N
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according to the reading examples, the net change is always the same as the net displacement for a particle in motion, moving along a straight line.
If a particle is moving along a straight line, the net change and the net displacement are always equal.
If a particle is moving along a straight line, then the net change and the net displacement are always the same. Net change is the total change in position of the particle, which is the final position minus the initial position. Net displacement, on the other hand, is the change in position of the particle in a particular direction, which is the final displacement minus the initial displacement.
When a particle moves along a straight line, the direction of its displacement is always the same as the direction of its motion. Therefore, the net displacement is simply the distance traveled by the particle in the direction of motion. And since the net change in position is also the distance traveled by the particle, the net change is always equal to the net displacement in this case.
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the space between two coaxial cylinders is filled with an incompressible fluid at constant temperature. the radii of the inner and outer wetted surfaces are kr and r, respectively. the angular velocities of rotation of the inner and outer cylinders are ai and a,. determine the velocity distribution in the fluid and the torques on the two cylinders needed to maintain the motion. (b) repeat part (a) for two concentric sph
The velocity distribution in the fluid can be found using the Navier-Stokes equation, which states that the net force on a fluid element is equal to its mass times its acceleration.
(a) Velocity distribution and torques on two coaxial cylinders:
The fluid is incompressible, so the continuity equation can be used to relate the fluid velocities at different radii. For the coaxial cylinders, the velocity distribution can be found by assuming a linear velocity profile between the two surfaces, where the velocity at the inner surface is ai * kr and the velocity at the outer surface is a * r. Therefore, the velocity profile is given by:
v(r) = (a - ai) / (r - kr) * (r - kr) + ai * kr
The torque required to maintain the motion of the cylinders can be found using the formula:
T = I * α
where T is the torque, I is the moment of inertia, and α is the angular acceleration. For each cylinder, the moment of inertia is given by:
I = (1/2) * m * R²
where m is the mass of the cylinder and R is its radius. The angular acceleration is related to the angular velocity by:
alpha = (a - ai) / (r - kr)
Therefore, the torque on the inner cylinder is:
Ti = (1/2) * m * kr² * (a - ai) / (r - kr)
and the torque on the outer cylinder is:
To = (1/2) * m * r² * (a - ai) / (r - kr)
(b) Velocity distribution and torques on two concentric spheres:
The velocity distribution and torques on two concentric spheres can be found in a similar way to the coaxial cylinders. Assuming a linear velocity profile between the two spheres, where the velocity at the inner sphere is ai * kr and the velocity at the outer sphere is a * r, the velocity profile is given by:
v(r) = (a - ai) / (r - kr) * (r - kr) + ai * kr
The torque required to maintain the motion of the spheres can be found using the same formula as for the cylinders, with the moment of inertia for each sphere given by:
I = (2/5) * m * R²
where m is the mass of the sphere and R is its radius. Therefore, the torque on the inner sphere is:
Ti = (2/5) * m * kr² * (a - ai) / (r - kr)
and the torque on the outer sphere is:
To = (2/5) * m * r² * (a - ai) / (r - kr)
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Consider the two vectors A and B. You know the magnitudes of these vectors (lmand 10 m respectively), but you do not know anything about their directions ca ment Status here for 9 H a vector is defined to be the sum of these two vectors CHA+B) which of the following are true about the magnitude of C7 Choose all that apply C. cannot be determined Grade Summary Cain
A. The magnitude of C can be determined.
D. The magnitude of C is between 1m and 10m.
When two vectors are added, the magnitude of the resulting vector can be found using the law of cosines. For the vectors A and B, the magnitude of their sum C is given by:
|C|² = |A|² + |B|² + 2|A||B|cosθ,
where θ is the angle between the vectors A and B. Since the directions of A and B are unknown, θ could take any value between 0 and 180 degrees. However, the minimum value of cosθ is -1, which occurs when θ = 180 degrees. Therefore, the minimum magnitude of C is:
|C|min = |A| - |B| = 1 m - 10 m = 9 m.
The maximum value of cosθ is 1, which occurs when θ = 0 degrees. Therefore, the maximum magnitude of C is:
|C|max = |A| + |B| = 1 m + 10 m = 11 m.
Therefore, the magnitude of C is between 1m and 10m, and it can be determined.
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correct question
Which of the following statements are true about the magnitude of the vector C, which is defined as the sum of two given vectors A and B with magnitudes 1m and 10m respectively, but unknown directions? (Choose all that apply.)
A. The magnitude of C can be determined.
B. The magnitude of C is less than 10m.
C. The magnitude of C is less than 1m.
D. The magnitude of C is between 1m and 10m.
E. The magnitude of C is greater than 11m.
What is the answer and how to get to that answer what is the equation
The gravitational force between the ball of mass 100 Kg and earth at a distance of 6.38 × 10⁶ m is 979.9 N.
What is gravitational force?The gravitational force is the force by which an object attracts other object into its center of mass. The gravitational force depends on the masses of the objects and distance between them by the equation written below:
Fg = G m1 m2/r²
where G is the universal gravitational constant equal to 6.67 × 10⁻¹¹ N/kg²m²
The gravitational force is given 2.30 ×10⁻⁸ N.
distance between the objects = 10 m.
then Fg = 6.67 × 10⁻¹¹ N × (100 kg × 5.98 ×10²⁴ kg)/(6.38 × 10⁶ m)² = 979.9 N
Therefore, the gravitational force between the ball and earth is 979.9 N. IN similar way, the force between any two objects can be determined using the given distance and mass.
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The visible part of the electromagnetic spectrum can be divided into seven color bands of Red, Orange, Yellow, Green, Blue, Indigo, and Violet (from long to short wavelength). A single photon of which of these colors has the greatest amount of energy?
*e. Violet mnemonic: "ROY" G "BIV"
A single photon of violet color has the greatest amount of energy among the visible colors of the electromagnetic spectrum. This is because violet light has the shortest wavelength and the highest frequency among the visible colors.
According to the equation E = hf, where E is the energy of a photon, h is Planck's constant, and f is the frequency of the radiation ,Because the wavelengths of electromagnetic radiation are inversely proportional to their frequencies, according to the equation c = λf, where c is the speed of light, λ is the wavelength of the radiation, and f is its frequency. Therefore, photons of violet light, having the highest frequency, also have the highest energy.
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Express the results of the following calculations in SI base units.
1. 40 × 107 nm - 4 MJ
dm
2. 13 PW 3 ns. 1 x 10³ Hz
The calculations in SI base units of 40 × 107 nm - 4 MJ dm will be [tex]13 X 10^1^5 W[/tex].
What is SI unit?The present version of the metric system is called the International System of Units, also referred to as the SI system and abbreviated SI in all languages.
40 × 107 nm - 4 MJTo convert the first quantity, 40 × 107 nm, to SI base units, we need to express it in meters (m).
Since 1 nm = [tex]10^{-9}[/tex] m, we can multiply 40 × 107 nm by [tex]10^{-9}[/tex] to obtain:
40 × 107 nm * [tex]10^{-9}[/tex] m/nm = 40 × 107 * [tex]10^{-9}[/tex] m = 4 × [tex]10^{-2}[/tex] m
Next, to convert the second quantity, 4 MJ, to SI base units, we need to express it in joules (J). Since 1 MJ = [tex]10^{6}[/tex] J, we can multiply 4 MJ by [tex]10^{6}[/tex] to obtain:
4 MJ x [tex]10^{6}[/tex] J/MJ = 4 x [tex]10^{6}[/tex] J = 4 × [tex]10^{6}[/tex] J
So, the expression 40 × 107 nm - 4 MJ can be expressed in SI base units as:
4 ×[tex]10^{-2}[/tex] m - 4 × [tex]10^{6}[/tex] J
13 PW 3 ns. 1 x 10³ HzTo convert the first quantity, 13 PW, to SI base units, we need to express it in watts (W). Since 1 PW = [tex]10^{15}[/tex] W, we can multiply 13 PW by [tex]10^{15}[/tex] to obtain:
13 PW x [tex]10^{15}[/tex] W/PW = 13 x [tex]10^{15}[/tex] W = 13 × [tex]10^{15}[/tex] W
Next, to convert the second quantity, 3 ns, to SI base units, we need to express it in seconds. Since 1 ns = [tex]10^{-9}[/tex] s, we can multiply 3 ns by [tex]10^{-9}[/tex]to obtain:
3 ns x [tex]10^{-9}[/tex] s/ns = 3 x [tex]10^{-9}[/tex] s = 3 × [tex]10^{-9}[/tex] s
Finally, to convert the third quantity, 1 x 10³ Hz, to SI base units, we need to express it in hertz (Hz). Since the value is already in Hz, we don't need to perform any conversions:
1 x 10³ Hz = 1 × [tex]10^3[/tex] Hz
Thus, the expression 13 PW 3 ns. 1 x 10³ Hz can be expressed in SI base units as: 13 × 10^15 W * 3 × 10^(-9) s * 1 × 10^3 Hz.
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The motions of a car and a truck along a straight road are represented by the velocity-time graphs in the figure. The two vehicles are initially alongside each other at time t = 0.
At time T, what is true of the distances traveled by the vehicles since time t = 0?
a. They will have traveled the same distance.
b. The truck will not have moved.
c. The car will have travelled further than the truck.
d. The truck will have travelled further than the car.
Based on the graphs in the figure, the motion of a car and a truck that initially alongside each other at time t = 0. And at time T, the distances traveled by the vehicles since time t = 0 is the car will have travelled further than the truck (option C)
Looking at the graph, the distance traveled by the truck and the car at time T = t is equal.
When T = t, the journey's duration and the speeds of the automobile and truck exactly match each other, as shown by the graph.
Consequently, if we take the equation into account;
V = Δs/Δt
Where;
v = velocity
s = the distance change
t = time change.
Given that the coordinates of velocity and time for the automobile and the truck match, the two objects have gone the same distance.
The area under the curve is used to calculate the mit. The truck would have traveled nearly half as far as the car, which will have traveled the greatest distance.
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the electric field inside a hollow conductor is said to be zero, which requires that there is an induced charge of q on the inner surface of the hollow conductor
This assertion is true: There is no electric field inside a hollow charged conductor.
What exactly is a "electric field"?Any sort of charge causes an electric field to be associated to a location in space. The strength and direction of the electric field are expressed by the value of E, also referred to as the electric field strength, electric field intensity, or simply the electric field.
What is an example of an electric field?The electric field is the region of space around an electrically charged particle or object where the charge body feels force. Examples: -Electric fields are created by charges and their configurations, such as capacitors and battery cells.
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A small frictionless 8.00 kg cart is released from rest at the top of the hill on a road in a town (assume the hill is perfectly straight and flat, like a ramp). A student is interested in how the motion of the frictionless cart on the hill differs from the motion of a solid cylinder when they are released from rest. The length of the hill from starting point to the ending point is 300 m and the point of release for the cart is 54 m above the ending point.
a.) Determine the acceleration of the cart. (m/s/s)
b.) Determine the time it takes the cart to travel from the starting point to the ending point. (s)
Now, the solid cylinder with the same mass as the cart and a radius of 0.024 m is released from rest at the top of the hill. Assume there is more than enough friction so that the cylinder rolls without slipping.
c.) Determine the acceleration of the cylinder. (m/s/s)
d.) Determine the time it takes the cylinder to travel from the top of the ramp to the bottom. (s)
a.) The acceleration of the cart can be calculated using the formula g = 9.8 m/s², where g is the acceleration due to gravity. a = F/m = m × g = 4.40 kg × 9.8 m/s² = 43.12 m/s²
b.) The time it takes the cart to travel from the starting point to the ending point can be calculated using the kinematic equation:
d = v_0t + 1/2at²,
366 m - 53 m = 313 m
313 = 0t + 1/2(43.12)t² = 1/2(43.12)t²
313 = 21.56t², t² = 313 / 21.56
t² = 14.52, t = √14.52 = 3.8 sec.
c.) The acceleration of the cylinder can be calculated using the formula a = g - (v²)/Rg
d.) The time it takes the cylinder to travel from the top of the ramp to the bottom can be calculated using the kinematic equation:
d = v_0t + 1/2at²,
What is acceleration?
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Six identical blocks of steel, each with mass 10.0 kg, are taken to the Moon. On the Moon, their combined mass is
The combined mass of the six blocks of steel on the Moon would be 10.0kg. This is because the gravitational force on the Moon is only one sixth of the gravitational force on Earth, meaning that the mass of the blocks would be correspondingly reduced. On the Moon, the blocks of steel would weigh only 1.67 kg each, for a total mass of 10.0kg.
The effect of the reduced gravity on the blocks of steel is due to the inverse square law of gravitation. This law states that the force of gravity between two objects is inversely proportional to the square of the distance between them. Since the Moon is much farther away from the Earth than the blocks of steel were on Earth, the gravitational force on the blocks is much weaker. The reduced gravitational force on the Moon means that the six blocks of steel have a collective mass of 10.0kg. This mass is significantly lower than their combined mass of 60 kg on Earth, which is due to the inverse square law of gravitation.
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The six steel blocks on the Moon would weigh a total of 10.0kg. This is due to the fact that the gravitational force on the Moon is only one sixth that on Earth, which implies that the mass of the blocks would be lowered accordingly.
The steel blocks would only weigh 1.67 kg each, for a total mass of 10.0 kg, on the Moon.
The inverse square law of gravitation is what causes the steel blocks to be affected by the decreasing gravity. According to this rule, the force of gravity is inversely proportional to the square of the distance between two objects. The gravitational pull on the steel blocks is much weaker on the Moon since it is much further away from the Earth than the steel blocks were on Earth. The six steel blocks weigh a total of 10.0 kg due to the Moon's lower gravitational pull. The inverse square law of gravitation explains why this mass is far smaller than their total mass of 60 kg on Earth.
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Which type of energy is stored in molecules that make up gasoline? A. Sound energy B. Electromagnetic energy C. Nuclear energy D. Chemical energy
A rocket is attached to a person in a sled with a combined mass of 48 kg. The sled is launched with 431 N of thrust up a frictionless icy hill sloped at 16.2° from the horizontal. What is the magnitude of acceleration of the sled while it travels up the hill?
0.821 m/s2.
2.73 m/s2.
11.7 m/s2.
6.25 m/s2.
Answer:
Explanation:
To determine the acceleration of the sled, we need to balance the net force acting on it with its weight.
The weight of the sled and person is given by:
Weight (W) = mass (m) x acceleration due to gravity (g) = 48 kg x 9.8 m/s^2 = 470.4 N
The weight acts vertically downward, perpendicular to the slope of the hill. The net force acting on the sled can be found by subtracting the force of friction from the thrust:
Net force (F) = thrust (T) - weight (W) x sin(θ)
where θ is the angle between the horizontal and the slope of the hill, given as 16.2°.
The force of friction is zero in this case, as the sled is moving up a frictionless icy hill.
So, the net force is simply equal to the thrust:
Net force (F) = thrust (T) = 431 N
The acceleration of the sled is given by:
acceleration (a) = net force (F) / mass (m) = 431 N / 48 kg = 9 m/s^2
Therefore, the magnitude of the acceleration of the sled while it travels up the hill is 9 m/s^2.
estimate the radiation pressure due to a 75-w bulb at a distance of 8.0 cm from the center of the bulb. estimate the force exerted on your fingertip if you place it at this point.
At a height of 8.0 cm from the bulb's center, the radiation pressure caused by a 75-w bulb is calculated as current=watts divided by voltage=75/120=0.625 amperes.
How do you define radiation pressure class?The mechanical stress that is applied to any surface as a result of the electrical waves and the object exchanging momentum is known as radiation pressure. When photons hit the object's surface in this instance, momentum is transferred.
What does radiation pressure look like in practice?The development of cometary tail, in which dust particles ejected by cometary nuclei are driven by solar radiation into distinctive trailing patterns, is another visually striking example of radiation pressure. With the development of, it became possible to apply radiation pressure to terrestrial environments.
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Which of the following quantities has units of a displacement? (There could be more than one correct choice). 32 ft/s^2 vertically download. 9.8m/s^2 40km southwest. 186,000ml. -120 m/s.
Displacement is expressed magnitude and a direction in m, km, ft etc. Among the given options, the one indicting a displacement is 40 km southwest.
What is displacement ?Displacement is a physical quantity measuring how far an object is travelling and in which direction from the initial position. The displacement is a vector quantity having both magnitude and direction.
Displacement can be expressed in different units such as m, km, ft etc. Here, 32 ft/s² and 9.8 m/s² are acceleration. 120 m/s is velocity. Then, 186000 ml is expressing volume of a substance.
Therefore, among the given options, 40 km southwest is indicating the displacement of an object with its magnitude and direction. 40 Km is magnitude and southwest is the direction.
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What part of acceleration formula represents the time has passed?
The general formula for acceleration is:
[tex]a = (v_f - v_i) / t[/tex]
where a is the acceleration, [tex]v_f[/tex] is the final velocity[tex], v_i[/tex] is the initial velocity, and t is the time interval during which the change in velocity occurs.
What is acceleration?Acceleration is the rate of change of an object's velocity over time. It is a vector quantity that is defined as the change in velocity divided by the time interval during which the change occurs. Acceleration can be positive, negative, or zero, and it is measured in units of meters per second squared [tex](m/s^2).[/tex]
To find the time that has passed given the acceleration formula, we would need to rearrange the formula to solve for time "t" in terms of the other variables. For example, if we know the initial velocity, final velocity, and acceleration, we can use the formula to find the time interval during which the velocity changes.
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An 8.90-kg block of ice, released from rest at the top of a 1.15-meter long frictionless ramp, slides downhill, reaching a speed of 2.87 m/s at the bottom.
What would be the speed of the ice at the bottom if the motion were opposed by a constant friction force of 11.0 N parallel to the surface of the ramp?
I have already solved the angle of the ramp, it is 21.4 degrees.
Answer:
2.32 m/s
Explanation:
If an 8.90 kg block of ice slides down a 1.15 m frictionless ramp to reach a speed of 2.87 m/s, you want to know its final speed if there were friction opposing the motion with a force of 11.0 N.
EnergyThe kinetic energy at the bottom of the frictionless ramp is ...
KE = 1/2mv²
KE = 1/2(8.90 kg)(2.87 m/s)² = 36.654205 J
FrictionWhen friction is introduced, the work done to oppose the friction is ...
W = Fd
W = (11 N)(1.15 m) = 12.65 J
Hence the remaining energy of the block at the bottom of the ramp with friction is ...
KE' = 36.654205 -12.65 J = 24.004205 J
This corresponds to a speed of ...
v = √(2·KE/m) = √(2·24.004205/8.9) ≈ 2.32 . . . . m/s
The speed at the bottom of the ramp with friction is about 2.32 m/s.
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Additional comment
We can find the slope of the ramp by equating the ending kinetic energy to the beginning potential energy. As you can see, that is not relevant to the problem, since the opposing force is parallel to the ramp.
true/false. living cells contribute to the turbidity of a culture, but cells also contribute to the turbidity of a culture, which is a disadvantage of the indirect spectrophotometer method.
The given statement " Living cells contribute to the turbidity of a culture, and this contribution can be a disadvantage of the indirect spectrophotometer method, is True.
The indirect spectrophotometer method, which measures the turbidity of a culture to estimate cell density, assumes that the only contributor to turbidity is the cells themselves. However, other factors such as debris, bubbles, and extracellular materials can also contribute to the turbidity, leading to inaccuracies in cell density measurements. In microbiology, turbidity is a measure of the cloudiness or haziness of a liquid culture, and it is often used as an indirect measure of cell density. The more cells there are in the culture, the more turbid it will appear.
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match the words in the left-hand column to the appropriate blank in the sentences in the right-hand column. use each word only once. view available hint(s)for part a resethelp 1. the blankof the hubble space telescope is better for shorter (bluer) wavelengths of light than for longer (redder) wavelengths of light.target 1 of 7 2. the large research observatories on mauna kea use giant blank.target 2 of 7 3. blankseparate the various colors of light, allowing astronomers to determine stellar composition and many other stellar properties.target 3 of 7 4. the twin 10-m keck telescopes can work together to obtain better angular resolution through a technique known as blank.target 4 of 7 5. the chandra x-ray observatory focuses x rays with blankmirrors.target 5 of 7 6. a 10-meter telescope has a larger blankthan a 4-meter telescope.target 6 of 7 7. galileo's telescope designs using lenses were examples of blank.
In the sentences for the telescope in the right-hand column from the first-hand column, the relevant blank has been filled.
Describe the telescope.
A telescope is the device used to show an enlarged view of a far-off object.
There are different types of telescopes, and each is used for a particular purpose.
The blank that should be filled in correctly from the first column is as follows:
1. Shorter (bluer) wavelengths of light have better angular resolution than longer (redder) wavelengths of light for the Hubble Space Telescope.
2. Huge reflecting telescopes are employed by the numerous research observatories on Mauna Kea.
3. The spectrograph, which divides light into its various colors, enables astronomers to ascertain the stellar composition as well as a number of other stellar characteristics.
4. The identical 10-m Keck
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If a lining is ciliated, what is it covered in?
mucous
O
Oskin
Ogrooves
hair
If a lining is ciliated, then it is covered in hair. Thus, the correct option is D.
What is Ciliated lining?Cilia are the small, slender, hair-like structures which are present on the surface of all the mammalian cells. They are primitive in nature and could be single or many types.
Cilia play a major role in the locomotion of body parts. Cilia are also involved in the mechanoreception. The organisms which possess the cilia are known as ciliates.
The bronchus present in the lungs are lined with the hair-like projections called cilia which move the microbes and debris up and out of the airways in the respiratory tract. Scattered throughout the cilia are the goblet cells which secrete mucus that helps in protection of the lining of the bronchus and trapping the microorganisms.
Therefore, the correct option is D.
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Answer:
It's hair!
Explanation:
I got it right on me test~
Two copper wires are labeled A and B. A is twice as long and has twice the diameter of B. Which of the following statements is true?
B and A have the same resistance.
B has twice the resistance of A.
B has 1/2 the resistance of A.
B has 4 times the resistance of A.
A wire's resistance is inversely correlated with its cross-sectional area and inversely proportional to its length. Wire A will therefore have four times the area of Wire B if it is twice as long and twice as thick.
Why does a wire's resistance have an inverse relationship to its cross-section area?The distance between charged particles will increase as the conductor's cross-sectional area does. As a result, there will be less chance of electron collisions. As a result, resistance will decrease as the conductor's cross-sectional area increases.
What relationship exists between a wire's cross-sectional area and wire resistance?It is inversely related to the wire's cross-sectional area. The resistance decreases with increasing wire cross-section area and increases with decreasing cross-section area.
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which of these diagrams may possibly correspond to the situation at point a on the motion diagram? type, in increasing order, the numbers corresponding to the correct diagrams. do not use commas. for instance, if you think that only diagrams 3 and 4 are correct, type 34.
The force diagrams that may possibly correspond to the situation at point A on the motion diagram are 356.
What are force diagrams?A force diagram, also known as a free-body diagram, is a graphical representation that shows the forces, moments, and reactions acting on a body under a specific state. It shows a body or group of connected bodies along with all the applied forces, times, and reactions that the bodies experience.
At point A in the motion diagram, the force acting at point A are as follows:
a net force acting in the forward directiona frictional force acting backward in opposition to the direction to the net forcegravitational force or weight of the object acting downwardsnormal reaction acting upwards.Hence, the correct diagrams are 3, 5, and 6.
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