Answer:
A 100V battery is connected to two oppositely charged plates that are 10cm apart.
i. what is the magnitude of the electric field?
ii. Calculate the electric force exerted on a +200uC point charge.
Explanation:
A 21.2 kg mass falls from a height of 4.000m. The momentum of the mass just before it hits the ground is
A. 144.2
B. 187.8
C. 320.0
D. 442.4
E. 502.1
By third equation of motion -
[tex]\green{ \underline { \boxed{ \sf{v^2-u^2=2aS}}}}[/tex]
where
v= final velocityu = initial velocitya = accelerationS = distance travelledPutting Values to find final velocity of mass before hitting the ground-
[tex]\begin{gathered}\\\implies\quad \sf v^2-(0)^2=2\times g \times 4 \quad (g = acceleration \: due \:to \: gravity) \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf v^2=2\times 9.8 \times 4\quad (g= 9.8 \:m/s) \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf v=\sqrt{78.6} \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf v= 8.86 \:m/s \\\end{gathered} [/tex]
Now finding the momentum of the mass at that moment -
[tex]\green{ \underline { \boxed{ \sf{Momentum= mass \times velocity}}}}[/tex]
[tex]\begin{gathered}\\\implies\quad \sf Momentum= 21.2 \times 8.86 \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf Momentum= 187.8 \:kgms^{-1} \\\end{gathered} [/tex]
[tex]\longrightarrow[/tex]The momentum of the mass just before it hits the ground is 187.8 kgm/s
[tex]\\[/tex]
[tex]\therefore \sf Option \: B) \: is \:correct [/tex]✔️
A grinding wheel with a moment of inertia of 2.0 kg•mº is initially at rest. What angular momentum will the wheel have 10.0 s after a 2.5 N·m torque is applied to it?
a. 25 kg•m/s
b. 4.0 kg•m/s
c. 7.5 kg•m/s
d. 0.25 kg•m/s
Answer:
25 kg m^2/s
Explanation:
The angular acceleration due to the application of torque to the grinding wheel is:
[tex]\tau=I\alpha \rightarrow \alpha=\frac{2.5}{2}=1.25[/tex] (in radian per square second)
So, by the basic equation of the angular acceleration, we can get the angular velocity at t = 10 s as follows:
[tex]\omega=\omega_{o}+\alpha t \rightarrow \omega =0+(1.25)(10) =12.5[/tex] rad/s.
So, the angular momentum at t = 10 s:
[tex]L=I\omega=(2)(12.5) = 25[/tex] kg m^2/s
Problem 3
A car starts from rest at constant acceleration of 2.0 m/s2. At the same instant a truck travelling with a constant
speed of 10 m/s overtakes and passes the car.
(a) How far beyond the starting point will the car overtake the truck?
Answer:
100m
Explanation:
Equation of motion for he truck: s=ut
Equation of motion for the car: s=1/2at^2
the second solution gives , s=2u^2/a = 2*10^2/2 = 100m
i need to know the angle of incidence, reflection, and refraction
Answer:
incident 50°
reflection 90°
refraction 20°
. Satisfied with the jeweler’s method, the customer next takes out a large and rigid bracelet, adds it to the measuring container and records the new mass and the volume level of the liquid, planning to use the same method to determine what it is made of. Unfortunately, the customer failed to notice that the bracelet was much larger than the ring, and was not fully submerged, but was partially protruding above the surface of the water. Do you believe that the density the customer calculated was higher or lower than the actual density of the bracelet? Explain how you came to your conclusion.
Answer:
value is obtained than the real one.
ρ > ρ_real
Explanation:
A widely used method to determine the density of a body is to measure its mass and measure its volume by immersing it in a transparent liquid, to measure its volume by the difference in volumes of the liquid then use the relationship
ρ = m / V
In this case, part of the body remains the force of the liquid, in this case using Archimedes' principle that establishes that the weight of the desalted liquid is equal to the thrust, let's use the equilibrium equation
B - W = 0
B = W
ρ_liquid g V_submerged = ρ_body g V_body
V_submerged = (ρ_body /ρ-liquid) V_body
We can see that the volume is only a fraction of the volume of the body, therefore when performing the division a higher value is obtained than the real one.
What is the volume of a 100g object with a density of 50g/cm3?
A. 5,000cm3
B. 2cm3
C. 0.5cm3
D. 2g
Answer:
The answer is 2 cm³Explanation:
The volume of a substance when given the density and mass can be found by using the formula
[tex]volume = \frac{mass}{density} \\ [/tex]
From the question we have
[tex]volume = \frac{100}{50} \\ [/tex]
We have the final answer as
2 cm³Hope this helps you
A plane maintains constant acceleration and its velocity increases
from 40m/s to 100m/s over a 10 second interval. What is the plane's
average Distance ?
First calculate a, the acceleration of the plane, given by the equation;
[tex] \alpha = \frac{vf - vi}{t} = \frac{100 - 40}{10} = \frac{60}{10} = 6[/tex]
The use the relation given by
Vf²-Vi²=2ad
[tex]d = \frac{100 {}^{2} - 60 {}^{2} }{2 \times 6} = \frac{10000 - 3600}{12} = \frac{6400}{12} = 533.33 \: meters[/tex]
Notice that the speed halfway down is not half the final speed. Another interesting point is that the final answer doesn't depend on the mass. That is really a consequence of neglecting the change in kinetic energy of Earth, which is valid when the mass of the object, the diver in this case, is much smaller than the mass of Earth. In reality, Earth also falls towards the diver, reducing the final speed, but the reduction is so minuscule it could never be measured. QUESTION Qualitatively, how will the answers change if the diver takes a running dive off the end of the board
Answer:
its speed is insignificant before the diver's speed change, so the result does not change
Explanation:
In this exercise of conservation of the momentum, the system is formed by the diver and the Earth
initial instant (before jumping)
p₀ = 0
final instant (after jumping)
[tex]p_{f}[/tex] = m v + M v²
how momentum is conserved
p₀ = p_{f}
0 = m v + M v²
v² = m / M v
since the mass of the Earth is M = 10²⁴ kg
its speed is insignificant before the diver's speed change, so the result does not change
a starting A resultant force of 25 Newton's act on a mass of 0.50kg starting from rest find acceleration in m/s2,final velocity after 20 minutes, distance moved in 20 minutes
Answer:
Using Newton's second law of motion;
F=ma
25=0.25a
a=25/0.25=100 m/s²
After 20 minutes;
Vf=at+Vi
Vf=100(1200)+0
Vf=120000 m/s
d=at²/2 +Vi×t
d=100(1200)²+0
d=144 000 000 meters
How many atoms of each element are present in the formula for bromoethane?
CH3CH2BT
Answer:
Explanation:
How many atoms of each element are present in the formula for bromoethane
10. The force with which one thing hits another or with which two objects collide is
a. Impact force
b. Motion force
c. External force
d. Internal force
Impact force
What is impact force?Impact force is the force exerted by bodies when they come in contact. Impact force has same unit as force. it is similar to impulse the difference is that impulse considers time.
hope it helps...
Which material rises from cracks in oceanic crust?
dense crust
molten rock
continental crust
pillow-shaped rocks
Answer:
molten rocks is the correct answerThe molten rock rises from cracks in the oceanic crust, so option B is correct.
What is crust?The thinnest and most significant layer on our planet is its crust, which is made up of rocks and forms the planet's outermost layer. Despite making up less than 0.5 percent of the globe's total volume, it is essential to the majority of the natural cycles that take place all over the planet. The crust of the Earth is divided into layers, each of which contains a unique element.
Metamorphic rocks are defined as rocks that change into another rock. Sedimentary rocks are created by the deposition of material at the Earth's surface within water bodies, followed by cementation.
The crust that lies beneath land masses is known as the continental crust, whereas the crust that lies beneath the ocean's surface is known as the oceanic crust. The oceanic crust is younger and much thinner than the continental crust.
Therefore, the molten rock rises from cracks in the oceanic crust.
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this diagram shows the sectionary box sitting on the floor which statement about other force exerted on the box are true?
questions:
it's normal force exerted by the floor. it balances the gravitational force.
it's friction force exerted by the floor. it balances the gravitational force.
it's normal for exerted by the floor. does not balance the gravitational force.
it's an applied force exerted from the left. It doesn't balance the gravitational force.
Answer: A) It's a normal force exerted by the floor. It balances out the gravitational force.
The normal force pushes up which means the box doesn't go through the floor. The up and down forces are balance. If the normal force was larger than the gravitational force, then the box would be pushed up and float/jump in the air. But the box is stationary and not moving, so that's why we don't have any acceleration and the forces effectively cancel each other out. In a way you can think of it like a see-saw.
Friction would only come into play if you applied a force and were trying to move the box. Friction counteracts the applied force. If you push the box to the left, then the friction would push to the right. Friction slows down the box and it allows it to not slide forever.
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Is normal force equal to gravity?
The normal force on an object at rest on a flat surface is equal to the gravitational force on that object.
▀▄▀▄Is friction a gravitational force?
Friction is the resistance to motion of one object moving relative to another. It is not a fundamental force, like gravity or electromagnetism. Instead, scientists believe it is the result of the electromagnetic attraction between charged particles in two touching surfaces.
▀▄▀▄Can normal force be greater than gravity?
Can you imagine the situation when Normal force is greater than mg ? Yes. When an additional downward force F is applied to a mass m resting on a horizontal surface, the normal force is FN=F+mg. ... An example is the normal force on an incline plane with an angle of θ due to a mass m.▄▀▄▀▄▀▄
What is the direction of the force you applied?
An applied force is an interaction of one object on another that causes the second object to accelerate or change velocity or direction. The force can be a push, pull, or drag. The resulting direction of an object depends on the relative direction of the force on the object. A force equation is F = ma.
What is the mass of a child that has a KE of 400 J who is riding her bike at 3.9 m/s?
Answer:
52.6 kg
Explanation:
KE = 1/2mv^2
400 = 1/2 x m x 3.9^2
m = 2(400 J)/ ( 3.9 m/s)^2
m = 52.6 kg
2. The weight of a basketball player is 6 ft and 1 12 inches. Change his height to:
a. Feet
b. Inches
C. Centimeters
d. Meters
Answer:
a feat
Explanation:
cause the mf already 7ft on the dot there is no such thing as 6 ft 12
A 50 kg cart is currently in static equilibrium. Which of the following claims is true? *
A.)The cart is experiencing unbalanced forces B.)The cart is at rest
C.)The cart is accelerating
D.)The cart is moving at a constant speed or velocity
During a care on level ground, Andra runs with an average velocity of 6.02 m/s to the East. What distance does Andra cover in 137 seconds?
Answer:
The distance covered is: 824.74 meters
Explanation:
Use the formula for velocity (v) as the distance (d) covered over the time (t) it took:
v = d / t
in our case:
6.02 m/s = d / 137 s
d = 6.02 * 137 = 824.74 meters
Name the charcteristic which help us distinguish berween aman's voice and awamen's seeing them
Answer:
Asalamalikum maryam
Following are the characteristics that help to distinguish between man's and women's voice
Mans have low pitched sound while as women have hight pitched sound.Mans voice is thick while as women's voice is thin.1 point
An object has 50 J of kinetic energy and 20 J of potential energy. What is
the total energy possessed by the object?
30 J
35 J
50 J
70 J
Answer:
30 j
Explanation:
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The kinetic energy of an object is 50 J, and the potential energy is 20 J. The total energy of the object is 30J.
What is potential energy?In physics, potential energy is the energy that an object retains due to its position in relation to other objects, internal tensions, electric charge, or other elements.Potential energy is a type of stored energy that is determined by the interactions of various system components. When a spring is crushed or stretched, its potential energy increases. A steel ball has more potential energy if it is raised above the ground rather than falling to the ground.Potential energy, which is the latent energy in an object at rest, is one of the two types of energy. Kinetic energy, on the other hand, is the energy expressed by a moving object.To learn more about potential energy refer to:
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What is occurring when two waves traveling along the same medium meet and cancel each other out?
O destructive interference
O constructive interference
O reflection
O refraction
Answer:
Destructive interference
Explanation:
Destructive interference occurs when two waves traveling along the same medium meet and cancel each other out. The resultant wave has a smaller amplitude than the individual waves. In this case, the maxima of two waves are 180 degrees out of phase.
Hence, the correct option is (A) "destructive interference"
Answer: the answer is A. Destructive inference
Explanation: I took the test
The wavelengths of visible light vary from about 300 nm to 700 nm. What is the range of frequencies of visible light in a vacuum
The range of frequencies of visible light in a vacuum is mathematically given as
Fmin=4.19*10^14Hz to Fmax=1*10^15Hz
What is the range of frequencies of visible light in a vacuum?Question Parameters:
The wavelengths of visible light vary from about 300 nm to 700 nm.
Generally, the equation for the frequency is mathematically given as
F=C/\lambda
Therefore
For Fmax
[tex]Fmax=\frac{300*10^8}{3*10^9}[/tex]
Fmax=1*10^15Hz
Where
[tex]Fmin=\frac{3*10^8}{700*10^9}[/tex]
Fmin=4.19*10^14Hz
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A body travels at an initial speed of 2.5 m/s. Given a constant acceleration of 0.2 m/s 2 what is the speed of the body at time 25 seconds later?
Answer:
We are given:
u = 2.5 m/s
a = 0.2 m/s/s
t = 25 seconds
v = v m/s
Solving for 'v':
From the first equation of motion:
v = u + at
Replacing the values
v = 2.5 + (0.2)(25)
v = 2.5 + 5
v = 7.5 m/s
A cheetah starts from rest and accelerates after a gazelle at a rate of 6.5 meters per second2for 3.0 seconds. Calculate the cheetah’s speed at the end of these 3.0 seconds.
Answer:
the speed of the cheetah at the end of the 3 seconds is: 19.5 m/s
Explanation:
Let's use the equation that relates speed with acceleration:
vf = vi + a * t
where vf stands for final velocity, vi stands for initial velocity, a for acceleration, and t for the time acceleration is applied. Then, in our case we have:
vf = 0 + 6.5 (3)
vf = 19.5 m/s
At t = 0, Ball 1 is dropped from the top of a 22 m-high building. At the same instant Ball 2 is thrown straight up from the base of the building with an initial velocity of +12 m/s. Assume that Ball 1 starts from rest and that air friction can be ignored. At what height will the two balls pass each other? What is the velocity of each ball at the moment they are at the same height?
Answer:
The two balls pass each other at a height of 5.53 m
vf1=17.97 m/s
vf2=-5.96 m/s
Explanation:
Vertical Motion
An object thrown from the ground at speed vo, is at a height y given by:
[tex]y=vo.t-g.t^2/2[/tex]
Where t is the time and [tex]g=9.8\ m/s^2[/tex]
Furthermore, an object dropped from a certain height h will fall a distance y, given by:
[tex]y=g.t^2/2[/tex]
Thus, the height of this object above the ground is:
[tex]H = h-g.t^2/2[/tex]
The question describes that ball 1 is dropped from a height of h=22 m. At the same time, ball 2 is thrown straight up with vo=12 m/s.
We want to find at what height both balls coincide. We'll do it by finding the time when it happens. We have written the equations for the height of both balls, we only have to equate them:
[tex]vo.t-g.t^2/2=h-g.t^2/2[/tex]
Simplifying:
[tex]vo.t=h[/tex]
Solving for t:
[tex]t=h/vo=22/12=1.833\ s[/tex]
The height of ball 1 is:
[tex]H = 22-9.8.(1.833)^2/2[/tex]
H = 5.53 m
The height of ball 2 is:
[tex]y=12\cdot(1.833)-9.8\cdot(1.833)^2/2[/tex]
y=5.53 m
As required, both heights are the same.
The speed of the first ball is:
[tex]vf1=g.t=9.8\cdot 1.833=17.97\ m/s[/tex]
vf1=17.97 m/s
The speed of the second ball is:
[tex]vf2=vo-gt=12-9.8\cdot 1.833=-5.96\ m/s[/tex]
vf2=-5.96 m/s
This means the second ball is returning to the ground when both balls meet
An electric light bulb has an efficiency of 18%.
400J of energy are supplied to the light bulb by electricity.
a Calculate the amount of energy transferred by light
Answer:
The answer that we got will be 22.22....
If 600 N of force is used to move a car 4 meters, how much work is done?
Answer:
The answer is 2400 JExplanation:
The work done by an object can be found by using the formula
workdone = force × distanceFrom the question
force = 600 N
distance = 4 m
We have
work done = 600 × 4
We have the final answer as
2400 JHope this helps you
A series circuit contains both a 6Ω and a 3Ω resistor. Through the 6Ω resistor, the current is 0.5 amps. What will the current be through the 3Ω resistor?
Answer:
0.5 amps
Explanation:
the amps will be constant no matter what
If, according to Newton’s Third Law, every action force has an equal reaction
force that acts in the opposite direction, why do these forces not just cancel each
other out, resulting in no net force and therefore no motion? Explain.
Answer:
They act on different objects
Explanation:
Let's say that I push a cart, the cart moves because the force is also going into the ground. Hope this makes sense.
Why does the ocean have waves?
Answer:
Waves are most commonly caused by wind. Wind-driven waves, or surface waves, are created by the friction between wind and surface water. As wind blows across the surface of the ocean or a lake, the continual disturbance creates a wave crest. ... The gravitational pull of the sun and moon on the earth also causes waves.
How would the conduction of someone’s hand holding the cold water jar affect the jar’s temperature?
Answer:
The person's hand will warm up the jar
Explanation:
Thermal energy will be conducted from his hand to the jar