A 1000 kg car is moving at 30. m/s and comes to a rest after 6.0 seconds. What is the force on the car?

Answers

Answer 1

The force of the car would be = 5000m/s²

What is force?

Force is defined as the external push or pull that makes an object to move from one position to another.

Mathematically, force is defined as the product of mass and acceleration of a moving object.

That is, F = mass × acceleration

But acceleration= velocity/time

F = mass × velocity/time

mass = 1000kg

velocity = 30 m/s

time = 6 second

Force = 1000× 30/6

= 30000/6

= 5000 m/s²

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Related Questions

What Is The Difference Between A Mile And A Nautical Mile?

Answers

The Difference Between A Mile And A Nautical Mile is that mile is commonly used for terrestrial measurements, while the nautical mile is specifically used for navigation at sea.

A mile and a nautical mile are both units of measurement for distances, but there is a difference between the two. A mile is a standard unit of distance commonly used in the United States and is equal to approximately 1.609 kilometers. A nautical mile, on the other hand, is a unit of measurement used specifically for navigation at sea and is equivalent to 1.852 kilometers, or approximately 1.1508 miles.

In other words, a nautical mile is longer than a standard mile by about 0.1508 miles. This difference is important for navigation on the open sea, where a nautical mile provides a more accurate measure of distance, taking into account the curvature of the earth and the effects of latitude on measurements.

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Which action describes a response to internal stimuli? A Catching a ball at a baseball game B Drinking when you are thirsty C Running at the sight of a wild lion D Writing a thank you note

Answers

Drinking when you are thirsty is response to internal stimuli.

Stimuli is the physical or chemical change in the environment of a living organism. Stimuli may results in some action or some functional activity. There are two types of stimuli, internal stimuli and external stimuli.

Internal stimuli is the internal response which arises inside the body of the organism.

External stimuli is the response of the organism to some external change in the environment.

Catching a ball at a baseball game is the response to the change in the outside the body activity (external change).

Drinking the water when you are thirsty is the response to that activity which is felt by us inside the body.

Running at the sight of a wild lion is the response an to external activity.

Writing a thank you note is also a response to the external activity to a nice gesture of someone.

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What is the best term or statement to define energy?

Answers

The power to do activities is the best term or statement to define energy.

Energy is the potency to do work or make changes to an object. Nowadays, it is very possible to do this because several studies and experiments have been carried out on how to convert energy to do work. People use energy to carry out many activities and make human life easier. Such as cooking, moving cars and ships, lighting houses and roads, walking, making various products, and sending astronauts into outer space.

Energy can be found in many forms such as motion, light, heat, electricity, gravitational, and chemicals.

Energy cannot be destroyed but can be changed from one form to another. An example is the energy contained in coal or natural gas which can be converted into electrical energy. Likewise when humans eat. Food contains chemical energy, and the body stores this energy to use as kinetic energy during activities.

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8. Jane ride a led down a lope of angle θ at contant peed v. Determine the coefficient of kinetic friction between the led and the lope. Neglect air reitance. (A) μ=ginθ (B) μ=mgcoθ (C) μ=tanθ (D) μ=gcoθ

Answers

The coefficient of kinetic friction will be tanθ, along a slope of angle θ.

On a slope of angle θ, the weight (mg) of the led will have to components.

The component of the weight(mg) long the slope(θ) = mg×sinθ

The component of the weight normal to the surface = mg×cosθ

So, the normal reaction of the led on the surface(N) = mg×cosθ

Kinetic friction force = Normal reaction(N) × Coefficient of kinetic friction(η)

Kinetic friction working on the surface is balanced by the component of weight(mg) along the slope, mathematically,

mg×sinθ = N × Coefficient of kinetic friction(η)

mg×sinθ = mg×cosθ × Coefficient of kinetic friction(η)

Coefficient of kinetic friction(η) = mg×sinθ / mg×cosθ

η = sinθ/cosθ

η= tanθ

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if a generator transmits electricity at a rate of 20 k a through a transmission line with a resistance of 0.1 w , how much power is lost in the transmission

Answers

The electric power  lost in the transmission  is  40 MW.

What is electric power?

The rate at which electrical energy is carried over an electric circuit is known as electric power. The watt, or one joule per second, is the SI unit of power.

Transmission lines enable the efficient delivery of electric power across great distances for uses including motion, lighting, and heating.

Current through the transmission line = 20 kilo ampere

Resistance of the transmission line = 0.1 Ω

The power  lost in the transmission = (current)² × resistance

= (20 ka)² × (0.1 Ω)

= 40 MW.

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An archer shoots an 126 g (remember to convert to kilograms) arrow 88 m/s. How much kinetic energy does it have?

Answers

To calculate the kinetic energy of an arrow, we need to know its mass and velocity. Given that the arrow's mass is 126 g, and its velocity is 88 m/s we can use the formula:

kinetic energy = 1/2 * mass * velocity^2

First, we have to convert the mass of the arrow from grams to kilograms, as the formula requires units in kilograms.

1 kg = 1000 g

126 g = 126/1000 kg = 0.126 kg

Then we can substitute the values into the formula:

kinetic energy = 1/2 * 0.126 kg * (88 m/s)^2

kinetic energy = 1/2 * 0.126 * 7744 m^2/s^2

kinetic energy = 468.3 J (joules)

So the kinetic energy of the arrow is 468.3 J. Kinetic energy is a scalar quantity and it represents the energy of motion of an object. In this case, the energy possessed by the arrow due to its motion.

You weigh 770 N.
What would you weigh if the Earth were six
times as massive as it is and its radius were
two times its present value?
Answer in units of N.

Answers

If the Earth were six times as massive as it is and its radius were two times its present value, then weight is calculated as 1155 N.

What is weight?

In science and engineering, weight of an object is the force acting on object due to the gravity.

As we know , F = G * M * m / r ^ 2

Here, F = Gravitational force ; G = Gravitational constant (6.67 x 10 ^ -11 Nm ^ 2 / kg ^ 2) ;  M = mass of earth ; m = mass of object and r = radius of earth

Given, the earth were six times as massive

So,  M = 6M

radius is three times its present value: r = 2r

So, F = G * (6M) * m / (2r) ^ 2

= (6/4) * (G * M * m / r ^ 2)

= (3/2) * (G * M * m / r ^ 2 )

Therefore, weight will be;

(3/2) * F = (3/2) * (770)

Weight = 1155 N

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When the beam just starts to tip, what is the force exerted on the beam by the right support?.

Answers

When the beam start to tip, the force for its support is at least equal to beam weight multiple with the height of field and divided by length of inclined field.

What is force?

Force is an influence that might change the movement of an object. To create an object in static condition, you have to put the same force with the same value of that object force have, but in the opposite direction as to why in the case to give the right support to a beam, you have to hold it with a force that equal or higher to the beam force given.

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what force does the car exert if it’s mass is 1201 kg and the car goes from 5.40 m/s to 16.3 m/s in 107 m

Answers

122 N force does the car exert if it’s mass is 1201 kg and the car goes from 5.40 m/s to 16.3 m/s in 107 S.

What is the straightforward meaning of force?

At this point, it is perfectly acceptable to refer to a force as a pushed or even a pull. A power is not a material that an object "contains" or "has in it." A force is applied to one thing by another. The idea of a force encompasses both living and non-living things.

GIVEN-

a = (16.3- 5.4)/107

=0.10 m/s^2

m= 1201 kg

F = ma

= 122 N

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I need this ASAP please because it's for an essay! "When we pedal a bicycle and stop doing it, it keeps moving a little more, unless we press the breaks" Explain how this works in daily life - Has to do with First Law of Newton

Answers

Answer:Friction

Explanation:When you apply friction to a force it slows it down or stops it

Lisa had a velocity of 10 m/s until the neighbors dog started chasing her. She ended up running at 15 m/s after 5 seconds. What was her acceleration?

Formula-

Work with units-

Answers with units-

Answers

The acceleration of Lisa having an initial velocity of 10 m/s is 1 m/s².

What is acceleration?

Acceleration is the rate of change of velocity.

To calculate Lisa acceleration, we use the formula below,

Formula:

a = (v-u)/t....................... Equation 1

Where:

a = Accelerationv = Final velocityu = Initial velocityt = Time

From the question,

Given:

v = 15 m/su = 10 m/st = 5

Substitute these values into equation 1

a = (15-10)/5a = 5/5a = 1 m/s²

Hence, the acceleration of Lisa is 1 m/s².

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a Two cars are involved in a head-on collision in an alley. The driver of a car with mass,
ma = 1,200 kg claims to have been traveling west at via = 7 m/s. The driver of the
other car with mass, mb = 1,000 kg claims to have been traveling east at vib = 10
m/s. The investigating officer found that both cars were stuck together and traveled
with a common final velocity after the collision.
Which direction would they be moving after the collision?
west
east
north
no direction/ not moving

Answers

Either the eastbound car's driver overestimated or the westbound car's driver underestimated his velocity.

What is the difference between mass and velocity?

It has a direction and a magnitude and is a two-dimensional vector quantity. The momentum of an item is given by the equation p=mv if its mass is m and its velocity is v (also a vector quantity). As a result, momentum is calculated by multiplying mass by speed.

Let the given values be

[tex]& m_a[/tex] = Mass of west moving car = 1200 kg

[tex]& m_b[/tex] = Mass of east moving car = 1000 kg

[tex]& v_{i a}[/tex] = Velocity of west moving car = -7 m/s  

[tex]$v_{i b}[/tex] = Velocity of east moving car = 10 m/s

v = Combined velocity of the cars = 3 m/s

From the conservation of momentum we get

[tex]$$\begin{aligned}& m_a v_{i a}+m_b v_{i b}=\left(m_a+m_b\right) v \\& \Rightarrow 1200 \times-7+1000 \times 10=(1000+1200) \times 3 \\& \Rightarrow 1600 \neq 6600\end{aligned}$$[/tex]

So, either westward [tex]$(1000 \times 10)$[/tex] moving car needs to have more velocity or eastward [tex]$(1200 \times-7)$[/tex] moving car needs to have less velocity.

Since, mass is constant only the velocity can be different.

Therefore, the correct answer is option d) Either the driver of the westbound car underestimated his velocity, or the driver of the eastbound car overestimated his velocity.

The complete question is:

Two cars are involved in a head-on collision in an alley. The driver of a car with mass, ma = 1,200 kg claims to have been traveling west at via = 7 m/s. The driver of the other car with mass, mb = 1,000 kg claims to have been traveling east at vib - 10 m/s. The investigating officer found that both cars were stuck together and traveled with a common final velocity of 3 m/s, eastward, after the collision.

Assuming that at least one driver is correct, what does an application of the law of conservation of momentum allow the officer to conclude about the accident?

a) The driver of the westbound car was moving significantly faster than reported.

b) Both drivers correctly reported their velocities at the time of the collision.

c) Either the driver of the westbound car overestimated his velocity or the driver of the eastbound car underestimated his velocity, KID.

d) Either the driver of the westbound car underestimated his velocity, or the driver of the eastbound car overestimated his velocity.

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using newton's second law, why does a hunter always presses the butt of a rifle tightly against his shoulder before firing a bullet ?

Answers

Answer:

Below

Explanation:

SO the equal but opposite force of the bullet being fired forward doesn't cause the backward force of the rifle to slam into his shoulder possibly causing injury

A hunter always presses the butt of a rifle tightly against his shoulder before firing a bullet because this causes a change in the momentum of the bullet being fired.

What is Newton's second law of motion?

Newton's second law of motion states that the rate of change of momentum of a body is directly proportional to the force which is applied to it and the change in momentum of an object takes place in the direction in which the force is being applied.

The acceleration of an object as produced through a net force is directly proportional to the magnitude of the net force, in the same direction as that of the net force, and inversely proportional to the mass of the object.

The butt of the rifle is pressed tightly against the shoulder of the hunter to cause a change in the momentum of the bullet.

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The cue ball strikes a the 8 ball. The two balls have the same mass. Which of the following is true.
a.
The amount the cue ball slows down is equal to the amount the 8 ball speeds up.
b.
The 8 ball will speed up more than the cue ball slows down.
c.
The cue ball will slow down more than the 8 ball speeds up.

Answers

Answer: A. The amount the cue ball slows down is equal to the amount the 8 ball speeds up. ✅

Explanation:

This is true due to the law of conservation of momentum. In an isolated system, the total momentum before the collision is equal to the total momentum after the collision. Since the two balls have the same mass, the amount of momentum lost by the cue ball will be equal to the amount of momentum gained by the 8 ball. ✅

A peron ha a weight if 800N in an elevator that a econd with an acceleration of 5m/. What i the reading on the cale of the elevator

Answers

The scale in the moving elevator will read 1200 N. The result is obtained by using Newton's second law.

What is Newton's second law?

The Newton's second law states that "The acceleration is directly proportional to the net force acting on an object and inversely proportional to the object's mass." It can be expressed as

a = ∑F/m

or

∑F = ma

Where

∑F = net forcea = accelerationm = object's mass

In an elevator, a person has a weight of 800 N. It moves with acceleration of 5 m/s². Find the scale read!

We use g = 10 m/s².

The mass of the person is

W = mg

800 = m(10)

m = 80 kg

The acceleration is positive. So, we assume that the elevator is travelling upward with acceleration of a. By using Newton's second law, we'll get

∑F = ma

N - W = ma

N = W + ma

N = 800 + 80(5)

N = 800 + 400

N = 1200 N

Hence, in the moving elevator, the scale will read 1200 N.

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What is the percent composition of HCl by numbers of atoms?
Group of answer choices
a. 1 to 1
b. 1 to 35.5

Answers

The composition of HCl (hydrochloric acid) by numbers of atoms is 37% HCl by weight and can be find out by using empirical formula.

Empirical formulas give the lowest whole number ratio of the atoms in a compound. The true or molecular formula gives the exact composition of one molecule. A molecular formula describes the actual numbers of atoms of each element in a molecule.

When the subscripts in a chemical formula represent the simplest ratio of the kinds of atoms in the compound, the formula is called an empirical formula. Most ionic compounds are described with empirical formulas.

If you are not given mass in grams for each element, convert the data you are given to grams of each element. This may involve simple unit conversions. For example, you may be given pounds or milligrams, which you convert to grams using unit analysis.

Sometimes you are given the percentage of each element in the compound. Assume that you have 100 g of compound, and change the numbers for the percentages to grams.

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What describes the speed of a planet traveling in an elliptical orbit around the sun? a. Constant b. Fastest when closest to the sun c. Slowest when closest to the sun d. Fastest when closest to the moon.

Answers

The speed of a planet traveling in an elliptical orbit around the sun is b. Fastest when closest to the sun.

ABOUT ELLIPTICAL ORBIT

The planets in the solar system revolve around the sun in certain paths called orbits or orbits that are elliptical, not circular.

In ancient times, humans adhered to geocentric understanding. This theory was introduced by the Greek astronomer Claudius Ptolemy in 100-170 AD.

This belief persisted for 1,400 years. According to him, the earth is the center of the solar system. The sun and planets revolve around the earth in a circular path.

Then in 1543, the astronomer Nicolaus Copernicus sparked the Heliocentric model. According to him, the Earth and other planets revolve around the Sun in circular paths. This theory is better than ever. Although, the assumption that the trajectory of a planet's motion is still in the form of a circle.

The planet's orbit is elliptical due to the gravitational interaction between the planet and the sun and other celestial bodies. Johannes Kepler in the 1600s was the first to discuss the shape of planetary orbits.

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Answer: B.

fastest when closest to the Sun

Explanation: plato :3

Hope this helps!

calculate the linear expansivity of brass of length 120 m that assumed a new length of 120.05 m when heated to a temperature 100° c​

Answers

The linear expansivity of brass of length 120 m that assumed a new length of 120.05 m when heated to a temperature 100° c​ is 4.167.10⁻¹⁶ 1/K.

What is Linear expansivity?

Linear expansivity is the ratio of the length increase of a solid specimen to the temperature change. The expansivity (α) of a specimen is given by the formula l2 = l1(1 +), where l1 is the length of the specimen, and l2 is the length of the specimen when the temperature increases by °.

The linear expansion coefficient can be written in SI units as either °C-1 or °K-1. C in this context stands for Celsius, and K for Kelvin. M0L0T0K1 will be the size of the linear expansion coefficient.

Modifying or lengthening is referred to as expansion. When one dimension (length) changes in length in relation to the volume, this is referred to as linear expansion.

When the temperature rises by one degree, a solid's linear expansivity increases by a fractional amount.

calculate the linear expansivity of brass of length 120 m ?

Assuming the temperature change is 100°C.

       α=L−L0/L0- ΔT⇒(1)  Δ Greek value is 4

Given L=120

L0=120.05

T=100°c

 substitute the given values in equation 1 we have

        α=120-120.5/120.05-4(100)

           =4.167.10⁻¹⁶ 1/K

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A car traveling 24 m/s comes to a stop in 8 seconds. What is the acceleration/deceleration?

Answers

The acceleration/deceleration is -3 m/s².

This can be calculated by using the equation a = (vf - vi) / t,

where a is the acceleration/deceleration, vf is the final velocity (in this case 0 m/s), vi is the initial velocity (in this case 24 m/s), and t is the time (in this case 8 seconds).

Plugging in the values, we get a = (-0 - 24) / 8, which simplifies to a = -3 m/s².

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What is the change in potential energy for a 61 kg diver from when she jumps off a 13m high diving board and when she first hits the water?

Answers

The change in potential energy for a 61 kg diver from when she jumps off a 13m high diving board is 7,779.33J.

How to calculate potential energy?

Potential energy in physics refers to the energy stored by an object due to its position.

The formula for potential energy depends on the force acting on the two objects. For the gravitational force, the formula is:

W = m×g×h = mgh

Where,

m is the mass in kilogramsg is the acceleration due to gravityh is the height in meters

According to this question, a diver with mass 61kg jumps off 13m high diving board. The potential energy can be calculated as follows:

W = 61 × 9.81 × 13

W = 7,779.33J

Therefore, 7,779.33J is the potential energy of the diver.

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A 2 kg box slides down a frictionless ramp starting
from a height of 3 m. The slope of the ramp is 30°,
What is the box's momentum when it reaches the
bottom of the ramp?

Answers:

A) 15.3 kg•m/s down the ramp
B) 7.7 kg.m/s down the ramp
C) 5.5 kg•m/s down the ramp
D) 2.8 kg•m/s down the ramp

Answers

The box's momentum when it reaches the bottom of the ramp  is 2.8 kg•m/s down the ramp.

What is the velocity of the box when it reaches the bottom?When the box reaches the bottom of the slope, its speed is v = (nh) n has a value. The block has gravitational potential energy when it briefly comes to rest at the top of the ramp and starts with kinetic energy at the bottom. However, some of that energy is lost due to frictional effort. You can use a free body diagram and Newton's second law to calculate the frictional force on the block. What will happen if you roll two cylinders of the same mass and diameter—one solid and one hollow—down a ramp is how this traditional physics textbook version of the problem is phrased. The solid one will eventually sink, is the solution.

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12. a) Sound waves travel at a speed of 340 m s¹ in air
at 20°C. If the frequency of these waves is 2.5 kHz,
what is their wavelength?
b) Infra-red electromagnetic waves travel at a
speed of 3.0 x 108 m s¹. Calculate the frequency of
these waves if their wavelength is 1.2 x 10-6 m.

Answers

Answer:

[tex]a)0.136m \\ b)2.5 \times 10 {}^{14} cycle \: per \: sec[/tex]

Explanation:

Greetings!!

Let's start from question a

Given values :-

speed(velocity)= 340m/s

frequency=2.5kHz

Temperature= 20°c

required values:-

wave length=?

solution:-

Firstly, recall velocity-wavelength equation

v=λf,

substitute known variables into the equation

(340)= (2500). λ

To not get confused 2500 comes when kHz is changed to Hz. (notice)

solve for wavelength

λ= 0.136m

for the second question b. also use the same procedure and the same format ( formula)

Thus, we work as

Given values:-

speed(velocity)= 3.0×10^8

wavelength=12×10^-6

required values:-

frequency=?

solution:-

Firstly, recall velocity-wavelength equation

v=λf

substitute known values into the equation

(3.0×10^8)= f(1.2×10^-6)

solve for frequency

f= 2.5× 10^14 Hz

If any questions or anything else tag me on comments.

Hope it helps!!!

a 0.52 kg football is thrown with a velocity of 15 m/s to the right. A stationary receiver catches the ball and brings it to rear in 0.017s. What is the force exerted on the receiver?

Answers

On the receiver, a force of 375 Newton was applied.

What does one newton weigh?

In the walking (English, or customary) system, one newton is equivalent to around 0.2248 pounds of force or 100,000 dynes in the centimeter-gram-second (CGS) system.

What is a force unit of newton?

The newton, abbreviated N, is the Si derived unit of force. Base units that are pertinent to force are: The symbol for the length unit of a metre is m. the kilogramme (kg), a unit of mass. s stands for the second, a unit of time.

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A tractor trailer truck with a ma of 3,000 kg i traveling at a peed of 30 m/. What i it momentum?

Answers

Answer:

90,000 kgm/s

Explanation:

Momentum is mass × velocity as accorded to the equation:

[tex] \displaystyle{ \text{P = mv}}[/tex]

Where P is momentum, m is mass and v is velocity. Everything is given in the problem, we have to find momentum, therefore:

[tex] \displaystyle{ \text{P} = 3000 \times 30} \\ \\ \displaystyle{ \text{P} = 90000 \: \text{kgm/s}}[/tex]

Therefore, momentum is 90,000 kgm/s

Which is the best way to compare speed and velocity?

A. Slowing down versus speeding up

B. Distance over time vs distance over time and direction

C. Big vs small

D. One is the hunter and one is the prey

Please help as soon ASAP!

Answers

i think the answer is b

UNIT (5) Momentum 5.D Change in Momentum DATE NAME Scenario A 10 kg box, initially at rest, moves along a smooth horizontal surface. A horizontal force is applied to the box. The magnitude of the force changes as a function of time as shouwn. Take the positive direction to be to the right. Tme (econd Data Analysis Rank the magnitude of the impulse applied to the box by the force during each 2-second interval indicated below: PART A: A. 0-2 seconds B. 24 seconds C. 4-6 seconds D.6-8 seconds E.8-10 seconds Smallest impulse Greatest impulse Write a few sentences justifying your reasoning. Use words like speed, velocity, acceleration, time, force, momentum, and impulse. PART B: Using Representations PART C: Re-represent the data given in the force vs. time graph in Part A as a momentum vs. time graph for the same 10 kg box. Step 1: Identify the equation that relates force and momentum. Step 2: How can momentum be found from a force vs. time graph? Step 3: Plot the momentum as a function of time. (Make a table if you need to.) 10Time (s) Momentum (kgm/s) Forte Newtons) 5.D Change in Momentum Quantitative Analysis Use the graph above to calculate the velocity of the box after 10 seconds. For each line in the calculation, explain what was done mathematically. The first line is done for you. Ap = mai The change in momentum is equal to the mass times the change in velocity. UNIT 5. Momentum 5.D Change in Momentum NAME DATE Scenario A 10 kg box, initially at rest, moves along a smooth horizontal surface. A horizontal force is opplied to the box. The magnitude of the force changes as a function of time as shoun. Take the positive direction to be to the right. Tme econd Data Analysis Rank the magnitude of the impulse applied to the box by the force during each 2-second interval indicated below: PART A A. 0-2 seconds B. 2-4 seconds C. 4-6 seconds D. 6-8seconds E.8-10 seconds Greatest impulse Smallest impulse Write a few sentences justifying your reasoning. Use words like speed, velocity, acceleration, time, force, momentum, and impulse. PART B: Using Representations PART C: Re-represent the data given in the force vs. time graph in Part A as a momentum vs. time graph for the same 10 kg box. Step 1: Identify the equation that relates force and momentum. Step 2 How can momentum be found from a force vs. time graph? Step 3: Plot the momentum as a funetion of time. (Make a table if you need to) 10 Time (s) | 135 Return to Table of Contents 2Categeard Momentum (kom/s) 5.D Change in Momentum Quantitative Analysis Use the graph above to calculate the velocity of the bax after 10 seconds. For each line in the calculation, explain what was done mathematically. The first line is done for you. Ap = mAi The change in momentumis equal to the mass times the change in velocity.

Answers

From the given data,

Part A: -In opposite direction Greatest impulse B>C>A>D>E smallest impulse

Part B: -increasing constantly thus acceleration is increasing resulting in increase of velocity and momentum as well.

Part C: -[tex]Force $=m$ a $[/tex] =[tex]$m \frac{\Delta v}{\Delta t}=[/tex] [tex]m$ momentum[/tex]

       [tex]F=\frac{m}{\Delta t}[/tex]

Mass of box  [tex]=10kg[/tex]

Impulse = [tex]F_{average}[/tex] At

A. 0-2 seconds

Impulse = 1.5×2 = 3N sec

B. 2-4 sec

Impulse = 3×2 = 6N sec

C. 4-6 sec

Impulse = 2.75×2 =5.5N sec

D. 6-8 sec

Impulse = 1×2 = 2N sec

E. 8-10 sec

Impulse = 1×2 = 2N sec

In opposite direction Greatest impulse B>C>A>D>E smallest impulse.

For the first two seconds force is increasing constantly thus acceleration is increasing resulting in increase of velocity and momentum as well. Now for the next three seconds a constant force is acting on the box resulting in constant acceleration. After that for the next three seconds force goes on decreasing constantly thus deacceleration and decrease of impulse and velocity. In last 2 seconds deacceleration is in opposite direction that is how box starts moving in opposite direction

[tex](1) Force $=m$ a $[/tex][tex]$=m \frac{\Delta v}{\Delta t}=[/tex][tex]m$ momentum[/tex]

             [tex]F=\frac{m}{\Delta t}[/tex]

(2) Area under the curve gives the momentum

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A force of 57. 1 newtons is applied for 0. 977 meters; what work was done on the object?(1 point).

Answers

The work was done on the object is 55.8 Joule. The result is obtained by multiplying the force by the distance.

How to find the work done on an object?

The work done on an object can be counted by the equation:

W = F × d

Where

W = Work (Joule or Nm)F = Force (Newton)d = distance (meter)

We have an object which on it applied:

Force, F = 57.1 NewtonsDistance, d = 0.977 meters

Find the word done on the object!

W = F × d

W = 57.1 Newtons × 0.977 meters

W = 55.7867 Nm

W ≈ 55.8 Joule

Hence, the work done by the force on the object is 55.8 Joule or 55.8 Nm.

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A car (1600kg) is moving at 5.0 m/s on a mountainside road. The cars elevation is 4.5 m from the valley floor. What is the cars gravitational potential energy? J​

Answers

Answer:

70,560 J

Explanation:

GPE = mgh = (1600 kg)(9.8 m/s²)(4.5 m) = 70,560 J

**GPE is independent of velocity (v)

The answer is 70,560 J.

A carton designer is considering cost as she is comparing different shaped cartons. Which of these nets would create a cardboard carton that requires the least amount of cardboard for each cubic inch of volume?.

Answers

A carton designer is considering cost as she is comparing different shaped cartons. The nets would create a cardboard carton that requires the least amount of cardboard for each cubic inch of volume is  (8 in × 10 in × 10 in). the first option is the correct answer.

Each of the containers in this image is 800 cubic inches in volume.

As a result, for every cubic inch of volume, the carton with the smallest surface area will use the least quantity of cardboard.

The surface area of a cuboid with the dimensions L, W, and H is equal to 2(LW, WH, and LH).

Now, the first cardboard choice, which has dimensions of 8 in. x 10 in. x 10 in., will have a surface area of  2(8 × 10 + 10 × 10 + 8 × 10) = 520 sq, inches.

Now, the surface area of the cardboard in the second choice, which has dimensions of 2(5 × 8 + 8 × 20 + 5 × 20) = 600 sq, inches.

Once more, the third option's cardboard, which has dimensions of 2(4 × 10 + 10 × 20 + 4 × 20) = 640 sq, inches.

Finally, the cardboard in the fourth option, which has dimensions of 2 in × 10 in × 40 in, will have surface are = 2(2× 10 + 10 × 40 + 2 × 40) = 1000 sq, inches.

Hence, the first option will be our choice

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5. 20 points !! A water wave (a mechanical wave, not an electromagnetic wave!) has a frequency of 20 Hz and a wavelength of 0.1 m. Calculate the speed of this wave.

Answers

Hope u will understand
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