Acceleration is the change in the velocity of the object with time. Acceleration is the same for both objects so both objects will reach the ground at the same time.
How do you find out the common value for both objects?Given that both the object dropped at the same time. So the gravitational acceleration of both the objects will be the same which is nearly 10 m/s.
The force at object 1 is given below.
[tex]F_1 = m_1\times g = m_1\times a_1[/tex]
Where m1 is the mass of object 1 and a1 is the acceleration of object 1.
[tex]F _1 = 1\times 10 = 10 \;\rm N[/tex]
The acceleration of object 1 is calculated as below.
[tex]a_1 = \dfrac{F_1}{m_1}[/tex]
[tex]a_1=\dfrac{10}{1} = 10 \;\rm m/s^2[/tex]
The force at object 2 is given below.
[tex]F_2 = m_2\times g = m_2\times a_2[/tex]
Where m2 is the mass of object 2 and a2 is the acceleration of object 2.
[tex]F_2 = 2\times 10 =20 \;\rm N[/tex]
The acceleration of object 2 is calculated as below.
[tex]a_2 = \dfrac{F_2}{m_2}[/tex]
[tex]a_2=\dfrac{20}{2} = 10 \;\rm m/s^2[/tex]
Hence we can conclude that the acceleration of both the objects is the same at every point so they will reach the ground at the same time.
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The word photokinetic means “moving in response to light”. Why does this make sense based on the two main parts (morphemes) in this word?
Explanation:
photo means light in latin
kinetic means to move
For a balloon to rise in the air, the lifting force
must be greater than which force: Gravity,
Normal, or Friction?
Help please
Mark brainlist
Answer:
gravity
Explanation:
A car is at velocity of 20 km/h. If the car traveled 120 km in 3 hours at constant acceleration, what is its final velocity?
A source of sound produce waves in air of wavelength 3.42m . If the speed of sound in air is 330m/s, What is the period of vibration?
Explanation:
wavelength=3.42m
velocity=330m/s
T=?
v=f×wavelength
f=330÷3.42
f=96.5Hz
T=1/f
=1/96.5
T=0.01s
I really need help on this.
Earth's rotation is crucial to understanding the Coriolis effect. The Equator is where Earth rotates more quickly than the poles. There at Equator, Earth is larger.
Equatorial areas therefore move at a speed of around 1,600 km/h (1,000 mph) in a 24-hour period to complete a revolution. Earth rotates slowly towards to the poles, at 0.00008 km/h (0.00005 mi/h).
Low-pressure systems called cyclones draw air towards their "eye" or central region. Fluids representing high-pressure systems in the Northern Hemisphere pass low-pressure regions to the right.
Air masses are deflected when they're drawn inside cyclones from across all sides, giving the appearance that a hurricane is rotating clockwise. Trade winds refer to these air masses' recurrent circulation patterns.
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Which undergoes greater acceleration: an airplane that goes from 1000 km/h to 1005 km/h in 10 seconds or a skateboard that
goes from zero to 5 km/h in 1 second?
Answer:
Skateboard
Explanation:
Acceleration is change in velocity over time.
a = Δv / Δt
The airplane's acceleration is:
a = (1005 km/h − 1000 km/h) / 10 s
a = 0.5 km/h/s
The skateboard's acceleration is:
a = (5 km/h − 0 km/h) / 1 s
a = 5 km/h/s
A 57 kg paratrooper falls through the air. How much force is pulling him down?
Answer:
Explanation:
Force = Mass * acceleration due to gravity.
Given
Mass of the paratrooper = 57kg
Acceleration due to gravity = 9.81m/s²
Required
Force pulling him down
Substitute unto formula;
F = 57 * 9.81
Force = 559.17 N
Hence the force pulling him down is 559.17N
The force pulling the paratrooper as he falls down is 558.6 N.
The given parameters;
mass of the paratrooper, m = 57 kgacceleration due to gravity, g = 9.8 m/s²The force pulling the paratrooper is force of gravity and the magnitude can be determined by applying Newton's second law of motion as shown below;
F = mg
F = 57 x 9.8
F = 558.6 N
Thus, the force pulling the paratrooper as he falls down is 558.6 N.
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Find the magnitude of the magnetic field that will cause the electron to follow the semicircular path from A to B.
Answer:
[tex]B=1.61\times 10^{-4}\ T[/tex]
Explanation:
The attached figure shows the path followed by an electron in the semicircular path from A to B.
Velocity of the electron is, [tex]v=1.42\times 10^6\ m/s[/tex]
It can be seen from the figure that the radius of thenpath, r = 5 cm or 0.05 m
The magnetic force acting on the electron is balanced by the centripetal force acting on it. It means,
[tex]Bqv=\dfrac{mv^2}{r}[/tex]
B is the magnitude of the magnetic field
[tex]B=\dfrac{mv}{rq}\\\\\text{Putting all the values}\\\\B=\dfrac{9.1\times 10^{-31}\times 1.42\times 10^6}{0.05\times 1.6\times 10^{-19}}\\\\B=1.61\times 10^{-4}\ T[/tex]
So, the magnitude of the magnetic field is [tex]1.61\times 10^{-4}\ T[/tex].
The magnitude of the magnetic field that will cause the electron to follow the semicircular path from A to B will be [tex]B=1.61\times 10^-{4]\ T[/tex]
What is magnetic field?The magnetic field is defined as when the current passes through the wire, then the magnetic field is generated around the wire in a circular pattern.
The attached figure shows the path followed by an electron in the semicircular path from A to B.
The velocity of the electron is, [tex]v=1.42\times 10^6\ \frac{m}{s}[/tex]
It can be seen from the figure that the radius of then path, r = 5 cm or 0.05 m
The magnetic force acting on the electron is balanced by the centripetal force acting on it. It means,
[tex]Bqv=\dfrac{mv^2}{r}[/tex]
B is the magnitude of the magnetic field
[tex]B=\dfrac{mv}{rq}[/tex]
[tex]B=\dfrac{9.1\times 10^{-31}\times1.42\times 10^6}{0.05\times 1.6\times 10^{-19}}[/tex]
[tex]B=1.61\times 10^{-4}\ T[/tex]
So, the magnitude of the magnetic field is [tex]B=1.61\times 10^-{4]\ T[/tex]
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I’ve been stuck on this question, what’s the answer to this question?
Explanation:
[tex]\sf{H_2CO_3 + NaOH \longrightarrow NA_2CO_3 + H_2O}[/tex]
Where [tex]\sf{H_2CO_3 }[/tex] is Carbonic AcidWhere [tex]\sf{ NaOH }[/tex] is Sodium HydroxideReaction gives out [tex]\sf{ NA_2CO_3 + H_2O}[/tex]Where [tex]\sf{ NA_2CO_3 }[/tex] is Sodium HydroxideAnd [tex]\sf{ H_2O}[/tex] is water.So, [tex]\sf{ NA_2CO_3 }[/tex] Sodium Carbonate is the answer.
Hope it helps :)
Question 11(Multiple Choice Worth 3 points)
(01.01 LC)
Which of the following actions will decrease the gravitational force between two objects?
o
Increasing the mass of the objects
d
Increasing the density of the objects
O
Increasing the distiyance between the objects
Increasing the temperature of the objects
Answer:
Explanation:
The only thing that decreases the gravitational pull between 2 objects is if you increase the distance.
The formula is F = G*m*m/r^2
As r^2 gets larger and G and m1 and m2 remain the same, F has to get smaller because r^2 divides into G*m1*m2
What is an antibody and what does it do?
an antibody is a blood protein produced in response to and counteracting a specific antigen. Antibodies combine chemically with substances which the body recognizes as alien, such as bacteria, viruses, and foreign substances in the blood.
Antibodies are proteins that help fight off infections and can provide protection against getting that disease again (immunity). Antibodies are disease specific.
Who? What? Where? When? Why?
Which of the following is the primary force that shapes the Earth's landscape?
To increase muscular strength the number of reputation should be?
A high
B light
C heavy
D low
increase muscular endurance the number of repetitions should be?
A high
B light
C heavy
D low
To increase muscular endurance the weight being lifted should be?
A high
B light
C heavy
D low
to increase muscular strength the weight being lifted should be?
A high
B light
C heavy
D low
Answer:
Explanation:
heavyy
Explain why the interconnection is not valid. Explain why the interconnection is not valid. A valid interconnection would require the 3 AA and 4 AA sources to supply different currents in the same direction, which they do not. A valid interconnection would require the 3 AA and 4 AA sources to supply different currents in opposite directions, which they do not. A valid interconnection would require the 3 AA and 4 AA sources to supply the same current in opposite directions, which they do not. A valid interconnection would require the 3 AA and 4 AA sources to supply the same current in the same direction, which they do not.
Complete Question
The diagram for this question is shown on the first uploaded image
Explain why the interconnection is not valid.
i A valid interconnection would require the 3 A and 4 A sources to supply different currents in the same direction, which they do not.
ii A valid interconnection would require the 3 A and 4 A sources to supply different currents in opposite directions, which they do not.
iii A valid interconnection would require the 3 A and 4 A sources to supply the same current in opposite directions, which they do not.
iv A valid interconnection would require the 3 A and 4 A sources to supply the same current in the same direction, which they do not
Answer:
The correct option is iv
Explanation:
Looking at the diagram we see that the current source are connected in series, generally the current flowing through two source that are connected in series is suppose to be the same but in this case it is not so
i.e [tex]4A \ne 3 A[/tex] hence Kirchhoff's law is broken or not followed in this circuit which means the interconnection is not valid
also another reason why the interconnection is not valid is because the current are flowing in the different directions
What happens when light hits a transparent material like water or glass? What is
the phenomenon called?
HELP
A net force of 500 newtons causes
an object to accelerate at a rate of
5.0 m/s2. What is the mass of the
object?
A - 100 kg
B - .20kg
C - 600 kg
D - 2500 kg
Answer:
The answer is option AExplanation:
To find the mass of an object given it's acceleration and the force acting on it we use the formula
[tex]mass = \frac{force}{acceleration} \\ [/tex]
From the question
force = 500 N
acceleration = 5.0 m/s²
We have
[tex]mass = \frac{500}{5} \\ [/tex]
We have the final answer as
100 kgHope this helps you
Doctors were furious. Their patients didn't care about regular medicine anymore. All they wanted was a wave of Dr. Mesmer's wand. The doctors griped — and groused — and fussed — and fumed. What is most likely the meaning of the word furious?
A quietly curious B quite thrilled C mildly annoyed D extremely angry
Answer:
am pretty sure the answer is d
A man runs 400.0m around the track,
then another 400.0m around the track again.
As the track is 400.Om long, the man is back
where he started!
a) calculate distance travelled
b) calculate mans displacement
Answer:
Distance = 800 m, Displacement = 0
Explanation:
It is given that,
A man runs 400 m around the track, then another 400 m around the track again.
(a) Distance travelled by an object is the sum of total path covered.
In this case, he has covered total path of 400 m + 400 m i.e. 800 m. It means he travelled a distance of 800 m.
(b) Displacement covered by an object is the shortest path covered by it. In this problem, he reaches the point from where he has started. It means that his displacement is equal to 0.
If a drag racing car accelerated at 69 miles per second in 0.25 s, what is the acceleration of the car
Answer:
acceleration is : 276 mi/s^2
(276 miles per second squared)
Explanation:
We use the formula for acceleration (a) which is the change in velocity divided by the time it took to change it:
a = (vf - vi) / t
where "vf" stands for final velocity, "vi" for initial velocity, and "t" for the time it took for the velocity to change.
In our case:
a = (69 - 0) / 0.25 = 276 mi/s^2
(276 miles per second squared)
Which is the correct answer? Please help.
Answer:
i believe it is c
Explanation:
hope this helps and plz mark brainliest
How does energy from the sun travel to earth .
Answer:
through uv light
If this piece of abductin is 3.1 mm thick and has a cross-sectional area of 0.49 cm2 , how much potential energy does it store when compressed 1.5 mm ?
Complete question:
A scallop forces open its shell with an elastic material called abductin, whose Young's modulus is about 2.0×10⁶ N/m2 .
If this piece of abductin is 3.1 mm thick and has a cross-sectional area of 0.49 cm2 , how much potential energy does it store when compressed 1.5 mm ?
Answer:
The elastic potential energy of the material is 0.036 J
Explanation:
Given;
Young's modulus, E = 2.0×10⁶ N/m²
Thickness of the abductin, l = 3.1 mm = 0.0031 m
compression of the abductin, x = 1.5 mm = 0.0015 m
area, A = 0.49 cm² = 0.49 x 10⁻⁴ m²
Young's modulus for elastic material is given by;
[tex]E = \frac{stress}{strain} = \frac{Fl}{Ax} \\\\ E = \frac{F}{x}*\frac{l}{A}\\\\ E = k*\frac{l}{A}\\\\k = \frac{AE}{l}\\\\k = \frac{(0.49 x10^{-4})(2*10^6)}{0.0031}\\\\ k = 31,612.9 \ N/m[/tex]
The elastic potential energy of the material is given by;
U = ¹/₂kx²
U = ¹/₂(31,612.9)(0.0015)²
U = 0.036 J
Therefore, the elastic potential energy of the material is 0.036 J
The effect wind has on an airplane can be modeled by using a wind tunnel. What is one limitation of this model
Answer:
The limitations of this this model is the amount of wind being blown to effect the airplane.
Answer: Highly skilled workers are necessary to run the wind tunnel.
Explanation: I took the quiz on A pex.
A
A penny is dropped from the top of a 200 m building and is in free fall. How long will it take
the penny to hit the ground?
Answer:
The penny will hit the ground at 6.39 seconds
Explanation:
Free Fall
The penny is dropped from a height of y=200 m. The equation of the height on a free-fall motion is given by:
[tex]\displaystyle y=\frac{gt^2}{2}[/tex]
Where [tex]g=9.8\ m/s^2[/tex], and t is the time.
Solving for t:
[tex]\displaystyle t=\sqrt{\frac{2y}{g}}[/tex]
Using the value y=200:
[tex]\displaystyle t=\sqrt{\frac{2*200}{9.8}}[/tex]
t=6.39 sec
The penny will hit the ground at 6.39 seconds
A child (mass Me) pulls a sled (mass Ms) holding a baby (mass m) across the snow (assume the snow is frictionless). When the child starts the sled moving the baby brother slips off the sled instead of moving with the sled. The child tries again with a slightly smaller force and the baby stays on the sled due to the friction between the baby and the sled. Write a symbolic solution for the coefficient offriction between the baby and the sled if the maximum acceleration ofthe sled for the baby to stay on the sled is a. The solution may include the variables MC: Ms, m: a and g but does not need to have all ofthem_ The computer Ivill not recognize any other variables. Do not include any numbers (or the in your answer). Fill in the blank
Answer:
symbolic solution for the coefficient of friction between the baby and the sled is
[tex] \mu = \frac{m + M_s}{m} * \frac{a}{g}[/tex]
Explanation:
From the question we are told that
The mass of the boy is [tex]M_e =[/tex]
The mass of the shed is [tex]M_s[/tex]
The mass of the baby is [tex]m[/tex]
The maximum acceleration for the baby to stay is a
Generally the frictional force between the baby and the shed is mathematically represented as
[tex]F_f = \mu N[/tex]
Here N is the normal force acting on the baby which is mathematically represented as
[tex]N = m * g[/tex]
=> [tex]F_f = \mu * m * g[/tex]
Now for the baby not the slip off the shed the frictional force between the baby and the shed must be equal to the the force applied by the child
The force applied by the child is mathematically represented as
[tex]F = [M_s+m] * a[/tex]
So
[tex] \mu * m * g = [M_s+m] * a[/tex]
=> [tex] \mu = \frac{m + M_s}{m} * \frac{a}{g}[/tex]
Dillon wants to go to the park to play basketball. To get to the park, he must travel 9 km East, and then 6 km South, then 9 Km West. Calculate the distance
Answer:
24 km
Explanation:
9 + 9 + 6 = 24
when are two magnets attracted?
Answer:
when the negative and positive energy is connected
Explanation:
Which of the following represents an example of thermal energy?
O a
Saxophone
Ob
Oven
с
Powerlines
Od
Windmill
Answer:
The answer of this question is windmill
A automotive test driver travels due north in a prototype hybrid vehicle at 30 mi/h
for 2 hours. She then reverses her direction and travels due south at 60 mi/h for 1 hour.
What is the average speed of the vehicle?
a) 40 mi/h
b) 50 mi/h
c) zero mi/h
d) 60 mi/h
e) 30 mi/h
Answer:
Option A. 40 mi/h
Explanation:
To obtain the average speed of the vehicle, we'll begin by calculating the distance travelled by the vehicle in each case. This is illustrated below:
Case 1:
Speed = 30 mi/h
Time = 2 h
Distance =...?
Speed = Distance /Time
30 = Distance /2
Cross multiply
Distance = 30 × 2
Distance = 60 mi
Case 2:
Speed = 60 mi/h
Time = 1 h
Distance =...?
Speed = Distance /Time
60 = Distance /1
Cross multiply
Distance = 60 × 1
Distance = 60 mi
Finally, we shall determine the average speed of the vehicle as follow:
Total distance travelled = 60 + 60
Total distance travelled = 120 mi
Total time = 2 + 1
Total time = 3 h
Average speed =..?
Average speed = Total Distance travelled /Total time
Average speed = 120/3
Average speed = 40 mi/h
Therefore, the average speed of the vehicle is 40 mi/h