A 0.700 g unknown mixture with CaCl2 reacts with aqueous sodium phosphate to give 0.425 g Ca3(PO4)2. Show calculation for the percentage CaCl2?

Answer:

Explanation:

The acceleration of gravity of an object given it's mass and the force acting on it can be found by using the formula

[tex]a = \frac{f}{m} \\ [/tex]

f is the force

m is the mass

From the question we have

[tex]a = \frac{800}{75} = \frac{32}{3} \\ = 10.666666...[/tex]

We have the final answer as

Hope this helps you

Answer:

The answer is "152.28%".

Explanation:

Formula for ideal gas:

PV=nRT

equation:

[tex]\to (P+\frac{an^2}{v^2})(v-nb)=nRT \\\\a=2.253 \frac{L^2 atm}{mol^2}\\\\b=4.278 \times 10^{-2} \frac{L}{mol}\\\\n=10.68 \ mol\\\\v= 0.8295 \ L\\\\\to (P+\frac{an^2}{v^2})= \frac{nRT}{(v-nb)}\\\\\to (P)= \frac{nRT}{(v-nb)} - \frac{an^2}{v^2} \\\\[/tex]

          [tex]= \frac{10.68 \times 0.0082 \times 501.9}{0.8295 - (10.68 \times 4.278 \times 10^{-2})} - \frac{2.253 \times 10.68^2}{0.8295^2}\\\\=\frac{43.9543944}{0.4568904} - \frac{256.982587}{0.68807025}\\\\ = 96.2033661- 373.483067\\\\=-277.279701 \\\\ =-277.279701 \ atm[/tex]

The pressure of gas:

[tex]= (530.3 + 277.279701) \ atm\\\\= 807.579701 \ atm \\\\[/tex]

Calculating the pressure percentage:

[tex]=\frac{807.579701}{530.3} \times 100\\\\= 152.28 \%[/tex]

Answer:

48 hours

Explanation:

Because if the world would spin regularly, then it would take 24 hours. But if it spins half as fast, then it would be 2x more.

Heat required : 1.523 kJ

Reaction

N₂+2O₂⇒2NO₂ AH = 67.7 kJ

mol of N₂:(use Pv=nRT)

[tex]\tt n=\dfrac{3.32\times 0.304}{0.082\times 373}=0.033[/tex]

mol of O₂:

[tex]\tt n=\dfrac{3.32\times 0.41}{0.082\times 373}=0.045[/tex]

Limiting reactant :

N₂ : O₂

[tex]\tt \dfrac{0.033}{1}\div \dfrac{0.045}{2}=0.033:0.0225[/tex]

Limiting reactant : O₂(smaller ratio)

mol NO₂ = mol O₂ = 0.045

2 mol ⇒ 67.7 kJ, so for 0.045 mol, heat required :

[tex]\tt \dfrac{0.045}{2}\times 67.7=1.523~kJ[/tex]

The heat required to produce the maximum yield of NO2 is 1.52 kJ.

The balanced reaction equation is;

N2(g) + 2 O2(g) -> 2 NO2(g)

The number of moles of each gas is obtained from the ideal gas equation as follows;

For N2;

P = 3.32 atm

V = 304 ml or 0.304 L

T = 100ºC + 273 = 373 K

n = ?

R = 0.082 atmLK-1mol-1

From;

PV = nRT

n = PV/RT

n = 3.32 atm × 0.304 L/0.082 atmLK-1mol-1 × 373 K

n = 0.033 moles

For O2;

PV = nRT

n =  PV/RT

V = 410 ml or 0.410 L

P = 3.32 atm

R = 0.082 atmLK-1mol-1

T = 100°C + 273 = 373 K

n =  3.32 atm × 0.410 L/0.082 atmLK-1mol-1 × 373 K

n = 0.045 moles

1 mole of N2 reacts with 2 moles of O2

0.033 moles of N2 reacts with 0.033 moles × 2 moles/1 mole

= 0.066 moles

2 moles of O2 yields 2 moles of NO2

0.045 moles O2 yields 0.045 moles × 2 moles/2 moles = 0.045 moles

If 2 mole of NO2 requires 67.7 kJ

0.045 moles of NO2 requires 0.045 moles  × 67.7 kJ/2 mole

= 1.52 kJ

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Answer:

Explanation:

Wavelength (λ) = speed/frequency

(λ) = c/f

Where;

c = speed (3× 10^8m/s)

f = frequency (Hz)

(

Answer:

The major jet streams on Earth are westerly winds that flow west to east.

Answer:

Electronegativity  = 1.87.

Ionic radius = 109 pm.

Atomic radius = -39 pm

First ionization energy = 410 kJ/mol

Explanation:

Hello!

In this case, since electronegativity, ionic radius, atomic radius and first ionization energy are periodic properties that have specific trends, we can summarize it by realizing that oxygen and beryllium belong the same period 2 and differ in group, 6A and 2A respectively.

In such a way, the required comparison is written below:

Electronegativity = 3.44 (oxygen) - 1.57 (beryllium) = 1.87.

Ionic radius = 140 pm (oxygen)- 31 pm (beryllium) = 109.

Atomic radius = 73 pm (oxygen) - 112 pm (beryllium) = -39 pm

First ionization energy = 1310 kJ/mol (oxygen) - 900 kJ/mol (beryllium) = 410 kJ/mol

It means that electronegativity, ionic radius and first ionization energy increases from left to right whereas the atomic radius from right to left.

Best regards!

Oxygen and Beryllium are the elements that pertain to the same period and different groups 6A and 2A.

Ionic radius, atomic radius, electronegativity and first ionization energy are periodic qualities that have selective trends.

Differences in the trends are:

This can be explained as:

= 140 pm (oxygen)- 31 pm (beryllium)

= 109.

= 73 pm (oxygen) - 112 pm (beryllium)

= -39 pm

= 3.44 (oxygen) - 1.57 (beryllium)

= 1.87

= 1310 kJ/mol (oxygen) - 900 kJ/mol (beryllium)

= 410 kJ/mol

Therefore, these data tell that ionic radius, electronegativity and first ionization energy increases from left to right in a period whereas, the atomic radius increases from right to left in a period.

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Answer:

D. A reaction or change in a substance that results in a different substance

Explanation:

Chemical changes occur when a substance combines with another to form a new substance, called chemical synthesis or, alternatively, chemical decomposition into two or more different substances.

Answer:

The mass of Na₂O that can be produced by the chemical reaction of 4.0 grams of sodium with excess oxygen in the reaction is 5.39 grams.

Explanation:

You know  the balanced reaction:

4 NA + O₂ ⟶ 2 Na₂O

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) react and are produced:

Being:

the molar mass of the compounds participating in the reaction is:

Then by stoichiometry of the reaction they react and are produced:

Then you can apply the following rule of three: if 92 grams of Na produce 124 grams of Na₂O, 4 grams of Na, how much mass of Na₂O does it produce?

[tex]massofNa_{2}O =\frac{4 grams of Na*124 gramsofNa_{2}O }{92 grams of Na}[/tex]

mass of Na₂O=5.39 g

The mass of Na₂O that can be produced by the chemical reaction of 4.0 grams of sodium with excess oxygen in the reaction is 5.39 grams.

Answer:

The correct answer is 0.089 g/L ≅ 0.09 g/L

Explanation:

Density is defined as: mass/volume.

From the problem we have:

number of moles = n = 3 mol

volume = V = 67.20 L

We have to calculate the mass. For this, we need the molar mass (MM) of the gas. That is easily calculated from the molar mass of the element hydrogen (H), as we know that hydrogen gas has the molecular formula H₂:

MM(H₂) = 2 x molar mass H = 2 x 1 g/mol = 2 g/mol

Now, we multiply n by MM to obtain the mass (m) of the gas:

m = n x MM(H₂) = 3 mol x 2 g/mol = 6 g

Finally, we calculate the density from the mass and volume:

density = m/V = 6 g/(67.20) = 0.089 g/L ≅ 0.09 g/L

A. Breaking a Cl-Br bond

Answer:

NaBr + Cl2 = NaCl + Br2 - Chemical Equation Balancer.

Explanation:

Answer:

The correct answer is 5.6 × 10⁻²³ M.

Explanation:

As a highly soluble salt, KBr dissolves easily in water, while Hg₂Br₂ is very less soluble in comparison to KBr.

Let the solubility of Hg₂Br₂ is S mol per liter.

Therefore,

KBr (s) (1.0 M) ⇒ K⁺ (aq) (1M) + Br⁻ (aq) (1M)

Hg₂Br₂ (s) (1-S) ⇔ Hg₂⁺ (aq) (S) + 2Br⁻ (aq) (2S)

Net [Br-] = (2S + 1) M

Ksp = S (2S + 1)²

Ksp = S (4S² + 1 + 4S)

Ksp = 4S³ + S + 4S²

As the solubility is extremely less, therefore, we can ignore S² and S³. Now,

Ksp = S = 5.6 × 10⁻²³ M

Hence, the solubility of Hg₂Br₂ is 5.6 × 10⁻²³ M.

Answer:

No It cannot.

Explanation:

A water cycle does not have an end as it moves all around the earth

The process:

A water cycle can start by water evaporating through the sun's heat from a water bed, such as: Ocean, sea, pond etc.

The heat from the sun will turn the water into water vapour and will go up into the atmosphere.

The water vapor gets together with other vapors and forms clouds.

These clouds will move around the earth, once they are so full of water they drop the water to Earth in some form of precipitation. It could be rain, snow, sleet, or hail.

These water will form ponds or go back in the ocean and the process wil repeat again.

Answer:

Volume V2 = 948.13 ml

Explanation:

Given:

Volume V1 = 525 ml

Temperature T1 = -25°C + 273.15

Volume V2 = ?

Temperature T1 = 175°C + 273.15

Computation:

V1 / T1 = V2 / T2

525 / [-25°C + 273.15] = V2 / [175°C + 273.15]

Volume V2 = 948.13 ml

The new volume, in milliliters, of the gas is 948 L

From the question,

We are to determine the new volume of the gas.

From Charles' law which states that the volume of a fixed mass of gas is directly proportional to the temperature (in Kelvin) provided that the pressure remains constant.

That is,

V ∝ T

Then,

V = kT

Therefore, we can write that

[tex]\frac{V_{1} }{T_{1}} = \frac{V_{2}}{T_{2}}[/tex]

Where [tex]V_{1}[/tex] is the initial volume

[tex]T_{1}[/tex] is the initial temperature

[tex]V_{2}[/tex] is the final volume

and [tex]T_{2}[/tex] is the final temperature

From the given information,

[tex]V_{1} = 525 \ mL[/tex]

[tex]T_{1} = -25 ^{\circ}C = -25 + 273.15 \ K = 248.15 \ K[/tex]

[tex]T_{2} = 175 ^{\circ} C = 175 +273.15 \ K =448.15 \ K[/tex]

Putting the values into the formula, we get

[tex]\frac{525}{248.15} = \frac{V_{2} }{448.15}[/tex]

∴ [tex]V_{2} = \frac{525 \times 448.15}{248.15}[/tex]

[tex]V_{2} = \frac{235278.75}{248.15}[/tex]

[tex]V_{2} = 948.13 \ L[/tex]

V₂ ≅ 948 L

Hence, the new volume, in milliliters, of the gas is 948 L

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Answer:

What do you need help with?

Explanation:

Answer: 0.006 km

Explanation:

divide the length value by 1000

so 6/1000 = 0.006

Answer:

2Ag⁺ (aq)  + CrO₄⁻² (aq) ⇄  Ag₂CrO₄ (s) ↓

Ksp = [2s]²  . [s] → 4s³

Explanation:

Ag₂CrO₄ → 2Ag⁺  + CrO₄⁻²

Chromate silver is a ionic salt that can be dissociated. When we have a mixture of both ions, we can produce the salt which is a precipitated.

2Ag⁺ (aq)  + CrO₄⁻² (aq) ⇄  Ag₂CrO₄ (s) ↓ Ksp

That's the expression for the precipitation equilibrium.

To determine the solubility product expression, we work with the Ksp

Ag₂CrO₄ (s)  ⇄ 2Ag⁺ (aq)  + CrO₄⁻² (aq)   Ksp

                          2 s                 s

Look the stoichiometry is 1:2, between the salt and the silver.

Ksp = [2s]²  . [s] → 4s³

Answer:

b

Explanation:

b

At STP 32 g of O₂ would occupy by the same volume as  4 g of He

Complete question

At STP 32 g of O₂ would occupy by the same volume as:

Standard Conditions

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.

So the gas will have the same volume if the number of moles is the same

mol of 32 grams of O₂ :

[tex]\tt \dfrac{32}{32}=1[/tex]

[tex]\tt mol=\dfrac{4}{4}=1[/tex]

[tex]\tt mol=\dfrac{8}{16}=0.5[/tex]

[tex]\tt mol=\dfrac{64}{2}=32[/tex]

[tex]\tt mol=\dfrac{32}{64}=0.5[/tex]

So mol of 4 g He = mol of 32 g O₂

STP is the standard temperature and pressure of the gas to compare with the experimental data. At STP 32 gm of oxygen is equivalent to 4 gm of helium.

STP is the standard temperature and pressure of 0 degrees Celsius and 1 atm. At this temperature and pressure, the volume of the gas is 22.4 L/mol.

So, if the moles of the 32 gm oxygen are the same as the other element then the volume will also be the same. Here, the moles of oxygen are 1 mol.

Moles of 4 gm helium is 1, 8 gm methane is 0.5 mol, 64 gm dihydrogen is 32 mol, and 32 gm sulfur dioxide is 0.5 mol.

Therefore, the mole of 4 gm helium is equivalent to the mole of 32 gm oxygen.

Learn more about STP here:

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Answer:

True

Explanation:

Answer:

49.4 cal

Explanation:

Step 1: Given data

Composition of 1 cup of watermelon: 0.9 g protein, 0.2 g fat, and 11 g carbohydrate.

Step 2: Calculate the calories provided by 0.9 g of protein

1 g of protein yields 4 cal.

0.9 g × (4 cal/1 g) = 3.6 cal

Step 3: Calculate the calories provided by 0.2 g of fat

1 g of fat yields 9 cal.

0.2 g × (9 cal/1 g) = 1.8 cal

Step 4: Calculate the calories provided by 11 g of carbohydrate

1 g of carbohydrate yields 4 cal.

11 g × (4 cal/1 g) = 44 cal

Step 5: Calculate the total number of calories

3.6 cal + 1.8 cal + 44 cal = 49.4 cal

2-methyl-butanamide hydrolysis with NaOH forms a carboxyllic acid, sodiun salt of 2-methyl butanoic acid and ammonia

Explanation:

Answer:

I think it’s chlorine (Cl)

Explanation:

I’m literally doing the same question right now

The specific heat of metal = 0.897 J/g° C  

Heat absorbed can be calculated using the formula:  

Q = heat, J  

m = mass, g  

c = specific heat, joules / g ° C  

∆T = temperature difference, ° C / K  

Q = 8.793 J

m = 2 g

∆t = 4.9 °C

[tex]\tt c=\dfrac{Q}{m.\Delta t}\\\\c=\dfrac{8.793}{2\times 4.9}\\\\c=0.897~J/g^oC[/tex]

Answer:

A

Explanation:

liquids thake the shape of what holds them so shape is changing and volume is the same

Answer:1 mol

Explanation:

the conversion from mol to volume of gas at STP is 22.4L, meaning that the amount of mols in a gas of volume 22.4L at STP is one mol.

(7th grader sorry if its wrong)