Answer:
I = 138.75N*s
Explanation:
I = F*t
I = Impulse or momentum
t = Time or duration
F = Force
I = 18,500N*0.0075s
I = 138.75N*s
A 2kg water balloon is flying at a rate of 4m/s^2. With what force will it hit its target?
Explanation:
F=m×a
m=2kg
a=4m/s^2
F=2kg×4m/s^2
F=8N
A 2 kg water balloon is flying at a rate of 4 m/s². Force with which balloon will hit its target is 8 Newton.
What is force?A force is a push or pull upon an object resulting from the object's interaction with another object. Whenever there is body with some mass than there is force.
Given in the question mass and acceleration of balloon, force is given as
F = m*a
m = 2 kg
a = 4 m/s²
F = 2 kg×4 m/s²
F = 8 N
A 2 kg water balloon is flying at a rate of 4 m/s². Force with which balloon will hit its target is 8 Newton.
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Waves can be refracted.
Explain this term.
HELP PLSSS
Answer: By "waves can be refracted" they mean that refraction can occur with waves. To better explain, refraction is the "change in direction of a wave passing from one medium to another or from a gradual change in the medium." You probably know this best when you put a pencil inside a glass of water where the pencil bends a bit. The same can happen with sound or water waves as well!
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I need help quickly pls
Answer:
Ok I'm not 100% on this one but, try 3 lifes sorry if u get it wrong D:
Explanation:
easy one - giving brainly if correct.
Gas.
HOPE YOU GET 100!
Which of the following is NOT an indicator of a chemical reaction?
OPTIONS
A. A phase change
B. A temperature change
C. A color change
D. A gas being created
Answer:
c
Explanation:
The changing of color of a substance is not necessarily an indicator of a chemical change. For example, changing the color of a metal does not change its physical properties. However, in a chemical reaction, a color change is usually an indicator that a reaction is occurring.
I need help in question 7, a and b.
Answer:
The graph for 7a is shown in the attachment. For question 7b she walks a distance of 16 meters. (m)
Explanation:
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Imagine that a car is speeding down the highway and it hits a large bump in the road that forces it off the road. What would Newton call that object?
A.
a physical object
B.
a course interrupter
C.
an unbalanced force
D.
an unfortunate event
PLEASE NO LINKS OR I WILL REPORT YOU
Answer:
C. unbalanced force
Explanation:
it is called unbalanced force because it has changed direction of the moving object
sports photographers often use large aperture, long focal length lenses. what limitations do these lenses impose on the photographs?
Answer:
The depth of focus achievable with those lenses is small.
Explanation:
A larger aperture makes it much harder to focus on more than one object. When using a telephoto lens (the ones the question is referring to), the depth of focus is very small. For example, using a telephoto lens to take a photo of a runner might get the runner in focus, but certainly not the track, or the audience behind them. If you look at photos, especially older photos, of Olympians in almost any sport you can see this.
Hope this helps!
what kind of frog species is this
Answer: i think its a bullfrog forgive me if im wrong i dont exactly know
Explanation:
Answer:
that is an African bullfrog
Help me quickly! please!!!
A cable pulls a car up a mountain with a force of 4 × 103 N at a vertical constant velocity of 5 m.s-1. It takes 5 minutes to reach the top.
(a)How much work is done in getting the car to the top?
(b)How much work would have been done if the vertical speed was 2,5 m.s-1?
(c)Calculate the power exerted on the cable car in those 5 minutes.
Answer:
(a) 6,000,000J
(b) 3,000,000J
(c) For A 20,000W
But for B 10,000W
The work done in getting the car to the top is equal to 6 ×10⁶ J. If the vertical speed is 2.5 m/s then, the work done will be 3 ×10⁶ J. The power exerted on the car is in 5 minutes is 20000 J/s.
What is work done ?In physics, work done is the dot product of force and displacement. Let w be the work done and F and ds be the force and displacement. Then
W = F.ds
It is given that the, the force of the cable is 4 × 10³ N. The velocity is 5 m/s and time is 5 minutes or 300 seconds. Now, the displacement is the product of time and velocity.
ds = velocity × time
= 300 s × 5 m/s
= 1500 m.
Thus the work done = F × ds
= 4 × 10³ N × 1500 m
= 6 ×10⁶ J .
If the velocity is reduced to half 2.5 m/s , then work done will be reduced to half as 3 ×10⁶ J.
Power is the rate of work done. Thus it is the ratio of work done to time. The power exerted on the car in 5 minutes = 6 ×10⁶ J /300s
= 20000 J/s
Hence, the power exerted on the cable car in 5 minutes is 20000 J/s.
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Walter has a paper due on a novel that he has not read. He knows that his teacher will expect detailed references to the novel in his paper. He is thinking that he can listen to it while he is lifting weights and multi-task. What is the BEST response to Walter?
A.
He does not really need to concentrate on exercise, so it is fine.
B.
He would be better off focusing on his workout and then turning to the novel.
C.
If he is doing a type of exercise that allows him to stop and take notes, it is fine.
D.
Doing as many tasks as possible is generally a good idea and promotes efficiency.
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Answer:
I'm no expert, but multitasking is a no bueno. Because multitasking reduces your efficiency and performance because your brain can only focus on one thing at a time. When you try to do two things at once, your brain lacks the capacity to perform both tasks successfully.
Therefore I would choose A, considering he could easily workout another time, whilst the test is a one time thing. He can't redo the test, but he can workout again. So my answer is A.
If he HAS to workout and study at the same time, then C would be appropriate.
I hope this helps!
Please give an answer that is coherent
A ceiling fan operates at three speeds, using 120 V of electricity from the wall. At low speeds, it uses 0.25 A. Calculate the resistance needed to generate that current. Then in 1-2 sentences, describe how the resistance would change at medium and high speeds if larger currents are needed at those speeds. Your answer should include the calculated resistance and a sentence describing your reasoning.
Answer:
480
Explanation:
resistance equals to potential difference divide by electric current
120÷0.25
=480
Answer:
[tex]\mathsf {480 \Omega}[/tex]
Explanation:
[tex]\textsf {Formula used for calculating resistance :}[/tex]
[tex]\mathsf {Resistance = \frac{Voltage}{Current} }[/tex]
[tex]\textsf {This is otherwise known as Ohm's Law, hence the unit of resistance.}\\[/tex]
[tex]\textsf {Solving :}[/tex]
[tex]\implies \mathsf {R = \frac{120}{0.25}}[/tex]
[tex]\implies \mathsf {R = 480\Omega}[/tex]
[tex]\textsf{If the fan uses higher current at higher speeds, then}\\\textsf{the resistance would decrease as it is inversely}\\\textsf {proportional to the current.}[/tex]
When is there no atmospheric pressure pjysics.
What type of watches are used nowadays to measure time? Explain one of
them?
Answer:
Furthermore, some modern watches (like smart watches) even incorporate calculators, GPS and Bluetooth technology or have heart-rate monitoring capabilities, and some of them use radio clock technology to regularly correct the time. Most watches that are used mainly for timekeeping have quartz movements.
Explanation:
what third force must be added to the two forces 30 Newton at 30 degree and 80 Newton at 135 degree the resolution for equal to zero
Answer:
Resolve the vectors:
F1 = 30 cos 30 i + 30 sin 30 j = 26 i + 15 j
F2 = 80 cos 135 i + 80 sin 135 j = -56.6 i + 56,6 j
F1 + F2 = (26 - 56.6) i + (15 + 56.6) j = -30.6 i + 71.6 j
The offsetting force would be
F3 = 30.6 i - 71.6 j
The magnitude of this vector is (30.6^2 + 71.6^2)^1/2 = 77.9
cos theta 3 = 30.6 / 77.9 = 66.9 deg
Check:
77.9 * sin 66.9 = 71.6 agreeing in magnitude with F3
Now we need the quadrant of the offsetting vector
sin theta 3 = - cos theta 3 = +
This occurs in the fourth quadrant and theta 3 = 360 - 66.9 = 293.1 deg
Please I need help fast <3
Answer:
Where is the picture send again please
Explanation:
Change.
Wax melting is an example of a chemical reaction.
True or false
An ice skater at rest on ice catches a dance partner moving 1.5 m/s during a performance. The ice skater has a mass of 75 kg and the dance partner has a mass of 50 kg. What is the speed of the ice skater and dance partner after the collision?
What is the given formula for acceleration?.
Answer:
a=v/t (searched)
Explanation:
a=acceleration
v=change in velocity
t=time
(searched)
If 40 N force is exerted by a box covering 2 metre square area, calculate pressure.
[tex]\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}[/tex]
[tex]\\ \sf\longmapsto Pressure=\dfrac{40}{2}[/tex]
[tex]\\ \sf\longmapsto Pressure=20Pa[/tex]
[tex] \sf \huge \red {\dag} Given[/tex]
[tex]\sf \longmapsto \: Force \: = 40 \: Newtons[/tex]
[tex]\sf \longmapsto \: Area \: = \: 2m \: Square \: ( {2m}^{2} )[/tex]
We know that the formula of Pressure is
[tex]\sf \longmapsto \: Force/Area[/tex]
Let's start.
Put the values[tex]\sf \longmapsto \: \: P = 40 \: newtons(force)/2(Area)[/tex]
[tex]\sf \longmapsto Pressure \: 20 \: N/m^2[/tex]
[tex]\boxed{\sf\red{\boxed{ \sf Pressure ≈ \: 20 \: N/m^2}}}[/tex]
25 n object requires a 5. 0 n to start moving over a horizontal surface. What is the coefficient of static friction?.
Answer:
μ=1/5=0.2
Explanation:
using the formula
Fs=Fn*μ
Where
Fs is the static force
Fn = Normal force
μ= coefficient
so if Fn=25n
and it requires 5 n to start moving, means the max Fs is 5n
5=25μ
μ=5/25
μ=1/5=0.2
What is a milliliter.
A milliliter, abbreviated as ml or mL, is a unit of volume in the metric system. One milliliter is equal to one thousandth of a liter, or 1 cubic centimeter. In the imperial system, that's a small amount: . 004 of a cup
A state government wants to increase the taxes on cigarettes to increase tax revenue. Because cigarettes are addictive, we would expect its demand to be: ______________
a. Elastic, Thus, the government's cigarette-tax revenues would rise with a tax increase.
b. Elastic, Thus, the government's cigarette-tax revenues would fall with a tax increase.
c. Inelastic, Thus, the government's cigarette-tax revenues would rise with a tax increase.
d. Inelastic, Thus, the government's cigarette-tax revenues would fall with a tax increase.
The demand of cigarette is elastic so the government's cigarette-tax revenues would rise with a tax increase.
The demand of cigarette is elastic because of the addiction the people can buy the cigarette even at high prices and the government's cigarette-tax revenues would rise.
The demand for cigarettes is unitary elastic (−1.06) means that a 1% increase in the price of cigarette would reduce its consumption by 1.06% so we can conclude that the demand of the cigarette is elastic and the government revenues increases.
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Which of the following will require most developed countries to
decrease emissions of carbon dioxide and other greenhouse gases?
a. Montreal Protocol c. Emissions Reduction Act
b. Kyoto Protocol d. Reforestation Project
Answer:
Kyoto Protocol
Explanation:
which jovian planet should have the most extreme seasonal changes?
Answer:
Uranus
Explanation:
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The range of a target is found to be 20km. A shell leaves a gun with a velocity of 500m/s . What must be the angle of elevation of the gun if the ground is level
The angle of elevation of the shell must be approximately 25.840° in order to have a reach of 20 kilometers.
The shell experiments a parabolic motion, which is a combination of horizontal uniform motion and vertical uniform accelerated motion. If initial height of the shell is the same that its final height, then the range of the shell ([tex]d[/tex]), in meters, is described by the following expression:
[tex]d = \frac{v^{2}}{g}\cdot \sin 2\theta[/tex] (1)
Where:
[tex]v[/tex] - Initial speed of the shell, in meters per second[tex]g[/tex] - Gravitational acceleration, in meters per square second[tex]\theta[/tex] - Angle of elevation, in sexagesimal degreesIf we know that [tex]v = 500\,\frac{m}{s}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]d = 20000\,m[/tex], then the angle of elevation is:
[tex]\sin 2\theta = \frac{d\cdot g}{v^{2}}[/tex]
[tex]\theta = \frac{1}{2}\cdot \sin^{-1} \frac{d\cdot g}{v^{2}}[/tex]
[tex]\theta = \frac{1}{2}\cdot \sin^{-1} \frac{(20000\,m)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}{\left(500\,\frac{m}{s} \right)^{2}}[/tex]
[tex]\theta \approx 25.840^{\circ}[/tex]
The angle of elevation of the shell must be approximately 25.840° in order to have a reach of 20 kilometers.
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A 50-kg girl lifts a 1-kg box vertically upward a distance of 0.5 meter. How
much work is done on the box?
Answer:
Given mass = 2kg, height = 10m,g = 9.8.
We know that Work done W = FD
= > W = (mg)(D)
= > W = (2 * 9.8)(10)
= > W = 196 Joules.
Explanation:
Yan :).
How many sulfur atoms are there in 25 molecules c4h4s2?.
What would be the extension of the spring for a 3 N weight if the extension of the spring was 4 mm for a 50 g mass?
А 4 mm B)8 mm C)12mm D)24 mm
Answer:
24mm
Explanation:
3 N to g is 305.9 g
50g ---- 4 mm
305.9 ----- 4×305.9/50 = 24 mm
A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm. A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.
We have that for the Question, it can be said that the amount by which the length of the stack decreases is
[tex]dl'=3.621*10^{-4}m[/tex]
From the question we are told
A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm.
A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.
Generally the equation for copper cylinder is mathematically given as
[tex]dl=\frac{Flo}{yA}[/tex]
[tex]dl=\frac{7900*3*10^-^2}{1.1*10^{11}*\pi(0.24*10^{-2})^2}[/tex]
[tex]dl=1.19064778*10^-^4[/tex]
Generally the equation for brass cylinder is mathematically given as
[tex]dl=\frac{7900*5*10^-^2}{9*10^{10}*\pi(0.24*10^{-2})^2}[/tex]
[tex]dl=2.43*10^{-4}[/tex]
Therefore Total change in length
[tex]dl'=1.191*10^-^4+(2.43*10^{-4})[/tex]
[tex]dl'=3.621*10^{-4}m[/tex]
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