Answer:
=0.35hcn20 4.7 x hcn(poh) =hcnty sa pointd
what is the common name of hydrated calcium sulphate?
Answer:
Gypsum
Explanation:
Calcium sulphate, is a naturally occurring calcium salt. It is commonly known in its dihydrate form, a white or colourless powder called gypsum.
Using the material selection processes, justify why the manufacturers/designers used the materials they did for super glue?
Answer:
Aluminium reusable water bottle Purpose of aluminum: Weighs less by volume than most other metals and comes at an affordable price.
Explanation:
Question 1(Multiple Choice Worth 50 points)
(01.06 LC)
Which technology removes carbon dioxide from the air by binding to it?
Answers-
O Pyrolization
O Direct-air capture
() Engineered molecules
O Carbon ground injection
Answer:
Direct-air capture
Explanation:
To understand the technology I'm about to explain, I'll model it to something familiar. As you know, the process of photosynthesis is where trees and plants use sunlight, water, and carbon dioxide to create energy for themselves, and release oxygen as a byproduct. Direct- air capture is exactly like this. Its pulls in air and then through a range of similiar chemical reactions, it extracts the carbon dioxide from it while returning the rest of the air to the surrounding environment. Except, the Direct-air capture does this at a much faster rate than nature does. The direct-air capture uses a ginormous fan that pulls air in which then passes over plastic surfaces that have potassium hydroxide solutions covered over them. The potassium hydroxide solution chemically binds with the carbon dioxide molecules, removing them from the air and trapping them in the liquid solution as a carbonate salt. The carbon dioxide is then contained where it is compressed and purified and then stored for later use.
What instruments are used to measure moleculars vibration , rotation and translation?
Answer:
you hear
Explanation:
beautiful hear can be wonderful day in your life so to be rotations is not a big deal
Lithium carbonate, Li2CO3, is commonly used to treat bipolar disorder. What is the percent by mass of carbon in this compound (to the nearest whole percent)
Answer:
18.78%
Hence, the mass percent of lithium in lithium carbonate is 18.78%.
Explanation:
The percent by mass of carbon in this compound, lithium carbonates is
16.2%
The compound is lithium carbonates.
The molar mass of the compound will be calculated and the molar mass of carbon in the compound will also be calculated to find the percentage of carbon in it.
Molar mass of Li₂CO₃ = (7 ×2) + 12 + 48 = 74 g
Molar mass of carbon in the compound = 12g
percentage mass of carbon = 12 / 74 × 100
percentage mass of carbon = 1200 / 74
percentage mass of carbon = 16.2162162162
percentage mass of carbon = 16.2 %
learn more: https://brainly.com/question/5596184?referrer=searchResults
Learning Task 2: Read each statement or question below carefully and fill in the blank(s) with the best answer by choosing the words inside the box. Write your answers in a separate sheet of paper. cation 1 -ide -ine nonmetals O ion ionic compound anion metals root name 1. Any atom or molecule with a net charge, either positive or negative, is known as en 2. An atom that gains one extra electron forms an with a 1- charge. 3. A positive ion, called a is produced when one or more electrons are lost from a neutral atom. 4. Unlike a cation, which is named for the parent atom, an anion is named by taking the of the atom and changing the ending. 5. The name of each anions is obtained by adding the suffix to the root of the atom name. 6. The always form positive ions. 7. on the other hand, form negative ions by gaining electrons. 8. It is very important to remember that a chemical compound must have a net charge of
22. Which of the following molecules or ions contain polar bonds?
(a) O3
(b) S8
(c) 02 2-
(d) NO3
(e) CO2
(f) H2S
(g) BH4-
Answer:
D NO3 Nitrate is a nitrogen oxoanion formed by loss of a proton from nitric acid.
4.What volume of hydrogen gas at STP is produced when 2.5 grams of zinc react with an
excess of hydrochloric acid?
Answer:
0.86
Explanation:
1mol of Zn has mass of 65.39g.The amount of Zn is 2.5g65.39g/mol=0.038mol.
The amount of H2 produced is the same as the amount of Zn consumed (0.038mol).
1mol of ideal gas will occupy 22.4L at STP.
The H2 will occupy 0.038mol×22.4L/mol=0.86L
.
When the pressure of an equilibrium mixture of SO2, O2, and SO3 is doubled at constant temperature, what the effect on Kp
When the pressure of the equilibrium mixture of SO2, O2, and SO3 is doubled at constant temperature, the Kp is also doubled.
The equation of the reaction is given by; 2SO2 + O2 → 2SO3. The Kp of the reaction is obtained from;
Kp = pSO3^2/pSO2^2 . pO2
Since the Kp depends on the individual partial pressures of each of SO2, O2, and SO3 at equilibrium, if the pressure of the equilibrium mixture is doubled, the Kp is also doubled.
Learn more: https://brainly.com/question/11324711
What is it called when you have hydrogen peroxide that just eventually turns into water
Answer:
chlorine
Explanation:
Answer:chlorine reacts with hydrogen peroxide
Explanation:
Why is the first one (A) correct?
Answer: yes it is correct
Explanation: the higher it is the cooler.
The table below shows the dimensions of two colored cubes.
Dimensions of Cubes
Cube Side (cm) Mass
(g)
Yellow 3 135
Black 2 48
Answer: The correct answer is black because the product of its side and mass is lower.
Explanation: The density of a substance is defined as the amount of matter that can be stored in a given volume.
Hence, the black cube will be denser because the product of its side and mass is lower.
Answer: it was wrong on my test
Explanation:
literally dont believe them
A chemist heats the block of copper as shown in the interactive, then places the metal sample in a cup of oil at 25.00 °C instead of a cup of water. The temperature of the oil increases to 27.33 °C . Calculate the mass of oil in the cup. The specific heat of copper is 0.387 J/g⋅°C and the specific heat of oil is 1.74 J/g⋅°C .
When the oil is added to the heated copper, the energy in the system is
conserved.
The mass of the oil in the cup, is approximately 64.73 grams.Reasons:
The question parameters are;
Temperature of the oil in the cup = 25.00°C
Final temperature of the oil and copper, T₂ = 27.33 °C
Specific heat of copper, c₂ = 0.387 J/(g·°C)
Specific heat capacity of oil, c₁ = 1.74 J/(g·°C)
Required:
The mass of oil in the cup.
Solution:
The mass of the copper, m₂ = 17.920 g
Temperature of copper after heating, T₂ = 65.17°C
Temperature of the copper after being placed in the cup of oil, T₂ = 27.33°C
Heat lost by copper = Heat gained by the oil
m₂·c₂·(T₂ - T₃) = m₁·c₁·(T₃ - T₁)Therefore, we get;
17.920 × 0.387 × (65.17 - 27.33) = m₁ × 1.74 × (27.33 - 25)
262.4219136 = 4.0542·m₁
m₁ ≈ 64.73
The mass of the oil in the cup, m₁ ≈ 64.73 gLearn more here:
https://brainly.com/question/21406849
Possible part of the question obtained from a similar question online, are;
The mass of the copper, m₂ = 17.920 g
Temperature of copper after heating = 65.17°C
What is the mass of 8 moles of sodium chloride?
468 g
4.68 9
46.8 g
4.689 mol
Please answer
I'll mark BRAINLIST
Answer:
468 g _______________________
The mass of 8 moles of sodium chloride is 468 grams. Therefore, option A is correct.
Molar mass, also known as molecular weight, is the mass of one mole of a substance. It is typically expressed in grams per mole (g/mol). Molar mass is calculated by summing the atomic masses of all the atoms in a molecule.
To calculate the mass of a substance, multiply the number of moles by the molar mass of the substance. The molar mass of sodium chloride (NaCl) is approximately 58.44 grams per mole.
The mass of 8 moles of sodium chloride:
Mass = Number of moles × Molar mass
Mass = 8 moles × 58.44 g/mol
Mass = 467.52 grams
To learn more about the moles, follow the link:
https://brainly.com/question/20552052
#SPJ6
Tristan wraps some gifts and then brings them to the post office where they are delivered to people in different parts of the country. Which organelle is Tristan most like?
Answer:
Tristan wraps some gifts and then brings them to the post office where they are delivered to people in different parts of the country. Which organelle is Tristan most like?
Answer: Tristan is most like the Golgi Body
Explanation:
Find five household items that contain ionic compounds. List the following information for each compound: a.name of the product
b. the chemical name of the ionic compound
d.the chemical formula of the ionic compound c. identify the ions present in each compound
Answer:
D . GOD BLESS .
Explanation:
Using chemical equations, show how the triprotic acid H3PO4 ionizes in water. Phases are optional.
Ka1:
Ka2:
Ka3:
Explanation:
H3PO4 is a weak acid so it partially dissociates in water
Ka1
H3PO4 (aq) + H2O(l) <----> H2PO4-(aq) + H3O+ (aq)
Ka2
H2PO4- (aq) + H2O(l) <----> HPO4 2- (aq) + H3O+ (aq)
Ka3
HPO4 2- (aq) + H2O(l) < ---> PO4 3- (aq) + H3O+ (aq)
Which is true of protons and neutrons?
1. They have approximately the same mass and the same charge.
2) They have approximately the same mass but different charge.
by The have different mass and different charge.
O sette
4) They have different mass but the same charge.
Answer:
[tex]\blue{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}[/tex]
[tex]\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}[/tex]
What would the empirical formula be for the molecular compound CoH904?
The Difference between the number of protons and electrons give an atom it’s _________.
Answer:
it gives an atom its charge
How many moles of potassium iodide, KI, are required to precipitate all of the lead (II) ion from 25.0 mL of a 1.6 M Pb(NO3)2 solution? (First, write a balanced equation for the reaction.)
0.04 moles of iodide is required to precipitate all the lead II ions from 25.0 mL of a 1.6 M Pb(NO3)2 solution.
The reaction equation is;
2KI(aq) + Pb(NO3)2(aq) -------> PbI2(s) + 2KNO3(aq)
The net ionic equation is;
Pb^2+(aq) + 2I^-(aq) ------> PbI2(s)
Number of moles of Pb(NO3)2 = 25/1000 L × 1.6 M = 0.04 moles
Number of moles of Pb^2+ = 0.04 moles /2 = 0.02 moles
Since 2 moles of iodide reacts with 1 mole of Pb^2+
x moles of iodide reacts with 0.02 moles of Pb^2+
x = 2 moles × 0.02 moles/ 1 mole
x = 0.04 moles of iodide
Hence, 0.04 moles of iodide is required to precipitate all the lead II ions from 25.0 mL of a 1.6 M Pb(NO3)2 solution.
Learn more: https://brainly.com/question/9743981
Find the mass of 1.220 moles of PH5.
Answer:
43.93642
Explanation:
Phosphorus P 30.973762 1 86.0061
Hydrogen H 1.00794 5 13.9939
I don't know physics, but I hope this helps :)
(I'm a seventh grader so don't judge if this is wrong please)
PLS HELP ILL GIVE BRAINLIEST
Upload images that have physical and chemical properties
(six physical properties and 2 chemical properties)
Answer:
Explanation:
I hope this helps
An example of kinetic energy being converted into heat energy
Answer:
if you drop a water balloon onto the ground, its kinetic energy is converted mostly to thermal energy. If the balloon weighs 1 kilogram and you drop it from about 2 meters, it will heat up by less.
Explanation:
As you say, kinetic energy of large objects can be converted into this thermal energy. For example, if you drop a water balloon onto the ground, its kinetic energy is converted mostly to thermal energy. If the balloon weighs 1 kilogram and you drop it from about 2 meters, it will heat up by less than.
2. Alex pulls on the handle of a claw hammer with a force of 15 N. If
the hammer has a mechanical advantage of 5.2, how much force
is exerted on the nail in the claw?
Answer:
78n
Explanation:
The output force exerted on the nail in the claw is equal to 78 N which has a mechanical advantage of 5.2.
What is the mechanical advantage?The mechanical advantage can be demonstrated as the ratio of the output force to the Input force. The mechanical advantage of any machine can be expressed in the form of the ratio of the forces utilized to do the work.
The ratio of the resistance to the effort is said to be the actual mechanical advantage which will be less. The efficiency of a machine can be evaluated by equating the ratio of the output to its input.
Given, the input force = 15 N
The mechanical advantage of the hammer = 5.2
Mechanical advantage = Output force/ Input force
5.2 = Output/15
Output force = 15 ×5.2 = 78 N
Therefore, the force is exerted on the nail in the claw is equal to 78 N.
Learn more about the Mechanical advantage, here:
brainly.com/question/16617083
#SPJ2
What is the density of a sponge that has a mass of 100g and a volume of 10 mL?
Answer:
10
Explanation:
Equation: d = m/v
100/10 = 10
HELP!! what are the usual products of combustion reactions?
Explanation:
Carbon dioxide and water
I hope it helps
Answer:
The usual products of combustion reactions are carbon dioxide and water.
Explanation:
Combustion reaction is when a substance reacts with oxygen gas, resulting in a release of energy in the form of light and heat. Combustion reactions must have oxygen (O2) as one of the reactants.
To what volume would you have to change 6.5 Liters of a gas at 1.25 atm in order to
decrease its pressure to 1.0 atm?
Answer:
8.13 mLExplanation:
The required volume can be found by using the formula for Boyle's law
[tex]V_2 = \frac{P_1V_1}{P_2} \\[/tex]
where
P1 is the initial pressure
P2 is the final pressure
V1 is the initial volume
V2 is the final volume
From the question we have
[tex]V_2 = \frac{6.5 \times 1.25}{1} = 6.5 \times 1.25 \\ = 8.125[/tex]
We have the final answer as
8.13 mLHope this helps you
Determine the reducing agent in the following reaction. Explain your answer. 2 Li(s) + Fe(C2H3O2)2(aq) → 2 LiC2H3O2(aq) + Fe(s)
The reducing agent in the reaction 2Li(s) + Fe(CH₃COO)₂(aq) → 2LiCH₃COO(aq) + Fe(s) is lithium (Li).
The general reaction is:
2Li(s) + Fe(CH₃COO)₂(aq) → 2LiCH₃COO(aq) + Fe(s) (1)
We can write the above reaction in two reactions, one for oxidation and the other for reduction:
Oxidation reactionLi⁰(s) → Li⁺(aq) + e⁻ (2)
Reduction reactionFe²⁺(aq) + 2e⁻ → Fe⁰(s) (3)
We can see that Li⁰ is oxidizing to Li⁺ (by losing one electron) in the lithium acetate (reaction 2) and that Fe²⁺ in iron(II) acetate is reducing to Fe⁰ (by gaining two electrons) (reaction 3).
We must remember that the reducing agent is the one that will be oxidized by reducing another element and that the oxidizing agent is the one that will be reduced by oxidizing another species.
In reaction (1), the reducing agent is Li (it is oxidizing to Li⁺), and the oxidizing agent is Fe(CH₃COO)₂ (it is reducing to Fe⁰).
Therefore, the reducing agent in reaction (1) is lithium (Li).
Learn more here:
https://brainly.com/question/10547418?referrer=searchResultshttps://brainly.com/question/14096111?referrer=searchResults
I hope it helps you!
PLEASE HELPPPPPPPPPPPPPPPP