8. What is the mass of a toy car with a speed of 12.5 m/s and 47500 J of kinetic energy?

Answer:

Newton's theory identified mass as the factor that causes gravity. On the other hand, Einstein's theory identified the curvature of space-time as the factor that causes gravity.

Answer:

Hey mate...

Explanation:

This is ur answer....

In the 17th century Newton concluded that objects fall because they are pulled by Earth's gravity. Einstein's interpretation was that these objects do not fall. According to Einstein, these objects and Earth just freely move in a curved spacetime and this curvature is induced by mass and energy of these objects.

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Answer:

Yes it is

Explanation:

Electricity is the positive and negative matter that's found in protons and electrons.

Answer:

yes

Explanation:

because electricity is a positive and negative proton

Answer:

Vb = 0.334 m/s

Va = -1.265 m/s

Vc = 1.424 m/s

Explanation:

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Initial momentum = 255(2) – 242.5(1.5) = 146.25

Final momentum = 255Va + 290Vb + 242.5 Vc = 146.25

Vb - Va = 0.8(2) = 1.6

Vc - Vb = 0.8(1.5) = 1.2

Va = Vb -1.6

Vc = Vb + 1.2

255(Vb -1.6) + 290Vb + 242.5(Vb + 1.2) = 146.25

255 Vb – 408 + 290 Vb + 242.5 Vb + 291 = 146.25

787.5 Vb = 263.25

Vb = 0.334 m/s

Va = Vb -1.6 = 0.334 – 1.6 = -1.265 m/s

Vc = Vb + 1.2 = 0.224 + 1.2 = 1.424 m/s

Answer:

D. A large force produces a large change in the object’s momentum only if the force is applied over a very short time interval.

Explanation:

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

[tex] Momentum = mass * velocity [/tex]

Also, the impulse of an object is given by the formula;

[tex] Impulse = force * time [/tex]

In accordance with the impulse-momentum theorem, the statement which is true about the effect of a force exerted upon an object is that a large force produces a large change in the object’s momentum only if the force is applied over a very short time interval.

Answer:

the Laws of Thermodynamics

Explanation:

these laws states that no form of energy can be created by anyone or anything, without a previous and equal input of energy being put in, that energy can only be transferred from object to object and through different forms

Example: the way a heater runs to warm up an area, that is the process of electrical energy, or energy stored in propane being converted into heat energy

this law is universally implied and has been proven on multiple accounts to be true, in no way can you create energy out of thin air, all you can do is transform and transfer it

hope this is what you was going for, very good point in science

this is one of two correct answers, the other answer to this question is also correct

Answer:

Hello there Dude answer is B :D hope it helped mark me brainliest.

The formula of the compound formed has been  [tex]\rm \bold {K_2O}[/tex]. Thus, option D is correct.

The sample of potassium has mass of 0.242 g. Since, the substance has been heated in the presence of oxygen, the gain in the weight has been corresponds with the mass of oxygen.

The given sample has:

Mass of potassium, [tex]m_K=0.242\;\text g[/tex]

Mass of heated sample, [tex]m_S=0.292\;\text g[/tex]

The mass of oxygen ([tex]m_O[/tex])  in the sample has been given as:

[tex]m_O=m_S-m_K[/tex]

Substituting the values:

[tex]m_O=0.292\;-\;0.242\;\text g\\m_O=0.05\;\text g[/tex]

The mass of oxygen in the sample has been 0.05 g.

The moles (M) of compounds in the sample has been given as:

[tex]M=\dfrac{m}{mwt}[/tex]

Where, m has been the mass of the compound, and

mwt has been the molecular weight of the compound.

The moles of potassium ([tex]M_K[/tex]) has been given as:

[tex]M_K=\dfrac{0.242}{39.098}\\M_K=0.006\;\text mol[/tex]

The moles of oxygen ([tex]M_O[/tex]) has been given as:

[tex]M_O=\dfrac{0.05}{16}\\M_O=0.003\;\text mol[/tex]

The molecular compound has been formed with Potassium and oxygen in the ratio of their moles as:

[tex]\rm \dfrac{K}{O}=\dfrac{0.006}{0.003}\\ \dfrac{K}{O}= \dfrac{2}1}[/tex]

Thus, the molecular formula of the compound has been [tex]\rm \bold {K_2O}[/tex]. Thus, option D is correct.

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Answer:

μs = 0.36

Explanation:

       [tex]F_{frmax} = \mu_{s}* F_{n} = m * g (1)[/tex]

      [tex]F_{n} = m* \omega^{2} * r (2)[/tex]

       [tex]\mu_{s} = \frac{g}{\omega^{2} r} (3)[/tex]

       [tex]\omega = 26.0 \frac{rev}{min} * \frac{1min}{60 sec} *\frac{2*\pi rad }{1 rev} = 2.72 rad/sec (4)[/tex]

Answer:

(a) The car is going approximately 40.43 m/s at the bottom of the hill

(b) The thermal energy will increase by 607,268.76 J

Explanation:

In the question, we have;

The height of the roller coaster above ground = 83.4 m

The mass of the roller coaster, m = 743.0 kg

(a) By the conservation of energy principle, we have;

The potential energy at the top of the hill, P.E., is equal to the kinetic energy at the bottom of the hill, K.E.

∴ P.E. = K.E.

P.E. = m·g·h

Where;

m = The mass of the roller coaster = 743.0 kg

g = The acceleration due to gravity = 9.8 m/s²

h = The height of the roller coaster = 83.4 m

Therefore, we have;

P.E. = 743.0 kg × 9.8 m/s² × 83.4 m = 607,268.76 J

P.E. = 607,268.76 J

K.E. = 1/2·m·v²

∴ K.E. = 1/2 × 743.0 kg × v²

P.E. = K.E.

∴ P.E. = K.E. = 607,268.76 J

1/2 × 743.0 kg × v² = 607,268.76 J

v² = 607,268.76 J/(1/2 × 743.0 kg) = 1,634.64 m²/s²

v = √(1,634.64 m²/s²) ≈ 40.43 m/s

(b) Given that the material wheel moves along polystyrene track, the sound released will be minimal and almost all the kinetic energy will be converted to heat energy when the train stops, therefore, the thermal energy will increase by K.E. = 607,268.76 J

The thermal energy change of the system is 624,492 J.

We know that in the roller coaster, there is an energy transformation from gravitational potential energy to kinetic energy. As such we can write;

mgh = 1/2mv^2

Where we cancel out the mass from both sides, we are left with;

gh=0.5v^2

v= √gh/0.5

v = √10 × 83.4 m/0.5

v = 41 ms-1

Now the kinetic energy is converted also into heat energy hence;

Thermal energy change of the system = 1/2 mv^2 = 0.5 × 743.0 kg × ( 41 ms-1)^2 = 624,492 J

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Density of blood = 1.06x10³

Viscosity = 4 mpas

Answer:

It should be 1.10 higher

Explanation:

L = 0.93

D = 0.75

R = 0.75/2 = 0.375

Q = 0.03x10^-3

Blood pressure = 11x10³

Pn = 4x10^-3

n = 4 x 10^-3

Density of blood = 1.06x10³

Pn - Pv = 8*Q*n*L/pi*r⁴

Pn - pv = 463.57pa

Pn - pv = 463.57pa

Make pn subject

Pn = Pv + 463.57pa ----1

Vn = Q/An

= 0.0679m/s

To get height above needle

Pn + 1/2pv²n = Pa + pgh ----2

We equate 1 and 2 together

We get

Pgh = 11466

To get h we divide through by pg

h = 11466/pg

h = 11466/(1.06x10³)x9.81

h = 1.1026

Approximately

Height = 1.1 meters

So it should be 1.10 meters higher

the full calculations are in the attachment.

thank you!

Answer:

The moon keeps the same face pointing towards the Earth because its rate of spin is tidally locked so that it is synchronized with its rate of revolution (the time needed to complete one orbit). In other words, the moon rotates exactly once every time it circles the Earth.

Answer:

A and C

Explanation:

Both have mass and are in motion

Answer:

A. 450 N

B. 3240 J

C. 0.77 KW

Explanation:

From the question given above, the following data were obtained:

Height of one step = 20 cm

Number of steps = 36

Mass of runner = 45 kg

Time taken = 4.2 s

Next, we shall convert 20 cm to metre (m). This can be obtained as follow:

100 cm = 1 m

Therefore,

20 cm = 20 cm × 1 m /100 cm

20 cm = 0.2 m

Next, we shall determine the total height. This can be obtained as follow:

Height of one step = 0.2 m

Number of steps = 36

Total height =?

Total height = 36 × 0.2

Total height = 7.2 m

A. Determination of the runner's weight.

Mass of runner (m) = 45 kg

Acceleration due to gravity (g) = 10 m/s²

Weight (W) =?

W = m × g

W = 45 × 10

W = 450 N

B. Determination of the increase in the potential energy.

At the ground level, the potential energy (PE₁) is 0 J.

Next, we shall determine the potential energy at 7.2 m. This can be obtained as follow:

Mass of runner (m) = 45 kg

Acceleration due to gravity (g) = 10 m/s²

Total height (h) = 7.2 m

Potential energy at height 7.2 m (PE₂) = ?

PE₂ = mgh

PE₂ = 45 × 10 × 7.2

PE₂ = 3240 J

Final, we shall determine the increase in potential energy. This can be obtained as follow:

Potential energy at ground (PE₁) = 0 J

Potential energy at height 7.2 m (PE₂) = 3240 J

Increase in potential energy =?

Increase in potential energy = PE₂ – PE₁

Increase in potential energy = 3240 – 0

Increase in potential energy = 3240 J

C. Determination of the power.

Energy (E) = 3240 J

Time (t) = 4.2 s

Power (P) =?

P = E/t

P = 3240 / 4.2

P = 771.43 W

Finally, we shall convert 771.43 W to kilowatt (KW). This can be obtained as follow:

1000 W = 1 KW

Therefore,

771.43 W = 771.43 W × 1 KW / 1000 W

771.43 W = 0.77 KW

Therefore, her power is 0.77 KW

Answer:

The mass will be 227kg.

Explanation:

Mass is a measure of how much "stuff" is in an object. It's a measure of the number and type of atoms in something, and is fixed. If you and I went to the moon right now, our bodies wouldn't change what they were made of. I would still be made up of all the same "stuff," as would you! So my mass would be the same and so would yours.

Weight would change on the moon, because weight is a measure of the local pull of gravity on an object's mass. Earth's gravitational force is about 10m/s2 and the moon's is about 1.6m/s2. So on the moon, I would have a weight of about 1/6 my weight on Earth... but I'd still wear the same size jeans!

Answer: A

Explanation:

Answer:

m = [tex]\frac{k}{g}[/tex] x,

graph of x vs m

Explanation:

For this exercise, the simplest way to determine the mass of the cylinder is to take a spring and hang the mass, measure how much the spring has stretched and calculate the mass, using the translational equilibrium equation

              F_e -W = 0

              k x = m g

              m = [tex]\frac{k}{g}[/tex] x

We are assuming that you know the constant k of the spring, if it is not known you must carry out a previous step, calibrate the spring, for this a series of known masses are taken and hung by measuring the elongation (x) from the equilibrium position, with these data a graph of x vs m is made to serve as a spring calibration.

  In the latter case, the elongation measured with the cylinder is found on the graph and the corresponding ordinate is the mass

Answer: add 10 cm plus 200 mpa divided by 2 min then caculate that into 160 bars.

Explanation:

a) The relaxation time constant of the polymer is approximately 8.9 min.

b) The viscosity of the dashpot in the Maxwell model is approximately 4.55 GPa s.

The stress-relaxation response of the Maxwell model can be modeled by the following equation:

σ(t) = σ₀ exp(-t/τ)

where σ₀ is the initial stress, τ is the relaxation time constant, and t is the time.

a) The relaxation time constant of the polymer:

σ(2 min) = 160 MPa

σ₀ = 200 MPa

160 MPa = 200 MPa exp(-2 min/τ)

Taking the natural logarithm of both sides, we get:

ln(160/200) = -2 min/τ

Solving for τ, we get:

τ = -2 min / ln(160/200) ≈ 8.9 min

Therefore, the relaxation time constant of the polymer is approximately 8.9 min.

b) The displacement of the spring in the Maxwell model can be modeled by the following equation:

x(t) = (σ₀ / G) (1 - exp(-t/τ))

where G is the shear modulus of the polymer. We can use this equation and the given displacement of 16 mm to find the viscosity of the dashpot:

x(t) = 16 mm = 0.016 m

σ₀ = 200 MPa

τ = 6.09 min = 365.4 s

Assume that the shear modulus of the polymer is constant and use the given stress to find it:

G = σ₀ / γ

where γ is the strain induced by the stretching.

Since the bar was stretched by 16 mm and its original length was 10 cm (i.e., 100 mm), the strain is:

γ = 16 mm / 100 mm = 0.16

Therefore,

G = 200 MPa / 0.16 = 1250 MPa

Now we can solve for the viscosity of the dashpot:

η = σ₀τ / x(t)

= (200 MPa) (365.4 s) / (0.016 m)

≈ 4.55 GPa s

Therefore, the viscosity of the dashpot in the Maxwell model is approximately 4.55 GPa s.

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Answer:

35.71 m

Explanation:

Potential energy is calculated using this formula:

We are given 3 out of the 4 variables in this problem. We want to solve for h, the height of the cannon ball.

List out the known variables:

Substitute these values into the potential energy formula.

The cannonball was 35.71 m high to have a potential energy of 14,000 J.

Answer:

94.25 seconds

Explanation:

Solve for period (T) using: v=(2*pi*r)/T

rearrange: vT=2*pi*r

rearrange: T=(2*pi*r)/v

Plug in values.

T=(2*pi*150)/10

T=94.25 seconds

If a race car goes around a circular track of a radius of 150 m at speed of 10.0 m/s ,then the time taken to complete the one lap would be 94.25 seconds.

The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object. The unit of speed is a meter/second. The generally considered unit for speed is a meter per second.

As given in the problem a race car goes around a circular track of radius 150 m at speed of 10.0 m/s.

vT = 2 × π × r

T = (2 × π × r)/ v

T = (2 × π× 150)/10

T = 94.25 seconds

Thus, the time taken to complete the one lap would be 94.25 seconds.

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Answer:

The answer should be uranus

Explanation:

The speed of the hoop when it has rolled halfway up the side of the pipe is √(v₀² - gR).

The speed of the hoop when it has rolled halfway up the side of the pipe is calculated as follows;

K.E = P.E

- ¹/₂mv₀²  + ¹/₂Iω² = (mgh₀ - mghf)

- ¹/₂mv₀²  + ¹/₂Iω² = (0 - 0.5mgh)        (hf = 0.5h) (half way up)

¹/₂Iω² = ¹/₂mv₀² - 0.5mgh  

where;

¹/₂(mr²)(vf/r)² = ¹/₂mv₀²  - 0.5mgh

¹/₂vf²  = ¹/₂v₀² - ¹/₂gh  

vf²  = v₀² - gh

vf = √(v₀² - gh)

where;

vf = √(v₀² - gR)

[tex]v_f = \sqrt{v_0^2 - gR}[/tex]

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Answer:20.8

Explanation:

Answer:

Motion that changes the orientation of a body is called rotation. ... In both cases all points in the body have the same velocity (directed speed) and the same acceleration (time rate of change of velocity).

Answer:

its called relative speed

Answer:

8 m/s²

Explanation:

From the question,

Since the same force act on both object,

F = ma = m'a'.............................. Equation 1

Where F = force action on the obeject, m = mass of the first object, a = acceleration of the first object, m' = mass of the second object, a' = acceleration of the second object.

make a' the subject of the equation

a' = ma/m'................... Equation 2

Given: m = 12 kg, a = 6 m/s², m' = 9 kg.

Substitute these values into equation 2

a' = 12(6)/9

a' = 8 m/s².

Hence the acceleration of the second object is 8 m/s²

Answer:

Fnet = 0

Explanation:

       [tex]F_{appx} = F_{app} * cos \theta = 295 N * cos 35 = 242 N (1)[/tex]

      [tex]F_{appy} = F_{app} * cos \theta = 295 N * sin 35 = 169 N (2)[/tex]

⇒    169 N + Fn = Fg = 216 N  (3)

Answer:

Second option

Explanation:

"Uniform" pretty much means the same thing happens.

Answer:

There are 75 people in the class. The number of boys is 48 and the number of girls is 27. The percentage of girls is 36% of 75.

Explanation: