8 + 2 + (1/2) + (1/8) +...... Find the sum of the infinite series.

If the given equations are indeed

[tex]\begin{cases}x-\frac4{5y} = 9\frac45 \\ -14x - 4y = -46\end{cases}[/tex]

we can solve by substitution. Solve the second equation for x :

[tex]-14x - 4y = -46[/tex]

[tex]\implies 7x + 2y = 23[/tex]

[tex]\implies7x = 23 - 2y[/tex]

[tex]\implies x = (23 - 2y)/7[/tex]

Substitute this into the first equation and solve for y :

[tex]\dfrac{23-2y}7 - \dfrac4{5y} = 9\dfrac45[/tex]

On the right side, write the mixed number as an improper fraction:

[tex]9 + \dfrac45 = \dfrac{45}5 + \dfrac45 = \dfrac{45+4}5 = \dfrac{49}5[/tex]

[tex]\implies \dfrac{23-2y}7 - \dfrac4{5y} = \dfrac{49}5[/tex]

Multiply both sides of this equation by 35y (the LCM of the denominator of all three fractions)

[tex]35y \times \dfrac{23-2y}7 - 35y \times \dfrac4{5y} = 35y \times \dfrac{49}5[/tex]

[tex]5y\times(23-2y) - 7\times4 = 7y \times 49[/tex]

[tex]115y - 10y^2 - 28 = 343y[/tex]

[tex]10y^2 + 228y + 28 = 0[/tex]

[tex]5y^2 + 114y + 14 = 0[/tex]

To solve the quadratic, I'll complete the square :

[tex]5\left(y^2 + \dfrac{114}5y\right) + 14 = 0[/tex]

[tex]5\left(\left(y + \dfrac{57}5\right)^2 - \left(\dfrac{57}5\right)^2 \right) + 14 = 0[/tex]

[tex]5\left(y + \dfrac{57}5\right)^2 - \dfrac{57^2}5 + 14 = 0[/tex]

[tex]5\left(y + \dfrac{57}5\right)^2 = -\dfrac{3179}5[/tex]

This system has no real solutions since the square of any real number must be positive.

If we allow complex numbers, we can continue solving to end up with two complex solutions for y,

[tex]\left(y + \dfrac{57}5\right)^2 = -\dfrac{3179}{25}[/tex]

[tex]y + \dfrac{57}5 = \pm i \sqrt{\dfrac{3179}{25}}[/tex]

[tex]y = -\dfrac{57}5 \pm i\dfrac{17\sqrt{11}}5[/tex]

and we can go on to solve for x.

Hence my comment; I suspect you meant to write the system

[tex]\begin{cases}x-\frac45 y = 9\frac45 \\ -14x - 4y = -46\end{cases}[/tex]

because its solution is far simpler. Multiplying through the first equation by 5 gives

[tex]5\times x - 5 \times \dfrac45 y = 5 \times 9\dfrac45[/tex]

[tex]\implies 5x - 4y = 49[/tex]

(since we know 9 + 4/5 = 49/5)

Meanwhile, multiplying through the second equation by -1 gives

[tex]-1 \times (-14x) + (-1) \times (-4y) = -1 \times (-46)[/tex]

[tex]\implies 14x + 4y = 46[/tex]

So if we combine the two equations, we can eliminate y and solve for x :

[tex](5x - 4y) + (14x + 4y) = 49 + 46[/tex]

[tex]\implies 19x = 95[/tex]

[tex]\implies \boxed{x = 5}[/tex]

and solving for y gives

[tex]14x + 4y = 46[/tex]

[tex]\implies 70 + 4y = 46[/tex]

[tex]\implies 4y = -24[/tex]

[tex]\implies \boxed{y = -6}[/tex]

What the judge should do is adhere strictly to the rules.

This is so because, in case of not abiding by the rules, the referee would be allowing the players to modify the sport at will, which would go against the stability of the game and the predictability of the rules.

Therefore, in case the captains want to modify the rules, in any case they should contact the governing association of the sport to request said modifications.

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The referee will have to allow halftime interval as a result of one of the

players wanting it.

Every sport has rules which guides the game to ensure fair play and  prevent

confusion from happening. Referee decisions are based on the rule of the

game but can also be negotiated.

In this scenario, if all the players wanted eliminate the halftime interval, it

could have been honored .But in this case, the referee has to follow the rules

of the game due to the other player disagreeing with the suggestion.

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Answer: Less likely since the number of cyan is quite lower or the lowest in comparison of magenta and yellow.

Based on the information given, the cost of each candy cane will be $3.00.

This is an incomplete information as you didn't provide the cost of the box. Let's assume that the cost of the box is $36.

From the information given, we are told that each box of candy canes has 12 candy canes. Therefore, the cost of each candy cane will be:

= $36 / 12

= $3.

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The fraction 8/3 of the chocolate bars would each of you get.

The division in mathematics is one kind of operation. In this process, we split the expressions or numbers into the same number of parts.

Given:

You have 4/3 chocolate bars.

You want to give 1/2 of the chocolate bars to your friend.

To find the fraction of the chocolate bars would each of you get:

Use division operation,

4/3 ÷ 1/2

Rearranging to multiplication term,

4/3 x 2/1

= 8/3

Therefore, 8/3  fraction of the chocolate bars would each of you get.

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#SPJ2

Answer:

67

Step-by-step explanation:

Because 180-113 is 67.

Answer:

67°

Step-by-step explanation:

A line is 180° so subtract the 113°

180 - 113 = 67°

hope that helps and have a great day :D

Step-by-step explanation:

We first calculate the lenght of the diameter, that is also the lenght of the hypotenuse of the right triangle shown in the figure:

d = [tex]\sqrt{3^2 + 4^2} = \sqrt{25} = 5[/tex] cm

The radius of the circle will be half of the diameter: r = d/2 = 2.5 cm

The area of the circle will be: Acircle = pi * r^2 = pi * 6.25 cm^2 = 19.6 cm^2 (circa).

Now from the area of the circle we subtract the area of the square:

Asquare = 4cm * 3cm = 12cm^2

A shaded = Acircle - Asquare = 19.6 cm^2 - 12cm^2 = 7.6 cm^2

Answer: Minimum for $150: 2 Hours

Step-by-step explanation: First, Tiffany charges $30 per additional child. If she babysits for 4 children, you do 30 x 4, which is equal to 120. That would be the cost for the children. Now, if she charges $15 PER HOUR, then you just add up $15 + $15, which is $30, and you add that $30 to the $120. Which is $150. There you have it. If this is wrong, correct me please!

Answer:

Option D is correct.

Explanation:

An obtuse angle is an angle that has more than 90°. In the picture, we can clearly see that ∠XYZ has more than 90°. This is an obtuse angle. ∠XWZ is also more than 90°, so that angle is also classified as an obtuse angle. Hence, Option D is correct.

Hoped this helped.

[tex]BrainiacUser1357[/tex]

Answer:

[tex]\huge\color{green}\boxed{\colorbox{black}{Answer ☘}}[/tex]

To find - sum of the given two terms.

[tex](4 + 3x) + (5 - 4x + 2x {}^{2} ) \\ 4 + 3x + 5 - 4x + 2x {}^{2} \\ = > 2x {}^{2} - x + 9[/tex]

[tex]\color{purple}\boxed{\colorbox{black}{Additional Information♡}}[/tex]

we basically added the like terms together..

like, the terms ( 3x and -4x ) will be added together.. and the terms ( 4 and 5 ) will be added together...

since there's none other term having "x²" as the coefficient.. so 2x² will be left as it is!

hope helpful~

The sum of the expression 4+3x and 5-4x+2x² is 2x² + 7x + 9

Given:

4+3x

5-4x+2x²

(4+3x) + (5-4x+2x²)

= 4 + 3x + 5 - 4x + 2x²

= 2x² + 3x - 4x + 5 + 4

= 2x² + 7x + 9

Therefore, the sum of the expression is 2x² + 7x + 9

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Answer:

  y = 2·5^x

Step-by-step explanation:

Using the given points, we can solve for 'a' and 'b'.

  y = ab^x

  2 = ab^0 = a . . . . . substitute (0, 2) for (x, y)

__

  1250 = 2·b^4 . . . . substitute for 'a' and (4, 1250) for (x, y)

  625 = b^4 . . . . divide by 2

  5 = b . . . . . . . take the 4th root

The function is ...

  y = 2·5^x

____

Additional comment

There are two real and two imaginary 4th roots of 625. Only the positive real root is useful as the base in an exponential function like this.

Answer:

12

2

answer

hope it helps

Answer:

The least number of stamps required is [tex]9[/tex]

Step-by-step explanation:

Let the number of [tex]3[/tex] cent stamps be [tex]x[/tex] and [tex]4[/tex] cent stamps be [tex]y[/tex]

We have

[tex]3x+4y=33[/tex]

The minimum number is obtained when more  [tex]4[/tex] cent stamps are used

Here [tex]y[/tex] cannot be greater than [tex]8[/tex] since [tex]\frac{33}{4} <9[/tex]

Substitute [tex]y=8[/tex]

[tex]3x+4\times 8=33\\\\3x=1\\\\x=\frac{1}{3}[/tex]

Not possible since [tex]x[/tex] is not a fraction

Substitute [tex]y=7[/tex]

[tex]3x+4\times 7=33\\\\3x=5\\\\x=\frac{5}{3}[/tex]

Not possible since [tex]x[/tex] is not a fraction

Substitute [tex]y=6[/tex]

[tex]3x+4\times 6=33\\\\3x=9\\\\x=\frac{9}{3}\\\\=3[/tex]

Possible

Hence minimum number of stamps is

[tex]=x+y\\\\=3+6\\\\=9[/tex]

Answer:

1050miles.

Step-by-step explanation:

since every 2 inches=350 miles, then 6 inches= 3(350miles)

since 6/2=3.

or you can think of it this way:

there are 3 2-inches in 6 inches, and every 2 inches, it's 350s miles.

350+350+350=1050miles.

Answer:

62.273  

Step-by-step explanation:

sorry it took me a little while to translate i speak only english

Answer:

Step-by-step explanation:

Given the value of the thickness of a dollar bill to be 0.00011 metre .

The standard scientific Notation is expressed as A * 10 ^ n

A is any value between 1 and 10 where n is any Integer .

0.00011 = 11 / 100000

0.00011 = 11 / 10000

0.00011 = 11 *1 / 1000

0.00011 = 11 * 0.0001

0.00011 = 1.1 * 0.001

0.0011 = 1.1 * 10 ^ -3

Answer:

k = 7

Step-by-step explanation:

The constant of proportionality k is calculated as

k = [tex]\frac{miles}{hours}[/tex]

Using the values from the table , then

k = [tex]\frac{14}{2}[/tex] = [tex]\frac{42}{6}[/tex] = [tex]\frac{56}{8}[/tex] = [tex]\frac{70}{10}[/tex] = 7

The slope of B'C' is 1 and it can be determined by using formula of scale factor.

Given that,

ABC is an isosceles right triangle in which has a slope of -1 and m ∠ABC = 90°.

ABC is dilated by a scale factor of 1. 8 with the origin as the center of dilation, resulting in the image A'B'C'.

We have to determine,

What is the slope of B'C'?

According to the question,

ABC is an isosceles right triangle in which,

Slope of AB = -1

And AB is perpendicular to BC.

When the two lines are perpendicular to each other then,

[tex]\rm The \ slope\ of\ AB \times Slope\ of \ BC = -1\\\\-1 \times Slope\ of \ BC = -1\\\\ Slope\ of \ BC = 1\\[/tex]

ABC is dilated by a scale factor of 1. 8 with the origin as the center of dilation, resulting in the image A'B'C'.

Length of Line segment A'B'= 1.8 × AB

So, the slope of the two-line Segment that is AB and A'B' are the same.

Slope of A'B'= -1

Length of Line segment C'B'= 1.8 × CB

So, the slope of the two lines that is CB and C'B' are the same.

The slope of B'C' is 1.

Hence, The required slope of B'C' is 1.

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Answer:

Slope of 1

Step-by-step explanation:

C.  1

Answer:

Step-by-step explanation:

We are being asked for times, so we can express the rate in terms of seconds per meter.

  (15 seconds)/(14 meters) = (15/14) seconds per meter = 1 1/14 seconds/meter

__

1) It will take Robot A 1 1/14 seconds to go 1 meter.

2) it will take Robot A 4 2/7 seconds to go 4 meters. (4 times as long)

Answer:

5.620

Step-by-step explanation:

I hope this helps you

Answer:

0.00025

Step-by-step explanation:

Here is a example

The measure of side GH is 50.486 units.

Two triangles are similar if they share the same set of internal angles, that is, the following conditions are met:

[tex]\angle C \cong \angle F[/tex] (1)

[tex]\angle E \cong \angle H[/tex] (2)

[tex]\angle D \cong \angle G[/tex] (3)

Then, we can determine the length of the line segment [tex]GH[/tex] by the following relationship:

[tex]\frac{CD}{FG} = \frac{DE}{GH}[/tex] (4)

If we know that [tex]CD = 7[/tex], [tex]FG = 31[/tex] and [tex]DE = 11.4[/tex], then the value of the line segment [tex]GH[/tex] is:

[tex]GH = \frac{FG\cdot DE}{CD}[/tex]

[tex]GH = \frac{31\cdot 11.4}{7}[/tex]

[tex]GH = 50.486[/tex]

The measure of side GH is 50.486 units.

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80,000

Just look at the number in the ten thousand place and check if you have to round up or down.

Answer:

I think it might be the bottom right one but not sure

Answer:

Inequality: 30 - 3d ≤ 20

Rate of decrease from Monday to Thursday: greater than or equal to 10/3 degrees Celsius per day

Step-by-step explanation:

Translate theconditions into mathematical terms:

HIgh temperature on Monday = T₀ = 30°C.

The temperature decrease at a constant rate in the next 3 days. Call d such rate, so T₃ = T₀ - 3d = 30 - 3d

That the pool is open when the high temperature is higher than 20°C means that, if the pool is closed, then the temperature is less than or equal to (≤) 20°C:

30 - 3d ≤ 20

And that is the requested inequality.

From that, you can solve for the rate of temperature decrease, d:

Add 3d to both sides: 30 ≤ 20 + 3d

Subtract 20 from both sides: 10 ≤ 3d

Divide both sides by 3: 10/3 ≤ d

Apply symmetry property: d ≥ 10/3

Hence, the rate of temperature decrease is greater than or equal to 10/3 degrees Celsius per day, from Monday to Thursday.

Answer:

30 - 3d ≤ 20

d≥10/3

Step-by-step explanation:

Answer:

D.

Step-by-step explanation:

Answer:

882

Step-by-step explanation:

840 : 100 x 105 = 882