Answer:
a) La aceleración del movimiento es 1 metros por segundo al cuadrado, b) La fuerza que causa el movimiento es 80.000 newtons.
Explanation:
a) Supóngase que la locomotora acelera uniformemente, la aceleración se está descrita por la siguiente ecuación cinemática:
[tex]v = v_{o}+a\cdot t[/tex]
Donde:
[tex]v_{o}[/tex] - Rapidez inicial, medida en metros por segundo.
[tex]v[/tex] - Rapidez final, medida en metros por segundo.
[tex]a[/tex] - Aceleración, medida en metros por segundo al cuadrado.
[tex]t[/tex] - Tiempo, medido en segundos.
Se despeja la aceleración:
[tex]a = \frac{v-v_{o}}{t}[/tex]
Si [tex]v_{o} = 0\,\frac{m}{s}[/tex], [tex]v = 10\,\frac{m}{s}[/tex] y [tex]t = 10\,s[/tex], la aceleración del movimiento es:
[tex]a = \frac{10\,\frac{m}{s}-0\,\frac{m}{s}}{10\,s}[/tex]
[tex]a = 1\,\frac{m}{s^{2}}[/tex]
La aceleración del movimiento es 1 metros por segundo al cuadrado.
b) Dado que una locomotora es un sistema de masa constante, la fuerza ([tex]F[/tex]) que genera el movimiento es igual a:
[tex]F = m\cdot a[/tex]
Donde:
[tex]m[/tex] - Masa, medida en kilogramos.
[tex]a[/tex] - Aceleración, medida en metros por segundo al cuadrado.
Dados que [tex]m = 80.000\,kg[/tex] y [tex]a = 1\,\frac{m}{s^{2}}[/tex], la fuerza que causa el movimiento es:
[tex]F = (80.000\,kg)\cdot \left(1\,\frac{m}{s^{2}} \right)[/tex]
[tex]F = 80.000\,N[/tex]
La fuerza que causa el movimiento es 80.000 newtons.
what is the speed of a car that travels 25km in 15 minutes?
Answer:
[tex] \boxed{ \bold{ \huge{ \boxed{ \sf{27.78 \: m/s}}}}}[/tex]Explanation:
Given,
Speed of a car = 25 km
Converting 25 km into m
[tex] \sf{1km = 1000m}[/tex]
[tex] \sf{25 \: km = 25 \times 1000m = 25000m}[/tex]
Time taken ( t ) = 15 minutes
Converting minutes into seconds
[tex] \sf{1 \: minutes = 60 \: seconds}[/tex]
[tex] \sf{15 \: minutes = 15 \times 60 sec = 900 \: seconds}[/tex]
Finding the speed of the car
[tex] \boxed{ \sf{speed = \frac{distance \: travelled}{time \: taken} }}[/tex]
[tex] \sf{ = \frac{25000 \: m}{900 \: s} }[/tex]
[tex] \sf{ = 27.78 \: m/s}[/tex]
Hope I helped!
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T or F? potential energy is limited to electormagnetic, mechanical, and nuclear energy.
how much work is done in moving a charge of 3 coulomb for a point at the volts 115 to a point at 125 volts
Answer:
We use the Formula,
Work done = total chargr×potential difference
W=Q(total)× V
Here
Q= total charge= Give 3c
V=potential difference= 10v
so the work done in moving the charge from A to B will be,
w=3×10
w= 30 joules
Question 3
What natural event do scientists blame for the desertification taking place in South Africa?
Answer:
Explanation:
Overgrazing and woodcutting are responsible for most of the desertification of rangelands, cultivation practices inducing accelerated water and wind erosion are most responsible in the rain-fed croplands, and improper water management leading to salinization is the cause of the deterioration of irrigated lands.
express 0.0097 in scientific notation
Explanation:
Move the decimal point until it is behind the first non-zero digit.
In this case, we move it 3 places to the right so it is behind the 9.
Therefore, 0.0097 = 9.7×10⁻³.
Imagine you and your friend are trying to rearrange the furniture in your classroom. You push on a desk with a force of 100 n to the right ,your friendpushes on the same desk with a force of 80 n to the left .What is the net force on the desk
Answer:20n Force :Right
Explanation:
The Answer To the equation is 20n because If the net force is opposite ways you subtract and the net force is the highest number !
2
Which of the following has the most kinetic energy?
A.
a 250 kg motorcycle moving at a speed of 45 m/s
OB. a 0.003 kg hummingbird moving at a speed of 16.7 m/s
C.
a 3500 kg elephant moving at a speed of 3 meters per second
OD
a 5000 kg truck that is not moving at all
Reset
Submit
Answer:
My answer to the question is "250kg motorcycle moving at a speed of 45m/s.
When it is necessary to place flares around a truck on a two-way roadway with a clear view, one must be placed beside the truck; the other two must be placed:
Answer:
during an accident
Explanation:
so the truck doesn't hit cars
An object is observed to move under the following equation of motion ... x(t) = A√t ... take A =√2. Determine the equations for the velocity and acceleration as a function of time. Write each equation in differential equation format, including second-order, if necessary.
Explanation:
x(t) = A√t
x(t) = √(2t)
v(t) = dx/dt
v(t) = ½ (2t)^-½ × 2
v(t) = (2t)^-½
a(t) = dv/dt
a(t) = -½ (2t)^⁻³/₂ × 2
a(t) = -(2t)^⁻³/₂
Calculate the kinetic energy of abody
of mass 5kg moving with
Velocity of
a
3mls-
Answer:
The kinetic energy is 22.5J .
Explanation:
Assuming that the formula to find kinetic energy is K.E = 1/2×m×v² where m represents the mass and v is the speed. Then, you have to substitute it :
[tex]k.e = \frac{1}{2} \times m \times {v}^{2} [/tex]
[tex]let \: m = 5,v = 3[/tex]
[tex]k.e = \frac{1}{2} \times 5 \times {3}^{2} [/tex]
[tex] k.e = \frac{1}{2} \times 5 \times 9[/tex]
[tex]k.e = \frac{1}{2} \times 45[/tex]
[tex]k.e = 22.5 \: joules[/tex]
(Correct me if I am wrong)
Help me please !!!!!! I really need help !!!!!! A spring is compressed, resulting in its displacement to the right. What happens to the spring when it is released? The spring exerts a restoring force to the right and returns to its equilibrium position. The spring exerts a restoring force to the right and compresses even further. The spring exerts a restoring force to the left and stretches beyond its equilibrium position. The spring exerts a restoring force to the left and returns to its equilibrium position.
Answer:the spring exerts a restoring force to the left and returns to its equilibrium position
Explanation:
Answer:
The spring exerts a restoring force to the left and returns to its equilibrium position.
Explanation:
Mercury has a density of 13.56 g/mL. How many kilograms of mercury would you expect to fit in a cylindrical glass cup with a bottom radius of 5.75 inches and a height of 0.950 ft?
Answer:
263.152kg
Explanation:
The density of a substance is related to its mass and volume as follows;
density = mass / volume
mass = density x volume -------------(i)
The substance in question here is mercury which has;
density = 13.56g/mL = 13.56g/cm³
Since the mercury is going to be put in the cylindrical glass, the volume of the cylindrical glass is going to be equal to the volume of the mercury that will be put.
And we know that the;
volume of a cylinder = πr²h
Where;
π = 3.142
r = bottom radius of the cylinder = 5.75inches
h = height of the cylinder = 0.950ft
For uniformity, let's convert the radius and height of the cylinder to their corresponding values in cm
r = 5.75 inches = 5.75 x 2.54 cm = 14.605cm
h = 0.950 ft = 0.950 x 30.48 cm = 28.956cm
Therefore, the volume of the cylinder;
v = 3.142 x (14.605cm)² x 28.956cm = 19406.5cm³
v = 19406.5cm³ [This is also the volume of the mercury necessary to fit the cylinder]
Now the following value has been found;
volume = 19406.5cm³
Substitute the values of density and volume into equation (i) as follows;
mass = 19406.5cm³ x 13.56g/cm³
mass = 263152.14g
Convert the result to kg by dividing by 1000
mass = 263.152kg
Therefore, 263.152kg kilograms of mercury would fit in the cylindrical glass.
Adapt the velocity equation v=v0 + at to solve for average acceleration where the ball starts at t = 0.0 seconds and v0 = 0.00 meters/second
Answer:
The adapted expression for average acceleration is [tex]a = \frac{v}{t'}[/tex].
Explanation:
Let be [tex]v = v_{o} + a\cdot t[/tex], which can be adapted by using the following substitution:
[tex]t = t'-t_{o}[/tex]
Where:
[tex]t'[/tex] - Final instant, measured in seconds.
[tex]t_{o}[/tex] - Initial instant, measured in seconds.
[tex]v = v_{o}+a\cdot (t-t_{o})[/tex]
Where:
[tex]v[/tex] - Final velocity, measured in meters per second.
[tex]v_{o}[/tex] - Initial velocity, measured in meters per second.
[tex]a[/tex] - Average acceleration, measured in meters per square second.
Now, average acceleration is cleared:
[tex]a = \frac{v-v_{o}}{t'-t_{o}}[/tex]
Given that [tex]t_{o} = 0\,s[/tex] and [tex]v_{o} = 0\,\frac{m}{s}[/tex], then:
[tex]a = \frac{v}{t'}[/tex]
Answer:
a = (v-v0)
____ where v = final velocity, v0
t
Explanation:
Using algebra, , where v = final velocity, v0 = initial velocity, and t = time. So,
= -9.3 m/s2.
The speedometer of a car moving east reads 60 mph. It passes another car that moves west at 60 mph. Which statement is the most accurate description of the motion of the vehicles?
Answer:
correct statement should be the same speed.
Explanation:
if the car is moving east reads 60 mph and it passes another car with the same speed.
therefore, the magnitudes of their velocities are equal.
and each car's velocity is the negative of the other car vehicle.
so the correct statement should be the same speed.
Answer:
They have different velocities
Explanation:
The cars are passing each other at the same speed, and because velocity is speed with direction they are at different velocities.
Make the following prefix conversions.
600,000 cm= ?? km
i need help
Answer:
6 km
Explanation:
A kilometer is 100,000 centimeters, so 600,000 centimeters equals 6 kilometers.
what is relative velocity in one dimension if va and vb are the velocities of two body a and b respectively then prove vab=va -vb
Answer:
Relative velocity is nothing but the velocity of one body with respect to the velocity of some other body.
Explanation:
Relative velocity may be defined as the rate at which the change of separation takes place between any two object.The relative velocity of any object A w.r.t. another object B when they are in motion is nothing but the rate of change of their position from one another.
Now, let the velocity of object A be [tex]$ v_A$[/tex]
and velocity of object B is [tex]$ v_B$[/tex]
Therefore, relative velocity of a object A when compared to the velocity of object B is given by [tex]$v_{AB}=v_A - v_B$[/tex].
Which statement best compares the accelerations of two objects in free fall?
Answer:
increasing the masses of the objects and decreasing the distance between the objects
Answer:the objects have the same acceleration
Explanation:
Part 1: Newton’s Laws Observe the virtual skateboarder coming down the hill and over the ramp. Describe how each of Newton’s laws of motion can be observed in this action. You can choose the dry, wet, or muddy conditions, or some combination of these. Newton’s First Law of Motion The skateboard riding down a hill with mud once the skateboard reaches the bottom it slows down due to frictional force acting in the opposite direction. Newton’s Second Law of Motion Newton’s Third Law of Motion
Answer:
the FIRST LAW NEWTON's skater goes down at a constant speed.
eaching the ramp in skidding, it has an acceleration due to the decrease in friction force. This is NEWTON'S SECOND LAW
NEWTON'S THIRD LAW, in the Normal force which is a reaction to the support of the skating
Explanation:
This problem asks to describe Newton's laws in a skater.
When going down a hill the skater acquires a constant speed, since the friction grows with the speed until it reaches the value of the weight component, In this case we see that the sum of the external forces is zero and According to the FIRST LAW NEWTON's skater goes down at a constant speed.
When reaching the ramp in skidding, it has an acceleration due to the decrease in friction force. This is NEWTON'S SECOND LAW
in this same part we can appreciate NEWTON'S THIRD LAW, in the Normal force which is a reaction to the support of the skating on the ramp and the planes the force of the skateboard on the ramp.
The force of friction of that stops the skateboard is equal to the product of mass and acceleration of the skateboard.
The skateboard riding down a hill with mud once the skateboard reaches the bottom it slows down due to frictional force acting in the opposite direction.
The force of the skateboard is equal in magnitude to the frictional force but in opposite direction.
Newton's first law of motion states an object at rest or uniform motion in s straight line will continue in that form unless acted upon by an external force.
The skateboard riding down a hill with mud once the skateboard reaches the bottom it slows down due to frictional force acting in the opposite direction.Newton's second law of motion states that the force applied to an object is directly proportional to the product of mass and acceleration of the object.
The force of friction of that stops the skateboard is equal to the product of mass and acceleration of the skateboard.Newton's third law of motion states that for every action there is equal and opposite reaction.
The force of the skateboard is equal in magnitude to the frictional force but in opposite direction.Learn more about Newton's law of motion here: https://brainly.com/question/10454047
what are the differences and the similarities between psychology and the social science
Answer:
psychology has to do with the mind and brain while social science has to do with the scientific study if human relationships
Differentiate between rest and motion.
Answer:
1. A body is said to be at rest if its position does not change with respect to its surroundings.
What mathematical relationship between variables is suggested by a graph showing a diagonal line from the lower left to the upper right of the
graph?
a
Inverse
B
Linear
C
Quadratic (power)
Answer:
B; Linear
Explanation:
A boy runs 20 M/sec and after 4 sec velocity become 10m/sec find the acceleration
Explanation:
Hey, there!!!
Here,
Given that,
initial velocity (u)= 20 m/s
final velocity (v)= 10 m/s
now,
[tex]acceleration \: = \frac{v - u}{t} [/tex]
[tex]a = 10-20/4
[tex] a= -2.5m/s^2
Therefore, theacceleration is -2.5m/s^2.
{ it gives negative acceleration because final velocity is decreased }.
Hope it helps....
Answer:
-2.5 m/(s^2)
Explanation:
Acceleration = Final Velocity - Initial velocity / Time
=> Acceleration = 10 - 20 /4
=> Acceleration = -10/4
=> Acceleration = -5/2
=> Acceleration = -2.5 m/(s^2)
An aluminum bar has a mass of 9 kg in the air. Calculate its volume. Now imagine that you submerge the aluminum bar in water hanging it from a rope. Calculate the apparent weight it would have in the water.
Answer:
55.7 N
Explanation:
The density of aluminum is 2710 kg/m³. So its volume is:
V = (9 kg) / (2710 kg/m³)
V = 0.00332 m³
The apparent weight is the actual weight minus the buoyant force.
N = mg − B
N = mg − ρVg
N = g (m − ρV)
N = (9.8 m/s²) (9 kg − (1000 kg/m³) (0.0332 m³))
N = 55.7 N
A roofer needs to get shingles onto a roof. Pulling the shingles up manually uses 1,549 N or force. The roofer decides to use a system of pulleys. Using the pulleys, 446 N are required to lift the shingles. What is the mechanical advantage of the system of pulleys?
Answer:
Mechanical advantage of pulleys = 3.47 (Approx)
Explanation:
Given:
Manual force = 1,549 N
Pulleys force = 446 N
Find:
Mechanical advantage of pulleys
Computation:
Mechanical advantage of pulleys = Manual force / Pulleys force
Mechanical advantage of pulleys = 1,549 / 446
Mechanical advantage of pulleys = 3.4730
Mechanical advantage of pulleys = 3.47 (Approx)
. For a body of Mass ‘m’ moving in a circle of radius ‘r’ if its velocity is halved, what will be the effect on the value of centripetal force?
As the space shuttle orbits the Earth, the shuttle and the astronauts
accelerate towards the Earth with the same acceleration. What effect does
this create?
Answer:
a=g.
the body is in one of these INGRAVIDITY, so the weight of the body would be ZERO
Explanation:
When the spacecraft revolves around the Earth, it is subjected to Newton's second law
F = m a
where the force is the universal attractive force, the mass of the astronauts, and the centripetal acceleration.
a = F / m
a = (G M m / r²) / m
a = G M / r²
the amount of is the acceleration of gravity at height r.
a = g
Therefore, we see that the acceleration of the body is equal to the acceleration of gravity, which is why the body is in one of these INGRAVIDITY, so the weight of the body would be ZERO
what was the acceleration of the cart with Low fan speed cm/s squared? what was the acceleration of the cart with medium fan speed cm/s squared? what was the acceleration of the cart with high fan speed cm/s squared?
Explanation:
The attached figure shows data for the cart speed, distance and time.
For low fan speed,
Distance, d = 500 cm
Time, t = 7.4 s
Average velocity,
[tex]v=\dfrac{d}{t}\\\\v=\dfrac{500}{7.4}\\\\v=67.56\ cm/s[/tex]
Acceleration,
[tex]a=\dfrac{v}{t}\\\\a=\dfrac{67.56}{7.4}\\\\a=9.12\ cm/s^2[/tex]
For medium fan speed,
Distance, d = 500 cm
Time, t = 6.4 s
Average velocity,
[tex]v=\dfrac{d}{t}\\\\v=\dfrac{500}{6.4}\\\\v=78.12\ cm/s[/tex]
Acceleration,
[tex]a=\dfrac{v}{t}\\\\a=\dfrac{78.12}{6.4}\\\\a=12.2\ cm/s^2[/tex]
For high fan speed,
Distance, d = 500 cm
Time, t = 5.6 s
Average velocity,
[tex]v=\dfrac{d}{t}\\\\v=\dfrac{500}{5.6}\\\\v=89.28\ cm/s[/tex]
Acceleration,
[tex]a=\dfrac{v}{t}\\\\a=\dfrac{89.28}{5.6}\\\\a=15.94\ cm/s^2[/tex]
Hence, this is the required solution.
Answer:low fan speed 18.0
Medium fan speed 24.0
High fan speed 32.0
Explanation:
I am looking at the answers
factors that affect acceleration due to gravity.
Answer
Factors Affecting Acceleration Due to Gravity
(1) Position on the planetary surface, it is higher at the axis (poles),
(2) Mass of the planet, higher with planets of larger masses
(3) Distance between object and the centre of planet, the larger the distance, the smaller the acceleration due to gravity.
Mark me as Brainlist if this answer is helpful for you
Explanation:
the factors affecting acceleratiom due to gravity are:
Altitude above the earth’s surface.Depth below the earth’s surface.The shape of the earth.Rotational motion of the earth.Find the slope of the line containing the two points (1,-1) and 7-5,-3). (1 point)
a
-1
b
-1/3
ос
1/3
Od
2
e
3
Answer:
[tex]m = \frac{-2}{3}[/tex]
Explanation:
Given
Points: (1,-1) and (-5,3)
Required
Determine the slope
The slope of a line is represented by m and is calculated as thus;
[tex]m = \frac{y_1 - y_2}{x_1 - x_2}[/tex]
Where
[tex](x_1,y_1) = (1,-1)[/tex]
[tex](x_2,y_2) = (-5,3)[/tex]
Substitute these values in the given formula
[tex]m = \frac{-1 - 3}{1 - (-5)}[/tex]
[tex]m = \frac{-1 - 3}{1 +5}[/tex]
[tex]m = \frac{-4}{6}[/tex]
Simplify fraction
[tex]m = \frac{-2}{3}[/tex]
Hence, the slope of the line is [tex]m = \frac{-2}{3}[/tex]
Answer:
The answer is 1/3
Explanation:
Change in y/Change in x
-2/-6=1/3
Very little is known about Pluto's surface conditions. TrueFalse
The statement is true.