7. Determine what happens to the wavelength when the
waves change between the following parts of the
electromagnetic spectrum.
Infrared to Radio waves:
Radio waves to Microwaves:
Ultraviolet to gamma rays:
Gamma rays to X-rays:
Infrared to Ultraviolet:
Yellow to blue:
Green to orange:
Infrared to red:
Ultraviolet to violet:

The diffraction limit of the visible light observatory Hubble Space Telescope is 0.05 arcseconds.

telescopic seeing. The lowest angle between close objects that can be seen to be distinctly separate is the telescope's angular resolving power (or resolution). The fact that light is a wave limits resolution.

Because radio waves have a significantly longer wavelength than optical waves, radio telescopes have a lower angular resolution than optical telescopes. In terms of design, all radio telescopes are reflectors.

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The final speed of both play doughs which stick together after the collision is 0.5 m/s.

The mass of the first play dough = 0.5 kg

The mass of the second play dough = 0.25 kg

The initial speed of the first play dough = 1.5 m/s

The initial speed of the second play dough = 2 m/s

The final speed of both play doughs can be found using the formula,

m₁u₁ + m₂u₂ = (m₁ + m₂) v

where,

m₁,m₂ is the mass of the first and second play dough respectively

u₁,u₂ is the initial speed of the first and second play dough respectively

v is the final speed of both play dough

Let us enter the known values in the above equation,

0.5 × 1.5 + 0.25 × 2 = (0.5 + 0.25) v

0.75 × 0.5 = 0.75v

0.375 = 0.75v

v = 0.375 / 0.75 = 0.5 m/s

The given question is incomplete. The complete question is ' The speed of the bob of the pay dough is 2 m/s.'

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The smallest speed at which cars can move on this track without relying on friction is 31.46 m/s.

The largest speed at which cars can move on this track without relying on friction is 39.10 m/s.

An attribute of an object moving in a circular route is centripetal acceleration. Any object moving in a circle with an acceleration vector pointing in the direction of the circle's center is said to be experiencing centripetal acceleration.

a) The smallest speed at which cars can move on this track without relying on friction is = √(gr₁)

= √(9.8 × 101) m/s

= 31.46 m/s.

b) The largest speed at which cars can move on this track without relying on friction is = √(gr₂)

= √(9.8 × 159) m/s

= 39.10 m/s.

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The force if they are moved so they are only one-eighth as far apart will be 2.688 N.

Objects' velocities can be changed by the concepts of thrust, drag, and torque.

Thrust causes an object to move faster, while torque causes an object to move slower.

Each part of an extended body typically exerts forces on its neighbouring sections; the internal mechanical stress in the body is the result of the distribution of these forces.

As the forces balance, the internal mechanical stresses have no effect on the body's acceleration.

The expression for the electric force is as follows,

F= kQ1Q2/r²

The new force between the dust particles after they moved.

F′ = kQ1Q2/(r/8)²

F′/F = {kQ1Q2/(r/8)²}/kQ1Q2/r²

F′/F = 1/(1/64)

F′ = 64F

Substitute 4.2×10⁻²N for F in the equation F′ =64F to find F1.

F′ =64(4.2×10⁻² N)

= 2.688 N

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Two force vectors would be shown on a free-body diagram for an elevator descending at a constant velocity: the gravitational force and the tension force in the cable.

In a free-body diagram, the forces acting on an object are represented as vectors pointing in the direction that the force is acting. When an elevator is suspended by a cable and is descending at a constant velocity, there are two main forces acting on the elevator:

Gravity is a force that acts downward on all objects and is equal to the mass of the object times the acceleration due to gravity (g). The force of gravity on an elevator can be represented as a downward-pointing vector.

The tension in the cable is the force exerted by the cable on the elevator that opposes the force of gravity. This force can be represented as an upward-pointing vector.

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The new charge on the second capacitor when two capacitors are connected in parallel is calculated to be 611× 10⁻¹⁴ C.

The formula Q = C V = C E d describes the charge held in a capacitor.

where,

C is capacitance

V is the potential across the capacitor

E is the uniform electric field

d is the distance between the plates

The energy stored in a capacitor is given by,

U = 1/2 C V² = 1/2 Q²/C = 1/2 A ε₀ E² d

where,

C is the capacitance

V is the voltage

Q is the charge stored

A is the area of the plates

ε₀ is 8.85 × 10⁻¹² F/m is the permittivity free space

E is the electric field

d is the distance

C₁ is given as 15 × 10⁻¹² F

C₂ is given as 65 × 10⁻¹² F

V₁ is given as 5 × 10³ V

Initial charge on the first capacitor is,

Q' = C₁ V₁ = 15 × 10⁻¹² × 5 × 10³ = 75× 10⁻⁹ C

When two capacitors are connected together, the equivalent capacitance of the new system is,

C = C₁ + C₂ = 15 × 10⁻¹² + 65 × 10⁻¹² = 80 × 10⁻¹² F

Voltage for the new system is, V = Q'/C = (75× 10⁻⁹)/(80 × 10⁻¹²) = 9.4× 10⁻² V

Charge on the second capacitor is,

Q₂ = C₂ V = 65 × 10⁻¹² × 9.4× 10⁻² = 611× 10⁻¹⁴ C

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The Angular Resolution measures the (a) the angular size of the smallest features that the telescope can see .

The Angular resolution is defined as a measure of the ability of an imaging device, such as a telescope or a camera, to distinguish fine details in an image.

It is expressed as an angle and represents the smallest separation between two objects that can still be distinguished as separate by the imaging device.

The Angular Resolution of a telescope is limited by the size of its aperture, the wavelength of the light it is observing, and the quality of its optics.

A Telescope with a larger aperture and high-quality optics will typically have a higher angular resolution, allowing it to see smaller and finer details.

The given question is incomplete , the complete question is

What does angular resolution measure ?

(a) the angular size of the smallest features that the telescope can see

(b) the brightness of an image

(c) the size of an image

(d) the number of electromagnetic waves captured by an image .

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The center of mass is usually near the middle of the suitcase and about halfway up its height and at a height that allows you to maintain good balance and control while running.

For a carry-on suitcase,. Keeping the center of mass low and close to your body can help reduce the amount of effort required to carry the suitcase, as well as improve stability and control while running.

When running with a suitcase, it's important to keep your upper body as upright and relaxed as possible, while allowing your legs and arms to move freely. This will help you maintain balance and reduce the strain on your muscles and joints. Additionally, it's helpful to grip the handle of the suitcase firmly, but not too tightly, so that you have control over its movement.

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The tuning forks will give rise to a beat frequency are 220 Hz and 260 Hz.

Tuning forks are available in a wide range of frequencies (64 Hz to 4096 Hz); 128 Hz is a commonly used frequency for screening.

Beat frequency formed by the tuning fork is given by: [tex]f_{beat} = f_1 \pm f_2[/tex].

Here, the beat frequency, [tex]f_{beat} = 20 Hz[/tex].

The frequency of a tuning fork, [tex]f_2 = 270\ Hz[/tex].

If  [tex]f_{beat} = f_1 + f_2[/tex],

[tex]f_1 = 20-240[/tex]

[tex]f_1 = 220\ Hz[/tex]

If  [tex]f_{beat} = f_1 - f_2[/tex],

[tex]f_1 = 20+240[/tex]

[tex]f_1 = 260\ Hz[/tex]

So, the tuning forks will give rise to a beat frequency are 220 Hz and 260 Hz. Hence, this is the required solution.

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--The complete question is, Two tuning forks are sounded at the same time. which tuning forks will give rise to a beat frequency of 20 hz when sounded together with a 240 hz tuning fork?--

It is known as a force that acts between moving surfaces as kinetic friction. The movement of a body on the surface is opposed by a force that is perceived.

There may still be friction between the surfaces even when they are moving past one another; this sliding friction is known as a kinetic frictional force.

Friction is a force that exists between two surfaces that are sliding or attempting to slide over one another. As an illustration, friction makes it difficult to push a book over the floor. An object is always moved by friction in the opposite direction from where it is moving or trying to move.

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The time taken is 2.3s for a spaceship hovering over the surface of Venus to drop an object from a height of 24m, and 2.21s for the same spaceship hovering over the surface of Earth to drop an object from the same height.

To solve this problem, we will use the motion equation to calculate the time of flight of an object on the surface of Venus and the Earth. The height is related by the following equation of motion:

h = v₀t + gt²/2

Because the object's initial velocity before dropping is zero, we can simplify the equation to:

h = gt²/2

We know the height h of the spaceship hovering, and Venus's gravity is g = 9.07m/s². Substituting the following values into the equation:

24m = (9.07 m/s²t²)/2

To calculate the time it takes an object dropped by a spaceship hovering from a height of 24m to reach the surface of Venus, we must remove t from the equation above, yielding:

t = [tex]\sqrt{2(24m)/9.07m/s^{2} }[/tex]

 = [tex]\sqrt{48m/9.07m/s^{2} }[/tex]

 = 2.3s

Similarly, to calculate the time it takes an object dropped from a height of 24m to reach the Earth's surface, and the gravity of the Earth is g = 9.81m/s² .

t = [tex]\sqrt{2(24m)/9.81m/s^{2} }[/tex]

 = [tex]\sqrt{48/9.81m/s^{2} }[/tex]

 = 2.21s

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A converging lens, also known as a positive lens, is a type of lens that has the ability to focus light rays to a single point, known as the focal point. This property can be utilized to ignite a piece of carbon paper.

When using a converging lens to burn carbon paper, care must be taken to position the lens such that sunlight (or another light source) is focused on the paper. As the light is focused, its intensity rises until it eventually reaches a temperature high enough to burn the carbon paper. The lens serves as a magnifying glass in this process, focusing the light beams onto a pinpoint area of the carbon paper and creating heat that eventually ignites the paper.

The size and temperature of the point of ignition will depend on the lens's distance from the paper, its size, and the angle at which the light rays are directed. The "fire by reflection" or "camera obscura" principle refers to this phenomenon. The principle of refraction, which asserts that light changes direction as it passes through various media with differing refractive indices, can be demonstrated in this way.

It is feasible to create a concentrated point of heat hot enough to ignite the carbon paper by employing a converging lens to focus the light.

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Newton's law of restitution is expressed in this formula. The restitution coefficient always fulfills 0e1. The balls continue to be in contact after the impact when e=0.

The equation yields the coefficient of restitution. Speed increase/decrease is the Coefficient of Restitution. We had to use the average height that we measured and enter it into the calculation in order to calculate speed. v = √(2gh) (2gh) where v = speed, g = 9.8 m/s2, and h = measured average height.

The coefficient of restitution is a value that ranges from 0 to 1. The difference between the velocity of two objects following a collision in a perfectly inelastic collision is zero because they things cling to one another.

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The Kline-McClintock uncertainty analysis is used to estimate the uncertainty associated with measurements of power output from a pump. The uncertainty is usually determined by analyzing the errors associated with the measurements taken and the accuracy of the equipment used.

The uncertainty of the pump power measurement in watt will depend on the accuracy of the measurements, the precision of the instruments used, and the degree of accuracy of the calculations. Generally, the uncertainty of the pump power measurement in watt can be estimated as the combined standard deviation of all measurement errors.

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Answer: I don't know sorry

Explanation:

yeah

Answer:

Z

Explanation:

Momentum = mass * velocity

      Z has the highest  mass * velocity = 15 * 3 = 45  kg m/s

At the 39.7 cm mark on the meter stick, the electric potential (relative to infinity) is -140.74 x 106 V.

Electric potential is the effort required to transport an units charge from one place to another in the presence of an electric field. Earth is typically chosen as the reference point, but any location outside the range of the applied electric charge can be used. potential electricity.

Let the negative charge be located at the left end of the meter stick and the positive charge at the right end. E = kq / x2, where k is the Coulomb constant (8.99 x 109 Nm2/C2) and q seems to be the charge at the left end of the meter stick, can be used to calculate the electric field at a location x cm from the left end of the meter stick (4.02 C).

The following equation can be applied to compute the electrical potential difference seen between left end of the meter stick & infinity:

ΔV left = -kq / d = -kq / 100 cm = -kq / 0.01 m = -8.99 x 10^9 Nm^2/C^2 * 4.02 C / 0.01 m = -359.57 x 10^6 V

Similarly, the electric potential difference between the right end of the meter stick and infinity can be calculated as:

ΔV right = kq / d = kq / 100 cm = kq / 0.01 m = 8.99 x 10^9 Nm^2/C^2 * 4.02 C / 0.01 m = 359.57 x 10^6 V

The total electric potential difference between the 39.7 cm mark and infinity can then be calculated as:

ΔV_total = ΔV_left + ΔV_right * (100 cm - 39.7 cm) / 100 cm = -359.57 x 10^6 V + 359.57 x 10^6 V * (100 cm - 39.7 cm) / 100 cm = -359.57 x 10^6 V + 218.83 x 10^6 V = -140.74 x 10^6 V

Therefore, the electric potential (V) at the 39.7 cm mark relative to infinity can be calculated as:

V = ΔV_total = -140.74 x 10^6 V

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The amount of work required to stretch the spring to 40 cm beyond its original length is 5333 J.

Spring is defined as an elastic object which gets deformed from its original shape when an external force is applied to it and again reverts back to its original shape when the external force is removed. When a force is placed on a material, the material stretches or compresses in response to the force. The length of the extension is directly proportional to the amount of force applied to it. Hence more the extension more the force is applied. Force and stretch are proportional to one another such that if you double the force applied, the amount of stretching of the spring will also be double. F 1 =kx 1, 3=k×20. This spring constant  k= 20/3 N/m. Now, W= ½ k x^2 =1/2×20/3×40×40= 5333 J.

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The distance from star A to star B is about 3.999 billion miles.

AU stands for "astronomical unit". It is a unit of measurement used in astronomy and represents the average distance from the Earth to the Sun, which is about 93 million miles (or 149.6 million kilometers).

If the average distance from star A to star B is 43 AU, then we can find the distance in miles by multiplying 43 by the distance of 1 AU from the sun, which is about 93 million miles:

Distance from star A to star B = 43 x 93,000,000 miles

Distance from star A to star B = 3,999,000,000 miles

Therefore, the distance from star A to star B is about 3.999 billion miles (or 3.999 x 10^9 miles).

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--The complete question is, The distance from Earth to the sun is defined as 1 astronomical unit, or AU. It is about 93 million miles, The average distance from star A to star B is 43AUs.

Find this distance in miles.--

The propulsive efficiency of the turbojet engine is approximately 12,500 N/kg/s and the specific thrust is approximately 250 N/kg/s.

The propulsive efficiency of a turbojet engine is defined as the ratio of the net thrust produced by the engine to the rate of energy supplied to the engine. The specific thrust is defined as the net thrust per unit mass flow rate of the engine.

To calculate these parameters, we need to determine the net thrust produced by the engine. This can be calculated using the equation:

Thrust = (V_e - V_0) × m_air + (p_e - p_0) × A_e

where V_e is the exhaust velocity, m_air is the air mass flow rate, V_0 is the velocity of the aircraft, p_e is the exit pressure, p_0 is the ambient pressure, and A_e is the exit area.

Substituting the given values, we get:

Thrust = (450 m/s - 200 m/s) × 250 kg/s + (35,000 Pa - 30,000 Pa) × 2 m^2 = (250 kg/s)(250 m/s) = 62500 N

The propulsive efficiency is given by:

η = net thrust / (fuel consumption rate) = 62500 N / (250 kg/s × 2.0%) = 62500 N / (250 kg/s × 0.02) = 62500 N / 5 kg/s = 12500 N/kg/s

The specific thrust is given by:

T_sp = net thrust / air mass flow rate = 62500 N / 250 kg/s = 250 N/kg/s

Therefore, the propulsive efficiency of the turbojet engine is approximately 12,500 N/kg/s and the specific thrust is approximately 250 N/kg/s.

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The direction of the electric field at the position indicated by the dot in the figure can be specified as an angle above the horizontal line. The angle is determined by the direction of the electric field vector at that point, which can be determined using the right-hand rule.

The direction of the electric field is determined by the sign of the charge, which is responsible for creating the field. Positive charges create an electric field that extends outward from them, while negative charges create an electric field that extends inward towards them. Additionally, the direction of the electric field is the same as the direction of the force it would exert on a positive test charge.

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The required energy the carriage has, when the displacement of the carriage and mass of the carriage with the baby are given is calculated to be 1029 J.

The energy in the above case is nothing but the work done by the carriage.

The work is defined as,

W = F d

where,

F is force

d is displacement

Entering the values in the above equation, we have,

W = F d = m × a × d = 5 × 9.8 × 21 = 1029 J

Thus, the required energy the carriage has is calculated to be 1029 J.

The given question is inappropriate. The question is 'a baby carriage is sitting at the top of a hill that is 21 m high. The carriage with the baby has a mass of 5kg whats the energy the carriage has?'

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The statements stands true. A vector have a component which is equal to zero and still have nonzero magnitude.

In a 2-D plane a vector can be resolved into the rectangular components. These are rectangular components to each other. These are available at right angles to each other. One component is directed along x-axis. It is the termed as horizontal component. The other one is directed along y-axis. Is termed as vertical component.

Sometimes, the vector is directed entirely either along x-axis or y-axis. When the vector is along x-axis or parallel to x-axis, then the complete magnitude will be directed along horizontal component. The vertical component will be zero. For a vector which is along y-axis, the horizontal component will be zero. The entire magnitude will be along y-axis.

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The average velocity for this trip is calculated by taking the total displacement (the difference between the final and initial positions) and dividing it by the total time.

In this case, the total displacement is 25 meters (50 meters west minus 25 meters east) and the total time is 100 seconds (60 seconds plus 40 seconds). Therefore, the average velocity for this trip is 0.25 meters per second.

Average velocity is a measure of the rate of change in an object's displacement over a period of time. It is calculated by dividing the change in an object's displacement by the time it took for the change to occur. Average velocity can be used to measure the speed of an object in a particular direction.

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Answer: .250m/s

Explanation:

The impulse required to stop the 10-kg bowling ball moving at 7.0 m/s is -70 kg m/s.

The impulse required to stop a moving object can be calculated using the principle of momentum conservation.

The formula for impulse can be given as:

I = Δp = mΔv

where I is the impulse, Δp is the change in momentum, m is the mass of the object, and Δv is the change in velocity.

In this case, the initial velocity of the 10-kg bowling ball is 7.0 m/s and it needs to be brought to a stop, so its final velocity is 0 m/s.

Therefore, the change in velocity can be given as:

Δv = vf - vi = 0 - 7.0 m/s = -7.0 m/s

Substituting the values in the formula for impulse, we get:

I = Δp = mΔv = 10 kg × -7.0 m/s = -70 kg m/s

So, the impulse required to stop the 10-kg bowling ball moving at 7.0 m/s is -70 kg m/s. The negative sign indicates that the impulse is acting in the opposite direction to the velocity of the ball.

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It would take 8 J of work to stretch the spring from 1 m to 1.2 m.

The work required to stretch a spring is given by the formula:

[tex]W = (1/2)kx^2,[/tex] where W is the work done, k is the spring constant, and x is the distance the spring is stretched or compressed.

Given that the spring requires 10 J of work to stretch from 1 m to 1.1 m, we can calculate the spring constant as follows:

[tex]10 J = (1/2)k(0.1 m)^2[/tex]

[tex]k = 200 J/m[/tex]

Using this spring constant, we can calculate the work required to stretch the spring from 1 m to 1.2 m:

[tex]W = (1/2)(200 J/m)(0.2 m)^2[/tex]

[tex]W = 8 J[/tex]

Therefore, it would take 8 J of work to stretch the spring from 1 m to 1.2 m.

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As a result, the sound wave's frequency and wavelength are 440 Hz and 5.4 m, respectively, for a bike traveling at either 10.0 m/s toward the bagpiper or away from him.

The quantity of waves passing a fixed place in a unit of time is known as the frequency in physics. A body undergoing periodic motion undergoes how many cycles or vibrations in one unit of time, according to this definition.

They have a relationship between frequency and amplitude and the quantity of energy they transport. Energy is inversely correlated with frequency and amplitude, increasing with higher frequency.

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This individual launches a ball upward at a 15 meter per second beginning speed. We'll assume that the ball is held in the guy's mouth at beginning height zero meters.

What is the speed measurement unit?

Units of speed include nautical miles per hour (kn or kt), feet per minute (symbol fps or ft/s), kilometers per hour (symbol km/h), miles an hour (symbol km in or mph), and metres per moment (symbol μ s 1 or m/s), the SI-derived unit. Speed multiplied by the sound speed is known as the dimensionless Mach number;

What does speed have a shorthand for?

L T-1. The parameters of speed are time divided by distance. The most often used measure of speed in daily life is the kilometer per hour, or miles per hour in the United States and the UK. The Si derived unit of velocity is the meter per second.

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The goalie slides on the ice with the speed of 0.0498 m/s. The result is obtained by using the Law of Conservation of Momentum.

The Law of Conservation of Momentum states that the total momentum in a closed system before and after the collision is constant.

It can be expressed as

m₁v₁ + m₂v₂ + ... = m₁v₁' + m₂v₂' + ...

Where

A 0.105-kg hockey puck moving at 29.0 m/s is caught and held by a 61.0 kg goalie at rest. Find the speed does the goalie slide on the ice!

We have

They are collided inelastically. The hockey puck eventually moves with the goalie at the same speed, v.

So,

m₁v₁ + m₂v₂ = (m₁ + m₂)v'

0.105(29) + 0 = (0.105 + 61.0)v'

3.045 = (61.105)v'

v' = 0.0498 m/s

Hence, the speed of the goalie sliding after holding the hockey puck is 0.0498 m/s.

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The required type of motion can Margaret predicts this coin will have is a circling motion. Option B is correct.

motion is defined as an object's change of position over time is called motion.

Here,

As Margaret drops a coin down a funnel-shaped object. The coin rolls around the outer edge in a circular motion. As it moves closer to the bottom, it completely rolls around the edge.

Margaret can predict that the second coin will have a circling motion as it moves down the funnel-shaped object. The shape of the funnel will cause the coin to roll around the edge in a circular motion.

Thus, the required type of motion can Margaret predicts this coin will have is a circling motion. Option B is correct.

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