6.
Mg(s) + 2 HCl(aq) → MgCl₂(aq) + H₂(g)
The chemical equation shown above represents the reaction between Mg(s) and HCl(aq). When 12.15 g of
Mg(s) is added to 500.0 mL of 4.0 M HCl(aq), 95 kJ of heat is released. The experiment is repeated with
24.30 g of Mg(s) and 500.0 mL of 4.0 M HCl(aq). Which of the following gives the correct value for the
amount of heat released by the reaction?

The correct option is C. Friction is the force that keeps your tires from sliding around on the road.

Friction is the force exerted by a surface when an object moves across it. It always acts in the opposite direction of the movement of the object. That is it resists the movement of the object and if there's no force acting on the moving object, the frictional force will eventually stop the motion of the object.

In absence of friction the tires of the vehicles and even humans would not have been able to cover a distance without slipping and falling.

Therefore, the correct option is C. Friction is the force that keeps your tires from sliding around on the road.

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The pH of the original buffer solution is 43.85 mM.

To calculate the pH of the original buffer solution, use the Henderson-Hasselbalch equation:

pH = pKa + log([A^-]/[HA])

Where

pKa = acid dissociation constant of the weak acid (acetic acid in this case),

[A^-] = concentration of the conjugate base (acetate ion), and

[HA] = concentration of the weak acid (acetic acid).

Calculate the concentrations of acetate ion and acetic acid in the original buffer solution. Therefore:

(3509.9 mg) / (136 g/mol) = 25.81 mmol NaC₂H₂O₂·3H₂O

Since NaC₂H₂O₂·3H₂O dissociates completely into Na⁺ and C₂H₃O₂⁻ in solution:

[NaC₂H₂O₂·3H₂O] = [C₂H₃O₂⁻] = 25.81 mM

The pH of the original buffer solution is 4.80 means that:

pH = pKa + log([A^-]/[HA])

4.80 = pKa + log([C₂H₃O₂⁻]/[HA])

Rearrange this equation to solve for pKa:

pKa = pH - log([C₂H₃O₂⁻]/[HA])

Substituting the given values:

pKa = 4.80 - log(25.81 mM / [HA])

Calculate [HA]:

Mass of NaC₂H₂O₂·3H₂O = Mass of C₂H₄O₂ (acetic acid) + Mass of C₂H₃O₂⁻ (acetate ion)

3509.9 mg = Mass of C₂H₄O₂ + (25.81 mM) × (136 g/mol) × (1 L / 1000 mM) × (1000 g / 1 kg)

Solving for the mass of C₂H₄O₂:

Mass of C₂H₄O₂ = 3509.9 mg - (25.81 mM) × (136 g/mol) × (1 L / 1000 mM) × (1000 g / 1 kg)

Mass of C₂H₄O₂ = 2634.4 mg

Now calculate [HA]:

[HA] = (2634.4 mg / 60.05 g/mol) × (1 L / 1000 g) × (1000 mM / 1 L)

[HA] = 43.85 mM

Substituting this into the equation for pKa:

pKa = 4.80 - log(25.81 mM / 43.85 mM)

pKa = 4.80 + 0.222

pKa = 5.02

Use the Henderson-Hasselbalch equation to calculate the pH of the original buffer solution with [A^-] = [C₂H₃O₂⁻] = 25.81 mM and [HA] = 43.85 mM

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The charge on the ions in an ionic compound containing cobalt(III) and fluoride ions is Co³⁺ and F⁻¹ and the formula of the compound is CoF₃.

Ionic compounds are a type of chemical compound where the oppositely-charged ions of a metal and a nonmetal are attracted to each other to form an ionic bond.

The compound formed from the bonded ions will have very different properties from the elements that make up the compound.

While atoms are neutral because they have an equal number of protons and electrons, ions have a net charge and result when an atom loses or gains electrons.

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Answer: 5,266

Explanation:

5,266

The mass (in grams) of NaCl present in 87.5 moles of NaCl is 5118.75 grams

From the question given above, the following data were obtained:

Mole is related to mass and molar mass as follow:

Mole = Mass / Molar mass

Inputting the given parameters, we can obtain the mass of NaCl as follow:

87.5 = Mass of NaCl / 58.5

Cross multiply

Mass of NaCl = 87.5 × 58.5

Mass of NaCl = 5118.75 grams

Therefore, the mass of NaCl present is 5118.75 grams

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To neutralize 11.3 mL of 0.16 M HCl in stomach acid, 0.001632 grams of KOH required are 0.10145

Potassium hydroxide, also known as caustic potash, is an inorganic compound with the formula KOH. It's a strong base, dissolving easily in water, creating a strongly alkaline solution. The reaction between an acid and a base that produces water and a salt is called neutralization. A salt is a compound that is formed when the hydrogen ion in an acid is replaced by a metal ion or another positive ion.

The balanced chemical equation for the reaction is:

HCl(aq) + KOH(aq) → H₂O(l) + KCl(aq)

The equation tells us that 1 mole of HCl is neutralized by 1 mole of KOH, thus the amount of KOH required is equal to the amount of HCl. For this specific problem, we are given 11.3 mL of 0.16 M HCl, which we will need to convert to moles of HCl.

11.3 mL of 0.16 M HCl = 11.3 × 0.16/1000 = 0.001808 mol of HCl

To neutralize this much HCl, we need 0.001808 mol of KOH.

The molar mass of KOH is 56.11 g/mol.

Thus, the mass of KOH needed is:

0.001808 mol × 56.11 g/mol

= 0.10144688 g or 0.10145 g of KOH (rounded to four significant figures).

Therefore, to neutralize 11.3 mL of 0.16 M HCl in stomach acid, 0.10145 grams of KOH are required.

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The molecular mass of the gas, given that 2.63 g of the gas occupied 0.98 L at standard conditions of temperature and pressure is 60 g/mol

First, we shall obtain the mole of the gas. Details below:

PV = nRT

1 × 0.98 = n × 0.0821 × 273

0.98 = n × 22.4133

Divide both sides by 22.4133

n = 0.98 / 22.4133

n = 0.0437 mole

Finally, we shall obtain the molecular mass of the gas. This is shown below:

Molar mass = mass / mole

Molar mass of gas = 2.63 / 0.0437  

Molar mass of gas = 60 g/mol

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The balanced equation for the reaction between benzene and chlorine gas is: C6H6 + Cl2 → C6H5Cl + HCl

In this reaction, benzene reacts with chlorine gas to produce chlorobenzene and hydrogen chloride as a byproduct.

This reaction is an example of electrophilic aromatic substitution, where the chlorine molecule acts as an electrophile, or electron-poor species, and the benzene ring acts as a nucleophile, or electron-rich species.

The chlorine molecule is first activated by a catalyst, such as iron or aluminum chloride, to become an electrophile that can react with the benzene ring.

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Chlorobenzene, C6H5Cl, is used in the production of chemicals such as aspirin and dyes. One way that chlorobenzene is prepared is by reacting benzene, C6H6, with chlorine gas according to the following BALANCED equation. C6H6 (l) + Cl2 (g) → C6H5Cl (s) + HCl (g).

a. To calculate the theoretical yield of chlorobenzene, we need to use stoichiometry to determine how many moles of chlorobenzene can be produced from 45.6 g of benzene.

The molar mass of benzene (C6H6) is 78.11 g/mol.

We start by calculating the number of moles of benzene

45.6 g C6H6 x (1 mol C6H6/78.11 g C6H6) = 0.583 mol C6H6

From the balanced equation, we see that 1 mole of benzene reacts with 1 mole of chlorine gas to produce 1 mole of chlorobenzene. Therefore, the number of moles of chlorobenzene produced will be the same as the number of moles of benzene

0.583 mol C6H6 x (1 mol C6H5Cl/1 mol C6H6) = 0.583 mol C6H5Cl

Now, we can calculate the theoretical yield of chlorobenzene

Theoretical yield = number of moles of C6H5Cl x molar mass of C6H5Cl

The molar mass of chlorobenzene (C6H5Cl) is 112.56 g/mol.

Theoretical yield = 0.583 mol C6H5Cl x 112.56 g/mol = 65.6 g C6H5Cl

Therefore, the theoretical yield of chlorobenzene is 65.6 g.

b. The percent yield can be calculated using the formula

Percent yield = (actual yield / theoretical yield) x 100%

Putting in the given values

Percent yield = (63.7 g / 65.6 g) x 100% = 97.1%

Therefore, the percent yield of chlorobenzene is 97.1%.

The given question is incomplete and the complete question is '' Chlorobenzene, C6H5Cl, is used in the production of chemicals such as aspirin and dyes. One way that chlorobenzene is prepared is by reacting benzene, C6H6, with chlorine gas according to the following BALANCED equation. C6H6 (l) + Cl2 (g) → C6H5Cl (s) + HCl (g).

a. What is the theoretical yield if 45.6 g of benzene react?

b. If the actual yield is 63.7 g of chlorobenzene, calculate the percent yield''.

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If the object takes 3.62s to fall from a height of 65.0m then the speed of the object is 17.95m/s

According to the scenario, the object is falling from a height, so it is likely to follow a straight path.

When the motion of a body is in a straight line, it's speed will be numerically equal to it's velocity.

Mathematically, velocity could be calculated as follows

 [tex]\rm Velocity\ =\ \frac{displacement}{time}[/tex]

Here, the displacement of the object is the total height from where it is dropped.

Therefore, [tex]\rm Velocity\ =\ \frac{65.0}{3.62}[/tex]

                                 [tex]=\ 17.95\ m/s[/tex]

So if the object takes 3.62s to fall from a height of 65.0m then the speed of the object is 17.95m/s

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A major purchase refers to a high-cost item or service that is considered a significant investment for an individual or household, such as a car, home, or college education. Major purchases usually involve a large sum of money and require careful planning and consideration before a final decision is made.

Any item that a person or a household buys for their own use or consumption is called a consumer good. Durable and non-durable goods are two types of consumer goods that can be classified. Consumer goods are tangible items that people or households buy for their own use or consumption.

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Your question is incomplete, most probably the complete question is:

The difference between Major purchase and Consumer good​?

We can not use a salt bridge saturated with potassium chloride solution in an electro-chemical cell made from a Ag/Ag+ cathode and a Cu/Cu²+ anode because it will precipitate.

An electrochemical cell that uses a weak electrolyte and a salt bridge to connect oxidation as well as reduction half cells. A junction that joins the anodic with cathodic compartments of a cell and electrolytic solution is referred to as a salt bridge.

Because both chloride and potassium ions have very similar diffusion coefficients and minimise junction potential, the inactive minerals potassium chloride (KCl) frequently used. We can not use a salt bridge saturated with potassium chloride solution in an electro-chemical cell made from a Ag/Ag+ cathode and a Cu/Cu²+ anode because it will precipitate.

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The concentration of NaCl (salt) when 4.9 moles are dissolved in 7 liters of water is 34.3M

Molarity is a unit of concentration measuring the number of moles of a solute per litre of solution.

Chemists primarily need the concentration of solutions to be expressed in a way that accounts for the number of particles that react according to a particular chemical equation. Since percentage measurements are based on either mass or volume, they are generally not useful for chemical reactions. A concentration unit based on moles is preferable.

Given,

Moles of NaCl = 4.9 moles

Volume = 7 L

Concentration = moles × volume (L)

= 34.3 M

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1. Examples of solids, liquids, and gases found in a home

Solids: books, furniture, toys

Liquids: water, juice, shampoo

Gases: air, natural gas, propane

2. The human body contains solids, liquids, and gases. Solids include bones, muscles, and organs. Liquids include blood, saliva, and urine. Gases include air in the lungs and dissolved gases in the bloodstream. The body is mostly made up of liquids, as they make up a large percentage of its overall volume.

3. If you needed to remove the water from a sample of blood to study the solids that remained, you could use a process such as evaporation or freeze-drying. Evaporation involves heating the sample to allow the water to evaporate, leaving behind the solids. Freeze-drying involves freezing the sample and then removing the water under vacuum, leaving behind a dry solid.

4. Some metals that could be found within the human body include iron, zinc, and copper. These metals are commonly found in foods such as meat, seafood, nuts, and whole grains. Other metals such as calcium, magnesium, and potassium are also important for the body and are found in a variety of foods.

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The ideal gas law may be used to determine the volume of oxygen created in the electrolysis that produces 548 litres of hydrogen at STP (Standard Temperature and Pressure). PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature, according to the ideal gas equation.

The pressure is 1 atm, the temperature is 273 K, and the number of moles of hydrogen is 548/22.4 = 24.5 in this example. We may compute the volume of oxygen created by rearranging the ideal gas law: V = nRT/P = 24.5*0.082*273/1 = 483.3 litres.

As a result, the volume of oxygen created in the electrolysis at STP that produces 548 litres of hydrogen is 483.3 litres.

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Answer:

D.) State the question, form a hypothesis, conduct an experiment

Explanation:

https://www.colorincolorado.org/article/steps-scientific-process

At a pressure of 939 mbar, the corresponding height of the mercury in the column of a mercury barometer is approximately 141.9 cm.

The height of the mercury column in a barometer is proportional to the atmospheric pressure. The proportionality constant depends on the density of mercury and the acceleration due to gravity. At standard conditions, the height of the mercury column in a barometer is about 760 mm.

To find the height of the mercury column at a pressure of 939 mbar, we can use the following proportion;

pressure / height = constant

The constant is the product of the density of mercury and the acceleration due to gravity, which we can take as 13,595 kg/m^3 * 9.81 m/s^2 = 133,322 Pa/m.

Substituting the given pressure and the constant, we get;

939 mbar / height = 133,322 Pa/m

Solving for height, we get;

height = 133,322 Pa/m / 939 mbar

= 141.9 cm

Therefore, the height of the mercury in the column of a mercury barometer is 141.9 cm.

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Answer:

56.96 grams

Explanation:

To find the mass of 1.78 moles of O2, we need to use the molar mass of O2, which is the mass of one mole of O2.

The chemical formula for O2 is O-O or simply O2. The molar mass of O2 is the sum of the atomic masses of two oxygen atoms, which can be found on the periodic table.

The atomic mass of oxygen (O) is approximately 16.00 g/mol. So the molar mass of O2 is:

Molar mass of O2 = 2 x atomic mass of O

= 2 x 16.00 g/mol

= 32.00 g/mol

Therefore, the mass of 1.78 moles of O2 is:

Mass = number of moles × molar mass

= 1.78 mol × 32.00 g/mol

= 56.96 g

So the mass of 1.78 moles of O2 is 56.96 grams.

The given statement "A parasitic way of life can be best demonstrated by the feeding adaptations of the spider." is False. Because, While some spiders are parasites, not all spiders are parasitic.

Additionally, many spiders are not even true parasites, as they typically do not harm their host organism. Spiders are typically classified as predators, as they feed on other insects and arthropods. While some spiders may occasionally feed on the blood of larger animals, such as birds or mammals, this behavior is not typically considered parasitic, as it does not involve a long-term relationship between the spider and the host organism.

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The exit gas stream has an average molecular weight of 29.0 g/mol and the amount of leftover Phenanthrene in the reactor is 5377 g.

Start by calculating the stoichiometric amount of air required to burn 10 kg of Phenanthrene. The balanced chemical equation for the combustion of Phenanthrene is:

C₁₄H₁₀ + 19O₂ → 14CO2 + 5H₂O

Therefore, to burn 10 kg (10000 g) of Phenanthrene:

nO₂ = 19 x (10000 g / 178.24 g/mol) = 1065.5 mol

So the actual amount of oxygen supplied will be:

nO₂, supplied = 0.7 x nO₂ = 745.9 mol

The amount of air required to supply this much oxygen can be calculated using the ideal gas law:

PV = nRT

where P = pressure, V = volume, n = number of moles, R = gas constant, and T = temperature.

Assuming standard temperature and pressure (STP):

P = 1 atm = 101.3 kPa

T = 273 K

R = 8.314 J/mol.K

The volume of air required is then:

Vair = nair × RT/P = (nO₂,supplied + nN₂,supplied) × RT/P

where nN₂,supplied = number of moles of nitrogen in the supplied air.

Since air is about 79% nitrogen by volume, assume that the number of moles of nitrogen is proportional to the number of moles of oxygen:

nN₂,supplied = (0.79/0.21) x nO₂,supplied = 2807.2 mol

Therefore,

Vair = (nO₂,supplied + nN₂,supplied) × RT/P

= (745.9 + 2807.2) × 8.314 × 273 / 101.3

= 63106 L

Calculate the average molecular weight of the exit gas stream using the ideal gas law again:

n = PV/RT

where n = number of moles of gas, P = pressure, V = volume, R = gas constant, and T = temperature.

Assuming that the combustion products are at the same temperature and pressure as the supplied air (STP):

nCO₂ = nH₂O = nO₂,supplied = 745.9 mol

nN₂ = nN₂,supplied = 2807.2 mol

The total number of moles of gas in the exit stream is then:

ntotal = nCO₂ + nH₂O + nN₂ = 745.9 + 745.9 + 2807.2 = 4298.0 mol

The volume of the exit stream can be calculated using the ideal gas law:

Vexit = ntotal × RT/P = 4298.0 × 8.314 × 273 / 101.3 = 36534 L

The average molecular weight of the exit gas stream is then:

M = mtotal/ntotal

where mtotal = total mass of gas in the exit stream.

Calculate mtotal by adding up the mass of each component in the exit stream:

mtotal = mCO₂ + mH₂O + mN₂

where mCO₂, mH₂O, and mN₂ = masses of carbon dioxide, water vapor, and nitrogen, respectively.

Calculate these masses using the molecular weights of the compounds and the number of moles:

mCO₂ = nCO₂ × MCO₂ = 745.9 × 44.01 g/mol = 32804 g

mH₂O = nH₂O × MH₂O = 745.9 × 18.02 g/mol = 13419 g

mN₂ = nN₂ × MN₂ = 2807.2 × 28.01 g/mol = 78617 g

Therefore,

mtotal = mCO₂ + mH₂O + mN₂ = 32804 + 13419 + 78617 = 124840 g

Substituting into the equation:

M = mtotal/ntotal = 124840 g/4298.0 mol = 29.0 g/mol

So the exit gas stream has an average molecular weight of 29.0 g/mol.

The leftover Phenanthrene amount can be calculated as follows:

mPhenanthrene,leftover = mPhenanthrene,initial - mCO₂ - mH₂O

where mPhenanthrene,initial = initial mass of Phenanthrene, which is 10 kg (10000 g).

Substitute these values into the equation:

mPhenanthrene,leftover = 10000 - 32804 - 13419 = 5377 g

Therefore, the amount of leftover Phenanthrene in the reactor is 5377 g.

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When two oppositely charged particles are closer together, they have a stronger attraction toward one another than if they are farther apart.

The electrostatic force, which is the force of attraction or repulsion between two charged particles, is the cause of this attraction. The magnitude of the electrostatic force between two charged particles is inversely proportional to the square of the distance between them and directly proportional to the product of their charges.

The inverse square law states that as the distance between two charged particles moves closer together, the electrostatic force between them grows as a result of a smaller denominator. Therefore, the stronger the attraction between two oppositely charged particles will be the closer they are.

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The expression of the Ksp is Ksp =  [Ca²+] [2OH-]^2

In the balanced chemical equation for the solute's dissolution, Ksp is defined as the product of the ion concentrations in a saturated solution, each concentration being raised to the power of its stoichiometric coefficient.

Ksp is temperature-dependent and varies with different compounds. It is used to predict the maximum amount of a compound that can dissolve in a given solvent under specific conditions.

We know that we can be able to use the expression that has been given in the problem to arrive at the fact that;

Ksp =  [Ca²+] [2OH-]^2

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6 moles of oxygen gas will produce 134.4 liters of water vapor.

According to the balanced equation for cellular respiration:

[tex]C_6H_{12}O_6 + 6O_2[/tex] → [tex]6H_2O + 6CO_2[/tex]

The molar volume of any gas at standard temperature and pressure (STP) is 22.4 L.

Therefore, to calculate the volume of water vapor produced from 6 moles of oxygen gas, we need to determine the number of moles of water vapor produced and then convert that to volume:

6 moles of oxygen gas produce 6 moles of water vapor

1 mole of water vapor at STP = 22.4 L

Therefore, 6 moles of water vapor at STP = (6 moles) x (22.4 L/mole) = 134.4 L

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For a chemical reaction C₂H₆ + 137 kJ → C₂H₄ + H₂, the chemical energy of the reactant and the chemical energy of the products are equal. Option D is correct.

In an exothermic reaction, energy is released as the reactants are converted to products. The negative sign on the enthalpy change (ΔH) indicates that the reaction is exothermic, meaning that energy is released by the system to the surroundings. This energy comes from the chemical energy of the reactants, and in this case, 137 kJ of energy are released.

The chemical energy of a substance is the energy stored in the bonds between its atoms. In this reaction, C₂H₆ (ethane) is converted to C₂H₄ (ethylene) and H₂ (hydrogen gas), which means that some of the bonds in the reactant molecule are broken and new bonds are formed in the product molecules.

The total amount of energy stored in the bonds of the reactants is equal to the total amount of energy stored in the bonds of the products, since energy cannot be created or destroyed, only converted from one form to another. Therefore, the chemical energy of the reactant and the chemical energy of the products are equal.

Hence, D. is the correct option.

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Answer:

0.268

Explanation:

If you want to know how much of a radioactive substance is left after some time, you need to use some fancy math and some weird symbols. First, you need to know the decay constant (λ), which tells you how fast the stuff is disappearing. Then, you need to know the half-life (T1/2), which tells you how long it takes for half of the stuff to go poof. The formula to find out how much stuff is left is:

N = N0 ⋅ e − λt

where:

N = the amount of stuff left after time t N0 = the amount of stuff you started with λ = the decay constant t = the time that passed e = some number that nobody knows (just kidding, it's about 2.718)

For example, let's say you have some krypton-85, which is a radioactive gas that glows green. You have 100 grams of it and you want to know how much is left after 25 years. The half-life of krypton-85 is 10.76 years, so you can find the decay constant using this formula:

λ = ln 2 / T1/2

where:

ln 2 = natural log of 2 (about 0.693) T1/2 = half-life

So, you plug in the numbers and get:

λ = ln 2 / 10.76 λ ≈ 0.0644 year−1

Now you can use this value to find out how much krypton-85 is left using the first formula:

N/N0 = e − λt N/N0 = e − (0.0644)(25) N/N0 ≈ 0.268

This means that after 25 years, you have about 26.8% of krypton-85 left, or about 26.8 grams. The rest has turned into something else, probably something boring like argon or oxygen. The answer is 0.268.

The  name of the organic compound with structural formula of nine carbons and sixteen hydrogens  depends on different factors

The nomenclature of the organic molecule comprising nine carbons and sixteen hydrogens is determined by the arrangement of its atoms as well as the nature of the chemical bonds linking them together. Cyclononane is a circular formation of nine carbon atoms.

An organic substance belongs to a group of chemicals that have carbon atoms linked to each other and other atoms through covalent bonds, and are present in the biological cells. Organic compounds contain usual elements such as carbon, as well as hydrogen, oxygen, and nitrogen.

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Considering the definition of empirical and molecular formula, if the molecular formula mass of the compound is 60.0 g/mol, the molecular formula is N₂O₂.

The empirical formula is the simplest expression to represent a chemical compound, which indicates the elements that are present and the minimum proportion in whole numbers that exist between its atoms.

The molecular formula is the chemical formula that indicates the number and type of distinct atoms present in the molecule. The molecular formula is the actual number of elements that make up a molecule.

The empirical formula and the molecular formula are generally related in the following way:

Molecular Formula = n× Empirical Formula

where n is n=molecular mass÷ empirical mass

In this case, in first place you need to convert the number of grams given into percentage as follow:

Assuming a 100 grams sample, the percentages match the grams in the sample. So you have:

Then it is possible to calculate the number of moles of each atom in the molecule, taking into account the corresponding molar mass:

The empirical formula must be expressed using whole number relationships, for this the numbers of moles are divided by the smallest result of those obtained. In this case:

Therefore the N: O mole ratio is 1: 1

Finally, the empirical formula is N₁O₁= NO

The molecular mass is 60.0 g/mol and the empirical mass is 30 g/mole. Then, the value of n is:

n=60 g/mole÷ 30 g/mole

Solving:

n=2

Being the Molecular Formula = n× Empirical Formula, the you can calculate:

Molecular Formula = 2× (NO)

Molecular formula= N₂O₂

Finally, the molecular formula is N₂O₂.

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Answer:

The balanced chemical equation for the decomposition of solid lithium chloride into chlorine gas and solid lithium can be written as:

2LiCl(s) → 2Li(s) + Cl2(g)

This equation shows that for every 2 moles of solid lithium chloride, 2 moles of solid lithium and 1 mole of chlorine gas are produced. The equation is balanced because the number of atoms of each element is the same on both sides of the equation. There are 2 lithium atoms, 2 chlorine atoms, and 0 oxygen atoms on both the reactant and product side of the equation.

There are approximately 189.3 liters of hydrogen gas produced at STP.

To solve this problem, we need to use the ideal gas law:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.

At STP, the pressure is 1 atm and the temperature is 273 K. We can use Avogadro's number to convert the number of particles to moles:

[tex]n = 5.02*10^{30}\ particles / 6.022*10^{23}\ particles/mol =[/tex] 8.34 mol of [tex]H_2[/tex]

From the balanced chemical equation, we know that 1 mole of aluminum reacts to produce 1 mole of [tex]H_2[/tex]. Therefore, 8.34 moles  [tex]H_2[/tex] were produced.

Using the ideal gas law, we can solve for the volume of [tex]H_2[/tex]:

V = nRT/P =[tex](8.34 mol)(0.08206 L.atm/(mol.K))(273 K)/(1 atm)[/tex] = 189.3 L

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