6. The figure below is composed of nine congruent
squares. What is the area of the shaded portion?
12 in
Ath 12 in

Answer:

The answer would be 195 Strikeouts

Step-by-step explanation:

You take the number of each x then times by the number on the bottom so in this case, you have 3 15s that would be 45. for the 16s you have 5 so you do this math and you end up with 80 and keep going until you did all of them then add them up and that's your answer.

Let's analyze the data

Now lets solve:

      Total number of strikeouts = 3 * 15 + 5 * 16 + 2*17 + 2*18

                                                     = 15 + 80 + 34 +36

                                                     = 95 + 70 = 165

Hope that helps!

Answer:

[tex]\frac{5}{6}:1[/tex]

Step-by-step explanation:

[tex]10:12[/tex] divide both sides of this ratio by 12 to give a ratio in the form [tex]n:1[/tex]

[tex]\frac{10}{12}:1[/tex] which simplifies to [tex]\frac{5}{6}:1[/tex]

The sales receipt for the purchase includes the sales tax

The sales tax is calculated as:

Percentage sales tax * (Sum of Items subjected to tax) =  Sales tax.

So, we have:

T * (3 + 0.5) =  0.21

Evaluate the sum

T * (3.5) =  0.21

Divide both sides by 3.5

T =  6%

Hence, the sales tax is 6%

The price (p) at the top is calculated using:

p = 13 - 3 - 2 - 0.5

Evaluate the difference

p = 7.5

Hence, the price at the top is $7.50

60% of the original price (P) is p.

So, we have:

60% * P = p

Substitute 7.5 for p

60% * P = 7.5

Divide both sides by 60%

P = 12.5

Hence, the original price at the top is $12.50

Read more about sales tax and discounts at:

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Answer:

x = -1.33333333333

Step-by-step explanation:

[tex]\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}[/tex]

[tex]-2x+1-1=4x+9-1[/tex]

[tex]\mathrm{Simplify}[/tex]

[tex]-2x=4x+8[/tex]

[tex]\mathrm{Subtract\:}4x\mathrm{\:from\:both\:sides}[/tex]

[tex]-2x-4x=4x+8-4x[/tex]

[tex]\mathrm{Simplify}[/tex]

[tex]-6x=8[/tex]

[tex]\mathrm{Divide\:both\:sides\:by\:}-6[/tex]

[tex]\frac{-6x}{-6}=\frac{8}{-6}[/tex]

[tex]x=-\frac{4}{3}[/tex]

[tex]x=-1.33333333333[/tex]

~Lenvy~

Answer:

Step-by-step explanation:

emma really smells bad do not answer this question

The factorization of the given expression [tex]\rm x^2+10x+21[/tex] is (x+3)(x+7) the option first is correct.

It is given that the expression [tex]\rm x^2+10x+21[/tex]

It is required to find which expression is the factorization of the given expression, the options are:

a) (x + 3)(x + 7)

b) (x + 4)(x + 6)

c) (x + 6)(x + 15)

d) (x + 7)(x + 14)

Polynomial is the combination of variables and constants in a systematic manner with "n" number of power in ascending or descending order.

We have an expression:

[tex]\rm x^2+10x+21[/tex]

[tex]\rm x^2+7x+3x+21[/tex]  

Breaking 10x into 7x and 3x because the multiplication of 7x and 3x is [tex]\rm 21x^2[/tex] and the addition is 10x.

[tex]\rm x^2+7x+3x+21\\\\\rm x(x+7)+3(x+7)\\\\\rm (x+7)(x+3)[/tex]or

[tex]\rm (x+3)(x+7)[/tex]

Thus, the factorization of the given expression [tex]\rm x^2+10x+21[/tex] is (x+3)(x+7) the option first is correct.

Learn more about Polynomial here:

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The probability that a worker chosen at random works at least 8 hours is Option C: 0.84 approx.

Suppose the random variable in consideration be X, and it is discrete.

Then, the probability of X attaining at least 'a' is written as:

[tex]P(X \geq a)[/tex]

It is evaluated as:

[tex]P(X \geq a) = \sum_{\forall \: x_i \geq a} P(X = x_i)[/tex]

The probability distribution of X is:

        x                      f(x) = P(X = x)

        6                               0.02
        7                               0.11

        8                               0.61

        9                               0.15

        10                              0.09

Worker working at least 8 hours means X attaining at least 8 as its values.

Thus, probability of a worker chosen at random working 8 hours is

P(X ≥ 8) = P(X = 8) + P(X = 9) +P(X = 10) = 0.85 ≈ 0.84 approx.

By the way, this probability distribution seems incorrect because sum of probabilities doesn't equal to 1.

The probability that a worker chosen at random works at least 8 hours is Option C: 0.84 approx.

Learn more about probability distributions here:

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Answer:

For example, 16/21

Step-by-step explanation:

Are there choices?

There is an infinite number of numbers between any two numbers.

2/3 = 14/21

6/7 = 18/21

One example of a fraction between 2/3 and 6/7 is 16/21

16/21 is between 2/3 and 6/7.

Given:

[tex]\\[/tex]

❍Let's assume, Length of rectangle x feet and width of the rectangle x - 5 feet respectively.

[tex]\\[/tex]

To calculate the dimensions of the rectangle we will use the formula of Area of rectangle:

[tex]\\[/tex]

[tex] \: \: \: \: \: \: \: { \underline{ \boxed{ \pmb{ \frak{ Area_{(rectangle)} = Length \times width }}}}} \\ \\ [/tex]

[tex]\\[/tex]

[tex] \underline {\sf{Substituting \: the \: values~ in~ above~formula: }} \\ [/tex]

[tex]\\[/tex]

[tex] : \implies \sf \:x \times (x - 5) = 126 \\ \\ \\ : \implies \sf \:x^2 - 5x = 126 \\ \\ \\ : \implies \sf \:x^2 - 5x - 126 = 0 \\ \\ \\ : \implies \sf \:x^2 - 14x - 9x - 126 = 0 \\ \\ \\ : \implies \sf \:x (x - 14) - 9 (x + 14) = 0 \\ \\ \\ : \implies \sf \:(x - 14)(x - 9) = 0 \\ \\ \\ : \implies { \boxed { \purple{\pmb { \: x = 14 \: \: or \: \: x = -9}}} } \\ \\ \\ [/tex]

Hence,

[tex]\\[/tex]

[tex] \\ { \underline{ \pmb{ \frak{\therefore Dimensions \: of \: rectangle \: are \: 9~ feet \: and \: 14 ~feet \: }}}}[/tex]

Given that, width of the rectangle is 5 feet less than the length and area of the rectangle is 126 sq. feet, and we are told to find the dimensions i.e the length and width of the rectangle.

As we know that the area of a rectangle is length times it's width, so if we assume our length to be x, so our width is just going to be (x - 5) , and putting it in the area formule we can thus obtain;

[tex]{:\implies \quad \sf x(x-5)=126}[/tex]

[tex]{:\implies \quad \sf x^{2}-5x-126=0}[/tex]

[tex]{:\implies \quad \sf x^{2}-14x+9x-126=0}[/tex]

[tex]{:\implies \quad \sf x(x-14)+9(x-14)=0}[/tex]

[tex]{:\implies \quad \sf (x-14)(x+9)=0}[/tex]

So, here either (x - 14) = 0 or (x + 9) = 0, when you equate both, you will get x = 14 or -9 but as x ≠ -9, so x = 14, and then x - 5 = 14 - 5 = 9

Hence, the required length and width are 14 feet and 9 feet respectively

Answer:

23 feet

Step-by-step explanation:

The absolute value of -14 is fourteen.

The absolute value of 23 is twenty-three

23>14

Answer:

This question is asking for you to determine if the tables represent linear functions, functions in y=mx+b form, and to find the equation for the line.

If something is a linear function, each of the input values will have it's own corresponding y value, therefore c cannot be linear, as -1 and 1 both have 10 as the output.

I hope this helps, but if you need more clarification, please tell me in the comments!

Answer:4:15

Step-by-step explanation:

EZ

Answer:

MAYBE

Step-by-step explanation:

Answer:

SORRY

Step-by-step explanation:

ANSWERAnswer:

SORRY

Step-by-step explanation:

ANSWERAnswer:

SORRY

Step-by-step explanation:

ANSWERAnswer:

SORRY

Step-by-step explanation:

ANSWERAnswer:

SORRY

Step-by-step explanation:

ANSWERAnswer:

SORRY

Step-by-step explanation:

ANSWERAnswer:

SORRY

Step-by-step explanation:

ANSWERAnswer:

SORRY

Step-by-step explanation:

ANSWERAnswer:

SORRY

Step-by-step explanation:

ANSWERAnswer:

SORRY

Step-by-step explanation:

ANSWERAnswer:

SORRY

Step-by-step explanation:

ANSWERAnswer:

SORRY

Step-by-step explanation:

ANSWERAnswer:

SORRY

Step-by-step explanation:

ANSWER

SOORY

Answer:

53°

Step-by-step explanation:

Answer: Yes, only angles can be reflected over diagonal lines.

Step-by-step explanation:

see photo

Answer:

43.75%

Step-by-step explanation:

Step 1: Divide 7 by 16 to get the number as a decimal. 7 / 16 = 0.44

Step 2: Multiply 0.44 by 100. 0.44 times 100 = 43.75. That's all there is to it!

Answer:

The correct answer is 6 ft. Hope this helps!

Step-by-step explanation:

Answer:

m = 41/6

Step-by-step explanation:

Convert everything into improper fractions with a denominator of 6.

====================================================

let's evaluate this expression

[tex]\pmb{\displaystyle\frac{8-m}{n+p^2} }[/tex]

[tex]\pmb{\displaystyle\frac{8-8}{2+7^2}}[/tex] (step 1)

[tex]\pmb{\displaystyle\frac{0}{2+49}}[/tex] (step 2)

simplify:

[tex]\pmb{\displaystyle\frac{0}{51}}[/tex] (step 3)

[tex]\pmb{0}[/tex] (step 4)

=======================================

Hope everything is clear; if you need any more clarification/explanation, kindly let me know, and I will comment and/or edit my answer :)

Answer:

$94.00

Step-by-step explanation:

First, do [tex]79.9*\frac{100}{85}[/tex]

Then multiply to get your answer of 94.

Step-by-step explanation:

there are in total 21 marbles.

5 black, 6 blue = 11 black or blue marbles.

so, the probability of pulling a black or blue marbles is as always desired possible outcomes / total possible outcomes = 11/21

Answer:

X = 6

Step-by-step explanation:

Hope this helped!!

maybe mark brainiest

Answer:

a) 3/286

b) 7/286

Step-by-step explanation:

We start with 13 drinks. After the first person takes one drink, there are 12 drinks left, After the second person takes one drink, there are 11 drinks available for the third person.

a) From the 13 drinks, there are 3 colas, From the 12 remaining drinks, there are 3 ginger ales. From the 11 remaining drinks, there are 2 colas. We have:

[tex] \frac{3}{13} \times \frac{3}{12} \times \frac{2}{11} = \frac{3}{286} [/tex]

b) From the 13 drinks, there are 3 colas. From the 12 remaining drinks, there are 2 colas. From the 11 remaining drinks, there are 7 root beers. We have:

[tex] \frac{3}{13} \times \frac{2}{12} \times \frac{7}{11} = \frac{7}{286} [/tex]

Answer:

yeh

Step-by-step explanation:

1 gallons = 4 quarts

4,8,20,28

quarts= 2 pints

1,3,6,16

1 pint= 2 cups

2,6,5,18

Answer:

3y5 • (5y + 7)2 • (5y - 7) then solve that which is (3•2y5) • (5y + 7) • (5y - 7) and keep going { 3x−2y=5 & 2x−5y=7

SOLVE FOR X, Y

x=1

y=−1

I hope this helps a little

Answer AP might be 12

Step-by-step explanation:

The length of AP when secant AP intersects the circle at points A and B, and secant CP intersects the circle at points C and D. is 12 units.

The length of AP can be found using the following steps:

Draw a radius from the center of the circle to point P.

Let the radius intersect secant AP at point E.

Since AP and PE are secant segments, they share a common external tangent at point P.

Therefore, the two triangles, APE and BPF, are similar triangles.

The ratio of corresponding sides in similar triangles is equal, so:

AP/PB = PE/PF

We know that PB = 5 and PF = 20, so:

AP/5 = PE/20

Solving for AP, we get:

AP = 5 * 20/5 = 20

The diagram shows the two similar triangles, APE and BPF. The two triangles are similar because they share a common external tangent at point P. The ratio of corresponding sides in similar triangles is equal, so we can use the ratio of AP to PB to find the length of AP.

To learn more about length here:

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#SPJ2

Answer:

See below, please

Step-by-step explanation:

The right：

[tex] {(y + c)}^{2} - b \times (x + a) \\ = ( {y}^{2} + 2yc + {c}^{2} ) - bx - ba = [/tex]

[tex] = {y}^{2} - bx + 2cy + {c}^{2} - ab[/tex]

The left:

[tex] = {y}^{2} - 7x - 18y + 109[/tex]

So, after comparing the right side and the left side of this equation, we know

1)

[tex]b = 7[/tex]

2)

[tex]2c = - 18 \\ so \\ c = - 9[/tex]

3)

[tex] {c}^{2} - ab = 109[/tex]

So,

[tex]a = \frac{ {c}^{2} - 109}{b} = \frac{ { (- 9)}^{2} - 109}{7} = \frac{ - 28}{7} = - 4[/tex]

The graph of the pupil's score is an illustration of scatter plots

The student's expected score in paper 2 is 62

To predict the score of the pupil in the missed paper, we simply interpret the points on the line of best fit of the scatter plot

From the graph (see attachment), we have:

Paper 2 = 62 when Paper 1 = 50

This means that the student's expected score in paper 2 is 62

Read more about scatter plots at:

https://brainly.com/question/6592115

Answer:

D

Step-by-step explanation:

You can find the answer by memorizing the values of the unit circle.