6. Calculate the area of the octagon in the
figure below.

Answer:

0.33

Step-by-step explanation:

See comment for complete question

Given

[tex]H = 60\%[/tex]

[tex]W=25\%[/tex]

[tex]HW = 20\%[/tex] --- at-home wins

Required

The proportion of at-home games that were wins

This proportion is represented as:

[tex]Pr = HW : H[/tex]

Substitute values for HW and H

[tex]Pr = 20\% : 60\%[/tex]

Divide by 20%

[tex]Pr = 1 : 3[/tex]

Express as fraction

[tex]Pr = 1 /3[/tex]

[tex]Pr = 0.33[/tex]

Answer:

1.581

Step-by-step explanation:

Given the data:

13 15 14 16 12

The point estimate of the standard deviation will be :

√Σ(x - mean)²/n-1

Mean = Σx / n = 70 / 5 = 14

√[(13 - 14)² + (15 - 14)² + (14 - 14)² + (16 - 14)² + (12 - 14)² / (5 - 1)]

The point estimate of standard deviation is :

1.581

Answer:

Anything to the power of zero (with the exception of zero itself) is equal to one.

So 3⁰ = 1

Answer:

D. No, there isn’t enough information because only two pairs of corresponding sides can't be used to prove that two triangles are congruent.

Answer:

Step-by-step explanation:

A). Volume of a rectangular prism = Length × Width × Height

                                                        = lwh

1). Volume of a rectangular prism if the measures of the sides are,

    Length (l) = 9 cm

    Width (w) = 4 cm                                              

    Height (h) = 3 cm                                            

    Therefore, volume = lwh

                                   = 9 × 4 × 3

                                   = 108 cm³

2). Length = 10 cm

     Width = 7 cm

     Height = 15 cm

     Volume = lwh

                   = 10 × 7 × 15

                   = 1050 cm³

3). Length = 14 cm

    Width = 10 cm

    Height = 9 cm

    Volume = 14 × 10 × 9

                  = 1260 cm³

B. Volume of a cube = (Side)³

4). If the measure of one side = 12 cm

    Volume of the cube = (12)³

                                      = 1728 cm³

5). If the measure of one side = 6 cm

   Volume of the cube = (6)³

                                     = 216 cm³

Answer:

second can

Step-by-step explanation:

The radius is half of the diameter.

The radius is squared in the formula for the volume of the cylinder.

A diameter of 7 and height of 6 will make a larger can than a diameter of 6 and height of 7.

Answer:

1100 ft³

Step-by-step explanation:

Use the formula for the volume of a cylinder. For height, use the average of the minimum and maximum depths.

V = πr²h

r = d/2 = 20 ft/2 = 10 ft

h = (1 ft + 6 ft)/2 = 3.5 ft

V = π(10 ft)²(3.5 ft)

V = 1100 ft³

Answer:

The equation of [tex]f(x) = e^{-3\cdot x}[/tex] by Maclaurin series is [tex]f(x) = \Sigma\limits_{i=0}^{\infty} \frac{(-3\cdot x)^{i}}{i!}[/tex].

Step-by-step explanation:

The Maclaurin series for [tex]f(x)[/tex] is defined by the following formula:

[tex]f(x) = \Sigma\limits_{i = 0}^{\infty} \frac{f^{(i)}(0)}{i!} \cdot x^{i}[/tex] (1)

Where [tex]f^{(i)}[/tex] is the i-th derivative of the function.

If [tex]f(x) = e^{-3\cdot x}[/tex], then the formula of the i-th derivative of the function is:

[tex]f^{(i)} = (-3)^{i}\cdot e^{-3\cdot x}[/tex] (2)

Then,

[tex]f^{(i)}(0) = (-3)^{i}[/tex] (2b)

Lastly, the equation of the trascendental function by Maclaurin series is:

[tex]f(x) = \Sigma\limits_{i=0}^{\infty} \frac{(-3)^{i}\cdot x^{i}}{i!}[/tex]

[tex]f(x) = \Sigma\limits_{i=0}^{\infty} \frac{(-3\cdot x)^{i}}{i!}[/tex] (3)

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

The attachment shows the ordered pairs (x, f(x)) and their graph.

Answer:

the total number of participants required is 90

Step-by-step explanation:

Given the data in the question;

Factor A has three levels

Factor B has three levels

sample size n; ten participants

we have two Way ANOVA involving Factor A and Factor B.

Now,

{ Total # Participants Required } = { #Levels factor A } × { #Levels factor B } × { Sample size of each level }

we substitute

{ Total # Participants Required } = 3 × 3 × 10

{ Total # Participants Required } = 9 × 10

{ Total # Participants Required } = 90

Therefore, the total number of participants required is 90

Answer:

0.9898 = 98.98% probability that there will not be more than one failure during a particular week.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

In which

x is the number of sucesses

e = 2.71828 is the Euler number

[tex]\mu[/tex] is the mean in the given interval.

3 failures every twenty weeks

This means that for 1 week, [tex]\mu = \frac{3}{20} = 0.15[/tex]

Calculate the probability that there will not be more than one failure during a particular week.

Probability of at most one failure, so:

[tex]P(X \leq 1) = P(X = 0) + P(X = 1)[/tex]

Then

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-0.15}*0.15^{0}}{(0)!} = 0.8607[/tex]

[tex]P(X = 1) = \frac{e^{-0.15}*0.15^{1}}{(1)!} = 0.1291[/tex]

Then

[tex]P(X \leq 1) = P(X = 0) + P(X = 1) = 0.8607 + 0.1291 = 0.9898[/tex]

0.9898 = 98.98% probability that there will not be more than one failure during a particular week.

Answer:

C) x = ± 4

Step-by-step explanation:

12x² - 288 = 0

12x ² = 288

[tex] \small \sf \: x {}^{2} = \frac{288}{12} \\ [/tex]

[tex]\small \sf x {}^{2} = \frac{ \cancel{288 }}{ \cancel{12}} \\ [/tex]

x² = 24

[tex] \small \sf \: \sqrt{x {}^{2} } = ± \sqrt{ 24} [/tex]

[tex] \small \sf \: x_1, _2 = ± \sqrt{ 24} [/tex]

[tex] \small \sf \: x_1, _2 = ± 4.899 [/tex]

Answer:

[0.25, 2]

Step-by-step explanation:

We have

4t² ≤ 9t-2

subtract 9t-2 from both sides to make this a quadratic

4t²-9t+2 ≤ 0

To solve this, we can solve for 4t²-9t+2=0 and do some guess and check to find which values result in the function being less than 0.

4t²-9t+2=0

We can see that -8 and -1 add up to -9, the coefficient of t, and 4 (the coefficient of t²) and 2 multiply to 8, which is also equal to -8 * -1. Therefore, we can write this as

4t²-8t-t+2=0

4t(t-2)-1(t-2)=0

(4t-1)(t-2)=0

Our zeros are thus t=2 and t = 1/4. Using these zeros, we can set up three zones: t < 1/4, 1/4<t<2, and t>2. We can take one random value from each of these zones and see if it fits the criteria of

4t²-9t+2 ≤ 0

For t<1/4, we can plug in 0. 4(0)²-9(0) + 2 = 2 >0 , so this is not correct

For 1/4<t<2, we can plug 1 in. 4(1)²-9(1) +2 = -3 <0, so this is correct

For t > 2, we can plug 5 in. 4(5)²-9(5) + 2 = 57 > 0, so this is not correct.

Therefore, for 4t^2 ≤ 9t-2 , which can also be written as 4t²-9t+2 ≤ 0, when t is between 1/4 and 2, the inequality is correct. Furthermore, as the sides are equal when t= 1/4 and t=2, this can be written as [0.25, 2]

Answer:

interval?

Step-by-step explanation:

I'm not sure. I think so....hope its correct :)

Answer:

Hence,

a) The probability that the sample average would be less than 90 pounds is 0.0210.

b) The probability that the sample average would be between 98 and 105 pounds is 0.5045.

c) The probability that the sample average would be less than 112 pounds is 0.9935.

d) The probability that the sample average would be between 93 and 96 pounds is 0.1341.

Step-by-step explanation:

a) [tex]P(X < 90) = P(Z < (90 - 99.9) / (30\sqrt(38)))[/tex]

                     = P(Z < -2.03) = 0.0210

b )[tex]P(98 < x <105) = P((98 -99.9) / (30 \sqrt(38)) < Z < (105 -99.9) / (30 \sqrt(38)))[/tex]

                              = P(-0.39 < Z < 1.05) = 0.5045

c ) [tex]P(X < 112) = P(Z < (112 - 99.9) / (30\sqrt(38)))[/tex]

                        = P(Z < 2.49) = 0.9935

d )[tex]P(93 < x < 96) = P((93 -99.9) / (30 \sqrt(38)) < Z < (96 -99.9) / (30 \sqrt(38)))[/tex]

                            = P( -1.42 < Z < -0.8 )

                            = 0.2119 - 0.0778 = 0.1341

Answer/Step-by-step explanation:

2. a. 5y - 3 = -18

Add 3 to both sides

5y - 3 + 3 = -18 + 3

5y = -15

Divide both sides by 5

5y/5 = -15/5

y = -3

b. -3x - 9 = 0

Add 9 to both sides

-3x - 9 + 9 = 0 + 9

-3x = 9

Divide both sides by -3

-3x/-3 = 9/-3

x = -3

c. 4 + 3(z - 8) = -23

Apply the distributive property to open the bracket

4 + 3z - 24 = -23

Add like terms

3z - 20 = -23

Add 20 to both sides

3z - 20 + 20 = - 23 + 20

3z = -3

Divide both sides by 3

3z/3 = -3/3

z = -1

d. 1 - 2(y - 4) = 5

1 - 2y + 8 = 5

-2y + 9 = 5

-2y + 9 - 9 = 5 - 9

-2y = -4

-2y/-2 = -4/-2

y = 2

3. First, find the sum of 3pq + 5p²q² + p³ and p³ - pq

(3pq + 5p²q² + p³) + (p³ - pq)

3pq + 5p²q² + p³ + p³ - pq

Add like terms

= 3pq - pq + 5p²q² + p³ + p³

= 2pq + 5p²q² + 2p³

Next, subtract 2pq + 5p²q² + 2p³ from 3p³ - 2p²q² + 4pq

(3p³ - 2p²q² + 4pq) - (2pq + 5p²q² + 2p³)

Apply distributive property to open the bracket

3p³ - 2p²q² + 4pq - 2pq - 5p²q² - 2p³

Add like terms

3p³ - 2p³ - 2p²q² - 5p²q² + 4pq - 2pq

= p³ - 7p²q² + 2pq

4. Perimeter of the rectangle = sum of all its sides

Perimeter = 2(L + B)

L = (5x - y)

B = 2(x + y)

Perimeter = 2[(5x - y) + 2(x + y)]

Perimeter = 2[5x - y + 2x + 2y]

Add like terms

Perimeter = 2(7x + y)

Substitute x = 1 and y = 2 into the equation

Perimeter = 2(7(1) + 2)

Perimeter = 2(7 + 2)

Perimeter = 2(9)

Perimeter = 18 units

5. First let's find the quotient to justify if the value we get is greater than or less than 2.25

7⅙ ÷ 3⅛

Convert to improper fraction

43/6 ÷ 25/8

Change the operation sign to multiplication and turn the fraction by the left upside down.

43/6 × 8/25

= (43 × 8)/(6 × 25)

= (43 × 4)/(3 × 25)

= 172/75

≈ 2.29

Therefore, the quotient of 7⅙ ÷ 3⅛ is greater than 2.25

Answer:

the anwer is B ( i mean second option)

And you can try it

you will find ;

[tex]y = \frac{x}{3} - 1[/tex]

HAVE A NİCE DAY

Step-by-step explanation:

GREETİNGS FROM TURKEY ツ

Answer:

he rate it 16%

Step-by-step explanation:

64-80\100=16

Answer:

Step-by-step explanation:

Speed - s,   Distance - d,  Time - t

Equation of time is:

Given,

Total time is the sum of time values to and from the town:

It is given that,

→ s1= 32 miles/h

→ s2 = 38 miles/h

Now t1 + t2 is,

→ 42 min

→ 42/60 hours

→ 7/10 hours

The formula we use,

→ Time = Distance/Speed

→ t = d/s

Then the total time is the,

Sum of time values to and from the town.

→ d/32 + d/38 = 7/10

→ d/16 + d/19 = 7/5

→ d{(1/16) + (1/19)} = 7/5

→ d(16 + 19) = (7/5) × (16 × 19)

→ 35d = 425.6

→ d = 425.6/35

→ d = 12.16

Hence, the distance is 12.16 miles.

Answer:

1.

M = 20 degrees

n =28.74

p = 20.12

2.

B = 73.65 degrees

C = 43.35 degrees

c = 30.05

3.

F = 21 degrees

G = 124 degrees

g = 23.13

Step-by-step explanation:

the law of sines is for a triangle ABC

a/sin(A) = b/sin(B) = c/sin(C)

1.

the sum of all angles in a triangle is always 180 degrees.

so, M = 180 - 125 - 35 = 20 degrees

m/sin(M) = n/sin(N)

12/sin(20) = n/sin(125)

sin(125) = sin(180-125) = sin(55)

n = 12×sin(55)/sin(20) = 28.74

p/sin(P) = m/sin(M)

p/sin(35) = m/sin(20)

p = m×sin(35)/sin(20) = 12×sin(35)/sin(20) = 20.12

2.

a/sin(A) = b/sin(B)

39/sin(63) = 42/sin(B)

sin(B) = 42×sin(63)/39 = 14×sin(63)/13

B = 73.65 degrees

therefore,

C = 180 - 63 - 73.65 = 43.35 degrees

c/sin(43.35) = 39/sin(63)

c = 39×sin(43.35)/sin(63) = 30.05

3.

e/sin(E) = f/sin(F)

16/sin(35) = 10/sin(F)

sin(F) = 10×sin(35)/16 = 5×sin(35)/8

F = 21 degrees

therefore,

G = 180 - 35 - 21 = 124 degrees

g/sin(124) = 16/sin(35)

sin(124) = sin(180-124) = sin(56)

g/sin(56) = 16/sin(35)

g = 16×sin(56)/sin(35) = 23.13

Answer:

Xin hãy đánh dấu cho tôi là một người tồi tệ nhất

Để tìm chu vi hình vuông, bạn phải nhân 2 cạnh với 4..

Sử dụng công thức

chu vi = 4 * (một mặt)

Complete Question

ymposium is part of a larger work referred to as Plato's Dialogues. Wishart and Leach† found that about 21.4% of five-syllable sequences in Symposium are of the type in which four are short and one is long. Suppose an antiquities store in Athens has a very old manuscript that the owner claims is part of Plato's Dialogues. A random sample of 498 five-syllable sequences from this manuscript showed that 129 were of the type four short and one long. Do the data indicate that the population proportion of this type of five-syllable sequence is higher than that found in Plato's Symposium? Use = 0.01.  

a. What is the value of the sample test statistic? (Round your answer to two decimal places.)  

b. Find the P-value of the test statistic. (Round your answer to four decimal places.)

Answer:

a) [tex]Z=2.45[/tex]

b) [tex]P Value=0.0073[/tex]

Step-by-step explanation:

From the question we are told that:

Probability of Wishart and Leach [tex]P=21.4=>0.214[/tex]

Population Size [tex]N=498[/tex]

Sample size [tex]n=12[/tex]

Therefore

[tex]P'=\frac{129}{498}[/tex]

[tex]P'=0.2590[/tex]

Generally the Null and Alternative Hypothesis is mathematically given by

[tex]H_0:P=0.214[/tex]

[tex]H_a:=P>0.214[/tex]

Test Statistics

[tex]Z=\frac{P'-P}{\sqrt{\frac{P(1-P)}{n}}}[/tex]

[tex]Z=\frac{0.2590-0.214}{\sqrt{\frac{0.214(1-0.214)}{498}}}[/tex]

[tex]Z=2.45[/tex]

Therefore P Value is given as

[tex]P Value =P(Z\geq 2.45)[/tex]

[tex]P Value =1-P(Z\leq 2.45)[/tex]

[tex]P Value =1-0.99268525[/tex]

[tex]P Value=0.0073[/tex]

Answer:

ok so 90 is 40 more dollars then 50 and there is 4 25 cents in each dollars so

4*40=160

so she would have to drive 161 miles to save money

Hope This Helps!!!

Step-by-step explanation:

guess

Dependent variable: y and Independent variable: x

gauthammath dot com 

Answer:

A=W, B=X, C=Y, D=Z, AB=WX, BC=XY, CD=YZ, AD=WZ

(The second answer down)

Step-by-step explanation:

Answer:

10/1 is the largest because 10÷1 = 10

Answer:

10/1 =  10 and is by far the biggest value in the list

Step-by-step explanation:

Answer:

The farmer should plant 14 additional trees, for maximum yield.

Step-by-step explanation:

Given

[tex]Trees = 24[/tex]

[tex]Yield = 104[/tex]

[tex]x \to additional\ trees[/tex]

So, we have:

[tex]Trees = 24 + x[/tex]

[tex]Yield = 104 - 2x[/tex]

Required

The additional trees to be planted for maximum yield

The function is:

[tex]f(x) = Trees * Yield[/tex]

[tex]f(x) = (24 + x) * (104 - 2x)[/tex]

Open bracket

[tex]f(x) = 24 * 104 + 104x - 24 * 2x - x * 2x[/tex]

[tex]f(x) = 2796 + 104x - 48x - 2x^2[/tex]

[tex]f(x) = 2796 + 56x - 2x^2[/tex]

Rewrite as:

[tex]f(x) = - 2x^2 + 56x + 2796[/tex]

Differentiate

[tex]f'(x) = -4x + 56[/tex]

Equate [tex]f'(x) = -4x + 56[/tex] to 0 and solve for x to get the maximum of x

[tex]-4x + 56 = 0[/tex]

[tex]-4x =- 56[/tex]

Divide by -4

[tex]x =14[/tex]

The farmer should plant 14 additional trees, for maximum yield.

Answer:

CI 96 %  =  ( - 0.1128  ; 0.0728 )

CI 95%  =  ( - 0.1087 ; 0.6878 )

The two intervals contain 0 value therefore we can support that there is not statistics difference between the two groups with confidence level of 96 % and  95%

Step-by-step explanation:

Boys sample:

sample size   n₁  = 200

x₁  number of boys saying their parents are very involved in their lives

=  93

p₁ = x₁/n₁   =  93/200  =  0.465  then  q₁ =  1  -  p₁   q₁ = 1 - 0.465  q₁ = 0.535

Girls sample

sample size   n₂  = 300

x₂  number of girls saying their parents are very involved in their lives

=  172

p₂  =  x₂/n₂  =  172/ 300  =  0.573 then  q₂ = 1 -0.573  q₂ =  0.427

CI 96 %      α = 4 %  α = 0.04    α/2 = 0.02  

p₁  -  p₂  =  0.465 -  0.573  = - 0.168

CI 96 %   =  (  p₁  -  p₂ ) ±  z(c) * SE

z(c)  for  α  =  0.02       z(c)  =  - 2.05

SE = √ (p₁*q₁)/n₁  +  (p₂*q₂)/n₂

SE = √ ( 0.465*0.535)/200  +  (0.573*0.427)/300

SE =  √  0.00124  +  0.000815    

SE =  √  0.00205

SE =   0.0453

CI 96 %  =  (  -0.02  ±  ( 2.05 * 0.0453 ) )

CI 96 %  =  (  -0.02  ±  ( 0.0928 ))

CI 96 %  =  ( - 0.1128  ; 0.0728 )

a) CI 95%  α =  5 %   α = 0.05     α/2 =  0.025

SE = 0.0453

z(c) for  0.025 is from z-table   z(c)  =  1.96

CI 95%  =  ( - 0.02 ±  1.96 * 0.0453)

CI 95%  =  ( - 0.02 ± 0.08878 )

CI 95%  =  ( - 0.1087 ; 0.6878 )