Answer: 89.345
Explanation:
What cell would you use to electroplate silver over on iron
Answer:
You would use an electrolytic cell.
Consider a solution made from a nonvolatile solute and a volatile solvent. Which statement is true?
a) The vapor pressure of the solution is always greater than the vapor pressure of the pure solvent.
b) The boiling point of the solution is always greater than the boiling point of the pure solvent.
c) The freezing point of the solution is always greater than the freezing point of the pure solvent.
Answer:
b) The boiling point of the solution is always greater than the boiling point of the pure solvent.
Explanation:
Hello,
In this case, when we add a nonvolatile solute to a volatile solvent which has a relatively low boiling point, we can evidence the increase of the boiling point of the resulting solution as more energy must be supplied to take the molecules from liquid to gas. This fact matches with the boiling point elevation colligative property due to the solute's addition, which states that the boiling point of the solution is always greater than the boiling point of the pure solvent, therefore, answer is b).
Best regards.
The statement true about the solution made from a nonvolatile solute and a volatile solvent is, the boiling point of the solution is always greater than the boiling point of the pure solvent. Thus option C is correct.
The boiling point of the solution can be defined as the temperature where the liquid has been converted to the gaseous state. In the solvent, the energy has been provided to the sample for the conversion of liquid molecules to gas.
The addition of a nonvolatile solute to the volatile solvent results in the addition of the molecules to the solvent. This will result in the requirement of more energy for the conversion of solvent from a liquid state to a gaseous state.
Thus, with the addition of a nonvolatile solute to the volatile solvent, the boiling point of the solution will be increased and will always be greater than the boiling point of the pure solvent.
Thus option C is correct.
For more information about the volatile solvent, refer to the link:
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why are step by step written procedures are an essential part of any scientific experiment
Answer: The scientific method attempts to minimize the influence of bias or prejudice in the experimenter. Even the best-intentioned scientists can't escape bias. ... That's the job of the scientific method. It provides an objective, standardized approach to conducting experiments and, in doing so, improves their results.
he mass of a single molybdenum atom is 1.59×10-22 grams. How many molybdenum atoms would there be in 38.3 milligrams of molybdenum?
Answer:
2.41 × 10²⁰ atoms
Explanation:
Step 1: Given data
Mass of a single molybdenum atom: 1.59 × 10⁻²² gMass of the molybdenum sample: 38.3 mgStep 2: Convert the mass of the sample to grams
We will use the relationship 1 g = 1,000 mg.
38.3 mg × (1 g/1,000 mg) = 0.0383 g
Step 3: Calculate the number of atoms in 0.0383 g of molybdenum
0.0383 g × (1 atom/1.59 × 10⁻²² g) = 2.41 × 10²⁰ atom
Larissa needs to make 500ml of 2.00 M NaCl. The molecular weight of NaCl is 58.44. How does she make 500ml of 2.00 M NaCl? Question 3 options: A) Measure 29.22g NaCl and dissolve it into 500ml water. B) Measure 29.22g NaCl, dissolve it into 400ml water, and then top off to 500ml in a volumetric flask. C) Measure 58.44g NaCl and dissolve it into 500ml of water. D) Measure 58.44g NaCl, dissolve it into 400ml water, and then top off to 500ml in a volumetric flask.
Answer:
D) Measure 58.44g NaCl, dissolve it into 400ml water, and then top off to 500ml in a volumetric flask.
Explanation:
Step 1: Given data
Molarity (M): 2.00 M
Volume (V): 500 mL = 0.500 L
Molar mass of NaCl: 58.44 g/mol
Step 2: Calculate the required moles of NaCl
We will use the following expression.
n = M × V
n = 2.00 mol/L × 0.500 L
n = 1.00 mol
Step 3: Calculate the mass corresponding to 1.00 moles of NaCl
1.00 mol × 58.44 g/mol = 58.44 g
Step 4: Describe the procedure to prepare the solution
Measure 58.44g NaCl, dissolve it into 400ml water, and then top off to 500ml in a volumetric flask.
Answer:
D) Measure 58.44g NaCl, dissolve it into 400ml water, and then top off to 500ml in a volumetric flask.
Explanation:
I got it right in class!
Hope this helps!! :))
Using the measurements in the table, determine which unidentified metal has the lowest density?
Answer:
Metal C
Explanation:
Density = mass (g)/ volume (mL, which is the same thing as cm cubed)
Divide mass by volume for each metal, the metal with the lowest value (metal C) is your answer.
Answer:
IT IS
NOT. I REPEAT - IT IS NOT> D
Explanation:
i got it wrong :(
Draw the Lewis structure for H2O. How many lone pairs of electrons are there in the central atom?
Answer:
2 lone pairs of electrons
Explanation:
In this case, the central atom is oxygen. If we check the periodic table we will have an atomic number of 8. So, the electronic configuration would be:
[tex]1s^2~2s^2~2p^4[/tex]
We have 6 electrons in the last level. Therefore, we have 6 valence electrons. For the hydrogens, we will have only 1 electron each. So, in total, we have 8 electrons.
With this in mind, we have to draw two lone pairs in the oxygen and 1 bond with each hydrogen.
See figure 1.
I hope it helps!
How many seconds (s) are needed to deposit 7.25 g of copper metal from an aqueous solution of CuCl2, using a current of 3.1 Amps.
Answer:
7,052.6secs
Explanation:
n of Cu = +2
R.A.M of Cu = 64g
m = 7.25g
I = 3.1A
F = 96500
nF = R.A.M
It = m
2*96500 = 64
3.1*t = 7.25
1,399,250 = 198.4t
t = 7,052.6secs
Answer quick please I’m begging you
Answer:
The sun warms up parts of the oceans. Warm waters rise just like warm air rises. So, as the warmer ocean waters begin to rise in a particular area, the cooler ocean waters from a different area will move in to replace the warmer ocean waters, and this creates our ocean currents.
Hope it helps!
Arrange the following substances in the order of increasing entropy at 25°C.
a. HF(g)
b. NaF(s)
c. SiF 4(g)
d. SiH 4(g)
e. Al(s)
Answer:
In solving this question it is important to note that entropy is referred to as the degree of randomness in a compound or system.
Entropy is highest in gas and lowest in solids
The order is given as:
Gas > Liquid > Solid
Another criteria is the more the elements in a compound, the more the entropy.
For example: KO3 has more entropy than KO2 due to the presence of more elements.
The last criteria is calculating their masses , the one with a greater mass has the higher entropy.
The option with the least entropy will be a solid. Al(s) and NaF(s) are both solids. NaF(s) has more elements in a compound which makes it have a higher entropy than Al(s). This means NaF(s) > Al(s).
The next to consider are the gaseous compounds which are HF(g) , SiF4(g) and SiH4(g). The least entropy will be HF(g) . This is because it has the least number of elements of the 3 compounds.
SiF4(g) and SiH4(g) have equal number of elements in a compound but the one with the highest mass is SiF4(g) because fluorine has a higher mass when compared to hydrogen. This means the compound with the highest entropy is SiF4(g).
The order of increasing entropy is given below:
Al(s) < NaF(s) < HF(g) < SiH4(g) < SiF4(g)
At what temperature, Teq, do the forward and reverse corrosion reactions occur in equilibrium?
The chemical reaction that causes aluminum to corrode in air is given by
4Al+3O2?2Al2O3
in which at 298 K
?Hrxn? = ?3352 kJ
?Srxn = ?625.1 J/K
What is the standard Gibbs free energy for this reaction? Assume the commonly used standard reference temperature of 298 K?
What is the Gibbs free energy for this reaction at 5975K ? Assume that ?H and ?S do not change with temperature.
At what temperature, Teq, do the forward and reverse corrosion reactions occur in equilibrium?
Answer:
See explanation below.
Explanation:
We can obtain the Gibb's free energy from the formula;
∆G= ∆H - T∆S
Where;
∆G = change in free energy= the unknown
∆H= change in enthalpy = 3352 kJ
∆S= change in entropy of the solution= 625.1 J/K
T= absolute temperature = 298 K
Substituting values;
∆G= 3352 ×10^3 J - (298 K × 625.1 J/K)
∆G= 3352 ×10^3 J - 186279.8
∆G= 3.16 × 10^6 J
At 5975K,
∆G= ∆H - T∆S
∆G= 3352 ×10^3 J - (5975K × 625.1 J/K)
∆G= 3.352 ×10^6 J - 3.735 × 10^6
∆G= -3.83×10^5 J
At equilibrium, ∆G=0, Teq is given by;
0= 3352 ×10^3 J - (Teq × 625.1 J/K)
0= 3352 ×10^3 - 625.1Teq
625.1Teq = 3352 ×10^3
Teq= 3352 ×10^3/625.1
Teq= 5362.3 K
Standard Gibb's free energy at 298 & 5975K is 3.16×10⁶J and -3.83×10⁵J respectively, and temperature at equilibrium state is 5362.3 K.
How do we calculate standard Gibb's free energy?Standard Gibb's free energy of any reaction will be calculated as:
∆G° = ∆H° - T∆S°, where
∆G° = change in free energy = to find?
∆H° = change in enthalpy = 3352 kJ = 3,352 × 10³J
∆S° = change in entropy = 625.1 J/K
T = absolute temperature = 298 K
On putting all these values on the above equation, we get
∆G° = (3,352 × 10³) - (298 × 625.1) = 3.16 × 10⁶J
Gibb's free energy at 5,975 K temperature:
∆G° = (3,352 × 10³) - (5,975 × 625.1) = -3.83 × 10⁵J
At the equilibrium state value of Gibb's free energy is zero, so from the equation and given data we can calculate the value of temperature as:
0 = (3352 × 10³)J - (T × 625.1 J/K) = 5362.3 K
Hence required values are 3.16 × 10⁶J, -3.83 × 10⁵J and 5362.3 K.
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Part D There is a structure for CH2CHCHCH2CHCH3 with a double bond between the first (from left to right) and the second carbons and a chlorine atom attached to the third and the fifth carbon. Spell out the full name of the compound.
Answer:
3,5-dichlorohex-1-ene
Explanation:
The compound is; H2C=CH-C(Cl)H-CH2-C(Cl)H-CH3. We can rightly call this compound by the name, 3,5-dichlorohex-1-ene.
We arrived at this name by first counting the longest parent carbon chain, that gives hexane. The compound has a double bond at the 1-position. Also, there are two substituent chlorine atoms at positions 3 and 5 in the structure, hence the name given.
The melting point of water is 0°C at 1 atm pressure because under these conditions:
A. ΔS for the process H2O(s) → H2O(l) is positive.
B. ΔS and ΔSsurr for the process H2O(s) → H2O(l) are both positive.
C. ΔS and ΔSsurr for the process H2O(s) → H2O(l) are equal in magnitude and opposite in sign.
D. ΔG is positive for the process H2O(s) → H2O(l).
E. None of these is correct.
Answer:
The correct answer is option C, that is, ΔS and ΔSsurr for the process H2O (s) ⇒ H2O(l) are equal in magnitude and opposite in sign.
Explanation:
The temperature at which solid state of water get transformed into liquid state is termed as the melting point of 0 °C. It can be shown by the reaction:
H2O (s) ⇒ H2O (l)
The degree of randomness of a molecule is known as entropy. With the transformation of ice into liquid state, there is an increase in randomness. Thus, the value of entropy becomes positive as shown:
Entropy change (ΔSsys) = ΔSproduct - ΔSreactant
= (69.9 - 47.89) J mol/K
= 22.0 J mol/K
Therefore, the value of entropy change is positive.
Now the value of entropy for surrounding ΔSsurr will be,
ΔSsurr = -ΔHfusion/T
= -6012 j/mol/273
= -22.0 J/molK
Hence, the value of ΔSsurr and ΔSsys exhibit same magnitude with opposite sign.
How many TOTAL ions would be produced as aqueous species in the water solvent if four molecules of aluminum perchlorate dissolved? The answer is _____ total ions
Answer:
the total I think would be 35
The reaction system POBr3(g) =POBr(g) + Brz(g) is at equilibrium. Which of the following statements describes the behavior of the system if POBr is added to the container?
A.POBr will be consumed in order to establish a new equilibrium.
B. the partial pressures of POBrand POBr will remain steady while the partial pressure of bromine increases.
C. the partial pressure of bromine will increase while the partial pressure of POBr decreases.
D. the partial pressure ofbromine remains steady while the partial pressures of POBrand POBr increase.
E, the forward reaction will proceed to establish equilibrium.
Answer:
A. POBr will be consumed in order to establish a new equilibrium.
Explanation:
POBr3(g) =POBr(g) + Brz(g)
The question is based on Le Chatelier's principle. This principle states that whenever a system at equilibrium is stressed, the system would undergo changes to annul that stress.
If more POBr is added to the system, it means that the concentration of the products have been increased and as a result the equilibrium has been disturbed. To restore equilibrium, the system would have to shift in a direction that reduces the product concentration.
This direction is the backward direction and in doing so, POBr will be consumed.
The correct option is option A.
The statement that describes the behavior of the system is:
A. POBr will be consumed in order to establish a new equilibrium.
Reaction system:POBr₃(g) ⇄ POBr(g) + Br₂(g)
According to Le Ch-atelier principle, if a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium shifts to counteract the change to re-establish an equilibrium.
If more POBr is added to the system, it means that the concentration of the products have been increased and as a result the equilibrium has been disturbed. To restore equilibrium, the system would have to shift in a direction that reduces the product concentration.
This direction is the backward direction and in doing so, POBr will be consumed.
Thus, the correct option is option A.
Find more information about Equilibrium here:
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Which of the following gases will escape through a hole in a balloon at the highest rate? Kr NO Ar N2O
Answer:
NO.
Explanation:
The rate of diffusion of gases is inversely proportional to the square root of its density as explained by Graham's law of diffusion i.e
Rate (R) & 1/√(density (d))
R & 1/√d
But the density of a gas is proportional to the molar mass (M) of the gas.
Thus, the above equation can written as:
R & 1/√d
R & 1/√M
This implies that rate is inversely proportional to the molar mass of a gas i.e the lighter the gas, the faster the rate and the heavier the gas, the slower the rate of diffusion.
Now, to obtain the answer to the question, let us determine the molar mass of each gas.
This is illustrated below:
Molar mass of Kr = 84 g/mol
Molar mass of NO = 14 + 16 = 30 g/mol
Molar mass of Ar = 40 g/mol
Molar mass of N2O = (14x2) + 16 = 44 g/mol
Summary
Gas >>>>>>> Molar mass
Kr >>>>>>>>> 84 g/mol
NO >>>>>>>> 30 g/mol
Ar >>>>>>>>> 40 g/mol
N2O >>>>>>> 44 g/mol
From the above table, we can see the lightest gas is NO.
Therefore, NO will escape through the hole in the balloon at the highest rate.
If you are not sure about what to do during a lab activity, what should you do?
Ask someone else at your table.
Use your best judgement.
Watch to see what everyone else isdoing.
Ask the teacher.
Answer:
ask a teacher is the correct answer.
Explanation:
You must ALWAYS ask a teacher if you are not sure about what to do during a lab activity.
Answer:
It's important to ask the teacher, lab safety policies all state that if you're confused about instructions it's always good to ask the teacher to clarify them.
Sodium hydroxide is a strong base. What is the pH in a 0.01 mol/dm3
solution?
a. pH=2
b. pH=12
c. pH=-2
d. pH=0.01 mol/dm3
Answer:
b. pH=12
Explanation:
Step 1: Given data
Concentration of NaOH: 0.01 mol/dm³ = 0.01 mol/L = 0.01 M
Step 2: Write the reaction for the dissociation of NaOH
NaOH is a strong base that dissociates according to the following equation.
NaOH(aq) ⇒ Na⁺(aq) + OH⁻(aq)
The molar ratio of NaOH to OH⁻ is 1:1. Then, the concentration of OH⁻ is 0.01 M.
Step 3: Calculate the pOH
pOH = -log [OH⁻] = -log 0.01 = 2
Step 4: Calculate the pH
We will use the following expression.
pH + pOH = 14
pH = 14 - pOH = 14 -2 = 12
Match.
The expression of concentration that provides the moles of solute per kilograms of solvent is _______.
A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution,the_______ is water.
A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution, the ________is sodium chloride.
If you place 5 moles of sodium chloride and 4 moles of sucrose into 11 moles of water, the ________of sodium chloride would be 0.25.
A way to express concentration that provides the moles of solute per liter of solution is _______-.
Solvent
Mole fraction
solute
pH
Molarity
Molality
Answer:
Molality, Solvent, Solute, Mole fraction, Molarity.
Explanation:
The expression of concentration that provides the moles of solute per kilograms of solvent is Molality. This in the only expression referred to the solvent.
A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution, the Solvent is water. When water is present, it is usually considered the solvent.
A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution, the Solute is sodium chloride. There can be 1 or more solutes in a solution.
If you place 5 moles of sodium chloride and 4 moles of sucrose into 11 moles of water, the Mole fraction of sodium chloride would be 0.25. The mole fraction is equal to the moles of a substance divided by the total number of moles.
A way to express concentration that provides the moles of solute per liter of solution is Molarity.
What is the definition of weight
Answer:
Weight is a noun that means a human body's mass.
For example: Joh is 168 pounds.
This is the correct definition of weight.
Here to help!
Phosphoric acid, H3PO4, will undergo three successive ionization reactions to varying extents in water. What is the balanced equilibrium identified as Ka3
Answer:
HPO₄⁻² + H₂O ⇄ PO₄⁻³ + H₃O⁺ Ka3
Explanation:
Phosphoric acid, H3PO4 is a dyprotic acid which undergoes in these three succesive ionization reactions.
The last equillibrium is conditionated to the Ka3
H₃PO₄ + H₂O ⇄ H₂PO₄⁻ + H₃O⁺ Ka1
H₂PO₄⁻ + H₂O ⇄ HPO₄⁻² + H₃O⁺ Ka2
HPO₄⁻² + H₂O ⇄ PO₄⁻³ + H₃O⁺ Ka3
It is an acid because it release a proton, to make the [H₃O⁺] rise.
pH of solution will always be < 7
H₂PO₄⁻ and HPO₄⁻² are amphoteric compounds, which means that they can work as an acid (release protons), or base (take protons)
Write the molecular balanced chemical equation and the net ionic equation for the reaction between Ca(OH)2(aq) and HCl(aq).
Answer:
1. Balanced Molecular equation
Ca(OH)2(aq) + 2HCl(aq) —> CaCl2(aq) + 2H2O(aq)
2. Net ionic equation
OH-(aq) + H+(aq) —> H2O(l)
Explanation:
1. Molecular balance equation for the reaction between Ca(OH)2(aq) and HCl(aq).
This is illustrated below:
Ca(OH)2(aq) + HCl(aq) —> CaCl2(aq) + H2O(aq)
There are 2 atoms of Cl on the right side and 1 atom on the left side. It can be balance by putting 2 in front of HCl as shown below:
Ca(OH)2(aq) + 2HCl(aq) —> CaCl2(aq) + H2O(aq)
There are 2 atoms of H on the right side and a total of 4 atoms on the left side. It can be balance by putting 2 in front of H2O as shown below:
Ca(OH)2(aq) + 2HCl(aq) —> CaCl2(aq) + 2H2O(aq)
Therefore the equation above is balanced.
2. Net ionic equation for the reaction between Ca(OH)2(aq) and HCl(aq).
In solution, Ca(OH)2(aq) and HCl(aq) will dissociate as follow:
Ca(OH)2(aq) —> Ca2+(aq) + 2OH-(aq)
HCl(aq) —> H+(aq) + Cl-(aq)
Ca(OH)2(aq) + 2HCl(aq) —>
Ca2+(aq) + 2OH-(aq) + 2H+(aq) + 2Cl-(aq) —> Ca2+(aq) + 2Cl-(aq) + 2H2O(l)
Cancel out the spectator ions i.e Ca2+ and Cl- to obtain the net ionic equation
2OH-(aq) + 2H+(aq) —> 2H2O(l)
OH-(aq) + H+(aq) —> H2O(l)
A person tries to heat up her bath water by adding 5.0 L of water at 80°C to 60 L of water at 30°C. What is the final temperature of the water? Group of answer choices
Answer:
33.85°C
Explanation:
From the question,
Heat lost by the hotter water = heat gained by the colder water
cm'(t₂-t₃) = cm(t₃-t₁)................. Equation 1
Where c = specific heat capacity of water, m' = mass of hot water, m = mass of cold water, t₁ = Initial temperature of cold water, t₂ = Initial temperature of hot water, t₃ = final temperature of the mixture.
But since the density of water is constant, and mass varies directly as volume, We can replace the mass of water with the volume of water. i.e,
cv'(t₂-t₃) = cv(t₃-t₁)................. Equation 2
Where v' and v are the volume of hot water and cold water respectively
make t₃ the subject of the equation
t₃ = (v't₂+vt₁)/(v'+v)............ Equation 3
Given: v' = 5.0 L, v = 60 L, t₁ = 30°C, t₂ = 80°C
Substitute these values into equation 3
t₃ = (5×80+60×30)/(60+5)
t₃ = 2200/68
t₃ = 33.85°C
Need help I need a short imaginary science lab story where several safety rules were ignored by students and things went wrong include at least 4 safety rules that were ignored.
Which of the following could be considered a scientific statement? (2 points)
Answer:
The answer of the scientific STATEMENT is" Appears That Ants Live In Colonies."
Deduce the identity of the following compound from the spectral data given. C3H4BrN: H NMR, δ 2.98 (2H, triplet), 3.53 (2H, triplet) 13C NMR, δ 21.05 (triplet), 23.87 (triplet), 118.08 (singlet) (ppm):JR, 2963, 2254 cm" Express your answer as a chemical formula.
Answer: Br-CH₂-CH₂-C≡N (3-bromopropanenitrile)
Explanation:
The question tells us to " Deduce the identity of the following compound from the spectral data given. C3H4BrN: H NMR, δ 2.98 (2H, triplet), 3.53 (2H, triplet) 13C NMR, δ 21.05 (triplet), 23.87 (triplet), 118.08 (singlet) (ppm):JR, 2963, 2254 cm" Express your answer as a chemical formula".
Answer: Another Alternative to this is seen below
The Double Bond Equivalent of C₃H₄BrN = 3+1-4/2-1/2+1/2 = 2
2254 cm-1 Vc ≡N [IR analysis]
2963.4 = sp³Vc-H streek [IR analysis]
N≡C-CH₂-CH₂-Br (C₃H₄NBr)where the first CH₂ = b = 2.98 (2H,triplet) and
the second CH₂ = a = 3.53 (2H,triplet)
Note: where both are 1HNMR.
N≡C-CH₂-CH₂-Br
where C = c = 118.08 (singlet)
CH₂ = b = 21.05 (triplet)
CH₂ = a = 23.87 ( triplet)
Note: where all are 13CNMR
Important:
I have attached a copy of the solution to enhance better understanding in case the typed solution isn't clear enough.
An unknown gas diffusion 0.25 times as fast as he .what is the molecules mass of the unknown gas
Answer:
identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simultaneously. After a certain amount of time, it was found that 6.23 mL of O2 had passed through the membrane, but only 3.85 mL of of the unknown gas had passed through. What is the molar mass of the unknown gas
identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simultaneously. After a certain amount of time, it was found that 6.23 mL of O2 had passed through the membrane, but only 3.85 mL of of the unknown gas had passed through. What is the molar mass of the unknown gas
Explanation:
identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simultaneously. After a certain amount of time, it was found that 6.23 mL of O2 had passed through the membrane, but only 3.85 mL of of the unknown gas had passed through. What is the molar mass of the unknown gas
Barium fluoride, , is partially soluble with Ksp of 1.7e-06. What is the solubility of barium fluoride in pure water
Answer:
[tex]7.5x10^{-3}M[/tex]
Explanation:
Hello,
In this case, since the dissociation barium fluoride is represented at equilibrium by:
[tex]BaF_2(s)\rightleftharpoons Ba^{2+}(aq)+2F^-(aq)[/tex]
Hence, the equilibrium expression is:
[tex]Ksp=[Ba^{2+}][F^-]^2[/tex]
Whereas the molar solubility is represented as the reaction extent [tex]x[/tex]:
[tex]Ksp=[x][2x]^2[/tex]
In such a way, we can solve for [tex]x[/tex]:
[tex]1.7x10^{-6}=4x^3\\\\x=\sqrt[3]{\frac{1.7x10^{-6}}{4} } \\\\x=7.5x10^{-3}M[/tex]
Which as said before, is the molar solubility.
Best regards.
Which two philosophers challenged Democritus?
Answer:
I don't know the second one but one of them is Aristotle
Answer:
Aristrotle and John Dalton
Explanation:
Balanced chemical equations show:
the reactants entering the reaction
the products formed by the reaction
the ratios of moles needed to balance the reactants and products
all of the above
the products formed from the reaction
all of the above