(50 POINTS HELP)The manager of a restaurant chain wants to know how many times per month diners come to his restaurant. The table shows the number of visits in one month for three samples of 10 randomly chosen diners.


Answer the questions to find the means, compare the samples, and make a prediction.

1. What are the means of Samples 1 and 2? Show your work (what number did you use).

Write your answer in the space below.

The mean of sample 1 =

The mean of sample 2 =



2. What is the mean of Sample 3? Show your work (what number did you use).

Write your answer in the space below.


The mean of sample 3 =

3. Based on the data, would you predict that, in one month, the average diner would visit the restaurant fewer than 3 times, 3 or 4 times, or, about 4 times? Explain your reasoning.

Write your answer in the space below.

Answer:

Means

sample 1: 3.6

sample 2: 3.3

sample 3: 3.8

Step-by-step explanation:

Three or four times. All of these means are no less than three but no more than four this means that the average number of times is between three or four

a) The mean of the sample 1 = 3.6

b) The mean of the sample 2 = 3.3

c) The mean of the sample 3 = 3.8

d) In one month, the average diner would visit the restaurant 3 or 4 times

The mean value in a set of numbers is the middle value, calculated by dividing the total of all the values by the number of values.

Mean = Sum of Values / Number of Values

Given data ,

Let the mean of the sample 1 be represented as M₁

Let the mean of the sample 2 be represented as M₂

Let the mean of the sample 3 be represented as M₃

where the number of visits to restaurant in one month is given by

Sample 1 = { 5 , 2 , 6 , 4 , 4 , 7 , 2 , 1 , 2 , 3 }

The number of visits = 10 visits

The total sum of sample 1 = 36

So , mean M₁ = 36/10 = 3.6

And , Sample 2 = { 2 , 6 , 1 , 3 , 4 , 5 , 2 , 1 , 5 , 4 }

The number of visits = 10 visits

The total sum of sample 1 = 33

So , mean M₂ = 33/10 = 3.3

And , Sample 3 = { 3 , 3 , 6 , 4 , 1 , 5 , 3 , 4 , 4 , 5 }

The number of visits = 10 visits

The total sum of sample 1 = 38

So , mean M₃ = 38/10 = 3.8

And , the average diner would visit the restaurant 3 or 4 times because the mean value of the three samples lies between 3 and 4

Hence , the mean of the sample is solved

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