50 points
lab report guide (4).docx What do the results tell you about your hypothesis(es)? Results will tell you which hypothesis is true How do the data support your claim above?

The magnitude of the electrical force between the two identical electrical charges is 8.98755 × 10⁹N.

Given the data in the question;

Coulomb's law states "that the force between two electrical charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them".

It is expressed as;

[tex]F = k\frac{q_1q_2}{r^2}[/tex]

Here, [tex]q_1\ and\ q_2[/tex]  are the two electrical charges, r is the distance between them and k is the Coulomb constant (  [tex]k = 8.98755*10^9 kgm^3/s^2C^2[/tex])

To determine the electrical force between the two charges, we substitute our values into the expression above.

[tex]F = k\frac{q_1q_2}{r^2}\\\\F = (8.98755*10^9 kgm^3/s^2C^2)*\frac{(1C)(1C)}{(1m)^2}\\\\F = (8.98755*10^9 kgm^3/s^2C^2)*\frac{1C^2}{1m^2}\\\\F = 8.98755*10^9 kgm/s^2\\\\F = 8.98755*10^9 N[/tex]

Therefore, the magnitude of the electrical force between the two identical electrical charges is 8.98755 × 10⁹N.

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The magnitude of the electrical force between the two charges is 8.987×10⁹ N.

As per the coulomb's law,  the electrical force between any two charges separated by a distance of r is given by the formula,

[tex]F = k\dfrac{q_1q_2}{r^2}[/tex]

Given that the value of q₁ and q₂ is 1 coulomb, while the distance between them is 1 meter. Also, the value of k is 8.987×10⁹ N·m²·C⁻², therefore, the force can be written as,

[tex]F = k\dfrac{q_1q_2}{r^2}\\\\F = (8.987 \times 10^{9}) \times (\dfrac{1 \times 1}{1^2})\\\\F= 8.987 \times 10^{9}\rm\ N[/tex]

Hence, the magnitude of the electrical force between the two charges is 8.987×10⁹ N.

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The net torque on the seesaw is 294 Nm.

Torque is the force that tends to rotate the body to which it was applied.

To calculate the net torque, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, The net torque on the seesaw is 294 Nm.

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Explanation:

i think is per the International System of Units is Kelvin which is represented by the symbol K.

Answer:

The energy of these two photons would be the same as long as their frequencies are the same (same color, assuming that the two bulbs emit at only one wavelength.)

Explanation:

The energy [tex]E[/tex] of a photon is proportional to its frequency [tex]f[/tex]. The constant of proportionality is Planck's Constant, [tex]h[/tex]. This proportionality is known as the Planck-Einstein Relation.

[tex]E = h\, f[/tex].

The color of a beam of visible light depends on the frequency of the light. Assume that the two bulbs in this question each emits light of only one frequency (rather than a mix of light of different frequencies and colors.) Let [tex]f_{1}[/tex] and [tex]f_{2}[/tex] denote the frequency of the light from each bulb.

If the color of the red light from the two bulbs is the same, those two bulbs must emit light at the same frequency: [tex]f_{1} = f_{2}[/tex].

Thus, by the Planck-Einstein Relation, the energy of a photon from each bulb would also be the same:

[tex]h\, f_{1} = h\, f_{2}[/tex].

Note that among these two bulbs, the brighter one appears brighter soley because it emits more photons per unit area in unit time. While the energy of each photon stays the same, the bulb releases more energy by emitting more of these photons.

Answer:

-18,750N

Explanation:

90x1000

-------------

3600

u=25m/s

v=0m/s

v^2=u^2+2as

v=0

=625+(2×a×20)

625+40a

-625=40a

a= -15.625 m/s^2

F=ma

=(1200)(-15.625)

= -18,750N

Answer:

Temporary? You have two options

If you have a positively charged object, bring it close to the LEFT side of the ball (not touching it!).

If you have a negatively charged object, bring it close to the RIGHT side of the ball (again, not in contact).

Either way, the electron cloud will migrate towards the right side of the of your sphere.

Another option is to have a capacitor large enough to house the sphere inside it, and polarize it by attaching it to a DC source making sure that the negative plate of it is to the right of the sphere.

Answer:

a) 1500 j

b) 3000 j

c) 34.64 m/s

Explanation:

at halfway point 1/2 of the potential energy has been converted to kinetic energy

so 1 /2 P E =  1500 j

   it will still have the OTHER half of its PE     1500 j

c) PE will be entirely converted to KE when it is at the bottom

       KE = 1/2 m v^2

       3000 = 1/2 (5)(v^2)     show   v = 34.64 m/s

Explanation:

wavelength = l

speed of wave = v

frequency = f

v = lf → f = v/l = 2.42 × 10⁴ ÷ 1.1 = 2.2 × 10⁴ 1/s

T = 1/f = 1/ 2.2 × 10⁴ = 0.45 × 10 -⁴ s

The frequency of the sound wave produced from the drum is the speed divided by the wavelength. The frequency of the wave 22 kHz.

Frequency of a wave is the number of wave cycles per unit time. Frequency of a wave is directly proportional to the energy and inversely proportional to the wavelength.

The relation between speed of the wave c, wavelength and frequency of the wave can be written as follows:

c = νλ.

Given speed of the sound wave produced from the drum = 2.42 × 10⁴ m/s

wavelength λ = 110 cm = 1.1 m

The frequency of the sound wave  = speed/wavelength

ν = 2.42 × 10⁴ m/s / 1.1 m = 22000 Hz or 22 kHz.

Time period = 1/frequency

T = 1/ 22000 = 4.45× 10⁻⁵ seconds.

Therefore, the frequency of the wave is 22 kHz and time period of  4.45× 10⁻⁵ seconds.

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Answer:

The continents will be in different positions because tectonic plate boundaries are always moving.

For a mass m1 on the frictionless table, the speed m1 must rotate a with radius r if m2 is to remain hanging at rest is mathematically given as

[tex]v=\sqrt{m1/m2*xg}[/tex]

Generally, the equation for the Force  is mathematically given as

Fc=Fw

Therefore

[tex]\frac{m1v1}{x}=m2g[/tex]

[tex]v=\sqrt{m1/m2*xg}[/tex]

In conclusion,  if m2 is to remain hanging at rest the speed of ratio of m1 is calcuylated using

[tex]v=\sqrt{m1/m2*xg}[/tex]

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The value of the velocity for the mass m₁ on the frictionless table will be [tex]\rm v = \sqrt{\frac{m_1}{m_2 xg} }[/tex]. Velocity is a time-based component. Its unit is m/sec.

The change of distance with respect to time is defined as speed. Speed is a scalar quantity.

The given data in the problem is

m is the mass

g is the acceleration of free fall =10m/sec²

v is the velocity

From the balancing equation of force the centripetal force is equal to the weight;

[tex]\rm F_c= m_2 g \\\\ \rm \frac{m_1v_1^2}{x} = m_2 g \\\\ v= \sqrt{\frac{m_1}{m_2xg} } \\\\[/tex]

Hence the value of the velocity for the mass m₁ on the frictionless table will be [tex]\rm v = \sqrt{\frac{m_1}{m_2 xg} }[/tex].

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Explanation:

Gravity = 1.6 m/s^2

Mass = 85 kg

Full infomation needed your question is incomplete and BTW fomula : G Mm

R^2

Answer: 13%

Explanation: The reason this is 13 is because you can eat carlories and you can also be an amazing person 200 calories and 7 grams

Answer:

Yes

Explanation:

Displacement is the distance from the starting point to the end point. If you live and die at the same place, you will have 0m as your displacement.

Answer:

The change is momentum is given by ∆p=p(inital) - p(final) =4-2=2 kg.m/s

Explanation:

momentum is the product of mass and velocity (speed)

So it's initial momentum would be:

p=mv=(1)(4)=4 kg.m/s

It's final momentum is given by:

p=mv=(1)(2)=2 kg.m/s

[tex]\\ \rm\rightarrowtail T=2\pi\sqrt{\dfrac{l}{g}}[/tex]

[tex]\\ \rm\rightarrowtail T=2\pi\sqrt{\dfrac{4}{9.8}}[/tex]

[tex]\\ \rm\rightarrowtail T=2\pi(0.63887)[/tex]

[tex]\\ \rm\rightarrowtail T=1.27774\pi [/tex]

[tex]\\ \rm\rightarrowtail T=4.012s[/tex]

Answer: When a car is struck by lightning, the resulting electric field inside the car is zero.

Explanation:

The orientation with the largest magnetic torque on the dipole is Orientation B (See attached image).

The torque on the dipole is defined as:

τ = µ×B,

where B is the external magnetic field.

The magnitude of this torque is µB sinθ, where θ is the angle between B and µ

Magnetic Torque is highest when;

→     →

µ ⊥ β

That is when θ  = 90°. Hence B is the correct answer. Please see attached image.

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Answer:

b

Explanation:

no

Explanation:

no not an vibration signal

6.21 cm

where

Given:

solving step-wise:

[tex]\dashrightarrow \mathrm{T}=2 \pi \sqrt{\dfrac{\mathrm{L}}{\mathrm{g}}}[/tex]

[tex]\sf \dashrightarrow \mathrm{0.5}=2 \pi \sqrt{\dfrac{\mathrm{L}}{\mathrm{9.8}}}[/tex]

[tex]\dashrightarrow \mathrm{\dfrac{0.5}{2 \pi } }=\sqrt{\dfrac{\mathrm{L}}{\mathrm{9.8}}}[/tex]

[tex]\dashrightarrow\sqrt{\dfrac{\mathrm{L}}{\mathrm{9.8}}}= \mathrm{\dfrac{0.5}{2 \pi } }[/tex]

[tex]\sf \dashrightarrow{\dfrac{\mathrm{L}}{\mathrm{9.8}}}= (\mathrm{\dfrac{0.5}{2 \pi } })^2[/tex]

[tex]\sf \dashrightarrow{{\mathrm{L}}= (\mathrm{\dfrac{0.5}{2 \pi } })^2*9.8[/tex]

[tex]\sf \dashrightarrow{{\mathrm{L}}=0.06205922 \ m[/tex]

[tex]\sf \dashrightarrow{{\mathrm{L}}=6.2059\ cm[/tex]

[tex]\sf \dashrightarrow{{\mathrm{L}}=6.21\ cm[/tex]             { rounded to nearest hundredth }

Let's see

[tex]\\ \rm\rightarrowtail T=2\pi \sqrt{\dfrac{l}{g}}[/tex]

[tex]\\ \rm\rightarrowtail 0.5=2\pi \sqrt{\dfrac{l}{9.8}}[/tex]

[tex]\\ \rm\rightarrowtail 0.783=\pi \sqrt{l}[/tex]

[tex]\\ \rm\rightarrowtail 0.2494=\sqrt{l}[/tex]

[tex]\\ \rm\rightarrowtail \ell=0.0622m[/tex]

The visible spectrum is composed of red, orange,yellow,  green, blue, violet, indigo.

The visible spectrum refers to the portion of the electromagnetic spectrum that can be seen with the eyes. All other portions of the electromagnetic spectrum are invisible.

The question is incomplete as the details are missing. The visible spectrum is composed of red, orange,yellow,  green, blue, violet, indigo.

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Answer:

C

Explanation:

true because c is the best answer

Answer: The answer is C. It is true because the two cities are at the same latitude.

Explanation:

Hi I was doing the same test are u in flvs lol I am too if you are!

Explanation:

work = Force×distance

Force in this question is equal to the weight (force of gravity)

work = 1 × 1 = 1 J

Jole is the unit of work

Different patterns we observe in earth’s surface temperature due to angle, distance from the sun, latitude of the place and ocean currents.

The Earth's surface experiences a range of temperature due to different conditions such as angle of the sun, distance from the sun, the latitude of the place, distance from the sea, altitude of the place and ocean currents.

So we can conclude that different patterns we observe in earth’s surface temperature due to angle, distance from the sun, latitude of the place and ocean currents.

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Answer:

A

Explanation:

The endocrine system has all of the body's hormones it regulates the biological processes. For example it can help brain development, nervous system development, and it can regulate blood sugar. (This is the closest to A)

8n/m this is because 200×2500 all over 100 . 0's will cancile 0's living 200×2500×1 ,25 will go into 200 8 times ×1 =8n/m

The length by which the spring got stretched will be 0.08 m. The force is directly propotional to the distance by which the spring stretched.

The force required to extend or compress a spring by some distance scales linearly with respect to that distance is known as the spring force. Its formula is

F = kx

The given data in the problem is;

F is the spring force =200

K is the spring constant= 2500 N/m

x is the length by which spring got stretched =?

The stretch of the spring is found as;

[tex]\rm F=kx \\\\ x = \frac{F}{k} \\\\\ x= \frac{200}{2500} \\\\ x=0.08 \ m[/tex]

Hence the length by which the spring got stretched will be 0.08 m.

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Answer:

1.In dry cells, manganese dioxide acts as a ‘depolariser'.

In the depolarization process, the depolariser is used to remove hydrogen and doesn't allow the voltage to get reduced due to polarisation of the cell . Manganese oxide was used as a depolariser in Leclanché cell .

In zinc-carbon dry cell, the manganese dioxide takes in electrons as it is converted to Manganese III oxide (Mn2O3)

2.The fuse breaks the circuit if a fault in an appliance causes too much current flow. This protects the wiring and the appliance if something goes wrong. The fuse contains a piece of wire that melts easily. If the current going through the fuse is too great, the wire heats up until it melts and breaks the circuit.

The temperature difference between the wooden wall is 16⁰C, and the heat current per square metre of the wall is 7,325 W/m².

The temperature difference between the wooden wall is calculated as follows;

[tex]\frac{dQ_A}{dt } = \frac{dQ_B}{dt} \\\\\frac{K_A \Delta T_A \times A}{L_A} = \frac{K_B \Delta T _B \times A}{L_B}\\\\\frac{K_A \Delta T_A }{L_A} = \frac{K_B \Delta T _B}{L_B}\\\\\frac{0.5 \times 20}{0.1} = \frac{0.125 \times \Delta T _B }{0.02} \\\\100 = 6.25\Delta T _B\\\\\Delta T _B = \frac{100}{6.25} \\\\\Delta T _B = 16 \ ^oC[/tex]

Q = KL(ΔT)

Q = 0.5 x 0.1 x (20 + 273)

Q = 14.65 W

QA = W/A

QA = (14.65)/A

QA = 14.65/0.002

QA = 7,325 W/m²

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