Answer:
Since M1 has the higher probability of being in the desired range, we choose M1.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Two machines M1, M2 are used to manufacture resistors with a design specification of 1000 ohm with 10% tolerance.
So we need the machines to be within 1000 - 0.1*1000 = 900 ohms and 1000 + 0.1*1000 = 1100 ohms.
For each machine, we need to find the probabilty of the machine being in this range. We choose the one with the higher probability.
M1:
Resistors of M1 are found to follow normal distribution with mean 1050 ohm and standard deviation of 100 ohm. This means that [tex]\mu = 1050, \sigma = 100[/tex]
The probability is the pvalue of Z when X = 1100 subtracted by the pvalue of Z when X = 900. So
X = 1100
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{1100 - 1050}{100}[/tex]
[tex]Z = 0.5[/tex]
[tex]Z = 0.5[/tex] has a pvalue of 0.6915.
X = 900
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{900 - 1050}{100}[/tex]
[tex]Z = -1.5[/tex]
[tex]Z = -1.5[/tex] has a pvalue of 0.0668
0.6915 - 0.0668 = 0.6247.
M1 has a 62.47% probability of being in the desired range.
M2:
M2 are found to follow normal distribution with mean 1000 ohm and standard deviation of 120 ohm. This means that [tex]\mu = 1000, \sigma = 120[/tex]
X = 1100
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{1100 - 1000}{120}[/tex]
[tex]Z = 0.83[/tex]
[tex]Z = 0.83[/tex] has a pvalue of 0.7967.
X = 900
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{900 - 1000}{120}[/tex]
[tex]Z = -0.83[/tex]
[tex]Z = -0.83[/tex] has a pvalue of 0.2033
0.7967 - 0.2033 = 0.5934
M2 has a 59.34% probability of being in the desired range.
Since M1 has the higher probability of being in the desired range, we choose M1.
Which is the graph of r = 4 sine?
Answer:
you need to include a picture of all the graphs
30 - -5n + 16 + 3n =
Answer:
8n + 46
Step-by-step explanation:
Combine like terms. First, simplify the signs. two negatives directly next to each other equals one positive:
- (-5n) = + 5n
30 + 5n + 16 + 3n = (30 + 16) + (5n + 3n)
(30 + 16) = 46
(5n + 3n) = 8n
8n + 46 is your answer.
What are the coordinates of the roots of the equation 3+2x-x^2
Answer:
3+2x-x^3is the answer
How much do you need to subtract from 47/6 to make 7
Answer:
5
Step-by-step explanation:
47-5=42
42/6=7
5/6 is the number we have to subtract from 47/6 to make 7
What is Equation?Two or more expressions with an Equal sign is called as Equation.
We have to find the number when we need to subtract from 47/6 to make 7.
Let the unknown number be x
47/6-x=7
Add x-7 on both the sides
47/6-7=x
Take LCM as 6
(47-42)/6=x
When 42 is subtracted from 47 we get 5.
5/6=x
Hence, 5/6 we have to subtract from 47/6 to make 7
To learn more on Equation:
https://brainly.com/question/10413253
#SPJ2
A friend who works in a big city owns two cars, one small and one large. One-quarter of the time he drives the small car to work, and three-quarters of the time he takes the large car. If he takes the small car, he usually has little trouble parking and so is at work on time with probability 0.7. If he takes the large car, he is on time to work with probability 0.5. Given that he was at work on time on a particular morning, what is the probability that he drove the small car? (Give the answer to three decimal places.)
Answer:
The probability that he drove the small car is 0.318.
Step-by-step explanation:
We are given that a friend who works in a big city owns two cars, one small and one large. One-quarter of the time he drives the small car to work, and three-quarters of the time he takes the large car.
If he takes the small car, he usually has little trouble parking and so is at work on time with probability 0.7. If he takes the large car, he is on time to work with probability 0.5.
Let the Probability that he drives the small car = P(S) = [tex]\frac{1}{4}[/tex] = 0.25
Probability that he drives the large car = P(L) = [tex]\frac{3}{4}[/tex] = 0.75
Also, let WT = event that he is at work on time
So, Probability that he is at work on time given that he takes the small car = P(WT / S) = 0.7
Probability that he is at work on time given that he takes the large car = P(WT / L) = 0.5
Now, given that he was at work on time on a particular morning, the probability that he drove the small car is given by = P(S / WT)
We will use the concept of Bayes' Theorem for calculating above probability;
So, P(S / WT) = [tex]\frac{P(S) \times P(WT/S)}{P(S) \times P(WT/S)+P(L) \times P(WT/L)}[/tex]
= [tex]\frac{0.25 \times 0.7}{0.25 \times 0.7+0.75 \times 0.5}[/tex]
= [tex]\frac{0.175}{0.55}[/tex]
= 0.318
Hence, the required probability is 0.318.
In scheduling your time, which of the following will help you reach your goals?
a) Limiting the time you spend on any one task
b) Finding ways to multitask
c) Sticking to a daily routine
d) All of the above
Um investidor aplica R$ 1.000,00 a juros simples de 3% ao mês. Determine o valor recebido após um ano:
Responder:
$ 1360
Explicación paso a paso:
La pregunta está incompleta. Aquí está la pregunta completa.
Un inversor aplica R $ 1,000.00 a votos simples de 3% al año o más. Determinar o valor recibido después de 12 años:
Antes de determinar el valor recibido después de un año, necesitamos encontrar el interés simple sobre el dinero después de 12 años.
Interés simple = Principal * tasa * tiempo / 100
Principal dado = $ 1,000 (cantidad invertida)
Tasa = 3%
Tiempo = 1 año
SI = 1000 * 3 * 12/100
SI = 36000/100
SI = $ 360
Cantidad después de 12 años = Principal + Interés
Cantidad = $ 1000 + $ 360
Cantidad = $ 1360
A surf instructor has an initial fee of $12 and charges $8
per hour for lessons.
Explain how to determine what the y-intercept is and
where it would be located on the graph.
Answer:
For this case we can define y as the response variable and represent the cost and x the independent variable who represent the hours of lessons. We know that the instructor has an initial fee of 12 and charges 8 per hour. So then we can model the situation with this formula:
[tex] y =mx+b[/tex]
Where m = 8 represent the slope and b =12 the intercept so our model would be:
[tex] y = 8x +12[/tex]
And the y intercept would be at x=0 and y=12 and represent the initial amount of money that we need to pay in order to have the instructor.
Step-by-step explanation:
For this case we can define y as the response variable and represent the cost and x the independent variable who represent the hours of lessons. We know that the instructor has an initial fee of 12 and charges 8 per hour. So then we can model the situation with this formula:
[tex] y =mx+b[/tex]
Where m = 8 represent the slope and b =12 the intercept so our model would be:
[tex] y = 8x +12[/tex]
And the y intercept would be at x=0 and y=12 and represent the initial amount of money that we need to pay in order to have the instructor.
Answer:
y= 8x+12
Explanation:
I have just completed it. Thank me later.
Solve xy^m=yx^3 for m
Answer:
m = 1 + 2log(x)/log(y)
Step-by-step explanation:
Taking logarithms, you have ...
log(x) +m·log(y) = log(y) +3log(x)
m·log(y) = log(y) +2·log(x) . . . . subtract log(x)
m = (log(y) +2·log(x))/log(y) . . . divide by the coefficient of m
m = 1 +2·log(x)/log(y) . . . . . . . simplify a bit*
_____
* The "simplified" form will depend on your preference. Here, I like the integer 1 brought out because most logs are irrational. The result may be very slightly more accurate if we add 1, rather than log(y)/log(y)--depending on your calculator.
in triangle ABC, what is the measurement of angle c? A=2x B=6x C=2x
Answer:
36 degrees
Step-by-step explanation:
This problem can be solved with the help concept of sum of angles of any triangle.
sum of angles of any triangle is 180.
Given angular value of triangle ABC is A=2x B=6x C=2x
Thus sum of A, B , C is 180
A+B+C = 180 plug in th evalue of angle A, B and C
=>2x+6x+2x = 180
=> 10x=180
=> x = 180/10 = 18
Value of angle C in terms of x is 2x
Thus angular value of angle c = 2*18 = 36 degrees.
7 squared plus 7 cubed
Answer:
392
Step-by-step explanation:
49+343
Answer: 392
Step-by-step explanation: The term “squared“ means times two. And the term “cubed” times three. So multiply 7*7 then add that to 7*7*7
If you found this answer helpful, give it a five-star rating and a thanks!
(Maybe even a brainliest if you feel like it ;D)
kylie is 6 years younger than her brother. The sum of their ages is 22. How old is Kylie? How old is her brother
Glaucoma is a disease of the eye that is manifested by high intraocular pressure. The distribution of intraocular pressure in the general population is approximately normal with mean 16 mm Hg and standard deviation 3 mm Hg.
(a) What percentage of people have an intraocular pressure lower than 12 mm Hg?
(b) Fill in the blank. Approximately 80% of adults in the general population have an intraocular pressure that is greater than ________ (how many?) mm Hg.
Answer:
(a) 9.18% of people have an intraocular pressure lower than 12 mm Hg.
(b) 80% of adults in the general population have an intraocular pressure that is greater than 13.47 mm Hg.
Step-by-step explanation:
We are given that the distribution of intraocular pressure in the general population is approximately normal with mean 16 mm Hg and standard deviation 3 mm Hg.
Let X = intraocular pressure in the general population
So, X ~ Normal([tex]\mu=16,\sigma^{2} = 3^{2}[/tex])
The z score probability distribution for normal distribution is given by;
Z = [tex]\frac{ X-\mu}{\sigma } }[/tex] ~ N(0,1)
where, [tex]\mu[/tex] = population mean = 16 mm Hg
[tex]\sigma[/tex] = standard deviation = 3 mm Hg
(a) Percentage of people have an intraocular pressure lower than 12 mm Hg is given by = P(X < 12 mm Hg)
P(X < 12) = P( [tex]\frac{ X-\mu}{\sigma } }[/tex] < [tex]\frac{ 12-16}{3 } }[/tex] ) = P(Z < -1.33) = 1 - P(Z [tex]\leq[/tex] 1.33)
= 1 - 0.9082 = 0.0918 or 9.18%
The above probability is calculated by looking at the value of x = 1.33 in the z table which has an area of 0.9082.
(b) We have to find that 80% of adults in the general population have an intraocular pressure that is greater than how many mm Hg, that means;
P(X > x) = 0.80 {where x is the required intraocular pressure}
P( [tex]\frac{ X-\mu}{\sigma } }[/tex] > [tex]\frac{ x-16}{3 } }[/tex] ) = 0.80
P(Z > [tex]\frac{ x-16}{3 } }[/tex] ) = 0.80
Now, in the z table the critical value of z which represents the top 80% of the area is given as -0.842, that is;
[tex]\frac{ x-16}{3 } } = -0.842[/tex]
[tex]x -16 = -0.842 \times 3[/tex]
x = 16 - 2.53 = 13.47 mm Hg
Therefore, 80% of adults in the general population have an intraocular pressure that is greater than 13.47 mm Hg.
What is the solution to this equation?
5x - x + 12 + 2x - 7 = 10
A. X=
15
6
B. X=
15
7
C.
X =
V01
D. x=
Isolate the variable by dividing each side by factors that don't contain the variable.
Exact Form:
x=5 (over)/6
Decimal Form:
x=0.8¯3
(Hopefully this helped you solve the problem.)
The owner of an office building is expanding the length and width of a parking lot by the same amount. The lot currently measured 120ft by 80ft, and the expansion will increase its area by 4,400ft^2. By how many feet should the parking lot be increased?
Answer:
20
Step-by-step explanation:
The current area is 120(80)=9600 and he want to expand it by 4400 so that the new area will be 9600+4400=14000
14000=(120+x)(80+x)
14000=9600+200x+x^2
x^2+200x-4400=0
x^2-20x+220x-4400=0
x(x-20)+220(x-20)=0
(x+220)(x-20)=0, since x is an increase it must be greater than zero so
x=20ft
(120+20)(80+20)=14000ft^2
Which represents 236 as the sum of a whole number and a fraction? CLEAR CHECK 2+36 3+36 3+56 4+16
Question:
Which represents [tex]2 \frac{3}{6}[/tex] as the sum of a whole number and a fraction?
[tex]2+ \frac{3}{6}[/tex]
[tex]3 + \frac{3}{6}[/tex]
[tex]3+ \frac{5}{6}[/tex]
[tex]4+ \frac{1}{6}[/tex]
Answer:
[tex]2 \frac{3}{6}[/tex] as the sum of a whole number and a fraction is equivalent to [tex]2+ \frac{3}{6}[/tex]
Step-by-step explanation:
Given
Mixed Fraction: [tex]2 \frac{3}{6}[/tex]
Required
Express as the sum of a whole number and fraction.
Given that [tex]2 \frac{3}{6}[/tex] is a mixed fraction; it can be converted to the sum of a whole number and a fraction by following the steps below.
1. Convert the mixed fraction to improper fraction
[tex]2 \frac{3}{6} = \frac{(6 * 2 + 3)}{6}[/tex]
2. Split the numerator
[tex]2 \frac{3}{6} = \frac{((6 * 2) + (3))}{6}[/tex]
3. Split fraction to 2
[tex]2 \frac{3}{6} = \frac{(6 * 2)}{6} +\frac{(3)}{6}[/tex]
Simplify
[tex]2 \frac{3}{6} = \frac{(12)}{6} +\frac{(3)}{6}[/tex]
[tex]2 \frac{3}{6} = 2 + \frac{3}{6}[/tex]
Hence, [tex]2 \frac{3}{6}[/tex] as the sum of a whole number and a fraction is equivalent to [tex]2+ \frac{3}{6}[/tex]
The New York Transportation Department issued a report indicating that over the past year, on average, 234 accidents occurred at the intersection of Broad Street and Pine Street. The transportation department has indicated tahta traffic light will be installed if there is at least an 80% probability of more than two accidents at this intersection in any given week. What is the probability a light wil be installed? A. 11.3% B. 94.1% C. 17.4% D. 88.9% E. None of the above
Answer:
The correct option is B: 94.1%
Step-by-step explanation:
There are 52 weeks in a year so, if we divide 234 by 12 it gives 4.5 accidents per week on average. Given this information, we can say that in any randomly selected week, there will be an 80% probability of at least two accidents occurring on the said intersection. Hence, this means that a traffic light should be very likely will have to get installed in order to ensure safety of the residents.
Hope that answers the question, have a great day!
133+103=420-___ need help
BASE
Which angle has a positive measure?
Answer:
An angle with a positive measure will have rotated counterclockwise, or doesn't cross over itself at the start of the rotation. As you can see, the only graph that initially turns counterclockwise is the first graph.
Step-by-step explanation:
Estimate the range of 1,294 × 48 use a hyphen (-) to separate the two numbers
Answer:
54000-65000
Step-by-step explanation:
round the numbers first down to 1200 and 45, and multiply, then round up for the larger, like 1300 and 50 to get your answer.
You purchased a rare painting for $150 that is increasing in value by 3% annually. How many years will it take until it is doubled in value? Round to the nearest whole year
Answer:
23 years.
Step-by-step explanation:
It is given that the initial price of painting is $150 and its values increasing by 3% annually.
We need to find how many years will it take until it is doubled in value.
The value of painting after t years is given by
[tex]y=150(1+0.03)^t[/tex]
[tex]y=150(1.03)^t[/tex]
The value of painting after double is 300. Substitute y=300.
[tex]300=150(1.03)^t[/tex]
Divide both sides by 150.
[tex]2=(1.03)^t[/tex]
Taking log both sides.
[tex]\log 2=\log (1.03)^t[/tex]
[tex]\log 2=t\log (1.03)[/tex]
[tex]t=\dfrac{\log 2}{\log (1.03)}[/tex]
[tex]t=23.44977[/tex]
[tex]t\approx 23[/tex]
Therefore, the required number of years is 23.
Is 3 gallons of paint more than 15 quarts of paint??
Answer:
3 gallons is 12 quarts and is less than 15 quarts
Step-by-step explanation:
1 gallon = 4 quarts
2 gallons = 8 quarts
3 gallons = 12 quarts
Answer
no, 3 gallons is less than 15 quarts
Step-by-step explanation:
1 gallon=3 quarts
3 gallons=12 quarts
The amount of time people spend exercising in a given week follows a normal distribution with a mean of 3.8 hours per week and a standard deviation of 0.8 hours per week.
i) Which of the following shows the shaded probability that a person picked at random exercises less than 2 hours per week?
ii) What is the probability that a person picked at random exercises less than 2 hours per week? (round to 4 decimal places)
iii) Which of the following shows the shaded probability that a person picked at random exercises between 2 and 4 hours per week?
iv) What is the probability that a person picked at random exercises between 2 and 4 hours per week? (round to 4 decimal places)
Answer:
i and iii) In the figure attached part a we have the illustration for the area required for the probability of less than 2 hours and in b the illustration for the probability that X would be between 2 and 4
ii) [tex]P(X<2)=P(\frac{X-\mu}{\sigma}<\frac{2-\mu}{\sigma})=P(Z<\frac{2-3.8}{0.8})=P(z<-2.25)[/tex]
And using the normal standard table or excel we got:
[tex]P(z<-2.25)=0.0122[/tex]
iv) [tex]P(2<X<4)=P(\frac{2-\mu}{\sigma}<\frac{X-\mu}{\sigma}<\frac{4-\mu}{\sigma})=P(\frac{2-3.8}{0.8}<Z<\frac{4-3.8}{0.8})=P(-2.25<z<0.25)[/tex]
And we can find the probability with the following difference and usint the normal standard distirbution or excel and we got:
[tex]P(-2.25<z<0.25)=P(z<0.25)-P(z<-2.25)= 0.5987-0.0122= 0.5865[/tex]
Step-by-step explanation:
Let X the random variable that represent amount of time people spend exercising in a given week, and for this case we know the distribution for X is given by:
[tex]X \sim N(3.8,0.8)[/tex]
Where [tex]\mu=3.8[/tex] and [tex]\sigma=0.8[/tex]
Part i and iii
In the figure attached part a we have the illustration for the area required for the probability of less than 2 hours and in b the illustration for the probability that X would be between 2 and 4
Part ii
We are interested on this probability:
[tex]P(X<2)[/tex]
We can use the z score formula given by:
[tex]z=\frac{x-\mu}{\sigma}[/tex]
Using this formula we have:
[tex]P(X<2)=P(\frac{X-\mu}{\sigma}<\frac{2-\mu}{\sigma})=P(Z<\frac{2-3.8}{0.8})=P(z<-2.25)[/tex]
And using the normal standard table or excel we got:
[tex]P(z<-2.25)=0.0122[/tex]
Part iv
We want this probability:
[tex]P(2<X<4)[/tex]
Using the z score formula we got:
[tex]P(2<X<4)=P(\frac{2-\mu}{\sigma}<\frac{X-\mu}{\sigma}<\frac{4-\mu}{\sigma})=P(\frac{2-3.8}{0.8}<Z<\frac{4-3.8}{0.8})=P(-2.25<z<0.25)[/tex]
And we can find the probability with the following difference and usint the normal standard distirbution or excel and we got:
[tex]P(-2.25<z<0.25)=P(z<0.25)-P(z<-2.25)= 0.5987-0.0122= 0.5865[/tex]
o) x² – 18x - 19 + 20y - y2,
Answer:
19x-19+23y
Step-by-step explanation:
add the like terms
Which values are solutions to the inequality below. Check all that apply
x^2 >64
A.6
B. 8
C.11
D.-6
E.-8
F.-11
Answer:
x=8
Step-by-step explanation:
[tex]square \: both \: side \\ \sqrt{ {x}^{2} } = \sqrt{64 } \: \: \: \\ \\x = 8[/tex]
Suppose that y varies directly with x. Given x=4 when y=20.
Find y when x = 3
Answer:
y = 15
Step-by-step explanation:
Given: y varies directly with x, x=4 when y=20
To find: y when x = 3
Solution:
As y varies directly as x, it means that as x increases, y also increases by the same factor.
As y varies directly with x,
[tex]y=kx[/tex]
Here, k is a constant
As x = 4 when y = 20,
[tex]20=4k\\k=\frac{20}{4}=5\\\Rightarrow y=5x[/tex]
Put x = 3
[tex]y= 5(3) = 15[/tex]
Suppose 1000 people enter a chess tournament. The champion is determined in such a way that a player is eliminated after one loss and games are played until only one entrant has not lost. (Assume there are no ties.)
Required information:
The given tournament can be modeled as a full binary tree with the winner of the entire tournament as the root. Which of the following is true for the binary tree?
A. Each internal vertex represents the winner of the game played by its two siblings, and there are 1000 leaves, one for each contestant.
B. Each internal vertex represents the winner of the game played by its parents, and there are 2000 leaves, two for each contestant.
C. Each internal vertex represents the winner of the game played by its parents, and there are 1000 leaves, one for each contestant.
D. Each internal vertex represents the winner of the game played by its two children, and there are 1000 leaves, one for each contestant.
E. Each internal vertex represents the winner of the game played by its two children, and there are 2000 leaves, two for each contestant.
Answer:
Each internal vertex represents the winner of the game played by its parents, and there are 1000 leaves, one for each contestant.
Step-by-step explanation:
There are many ways to illustrate the rooted tree model to calculate the number of games that must be played until only one player is left who has not lost.
We could go about this manually. Though this would be somewhat tedious, I have done it and attached it to this answer. Note that when the number of players is odd, an extra game has to be played to ensure that all entrants at that round of the tournament have played at least one game at that round. Note that there is no limit on the number of games a player can play; the only condition is that a player is eliminated once the player loses.
The sum of the figures in the third column is 999.
We could also use the formula for rooted trees to calculate the number of games that would be played.
[tex]i=\frac{l - 1}{m - 1}[/tex]
where i is the number of "internal nodes," which represents the number of games played for an "m-ary" tree, which is the number of players involved in each game and l is known as "the number of leaves," in this case, the number of players.
The number of players is 1000 and each game involves 2 players. Therefore, the number of games played, i, is given by
[tex]i=\frac{l - 1}{m - 1} \\\\ i=\frac{1000 - 1}{2 - 1} \\\\= \frac{999}{1} \\\\=999[/tex]
Answer: C. Each internal vertex represents the winner of the game played by its parents, and there are 1000 leaves, one for each contestant.
Step-by-step explanation: A tree is a connected undirected graph with no simple circuits. When its elements has at most 2 children, it is a Binary Tree.
The tree is formed by nodes. The topmost node is called Root and except for it, every node is connected by a direct line from exactly one other node. This type of node is called Parent.
Parent can be direct connect to a number of other nodes, which are Children and can also be internal nodes.
NOdes with no children are Leaves or external nodes.
In the Binary Tree described by the question, the number of participants is 1000, so there will be 1000 leaves. Each internal vertex repsents the winner of a game played by its parents, i.e., each is a Child, a internal node.
The right answer is alternative C.
If 160 girls are in a school and 112 study latin what percent of them do latin...also could you show the process
Answer:
70%
Step-by-step explanation:
Divide the two numbers to get a decimal:
112/160 = 0.7
Multiply by 100:
0.7 * 100 = 70
Add a percent sign:
70%
70% percent of the girls in the school study Latin.
Please help 50point reward!! show evidence
1g: Is it over or under car payment
1h: How much is his car payment spending over or under the Guidelines?
-------------------------------------------------------------------------------------------------------
1i: car insurance Is it over or under?
1j: How much is his car insurance spending over or under the Guidelines? *
-------------------------------------------------------------------------------------------------------
Guidelines Transportation is 11% which = $671
Answer:
1g/h) transportation budget is $6100*0.11=$610+$61= $671
$671 - $150 = $521
So the car payments alone are $521 under the guidelines
1i/j)
$671 - $75 = $596
The car insurance alone is $596 under the guidelines
Note to really compare such things in the real world you would sum up the costs and add gas and repairs to it. That could make such a high budget for transportation plausible.
(would really, reallly appreciate the brainliest)
A department store wraps gifts for its customers. What is the amount of wrapping paper it would take to wrap a gift box with a width of 8 inches, a height of 6 inches, and a length of 5 inches?
Answer:[tex]236\ in.^2[/tex]
Step-by-step explanation:
Given
Dimension of gift box is
Width [tex]b=8\ in.[/tex]
height [tex]h=6\ in.[/tex]
Length [tex]L=5\ in.[/tex]
So, box is in shape cubiod
and its surface area is given by
[tex]S.A.=2(lb+bh+hl)[/tex]
[tex]S.A.=2(5\times 8+8\times 6+6\times 5)[/tex]
[tex]S.A.=2(40+48+30)[/tex]
[tex]S.A.=2\times 118[/tex]
[tex]S.A.=236\ in.^2[/tex]
So, [tex]236\ in.^2[/tex] of gift paper is required