5 plus 6 times 8 plus 9 times 10 plus 8 plus 4 plus 2 plus 9 plus 8 plus 7 plus 5 plus 7 plus 6 times 7 times 9 times 8 times 5 times 4 times 3 times 2 times 1 times 6 times 8 times 9 times 12 times 17 times 19 times 20 times 12 times 11 times 13 times 14 times 15 times 16

Answer:

[tex] \rm Numbers = 4 \ and \ -3.[/tex]

Step-by-step explanation:

Given :-

The sum of two numbers is 1 .

The product of the nos . is 12 .

And we need to find out the numbers. So let us take ,

First number be x

Second number be 1-x .

According to first condition :-

[tex]\rm\implies 1st \ number * 2nd \ number= -12\\\\\rm\implies x(1-x)=-12\\\\\rm\implies x - x^2=-12\\\\\rm\implies x^2-x-12=0\\\\\rm\implies x^2-4x+3x-12=0\\\\\rm\implies x(x-4)+3(x-4)=0\\\\\rm\implies (x-4)(x+3)=0\\\\\rm\implies\boxed{\red{\rm x = 4 , -3 }}[/tex]

Hence the numbers are 4 and -3

Step-by-step explanation:

[tex]numbers \: = x \: and \: y \\ x \times y = - 12......(1) \\ x + y = 1..... ..(2) \\y = 1 - x \\ put \: this \: in \: (1) \\ x(1 - x) = - 12 \\ x - {x}^{2} = - 12 \\ - x + {x}^{2} - 12 = 0 \\ factorise \\ {x}^{2} - 4x + 3x - 12 = 0 \\ x(x - 4) + 3(x - 4) = 0 \\ (x - 4)(x + 3) = 0 \\ x = + 4 \: or \: - 3 \\ thank \: you[/tex]

Answer:

The length of tape to wrap = 5 cm

Step-by-step explanation:

Let the length of tape used to wrap 1 present be = x

Tape length            Number of presents

   15 cm                            3

      x                                 1

     [tex]\frac{15}{x} = \frac{3}{1} \\\\x \times 3 = 1 \times 15\\\\x = \frac{15}{3} = 5 \ cm[/tex]

B. 63

some simple googling would've been able to help you with this. but 0 isn't prime or composite, not sure about 1, 19 is prime, 63 is a definite composite

Answer:

x² + 2² =(√15)²

x²+ 4. =15

x² =15-4

x² =11

x. =√11 mi

so the answer is 4th option

That's impossible. There are no solutions.

Answer:

_____________________________

2 x 5 = 10

2 x 4 = 8

10 + 8 = 18

______________________________

5 + 4 = 9

_______________________________

_ 9 = 18

18 : 9 = 2

Answer:

The answer is "6.093 years".

Step-by-step explanation:

The rate of decline in sales in [tex]22\%[/tex] per year.

The starting sales is 100 units:

Using compounding formula:

[tex]\to 100 \times (1-\frac{22}{100})^t=22\% \ of \ 100\\\\\to 100 \times (\frac{100-22}{100})^t=\frac{22}{100} \times \ 100\\\\\to (\frac{78}{100})^t=\frac{22}{100}\\\\\to 0.78^t=0.22\\\\\text{taking \log on both the sides}\\\\[/tex]

taking log on both sides

[tex]\to \log_e \ 0.78^t= \log_e\ 0.22\\\\\to t \log_e \ 0.78= \log_e\ 0.22\\\\\to t = \frac{\log_e 0.22}{\log_e 0.78}\\\\[/tex]

      [tex]= \frac{-0.6575}{-0.1079}\\\\= \frac{0.6575}{0.1079}\\\\=6.093[/tex]

Answer:

P=2.5

Step-by-step explanation:

12p = 25+5

12p = 30

P =30/12

Simplification:

P= 15/6

= 5/2 = 2.5

Answer: a^2 + b^2 = c^2

c^2 - a^2 = b^2 \/---

b^2

Step-by-step explanation: once completed you have ur answer

Answer:

[tex]\boxed {\boxed {\sf 18 \ yards}}[/tex]

Step-by-step explanation:

This triangle is a right triangle. We know this because of the small square in the corner representing a 90 degree angle. Therefore, we can use the Pythagorean Theorem.

[tex]a^2+b^2=c^2[/tex]

In this formula a and b are the legs of the triangle and c is the hypotenuse.

In this triangle, the legs are 24 and a, because these sides form the right angle. 30 is the hypotenuse because it is opposite the right angle.

Substitute the values into the formula.

[tex]a^2+(24)^2=(30)^2[/tex]

Solve the exponents.

[tex]a^2+ 576=900[/tex]

We are solving for a, the missing side of the triangle. We must isolate the variable. 576 is being added. The inverse of addition is subtraction, Subtract 576 from both sides of the equation.

[tex]a^2+576-576=900-576\\a^2=900-576\\a^2=324[/tex]

a is being squared. The inverse of a square is a square root. Take the square root of both sides.

[tex]\sqrt{a^2}=\sqrt{324}\\a=\sqrt{324}\\a=18[/tex]

The missing side of the triangle is 18 yards.

Answer:

[tex]h = 6 + 11 - 22 \\ h = 17 - 22 \\ h = - 5[/tex]

Answer:

-5

Step-by-step explanation:

6+11 = 17↓

17-22 = -5

or

11-22 = -11↓

-11+6 = -5

Answer:

did i got it correct if yes follow plz

used a graphing tool to, well, graph it

see the solution in the screenshot, it's the point where the two lines intersect

Answer:

Step-by-step explanation:

slope>0 so graph is increasing.

[tex] \huge\boxed{\mathfrak{Answer}}[/tex]

[tex]3(x + 4) = 123 \\ 3x + 12 = 123 \\ 3x = 123 - 12 \\ 3x = 111 \\ x = \frac{111}{3} \\ x = 37[/tex]

=> The answer is 37.

Answer:

X=37

Step-by-step explanation:

3(x+4)=123

3x+12=123

3x=123-12

3x=111

3x/3 =111/3

x=37

( f ∘ g ) ( x ) is equivalent to f ( g ( x ) ) . We solve this problem just as we solve f ( x ) . But since it asks us to find out f ( g ( x ) ) , in f ( x ) , each time we encounter x, we replace it with g ( x ) . In the above problem, f ( x ) = x + 3 . Therefore, f ( g ( x ) ) = g ( x ) + 3 . ⇒ ( f ∘ g ) ( x ) = 2 x − 7 + 3 ⇒ ( f ∘ g ) ( x ) = 2 x − 4 Basically, write the g ( x ) equation where you see the x in the f ( x ) equation. f ∘ g ( x ) = ( g ( x ) ) + 3 Replace g ( x ) with the equation f ∘ g ( x ) = ( 2 x − 7 ) + 3 f ∘ g ( x ) = 2 x − 7 + 3 we just took away the parentheses f ∘ g ( x ) = 2 x − 4 Because the − 7 + 3 = 4 This is it g ∘ f ( x ) would be the other way around g ∘ f ( x ) = 2 ( x + 3 ) − 7 now you have to multiply what is inside parentheses by 2 because thats whats directly in front of them. g ∘ f ( x ) = 2 x + 6 − 7 Next, + 6 − 7 = − 1 g ∘ f ( x ) = 2 x − 1

Hello,

[tex]f(x)=7x-3\\g(x)=x^2\\\\(fog)(x)=g(f(x))=g(7x-3)=(7x-3)^2=49x^2-42x+9\\\\(gof)(x)=f(g(x))=f(x^2)=7x^2-3\\\\(fog)(0)=g(f(0))=49*0^2-42*0+9=9\\\\(gof)(0)=f(g(0))=7*0^2-3=-3\\[/tex]

Since i don't know what is (g°O(1)  and you haven't correct your question ,

i has put the 2 possibles answsers.

Answer:

-2,-1,0,1,2

Step-by-step explanation:

Answer:

-2.0

0,0

Step-by-step explanation:

i just did the test

Answer:

38

Step-by-step explanation:

To find the value of f(6), we substitute the value 6 where x is into the function. You would get:

7(6) - 4

42 - 4

f(6) = 38

Answer:

See my writting here have answer

Given:

Total number of gym members = 685

257 said they use the treadmill, 157 said they use the elliptical, and 85 said they use both.

To find:

a. The venn diagram.

b. The probability that a member uses the treadmill only?

Solution:

(a)

We have,

Total number of gym members = 685

Treadmill user = 257

Elliptical user = 157

Who use both = 85

Only treadmill user is:

[tex]257-85=172[/tex]

Only Elliptical used

[tex]157-85=72[/tex]

Therefore, the venn diagram for the given situation is shown below.

(b)

The member who use treadmill only = 172

Total user = 685

The probability that a member uses the treadmill only is:

[tex]P(\text{Only treadmill})=\dfrac{\text{Only treadmill users}}{\text{Total users}}[/tex]

[tex]P(\text{Only treadmill})=\dfrac{172}{685}[/tex]

Therefore, the probability that a member uses the treadmill only is [tex]\dfrac{172}{685}[/tex].

Given:

Cost of gift = $20.48

Mark pays for [tex]\dfrac{2}{3}[/tex] of the gift and John pays for the remaining [tex]\dfrac{1}{3}[/tex].

To find:

The amount paid by each boy.

Solution:

We have,

Cost of gift = $20.48

Mark pays for [tex]\dfrac{2}{3}[/tex] of the gift. So, the amount paid by Mark is:

[tex]20.48\times \dfrac{2}{3}\approx 13.653[/tex]

John pays for the remaining [tex]\dfrac{1}{3}[/tex]. So, the amount paid by John is:

[tex]20.48\times \dfrac{1}{3}\approx 6.827[/tex]

Therefore, the amount paid by Mark and John are $13.653 and $6.827 respectively.

Answer:

d)

Step-by-step explanation:

>The domain are all the values of x , so you can graph on the calculator that on the x-axis the graph starts at 9 and keeps going to the right so the domain is x≥9 or [9,∞)

or

>Solve for x in the given equation when f(x) =y = 0 to find the roots

√(x-9) = 0 , square both sides

x-9 = 0 , add 9 to both sides

x= 9

from this root the graph moves to the right to ∞

the domain is [9, ∞)

Answer:

h

Step-by-step explanation:

Answer:

Step-by-step explanation:

MM oute le iloa

Answer:

C. x ≥ -4

General Formulas and Concepts:

Pre-Algebra

Equality Properties

Step-by-step explanation:

Step 1: Define

Identify

-10x ≤ 40

Step 2: Solve for x

Answer:

C. x ≥ -4

Step-by-step explanation:

To solve this inequality isolate the variable. Do this by using the properties of equality, specifically the division property. So, divide both sides by -10. This equals, x ≤ -4. However, whenever an inequality is divided or multiplied by a negative number the sign must be flipped. Therefore, the final answer is x ≥ -4.

Answer:

The answer is

[tex] \frac{3}{x} = \frac{11}{10} - \frac{4}{5} \\ \frac{3}{x} = \frac{55 - 40}{50} \\ \frac{3}{x} = \frac{15}{50} \\ \frac{3}{x} = \frac{3}{10} \\ x = 10[/tex]

Answer:

[tex] a_n = 2n^2 + n + 1 [/tex]

Step-by-step explanation:

4, 11, 22, 37, 56

11 - 4 = 7

22 - 11 = 11

37 - 22 = 15

56 - 37 = 19

After the first difference, 11 - 4 = 7, each difference is 4 more than the previous difference.

Difference of differences:

11 - 7 = 4

15 - 11 = 4

19 - 15 = 4

Since we need the difference of differences to find a constant, this must be a second degree function.

[tex] a_1 = 4 = 2^2 + 1(0)[/tex]

[tex] a_2 = 11 = 3^2 + 2 = 3^2 + 2(1) [/tex]

[tex] a_3 = 22 = 4^2 + 6 = 4^2 + 3(2) [/tex]

[tex] a_4 = 37 = 5^2 + 12 = 5^2 + 4(3) [/tex]

[tex]a_5 = 56 = 6^2 + 20 = 6^2 + 5(4)[/tex]

[tex] a_n = (n + 1)^2 + (n)(n - 1) [/tex]

[tex] a_n = (n + 1)^2 + (n)(n - 1) [/tex]

[tex] a_n = n^2 + 2n + 1 + n^2 - n [/tex]

[tex] a_n = 2n^2 + n + 1 [/tex]

Answer:

$5084745.76271

Step-by-step explanation:

Given data

Final amount= $6000000

Rate=6%

Time= 3 years

Now let us find the initial amount which is the principal

using the simple interest formula we have

6000000 = P(1+0.06*3)

6000000 =P(1+0.18)

6000000 =P*1.18

P= 6000000 /1.18

P=$5084745.76271

Hence the initial deposite is $5084745.76271

Step-by-step explanation:

So here is my attempt. And i guess its correct

Answer:

[tex]\frac{1}{2^{n} }[/tex]

Step-by-step explanation:

The rules of exponents state that

[tex]a^{-m}[/tex] = [tex]\frac{1}{a^{m} }[/tex] and [tex]a^{0}[/tex] = 1

Thus

[tex]2^{-5}[/tex] = [tex]\frac{1}{2^{5} }[/tex] = [tex]\frac{1}{32}[/tex]

[tex]2^{-4}[/tex] = [tex]\frac{1}{2^{4} }[/tex] = [tex]\frac{1}{16}[/tex]

[tex]2^{-3}[/tex] = [tex]\frac{1}{2^{3} }[/tex] = [tex]\frac{1}{8}[/tex]

and so on , to

[tex]2^{0}[/tex] = 1

Given:

The batting order for nine players on a team with 11 people.

To find:

The number of possibilities for the given scenario.

Solution:

First, we need to select 9 players from 11 people, it involves combination, i.e. [tex]^{11}C_9[/tex].

Second, we need to arrange the order of 9 selected players, it involves permutation, i.e., [tex]^9P_9[/tex].

The number of possibilities for the given scenario is:

[tex]\text{Possibilities}=^{11}C_9\times ^9P_9[/tex]

[tex]\text{Possibilities}=\dfrac{11!}{(11-9)!9!}\times \dfrac{9!}{(9-9)!}[/tex]

[tex]\text{Possibilities}=\dfrac{11\times 10\times 9!}{2!9!}\times \dfrac{9!}{0!}[/tex]

[tex]\text{Possibilities}=\dfrac{110}{2\times 1}\times \dfrac{9\times 8\times 7\times 6\times 5\times 4\times 3\times 2\times 1}{1}[/tex]

[tex]\text{Possibilities}=55\times 362880[/tex]

[tex]\text{Possibilities}=19958400[/tex]

Therefore, the following scenario involves both permutation and combination, and the number of possibilities is 19958400.