5. An acrobat, starting from rest, swings freely on a trapeze of
length 3.7 m (Figure 6). If the initial angle of the trapeze is
48°, use the law of conservation of energy to determine
(a) the acrobat's speed at the bottom of the swing
(b) the maximum height, relative to the initial position, to
which the acrobat can rise

Answers

Answer 1

The energy conservation and trigonometry we can find the results for the questions about the movement of the acrobat are;

     a) The maximum speed is v = 4.89 m / s

     b) The maximum height is h = 1.22 m

The energy conservation is one of the most fundamental principles of physics, stable that if there are no friction forces the mechanistic energy remains constant. Mechanical energy is the sum of the kinetic energy plus the potential energies.

               Em = K + U

Let's write the energy in two points.

Starting point. Highest part of the oscillation

            Em₀ = U = m g h

Final point. Lower part of the movement

            [tex]Em_f[/tex] = K = ½ m v²

Energy is conserved.

            Emo = [tex]Em_f[/tex]  

            m g h = ½ m v²

            v² = 2 gh

Let's use trigonometry to find the height, see attached.

         h = L - L cos θ

         h = L (1- cos θ)

They indicate that the initial angle is tea = 48º and the length is L = 3.7 m, let's calculate.

         h = 3.7 (1- cos 48)

          h = 1.22 m

this  is the maximum height of the movement.

Let's calculate the velocity.  

          [tex]v= \sqrt{2 \ 9.8 \ 1.22}[/tex]  

          v = 4.89 m / s

In conclusion using the conservation of energy and trigonometry we can find the results for the questions about the movement of the acrobat are;

     a) The maximum speed is v = 4.89 m / s

     b) The maximum height is h = 1.22 m

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5. An Acrobat, Starting From Rest, Swings Freely On A Trapeze Oflength 3.7 M (Figure 6). If The Initial

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From the experiment, the constructed conclusion was that;

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I'll Head Is Boiling From Question That Keeps Popping Up My Head, Someone Might Give You A Positive Hand

A student tested a variety of interacting forces to determine how they would result in motion of an object. If the student used the forces as shown in the lettered choices above, predict which results would occur. Select ALL that apply.A) The variable shown by letter B would result in a movement of the object to the left. B) The variable shown by letter B would result in a movement of the object to the right. C) The variable shown by letter A would result in a movement of the object to the right. D) The variable shown by letter C would result in a movement of the object to the right. E) The variable shown by letter D would result in a movement of the object

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Answer:

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An astronomer discovers a massive galaxy which has four nuclei. What is a likely explanation for a galaxy having more than one nucleus

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Answer:

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Explanation:

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how have astronomers interpreted the unexpectedly fast rotation of galaxies

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Answer:

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given a force of 88N and an acceleration of 4 m/s 2, what is the mass?

Answers

Answer:22kg

Explanation:

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a uniform metre rule of mass 100g balances at the 40cm mark when a mass X is placed at the 10cm mark what is the value of x.pls help I don't know how to solve it​

Answers

Answer:

The fulcrum of the metre stick is at the 40 cm mark

100 g * 10 cm = 1000 g-cm clockwise torque

x * 30 cm = 1000 gm-cm = counterclockwise torque for balance

X = 1000 / (40 -10) = 1000 / 30 = 33.3 gm  at 10 cm to balance

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Answer:

Explanation:

Amplitude is a measure of the size of sound waves. It depends on the amount of energy that started the waves. Greater amplitude waves have more energy and greater intensity, so they sound louder.

Answer:

Amplitude determines the loudness of a wave. Greater the amplitude, greater is the loudness.

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Lead pellets, each of mass 1.10 g, are heated to 200°C. How many pellets must be added to 536 g of water that is initially at 20.0°C to make the equilibrium temperature 25.0°C? Neglect any energy transfer to or from the container.

Answers

The number of lead pellets to be added to the water to achieve the given equilibrium temperature is 451.54.

The given parameters;

mass of each lead pellets, m = 1.10 gtemperature of the lead, = 200 °Cmass of water, = 536 gtemperature of the water, = 25 °Cspecific heat capacity of water = 4.184 J/g°Cspecific heat capacity of lead, = 0.129 J/g°C

Apply the principle of conservation of energy to determine the number of lead pellets to be added to given water to achieve the given equilibrium temperature.

Heat lost the lead = Heat absorbed by the water

[tex]m_lC_{l} \Delta t_l = m_wC_{w} \Delta t_w\\\\(n\times m)C_{l} \Delta t_l = m_wC_{w} \Delta t_w\\\\n(1.1)(0.129)(200 - 25) = (536)(4.184)(25-20)\\\\24.833n = 11,213.12\\\\n = \frac{11,213.12}{24.833} \\\\n = 451.54 \[/tex]

Thus, the number of lead pellets to be added to the water to achieve the given equilibrium temperature is 451.54.

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Answer:

A covalent bond consists of the mutual sharing of one or more pairs of electrons between two atoms. These electrons are simultaneously attracted by the two atomic nuclei. A covalent bond forms when the difference between the electronegativities of two atoms is too small for an electron transfer to occur to form ions.

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Answers

This is the answer, (Vout )=V / (R1 + R2) x R2

Historia de baloncesto internacional resumen

Answers

Answer:

?

Explanation:

The 5.0-m-long rope in (Figure 1) hangs vertically from a tree right at the edge of a ravine. A woman wants to use the rope to swing to the other side of the ravine. She runs as fast as she can, grabs the rope, and swings out over the ravine.
When she's directly over the far edge of the ravine, how much higher is she than when she started?
Given your answer to Part A, how fast must she be running when she grabs the rope in order to swing all the way across the ravine?

Answers

She is 1.0 m higher than she is when she started. The speed at which the woman must be running when she grabs the rope is 4.427 m/s

Suppose we consider the Figure 1 to be a right-angle triangle;

where;

the hypotenuse is the rope = (5.0 m),the opposite side is the ravine = (3.0 cm) and;the adjacent is the slant imaginary distance = (x)

Using Pythagoras rule;

(hyp)² = opp² + adj²

5.0² = 3.0² + x²

x² = 25 - 9

x² = 16

x = √16

x = 4 m.

When she is directly over the far edge of the ravine, the height at which she is far higher than where she started is:

= 5cm - 4cm

= 1 cm

The speed at which the woman must be running when she grabs the rope can be determined by taking both the potential energy and kinetic energy of the system, which can be computed as:

mgh = 1/2 mv²

Making the speed the subject of the formula, we have:

[tex]\mathbf{v = \sqrt{2gh}}[/tex]

[tex]\mathbf{v = \sqrt{2\times 9.8 \times 1.0}}[/tex]

v = 4.427 m/s

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What can we say about energy on
the low end of the
electromagnetic spectrum?

A. They have longer wavelengths and less dangers.

B. They have lower frequencies and more energy.

C. They have shorter wavelengths and less dangers.

D. They have higher frequencies and more energy.

Answers

Answer:

A. Longer wavelengths and less dangers

Explanation:

Radio waves are at the lowest end of the EM spectrum, they have the longest wavelength of any other EM waves, the lowest energy and, accordingly, the lowest frequency;

Their low energy and frequency means they pose little risk of harm or danger as they don't get absorbed by human being.

A 0.04 kg honeybee circles a field looking for a flower upon which to land. The radius of the circle she travels is 2.5 m and it takes her 1.57 s to complete the circle.

Find the following:
a) Tangential Velocity
b) Centripetal Acceleration
c) Centripetal Force.​

Answers

For the honeybee that circles a field looking for a flower upon which to land, we have:

a) The tangential velocity is 10.01 m/s.

b) The centripetal acceleration is 40.1 m/s².

c) The centripetal force is 1.60 N.

a) The tangential velocity can be calculated as follows:

[tex] v = \omega r = \frac{2\pi r}{T} [/tex]  (1)

Where:

r: is the radius of the circle = 2.5 m

ω: is the angular velocity = 2π/T

T: is the period = 1.57 s

By entering the above values into equation (1), we have:

[tex] v = \frac{2\pi r}{T} = \frac{2\pi 2.5 m}{1.57 s} = 10.01 m/s [/tex]  

Hence, the tangential velocity is 10.01 m/s.

b) The centripetal acceleration is related to the tangential velocity as follows:

[tex] a_{c} = \frac{v^{2}}{r} = \frac{(10.01 m/s)^{2}}{2.5 m} = 40.1 m/s^{2} [/tex]

Therefore, the centripetal acceleration is 40.1 m/s².

c) The centripetal force is given by:

[tex] F = ma_{c} [/tex]

Where:

m: is the honeybee's mass = 0.04 kg

[tex] F = ma_{c} = 0.04 kg*40.1 m/s^{2} = 1.60 N [/tex]

Hence, the centripetal force is 1.60 N.

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Calculate the charge on two identical spheres that are similarly charged if they are separated by 20cm and the electrostatic force between them is 0.006 N.

Answers

Answer:

[tex]Q = 21.09 \times 10^{-8} C[/tex]

Explanation:

We know from theory that the magnitude of the force between two charges is measured by the expression

[tex]F=\frac1{4\pi\epsilon} \frac{Qq}{r^2}[/tex]

We know that two spheres have the same charge, and let's assume they're in a vacuum, so [tex]\epsilon = \epsilon_0 =8.85\times10^{-12} C^2/Nm^2[/tex]

At this point we can solve for Q

[tex]Q^2 = 4\pi\epsilon F r^2 = 4\pi \times (8.85 \times 10^-12)\times (6\times 10^-3) \times (2 \times 10^-1)^2 = 444.624 \times 10^{-17} = 4446.24\times 10^-16 C^2 \rightarrow Q = 21.09 \times 10^{-8} C[/tex]

Double check calculations for safety, as usual

What is the anomalous expansivity of water

Answers

Answer:

The anomalous expansion of water is an abnormal property of water whereby it expands instead of contracting when the temperature goes from 4°C to 0°C, and it becomes less dense. The density becomes less and less as it freezes because molecules of water normally form open crystal structures when in solid form.

if acceleration due to gravity is 10m/s², what will be the potential energy of a body of mass 2 kg kept at a height of 5 meter ?​

Answers

Answer:

50J

Explanation:

Ep = mgh

Here,

m = 1kg; g = 10 m/s2; h = 5m

So, Ep = 1kg*10m/s2*5m

= 50J

So, the potential energy is 50J (Ans).

As an object falls freely to the ground, what happens to its acceleration? increase decrease remains the same.

Answers

The acceleration will remain the same (assuming air resistance is negligible or consistent) however the velocity will change in magnitude.

Electric current can be measured. It is a rate. What does that mean?
Question 3 options:


The amount of current that passes a certain point in a certain amount of time


The amount of energy available that could be used


The strength of power used by something plugged into a wall


How bright a light will burn when plugged in

Answers

Answer:

a

Explanation:

cuz im smart ;)

What is an electron cloud 5th grade short answer.

Answers

Answer:

the system of electrons surrounding the nucleus of an atom

If your neighbor leaves his house, walks 2 miles south, then turns around and walks home, what is his displacement?

Answers

Answer:

0

Explanation:

The neighbors displacement is 0 as displacement is how far the person is from their starting location. If they walk 2 miles away and then head back those 2 miles back to their house; 2-2=0

0 because displacement is a state function!!!

This means that it is where he started vs. where he ended up, it doesn’t matter the steps in between!!
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