5. A ball is shot directly into the air vertically with an
initial velocity of 49.7 m/s. What is the velocity of the
ball after 3 seconds?
a. 3.4 m/s
b. 20.3 m/s
c. 12.4 m/s
d. 202.0 m/s

Answer:

gunrun

Explanation:

Inside the bar magnet, the magnetic field points from north to south. Statement A is correct.

Magnetic Field:

It is defined as a vector field or the influence of the magnet on the electric current, charges and ferromagnetic substance.

The strength of magnetic field is depends up on the numbers of magnetic field lines per unit area.

Therefore, inside the bar magnet, the magnetic field points from north to south.

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Answer:b

Explanation:

Answer:

Matter

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Answer:

$2140

Explanation:$2000 missing plus 7 percent of 2000 is 140 so 2000+140=2140. Each month she would pay $268 approx.

Answer:

25.48

Explanation:

The magnitude of the magnetic force acting on the charge which moves to the right is 0 N.

Given to us,

the charge [tex]q[/tex] =  [tex]5\times 10^{-7}[/tex] C,

the velocity [tex]v[/tex] = [tex]2.6\times 10^5[/tex]  m/sec,

the magnetic field [tex]B[/tex] = [tex]10^{-2}[/tex] T,

angle between the direction of v and B [tex]\theta[/tex] = 0,

Magnetic force is as important as the electrostatic or Coulomb force. The magnitude of the magnetic force F on a charge q moving at a velocity of v in a magnetic field of strength B is given by

[tex]\begin{aligned}F&=qvB\ sin\Theta\\&= 5\times10^{-7}\times2.6\times10^5\times10^{-2} \times sin(0)\\&= 0\ N\\\end{aligned}[/tex]

Hence, the magnitude of the magnetic force acting on the charge which moves to the right is 0 N

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1. • Here, force of gravity on the block = 20 N.

• Therefore, the normal force will also be the same, i.e., 20 N [According to Newton's Third Law, on every action, there is an equal and opposite reaction]

• The coefficient

[tex] u_{k} = 0.4[/tex]

• Force of friction =

[tex]u_{k} \times \: normal \: \: \: force \\ = 0.4 \times 20N \\ = 8N[/tex]

• Hence, the force of sliding friction between the block and the ground is 8 N.

• So, it is option c. 8 N

2. The answer is option d. continue in the same direction with no change in speed.

We know, force = mass × acceleration. When force is 0, then acceleration will also be 0 since mass cannot be 0. So, there will be no change in speed.

3. It is option b. force that is required to give a one kilogram object the acceleration of 1 m/s^2.

Newton is the SI unit of force. As mentioned earlier, force = mass × acceleration. The SI unit of mass and acceleration is Kg and m/s^2 respectively.

So, 1 N = 1 Kg × 1 m/s^2.

4. It is d. not zero.

Acceleration is the change in speed. So, if the force is zero, then acceleration will not occur.

5. Force = 2 N

Acceleration of the object A = 2 m/s^2.

Acceleration of the object B = 1 m/s^2.

Therefore, mass of the object A = 2 N ÷ 2 m/s^2 = 1 Kg

And, mass of the object B = 2 N ÷ 1 m/s^2 = 2 Kg

So, the mass of object B is greater than that of object A.

Hence, the answer is option c. Object B has more mass.

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Answer:

I hope this helps:)

Explanation:

good luck:)

Answer:

less than.

Explanation: because Friction is the resistance to motion of one object moving relative to another. which means it cant be greater because how would it be greater if its pushing forward when friction is the resistance.

THANKS FOR THE POINTS :D

St. John’s

_________

o0o0o0o0o0

3. Distance is a quantity that is always a vector.

B.

Answer:

They are kg * m/s.

The unit of the momentum p would be kg × m/s..

Momentum is defined as the ability or tendency of an object to continue moving.

Also momentum is the product of mass and velocity. It can be shown as follows;

p = m × v

where,    

p = momentum

m = mass

v = velocity

Thus, we can conclude that the formula p = mv show the relationship between momentum, mass, and velocity.

Now the unit of the momentum p would be;

p = m × v

p = kg × m/s

Hence, the unit of the momentum p would be kg × m/s.

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A motion in one dimension is a type of motion that is always along a straight line and has a constant acceleration.

Motion refers to a change in the location (position) of an object or physical body with respect to a reference point, especially due to the action of an external force.

In Science, the motion of an object or physical body is described in terms of the following parameters:

Furthermore, there are three (3) forms of motion based on dimension and these include:

1. Motion in one dimension

2. Motion in two dimension

3. Motion in three dimension

A motion in one dimension (one-dimensional motion) is also referred to as rectilinear or linear motion. Also, it is always along a straight line in any direction and characterized by constant acceleration.

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The magnitude and the position of the 350 N vector can be represented using arrow pointing out from the South-East of a Cartesian coordinate.

The given parameters:

The vector is represented with arrow pointing out from south-east represented in a Cartesian coordinate.

Thus, the magnitude and the position of the 350 N vector can be represented using arrow pointing out from the South-East of a Cartesian coordinate.

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Hi there!

I. They are the same.

Due to the Conservation of Momentum, an explosion as such means that the TOTAL momentum of the system (all of the pieces) is conserved.

Answer:

mesa

Explanation:



A mesa is a flat-topped mountain or hill. It is a wide, flat, elevated landform with steep sides. ... Spanish explorers of the American southwest, where many mesas are found, used the word because the tops of mesas look like the tops of tables.

Answer:

the interval between transits of the apparent or mean sun across the meridian at any place.

The total momentum of the system is conserved and the momentum did not change.

The given parameters:

The initial momentum of the system is calculated as follows;

[tex]P_i = m_1 u_1 + m_2 u_2\\\\P_i = 0.17 \times 4 \ + \ 0.16(0)\\\\P_i = 0.68 \ kg m/s[/tex]

The final momentum of the system is calculated as follows;

[tex]P_f = m_1 v_1 + m_2 v_2 \\\\P_f = 0.17 (0) \ + 0.16(4.25)\\\\P_f = 0.68 \ kg m/s[/tex]

Thus, the total momentum of the system is conserved and the momentum did not change.

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The characteristics of the kinematics allow to find the results for the questions about the movement of the body are:

a)  we have four sections;

b)  The acceleration is the first 8 s is:  a = 0.25 m / s²

c) The maximum acceleration is:    a = 1 m / s²

d) The displacement   is:  i) d₁ =  8m,     ii)  [tex]d_{total}[/tex]= 16 m

e) maximum speed  is:      v = 6 m / s

Kinematics studies the movement of bodies by finding relationships between the position, speed and acceleration of bodies.

        v = v₀ + a t

        y = v₀ t + ½ a t²

where v and v₀ is the current and initial velocity, respectively, a is the acceleration and t is time.

In many circumstances graphs are made for their analysis, in a graph of speed versus time when we have a horizontal line the speed is constant, the acceleration is zero and in the case of a slope there is an acceleration, we have two cases:

Let's answer the different questions about the system.

a) in the attached we have a graph of the velocity versus time, each section corresponds to a change in the slope of the graph, we have four sections;

b) The acceleration is the first 8 s

          v = v₀ + a t

          [tex]a = \frac{v-v_o}{\Delta t}[/tex]  

          [tex]a = \frac{2-0}{8-0}[/tex]  

          a = 0.25 m / s²

c) The maximum acceleration is when the slope is maximum.

          [tex]a = \frac{6-2}{ 14-10}[/tex]  

          a = 1 m / s²

Therefore the acceleration is maximum in the section between 10 and 14 s

d) The total displacement is the sum of the displacements of each section.

         [tex]d_{total } = d_1 +d_2 + d_3 +d_4[/tex]  

We look for every displacement.

       d₁ = v₀ + ½ a₁ Δt²

       d₁ = 0 + ½ 0.25 8²

       d₁ = 8 m

In the second section the velocity is constant

         d₂ = v₂ Δt₂

         d₂ = 2 (10-8)

         d₂ = 4 m

The third section.

    d₃ = v₀ + ½ a t²

    d₃ = 2 + ½ 1 (14-10) ²

    d₃ = 10 m

The distance of the fourth section.

we look for acceleration

          a₄ = [tex]\frac{v-v_o}{\Delta t}[/tex]  

          a₄ = [tex]\frac{0-6}{18-14}[/tex]  

          a₄ = -1.5 m / s²

          d₄ = 6 + ½ (-1.5) (1814) ²

          d₄ = -6 m

The total displacement is;

          [tex]d_{total}[/tex] = 8 + 4 + 10 -6

          [tex]d_{total}[/tex] = 16 m

e) The maximum speed is the highest point in the graph of speed versus time that in the attachment we can see corresponds to

          v = 6 m / s

In conclusion using the characteristics of kinematics we can find the results for the questions about the motion of bodies are:

  a)  we have four sections;

b)  The acceleration is the first 8 s is:  a = 0.25 m / s²

c) The maximum acceleration is:    a = 1 m / s²

d) The displacement   is:  i) d₁ =  8m,     ii)  [tex]d_{total}[/tex]= 16 m

e) maximum speed  is:      v = 6 m / s

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Answer:1590 N

Explanation:

Impulse =  change in momentum/time

change in momentum = 0 - 50 x 35 = -1750

-1750/1.1 = 1590 (3s.f.) N

Answer:

I think you ask for another way of writing the joule (J). It can be expressed as the product between a force applied to a body and the deployment of the body (not necessarily caused by that force applied), so N*m (newton * meter).

The quantity work—which has units of energy—was defined, another unit for energy, equivalent to the joule (j), is Newton ·meter (N· m).

The quantity with a constant magnitude that is used to measure the magnitudes of other quantities of the same type is referred to as a unit in physics.

Unit of work is that of energy, that is, Joule (J).

Again, work = force × displacement

Unit of work = Unit of force × Unit of displacement = Newton . meter (N.m).

Hence, the quantity work—which has units of energy—was defined, another unit for energy, equivalent to the joule (j), is Newton ·meter (N· m).

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Explanation:

hope this may help you

have a nice day

Answer:

Explanation:

The acceleration of an object given only it's mass and the force acting on it can be found by using the formula

[tex]a = \frac{f}{m} \\ [/tex]

f is the force

m is the mass in kg

From the question

m = 2400 kg

f = 740 N

We have

[tex]a = \frac{740}{2400} = \frac{74}{240} \\ = 0.308333...[/tex]

We have the final answer as

Hope this helps you

Answer:

Image result for what does and does not impact magnetic force?

The magnitude of the magnetic force between them depends on how much charge is in how much motion in each of the two objects and how far apart they are. The direction of the force depends on the relative directions of motion of the charge in each case

Explanation:

The factors that affect magnetic force are magnitude of the charge, speed, magnetic field and inclination of the field.

The magnetic force on a charged particle moving in a magnetic field is determined using the following formula;

F = qvBsin(θ)

where;

Thus, the factors that affect magnetic force are magnitude of the charge, speed, magnetic field and inclination of the field.

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Answer:

The reaction force is the water pushing the swimmer in the rightward direction.

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So, your science teacher has given your class the classic "mousetrap car" assignment: to make, design, and build a small vehicle powered by the snapping action of a mousetrap to make your car travel as far as possible. If you want to come out ahead of all the other students in your class, you'll need to make your car as efficient as possible so you can squeeze every last inch out of your "car". With the right approach, it's possible to streamline your car's design for maximum distance using only common home materials. You could also buy a mousetrap car kit from any craft store and skip wondering if it will work.

Use large rear wheels. Large wheels have greater rotational inertia than small wheels. In practice, this means that once they start rolling, they're harder to stop rolling. This makes large wheels perfect for distance-based contests — theoretically, they'll accelerate less quickly than smaller wheels, but they'll roll much longer and they'll travel a greater distance overall. So, for maximum distance, make the wheels on the drive axle (the one the mousetrap is tied to, which is usually the rear one) very large. The front wheel is a little less important — it can be large or small. For a classic drag racer look, you'll want big wheels in the back and smaller ones in front.

Use thin, light wheels. Thinner wheels have less friction and may go farther if the distance is what you want or need with your mousetrap racer. It's also important to take the weight of the wheels themselves into account — any unneeded weight will ultimately slow your car down or lead to added friction. In addition, it's worth noting that wide wheels can even have a small negative effect on the car's drag due to air resistance. For these reasons, you'll want to use the thinnest, lightest wheels available for your car.

Old CDs or DVDs work fairly well for this purpose — they're large, thin, and extremely light. In this case, a plumbing washer may be used to reduce the hole size in the middle of the CD (to fit the axle better).

If you have access to old vinyl, these also work extremely well, though they may be too heavy for the smallest mousetraps.

Use a narrow rear axle. Assuming your car is a rear-wheel-drive car, each time your rear axle turns, the rear wheels turn. If your rear axle is extremely skinny, your mousetrap car will be able to turn it more times for the same length of string than it would if it were wider. This translates to turning your rear wheels more times, meaning greater distance! For this reason, it's a wise idea to make your axle out of the skinniest material available that can still support the weight of the frame and wheels.

Narrow wooden dowel rods are a great, easily-accessible choice here. If you have access to thin metal rods, these are even better — when lubricated, they usually have less friction.

Create traction by giving the edges of the friction of the wheels. If the wheels slip against the ground when the trap is sprung, energy is wasted — the mousetrap works to make the wheels turn, but you don't get any extra distance. If this happens with your car, adding a friction-inducing material to the rear wheels may reduce their slippage. To keep your weight requirements down, use only as much as is necessary to give the tips of the wheels some grip and no extra. Some suitable materials are:[1]

Electrical tape

Rubber bands

Additionally, placing a piece of sandpaper under the rear wheels at the start line can reduce slippage as the car begins to move (when it is most likely)

Answer:

D

Explanation:

A is wrong as the direction of the car changes, implying velocity is changing and not constant.

B and C are wrong as both the change in speed and direction contribute to the change in velocity

Answer:

54

Explanation:4

4

4

Answer:

30d

Explanation:

30d