4
920
26°
?
74°
find the missing angle.

Answer: Power of a quotient

Step-by-step explanation:

The power of quotient basically is:

[tex](\frac{P}{q})^{3} =\frac{P^3}{q^3}[/tex]

Answer:

let inverse f(x) be m:

[tex]m = \frac{1}{2x + 1} \\ 2x + 1 = \frac{1}{m} \\ 2x = \frac{1 - m}{m} \\ x = \frac{1 - m}{2m} [/tex]

substitute x in place of m:

[tex]{ \bf{ {f}^{ - 1}(x) = \frac{1 - x}{2x } }}[/tex]

Answer:

The probability that the mean life expectancy of the sample is less than X years is the p-value of [tex]Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex], in which [tex]\mu[/tex] is the mean life expectancy, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

We have:

Mean [tex]\mu[/tex], standard deviation [tex]\sigma[/tex].

Sample of size n:

This means that the z-score is now, by the Central Limit Theorem:

[tex]Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

Find the probability that the mean life expectancy will be less than years.

The probability that the mean life expectancy of the sample is less than X years is the p-value of [tex]Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex], in which [tex]\mu[/tex] is the mean life expectancy, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.

Answer:

120Pi units squared

Step-by-step explanation:

π*12²*(360-60)/360

= π*144*300/360

= π*144*5/6

= π*720/6

= π*120

= 120π or 120Pi units squared

Answer:

120Pi units squared

Step-by-step explanation:

on edge

Answer:

Step-by-step explanation:

Given;

first leg of the right triangle, a = 15.21 cm

second leg of the right triangle, b = 17.34 cm

Angle C = 90 ⁰

The missing parameters;

Use Pythagoras theorem to calculate the missing side "c", which is the hypotenuse

c² = a² + b²

c² = (15.21)²  +  (17.34)²

c² = 532.02

c = √532.02

c = 23.1 cm

The missing angle A is calculated as;

[tex]tan(A) = \frac{a}{b} \\\\tan(A) = \frac{15.21}{17.34} \\\\tan(A) = 0.8772 \\\\A = tan^{-1} (0.8772)\\\\A = 41.26^0[/tex]

The missing angle is calculated as;

B = 90⁰ - A

B = 90⁰ - 41.26⁰

B = 48.74⁰

Answer:

3, 6, 11, 18, 27

Step-by-step explanation:

hope it helps

Answer:

15.9

Step-by-step explanation:

The distance between -10.2 and 5.7 is 15.9 after plotting the points on a number line.

It is defined as the representation of the numbers on a straight line that goes infinitely on both sides.

It is given that:

Two numbers on a number line:

-10.2 and 5.7

As we know, a number is a mathematical entity that can be used to count, measure, or name things. For example, 1, 2, 56, etc. are the numbers.

Indicating the above numbers on a number line:

= 5.7 -(-10.5)

The arithmetic operation can be defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has a basic four operators that is +, -, ×, and ÷.

= 5.7 + 10.5

= 15.9

Thus, the distance between -10.2 and 5.7 is 15.9 after plotting the points on a number line.

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(3.1) … … …

[tex]\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{2x-y}{x-2y}[/tex]

Multiply the right side by x/x :

[tex]\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{2-\dfrac yx}{1-\dfrac{2y}x}[/tex]

Substitute y(x) = x v(x), so that dy/dx = x dv/dx + v :

[tex]x\dfrac{\mathrm dv}{\mathrm dx} + v = \dfrac{2-v}{1-2v}[/tex]

This DE is now separable. With some simplification, you get

[tex]x\dfrac{\mathrm dv}{\mathrm dx} = \dfrac{2-2v+2v^2}{1-2v}[/tex]

[tex]\dfrac{1-2v}{2-2v+2v^2}\,\mathrm dv = \dfrac{\mathrm dx}x[/tex]

Now you're ready to integrate both sides (on the left, the denominator makes for a smooth substitution), which gives

[tex]-\dfrac12\ln\left|2v^2-2v+2\right| = \ln|x| + C[/tex]

Solve for v, then for y (or leave the solution in implicit form):

[tex]\ln\left|2v^2-2v+2\right| = -2\ln|x| + C[/tex]

[tex]\ln(2) + \ln\left|v^2-v+1\right| = \ln\left(\dfrac1{x^2}\right) + C[/tex]

[tex]\ln\left|v^2-v+1\right| = \ln\left(\dfrac1{x^2}\right) + C[/tex]

[tex]v^2-v+1 = e^{\ln\left(1/x^2\right)+C}[/tex]

[tex]v^2-v+1 = \dfrac C{x^2}[/tex]

[tex]\boxed{\left(\dfrac yx\right)^2 - \dfrac yx+1 = \dfrac C{x^2}}[/tex]

(3.2) … … …

[tex]y' + \dfrac yx = \dfrac{y^{-3/4}}{x^4}[/tex]

It may help to recognize this as a Bernoulli equation. Multiply both sides by [tex]y^{\frac34}[/tex] :

[tex]y^{3/4}y' + \dfrac{y^{7/4}}x = \dfrac1{x^4}[/tex]

Substitute [tex]z(x)=y(x)^{\frac74}[/tex], so that [tex]z' = \frac74 y^{3/4}y'[/tex]. Then you get a linear equation in z, which I write here in standard form:

[tex]\dfrac47 z' + \dfrac zx = \dfrac1{x^4} \implies z' + \dfrac7{4x}z=\dfrac7{4x^4}[/tex]

Multiply both sides by an integrating factor, [tex]x^{\frac74}[/tex], which gives

[tex]x^{7/4}z'+\dfrac74 x^{3/4}z = \dfrac74 x^{-9/4}[/tex]

and lets us condense the left side into the derivative of a product,

[tex]\left(x^{7/4}z\right)' = \dfrac74 x^{-9/4}[/tex]

Integrate both sides:

[tex]x^{7/4}z=\dfrac74\left(-\dfrac45\right) x^{-5/4}+C[/tex]

[tex]z=-\dfrac75 x^{-3} + Cx^{-7/4}[/tex]

Solve in terms of y :

[tex]y^{4/7}=-\dfrac7{5x^3} + \dfrac C{x^{7/4}}[/tex]

[tex]\boxed{y=\left(\dfrac C{x^{7/4}} - \dfrac7{5x^3}\right)^{7/4}}[/tex]

(3.3) … … …

[tex](\cos(x) - 2xy)\,\mathrm dx + \left(e^y-x^2\right)\,\mathrm dy = 0[/tex]

This DE is exact, since

[tex]\dfrac{\partial(-2xy)}{\partial y} = -2x[/tex]

[tex]\dfrac{\partial\left(e^y-x^2\right)}{\partial x} = -2x[/tex]

are the same. Then the general solution is a function f(x, y) = C, such that

[tex]\dfrac{\partial f}{\partial x}=\cos(x)-2xy[/tex]

[tex]\dfrac{\partial f}{\partial y} = e^y-x^2[/tex]

Integrating both sides of the first equation with respect to x gives

[tex]f(x,y) = \sin(x) - x^2y + g(y)[/tex]

Differentiating this result with respect to y then gives

[tex]-x^2 + \dfrac{\mathrm dg}{\mathrm dy} = e^y - x^2[/tex]

[tex]\implies\dfrac{\mathrm dg}{\mathrm dy} = e^y \implies g(y) = e^y + C[/tex]

Then the general solution is

[tex]\sin(x) - x^2y + e^y = C[/tex]

Given that y (1) = 4, we find

[tex]C = \sin(1) - 4 + e^4[/tex]

so that the particular solution is

[tex]\boxed{\sin(x) - x^2y + e^y = \sin(1) - 4 + e^4}[/tex]

Answer:

1/4

Step-by-step explanation:

The answer is 1/4.

1/2 is equivalent to 2/4.

2/4-1/4=1/4

Answer:

The graphs below have the same shape. What is the equation of the blue graph? A. G(x) = (x + 3)^3 B. G(x) = x^3 + 3 C. G(x) = x^3 - 3 D. G(x) = (x - 3)^3

The blue graph is a horizontal shift to the left by 3 units of F(x) = x³.

G(x) = (x + 3)³.

In mathematics, translation is the process of moving an object from one position to another without changing its shape, size, or orientation.

It involves sliding the object in a particular direction by a certain distance.

We have,

From the graph, the blue graph is G(x) = (x + 3)³.

The function f(x) = (x + 3)³ is a transformation of the function f(x) = x³.

Specifically, it is a horizontal shift to the left by 3 units.

To see why,

Let's consider the effect of replacing x with x + 3 in the original function f(x) = x³.

f(x + 3) = (x + 3)³

Notice that f(x + 3) is equal to f(x) translated horizontally to the left by 3 units.

For example, when x = 0, we have:

f(0) = 0³ = 0

f(0 + 3) = 3³ = 27

So the point (0, 0) on the graph of f(x) = x³ is transformed to the point

(-3, 27) on the graph of f(x) = (x + 3)³.

Similarly, we can see that every point on the graph of f(x) = x³ is shifted horizontally to the left by 3 units to obtain the graph of f(x) = (x + 3)³.

Therefore,

The blue graph is G(x) = (x + 3)³.

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Answer:

0.5015 = 50.15% probability that it came from manufacturer A.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Defective

Event B: From manufacturer A.

Probability a unit is defective:

2% of 43%(from manufacturer A)

1.5% of 57%(from manufacturer B). So

[tex]P(A) = 0.02*0.43 + 0.015*0.57 = 0.01715[/tex]

Probability a unit is defective and from manufacturer A:

2% of 43%. So

[tex]P(A \cap B) = 0.02*0.43 = 0.0086[/tex]

What is the probability that it came from manufacturer A?

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0086}{0.01715} = 0.5015[/tex]

0.5015 = 50.15% probability that it came from manufacturer A.

Answer:

The rule for the transformation is (x, y) (-x, -y).

The coordinates of L'are (-2,-2).

The coordinates of N'are (-1,-6).

Step-by-step explanation:

Given

[tex]L = (2,2)[/tex]

[tex]M = (4,4)[/tex]

[tex]N = (1,6)[/tex]

[tex]Ro=180[/tex]

Required

Select three options

The rule to this is:

[tex](x,y) \to (-x,-y)[/tex]

So, we have:

[tex]L = (2,2)[/tex]

[tex]L' =(-2,-2)[/tex]

[tex]M = (4,4)[/tex]

[tex]M =(-4,-4)[/tex]

[tex]N = (1,6)[/tex]

[tex]N' = (-1,-6)[/tex]

Answer:

-1.28 AND 2.61

Step-by-step explanation:

[tex]10= -4x+3x^2\\ 3x^2 -4x - 10 = 0\\\\[/tex]

use quadratic formula

x =  [tex]\frac{-b+\sqrt{b^{2} -4ac} }{2a}[/tex]   x =  [tex]\frac{-b-\sqrt{b^{2} -4ac} }{2a}[/tex]

Solution/X-Intercepts: -1.28 AND 2.61    

9514 1404 393

Answer:

  A. 5 should have been subtracted in step 4

Step-by-step explanation:

No question is stated, so there is no "answer."

__

If we assume the question is, "What error did Keith make?" then choice A properly describes it.

Step 4 should look like ...

  x -5 = 7y . . . . . . . 5 should be subtracted from both sides

and the final result should be ...

  g(x) = (x -5)/7

Step-by-step explanation

n^3-n.

Hope this will help you :) <3

Answer:

(-2,-1)

Step-by-step explanation:

let the number=x

its reciprocal=1/x

x+2(1/x)=-3

x+2/x=-3

x²+2=-3x

x²+3x+2=0

(x+2)(x+1)=0

x=-2,-1

Answer:

547 500

Step-by-step explanation:

Interest for 1 year:

0.01%×365=3.65 a year

3.65×10=36.5% for 10 years

36.5×1,500,000÷100=547 500

The interest paid after 10 years is 547 ,500 Baht.

Interest is the amount paid or earned when a loan is taken or an investment is done respectively.

It is given that

Principal = 1,500,000 Baht

Rate = 0.01 % per day

Time period = 10 years

Interest = ?

Interest = P *R *T/100

Interest = 1500000 * 0.01 *365* 10 / 100

Interest = 547,500 Baht

Therefore the interest paid after 10 years is 547 ,500 Baht.

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Answer:

Decison region :

Reject H0 : if χ² > 6.251

12.229

Step-by-step explanation:

Given :

Manufacturer A B C D

Unacceptable 29 17 9 22

Acceptable 171 183 191 178

Total 200 200 200 200

H0: There is no relationship between quality and manufacturer.

H1: There is a relationship.

Testing using the goodness of fit :

Chisquare = (observed - Expected)² / Expected

Expected Values:

19.25 19.25 19.25 19.25

180.75 180.75 180.75 180.75

Chi-Squared Values:

4.93831 0.262987 5.45779 0.392857

0.525934 0.0280083 0.581259 0.0418396

χ² = 4.93831 + 0.262987 + 5.45779 + 0.392857

+ 0.525934 + 0.0280083 + 0.581259 + 0.0418396 = 12.229

Degree of freedom, df = (4-1)(2-1) = 3*1= 3

The critical value,

χ² at 0.10, 3 = 6.251

Decison region :

Reject H0 : if χ² > 6.251

Reject H0 : 12.229 > 6.251

Answer:

[tex]P(Green\ and\ Green) = \frac{25}{144}[/tex]

Step-by-step explanation:

Given

[tex]Green=5[/tex]

[tex]Blue = 7[/tex]

Required

[tex]P(Green\ and\ Green)[/tex]

This is calculated as:

[tex]P(Green\ and\ Green) = P(Green) * P(Green)[/tex]

Since, it is a probability with replacement, we have:

[tex]P(Green\ and\ Green) = \frac{Green}{Total} * \frac{Green}{Total}[/tex]

So, we have:

[tex]P(Green\ and\ Green) = \frac{5}{12} * \frac{5}{12}[/tex]

[tex]P(Green\ and\ Green) = \frac{25}{144}[/tex]

Answer:

the answer is C

the y intercept is +3

if you do rise over run, the slope will be 1/2

Answer:

4yz^2

Step-by-step Explanation:

This question is incomplete, the complete question is;

United Airline flights from Newark to Seattle are typically booked to capacity. However, due to United’s current lenient rebooking policies, on average 17 customers (with a standard deviation of 10) cancel or are no shows for these flights. The average revenue collected on this flight is is $145/seat. However, if the flight is overbooked and the airline needs to rebook a ticketed passenger, United typically gives the customer a free round-trip ticket for a future flight. The cost of this free round-trip ticket averages $330. By how many seats should United overbook for this route?

Answer:

the number of seats that should be overbooked is approximately 12

Step-by-step explanation:

Given the data in the question;

average = 17 customers

standard deviation = 10

Cost of under booking the flight ( underage ); Cu = $145

Cost of overbooking the flight ( Overage ); Co = $330

we calculate the service level

service level = Cu / ( Cu + Co )

we substitute

Service level = 145 / ( 330 + 145 )

= 145 / 475

Service level = 0.3053

In excel, we use NORMSIV function to determine the z-value

z-value = NORMSIV ( 0.3053 )

z -value = -0.509

Now, the number of seats (Q) that should be overbooked will be;

Q = Average cancellations + Z-value × S.D

we substitute

Q = 17 + ( -0.509 × 10 )

Q = 17 + ( -5.09 )

Q = 17 - 5.09

Q = 11.91 ≈ 12

Therefore, the number of seats that should be overbooked is approximately 12

Answer:

9

Step-by-step explanation:

Let the number be X

From the problem we have the following equation:

7x - 17 = 3x + 19

-> 4x = 36

-> x = 9

Answer:

9

Step-by-step explanation:

that is the procedure above

The required solution for the given expression (c² - 4c + 7) - (7c² - 5c + 3) is -6c² + c + 4.

An algebraic expression is consists of variables, numbers with various mathematical operations,

The given expression is,

(c² - 4c + 7) - (7c² - 5c + 3)

Simplify the expression by solving bracket terms,

c² - 4c + 7 - 7c² + 5c - 3

Further, solve the expression by using mathematical operations,

-6c² + c + 4

The solution for the given expression is -6c² + c + 4.

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Answer:

There are 256 pairs in all.

Answer:

2

Step-by-step explanation:

Answer:

$2550

Step-by-step explanation:

Calculation to determine the amount of retained earnings at the beginning of Year 2

Using this formula

Beginning Retained Earnings + Revenue − Expenses − Dividends = Ending Retained Earnings

Let plug in the formula

Beginning Retained Earnings + $3,200 − $1,700 − $1,100 = $2950

Beginning Retained Earnings= $2,950-$400

Beginning Retained Earnings = $2,550

Therefore the amount of retained earnings at the beginning of Year 2 is $2550

Given :-

To Find :-

Answer :-

Taking the given expression,

→ 4x² - 8x + 4

→ 4x² - 4x -4x + 4

→ 4x ( x - 1 ) -4( x -1)

→ (4x - 4)(x-1)

Hence the required answer is (4x - 4)( x - 1) .