4. Water stands 12.0 m deep in a storage tank whose top is open to the atmosphere at
1.00 atm. The density of water is given as 1000 kg/m² and some pressure conversion
are 1 Pa = 1 N/m² while 1 atm = 101 325 Pa.
a) What is the absolute pressure at the bottom of the tank?
b) What is the gauge pressure at the bottom of the tank?
[4]
[4]​

Answers

Answer 1

Answer:

[tex]P=217600Pa[/tex]

Explanation:

From the question we are told that:

Density [tex]\rho=1000kg/m^3[/tex]

Depth of Water [tex]d=12.0m[/tex]

Generally the equation for Pressure is mathematically given by

 [tex]P=\rho gh[/tex]

 [tex]P=1000*9.8*12[/tex]

 [tex]P=117600N/m^2[/tex]

Therefore

Absolute Pressure=P+P'

Where

P=Pressure under water

P'=Atmospheric Pressure

Therefore

 [tex]P_A=P+P'[/tex]

 [tex]P_A=117,600+10^5[/tex]

 [tex]P=217600Pa[/tex]


Related Questions

Part C
When only one color of light reflects from a piece of paper, what happens to the other colors of light?
Remember that light is energy, and energy cannot be created or destroyed.
В І ох
х
Font Sizes
A
EEEE
I
Characters used: 0 / 15000
Plz help me yall I’m struggling

Answers

Answer:

the other colours get absorbed by the paper

Answer:

The other colors are absorbed by the paper and not reflected.

A peach pie in a 9.00 in diameter plate is placed upon a rotating tray. Then, the tray is rotated such that the rim of the pie plate moves through a distance of 208 in. Express the angular distance that the pie plate has moved through in revolutions, radians, and degrees.

Answers

Answer:

a)  [tex]X_1=7.36rev[/tex]

b)  [tex]X_2=46.22radians[/tex]

c) [tex]X_3=2649.6^o[/tex]

Explanation:

From the question we are told that:

Diameter [tex]d=9.00[/tex]

Distance [tex]x=208[/tex]

Generally the equation for circumference of a circle is mathematically given by

[tex]C=2 \pi r\\\\C=2*\pi*4.5[/tex]

[tex]C=28.3[/tex]

Therefore

Angular distance that the pie plate has moved through in revolutions is

[tex]X_1=\frac{x}{C}[/tex]

[tex]X_1=\frac{208}{28.3}[/tex]

[tex]X_1=7.36rev[/tex]

Generally Angular distance that the pie plate has moved through in radians is

[tex]X_2= 7.36rev* 2 \pi[/tex]

[tex]X_2=46.22radians[/tex]

Generally Angular distance that the pie plate has moved through in degrees is

[tex]X_3=7.36rev* 360[/tex]

[tex]X_3=2649.6^o[/tex]

A 3-kg projectile is launched at an angle of 45o above the horizontal. The projectile explodes at the peak of its flight into two pieces. A 2-kg piece falls directly down and lands exactly 50 m from the launch point. Determine the horizontal distance from the launch point where the 1-kg piece lands.

Answers

1517.4 m

Step-by-step explanation:

Since the projectile broke up at the peak of its flight, it already traveled half its initial range so we can find its initial launch velocity [tex]v_0[/tex] from the equation

[tex]\frac{1}{2}R= \dfrac{1}{2} \left(\dfrac{v_0^2}{g}\sin 2\theta_0 \right)[/tex]

where [tex]\theta_0 = 45°[/tex] and [tex]\frac{1}{2}R = 50\:\text{m}[/tex] so we will get [tex]v_0=31.3\:\text{m/s}[/tex]. Next, we can use the equation

[tex]v_y = v_0y - gt = v_0 \sin 45 - gt[/tex]

and since [tex]v_y=0[/tex] at its peak, we get t = 22.1 s. Let's set this aside for a moment and we'll use it later.

At the top of its peak, we can use the conservation law of linear momentum. Let M be the mass if of the original projectile, [tex]m_1[/tex] be the mass of the larger fragment (2 kg) and [tex]m_2[/tex] be the mass of the smaller fragment (1 kg). We can write the conservation law as

[tex]Mv_0x = m_1V_1 + m_2V_2[/tex]

where [tex]V_1\:\text{and}\:V_2[/tex] are the velocities of the fragments immediately after the break up. But we also know that [tex]V_1=0[/tex] so the velocity of [tex]m_2[/tex] can be calculated from the conservation law as

[tex]Mv_0 \cos 45° = m_2V_2[/tex]

or

[tex]V_2 = \dfrac{M}{m_2}v_0 \cos 45° = 66.4\:\text{m/s}[/tex]

Now we can calculate the horizontal distance the smaller fragment traveled after the break up. Recall that the amount of time for it to go up is also the amount of time to get down so the horizontal distance x is

[tex]x = V_2 t = (66.4\:\text{m/s})(22.1\:\text{s})= 1467.4\:\text{m}[/tex]

Therefore, the total distance traveled from the launch point is

[tex]D = 50\:\text{m} + 1467.4\:\text{m}=1517.4\:\text{m}[/tex]

Kinematics equations tells us the position of an object under constant acceleration increases linearly with time.
A. True
B. False

Answers

Answer:

False.

Explanation:

Suppose that we have an object that moves with constant acceleration A.

Then the acceleration of the object is defined by the equation:

a(t) = A

The acceleration is the rate of change of the velocity, then the velocity equation is given by the integration of the acceleration equation, we will get:

v(t) = A*t + V₀

Where V₀ is the velocity of the object at the time t = 0s.

Now, if we integrate it again, we will get the position equation:

p(t) = (1/2)*A*t^2 + V₀*t + P₀

Where P₀ is the initial position equation.

Here, we can see that the position equation is a quadratic equation (not a linear equation), then the statement is false.

The only variable we found that affects the speed of a wave on a string was the tension of the string. How does this relate to how a musician tunes a stringed instrument?

Answers

Answer:

We know that in a string with two fixed points (like the one you will find in a guitar, where the string is "fixed" at the bridge and at the nut) the only thing that defines the speed (the frequency) at which the string vibrates is the tension (the length is also important, but for the 6 strings in the guitar all of them have the same length, but, as you know, when you press in a given fret the note changes, this happens because you are changing the length of the string, finally, the mass of the string is also important, but all the strings have almost the same mass, so we can ignore this).

Then for the open notes (the notes that you play when you don't fret any note) the only thing that defines the note that will sound is the tension of the string.

And a musician can tune the stringed instrument by changing the tension of each string using a tuner, which is the mechanism in the headstock of the instrument). As more tense is the string, higher will be the open note.

. If force (F), work (W) and velocity (v) are taken as fundamental quantities.
What is the dimensional formula of time (T)?

Answers

Answer:

∴ [T]=[WF−1V−1]

Hope this answer is right!!

Answer :

[T] = [W(F)^-1(V)^-1]

what is the main limitation of debye huckel theory​

Answers

Answer:

Explanation:

For very low values of the ionic strength the value of the denominator in the expression above becomes nearly equal to one. In this situation the mean activity coefficient is proportional to the square root of the ionic strength. This is known as the Debye–Hückel limiting law.

Question 9 of 10
What causes the different seasons on Earth?
A. The angles at which the suns rays strike the Earth
Ο Ο Ο
B. The distance between Earth and the sun
C. The speed at which the Earth rotates on its axis
O
D. Increasing levels of carbon dioxide in the atmosphere.
SUBMIT

Answers

Answer:

B

Explanation:

The seasons are measured in how far or close the earth is to the sun.

Which of the following statements is false?

Weight is a vector quantity

Weight is measured in newtons. N

The weight of an object is the same on the Earth and the moon​

Answers

Answer:

the weight of an object is the same on earth and moon

Explanation:

bcoz weight depends on both mass and gravity

since the gravity of earth and moon is different then the weight is also different

mass doesn't change not weight

Define universal gravitational constant.​

Answers

The gravitational constant, denoted by the letter G, is an empirical physical constant involved in the calculation of gravitational effects in Sir Isaac Newton's law of universal gravitation and in Albert Einstein's general theory of relativity.
universal gravitational constant is needed in calculating the universal gravitational force between two objects.

What is the efficiency of a ramp that is 5.5 m long when used to move a 66 kg object to a height of 110 cm when the object is pushed by a 150 N force .






Answer and I will give you brainiliest

Answers

Explanation:

Energy input = F×d = (150 N)(5.5 m) = 825 J

Energy output = mgh = (66 kg)(9.8 m/s^2)(1.10 m) = 711 J

efficiency = [tex]\dfrac{\text{output}}{\text{input}}[/tex]×100% = 86.2%

The unit of distance used in astronomy is the light year, defined as the distance travelled by light in one calender year. How far away from earth (in km) is a star if its distance is quoted as 10 light years?

Answers

Answer:

9.7 trillion kilometers

Explanation:

The answer is 9.7 Trillion km

Một học sinh làm thí nghiệm sóng dừng trên dây cao su dài L với hai đầu A và B cố định . Xét điểm M trên dây sao cho khi sợi dây duỗi thẳng thì M cách B một khoảng a < L/2 . Khi tần số sóng là f = f1 = 60 Hz thì trên dây có sóng dừng và lúc này M là một điểm bụng . Tiếp tục tăng dần tần số thì lần tiếp theo có sóng dừng ứng với f = f2=72 Hz và lúc này M không phải là điểm bụng cũng không phải điểm nút . Thay đổi tần số trong phạm vi từ 73 Hz đến 180 Hz , người ta nhận thấy với f = fo thì trên dây có sóng dừng và lúc này M là điểm nút . Lúc đó , tính từ B ( không tính nút tại B ) thì M có thể là nút thứ ?

Answers

Have suxhebeuxhsbendixbebendue bride. Did e did e end Rudd. R

How does the density of water change when: (a) it is heated from 0o
C to
4o
C; (b) it is heated from 4o
C to 10o
C ?

Answers

Answer:

[b] it id heated from 4o

Explanation:

Which method of powering a vehiclewill help to reduce air pollution
using oil
using biofuels
using gasoline
using diesel fuel

Answers

Answer:

Using biofuels

Explanation:

The emissions of NOx and total VOCs lead to the formation of ozone in the troposphere, the main component of smog. ... Biofuels has a number of health and environmental benefits including improvement in air quality by reducing pollutant gas emissions relative to fossil fuels

state what is meant by graviration potential at a point in an orbit 6.5×10^7

Answers

Explanation:

The gravitational potential at a point in a gravitational field is the work done per unit mass that would have to be done by some externally applied force to bring a massive object to that point from some defined position of zero potential,

the minimum charge on any object cannot be less than​

Answers

Answer:

1.6 x 10^{-19} Coulombs

Explanation:

In Physics, the standard unit of measurement of a charge is Coulombs and it's denoted by C. Also, the symbol for denoting a charge is Q.

In Chemistry, electrons can be defined as subatomic particles that are negatively charged and as such has a magnitude of -1.

The minimum charge on any object such as an electron cannot be less than​ 1.6 x 10^{-19} Coulombs and it's usually referred to as the fundamental unit of charge.

A meter stick has a mass of 0.30 kg and balances at its center. When a small chain is suspended from one end, the balance point moves 28.0 cm toward the end with the chain. Determine the mass of the chain.

Answers

Answer:

M L1 = m L2       torques must be zero around the fulcrum

M = m L2 / L1 = .3 kg * 28 cm / 22 cm = .382 kg

A ball is thrown into the air with a velocity of 39 ft/s. Its height, in feet, after t seconds is given by s(t) = 39t − 16t2. Find the velocity (in ft/s) of the ball at time t = 1 second.

Answers

Answer:

7 ft/s

Explanation:

Applying,

V(t) = ds(t)/dt

Where V(t) = velocity of the ball at a given time

From the question,

Given: s(t) = 39t-16t²

Therefore,

V(t) = ds(t)/dt = 39-32t............. Equation 1

at t = 1 seconds,

Substitute the value of t into  equation 1

V(t) = 39-32(1)

V(t) = 39-32

V(t) = 7 ft/s

Một vật chuyển động tròn đều có chu kì T = 0,25 s. Tính tần số chuyển động f của vật?

Answers

Answer:8pi

Explanat:Omega =2pi/T

In an experiment to measure the value of pi, the following results are obtained for pi:
3.14 3.11 3.20 3.06 3.08
a) Calculate the Mean Value.
b) Calculate the Average Deviation from the Mean
c) Calculate the: True Standard Deviation
d) Calculate the: Standard Deviation of the Mean.
e) If the correct value is 3.14159, calculate the: Percent Error

Answers

Answer:

a)[tex]MV=3.118[/tex]      

b)[tex]AD=0.0416[/tex]  

c)[tex]TSD=0.00302[/tex]  

d)[tex]SD=0.00242[/tex]  

e)[tex]%E=0.75%[/tex][tex]PE=0.75\%[/tex]

Explanation:

a)

The mean value equation is:

[tex]MV=\frac{\Sum x}{n}[/tex]

Where:

x represents the values of pin is the number of pi values

[tex]MV=\frac{3.14+3.11+3.20+3.06+3.08}{5}[/tex]

[tex]MV=3.118[/tex]      

b)

The average deviation equations is:

[tex]AD=\frac{\Sum |x-MV|}{n}[/tex]    

[tex]AD=\frac{0.208}{5}[/tex]  

[tex]AD=0.0416[/tex]  

c)  

The true Standard Deviation equation is:

[tex]TSD=\sqrt{\frac{\Sum (x-MV)^{2}}{n-1}}[/tex]    

[tex]TSD=\sqrt{\frac{0.01208}{5-1}}[/tex]      

[tex]TSD=0.00302[/tex]    

d)

The  Standard Deviation equation is:

[tex]TSD=\sqrt{\frac{\Sum (x-MV)^{2}}{n}}[/tex]    

[tex]TSD=\sqrt{\frac{0.01208}{5}}[/tex]      

[tex]SD=0.00242[/tex]    

e)

The percent error equation is:

[tex]%E=\frac{|Measured value - True value|}{|True value|}[/tex][tex]PE=\frac{|Measured value - True value|}{True value}[/tex]

[tex]%E=\frac{|Measured value - True value|}{|True value|}[/tex][tex]PE=\frac{|3.118-3.14159|}{3.14159}*100[/tex]

[tex]%E=\frac{|Measured value - True value|}{|True value|}[/tex][tex]PE=0.75\%[/tex]

[tex]%E=0.75%[/tex]

I hope it helps you!

         

If distance between two charges increased by 2 times then force

Answers

Explanation:

The size of the force varies inversely as the square of the distance between the two charges. Therefore, if the distance between the two charges is doubled, the attraction or repulsion becomes weaker, decreasing to one-fourth of the original value.

(a) From an atomic point of view, why do you have to heat a solid to melt it? (b) If you have a solid and a liquid at room temperature, what conclusion can you draw about the relative strengths of their inter-atomic forces?

Answers

Answer:

A. & B. Heat energy is needed to convert solid into a liquid because heat energy increases the kinetic energy of the particles. The heat energy that it used to change 1 kg of solid into liquid at atmospheric pressure and at its melting point is called the latent heat of fusion.

Atoms of which two elements could combine with atoms of chromium (Cr) to
form ionic bonds?
O A. F.
B. Au
C. Se
D. Ti
E. Mg

Answers

Answer:

D and E

Ionic bonds are formed between metals and non-metals and both of those are metals

Newton's Second Law of Motion
14. Why was it necessary to transfer mass from the cart to the hanger rather than just
simply adding mass to the hanger?

Answers

Answer:

The weight of the hanging mass provides tension in the string, which helps to accelerate the cart along the track. A small frictional force will resist this motion. 

I was reading an old thermodynamics textbook and came across this equation describing change in internal energy. What does the (dU/dT)V and (dU/dV)T mean? I think it’s partial derivatives, but I’ve never seen a derivative sub (something). Please help

Answers

Explanation:

I remember that notation! The expression

[tex]dQ = dU = (\dfrac{\partial U}{\partial T})_{V} dT+ (\dfrac{\partial U}{\partial V})_{T}dV[/tex]

is the 1st law of thermodynamics and it refers to the heat supplied to the system dQ which is also a change in its internal energy dU. The first term is the partial derivative of the internal energy U with respect to temperature T while the volume V is kept constant, as denoted by the subscript V. The 2nd term is similar but this time, temperature is kept constant while its volume partial derivative is being taken.

Ah, memories!

An airplane flies between two points on the ground that are 500 km apart. The destination is directly north of the point of origin of the flight. The plane flies with an airspeed of 120 m/s. If a constant wind blows at 10 m/s toward the west during the flight, what direction must the plane fly relative to the air to arrive at the destination

Answers

Answer:

The right solution is "4.8° east of north".

Explanation:

Given:

Distance,

= 500 km

Speed,

[tex]\vec{v}=120 \ m/s[/tex]

Wind (towards west),

[tex]v_0=10 \ m/s[/tex]

According to the question, we get

The angle will be:

⇒ [tex]\Theta=Cos^{-1}(\frac{v_0}{v_1} )[/tex]

       [tex]=Cos^{-1}(\frac{10}{120} )[/tex]

       [tex]=85.21[/tex] (north of east)

hence,

The direction must be:

⇒ [tex]\Theta'=90-85.21[/tex]

        [tex]=4.79^{\circ}[/tex]

or,

        [tex]=4.8^{\circ}[/tex] (east of north)

If the car falls down the side of the cliff, what is happening to the gravitational potential energy of the falling car? (Assume the bottom of the cliff is zero)

Answers

Answer:

Sentences with many clauses and phrases are difficult to understand because the clauses and phrases typically _____.

modify other clauses and phrases in the sentence

refer to other sentences in the passage

make it hard to determine where the sentence ends

change the intended meaning of the sentence

Explanation:

Rank the six combinations of electric charges on the basis of the electric force acting on q1.

a.
q1 = -1nC
q2= +1nC
q3= +1nC

b.
q1 = -1nC
q2= -1nC
q3= -1nC

c.
q1 = +1nC
q2= +1nC
q3= -1nC

d.
q1 = +1nC
q2= -1nC
q3= +1nC

Answers

The anwser for this question would be D. Q1 = +1nC , Rank the six combinations of the electric charges on the basis of the electric force acting on q1.

THE ANSWER!!! Please

Answers

Answer:

I think -7 N. Netforce is 3N-10N= -7N

Explanation:

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