4. In the quadratic function y = 232 + ba + c, the
affects the width of the parabola.

Answer:

4.

Step-by-step explanation:

A line AB is perpendicular to the line CD.

As shown in the diagram, there are four angles which measures 90°.

Answer:

[tex]2x + 6 = 4x + -2[/tex]

[tex]\Longrightarrow2x+6-6=4x-2-6[/tex]

[tex]\Longrightarrow 2x=4x-8[/tex]

[tex]\Longrightarrow 2x-4x=4x-8-4x[/tex]

[tex]\Longrightarrow -2x=-8[/tex]

[tex]\Longrightarrow \frac{-2x}{-2}=\frac{-8}{-2}[/tex]

[tex]\hookrightarrow \underline{ANSWER: x=4}[/tex]

-------------------------

hope it helps...

have a great day!!

Step-by-step explanation:

In between 2000 and 90000

Don't use a 2

Answer:

no it is not perpedicular

Step-by-step explanation:

I plugged the equation into a graphing calculator and the line does not appear to be perpendicular

Answer:

3y = 5x+4

3y=9x

yx=9/3

yx=3

Answer:

2\sqrt2

Step-by-step explanation:

a=5-2√6 ...(1)

[tex]\frac{1}{a}=\frac{1}{5-2 \sqrt{6} } \times\frac{5+2\sqrt{6} }{5+2\sqrt{6} } =\frac{5+2\sqrt{6}}{(5-2\sqrt{6})(5+2\sqrt{6})} =\frac{5+2\sqrt{6}}{5 ^2-(2\sqrt{6})^2} =\frac{5+2\sqrt{6}}{25-24} =5+2\sqrt{6}\\a+\frac{1}{a}=5-2\sqrt{6}+5+2\sqrt{6}=10[/tex]

[tex](\sqrt{a}-\frac{1}{\sqrt{a}})^2=(\sqrt{a})^2+(\frac{1}{\sqrt{a}})^2-2 \times \sqrt{a} \times \frac{1}{\sqrt{a}}=a+\frac{1}{a}-2=10-2=8\\\sqrt{a}-\frac{1}{\sqrt{a}}=\sqrt{8}=2\sqrt{2}[/tex]

Answer:

Yes, the triangles are similar by SAS

Step-by-step explanation:

Looking at the picture, we see that there are two triangles with side lengths of different sides. We can deduce that the scale factor is 1 2/3, because 8 divided by 4.8 is 1 2/3, and 10 divided by 6 is the same. Now that we have clarified that the triangles share the same scale factor, we notice that the angle is also the same, as mentioned in the picture. This leads us to say that the triangles are similar by the SAS similarity theorem (Side, Angle, Side). I hope this helped and please don't hesitate to reach out with more questions!

Answer:

x = 14

Step-by-step explanation:

Since the terns form an arithmetic progression then they have a common difference d , that is

a₂ - a₁ = a₃ - a₂

x - 8 = 20 - x ( add x to both sides )

2x - 8 = 20 ( add 8 to both sides )

2x = 28 ( divide both sides by 2 )

x = 14

Answer: here is a picture of all of them I hope this helps :). This picture will clearly show the answers for 1 and 2

Step-by-step explanation:

Answer:

it must be 21

Step-by-step explanation:

I have very fast I think giving test just thank the answer after test mark me brainliest

Answer:

PLZZ MARK ME BRAINLIEST..!

Step-by-step explanation:

Bridgets fish: f , 2f, 3f+2 , 1/2f, 3/5f

Add for total weight: 7 1/10 f +2

Dads fish: 3f+2, 4/5f, 2f+4, 1/2f

Add for total weight:  6 3/10f +6

set the 2 total weights equal:

6 3/10f +6 = 7 1/10f +2

Subtract 6 3/10f from each side:

6 = 8/10f  + 2

Subtract 2 from each side:

4 = 8/10f

Divide both sides by 8/10:

f =  5

Bridget's first fish weighed 5 ounces.

Dads first fish weighed:  2 more than 3 times :3(5) + 2 = 15 +2 = 17 ounces.

Answer:

Step-by-step explanation:

x - y = 30

Substitute 15 for y.

x - (15) = 30

Add 15 to both sides.

x = 45

Answer:

[tex]\frac{28}{9}[/tex]

Step-by-step explanation:

[tex]\frac{-3}{11} +\frac{5}{9}[/tex]

[tex]=\frac{-27}{99} +\frac{55}{99}[/tex]

[tex]=\frac{-27+55}{99}[/tex]

[tex]=\frac{28}{99}[/tex]

Answer:

Original position: base is 1.5 meters away from the wall and the vertical distance from the top end to the ground let it be y and length of the ladder be L.

Step-by-step explanation:

By pythagorean theorem, L^2=y^2+(1.5)^2=y^2+2.25 Eq1.

Final position: base is 2 meters away, and the vertical distance from top end to the ground is y - 0.25 because it falls down the wall 0.25 meters and length of the ladder is also L.

By pythagorean theorem, L^2=(y -0.25)^2+(2)^2=y^2–0.5y+ 0.0625+4=y^2–0.5y+4.0625 Eq 2.

Equating both Eq 1 and Eq 2: y^2+2.25=y^2–0.5y+4.0625

y^2-y^2+0.5y+2.25–4.0625=0

0.5y- 1.8125=0

0.5y=1.8125

y=1.8125/0.5= 3.625

Using Eq 1: L^2=(3.625)^2+2.25=15.390625, L=(15.390625)^1/2= 3.92 meters length of ladder

Using Eq 2: L^2=(3.625)^2–0.5(3.625)+4.0625

L^2=13.140625–0.90625+4.0615=15.390625

L= (15.390625)^1/2= 3.92 meters length of ladder

hope it helps...

correct me if I'm wrong...

The ordered pairs of the transformation are A'(1,2), B'(1,-2), C'(-2,2) of the coordinates of the triangle ABC are A(2,3),B(2,-1),C(-1,-1).

What is meant by coordinates?

They are the points which together when jointed form a triangle.

How to do transformation of a triangle?

The transformation of triangle whose coordinates are as A(2,3), B(2,-1), C(-1,-1) is done as follows:

A'=(2-1,3-1)=(1,2)

B'=(2-1,-1-1)=(1,-2)

C'=(-1-1,-1-1)=(-2,-2)

Hence the ordered pairs are (1,2)(1,-2)(-2,-2).

Learn more about transformation of a triangle at https://brainly.com/question/4289712

#SPJ2

Answer:

[tex]12x^3+2x[/tex]

Step-by-step explanation:

The perimeter of a polygon is equal to the sum of its sides.

The sides in the triangle shown have lengths [tex]2x^3+6x[/tex], [tex]4x^3-5x[/tex], and [tex]6x^3+x[/tex] in no specific order.

Since its perimeter is given by the sum of its sides, the perimeter is equal to:

[tex]2x^3+6x+4x^3-5x+6x^3+x[/tex]

Combine like terms:

[tex]\boxed{12x^3+2x}[/tex]

Answer:

gradient = slope = [tex]\frac{y_{2} -y_{1} }{x_{2} -x_{1} }[/tex] = [tex]\frac{rise}{run}[/tex]

Slope intercept Form equation : y = mx + b

m = slope or gradient

b = y - intercept ( where the line crosses the y = axis)

x and y = are place holders for a coordinate pair that makes the equation true

c) y = -6x + 8

The -6 is the m. It's the slope or gradient.

the + 8  is the b. It's the y- intercept.

d) y = 4

This is a horizontal line. It intercepts the y-axis at 4.

That means the 4 is the y-intercept.

There is no x. That means the slope is 0. The line rises 0 as it runs left to right.

e) y -4x= 0  

equation needs to be is standard form y = mx + b.

add 4x to both sides in order to isolate the y variable.

y = 4x + 0.

The slope or gradient is 4. The y - intercept is 0. The line crosses through the origin.

f) y -x = -8

Add x to both sides.

y = x - 8

There is one x.  That means the gradient is 1. The y-intercept is the -8

g) y + 3x = 7

Subtract 3x from both sides.

y = -3x + 7

-3 = gradient. 7 = y-intercept.

h) y + [tex]\frac{1}{2}[/tex]x = -4

Subtract [tex]\frac{1}{2}[/tex]x from each side.

y = -[tex]\frac{1}{2}[/tex]x - 4

One last thing. If you are presented with an equation without a y, the gradient is  'undefined'.

example : x = 4

This a vertical line passing through 4 on the x-axis. There is no 'b' because its not crossing the y-axis.

Why is it 'undefined' ?

As the line rises it, it does not 'run' left or right. [tex]\frac{rise}{0}[/tex] . Zero can never, ever be in the denominator. Denominators can't be zero. That is why we say it's 'undefined'.

Hope this helps.

Answer:

3/20 of a cup of sugar

Step-by-step explanation:

Find how much she sprinkled on the brownies by multiplying 3/4 by 1/5:

3/4 x 1/5

= 3/20

So, she sprinkled 3/20 of a cup of sugar on the brownies

Answer:

11.7…?

Step-by-step explanation:

Small triangle and other triangle are similar based on sas theorem (I think) so find scale factor — 2— then do Pythagorean theorem

Answer:

This isn't going to be a circle even if we choose k to be -5.

I think there has to be an error in the question.

Step-by-step explanation:

We want the coefficient of x^2 and y^2 to be the same so we will want to solve:

k-5=2k

Subtract k on both sides:

-5=k

You should verify it will give a circle.

(k – 5)x²+ 2ky²-5x + 6y – 3 = 0 with k=-5:

(-5– 5)x²+ 2*-5y²-5x + 6y – 3 = 0

-10x²+ -10y²-5x + 6y – 3 = 0

Add 3 on both sides:

-10x²+ -10y²-5x + 6y = 3

Divide both sides by -10:

x²+ y²+5/10x -6/10y = -3/10

Gather the x's together and gather the y's together:

x²+5/10x+y²-6/10y = -3/10

We will begin to take steps to complete square for each the x part and the y part.

For each v^2+kv, add (k/2)^2 with goal to write as (x+k/2)^2. Remember whatever you do to one side you must do to the other.

x²+5/10x+(5/[2×10])^2+y²-6/10y+(-6/[2×10])^2 = -3/10+(5/[2×10])^2+(-6/[2×10])^2

Since radius square is not positive we can stop here. The radius has to be a real number after all. If you aren't convinced you can continue to write in center-radius form.

(x+1/4)²+(y-3/10)² = -3/10+1/16+9/100

(x+1/4)²+(y-3/10)² = -3/10+1/16+9/100

(x+1/4)²+(y-3/10)² = -59/400

Answer:

y=2/3x-11/3

Step-by-step explanation:

line is parallel so the gradient will be the same ( m=2/3)

using the point (4,-1)

y=2/3x+c

-1=2/3*4+c

-1=8/3+c

c= -11/3

equation ---> y=2/3x-11/3

Answer:

Step-by-step explanation:

2 colours were taken

Answer:

Step-by-step explanation:

If each CD at store A costs $.70, then 20 of them will cost 20(.7) = $14.

If each CD at store B costs $.60, then 20 of them will cost 20(.6) = $12.

The correct statement is that The cost at Store A is $2.00 greater than at Store B.

Answer:

D : [tex]x^{2} +81=x^{2} +20x+100[/tex]

Step-by-step explanation:

We start with the original equation:

[tex]\sqrt{x^{2} +81} =x+10[/tex]

Squaring both sides to remove the square root we get:

[tex]x^{2} +81=(x+10)^{2}[/tex]

Expanding the right side:

[tex]x^{2} +81=(x+10)(x+10)[/tex]

Multiplying the right side out and combining like terms we get:

[tex]x^{2} +81=x^{2} +20x+100[/tex]

Answer:

We know that the expression that models the situation is:

45 - n

Where n is the amount that she lost.

We know that she lost $3 for each hour closed.

And the shop was 8 hours closed, so the total loss is:

8*$3 = $24

The profit is the difference between the revenue (we know that it is $45) and the loss (we know that it is $24)

Then the profit is:

$45 - $24 = $21

Answer:

A) The sequence is {-23, -15, -7, 1,...}

The common difference of the sequence above, d = 8

The first term, a = -23

The number of terms, n = 15

The recursive formula is, aₙ = aₙ₋₁ + d

Using the recursive method gives;

a₅ = a₍₅₋₁₎ + d

Where;

a₍₅₋₁₎ = 1

Therefore, a₅ = 1 + 8 = 9, a₆ = 9 + 8 = 17, a₇ = 17 + 8 = 25, a₈ = 25 + 8 = 33, a₉ = 33 + 8 = 41, a₁₀ = 41 + 8 = 49, a₁₁ = 49 + 8 = 57, a₁₂ = 57 + 8 = 65 a₁₃ = 65 + 8 = 73, a₁₄ = 73 + 8 = 81, a₁₅ = 81 + 8 = 89

The 15th term of the sequence, {-23, -15, -7, 1,...}, a₁₅ = 89

We check by using explicit formula to get, aₙ = a + (n - 1)·d

Therefore

a₁₅ = -23 + (15 - 1)×8 = 89

B) The given sequence is B) {5 5.25, 5.50, 5.75,...}

The common difference, d = 0.25

The first term, a = 5

The required number of terms, n = 15

Using the recursive method gives;

a₅ = a₍₅₋₁₎ + d

Where;

a₍₅₋₁₎ = a₄ = 5.75

Therefore, a₅ = 5.75 + 0.25 = 6

a₆ = 6 + 0.25 = 6.25, a₇ = 6.25 + 0.25 = 6.5, a₈ = 6.5 + 0.25 = 6.75, a₉ = 6.75 + 0.25 = 7, a₁₀ = 7 + 0.25 = 7.25, a₁₁ = 7.25 + 0.25 = 7.5, a₁₂ = 7.5 + 0.25 = 7.75, a₁₃ = 7.75 + 0.25 = 8, a₁₄ = 8 + 0.25 = 8.25, a₁₅ = 8.25 + 0.25 = 8.5

The 15th term, of the sequence, {5 5.25, 5.50, 5.75,...}, a₁₅ = 8.5

We check by explicit formula to get, aₙ = a + (n - 1)·d

Therefore

a₁₅ = 5 + (15 - 1)×0.25 = 8.5

Step-by-step explanation: