Physics High School

4. A bullet of mass 30 g is fired from a rifle of mass 5kg at a speed of 259m/s. 

a) What is the momentum of the rifle just after the bullet is fired? 

b) What is the recoil velocity of the rifle?​

Answers

Answer 1

Answer:

Rifle Momentum=7.77kg*m/s v'= 1.554 m/s

Explanation:

a) m1v1 + m2v2 = m1v1' + m2v2'

0+0 = 0.03*259 + P(rifle momentum)

solve for P

p= 7.77kg*m/s

b) 7.77= 5*v'

v'= 1.554 m/s

Answer 2

The momentum of the rifle just after the bullet is fired is 7.77 kg.m/s and the recoil velocity of the rifle at the time of firing is 1.554 m/s.

What is momentum?

Momentum of a particle is the product of the mass of the particle and its velocity. Momentum is a vector quantity. It has both the magnitude and direction of motion. According to the Newton's second law of motion, the rate of change of the momentum is equal to the force acting on the particle which is in motion.

Momentum can be calculated by the general formula

p = m.v

where, p = momentum of the particle,

m = mass of the particle,

v = velocity of the particle.

Rifle Momentum= mass × velocity

P = m × v'

a) m1v1 + m2v2 = m1v1' + m2v2'

0+0 = 0.03 × 259 + P(rifle momentum)

0 = 7.77 + P

P = 7.77kg.m/s

b) p = m × v

7.77= 5 × v'

v'= 1.554 m/s

Learn more about Momentum here:

https://brainly.com/question/24030570

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