3(q - 7) = 27

Solve for q

Answer:

37

Step-by-step explanation:

239-17=222

222/6=37

37

Answer:

the answer would be 3x+y-15

Answer:

slope: -1/2

y-int: 9/2

Step-by-step explanation:

rearrange 9-x=2y into slope-intercept form: y=mx+b (m being slope and b is y-intercept)

2y = -x + 9

divide both sides by 2 to isolate the y and get:

y = -x/2 + 9/2

m (slope) = -(1)/2

b (y-int) = 9/2

Answer:

32 is the values 21 is the integers

Step-by-step explanation:

that's may answer ty hope it's help

Answer:

12 is the GFC.

Step-by-step explanation:

24 - 8, 3, 4, 6, 2, 12, 1, 24

60 - 10, 6, 2, 30, 20, 3, 5, 12, 4, 15

The greatest common factor of 24 and 60 is 12

The greatest common factor (GCF) of a set of numbers is the largest factor that all the numbers share.

For us to find the greatest common factor we need to find the common factors between the numbers.

The factors of 24 = 1,2,3,4,6,8,12 and 24

The factors of 60 = 1,2,3,4,5,6,12,15,30 and 60.

The common factors are ;

1,2,3,4,6 and 12

And the greatest common factor is 12. because it is the highest factor.

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Answer:

The value of the car today is $13,000, but will lose 11% of it's value each

Option second [tex]\rm (w-2.5)(w+2.5)[/tex] and option fourth  [tex]\rm (-4v-9)(-4v+9)[/tex]  are the products that result in a difference in squares.

It is required to identify which products result in a difference in squares.

Polynomial is the combination of variables and constants in a systematic manner with "n" number of power in ascending or descending order.

We know that:

[tex]\rm (a^2-b^2)=(a+b)(a-b)[/tex]

In option first:

[tex]\rm = (5z+3)(-5z-3)\\\rm = -(5z+3)(5z+3)\\\rm = -(5z+ 3)^2[/tex]

Which is not the difference between squares.

In option second:

[tex]\rm=(w-2.5)(w+2.5)\\\rm =(w^2-2.5^2)[/tex]By using [tex]\rm (a^2-b^2)=(a+b)(a-b)[/tex]

It is the difference between squares.

Similarly, in option third:

[tex]\rm =(8g+1)(8g+1)\\\rm =(8g+1)^2[/tex]

It is not the difference between squares.

Similarly, in option forth:

[tex]\rm = (-4v-9)(-4v+9)\\\rm = (4v+9)(4v-9)\\\rm = (4v)^2-9^2[/tex]

It is the difference between squares.

Similarly, in option fifth:

[tex]\rm = (6y+7)(7y-6)\\\rm = 42y^2+13y-42[/tex]

It is not the difference between squares.

Similarly, in option sixth:

[tex]\rm =(p-5)(p-5)\\\rm =(p-5)^2[/tex]

It is also not the difference between squares.

Thus, option second and option fourth are correct.

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Answer:

A=44 B=68

Step-by-step explanation:

There are two congruent sides, therefore the corresponding angles are also congruent.

Answer:

a and b both are 56 degree

Step-by-step explanation:

this is due to it's isosceles triangle. So, we take (180-68):2

Complete question:

A project is graded on a scale of 1 to 5. If the random variable, X, is the project grade, what is the mean of the probability

distribution below?

Grade(X)_____ 1_____2_____3_____4_____5

Frequency____3 _____5____ 9 ____ 5 ____ 3

P(X) : _______ 0.1 ___0.2 ___0.4 ___ 0.2 __0.1

Answer:

3

Step-by-step explanation:

Given the probability distribution :

Grade(X)_____ 1_____2_____3_____4_____5

Frequency____3 _____5____ 9 ____ 5 ____ 3

P(X) : _______ 0.1 ___0.2 ___0.4 ___ 0.2 __0.1

The mean of the distribution :

Σ(X * P(X)) :

(1*0. 1) + (2 * 0.2) + (3 * 0.4) + (4 * 0.2) + (5 * 0.1)

0.1 + 0.4 + 1.2 + 0.8 + 0.5

= 3

Answer:

the mean is 3

answer choice D

Veremos que el area del banderín es 930cm^2, entonces la opción correcta es A.

Luego de una pequeña busqueda online, pude ver que el banderin es un triangulo isósceles con base de 31cm y altura de 60 cm.

Recordar que para un triangulo de base b y altura h, el area es:

A = b*h/2

Entonces el area del banderín va a ser:

A = (31cm)*(60cm)/2 = 930cm^2

Entonces la opción correcta es A.

Sí quieres aprender más sobre triangulos, puedes leer:

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Answer:

■○■•♤•♤♤•》•♤~♤~♤~♤~♤♤~♤•♤○♤~

Answer:

Follow the steps shown below.

Step-by-step explanation:

12cos(30)+2tan(60)

[tex]12*\frac{\sqrt{3} }{2} + 2\sqrt{3}[/tex]

[tex]6\sqrt{3} + 2\sqrt{3}[/tex]

[tex]8\sqrt{3}[/tex]

[tex]\sqrt{64*3}[/tex]

[tex]\sqrt{192}[/tex]

The quadratic polynomial 6x² – 7x + 2 has factors (3x – 2) and (2x – 1). Then the correct option is A.

It is the method to separate the polynomial into parts and the parts will be in multiplication. And the value of the polynomial at this point will be zero.

The quadratic polynomial is 6x² – 7x + 2.

On factorization, we have

6x² – 7x + 2

6x² – (4 + 3)x + 2

6x² – 4x – 3x + 2

2x(3x – 2) –1(3x – 2)

(3x – 2)(2x – 1)

The factor is (3x – 2).

More about the factorization link is given below.

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Answer:

Step-by-step explanation:

place a marker every mile along the race course. How

Answer:

Step-by-step explanation:

Yes

Answer:

B

Step-by-step explanation:

it's just option B because it is only root

Answer:

the answer would be B. (2.5, -0.5)

plug the possibilities in and solve. just because it works for one, it doesn't mean that it will work for both.

3 (2.5) - (-0.5) = 7.5 + 0.5 = 8

(2.5) + (-0.5) = 2.5 - 0.5 = 2

i hope i helped. :)

Step-by-step explanation:

Read more about system of equations at:

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Answer:

Step-by-step explanation:

2: 4/2 is 2

3: 4/3 is 1 1/3

4: 4/4 is 1

5: 4/5 is .8

x                                       y                                       y/x

2                                      2                                      4/2

3                               1 1/3 or 1.333...                        4/3

4                                      1                                        4/4

5                                 4/5 or 0.8                              4/5

Hope this Helped! :)

-SGO

Answer:

c/d = 5x/3

Step-by-step explanation:

Given :-

c/d - a/b = x

a = 2c

b = 5d

To Find :-

Value of c/d in terms of x

Solving :-

Substitute value of a and b.

c/d - 2c/5d = x

3c/5d = x

c/d = 5x/3

Solution :-

c/d = 5x/3

Answer:

1. 2c+9=m

Step-by-step explanation:

The probabilities for each case are:

There are 8 reservations for passengers that may go or not, such that the probability of arriving to the flight is P = 0.42, and the probability of not arriving is Q = 0.58

a) There will be overbooking if 7 or more passengers go to the flight, the probability that the 8 attend is:

P(8) = (0.42)^8

The probability that 7 attend is:

P(7) = 8*(0.42)^7*(0.58)

(where the factor 8 is because there are 8 permutations)

The total probability is:

P = P(8) + P(7) = 0.012

b) Will be empty seats if less than 6 people go.

The probability that exactly 6 of these people go to the flight is:

P(6) = (28)*(0.42)^6*(0.58)^2

Where there are 28 permutations, that is why we used that factor.

Then, the probability of having empty seats is:

P = 1 - P(6) - P(7) - P(8) = 0.937

If you want to learn more about probability, you can read:

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Answer:

2474

Step-by-step explanation:

(725 x 2) + (512 x 2)

(1450)+(1024)

=2474

Answer:

8×7×7 diameters should be accurate

Answer:

no

Step-by-step explanation:

17/8 = 2.125

1/2 = 0.5

Two ratios are proportional if they are equal.

17/8 and 1/2 are note equal, so they are not proportional.

Answer:

28.01

Step-by-step explanation:

Since x = 5.1

Substitute

5.1² + 2

=26.01+2

Add the numbers

=28.01

Hence, Answer = 28.01

~Learn with Lenvy~

Answer:

Given That:

[tex]{ \large\longrightarrow { \rm{z = {x}^{2} + {y}^{2} }}}[/tex]

Partial differentiating both sides with respect to x, we get:

[tex]{ \large\longrightarrow { \rm{ \frac{∂z}{∂x} = 2x}}}[/tex]

Partial differentiating again with respect to x, we get:

[tex]{ \large\longrightarrow {{ \rm{ \frac{ {∂}^{2}z }{∂ {x}^{2} } \: = 2 \: \: \: \: \quad -(i) }}}}[/tex]

Consider again:

[tex]{ \large\longrightarrow {{ \rm{ z = {x}^{2} + {y}^{2} }}}}[/tex]

Partial differentiating both sides with respect to y, we get:

[tex]{ \large\longrightarrow { { \rm{ \frac{∂z}{∂y} = 2y}}}}[/tex]

Now, partial differentiating both sides with respect to x, we get:

[tex]{ \large\longrightarrow{ \rm{ \frac{ {∂}^{2}z }{∂x \:∂y } = 0 \: \: \: \quad - (ii) }}}[/tex]

Consider again:

[tex]{ \large\longrightarrow { \rm{ \frac{∂z}{∂y} = 2y}}}[/tex]

Partial differentiating both sides with respect to y, we get:

[tex]{ \large\longrightarrow{ \rm{ \frac{ {∂}^{2}z }{∂ {y}^{2} } = 2 \: \: \: \: \: \quad - (iii) }}}[/tex]

Now, consider Left Hand Side, we get:

[tex]{ \large{ \rm{ \longrightarrow {x}^{2} \frac{ {∂}^{2}z }{∂ {x}^{2} } + 2xy \frac{ {∂}^{2} x}{∂x \:∂y } + {y}^{2} \frac{ {∂}^{2}z }{∂ {y}^{2} } }}}[/tex]

From Equation (i),(ii) and (iii), we can write:

[tex]\longrightarrow{ \large{ \rm{ {2x}^{2} + 0 + {2y}^{2} }}}[/tex]

[tex]\longrightarrow \: { \large{ \rm{2( {x}^{2} + {y}^{2} ) }}}[/tex]

[tex]\longrightarrow{ \large{ \rm{2z}}}[/tex]

Therefore,

[tex]{ \large{\longrightarrow \: { \rm{{x}^{2} \frac{ {∂}^{2} z}{∂ {x}^{2} } + 2xy \frac{ {∂}^{2}x }{∂x \:∂y } + {y}^{2} \frac{ {∂}^{2}z }{∂ {y}^{2} } = 2z }}}}[/tex]

Hence Proved!!

[tex] \: [/tex]

[tex]\boxed{\begin{array}{c|c}\bf f(x)&\bf\dfrac{d}{dx}f(x)\\ \\ \frac{\qquad\qquad}{}&\frac{\qquad\qquad}{}\\ \sf k&\sf0\\ \\ \sf sin(x)&\sf cos(x)\\ \\ \sf cos(x)&\sf-sin(x)\\ \\ \sf tan(x)&\sf{sec}^{2}(x)\\ \\ \sf cot(x)&\sf-{cosec}^{2}(x)\\ \\ \sf sec(x)&\sf sec(x)tan(x)\\ \\ \sf cosec(x)&\sf-cosec(x)cot(x)\\ \\ \sf\sqrt{x}&\sf\dfrac{1}{2\sqrt{x}}\\ \\ \sf log(x)&\sf\dfrac{1}{x}\\ \\ \sf{e}^{x}&\sf{e}^{x}\end{array}}[/tex]

Refer to the attachments for answer

==============================

Explanation:

For problem 1, we will plot a closed circle at x = -2 to include this value in the shaded solution set. We include it because of the "or equal to". The shading is to the right because of the "greater than". So we're describing all x values that are either equal to -2 or larger than -2. You could say "x is -2 or larger".

---------------------

In problem 2, we'll exclude the endpoint since we don't have "or equal to". We shade to the left to visually show all values smaller than 3.

---------------------

In problem 3, we follow the same idea as the last problem. We have an open hole to exclude the endpoint and shade to the right of 12 to describe all values larger than 12.

---------------------

With problem 4, we now include the endpoint again. This is similar to problem 1. We shade to the left to describe x values that are either -15 or smaller.

Answer:

a₇ = 797

Step-by-step explanation:

substitute n = 7 into the explicit formula

a₇ = 800 - 0.5(7 - 1) = 800 - 0.5(6) = 800 - 3 = 797

The total finance charge for a $4,250 loan at 13. 25% interest compounded monthly for 24 months is $670.54.

What is Compound Interest?

Interest on interest, or compound interest, is the adding of interest to the principal sum of a loan or deposit. It's the outcome of reinvesting interest rather than paying it out so that interest is received on the principal plus previously collected interest in the next quarter.

[tex]A = P(1 + \frac{r}{n})^{nt}[/tex]

A is the final amount, P is the Initial principal balance, r is the interest rate, n is the number of times interest is applied per time period, t is the number of time periods elapsed.

As it is given that the principal amount is $4,250 while the interest rate is 13.25% compounded monthly and the principal amount is taken for 24 months, therefore,

[tex]A = P(1 + \frac{r}{n})^{nt}\\\\A = 4,250(1 + \frac{0.1325}{12})^{24 \times 2}\\\\A = 5,531.54[/tex]

Now, the total amount that is needed to be paid is $5,531.54, while $4,250 was the principal amount therefore, the finance charge or the interest is,

Financial Charge = Final amount - Principal amount

Financial Charge = $5531.54 - $4861 = $670.54

Hence, the total finance charge for a $4,250 loan at 13. 25% interest compounded monthly for 24 months is $670.54.

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