The total kinetic energy of each wheel is; 45 J, and each wheel reaches a maximum height of approximately 2.3 meters.
The total kinetic energy of each wheel is the sum of the translational kinetic energy of the center of mass and the rotational kinetic energy due to the rolling motion. For each wheel, the translational kinetic energy is given by;
K_trans = (1/2)mv²
where m is mass of the wheel and v is linear speed of the center of mass, which is 6.0 m/s.
K_trans = (1/2)(2.0 kg)(6.0 m/s)² = 36 J
The rotational kinetic energy due to rolling motion is given by:
K_rot = (1/2)Iω²
where I is moment of inertia of the wheel and ω is angular velocity of the wheel, which is related to the linear speed by ω = v/R, where R is radius of the wheel.
For a solid disk rotating about its center, the moment of inertia is given by I = (1/2)mr², where r is radius of the disk.
K_rot = (1/2)(1/2)(2.0 kg)(0.5 m)²(6.0 m/s)/(0.5 m)²
= 9 J
Therefore, total kinetic energy of each wheel is;
K_total = K_trans + K_rot = 36 J + 9 J
= 45 J
When each wheel rolls or slides up the incline, its kinetic energy is gradually converted to potential energy due to the increase in height. At the maximum height reached, all the kinetic energy has been converted to potential energy.
The maximum height reached by each wheel can be found using the conservation of energy, which states that the total mechanical energy (kinetic energy + potential energy) of the wheel is constant, assuming no energy is lost to friction or other non-conservative forces.
At the maximum height, the kinetic energy is zero and the potential energy is equal to the initial kinetic energy;
mgh = K_total
where m is mass of the wheel, g is acceleration due to gravity, h is the maximum height reached, and K_total is the total kinetic energy of the wheel, which is 45 J.
Solving for h, we get;
h = K_total/(mg) = 45 J/(2.0 kg)(9.81 m/s²) ≈ 2.3 m
Therefore, each wheel reaches a maximum height of 2.3 meters.
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electric heater has a power of 50 watts calculate the time taken for the electric element to transfer 4750 joules of energy to the vegetable oil
Answer:
3000 seconds
Explanation:
Mark and Nancy both take three measurements of the length of a pencil that is 15.1 cm. Mark records 15.0, 15.0, and 15.1 cm. Nancy records 15.1, 15.2, and 15.2 cm. Which of the following statements is true about Mark and Nancy's measurements?
A. Mark's measurement is more precise.
B. Nancy's measurement is more accurate.
C. Mark's measurement is more accurate.
D. Both sets of measurements are equally accurate and precise.
The work done on an amount of charge in a circuit is calculated by the equation ∆W = Vab I∆t. How can this equation be converted to express the power P for the circuit?
A.multiply both sides of the equation by I
B.divide both sides of the equation by ∆t*
C.divide both sides of the equation by Vab
D.multiply both sides of the equation by ∆Q
To convert the equation [tex]∆_{W}[/tex]= [tex]V_{ab}[/tex] I[tex]∆_t[/tex] to express power P for the circuit, we need to divide both sides of the equation by [tex]∆_t[/tex]. Option B is correct.
The power P for the circuit can be expressed using the equation;
P = [tex]∆_{W}[/tex]/[tex]∆_t[/tex]
where [tex]∆_{W}[/tex] is work done on the charge and [tex]∆_t[/tex] is time interval for which the work is done.
Starting with the equation [tex]∆_{W}[/tex]= [tex]V_{ab}[/tex] I[tex]∆_t[/tex], we can rearrange it as follows:
[tex]∆_{W}[/tex]/[tex]∆_t[/tex] = [tex]V_{ab}[/tex] I
Now, substituting the expression for power P, we get;
P = [tex]V_{ab}[/tex] I
Therefore, to convert the equation [tex]∆_{W}[/tex] = [tex]V_{ab}[/tex] I[tex]∆_t[/tex] to express power P for the circuit, we need to divide both sides of the equation by [tex]∆_t[/tex], as in option B;
[tex]∆_{W}[/tex]/[tex]∆_t[/tex] = [tex]V_{ab}[/tex] I
P = [tex]∆_{W}[/tex]/[tex]∆_t[/tex]
P = [tex]V_{ab}[/tex] I/[tex]∆_t[/tex]
Dividing both sides by [tex]∆_t[/tex], we get:
P = [tex]V_{ab}[/tex]I
Hence, B. is the correct option.
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What is sin-1 (0.61)?
Answer:0.65606 -> 0.66
Explanation:
Press 2nd on your calculator then hit sin, this will give you the inverse of sin. enter 0.61 in the ( ) and then enter.
The power rating of a resistor is the maximum power it can safely dissipate without damage from overheating. A 15 kΩ resistor is connected across a 160 V potential difference. The power rating for the resistor must be at least _____.
A.0.011 W
B.8.3 W
C.1.7 W*
D.3.2 W
A cannon sits on top of a cliff that is 20 meters above an area of level ground. It fires a 5 kg cannonball horizontally (cannonball A) at 5 meters/second. At the same time, a second cannonball (cannonball B) is dropped from the same height. If air resistance is ignored, which cannonball will hit the ground first?
Note: The gravitational acceleration due to the Earth is 9.8 m/sec².
A. Cannonball A
B. Cannonball B
C. Both will hit the ground at the same time.
D. It can not be found from the given information.
Answer:
d
Explanation:
A sample of helium behaves as an ideal gas as it is heated at constant pressure from 283 K to 358 K. If 70 J of work is done by the gas dur- ing this process, what is the mass of the he- lium sample? The universal gas constant is 8.31451 J/mol · K. Answer in units of g.
The mass of the helium sample is approximately 0.187 g.
To solve this problem, we can use following formula:
w = nR(T2 - T1)
We can rearrange this formula to solve for n:
n = w / (R * (T2 - T1))
To find the mass of the helium sample, we can use following formula:
m = n * M
where m is the mass of the sample, n is number of moles of gas, and M is the molar mass of helium.
Substituting the given values into the first equation, we get:
70 J = n * 8.31451 J/mol*K * (358 K - 283 K)
Simplifying this equation, we get:
n = 0.0467 mol
Substituting this value into the second equation, we get:
m = 0.0467 mol * 4 g/mol = 0.187 g
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A 35.30-kg box is attached to a light string that is wrapped around a cylindrical frictionless spool of radius 10.0 cm and moment of inertia 4.00 kg * m^2. The spool is suspended from the ceiling, and the box is then released from rest a distance from rest a distance 3.50 m above the floor. How long does it take for the box to reach the floor?
Answer:
The velocity of the box is related to the angular velocity of the spool, which is given by the equation:
v = r * ω
where r is the radius of the spool and ω is the angular velocity of the spool. The angular velocity of the spool, in turn, is related to the torque applied to the spool by the tension in the string, which is given by the equation:
τ = I * α
where τ is the torque, I is the moment of inertia of the spool, and α is the angular acceleration of the spool.
The tension in the string is equal to the weight of the box, which is given by:
T = m * g
Putting all of these equations together, we can solve for the time it takes for the box to reach the floor. Here's how:
First, we can find the angular acceleration of the spool using the torque equation:
τ = I * α
T = m * g = τ
m * g = I * α
α = (m * g) / I
α = (35.30 kg * 9.81 m/s^2) / 4.00 kg*m^2
α = 86.53 rad/s^2
Next, we can find the angular velocity of the spool using the kinematic equation:
ω^2 = ω_0^2 + 2 * α * θ
where ω_0 is the initial angular velocity (which is zero), θ is the angle through which the spool has turned (which is equal to the distance the box has fallen divided by the radius of the spool), and ω is the final angular velocity (which is what we want to find). Solving for ω, we get:
ω^2 = 2 * α * θ
ω = sqrt(2 * α * θ)
ω = sqrt(2 * 86.53 rad/s^2 * (3.50 m / 0.10 m))
ω = 166.6 rad/s
Finally, we can find the time it takes for the box to reach the floor using the equation:
v = r * ω
v = 0.10 m * 166.6 rad/s
v = 16.66 m/s
t = d / v
t = 3.50 m / 16.66 m/s
t = 0.21 s
A string of length 75.0cm has fixed ends. Two consecutive harmonics are 420 Hz and 315 Hz. Find the wave speed and the fundamental frequency.
please use equations: f=vλ and λ=[tex]\frac{2L}{n}[/tex]
The wave speed is 840 cm/s and the fundamental frequency is 1120 Hz.
Frequency is the number of cycles of a periodic waveform that occur per unit of time. It is measured in Hertz (Hz).
We can use the equation λ=2L/n, where λ is the wavelength, L is the length of the string, and n is the harmonic number. Since the string has fixed ends, the harmonics must be odd-numbered, so we have n=1 for the fundamental frequency, n=3 for the second harmonic (315 Hz), and n=5 for the third harmonic (420 Hz).
Using n=1 and λ=2L/n, we get:
λ = 2L/1
λ = 2L
Using n=3 and λ=2L/n, we get:
λ = 2L/3
Using n=5 and λ=2L/n, we get:
λ = 2L/5
We can use the formula f=v/λ to relate the wave speed v, wavelength λ, and frequency f. For the two consecutive harmonics, we can write:
v/λ1 = f1
v/λ2 = f2
Since the two harmonics are consecutive, we can assume that they correspond to adjacent values of n, so we have:
λ1 = 2L/1 = 2L
λ2 = 2L/3
Substituting these values into the above equations and solving for v, we get:
v = f1λ1 = f2λ2 = (420 Hz)(2L) / (2L) = (315 Hz)(2L)/(2L/3) = 840 cm/s
To find the fundamental frequency, we use the formula f=v/λ1:
f = v/λ1 = 840 cm/s / 2L = (840 cm/s) / (0.75 m) = 1120 Hz
Therefore, the wave speed is 840 cm/s and the fundamental frequency is 1120 Hz.
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By what factor will the ratio^Q/V increase for a capaci-
tor whose capacitance is doubled?
(a) No change
(b) 2
(d) 1/2
(c) 4
There will be no change in the ration of Q/V. Therefore the correct answer is (a).
How to proof there is no change in the Q/VThe ratio of charge Q to voltage V across a capacitor is given by:
Q/V = C
Where C is the capacitance of the capacitor.
If the capacitance is doubled, the new capacitance C' becomes 2C. Substituting into the equation, we get:
Q/V = C
Q/V = 2C/2 = C'
So the ratio of Q to V remains the same, and there is no change in the ratio Q/V when the capacitance is doubled.
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An iron ball of mass 3kg is suspended from a 6m thread of negligible mass. The ball is pulled back, so that the thread makes a 30° angle with the vertical. It is then released and oscillates. Calculate the maximum values of its potential energy and kinetic energy. What will be its velocity, while passing through the mean position?
Please solve this.. I can't find R_th and V_oc at 6kohm....
The current I through the 4 kΩ resistor in the original circuit is 0.199 mA.
Thévenin's theorem states that any linear network of voltage and current sources and resistors can be replaced by an equivalent circuit consisting of a single voltage source and a single resistor. The equivalent circuit provides the same output voltage and current as the original circuit for any external load connected to it.
To find the current I in the circuit using Thévenin's theorem, we need to follow these steps:
Step 1: Find the Thévenin equivalent voltage (Vth) across the 4 kΩ resistor.
To find Vth, we need to first find the open circuit voltage (Voc) across the 4 kΩ resistor. We can do this by removing the 4 kΩ resistor and finding the voltage between its two terminals using a voltage divider:
Voc = 6 kΩ/(2 kΩ + 6 kΩ) x 2 mA = 1.2 V
Next, we need to find the Thévenin equivalent resistance (Rth) across the 4 kΩ resistor. To do this, we need to short-circuit all the independent voltage sources (in this case, there is only one) and find the equivalent resistance seen from the terminals of the 4 kΩ resistor. With the 2 mA current source shorted out, the 2 kΩ and 4 kΩ resistors are in parallel:
Rth = 2 kΩ || 4 kΩ = 1.33 kΩ
Step 2: Replace the original circuit with the Thévenin equivalent circuit.
We can now replace the original circuit with the Thévenin equivalent circuit, which consists of a voltage source Vth = 1.2 V in series with a resistor Rth = 1.33 kΩ.
Step 3: Find the current I through the 4 kΩ resistor in the Thévenin equivalent circuit.
To find the current I, we can use Ohm's law:
I = Vth/(Rth + 4 kΩ) = 1.2 V/(1.33 kΩ + 4 kΩ) = 0.199 mA
Therefore, the current I through the 4 kΩ resistor in the original circuit is 0.199 mA.
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A student sets up four cups with 40 mL of water in each and adds different amounts of ice to each cup. The student measures the temperature of the water before and after the ice melts in each cup. Which statement describes how the student can determine the connection between the temperature change and the transfer of kinetic energy?
A student sets up four cups with 40 mL of water in each and adds different amounts of ice to each cup.
To determine the connection between the temperature change and the transfer of kinetic energy, the student can measure the initial and final temperatures of the water in each cup and the mass of the ice added to each cup. Then, the student can use the following equation to calculate the amount of heat transferred from the ice to the water
Q = m × c × ΔT
Where Q is the amount of heat transferred, m is the mass of the ice added, c is the specific heat capacity of water (4.184 J/g °C), and ΔT is the change in temperature of the water.
The student can then compare the amount of heat transferred from the ice to the water in each cup to the change in temperature of the water. If the temperature change is greater in a cup where more heat was transferred, this suggests a direct connection between the transfer of kinetic energy (as heat) from the ice to the water and the temperature change of the water.
Hence, This can be further supported by calculating the temperature change per unit of heat transferred, which should be approximately the same for each cup if there is a direct connection between the transfer of heat and the temperature change.
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The drawing shows a set of equipotential surfaces seen in cross-sections. Each is
labelled according to its electric potential. A 3.9 x 10-7 C point charge is placed at
position A. Find the work done on the point charge by the electric force when it is
moved (i) from A to B, and (ii) A to C.
(i) The work done on the point charge by the electric force when moved from A to B is 2.1 x 10⁻⁶ J.
(ii) The work done on the point charge by the electric force when moved from A to C is -5.5 x 10⁻⁶ J.
The work done by an electric force is equal to the negative of the change in potential energy, which is given by the product of the charge and the change in potential. The change in potential between two points is equal to the potential difference between those points.
For (i), the potential difference between A and B is 6 V, so the work done is (3.9 x 10⁻⁷ C) x (-6 V) = -2.1 x 10⁻⁶ J (negative because the charge moves from higher to lower potential).
For (ii), the potential difference between A and C is -15 V, so the work done is (3.9 x 10⁻⁷ C) x (-(-15 V)) = -5.5 x 10⁻⁶ J (negative because the charge moves from lower to higher potential).
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A 1200 W floor heater, a 360 W television, and a hand iron operating at 900 W are all plugged into the same 120 volt circuit in a house (that is, the same pair of wires that come from the basement fuse box). What is the total current flowing through this circuit?
20.5 A*
17.5 A
15 A
12.5 A
The structure of zinc telluride crystals is formed by a dense packing of anions, and cations occupy inter-nodes
a) Determine what type of packing corresponds to the stacking sequence for this structure? Explain the answer?
b) what type of internodes will the cations occupy? Why?
c) what fraction of the available voids will be occupied by cations?
d) depict two densely packed planes of anions stacked in the AB sequence and show the voids filled with cations.
The structure of zinc telluride crystals is formed by a dense packing of anions, and cations occupy inter-nodes.
a) The structure of zinc telluride crystals is formed by a close packing of anions in a hexagonal close-packed (HCP) lattice. The stacking sequence of HCP lattice is ABABAB.
b) The cations occupy octahedral voids which are formed in between the closely packed anions.
c) In HCP lattice, there are 6 octahedral voids per unit cell. Each unit cell contains 2 zinc cations. Hence, the fraction of the available voids occupied by cations is 2/6 or 1/3.
d) Here is a depiction of two densely packed planes of anions stacked in the AB sequence with the voids filled with cations
B Cation in one octahedral void
A B Cation in another octahedral void
A Anion
A Anion
B A Cation in one octahedral void
B Cation in another octahedral void
The two densely packed planes of anions are labeled as A and B. Hence, The cations occupy the octahedral voids between these planes.
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A hollow glass sphere has a density of 1.3g/cm at 20 C. Glycerine has a density of 1.26 g/cm at 20 C. At what temperature would the sphere begin to float in glycerine
A hollow glass sphere has a density of 1.3g/cm at 20 C. Glycerine has a density of 1.26 g/cm at 20 C.
To determine the temperature at which the hollow glass sphere begins to float in glycerine, we need to calculate the density of glycerine at various temperatures and compare it to the density of the glass sphere.
The density of glycerine changes with temperature, so we need to use a density-temperature chart or equation to determine the density of glycerine at different temperatures.
Assuming the hollow glass sphere has a uniform wall thickness, we can calculate its volume by subtracting the volume of the hollow interior from the volume of the whole sphere
Volume of sphere = (4/3)π[tex]r^{3}[/tex]
Volume of hollow interior = (4/3)π[tex](r-t)^{3}[/tex]
Volume of glass wall = (4/3)π([tex]r^{3}[/tex] - [tex](r-t)^{3}[/tex]), where t is the thickness of the glass wall.
From the density and volume of the glass sphere, we can determine its mass
Mass of glass sphere = Density of glass sphere x Volume of glass sphere
Next, we can use Archimedes' principle to determine the volume of glycerine displaced by the glass sphere when it is submerged in the glycerine
Volume of glycerine displaced = Mass of glass sphere / Density of glycerine at the given temperature
When the glass sphere floats, the volume of glycerine displaced will be equal to the volume of the glass sphere. Thus, we can set the two volumes equal to each other and solve for the temperature at which the density of glycerine matches the density of the glass sphere
Volume of glass sphere = Volume of glycerine displaced
(4/3)π[tex]r^{3}[/tex] - (4/3)π[tex](r-t)^{3}[/tex] = Mass of glass sphere / Density of glycerine at the given temperature
Hence, for the temperature requires knowing the radius and thickness of the glass sphere and the mass of the sphere.
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Calculate the volume of a parallelepiped with sides give as a = ( 7,2 , 4 ) , b = ( 4,7 , 6 ) and c = ( 3,4 , 7 )
The volume of the parallelepiped is 83 cubic units.
The volume of a parallelepiped with sides give as a = ( 7,2 ,4 ) , b = ( 4,7 ,6 ) and c = ( 3,4 ,7 ).
The volume of a parallelepiped with adjacent sides a, b, and c is given by the scalar triple product (a × b) · c.
First, need to calculate the cross product of vectors a and b
a × b =
[tex]\left[\begin{array}{ccc}i &j&k\\7&2&4\\4&7&6\end{array}\right][/tex]
= (2 × 6 - 4 × 7) i - (7 × 6 - 4 × 4) j + (7 × 7 - 2 × 4) k
= -8 i - 26 j + 45 k
Now, calculate the scalar triple product
(a × b) · c = (-8)(3) + (-26)(4) + (45)(7) = 83
Therefore, the volume of the parallelepiped is 83 cubic units.
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The equation for the acceleration of a body moving in a circle is , where a is acceleration, v is velocity, and r is the radius of the circle. Acceleration has units of m/s2.Solve the equation for velocity.
Help my brain ain’t braining
The arrows are drawn in the figure which shows gravitational forces on each person on earth.
Gravitational force is force of attraction between two masses. Gravitational force(F) between two bodies is directly proportion to the product of masses(m₁,m₂) of two bodies and inversely proportional to square of distance(r) between them. mathematically it is written as,
F∝ m₁.m₂
F ∝ 1/r²
F = G m₁,m₂÷r²
where G is gravitational constant, whose value is 6.6743 × 10⁻¹¹ m³ kg-1s⁻².
Force is expressed in Newton N in SI unit. its dimensions are [M¹L¹T⁻²].
This is analogous with coulomb's law which gives force between two charges.
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A well-coated structure is defined as A) 95% or better B) 90% or better C) 99% or better D) 93% or better
Answer and Explanation:
A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.
However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing. Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body.
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A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.
However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing.
Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body
State and explain the effects on an electromagnet of: i) removing the core. ii) replacing the iron core with a steel core
Answer:
An electromagnet is a type of magnet that is created by an electric current flowing through a coil of wire wrapped around a magnetic core. The core is usually made of a ferromagnetic or ferrimagnetic material, such as iron, that can increase the magnetic field strength by hundreds or thousands of times.
The effects on an electromagnet of removing or replacing the core depend on the properties of the core material. Here are some possible effects:
i) Removing the core: This will reduce the magnetic field strength of the electromagnet, as the core material is no longer concentrating the magnetic field lines. The electromagnet will become an air-core coil, which has a much lower magnetic permeability than a ferromagnetic or ferrimagnetic core. The electromagnet will also lose its ability to retain some magnetism when the current is switched off, as the core material is no longer magnetized.
ii) Replacing the iron core with a steel core: This will change the magnetic field strength and the magnetic behavior of the electromagnet, depending on the type and quality of steel used. Steel is an alloy of iron and other elements, such as carbon, manganese, nickel, chromium, etc. Some types of steel have higher magnetic permeability than iron, which means they can increase the magnetic field strength more than iron. However, some types of steel have lower magnetic permeability than iron, which means they can decrease the magnetic field strength. Steel also has higher coercivity and hysteresis than iron, which means it can retain more magnetism when the current is switched off, but it also requires more energy to magnetize and demagnetize. Steel can also be affected by temperature changes, corrosion, and mechanical stress, which can alter its magnetic properties over time.
b. printed circuit board A length th of copper track on a has a cross-sectional area of 5x108 m². The Current in the track is 3.5 mA. Your are with some useful information about of copper contains 6. 0x1026 atoms. show that the electron is about 10²⁹ m². copper. has a mass of 8.9x10³kg. skg of copper 29 for copper density number densi provided r. 1m²
Answer:
The change in mean drift velocity for electrons as they pass from one end of the wire to the other is 3.506 x 10⁻⁷ m/s and average acceleration of the electrons is 4.38 x 10⁻¹⁵ m/s².
The given parameters;
Current flowing in the wire, I = 4.00 mA
Initial diameter of the wire, d₁ = 4 mm = 0.004 m
Final diameter of the wire, d₂ = 1 mm = 0.001 m
Length of wire, L = 2.00 m
Density of electron in the copper, n = 8.5 x 10²⁸ /m³
The initial area of the copper wire;
The final area of the copper wire;
The initial drift velocity of the electrons is calculated as;
The final drift velocity of the electrons is calculated as;
The change in the mean drift velocity is calculated as;
The time of motion of electrons for the initial wire diameter is calculated as;
The time of motion of electrons for the final wire diameter is calculated as;
The average acceleration of the electrons is calculated as;
Thus, the change in mean drift velocity for electrons as they pass from one end of the wire to the other is 3.506 x 10⁻⁷ m/s and average acceleration of the electrons is 4.38 x 10⁻¹⁵ m/s².
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Explanation:
The changing mean drift velocity of the electrons plays out at 3.506 x 10⁻⁷ m/s along with an average acceleration nearing 4.38 x 10⁻¹⁵ m/s².
How to solveAs the electrons traverse one end of the wire to another, their mean drift velocity undergoes a shift of 3.506 x 10⁻⁷ m/s with an average acceleration of 4.38 x 10⁻¹⁵ m/s² in accordance with the following parameters:
- The current flowing through the wire is at 4.00 mA.
- The original diameter of the wire, d₁, measures at 4 mm or 0.004 m.
- Conversely, the final diameter, d₂, displays a measurement of 1 mm or 0.001 m.
- The length of the entire wire is consistent, measuring at 2 meters.
- Notably, the density of electrons present within copper reaches an estimated value of 8.5 x 10²⁸ /m³.
Calculations regarding both initial and final area coverage provided by copper must be explored along with numerical data involving the two varying drift velocities for accurate results.
Thus, we arrive at the change rate of the mean drift velocity between points in the wire as well as the plenitude of electron acceleration achieved after contemplation into the corresponding motion periods.
The conclusion reflects that our measurements find the changing mean drift velocity of the electrons plays out at 3.506 x 10⁻⁷ m/s along with an average acceleration nearing 4.38 x 10⁻¹⁵ m/s².
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A concave mirror forms a real image which is twice the size of an object.If the object is 20cm from mirror, concavature of the mirror m
The cuvature of the mirror is 26.67 cm.
What is the curvature of the mirror?The curvature of the mirror is calculated as follows;
1/f = 1/v + 1/u
Where;
f is the focal length of the mirror, u is the distance of the object from the mirror,v is the distance of the image from the mirror.The magnification of the mirror = 2
m = v/u
2 = v/u
v = 2u
The focal length of the mirror is calculated as;
1/f = 1/2u + 1/u
1/f = 3/2u
f = 2u/3
f = (2 x 20 cm )/3
f = 13.33 cm
Curvature = 2f = 26.67 cm
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Paul Cezanne's Still Life with Apples in a Bowl (1879-83) represents a break with the tradition of using ____in art.
value
modeled forms
local color
linear perspective
Paul Cezanne's Still Life with Apples in a Bowl (1879-83) represents a break with the tradition of using linear perspective in art.
One of the pioneers of modern art, Cezanne used a novel approach to painting at the time. In his still life paintings, Cezanne represented things utilizing a system of flattened planes and simplified forms rather than the conventional perspective techniques that provide the impression of depth and space.
Additionally, he played around with color, relying on color blocks rather than shading and modeling to convey a sense of volume and form.
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A smooth circular cylinder of radius 1.5m in a triangular grove, one side of which makes 15 °angle and the other 40° angle with the horizontal · Find the reaction. at the surface of contact, if there. is no fiction and the cylinder weigh 100N
Answer:
46.5 N
Explanation:
attached is explanation
Mark and Nancy both take three measurements of the length of a pencil that is 15.1 cm. Mark records 15.0, 15.0, and 15.1 cm. Nancy records 15.1, 15.2, and 15.2 cm. Which of the following statements is true about Mark and Nancy's measurements?
A. Mark's measurement is more precise.
B. Nancy's measurement is more accurate.
C. Mark's measurement is more accurate.
D. Both sets of measurements are equally accurate and precise.
A student slides a block on a surface by applying a force of 11 newtons (N) toward the left. The friction force on the block is 4 N.
A student slides a block on a surface by applying a force of 11 newtons (N) toward the left. The friction force on the block is 4 N and which is in right direction. the Net force acting on the box is 11-4 = 7N.( towards left)
Force is responsible for the motion of an object. it produces acceleration in the body. According to newton's second law force is mass times acceleration i.e. F =ma. Its SI unit is N which is equivalent to kg.m/s². There are two types of forces, balanced force and unbalanced force. Balanced forces are those forces which are opposite in direction and equal in magnitude. When Net force acting on a body is zero then we call it as balanced force. Balanced force is not responsible for the motion of the body. ex. when two persons pulling rope on both end with equal magnitude which cause them to be balanced force have 0 net force. Unbalanced forces are those when resultant of all the forces is not equal to zero is called as unbalanced force. unbalanced force is responsible for the motion of the body.
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what’s the answer for this
Answer:4 m/s
Explanation:
Look at the Graph Below and Answer the questions.
This graph shows a ball rolling from A to G.
LA
B
G
D
E
F
21. Which letter shows the ball when it has the maximum kinetic energy?
22. Which letter shows the ball when it has the maximum potential energy?
23. Which letter shows the ball when it has the least kinetic energy?
24. Which letter shows the ball when it has the least potential energy?
Letter F shows the ball when it has the maximum kinetic energy.
Letter A shows the ball when it has the maximum potential energy.
Letter G shows the ball when it has the least kinetic energy.
Letter C shows the ball when it has the least potential energy.
What is kinetic energy.?The kinetic energy of an object is described as the form of energy that it possesses due to its motion.
potential energy on the hand is described as the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors.
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