Answers
Answer:
The pressure on the wall is 9416.25 N/m²
Explanation:
Please see the attachments below
Related Questions
: An experienced spear fisherman sees a small fish swimming in a tidal pool. If the fisherman sees the fish at approximately a 40o angle (measured from vertical), he knows that he must release his spear at what angle
Answers
Answer:
He should aim below 40°
Explanation:
Because
His eyes are being deceived about the real location of the fish, because the light coming from the fish is refracting away from the normal, if traced from the vertical as it passes into the air and to his eye . so, he will perceive the fish as being shallower than it really is. So if he throws the spear which will travel in a straight line directly at where he perceives the fish to be, the spear will pass above its head so he needs to need to aim lower than 40°
Explanation:
In a Young's double-slit experiment, light of wavelength 500 nm illuminates two slits which are separated by 1 mm. The separation between adjacent bright fringes on a screen 5 m from the slits is: CONVERT FIRST
Answers
Answer:
The value is [tex]y = 0.0025 \ m[/tex]
Explanation:
From the question we are told that
The wavelength is [tex]\lambda = 500 \ nm[/tex]
The distance of separation is [tex]d = 1\ mm = 0.001 \ m[/tex]
The distance from the screen is [tex]D = 5 \ m[/tex]
Generally the separation between the adjacent bright fringe is mathematically represented as
[tex]y = \frac{D * \lambda }{ d}[/tex]
=> [tex]y = \frac{5 * 500 *10^{-9}}{0.001}[/tex]
=> [tex]y = 0.0025 \ m[/tex]
Calculate the radius of curvatuire of the concave lens based on the measured focal length.
Answers
Answer:
R₁ = (n -1) f
Explanation:
In geometric optics the focal length and the radius of curvature are related, for the case of a lens
1 / f = (n₂-n₀) (1 / R₁ - 1 / R₂)
where f is the focal length, n₂ is the refractive index of the material, n₀ is the refractive index of the medium surrounding the material, R₁ and R₂ are the radius of curvature of each of the material's
In our case, the most common is that the lens is in the air, so n1 = 1, in many cases one of the surfaces is flat, so its radius of curvature R₂ = ∞.
1 / f = (n-1) (1 / R₁)
we look for the radius of curvature R₁
1 / R₁ = 1 / f (n-1)
R₁ = (n -1) f
With this expression we can find the radius of curvature of a concave-plane lens
light of wavelength 610 nm is incident on a narrow slit. The angle between the first diffraction minimum on one side of the central meximum and the first minimum on the other side is 1.23°. What is the width of the slit?
Answers
Answer:
The width of the slit is [tex]d = 5.68 *10^{-5} \ m[/tex]
Explanation:
From the question we are told that
The wavelength is [tex]\lambda = 610 \ nm = 610 *10^{-9} \ m[/tex]
The angle is [tex]\theta = 1.23 ^o[/tex]
Generally the angle between the first minimum on one side and that the central maximum is evaluated as
[tex]\theta _1 = \frac{\theta}{2}[/tex]
=> [tex]\theta _1 = \frac{1.23}{2}[/tex]
=> [tex]\theta _1 = 0.615 ^o[/tex]
Generally the condition for minimum diffraction is mathematically represented as
[tex]d sin \theta_1 = n\lambda[/tex]
For first minimum n = 1
=> [tex]d = \frac{n \lambda }{ sin (\theta_1)}[/tex]
=> [tex]d = \frac{1 * 610 *10^{-9}}{ sin (0.615)}[/tex]
=> [tex]d = 5.68 *10^{-5} \ m[/tex]
How do you solve this ?
Why is the ans C not B ?
Answers
Explanation:
Draw a free body diagram of the toolbox. There are two forces:
Weight force mg pulling down,
and applied force F pulling up.
Sum of forces in the y direction:
∑F = ma
F − mg = ma
45 N − 15 N = (3 kg) a
a = 10 m/s²
The answer should be B. It's possible the answer key has a mistake.
The coefficient of static friction between a 3.00 kg crate and the 35.0o incline is 0.300. What minimum force F must be applied perpendicularly to the incline to prevent the crate from sliding down
Answers
Answer:
So the minimum force is
32.2Newton
Explanation:
To solve for the minimum force, let us assume it to be F (N)
So
F=mgsinA
But
=>>>> coefficient of static friction x (F + mgcosA
=>3 x 9.8 x sin35 = 0.3 x (F + 3 x 9.8 x cos35)
So making F subject of formula
F + 24.0 = 56.2
F = 32.2N
What is the wavelength of the light entering an interferometer if 402 bright fringes are counted when the movable mirror moves 0.115 mm?
Answers
Answer:
The value is [tex]\lambda = 572 *10^{-9} \ m[/tex]
Explanation:
From the question we are told that
The number of bright fringes is n = 402
The displacement of the mirror is [tex]\delta l = 0.115 \ mm = 1.15 *10^{-4} \ m[/tex]
Generally the number of fringes is mathematically represented as
[tex]n = \frac{2 * \delta l }{\lambda }[/tex]
=> [tex]\lambda = \frac{2 * \delta l }{n }[/tex]
=> [tex]\lambda = \frac{2 * 1.15*10^{-4} }{402 }[/tex]
=> [tex]\lambda = 572 *10^{-9} \ m[/tex]
A satellite travels around the earth at 37,000 km/hr. How far will it travel after 13 hours?
Answers
Explanation:
Distance = speed × time
d = (37,000 km/hr) (13 hr)
d = 481,000 km
A thin film with an index of refraction of 1.50 is placed in one of the beams of a Michelson interferometer. If this causes a shift of 8 bright fringes in the pattern produced by light of wavelength 540 nm, what is the thickness of the film?
Answers
Answer:
The thickness of the film is 4.32 μm.
Explanation:
Given;
index of refraction of the thin film on one beam, n₂ = 1.5
number of bright fringes shift in the pattern produced by light, ΔN = 8
wavelength of the Michelson interferometer, λ = 540 nm
The thickness of the film will be calculated as;
[tex]\delta N = \frac{2L}{\lambda} (n_2 -n_1)[/tex]
where;
n₁ and n₂ are the index of refraction on the beam
L is the thickness of the film
[tex]\delta N = \frac{2L}{\lambda} (n_2 -n_1)\\\\L = \frac{\lambda}{2} (\frac{N}{n_2-n_1} )\\\\L = \frac{540*10^{-9}}{2} (\frac{8}{1.5-1} )\\\\L = 4.32*10^{-6} \ m\\\\L = 4.32 \mu m[/tex]
Therefore, the thickness of the film is 4.32 μm.
Marcel is helping his two children, Jacques and Gilles, to balance on a seesaw so that they will be able to make it tilt back and forth without the heavier child, Jacques, simply sinking to the ground. Given that Jacques, whose weight is WWW, is sitting at distance LLL to the left of the pivot, at what distance L1L1L_1 should Marcel place Gilles, whose weight is www, to the right of the pivot to balance the seesaw
Answers
Answer:
L1 = WL/w
Explanation:
Jacques's weight = W
Jacques's distance from the pivot = L
Gilles's weight = w
Gilles's distance from the pivot must be L1
For the two boy to balance each other, they must generate equal amount of torques around the pivot
Torque = distance x weight
For Jacques, the torque generated = WL
For Gilles, the torque generated = wL1
Balancing the two torques, we have
WL = wL1
the distance L1 must be equal to
L1 = WL/w
A relaxed biceps muscle requires a force of 25.0N for an elongation of 3.0 cm; under maximum tension, the same muscle requires a force 500N for the same elongation. Find the Young's modulus for the muscle tissue under each of these conditions if the muscle can be modeled as a uniform cylinder with an initial length of 0.200 m and a cross-sectional area of 50 cm^2.
Answers
3.3 x10^4N/m²
6.7 x105N/m²
Explanation:
Let the young modulus of the relaxed biceps be
Y= F¹Lo/ deta L1 x A
= 25 x0.2/ 0.03* 50cm²(1m²
0.0004cm^-²)
= 3.3x10^4N/m²
But young modules of muscle under maximum tension will be
Y= F"Lo/ deta L" x A
= 500x 0.2/ 0.03* 50cm²(1m²
0.0004cm^-²)
= 6.7 x10^5N/m²
The Young's Modulus of the relaxed muscle and the muscle under maximum tension is 3.3×10⁴ N/m² and 6.6×10⁵ N/m² respectively.
Young's Modulus:
Assuming the biceps muscle as a uniform cylinder with an initial length of L = 0.2 m and cross-sectional area of A = 50cm² = 0.05m²
(i) For the relaxed muscle:
Force required for elongation of ΔL = 0.03m is, F = 25 N
Young's Modulus (Y) = stress/strain
Now, stress = F/A,
and strain = ΔL/L
thus,
Y = (F/A) / (ΔL/L)
Y = FL/AΔL
Y = (25×0.2)/(0.05×0.03)
Y = 3.3×10⁴ N/m²
(ii)(i) For the muscle under maximum tension:
Force required for elongation of ΔL = 0.03m is, F = 500 N
Young's Modulus (Y) = stress/strain
Now, stress = F/A,
and strain = ΔL/L
thus,
Y = (F/A) / (ΔL/L)
Y = FL/AΔL
Y = (500×0.2)/(0.05×0.03)
Y = 6.6×10⁵ N/m²
Learn more about Young's Modulus :
https://brainly.com/question/18793028?referrer=searchResults
What is the wavelength of the electromagnetic radiation needed to eject electrons from a metal?
Answers
Answer:
λ = hc/(eV + h[tex]f_{0}[/tex])
Explanation:
Let the work function of the metal = ∅
the kinetic energy with which the electrons are ejected = E
the energy of the incident electromagnetic wave = hf
Then, we know that the kinetic energy of the emitted electron will be
E = hf - ∅
because the energy of the incident electromagnetic radiation must exceed the work function for electrons to be ejected.
This means that the energy of the incident e-m wave can be written as
hf = E + ∅
also, we know that the kinetic energy of the emitted electron E = eV
and the work function ∅ = h[tex]f_{0}[/tex]
we can they combine all equations to give
hf = eV + h[tex]f_{0}[/tex]
we know that f = c/λ
substituting, we have
hc/λ = eV + h[tex]f_{0}[/tex]
λ = hc/(eV + h[tex]f_{0}[/tex]) This is the wavelength of the e-m radiation needed to eject electrons from a metal.
where
λ is the wavelength of the e-m radiation
h is the Planck's constant = 6.63 x 10^-34 m^2 kg/s
c is the speed of e-m radiations in a vacuum = 3 x 10^8 m/s
e is the charge on an electron
V is the voltage potential on the electron
[tex]f_{0}[/tex] is the threshold frequency of the metal
Which of the following is not a Health-Related fitness part? Question 1 options: Body composition Power Flexibility Speed
Answers
Answer:
The correct answer is - speed.
Explanation:
Health related fitness have five major components that are muscular strength or power, endurance, body composition, cardiovascular endurance and flexibility.
All these five health related fitness helps an individual to loose weight, better sleep, enhance mood and prevents from various disease and many other beneficiary results.
Thus, the correct answer is : speed.
Remove the wood block from the water. Place the brick block into the water and let it sink. How much water does the brick block displace? Hint: This is the liquid level with the block minus the liquid level before the block is added.
Answers
Answer:
the volume desalinated that is placed is equal to the volume of the block.
Explanation:
For this exercise we use the Archimedean principle which states that the thrust is equal to the weight of the desalted liquid.
B = ρ g V
When we have the block of wood the volume of water desalinated in the volume of the block under water, this is because the wood floats in the water
When placing the block of clay (brick), it sinks, so the volume desalinated that is placed is equal to the volume of the block.
V_body = V_waer = l to h
Which of the following landforms would you NOT expect to see in the Inland South?
a) Swamplands
b) Flat, sandy plains
c) Rugged mountains
d) Rolling hills
e) Glaciers
Answers
Answer:
Option: e) Glaciers
Explanation:
Historically, the Inland South viewed as a backwater of the United States. The Inland South is known for its Appalachians mountains, swampland. Flatland, sandy soils, and meandering rivers are some of its features. The climate is hot and humid, which allow the area to grow as Pantanal floodplains. Glaciers will be one of the landforms that one will not expect to see in the Inland South.
The ability of sculptural material to resist forces of pressure, like gravity, is called its __________.
Answers
A volleyball is released three times from three different heights: 5 m, 10 m, and 20 m. Which statement is correct about the volleyball?
The volleyball accelerates more quickly toward the ground when released from a higher height.
The volleyball accelerates the same amount toward the ground each time.
The volleyball accelerates more slowly toward the ground when released from a higher height.
The volleyball may accelerate more quickly or slowly depending on its mass.
A student is setting up an experiment with 10 different balls. The student wants to measure which ball hits the ground with the largest force when released from a box 5 feet above the ground. Which quantity should be measured to correctly calculate the force with which each ball hits the ground?
the initial velocity of each ball
the mass of each ball
the rate at which the velocity of each ball increases
the final velocity of each ball right before hitting the ground
Answers
Explanation:
1)
The answer is
The volleyball accelerates the same amount toward the ground each time.
Because gravitational acceleration is constant irrespective of altitude(height) or mass of the object.
2)
The answer is
the mass of each ball
because gravitational force is given by
F = mg
since g is a constant, he only needs to measure the mass if each ball
The concepts of free fall and Newton's second law allow to find the correct answers
1) Acceleration is constant
2) The mass of the body
The game of volleyball consists of throwing the balls from the serve to pass it to the other court, this is a two-dimensional movement type projectile launch, in this type of movement the acceleration is the constant on the y axis, it is called acceleration of the gravity and vale (g = 9.8 m / s²)
1) Let's review the different statements of the first part regarding acceleration.
a) The ball accelerates faster as it goes down
False. Acceleration is constant
b) The ball accelerates the same amount
True. Acceleration is constant and directed on the vertical axis
c) The ball accelerates slower or faster
False. Acceleration is constant
The vertical launch of kinematics, establishes that the ball as it descends it goes faster with an acceleration equal to the acceleration of gravity, in this part it is asked to look for the force of the ball when it reaches the ground, for this the second is used Newton law
F = m a
where in this case the acceleration is the acceleration of gravity
a = g
F = m g
Let's review the different claims
a) Initial velocity
False. To calculate the force you only need the mass since acceleration is constant
b) The mass
True. The product of the mass and the acceleration of gravity gives the force with which the ball hits the ground
c) Increasing speed
False. Increasing speed allows calculating acceleration not force
d) The final speed
False. Force does not depend on the speed of the body
In conclusion using the concepts of free fall and Newton's second law we can find the correct answers:
1) Acceleration is constant
2) Body mass
Learn more about free fall and Newton's second law here:
https://brainly.com/question/19897308
Suppose you wanted to hold up an electron against the force of gravity by the attraction of a fixed proton some distance above it. How far above the electron would the proton have to be? (k = 1/4πε0 = 9.0 × 109 N ∙ m2/C2, e = 1.6 × 10-19 C, mproton = 1.67 × 10-27 kg, melectron = 9.11 × 10-31 kg)
Answers
Answer:
The value is [tex]r = 5.077 \ m[/tex]
Explanation:
From the question we are told that
The Coulomb constant is [tex]k = 9.0 *10^{9} \ N\cdot m^2 /C^2[/tex]
The charge on the electron/proton is [tex]e = 1.6*10^{-19} \ C[/tex]
The mass of proton [tex]m_{proton} = 1.67*10^{-27} \ kg[/tex]
The mass of electron is [tex]m_{electron } = 9.11 *10^{-31} \ kg[/tex]
Generally for the electron to be held up by the force gravity
Then
Electric force on the electron = The gravitational Force
i.e
[tex]m_{electron} * g = \frac{ k * e^2 }{r^2 }[/tex]
[tex]\frac{9*10^9 * (1.60 *10^{-19})^2 }{r^2 } = 9.11 *10^{-31 } * 9.81[/tex]
[tex]r = \sqrt{25.78}[/tex]
[tex]r = 5.077 \ m[/tex]
g stAn experienced spear fisherman sees a small fish swimming in a tidal pool. If the fisherman sees the fish at approximately a 40o angle (measured from vertical), he knows that he must release his spear at what angle
Answers
Answer:
θ = 28.9
Explanation:
For this exercise let's use the law of refraction
n₁ sin θ₁ = n₂ sin θ₂
where we use index 1 for air and index 2 for water where the fish is
sin θ₂ = n₁ / n₂ sin θ₁
in this case the air repair index is 1 and the water 1.33
we substitute
sin θ₂ = 1 / 1.33 sin t 40
sin θ = 0.4833
θ = sin⁻¹ 0.4833
θ = 28.9
.If we had two unknown masses on opposite sides of the pivot, could we calculate both masses given just the information used in the experiment? Explain.
Answers
Answer:
No
Explanation:
No, it is impossible to calculate the two masses.
From the statement, there is one known mass on one of the side of the pivot and one "mystery" mass object on the other side of the pivot, so that we have to move that mystery mass or that known mass in a way that it balances both.
We need to know at least one mass. We cannot use any equilibrium condition involving torque with unknown masses.
un
An aircraft travelling at 600 km/h accelerates steadily at 10 km/h per second. Taking the
speed of sound as 1100 km/h at the aircraft's altitude, how long will it take to reach the
Sound barrier'?
Answers
Answer:
50 seconds
Explanation:
Acceleration = change in velocity / change in time
a = Δv / Δt
10 km/h/s = (1100 km/h − 600 km/h) / t
t = 50 s
How does area affect the pressure?
Answers
The smaller the area the greater the pressure, while the bigger the smaller the pressure. So they are inversely proportional
The measured value of the latent heat of vaporization of helium (at 1 atm) is
84 J/mol. Use this to estimate the binding energy of helium atoms in the liquid.
a. 2.6 x 10-6 eV
b. 3.6 x 10-4 eV
c. 5.1 x 10-4 eV
d. 8.6 x 10-3 eV
e. 3.6 x 10-2 eV
Answers
Answer:
d. 8.6 x 10-3 eV
Explanation:
Binding energy is energy that binds two atoms together . Energy is required to separate them . In the process of evaporation , energy is required to separate each molecules/ atoms of liquid so that they are separated and then get evaporated . That is why latent heat of evaporation is required .
1 mole of helium will contain 6.02 x 10²² atoms of it .
binding energy per atom = 84 / 6.02 x 10²² J
= 13.953 x 10⁻²² J
= 13.953 x 10⁻²² / 1.6 x 10⁻¹⁹ eV .
= 8.6 x 10⁻³ eV
A ranger in a national park is driving at 15.0 m/s when a deer jumps into the road 60 m ahead of the vehicle. After a reaction time, t, the ranger applies the brakes to produce an acceleration of a = -3.00 m/s2. What is the maximum reaction time allowed if she is to avoid hitting the deer?
Answers
Answer:
t = 5 s
Explanation:
In uniform rectilinear movement, the equation for final speed is:
vf = v₀ + a*t
In this case we need that the car stops just before 60 m after applied the brakes, then
vf = v₀ - a*t
vf = final speed = 0
v₀ = initial speed = 15 m/s
And negative acceleration is 3 m/s²
0 = 15 (m/s) - 3 ( m/s²)*t
t = 15 / 3 (m/s /m/s²)
t = 5 s
The point is that with that value ranger will hit the deer so in order to not to hit the deer that time should be smaller than 5 seconds
If the person generates another pulse like the first but the rope is tightened, the pulse will move:_________.
A. at the same rate
B. faster
C. slower
Answers
Answer:
the correct answer is B
Explanation:
The speed of a pulse on a string is described by the expression
v =√T/μ
where v is the speed of the pulse, t is the tension of the string and μ the linear density of the string
When applying this equation to our case, if the string is taut, it implies that the tension has increased so that the pulse speed is FASTER
the correct answer is B
Maggie completed a 10000-m race at an average speed of 160
m/min. If Tom took 12.5 fewer minutes to complete the race,
what was Tom's average speed?
Answers
Answer: 200m/min
Explanation:
Divide 10000m by 160m/min, you will get the answer 62.5. You then subtract 12.5 from 62.5 to understand what you will need your answer for the other person’s speed will be. 10000m divided by 50min is 200m/min.
J. Henry Alston was the first African American to publish his research findings on the perception of heat and cold in a major US psychology journal. Please select the best answer from the choices provided T F
Answers
Answer:
True
Explanation:
J. Henry Alston was known as a famous African American psychologist. He was known through his detailed study of the sensations of heat and cold which is a necessity for all humans.
He however became the first African American to publish his research findings on the perception of heat and cold in a major US psychology journal which gave him recognition in his field.
Answer:
True YOUR WELCOME
You push a box across the floor with a force of 20 N. You push it 10 meters in 5 seconds. How much work did you do? How much power did you use? Enter your answer in the space provided.
Answers
Explanation:
ur answer is in attachment.
hope it helps u
mark as brainlist
follow for good ans
Explanation:
Force applied on the box = 20 N
Displacement, s = 10 m
Time taken = 5 sec
According to first condition of the question, we could find the value of work done
i.e
Work done = force × displacement
= 20 × 10
= 200 Joule
According to second condition of the question, we could find the value of power
i.e
Power = work done/Time taken
= 200/5
= 40 watt.
Hope it helpful!!!!!!!!!!!!
Let a metallic rod 20 cm in length be heated to a uniform temperature of 100°C Suppose that at t=0 the ends of the bar are plunged into an ice bath at 0°C and thereafter maintained at this temperature, but that no heat is allowed to escape through the lateral surface. Find the time that will elapse before the center of the bar cools to a temperature of 5°C if the bar is made of (a) silver (b) aluminum (c) cast iron. The α2 values for silver, aluminum and cast iron are 1.71, 0.86 and 0.12 respectively.
(Round your answer to two decimal places. Use two-term approximation of the series.)
For silver, it takes _____ seconds to cool the bar to a temperature of 5°C
For aluminum, it takes _____ seconds to cool the bar to a temperature of 5°C
For cast iron, it takes _____ seconds to cool the bar to a temperature of 5°C
Answers
Answer:
a) t = 59 s , b) t = 107 s , c) t = 466 s
Explanation:
This is an exercise in thermal conductivity. The power dissipated or transferred is
P = Q / Δt = k A dT/dx
where Q is the thermal energy of the bar, k the constant of thermal conductivity.
If we assume that we are in a stable regime
dT / dx = (T₀ - [tex]T_{f}[/tex]) / L
the energy in the bar is
Q = m [tex]c_{e}[/tex] T₀
we substitute
m c_{e} T₀ / t = k A (T₀ -T_{f}) / L
t = c_{e} / k m L / A T₀ / (T₀ -T_{f})
let's use the concept of density
ρ = m / V
V = A L
m = ρ AL
t = c_{e} / k (ρ A L) L / A T₀ / (T₀ -T_{f})
t = [tex]c_{e}[/tex] /k ρ L² T₀/(T₀ -T_{f})
In this exercise, the initial temperature is T₀ = 100ºC, the final temperature is T_{f }= 5ºC and the length
L = L₀ / 2 = 20/2 = 10cm = 0.1m
a) case of silver
c_{e} = 234 J / kg ºC
k = 437 W / m ºC
ρ = 10,490 10³ kg / m³
let's calculate
t = 234/437 10.49 10³ 0.1² 100 / (100 -5)
t = 59 s
b) case materials aluminum
c_{e} = 900 J / kg ºC
k = 238 W / m ºC
ρ = 2.70 10³ kg / m³
t = 900/238 2.70 10³ 0.1² 100 / (100-5)
t = 107 s
c) iron material
c_{e} = 448 J / kg ºC
k = 79.5 W / m ºC
ρ = 7.86 10³ kg / m³
t = 448 / 79.5 7.86 10³ 0.1² 100 / (100-5)
t = 466 s
A charged particle is projected with its initial velocity parallel to a uniform magnetic field. What is the resulting path
Answers
Answer:
The particle will continue in a straight line parallel to the field
Explanation:
If a charged particle moves parallel to a magnetic field, without cutting across the field, then there will be no force on the particle. Since there is no force on the charged particle from the magnetic field, its velocity will continue in its original path, which is parallel to the field.