3/20 as a percentage?

Answer:

A. y = -0.7x + 1.9

Step-by-step explanation:

Answer:

is there a picture to answer?

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

(8,12)=(x1, y1)

(1,3)=(X2, y2)

distance=√(x2-x1)^2+(y2-y1)^2

=√(1-8)^2+(3-12)^2

=√(49+81)

√130

=11.40

SORRY B GFVBSDJ FS VBDF HVDFSBV FNVFDHS

Answer: 3.75 is at it's lowest terms. if you mean fractions its 15/4 or 3 & 3/4

Step-by-step explanation:

Answer:

N = -1

explanation:

x = N

solving steps:

[tex]\sf f(x)=x^2+2x-15[/tex]

To find symmetry of a quadratic function.

                                                                   vertex formula    :   [tex]\sf x=\dfrac{-b}{2a}[/tex]

[tex]a=1,\:b=2[/tex]

[tex]\sf x=\dfrac{-2}{2\cdot \:1}[/tex]

[tex]\sf x = -1[/tex]

Then,

N = -1

Answer:

D. Volume

Explanation:

Here the substance is soil and planter will hold the specific volume of soil.

4) -0.3 = -1/3 < -1/7 since the bigger a negative number is the less positive it is. 1/8 is positive so it is clear that it should be placed last. & thus do all options this way.

5) B

Area of a triangle = ½ bh.

where b = base &

h = height.

Area of outer shape = (½ x 16 x 12) in^2.

= 96 in^2.

Area of unshaded inner shape = (½ x 3 x 4) in^2.

= 6 in^2.

Area of shaded region = (96 – 6) in^2.

= 90 in^2.

The value of sin(80°)cos(20°) – cos(80°)sin(20°) using the trignometry property is √3/2.

The difference formula in trignometry for the sine funciton is given as,

[tex]\sin(A-B)=\sin(A)\cos(B) -\cos(A)\sin(B)[/tex]

The trignometric equation given in the problem is,

[tex]\sin(80^o)\cos(20^o) -\cos(80^o)\sin(20^o)[/tex]

Compare this equation with the above eqution, we get,

[tex]A=80^o\\B=20^o[/tex]

Thus, this equation can be written as,

[tex]\sin(80^o)\cos(20^o) -\cos(80^o)\sin(20^o)=\sin(80-20)\\\sin(80^o)\cos(20^o) -\cos(80^o)\sin(20^o)=\sin(60)\\\sin(80^o)\cos(20^o) -\cos(80^o)\sin(20^o)=\dfrac{\sqrt{3}}{2}[/tex]

Hence, the value of sin(80°)cos(20°) – cos(80°)sin(20°) using the trignometry property is √3/2.

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Answer:

(-4, -2)

Step-by-step explanation:

x-axis is horizontal and y-axis is vetical. The first valye of point A is -4, the second value of point B is -2, therefore, point C = (-4, -2)

The coordinates of C from the given graph are (-4, -2).

The coordinates in a graph indicate the location of a point with respect to the x-axis and y-axis.

The coordinates in a graph show the relationship between the information plotted on the given x-axis and y-axis.

We have,

The coordinates of A = (-4, 1)

The coordinates of B = (3, -2)

Now,

Point C has me same x-coordinate as point A and the same y-coordinate as point B

So,

The coordinates of C = -4, -2)

Thus,

The coordinates of C from the given graph are (-4, -2).

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Answer:

b no.is the correct answer.

Step-by-step explanation:

1-(a)

2-(c)

3-(d)

4-(b)

I hope it helped you

If u didn't understand anything pls ask in comment

Answer:

x = 2

x = -1.5

Step-by-step explanation:

The graph is of function f(x) = x²

Therefore, to find where the function intersects with y = 0.5x + 3,

equal the functions and solve for x:

⇒ x² = 0.5x + 3

⇒ x² - 0.5x - 3 = 0

Multiply both sides by 2:

⇒ 2x² - x - 6 = 0

Factor:

⇒ 2x² - 4x + 3x - 6 = 0

⇒ 2x(x - 2) + 3(x - 2) = 0

⇒ (x - 2)(2x + 3) = 0

Therefore:

(x - 2) = 0  ⇒  x = 2

(2x + 3) = 0  ⇒  x = -1.5

[tex]\dfrac{3a^2-6a+3}{a^2-1}\\\\=\dfrac{3(a^2 -2a+1)}{(a+1)(a-1)}\\\\=\dfrac{3(a-1)^2}{(a+1)(a-1)}\\\\=\dfrac{3(a-1)}{a+1}\\\\=\dfrac{3a-3}{a+1} ~~~\text{for}~ a\neq 1[/tex]

Answer:

20% off

Step-by-step explanation:

Divide:

72.8/364

Answer:

.20

Convert:

.20=20%

The shopkeeper giving 80% discount on the Christmas tree during the sale.

A discount is an amount that is subtracted from the regular price of an item.

[tex]discount \ percent = \frac{original \ price - final \ price }{original \ price } \times 100[/tex]

According to the given question.

The marked price of the Christmas tree i.e. original price = $364.

The price of the Christmas tree on sale i.e. final price  = $72.80

So,

The discount given on the Christmas tree

= Original price - final price

= $364 - $72.80

= 291.2

Therefore,

Discount percent  = [tex]\frac{291.2}{364} (100)= 80 \ percent[/tex]

Hence, the shopkeeper giving 80% discount on the Christmas tree during the sale.

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Answer:

Hope this helps!!!!!!

Mark Brainlest!!!!!!!!!!

Step-by-step explanation:

Mark and Henry win some money and share it in the ratio 1:3. Mark gets £9. How much did Henry get?

Ratio = 1 : 3

Let Mark's share be 1x = x

and Henry's share be 3x

We know that Mark gets £9

So,

1x = x = £9

Then 3x = £(3 * 9) = £27

HENCE,

Mark's share = £9

Henry's share = £27

Total money = Mark's share + Henry's share = £9 + £27 = £36

Answer:

£27

Step-by-step explanation:

so it shows mark is 1 while Henry is 3

we know that Mark is 1/4 while Henry is 3/4

/4 because the total is 4 so whatever their ratio is over their total

so we do: 1 = 9

3 = ?

and then u cross multiply

3*9 = 27 ÷ 1 = 27

so Henry receives £27

Answer:

Area of a Rectangle: l x w

2 x 3 = 6

Area of a Triangle:

[tex] \frac{b \times h}{2} [/tex]

The slanted height of the triangle is 2 and the base of the triangle is also 2 so

[tex] \frac{2 \times 2}{2} \\ \\ \frac{4}{2} = 2[/tex]

So to get the area of the figure you add the area of the rectangle plus the area of the triangle.

6+2=8

The area of the figure is 8 units square

Answer:

[tex]\begin{aligned}{&\cos \theta=\frac{10}{26} \\\bf{&\tan \theta=\frac{24}{10}}\end{aligned}[/tex]

Step-by-step explanation:

Since the angle is in the first quadrant, the values of all trigonometric functions are positive. Also. the formulas for the trigonometric functions we need to find from the problem are shown below:
[tex]\begin{aligned}\cos \theta &=\frac{x}{r} \\\tan \theta &=\frac{y}{x}\end{aligned}[/tex]

Based on the formulas listed, the value of y and r are y = 24 and r = 26 respectively. This means that in order to determine the value of the other functions, we need In compute for the value of x using the Pythagorean Theorem:

[tex]\begin{aligned}r^{2} &=x^{2}+y^{2} \\r^{2}-y^{2} &=x^{2}+y^{2}-y^{2} \quad\left[\text { \text{Subtracting \ both \ sides \ of \ the \ equation\ by} } y^{2}\right] \\r^{2}-y^{2} &=x^{2} \\\sqrt{r^{2}-y^{2}} &=\sqrt{x^{2}} \\\sqrt{r^{2}-y^{2}} &=x \\\sqrt{26^{2}-24^{2}} &=x \\10 &=x\end{aligned}[/tex]Then, substituting this to the formula to determine the answers yields:

[tex]\begin{aligned}\cos \theta &=\frac{x}{r} \\&=\frac{10}{26} \\\tan \theta &=\frac{y}{x} \\&=\frac{24}{10}\end{aligned}[/tex]

Therefore, the answers are:

[tex]\begin{aligned}&\cos \theta=\frac{10}{26} \\&\tan \theta=\frac{24}{10}\end{aligned}[/tex]

Answer:

See below

Step-by-step explanation:

We are here given that ,

[tex]\longrightarrow \sin\theta =\dfrac{24}{26}[/tex]

And we would like to find out other trigonometric ratios ( since it is not mentioned about which two I will find out all 6 ) . As we know that ,

[tex]\longrightarrow \sin\theta =\dfrac{perpendicular}{hypotenuse} =\dfrac{p}{h}[/tex]

So that ,

[tex]\longrightarrow \dfrac{p}{h} =\dfrac{24}{26}[/tex]

Let us assume the given ratio to be 24x : 26x .

So we can say that ,

Now let's find out the value of base , so that we can find out the other ratios .

By Pythagoras Theorem ,

[tex]\longrightarrow (perpendicular) ^2+(base)^2=(hypotenuse) ^2[/tex]

Substitute the respective values ,

[tex]\longrightarrow (26x)^2=(24x)^2+b^2\\[/tex]

[tex]\longrightarrow 676x^2 = 576x^2+b^2\\ [/tex]

[tex]\longrightarrow b^2=100x^2\\[/tex]

[tex]\longrightarrow b =\sqrt{100x^2}\\[/tex]

[tex]\longrightarrow \boldsymbol{ b = 10x } [/tex]

Now we may find the other ratios as ,

[tex]\longrightarrow \cos\theta = \dfrac{base}{hypotenuse}=\dfrac{10x}{26x}=\boxed{\boldsymbol{\dfrac{5}{13}}}\\[/tex]

[tex]\longrightarrow \tan\theta =\dfrac{perpendicular}{base}=\dfrac{24x}{10x}=\boxed{\boldsymbol{\dfrac{12}{5}}}\\[/tex]

[tex]\longrightarrow \cosec\theta =\dfrac{hypotenuse}{perpendicular}=\dfrac{26x}{24x}=\boxed{\boldsymbol{\dfrac{13}{12}}}\\ [/tex]

[tex]\longrightarrow \sec\theta =\dfrac{hypotenuse}{base}=\dfrac{26x}{10x}=\boxed{\boldsymbol{\dfrac{13}{5}}} \\[/tex]

[tex]\longrightarrow \cot\theta =\dfrac{base}{perpendicular}=\dfrac{10x}{24x}=\boxed{\boldsymbol{\dfrac{5}{12}}} [/tex]

And we are done !

Answer:

The answer should be C. 250 in^3

Answer:

C. 250 in^3

Step-by-step explanation:

Here's how we know that  [tex]\sqrt37[/tex] is a little more than 6:

6 squared is 36.

7 squared is 49.

Since 37 is between 36 and 49, we know that  [tex]\sqrt{37}[/tex] must be between 6 and 7. In other words, [tex]\sqrt{37}[/tex] is a little more than 6.We can also see this visually by looking at a number line. If we plot the numbers from 6 to 7 on a number line, we can see that  [tex]\sqrt{37}[/tex] is somewhere between 6 and 7.

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Answer:

$40

Step-by-step explanation:

Old Sale Price = $100

It was given 60% discount

 60% of 100 = 0.6 x 100 = 60

we remove the discount from  the original price( 100 -60 ) =  40.

So the new sale price for the pants are now $40

Answer:

black screen

Step-by-step explanation:

this is a black screen

Answer:

it's 2.9 that's how. I get the qnswer

Answer:

2x/x+2

Step-by-step explanation:

Factor out 2x in the numerator

Then you get: 2x(x+4)

Factor the denominator

Two numbers that multiply to 8 and add to 6(2 and 4)

So you get: (x+2)(x+4)

Now you have: (2x(x+4))/(x+2)(x+4)

Simplify by cancelling the x+4

2x/x+2

Hey there!

Answer: [tex] \Rightarrow \boxed {\sf{\frac{2x}{(x+2)}}}[/tex]

Solving steps:-

[tex] \rightarrow\sf{\frac{ {2x}^{2} + 8x}{ {x}^{2} + 6x + 8} }[/tex]

[tex] \rightarrow\sf{\frac{ 2x(x + 4)}{ {x}^{2} + 4x +2x + 8} }[/tex]

[tex] \rightarrow\sf{\frac{ 2x(x + 4)}{ x (x + 4) +2(x + 4)} }[/tex]

[tex] \rightarrow\sf{\frac{ 2x\sout{(x + 4)}}{ \sout{(x + 4)} (x + 2)} }[/tex]

[tex] \rightarrow\sf{\frac{ 2x}{ (x + 2)} }[/tex]

~Done~

Answer for first question: x-intercept(s): (92,0)(92,0) y-intercept(s): (0,−95) for second question : x-intercept(s): (23,0)(23,0) y-intercept(s): (0,−12)

Step-by-step explanation:

How far both planes travelled is an illustration of distance

Both planes are 510 km apart at 2 pm

The rates of the two planes are given as:

Plane A = 300km/h

Plane B = 45km/h

Calculate the difference (r) in their rates

r = 300km/h - 45km/h

This gives

r = 255km/h

At 2 pm, both planes have travelled for 2 hours.

So, the distance between them is:

d = 255 * 2

d = 510km

Hence, both planes are 510 km apart at 2 pm

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Answer:O a=5,b= -4,0 = 9?

Step-by-step explanation:i am not sure if this is right

Step-by-step explanation:

Answer:

11.42

Step-by-step explanation: